can ya'll help me with this 7r+8>64-r

Answer:

5 m/s

Step-by-step explanation:

The equation for speed is distance/time. The distance given is 50 meters. The time given is 10 minutes. 50/10 is 5. 5 meters per second is your speed.

The pattern is 1, 1, 11, 6, 6, 16, 11, 11, 21, 16, 16, 26.

Given,

The pattern: 1, 1, 11, 6, 6, 16, 11, 11, 21, 16.

Here,

First and second term:

1,1 = same number repeat for two times.

Third term:

11 = preceding term + 10

That is, 1 + 10 = 11: That is the third term.

As follows:

Fourth and fifth term:

6, 6 = same number repeat for two times.

Sixth term:

6 + 10 = 16

Seventh and eighth term:

11, 11 = same number repeat.

Ninth term:

11 + 10 = 21

Tenth term is given: 16

Now we have to find eleventh and twelth terms:

Tenth and eleventh should be same number repeat for two times:

16, 16

Twelth term:

16 + 10 = 26.

Now we can complete the pattern:

1, 1, 11, 6, 6, 16, 11, 11, 21, 16, 16, 26.

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The function of domain is X∈R and the range is [tex]\[\left\{ {f \in \mathbb{R}:f \le \frac{1}{4}(1 + 4\sqrt 2 )} \right\}\].[/tex]

The given function is  [tex]\[f\left( x \right) = \sqrt {2 - x - {x^2}} \][/tex]

Domain: The domain of a function is the set of input or argument values for which the function is real.

Use commutative properties to reorder the terms

[tex]\[f(x) = \sqrt { - x + 2} - {x^2}\][/tex]

Separate the function into parts to determine the domain of each part

[tex]\[f\left( x \right) = \sqrt { - x + 2} \]=-x+2= x^{2}[/tex]

Domain is XR (all real numbers)

The function has no undefined points nor domain constraints. Therefore, the domain is X∈R.

Range: The set of values of the dependent variable for which a function is defined

Range of [tex]\[\left\{ {f \in \mathbb{R}:f \le \frac{1}{4}(1 + 4\sqrt 2 )} \right\}\][/tex]

Combine the ranges of all domain intervals to obtain the function range.

Hence, the domain and the range of the function [tex]\[f\left( x \right) = \sqrt {2 - x - {x^2}} \][/tex] are

Domain = X∈R

Range [tex]=\[\left\{ {f \in \mathbb{R}:f \le \frac{1}{4}(1 + 4\sqrt 2 )} \right\}\][/tex].

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This is an example of an experimental study since the researcher chose who would get medicine and who would receive a placebo.

a quantitative research technique that controls other pertinent variables while observing the effects of changes in the study's key variables The Impact of Product Modularity on Supplier Integration: A Multi-Objective Approach2 provides further information. In experimental research, participants are randomly divided into distinct groups (such as experimental and control groups) in order to ascertain the causal relationship between a given condition (an independent variable) and a certain outcome (dependent variable).An illustration of an experimental research on the subject would be to assign people at random to either spend 10 minutes on their  page as the experimental treatment, or spend the same amount of time on other websites (control group).

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Answer: 6 words per minute

Step-by-step explanation:

54 words / 9 minutes =

54/9=6 words per minute

Answer:

6 words/min

Step-by-step explanation:

9 min --- 54 words

÷9 ( )÷9

1 min --- 6 words

Answer: B

I took the quiz

Answer:

(−3, 2); 2 ≤ y < ∞

Step-by-step explanation:

I literally took the test hours ago

Answer:

Step-by-step explanation:

im not sure but yea

The equivalent fraction is: 3/7 or 6/14 or 15/35

Equivalent fractions are those that, despite their visual differences, reflect the same value. You will have consumed half of a cake, for instance, if you have one, divide it into two equal pieces, and then eat one of the pieces.

