Can someone help with this and give the right answer I am on a time limit

Answer:

D.

x = 31; m∠ROS = 62°

Step-by-step explanation:

we know that a right angle is always 90 degrees, so we subtract 90° by ∠QOR:

[tex]90 - 28 = 62[/tex]

Then we insert the 62 with the (2x)

[tex]62 = 2x[/tex]

we divide both sides by 2 and we get:

[tex]31 = x[/tex]

so the answer is D

x is equal to 31 and we can multiply 31 by 2 and we can get 62°

The calculated measure of the angle Y is 38°

From the question, we have the following parameters that can be used in our computation:

The angle S and angle Y are corresponding angles

This means that the angles are congruent

So, we have

Y = S

Substitute the known values in the above equation, so, we have the following representation

Y = 38°

Hence, the measure of the angle Y is 38°

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Complete question

Lines MN and GH are parallel. If mS is 38°, then what is mY?

See attachment for figure

Answer:

it is 0.94 miles

Step-by-step explanation:

that is because to make a mile you need 63,360 but since you have 60,000 it is not technically a mile

If a, b, c are in Harmonic Progression, b+ca+ca+b ac' ab bc are in Arithmetic Progression.

Given a, b, c are in H.P.:

1/a + 1/b = 2/c

Multiplying both sides by abc:

bc + ac = 2ab

Adding c to both sides:

bc + ac + c = 2ab + c

Rearranging the terms:

c + ab = ac + bc

Adding the terms b + ca and ca + b to both sides:

b + ca + ca + b + ac' + ab + bc = ac + bc + b + ca + ca + b

Simplifying:

b + ca + ca + b + ac' + ab + bc = 2ac + 2b

Dividing both sides by 2:

(b + ca + ca + b + ac' + ab + bc)/2 = ac + b

Hence, b+ca+ca+b ac' ab bc are in A.P.

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Answer:

Step-by-step explanation:

To show that the triangle ABC is a right-angled triangle, we need to prove that one of the angles of the triangle is a right angle, which means it measures 90 degrees.

We can use the Pythagorean theorem to check if the sides of the triangle satisfy the condition for a right-angled triangle. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

Let's find the length of each side of the triangle:

AB = √[(5-2)² + (2-(-3))²] = √(3²+5²) = √34

BC = √[(2-(-8))² + (-3-3)²] = √(10²+6²) = √136

CA = √[(5-(-8))² + (2-3)²] = √(13²+1²) = √170

Now, let's check if the Pythagorean theorem is satisfied:

AC² = AB² + BC²

170 = 34 + 136

Since the Pythagorean theorem is satisfied, we can conclude that the triangle ABC is a right-angled triangle, with the right angle at vertex B.

We know that,

the distance between two points=√(x2-x1)²+(y2-y1)²

∴ The distance between points A and B, AB=√(2-5)²+(-3-2)²

                                                                         =√(9+25)

                                                                         = √(34)

∴ The length of side AB = √(34)

Again,

The distance between points B and C, BC= √[(-8-2)²+{3-(-3)}²]

                                                                      = √(100+36)

                                                                      = √136

∴ The length of side BC =√136

Also,

The distance between points A and D, AC= √(-8-5)²+(3-2)²

                                                                      = √(169+1)

                                                                      = √170

∴ The length of side AC=√170

Now, we get three sides of the triangle as AB = √(34), BC = √136, and AC=√170

Since AC is the longest side, we take it as hypotenuse, and the other sides as base and height in the Pythagoras theorem,

AC²=170

BC²=136

AB²=34

Clearly, 170=136+34

or, AC²=AB²+BC²

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The State Cash Flow Statement using the direct method.

                                                         OP                       INV                  FIN

Personnel emolument                  2,000,000

CRF charges                                 1,000,000

Statutory revenue allocation       20,000,000

Proceeds from sale of fixed assets                          100,000

Purchase of marketable securities                           50,000

Purchase & construction of fixed assets                  500,000

Share of VAT                                 200,000

Share of excess crude oil            100,000

Internally generated revenue    10,000,000

Gratuities and pension              15,000,000

Miscellaneous income                50,000

Overhead expenses                   36,000

Recurrent grant made                20,000

Miscellaneous expenses          10,000

Servicing & repayment of public debts                                            100,000

Grants & subventions from NGO                                                     200,000

Proceeds from loan & other borrowings                                         300,000

Dividends received                                                                           100,000

                                            12,234,000             -450,000              500,000  

  Net Cash Flow for the year ended 31 December 2006: 12,284,000  

To prepare the State Cash Flow Statement using the direct method, we'll classify cash flows into three categories: Operating Activities (OP), Investing Activities (INV), and Financing Activities (FIN). Then, we'll calculate the net cash flow for each category and add them together to find the net cash flow for the year.

