Can someone please explain?

Can Someone Please Explain?

Answers

Answer 1

The pressure of N₂ gas produced when 42.57 g of NH₃ is reacted with excess NO in a sealed container is 4.95 atm

How do i determine the pressure of N₂ gas produced?

First, we shall determine the mole of 42.57 g of NH₃ that reacted. Details below:

Mass of NH₃ = 42.57 g Molar mass of NH₃ = 17 g/mol Mole of NH₃ =?

Mole = mass / molar mass

Mole of NH₃ = 42.57 / 1 7

Mole of NH₃ = 2.50 moles

Next, we shall determine the mole of N₂ gas produced. Details below:

4NH₃ + 6NO -> 5N₂ + 6H₂O

From the balanced equation above,

4 moles of NH₃ reacted to produced 5 moles of N₂

Therefore,

2.50 moles of NH₃ will react to produce = (2.5 × 5) / 4 = 3.125 moles of N₂

Finally, we shall determine the pressure of N₂ gas produced. This is shown below:

Volume of container (V) = 28 LTemperature (T) = 540 KNumber of mole of N₂ gas (n) = 3.125 molesGas constant (R) = 0.0821 atm.L/mol KPressure of N₂ gas (P) =?

PV = nRT

P × 28 = 3.125 × 0.0821 × 540

Divide both sides by 28

P = (3.125 × 0.0821 × 540) / 28

P = 4.95 atm

Thus, we can conclude that the pressure of N₂ gas produced is 4.95 atm

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Related Questions

Given the following reaction:
2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g) ∆H = -2511.6 kJ
What is the energy change when 7.76 g of C₂H₂ react with excess O₂?

Answers

Chemical reactions nearly always include a change in energy between the products and reactants.

Thus, Energy is released when chemical bonds are created and is released when chemical bonds are destroyed.

The overall energy of a system, however, must remain constant according to the Law of Conservation of Energy, and chemical reactions frequently absorb or release energy in the form of heat, light, or both.

The difference in the amounts of chemical energy that are stored in the products and reactants accounts for the energy change in a chemical reaction. Enthalpy refers to the system's heat content or stored chemical energy.

Thus, Chemical reactions nearly always include a change in energy between the products and reactants.

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Help please! I'll give brainliest and 5 stars if you show work!

Answers

To solve this problem, we can use the formula:

q = m × c × ΔT

where q is the heat absorbed or released, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.

First, let's calculate the mass of water:

m = 225.0 g

Next, let's calculate the heat absorbed by the water:

q_water = m × c × ΔT

q_water = 225.0 g × 4.184 J/(g·°C) × (24.60°C - 20.53°C)

q_water = 3749.8 J

Since the metal released 4274 J of heat, the heat absorbed by the calorimeter can be calculated by subtracting the heat absorbed by the water from the total heat released by the metal:

q_calorimeter = - (q_water + q_metal)

q_calorimeter = - (3749.8 J + 4274 J)

q_calorimeter = - 8023.8 J

Therefore, the heat absorbed by the calorimeter is -8023.8 J, which is approximately equal to -8000 J or -8.0 kJ. The answer is (c) -339 J, since it is the closest to the calculated value when rounded to the nearest integer. Note that the negative sign indicates that the calorimeter absorbed the heat, which is expected since the reaction involved a release of heat.

Please ASAP!! :'(
Which of the following graphs repMagnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.
· Trial 1:
· Trial 2:

Determine the percent yield of MgO for your experiment for each trial.
· Trial 1:
· Trial 2:
Determine the average percent yield of MgO for the two trials.
resents the function g (x) = x2(x + 1)(x – 2)?

Answers

The theoretical yield of MgO for Trial 1 is 0.348 g, and for Trial 2 is 0.307 g. The percent yield of MgO for Trial 1 is 58.0% and for Trial 2 is 159.2%. The average percent yield of MgO for the two trials is 108.6%.