Given:

Ratio of number of adults to that of children = 3:7

3 : 7 = 3/7

There can be 'n' number of equivalent fractions for this fraction, such as: 3/7, 6/14, 15/35

Hence, The equivalent fraction is: 3/7, 6/14, 15/35

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(166÷2)

______

(1000÷2) = 83/500

Answer: a.{2, 4, 5, 7, 15}    b.{2, 3, 5, 6.5, 9}

Step-by-step explanation: for (a.) you find the median and both extremes, lower and highest value, and for (b.) you just have to re-find the median and the new upper and lower quartiles.

Hope this helps c:

Answer: $23.70/hr

Step-by-step explanation:

x= hourly wage

4= the number of hours worked

$94.80=total earned

4x=$94.80

x=$94.80/4

x= $23.70/hr

She earned $23.70 per hour

Answer:

False! as long as the the Scale Factor is 1, there is still a possibility that the figure will be congruent or greater! GOOD LUCK!

Answer: True

Step-by-step explanation: This is the difference between using transformations to create similar figures vs using transformations to create congruent figures. Similar figures are figures with the same shape. Congruent figures are figures with the same shape and size. If the scale factor is not equal to 1, then the figures are similar. If the scale factor is equal to 1, then the figures are congruent.

The fact that the sum of the interior angles of a triangle add up to 180 is equivalent to the parallel postulate. Therefore, the sum of the interior angles of a triangle in this type of geometry be different from those of triangle in Euclidean geometry.

There is only one parallel to the given line in Riemannian geometry. A straight line of finite length that can be continued endlessly is the second postulate of Euclid.

One of the non-Euclidean geometries that entirely rejects the validity of Euclid's fifth postulate and alters his second postulate is Riemannian geometry, commonly known as elliptic geometry. The fifth postulate of Euclid states that there is only one line that passes through a point that is not on a particular line and is parallel to that line.

In this case, the angles won't change as it's always equal

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As n approaches infinity, the area of the triangle decreases until it equals 1, resulting in a triangle of area 1.

Every term in a geometric sequence has a fixed relationship to the term before it. A popular representation of a geometric sequence containing the initial term a, the common ratio r, and a finite number of terms is  a, a*r, a*r₂, ..., a*r(ₙ₋₁).

According to given value;

                                         =1/2

(1/2)*(1/2)

                                                        =(1/2)²

                                                   =(1/2)³

               =(1/2)+(1/2)²+(1/3)³+.......+(1/2)ⁿ

               =(1)-(1/2ⁿ)

        = a₁-(1-qⁿ)/(1-q)

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Answer:

2⁹

Step-by-step explanation:

Repeatedly dividing 512 by 2 which is a prime number gives:

512 = 2 x 2 x 2 x 2 x 2 x 2 x 2x 2 x 2 = 2⁹ in index notation

Answer:

1,2,4,8,16,32,64,128,256,and 512

Answer:

y = - x³ - 3x² - 3x - 4

Step-by-step explanation:

!!!!!!

The function represented in the graph is -

[tex]y\ =\ -\left(x+0.9\right)^{3}-3.3[/tex]

In mathematics, if -

xⁿ = k

then -

[n] is called exponent

[x] is called base.

Logarithm is the inverse function to exponentiation. That means the logarithm of a number [x] to the base [b] is the exponent to which [b] must be raised, to produce [x]. We can write -

[tex]y = log_{e}x[/tex]

We have the function as -

f(x) = x³

Refer to the graph of the function in the modified form. The function after being translated is same as the one given in the question. The function after translation is -

[tex]y\ =\ -\left(x+0.9\right)^{3}-3.3[/tex]

Therefore, the function represented in the graph is -

[tex]y\ =\ -\left(x+0.9\right)^{3}-3.3[/tex]

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Diana drives for two hours at a speed of 30 mph, covering a total distance of 60 miles to get to Tony's house.

Diana drives for two hours at a speed of 30 miles per hour.

To calculate the distance she will travel

Average speed = total distance / total time

Total time = two hours and the average speed = 30 mph

30 mph = total distance / two hours

Total distance = 30 × 2

Total distance = 60 miles

Therefore, Diana drives for 2 hours at a speed of 30 mph, so the total distance traveled is 60 miles to get to Tony's house.