Operating Activities:

(-2,000,000 - 1,000,000 + 20,000,000 + 200,000 + 100,000 + 10,000,000 - 15,000,000 + 50,000 - 36,000 - 20,000 - 10,000) = 12,234,000

Investing Activities:

(100,000 - 50,000 - 500,000) = -450,000

Financing Activities:

(-100,000 + 200,000 + 300,000 + 100,000) = 500,000

Net Cash Flow for the year ended 31 December 2006:

12,234,000 (Operating Activities) - 450,000 (Investing Activities) + 500,000 (Financing Activities) = 12,284,000

The above answer is in response to the question below;

The following information has been extracted from the records of WELFARE STATE of Nigeria for the year ended 31 December 2006:

Personnel emolument                  2,000,000

CRF charges                                 1,000,000

Statutory revenue allocation       20,000,000

Proceeds from sale of fixed assets  100,000

Purchase of marketable securities  50,000

Purchase & construction of fixed assets  500,000

Share of VAT                                 200,000

Share of excess crude oil            100,000

Internally generated revenue    10,000,000

Gratuities and pension              15,000,000

Miscellaneous income                50,000

Overhead expenses                   36,000

Recurrent grant made                20,000

Miscellaneous expenses          10,000

Servicing & repayment of public debts      100,000

Grants & subventions from NGO               200,000

Proceeds from loan & other borrowings       300,000

Dividends received                                       100,000

You are required to:

Prepare the State Cash Flow Statements for the year ended 31 December 2006 using the direct method approach (ICAN May 2008)

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The meauser of center is the most appropriate answer for table two is the mean.

Mean, in terms of math, is the total added values of all the data in a set divided by the number of data in the set.

Each mean serves to summarize a given group of data, often to better understand the overall value of a given data set. Pythagorean means consist of arithmetic mean, geometric mean, and harmonic mean

It is the mean because all of the data points are fairly close and there aren't any outliers (extreme values).

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Using trigonometric ratio, the value of x in the figure is 2.61 units

The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec). In geometry, trigonometry is a branch of mathematics that deals with the sides and angles of a right-angled triangle. Therefore, trig ratios are evaluated with respect to sides and angles.

In this problem, we have the adjacent side and we need to find the opposite side.

The ratio that gives us room to find this is the tangent to the angle

tanθ = opposite / adjacent

tan 43 = x / 2.8

x = 2.8 * tan 43

x = 2.61

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Answer:

the 2 angles are 169.1° and 10.9°

Step-by-step explanation:

Supplementary angles add to 180

x = first angle

y = second angle = x - 158.2

x + y = 180

x + (x - 158.2) = 180

2x = 180 + 158.2

2x = 338.2

x = 338.2/2 = 169.1

y = 169.1 - 158.2 = 10.9

x + y = 169.1 + 10.9 = 180

The amount of grams that is equivalent to 3/10 of a kg is given as follows:

300 grams.

The amount of grams that is equivalent to 3/10 of a kg is obtained applying the proportions in the context of the problem.

The amount of kg is 3/10 of a kilogram is given as follows:

3/10 = 0.3kg.

(conversion of a fraction to decimal, divide the numerator by the denominator).

Each kg is composed by 1000 grams, hence the amount of grams in 0.3 kg is given as follows:

0.3 x 1000 = 300 grams.

(proportion applied to obtain the conversion).

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Answer:

a) 5

Step-by-step explanation:

the question say how many zero-dimensional objects are labeled on the object. so, you would count how many blue dots you see on the object, as you can see their are four dots on the the bottom, and one dot at the top.

so, 4 dots + 1 dot = ?

5 blue dots

so your answer is 5.

hopefully this helps, let me know if it doesn't.

When a cylinder is cut parallel to its base, the plane section that results is a circle. This circle will have the same radius as the cylinder's base. The center of the circle will be located at the center of the cylinder's base. This type of cut will create a circular cross-section that is parallel to the base of the cylinder.

Answer:

[tex] \sqrt{( {3 - 2)}^{2} + {( - 2 - 6)}^{2} } [/tex]

[tex] \sqrt{ {1}^{2} + {( - 8)}^{2} } [/tex]

[tex] \sqrt{1 + 64} = \sqrt{65} [/tex]

An example of where past performance does predict future performance would be Mt. Kīlauea's eruption in 2018.

An example of where past performance does not predict future performance would be the eruption of Hualālai last happening in 1801.

Using past data, there was a prediction that Mt. Kīlauea would erupt in the year 2018 and it did happen ( even though it was not very serious ) at the Lower East rift zone of the volcano. Past performance therefore predicted the future.