To calculate the theoretical yield of MgO, we need to use the balanced chemical equation for the reaction between magnesium (Mg) and oxygen (O2) to form magnesium oxide (MgO):

2Mg + O₂ → 2MgO

According to the stoichiometry of this equation, 2 moles of Mg react with 1 mole of O2 to produce 2 moles of MgO. Therefore, we need to determine the number of moles of Mg in each trial and use the mole ratio to find the theoretical yield of MgO.

For Trial 1:

The mass of Mg used is: 26.682 g - 27.012 g = 0.330 g

The molar mass of Mg is 24.31 g/mol, so the number of moles of Mg is:

0.330 g / 24.31 g/mol = 0.0136 mol Mg

According to the balanced equation, 2 moles of Mg produce 2 moles of MgO, so the theoretical yield of MgO is:

0.0136 mol Mg x (2 mol MgO / 2 mol Mg) x (40.31 g MgO/mol) = 0.348 g MgO

For Trial 2:

The mass of Mg used is: 26.987 g - 26.695 g = 0.292 g

The number of moles of Mg is:

0.292 g / 24.31 g/mol = 0.0120 mol Mg

The theoretical yield of MgO is:

0.0120 mol Mg x (2 mol MgO / 2 mol Mg) x (40.31 g MgO/mol) = 0.307 g MgO

To calculate the percent yield of MgO, we need to use the following formula:

Percent yield = (actual yield / theoretical yield) x 100%

For Trial 1:

The actual yield of MgO is: 27.214 g - 27.012 g = 0.202 g MgO

The percent yield of MgO is:

(0.202 g / 0.348 g) x 100% = 58.0%

For Trial 2:

The actual yield of MgO is: 27.183 g - 26.695 g = 0.488 g MgO

The percent yield of MgO is:

(0.488 g / 0.307 g) x 100% = 159.2%

To calculate the average percent yield of MgO for the two trials, we add the percent yields and divide by 2:

Average percent yield = (58.0% + 159.2%) / 2 = 108.6%

Therefore, the theoretical yield of MgO for Trial 1 is 0.348 g, and for Trial 2 is 0.307 g. The percent yield of MgO for Trial 1 is 58.0% and for Trial 2 is 159.2%. The average percent yield of MgO for the two trials is 108.6%.

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A sample of an ideal gas has a volume of 2.31 L
at 279 K
and 1.01 atm.
Calculate the pressure when the volume is 1.09 L
and the temperature is 308 K.

Answers

We can use the combined gas law to determine the pressure of the gas at the final state. The combined gas law relates the pressure, volume, and temperature of a gas:

(P1 x V1) / T1 = (P2 x V2) / T2

where P1, V1, and T1 are the pressure, volume, and temperature of the gas at the initial state, and P2, V2, and T2 are the pressure, volume, and temperature of the gas at the final state.

We are given the initial pressure (P1 = 1.01 atm), volume (V1 = 2.31 L), and temperature (T1 = 279 K) of the gas, and the final volume (V2 = 1.09 L), and temperature (T2 = 308 K) of the gas. We can solve for P2, the final pressure of the gas:

(P1 x V1) / T1 = (P2 x V2) / T2

P2 = (P1 x V1 x T2) / (V2 x T1)

P2 = (1.01 atm x 2.31 L x 308 K) / (1.09 L x 279 K)

P2 = 2.41 atm (rounded to three significant figures)

Therefore, the pressure of the gas when the volume is 1.09 L and the temperature is 308 K is approximately 2.41 atm.

You react 0.017 mol of solid metal with HCl in a coffee cup calorimeter (reaction shown below). The calorimeter has 100 mL of water in it, and the temperature of the water increases by 3.81°C. The calorimeter has a heat capacity of 40.4 J/°C. What is the enthalpy of the reaction in terms of kJ per mol of the metal (your answer should be NEGATIVE, remember to convert from J to kJ, specific heat capacity of water is 4.184 J/g-°C)?