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Answer:

3

Step-by-step explanation:

Point p was on -1, 2

Point p' was on -3, 6

IF you divde p' by p you get 3, so the dialation is 3.

The solution for the system of equation is 4534 and the graphical representation is attached below.

A system of equation or simultaneous equations are a pair of linear equation is 2 variables such that they represent a pair of straight line sin the cartesian plane.

The point of intersection of these two line on the cartesian plane is given by the solution of the two equation that are given.

A system of equations can be solved algebraically  by matrix method , elimination method or by substitution.

Now let us solve the given equation algebraically by elimination method.

5x - y = 35

3x + y = -3

Adding the equation we get:

or, 8 x = 32

or,  x  = 4

putting the value of x in the first equation we get:

5 × 4 - y = 35

or, -y = 35 - 20

or, y = -15

Hence the point of intersection is ( 4 , -15 )

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An AABA form can be repeated to create a larger form; when b and a are repeated after the first AABA, it is called a "partial reprise". The BA or ABA sections of the AABA structure are repeated in the majority of partial reprises.

The term "reprise" is derived from the French word "repris," which means "act of taking back." The word is also derived from the Latin word "reprendre," which means "taken up again." The term is typically used in music, but it can refer to any continuation of an action.

Various uses of reprise in musics are given below-

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The total cost of producing 75 shirts will be $1050.

It is given that Kara's Custom Tees experienced fixed costs of $800 and variable cost of $3 per shirt.

We have to find an equation and also the total cost of producing 75 shirts.

What is algebra ?

Algebra is the branch that deals with various symbols and the arithmetic operations such as addition , multiplication , etc.

As per the question ;

Fixed cost = $ 800

and

Variable cost per shirt = $3.

If x shirts are produced then ; then equation will be ;

= 800 + 3x

And total cost of 75 shirts will be ;

= 800 + 3 × 75

= 800 + 225

= $ 1050

Thus , the total cost of producing 75 shirts will be $1050.

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a) for given functions f(x) = 8x and g(x) = 12x + 3,

(f g)(x) = 96x² + 24x

b) for functions f(x)= 14 and g(x)= 3 - 12x,

f(x) • g(x) = 42 - 168x

In this question, we have been given two functions.

We need to find the given function.

a) f(x) = 8x and g(x) = 12x + 3

To find (f g)(x)

We know that, the product of functions f(x) and g(x) is:

(f g)(x) = f(x) . g(x)

(f g)(x) = (8x) (12x + 3)

(f g)(x) = 96x² + 24x

So, for given functions f(x) = 8x and g(x) = 12x + 3,

(f g)(x) = 96x² + 24x

b) f(x)= 14 and g(x)= 3 - 12x

To find f(x) • g(x)

f(x) • g(x) = (14) . (3 - 12x)

f(x) • g(x) = 42 - 168x

So, for functions f(x)= 14 and g(x)= 3 - 12x,

f(x) • g(x) = 42 - 168x

Therefore, a) for given functions f(x) = 8x and g(x) = 12x + 3,

(f g)(x) = 96x² + 24x

b) for functions f(x)= 14 and g(x)= 3 - 12x,

f(x) • g(x) = 42 - 168x

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The zeroes of the expression are 5 and -3.5.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The zeroes of the expression can be found by equating the factors of the given expression with 0. Therefore, the zeroes of the expression are,

x - 5 = 0

x = 5

2x + 7 = 0

2x = -7

x = -7/2

x = -3.5

Hence, the zeroes of the expression are 5 and -3.5.

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Answer:

$317.55

Step-by-step explanation:

There are 365 days in a year and the subscription is 0.87 cents per day.

365 * 0.87 = 317.55

The accuracy of a survey estimate refers to the closeness of the estimate to the true population value. Where there is a discrepancy between the value of the survey estimate and the true population value, the difference between the two is referred to as the error of the survey estimate.