However, the same prediction said that Hualālai would erupt in 1854 and yet the volcano has not erupted since 1801 which shows that the prediction was wrong.

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a

1.5/4

b

0.5/4

c

0.5/4

because half of 3 is 1.5

Answer:

I'm pretty sure the answer is B(

There are 960 bikes in the repair department and  1.98% of the bikes need two repairs.

The number of bikes with flat tires only is 0.25x, where x is the total number of bikes

The number of bikes with bent handlebars only is 0.05x

The number of bikes with ripped seats only is 0.1x

The number of bikes that need two repairs is 0.01Tx, where T is the percentage of bikes that need two repairs (expressed as a decimal)

The number of bikes that need all three repairs is 0.0833...x

So we have the equation:

0.25x + 0.05x + 0.1x + 0.01Tx + 0.0833...x = 101

Simplifying and solving for x, we get:

x = 960

So there are 960 bikes in the repair department.

To find the number of bikes that need two repairs, we can use the equation:

0.25x + 0.05x + 0.1x + 0.01Tx = 101 - 0.0833...x

Substituting x = 960, we get:

0.25(960) + 0.05(960) + 0.1(960) + 0.01T(960) = 101 - 0.0833...(960)

240 + 48 + 96 + 9.6T = 101 - 80

9.6T = 19

T = 1.98

About 1.98% of the bikes need two repairs.

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Answer:

Step-by-step explanation:

Observation of the real life and way of life of the peoples of Oceania are intertwined in them with local myths.

Based the provided information, the t-value is approximately 1.824.

We shall work out the t-value by calculating the difference between the sample mean and the population mean, divided by the standard error of the mean.

We shall use the t-test formula to calculate the t-value:

t = (sample mean - population mean) / (sample standard deviation / [tex]\sqrt(sample size)[/tex])

where:

sample mean = 86.3

population mean = 83.5

sample standard deviation = 7.2

sample size = 22

Plugging in these values, we have:

t = (86.3 - 83.5) / (7.2 / √22)

t = 2.8 / (7.2 / 4.69)

t = 2.8 / 1.535

t ≈ 1.824

Therefore, the t-value is approximately 1.824.

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Answer:

A!!!!!!!!!!!!!!!!!!!!!!!!!

a)There is higher variability of Y with larger values of X.

b) There is non linear relation between X and Y.

a) Based on the given figure, we can make the following observations:

Therefore, the correct statement is There is higher variability of Y with larger values of X.

b) Based on the features, it is likely that a linear model may not be suitable for these data, and a non-linear model or other regression techniques may be more appropriate to capture the relationship between X and Y accurately.

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The equivalent expression for the given expression 132/11 is 12.

1) Given that, 132/11

Here, the equivalent expression is 132/11 =12

2) 126/7 = 18

3) 7)98(14

      7

_______

     28

     28

________

      0

4) Sixty-four divided by four

That is, 64/4 = 16

5) 28÷2

= 28/2

= 14

6) 28/2 = 14

7) 48/3 = 16

8) 36÷2

= 36/2

= 18

9) 36÷3

= 36/3

= 12

Therefore, the equivalent expression for the given expression 132/11 is 12.

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So it would take A 10 days to do the whole job alone.

An equation is a statement that asserts the equality of two expressions. It typically contains variables, constants, and mathematical operations such as addition, subtraction, multiplication, division, exponentiation, etc. The goal of solving an equation is to find the values of the variables that make the equation true. Equations are used in a variety of mathematical contexts, including algebra, calculus, and geometry, as well as in physics, engineering, and many other fields.

Here,

Let's denote A's speed as "a" and B's speed as "b" (in units of work per day). Then, we know that:

In 5 days, A and B together completed the job, so we can write: 5(a + b) = 1 (where 1 represents the whole job).

If A worked at twice the speed (2a) and B worked at half the speed (0.5b), then they would complete the job in 4 days, so we can write: 4(2a + 0.5b) = 1.