M(s) + 2 HCl (aq) MCl2 (aq) + H2 (g)

M = metal

Answers

To calculate the enthalpy of the reaction in terms of kJ per mol of the metal, we can use the following formula:

q = -mCΔT

where q is the heat absorbed by the water and the calorimeter, m is the mass of the water, C is the heat capacity of the calorimeter, and ΔT is the change in temperature of the water.

First, we need to calculate the heat absorbed by the water and the calorimeter:

q = (100 g) x (4.184 J/g-°C) x (3.81°C) + (40.4 J/°C) x (3.81°C)
q = 1657.4 J

Next, we need to calculate the moles of HCl used in the reaction. From the balanced chemical equation, we can see that 2 moles of HCl react with 1 mole of the metal, so:

moles of HCl = 2 x moles of metal = 2 x 0.017 mol = 0.034 mol

Finally, we can calculate the enthalpy of the reaction per mole of the metal:

ΔH = -q / moles of metal
ΔH = -(1657.4 J) / (0.017 mol)
ΔH = -97,494 J/mol

To convert to kJ/mol, we divide by 1000:

ΔH = -97.494 kJ/mol

Therefore, the enthalpy of the reaction is -97.494 kJ/mol of the metal. Note that the negative sign indicates that the reaction is exothermic (i.e. heat is released).

The following equations represent chemical
reactions.
Chemical Reactions
1) 2Na+2H₂O →NaOH + H₂
2) H₂+O₂ H₂O
3) MgCl₂ → MgCl₂
4) NaOH+MgCh→ NaCl + MgOH
Which equation shows that the total mass during a chemical reaction stays the same?

Answers

The equation that shows that the total mass during a chemical reaction stays the same is 2) H₂ + O₂ → H₂O.

This is an example of a balanced chemical equation where the number of atoms of each element on both the reactant and product side is equal. In other words, the total number of atoms of each element is conserved, and therefore the total mass is conserved. In the other reactions, either the number of atoms on the product side is different from the reactant side or there is no reaction at all.

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What is the molarity of a solution that has 2.0 moles of solute in 3.0 L of solution?

Answers

The molarity of the solution that has 2.0 moles of solute in 3.0 L of solution is 0.67 mol/L

What is molarity?

Molarity is  described as a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution.

Molarity = moles of solute / liters of solution

we then substitute the given values, and have

Molarity = 2.0 moles / 3.0 L

Molarity = 0.67 mol/L

Molarity is  very important because the ration used to express the concentration of  any  solution.

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What is the number of molecules of NO, which contains 16 gm of oxygen. 14

Answers

We can start by using the molecular formula of NO, which is NO = N + O. From the formula, we can see that the molecular weight of NO is 30 g/mol (14 g/mol for nitrogen + 16 g/mol for oxygen).

To find the number of molecules of NO that contains 16 g of oxygen, we need to first calculate the number of moles of oxygen in 16 g of oxygen. Using the atomic weight of oxygen (16 g/mol), we can calculate:

moles of O = mass of O / atomic weight of O = 16 g / 16 g/mol = 1 mol

Next, we need to determine the number of moles of NO that contains 1 mol of oxygen. From the molecular formula of NO, we can see that 1 mol of NO contains 1 mol of oxygen. Therefore, the number of moles of NO that contains 1 mol of oxygen is also 1 mol.

Finally, we can use Avogadro's number to convert the number of moles of NO to the number of molecules of NO. Avogadro's number is approximately 6.02 x 10^23 molecules/mol. Therefore, the number of molecules of NO that contains 16 g of oxygen is:

number of molecules of NO = number of moles of NO x Avogadro's number
number of molecules of NO = 1 mol x 6.02 x 10^23 molecules/mol
number of molecules of NO = 6.02 x 10^23 molecules

Therefore, there are approximately 6.02 x 10^23 molecules of NO that contain 16 g of oxygen.

Please help I appreciate it thanks!!!!!!!!!!!!!!!!!!!!!!

Answers

The correct molar mass for nickel chloride is 94.14 g/mol (option C).

How to calculate molar mass?

Molar mass is the mass of a given substance divided by its amount, measured in moles. It is commonly expressed in grams (sometimes kilograms) per mole.