The total error of the survey estimate results from the two types of error:

sampling error, which arises when only a part of the population is used to represent the whole population; and

the non-sampling error which can occur at any stage of a sample survey and can also occur with censuses. Sampling error can be measured mathematically whereas measuring non-sampling error can be difficult.

Sampling error is affected by a number of factors including sample size, sample design, the sampling fraction, and the variability within the population. In general, larger sample sizes decrease the sampling error, however, this decrease is not directly proportional.

The most commonly used measure of sampling error is called the standard error (SE). The standard error is a measure of the spread of estimates around the "true value". In practice, only one estimate is available, so the standard error can not be calculated directly.

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The condition  [tex]f^{\prime}(2)[/tex] = 0 to form a subspace of  [tex]\mathbb{R}^{(0,3)}[/tex] is that f ∈ S is that otherwise, S wouldn't be closed under addition and thus would not be a subspace of  [tex]\mathbb{R}^{(0,3)}[/tex].

An identity element (like 0 in the collective of whole numbers under operation of addition) that leaves unaffected any element that it is added in a provided mathematical system.

Now, for the given question.

I'd just like to comment on the paragraph about intuition as well as the additive identity: That instinct is incorrect.

First, we could perhaps define a object that we need to confirm is a subspace of [tex]\mathbb{R}^{(0,3)}[/tex] in a more precise manner than the translation in which it is initially presented. We want to look at a set, S.

Where,

[tex]S=\left\{x, f \mid 0 < x < 3, f \in \mathbb{R}^{(0,3)} \wedge f^{\prime}(x)=0\right\}[/tex]

We are specifically tasked with having to prove the restriction just on derivative of f, which is best accomplished in the manner made reference.

The fact that S, as described above, describes a functional space explains why my initial intuition about problem is ultimately incorrect. I was hindering myself by viewing it solely as a geometric space.

As a result, I missed the fact that zero function (the additive identity in such a functional space) is indeed a natural member of S.

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The complete question is-

I'm working my way through Axler's "Linear Algebra Done Right", and I've run into a proposition that I don't understand. Namely:

The set of differentiable real-valued functions f on the interval (0, 3) such that [tex]f^{\prime}(2)[/tex] = b is a subspace of [tex]\mathbb{R}^{(0,3)}[/tex]  if and only if b = 0.

My intution is that this has something to do with the fact that a subspace requires an additive identity, but that because the domain of the differentiable functions is open and exludes 0, we have to make some concessions (i.e.  [tex]f^{\prime}(2)[/tex] = 0), though I'm unsure of how to work up a proof that backs this.

Why must   [tex]f^{\prime}(2)[/tex] = 0 to form a subspace of  [tex]\mathbb{R}^{(0,3)}[/tex]?

The inequality for the graph is given by   y > | x - 5 | + 1 .

An inequality in mathematics is a relation that compares two numbers or other mathematical expressions in an unequal way.

A graphical representation of an inequality in 2 dimension refers to as the region above or below the graph.

Given the graph of an inequality we write the required inequality using translation properties of a graph.

The parent function of the graph can be written as y > | x |.

the graph of y > | x | is attached below.

The following steps are used to write the inequality:

Hence the required inequality for the graph is given by y > | x - 5 | + 1

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28.007 x 10² = _2800.7_

[tex] \red{ {10}^{2} } = 100 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = \red{100} \times 28.007 \: \: multiply \: the \: numbers \\ = \green {2800.7}\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

that's all :)

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[tex] \: \Large \mathbb{SOLUTION:}[/tex]

[tex] \: \: \text{28.007 × 10² }[/tex]

[tex] \: \: \text{Calculate the power}[/tex]

[tex] \: \: \text{28.007 × 100 }[/tex]

[tex] \: \: \text{Calculate the product or quotient}[/tex]

[tex] \: \: \text{\underline{\underline{2800.7}}}[/tex]

Answer:

Step-by-step explanation:

34 millimeter