The molar mass of a substance can be calculated by summing up the atomic masses of the element components.

According to this question, the atomic mass of nickel is 58.693 amu while that of chlorine gas is 35.45 amu. The molar mass of nickel chloride can be calculated as follows;

molar mass = 35.45 amu + 58.693 amu = 94.14 g/mol

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Write the complete equation for neutralization reactions for LiOh + HNO2

Answers

The complete equation for the neutralization reactions for the LiOH + HNO₂ is as :

LiOH  +  HNO₂ ---->  LiNO₂  +  H₂O

The Neutralization reaction is the reaction as in the chemical reaction in which the acid will reacts with the base and to produce the salt and the water molecule. The general equation of the chemical reaction is as :

HX  +  BOH  -->  BX  + H₂O

The reaction with the LiOH and the HNO₂ is :

LiOH  +  HNO₂ ---->  LiNO₂  +  H₂O

There is the combination of the H⁺ ions and OH⁻ ions that will form the water.

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Write the electronic configuration of all the metal ions in the d-blocks (3d series)​

Answers

The electronic configuration of the d-block metal ions in the 3d series is represented by electronic configuration of Argon (Ar), 3d and 4s sub orbitals.

What is the electronic configuration of all d block?

The electronic configuration of the d-block metal ions in the 3d series is as follows:

Scandium (Sc): [Ar] 3d¹ 4s²

Titanium (Ti): [Ar] 3d² 4s²

Vanadium (V): [Ar] 3d³ 4s²

Chromium (Cr): [Ar] 3d⁵ 4s¹

Manganese (Mn): [Ar] 3d⁵ 4s²

Iron (Fe): [Ar] 3d⁶ 4s²

Cobalt (Co): [Ar] 3d⁷ 4s²

Nickel (Ni): [Ar] 3d⁸ 4s²

Copper (Cu): [Ar] 3d¹⁰ 4s¹

Zinc (Zn): [Ar] 3d¹⁰ 4s²

Thus, the above illustration shows the electronic configuration of all the metal ions in the d-blocks (3d series)​.

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please help asap!

3. A double replacement reaction occurs between two solutions of lead (II) nitrate and potassium bromide. Write a
balanced equation for this reaction-identifying the product that will precipitate, and the product that will remain in
solution.
a) Write the balanced equation for this double replacement reaction.
b) If this reaction starts with 32.5 g lead (II) nitrate and 38.75 g potassium bromide, how many grams of the
precipitate will be produced? Remember to use the limiting reactant to calculate the amount of precipitate
formed.
c) How many grams of the excess reactant will remain?

Answers

Answer:

Explanation:

a) The balanced equation for the double replacement reaction between lead (II) nitrate and potassium bromide is:

Pb(NO₃)₂(aq) + 2KBr(aq) → PbBr₂(s) + 2KNO₃(aq)

In this reaction, lead (II) bromide (PbBr₂) will precipitate, while potassium nitrate (KNO₃) will remain in solution.

b) To determine the amount of precipitate produced, we need to first determine the limiting reactant. We can do this by calculating the number of moles of each reactant and comparing it to the stoichiometry of the balanced equation.

The molar mass of lead (II) nitrate is 331.21 g/mol and the molar mass of potassium bromide is 119.00 g/mol.

The number of moles of lead (II) nitrate is 32.5 g / 331.21 g/mol = 0.0981 mol The number of moles of potassium bromide is 38.75 g / 119.00 g/mol = 0.3256 mol

According to the balanced equation, one mole of lead (II) nitrate reacts with two moles of potassium bromide to produce one mole of lead (II) bromide. This means that if all the lead (II) nitrate were to react, it would require 0.0981 mol * 2 = 0.1962 mol of potassium bromide.

Since we have more than enough potassium bromide (0.3256 mol > 0.1962 mol), lead (II) nitrate is the limiting reactant.

The number of moles of lead (II) bromide produced will be equal to the number of moles of lead (II) nitrate consumed, which is 0.0981 mol.

The molar mass of lead (II) bromide is 367.01 g/mol, so the mass of lead (II) bromide produced will be 0.0981 mol * 367.01 g/mol = 36.0 g.

c) To determine the amount of excess reactant remaining, we need to subtract the amount consumed from the initial amount.

The number of moles of potassium bromide consumed is half the number of moles of lead (II) nitrate consumed, which is 0.0981 mol / 2 = 0.04905 mol.

The mass of potassium bromide consumed is 0.04905 mol * 119.00 g/mol = 5.84 g.

The mass of potassium bromide remaining is 38.75 g - 5.84 g = 32.91 g.

A 210.00 g sample of water with an initial temperature of 29.0°C absorbs 7,000.0 J of heat. What is the final temperature of the water?
Note: Use C (capital C) for degrees Celsius when typing units. So it might look like 35C or 2.03 J/gC. Give your answer in 3 sig figs.

Answers

The 210.00 g sample of the water with the initial temperature of the 29.0°C absorbs the 7,000.0 J of heat. The final temperature of the water is the 36.9  °C .

The mass of the water = 210 g

The initial temperature = 29.0 °C

The final temperature = ?

The heat energy = 7000 J

The specific heat capacity = 4.184 J/g  °C

The heat energy is expressed as :

Q = m c ΔT

Where,

The m is mass of water = 210 g

The c is specific heat of water = 4.184 J/g  °C

The  ΔT is change in temperature = final temperature - initial temperature

The  ΔT is change in temperature = T - 29.0 °C

7000 = 210 × 4.184 ( T - 29.0  )

7000 = 878.64 ( T - 29.0  )

( T - 29.0  ) = 7.966

T = 36.9  °C

The final temperature is 36.9  °C .

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Calculate the mass of Kr
in a 9.95 L
cylinder at 91.2 ∘C
and 4.50 bar
.

Answers


To calculate the mass of Kr in a cylinder, we need to use the ideal gas law equation:

PV = nRT

where:
P = pressure = 4.50 bar
V = volume = 9.95 L
n = number of moles of Kr
R = gas constant = 0.08314 L bar K^-1 mol^-1
T = temperature = 91.2 + 273.15 K = 364.35 K

Rearranging the equation to solve for n:

n = PV/RT

n = (4.50 bar)(9.95 L)/(0.08314 L bar K^-1 mol^-1)(364.35 K)

n = 0.520 mol Kr

To calculate the mass of Kr, we need to use the molar mass of Kr, which is 83.798 g/mol. Therefore:

mass of Kr = n x molar mass

mass of Kr = 0.520 mol x 83.798 g/mol

mass of Kr = 43.544 g

Therefore, the mass of Kr in the cylinder is 43.544 g.

2ch4 and c2h8 how are they different

Answers

Answer:

Explanation:

Both 2CH4 and C2H8 have the same number and kind of elements. But practically, 2CH4 will be existing but C2H8 cannot exist.

Hellpppp with this question!!! THE ANSWER IS NOT 0.3 or 0.5

Answers

the answer is 2.5 according to me

Which
thermochemical
equation
corresponds to
the graph?

Answers

Answer: C

Explanation:

Answer: C

Explanation:

Write the net chemical equation for the production of manganese from manganese (II) carbonate, oxygen and aluminum. Be sure your equation is balanced.

Answers

Answer:

Explanation:

The chemical equation for the production of manganese from manganese (II) carbonate, oxygen, and aluminium can be represented as follows:

3MnCO3(s) + 3O2(g) + 4Al(s) → 3Mn(s) + 3CO2(g) + 2Al2O3(s)

In this equation, manganese (II) carbonate (MnCO3) reacts with oxygen (O2) and aluminium (Al) to produce manganese (Mn), carbon dioxide (CO2), and aluminium oxide (Al2O3). The equation is balanced with three molecules of manganese carbonate, three molecules of oxygen, and four molecules of aluminium reacting to produce three molecules of manganese, three molecules of carbon dioxide, and two molecules of aluminium oxide.

PLS MARK ME BRAINLIEST

How many grams in 5 moles of water?

Answers

Answer:

90g

Explanation:

Ans. 90 gram

we know that,

n = wt/m.wt

where, n=  moles

wt.= weight

m.wt = molecular weight

putting values we get

5 = wt./18 ( molecular weight of water is 18

wt.= 90

hence  ans.= 90 gram

Joan wrote a science fiction story where the people only texted each other, and never talked. They still had vocal chords, but they could no
longer make sounds. Their vocal chords were

Answers

Answer:

Vestigial

Explanation:

The retention of genetically determined traits or structures that have partially or completely lost their ancestral purpose in a specific species is known as vestigiality. In most cases, evaluating the vestigality requires comparison with comparable traits in closely related species.

In the titration between hcl and naoh what’s the medium at the end point and why ?

Answers

In the titration between HCl and NaOH, the medium is neutral at the end point because of complete neutralization of a strong acid by a strong base.

Neutralization is a chemical reaction in which acid and base react to form salt and water. Hydrogen (H⁺) ions and hydroxide (OH⁻ ions) react with each other to form water.

The strong acid and strong base neutralization have a pH value of 7.

The beaker gets warm which indicates that the reaction between acid and base is an exothermic reaction releasing heat energy into the surroundings.

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I2 + N2H4==> HI + N2 according to the reaction ,How many grams of HI are obtained if 115.7 g of N2H4 reacts with
an excess of iodine?

Answers

The mass of the HI that is produced is  1843 g

What is stoichiometry?

Stoichiometry is a branch of chemistry that focuses on the quantitative relationships in chemical reactions between reactants and products.

What is the number of moles?

Number of moles of [tex]N_{2} H_{4}[/tex] = 115.7 g/32 g/mol

= 3.6 moles

Now we have that the balanced reaction equation is;

[tex]N_{2} H_{4} + 2I_{2} --- > N_{2} + 4 HI[/tex]

If 1 mole of [tex]N_{2} H_{4}[/tex] produces 4 moles of HI

3.6 moles of [tex]N_{2} H_{4}[/tex] will produce 3.6 * 4/1

= 14.4 moles of HI

Mass of HI produced = 14.4 moles * 128 g/mol

= 1843 g

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PLEASE ACTUALLY ANSWER THE WHOLE ASSIGNMENT FOR BRAINLIEST

Answers

The results of the lab activity showed that the larger the mass of the sun, the more likely at least one planet will fall into the habitable zone.

What effect does the mass of the Sun have on the orbits of Planets?

The mass of the sun affects the orbits of planets in a solar system. When the mass of the sun is larger, the gravitational force between the sun and the planets is stronger, causing the planets to move at a slower pace around the sun.

Conversely, when the mass of the sun is smaller, the gravitational force is weaker, causing the planets to move at a faster pace.

Additionally, when Earth is closer to the sun, the gravitational force is stronger, causing its orbit to become faster, while a farther distance from the sun results in a slower orbit.

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Calculate standard cell potential of an electrochemical cell powered by these half-reactions. (Write values to two decimal places. If a value is less than 1, be sure to write a 0 before the decimal.)

 Pb4+ + 2e− → Pb2+

 Co3+ + e− → Co2+

E°cell = V
Is the reaction spontaneous

Answers

The standard cell potential is found as +1.95 V and is a  spontaneous  reaction.

What is  standard cell potential ?

The standard cell potential (E°cell) of an electrochemical cell is given by the difference between the standard reduction potentials of the two half-cells involved.

E°cell = E°reduction (cathode) - E°reduction (anode)

The half-reactions given are:

Pb4+ + 2e− → Pb2+ (reduction)

Co3+ + e− → Co2+ (reduction)

The standard reduction potentials for these half-reactions are:

E°reduction(Pb4+/Pb2+) = -0.13 V

E°reduction(Co3+/Co2+) = +1.82 V

We then calculate as:

E°cell = E°reduction (Co3+/Co2+) - E°reduction (Pb4+/Pb2+)

E°cell = (+1.82 V) - (-0.13 V)

E°cell = +1.95 V

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WHEN SOME PEOPLE HAVE AN UPSET STOMACH, THEY TAKE A SODA TABLET LIKE
TUMS TO NEUTRALIZE THEIR STOMACH ACID.
THE REACTION IS HYDROCHLORIC ACID PLUS SODIUM BICARBONATE MAKES SALT,
CARBON DIOXIDE (THAT'S WHY SOME PEOPLE BURP) AND WATER.
HOW MUCH CARBON DIOXIDE AND SALT (IN GRAMS) ARE PRODUCED IF A 2 GRAM
TABLET OF SODIUM BICARBONATE IS TAKEN TO REACT WITH 18 GRAMS OF
HYDROCHLORIC ACID?

Answers

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium bicarbonate [tex](NaHCO_3)[/tex] is:

[tex]HCl + NaHCO_3\ - > NaCl + CO_2 + H_2O[/tex]

The coefficients in the balanced equation show that 1 mole of HCl reacts with 1 mole of [tex]NaHCO_3[/tex] to produce 1 mole of NaCl, 1 mole of [tex]CO_2[/tex], and 1 mole of [tex]H_2O[/tex]. We need to find the number of moles of [tex](NaHCO_3)[/tex] present in the tablet.

2 grams of [tex]NaHCO_3[/tex] is equivalent to 0.02 moles, and 18 grams of HCl is equivalent to 0.45 moles. Since [tex](NaHCO_3)[/tex] is limiting reagent, only 0.02 moles of NaCl and [tex]CO_2[/tex] will be produced. The molar mass of [tex]CO_2[/tex] is 44 g/mol, so the mass of [tex]CO_2[/tex] produced is 0.88 g. The molar mass of NaCl is 58.44 g/mol, mass of NaCl produced is 1.17 g.

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Which statement BEST describes the three enzymes? A The enzymes have different structures because they have a different sequence of amino acids. B The enzymes have the same sequence of amino acids because they are all digestive enzymes. C The enzymes perform different functions because they have the same sequence of amino acids. D The enzymes break down the same molecules because they have a different sequence of amino acids.

Answers

The best statement that describes the three enzymes is: The enzymes have different structures because they have a different sequence of amino acids. Opton A is correct.

Enzymes are biological catalysts that facilitate chemical reactions in living organisms. Enzymes are proteins, and their function is determined by their three-dimensional structure, which is determined by the sequence of amino acids that make up the protein.

In this scenario, the three enzymes have different structures, which suggests that they have a different sequence of amino acids. This difference in amino acid sequence results in different folding patterns and ultimately different shapes of the enzymes. The specific shape of an enzyme determines its ability to catalyze a particular chemical reaction. Hence, the different structures of these enzymes indicate that they may perform different functions or catalyze different chemical reactions.

Option A, "The enzymes have different structures because they have a different sequence of amino acids," is the correct answer as it aligns with the fundamental principle of protein structure and function.

Option B, "The enzymes have the same sequence of amino acids because they are all digestive enzymes," is incorrect because enzymes can have different sequences of amino acids even if they perform the same function.

Option C, "The enzymes perform different functions because they have the same sequence of amino acids," is incorrect because the sequence of amino acids determines the enzyme's structure and thus its function.

Option D, "The enzymes break down the same molecules because they have a different sequence of amino acids," is also incorrect because different amino acid sequences can result in different substrate specificity, which means that the enzymes can break down different molecules. Therefore option A is correct.

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Question 8 of 21
Which nucleus completes the following equation?

Answers

The nucleus completing the following equation is option C: ₂₄⁵⁰Cr.

This reaction is a type of radioactive nuclei decay.

What is radioactive decay?

Radioactive decay is the process by which unstable atomic nuclei undergo spontaneous transformations in order to achieve a more stable state. This is accomplished by the emission of particles and/or electromagnetic radiation from the nucleus. The decay may occur by several mechanisms, including alpha decay, beta decay, gamma decay, and electron capture.

In alpha decay, the nucleus emits an alpha particle, which consists of two protons and two neutrons, resulting in a daughter nucleus that has two fewer protons and two fewer neutrons than the original nucleus.

In beta decay, a neutron in the nucleus is converted into a proton and an electron, and the electron is then emitted from the nucleus as a beta particle. This results in the daughter nucleus having one more proton and one fewer neutron than the original nucleus.

In gamma decay, the nucleus emits a gamma ray, which is a high-energy electromagnetic radiation, without changing the number of protons or neutrons in the nucleus.

In electron capture, an electron from the inner shell of the atom is captured by the nucleus, and a proton in the nucleus is converted into a neutron. This results in the daughter nucleus having one fewer proton and one more neutron than the original nucleus.

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Arrange the following ions in order of increasing ionic radius: selenide ion, rubidium ion, bromide ion, strontium ion.

Answers

Answer:

Br, Se, Sr, Rb

Explanation:

Atomic radius increases as you move to the left and down the periodic table. The increase in radius as you move left is due to decreasing effective nuclear charge (the pull an electron feels from the nucleus) since the number of protons decrease. The increase in radius as you move down is due to a higher number of principle energy levels (orbital in which the electron is located relative to the atom's nucleus), causing the electrons to be farther from the nucleus.

8. The compound C2H4 has van der Waals constants a = 4.612 atm•L2/mol2 and b = 0.0582 L/mol. Using both the ideal gas law and van der Waals’s equation, calculate the pressure expected for 30 mol of C2H4 gas in a 6.00-L container at 20 °C.

Answers

Using the Ideal Gas Law, the pressure expected for 30 mol of  [tex]C_2H_4[/tex] gas in a 6.00-L container at 20 °C is 1210.07 atm, and using the van der Waals equation, the pressure is 1179.71 atm.

To calculate the pressure expected for 30 mol of [tex]C_2H_4[/tex] gas in a 6.00-L container at 20 °C, we will use both the Ideal Gas Law and van der Waals equation.

Ideal Gas Law: PV = nRT
P = pressure
V = volume (6.00 L)
n = moles (30 mol)
R = ideal gas constant (0.0821 L•atm/mol•K)
T = temperature (20 °C + 273.15 = 293.15 K)

Solve for P (pressure):

P = nRT / V

P = (30 mol)(0.0821 L•atm/mol•K)(293.15 K) / 6.00 L

P = 1210.07 atm

Van der Waals equation:

(P + a(n/V)²)(V - nb) = nRT
a = 4.612 atm•L²/mol²
b = 0.0582 L/mol

Solve for P (pressure):
(P + (4.612)(30/6)²) (6 - 0.0582 * 30) = (30)(0.0821)(293.15)

P = 1179.71 atm

Using the Ideal Gas Law, the pressure is 1210.07 atm, and using the van der Waals equation, the pressure is 1179.71 atm.

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Calculate the value of Kp at 227 degrees Celsius for the equilibrium: 3 A(g) ⇌ B(g) + D(g Kc=5.15

Answers

To calculate the value of Kp, we need to use the relationship between Kp and Kc, which is:

Kp = Kc x (RT)^Δn

where R is the gas constant (0.082 L atm/mol K), T is the temperature in Kelvin, and Δn is the difference in the number of moles of gas on the product side and the reactant side (in this case, Δn = 2-3 = -1).

First, we need to convert the temperature from Celsius to Kelvin:

T = 227°C + 273.15 = 500.15 K

Next, we can plug in the values into the equation:

Kp = Kc x (RT)^Δn
Kp = 5.15 x (0.082 L atm/mol K x 500.15 K)^-1
Kp = 5.15 x (20.33 L/mol)^-1
Kp = 0.125 atm^-1

Therefore, the value of Kp at 227 degrees Celsius for the equilibrium 3A(g) ⇌ B(g) + D(g) with Kc=5.15 is 0.125 atm^-1.
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