We can simplify the second equation by multiplying out the brackets and collecting like terms:

8a + 2b = 1

Now we have two equations with two unknowns. We can solve for one of the variables in terms of the other, and substitute the result into the other equation to find the value of the remaining variable. Let's solve for "b" in terms of "a" from the first equation:

5(a + b) = 1

5b = 1 - 5a

b = (1/5) - a

Now we can substitute this expression for "b" into the second equation:

8a + 2b = 1

8a + 2((1/5) - a) = 1

8a + (2/5) - 2a = 1

6a = (3/5)

a = (1/10)

So A can do 1/10 of the job in one day. To find out how long it would take A to do the whole job alone, we can use the formula:

time = amount of work / rate

Since A can do the whole job alone, the amount of work is 1, and A's rate is 1/10. Therefore:

time = 1 / (1/10)

= 10 days

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[tex]\sf V_{3 Cylinders} =2.8274(in^{3} ).[/tex]

From the provided information about the ice cubes (height and diameter), it's safe to assume that they are cylinder shaped ice cubes. They could be circular cone ice cubes, but the safest assumption is cylinders. Now, to find the volume of a cylinder we use the following formula:

[tex]\sf V_{Cylinder} =\pi r^{2} h[/tex] or [tex]\dfrac{\pi d^{2} h}{4}[/tex].

For the fist equation, "r" stands for radius, and "h" for height.

On the alternate equation, "d" stands for diameter.

Since we're given the diameter and height, let's use the alternate equation:

[tex]\sf V_{Cylinder} =\dfrac{\pi (1(in))^{2} 1.2(in)}{4}=\dfrac{3}{10} \pi (in^{3} )=0.9425(in^{3} ).[/tex]

This can be done by just multiplying the volume of a single cube ([tex]\dfrac{3}{10} \pi (in^{2} )[/tex]) by 3.

[tex]\sf V_{3 Cylinders} =(3)\dfrac{3}{10} \pi (in^{3} )=\dfrac{9}{10} \pi (in^{3} )=\boxed{\sf 2.8274(in^{3} )}.[/tex]

Assuming the ice cubes have the shape of a circular cone, this is the process for calculating the volume of all 3 cubes:

[tex]\sf V_{Cone} =\dfrac{1}{3} \pi r^{2} h\\ \\\\ \\ V_{3Cones} =3*\dfrac{1}{3} \pi r^{2} h\\ \\ \\= \pi r^{2} h\\ \\ \\=\pi (\dfrac{1(in)}{2} )^{2} (1.2(in))\\ \\\\ =\dfrac{3}{10} \pi (in^{3} )=\boxed{\sf 0.9425(in^{3} )}[/tex]

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Answer:

Step-by-step explanation:

To solve this expression, we need to first combine the integer part of -2 and -1, which gives us -3. Then, we need to combine the fractional parts of -1 and 3/7.

To do this, we find a common denominator, which is 7, and convert -1 to an equivalent fraction with denominator 7 by multiplying both the numerator and denominator by 7, which gives us -7/7.

Now we can add -7/7 and 3/7 to get -4/7.

Therefore, -2 - 1 3/7 = -3 - 4/7, which can also be written as -3 4/7 or -23/7 in improper fraction form

Answer:

Step-by-step explanation:

The standard parametric equations for a circle with center (h, k) and radius r are:

x = h + r cos(theta)

y = k + r sin(theta)

Here, center is (−2, −3) and the radius is 6. Therefore, we have:

h = -2

k = -3

r = 6

Substituting these values into the standard equations, we get:

x = -2 + 6 cos(theta)

y = -3 + 6 sin(theta)

So the set of parametric equations for the circle is:

x(t) = -2 + 6 cos(t)

y(t) = -3 + 6 sin(t)

where t = theta.

In the given diagram, the areas of the figures are as follows:

Area of the rectangle is 1/6 cm²

Area of the parallelogram is 12 m²

From the question, we are to calculate the areas of the given plane shapes

From the diagram, we have a rectangle and a parallelogram

The area of a rectangle is given by the formula

Area = l × w

Where l is the length

and w is the width

From the given information,

l = 1/2 cm

w = 1/3 cm

Thus,

Area = 1/2 cm × 1/3 cm

Area = 1/6 cm²

Hence, the area of the rectangle is 1/6 cm²

For the parallelogram

The area of a parallelogram is given by the formula

Area = b × h

Where b is the base length

and h is the perpendicular height

From the given information,

b = 6 m

h = 2 m

Thus,

Area = 6 m × 2 m

Area = 12 m²

Hence, the area of the parallelogram is 12 m²

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4w+6.

The perimeter is just the summation of the length of all sides of a shape. In the case of a circle, the perimeters is its circumference length. So for this case, all we need to do is add up all the sides in a single expression that will represent the perimeter.

So perimeter for this triangle should be:

Side 1 + Side 2 + Side 3.

Where:

Side 1= w+4;

Side 2= 2w+2;

Side 3= w.

Then, perimeter is:

(w+4)+(2w+2)+(w)

Adding up all the like terms:

(w+2w+w)+(4+2)

(4w)+(6)

4w+6.

The number of times more high school football players were there is 500.

Given that, in 2015, there were roughly 1×10⁶ high school football players and 2×10³ professional football players in the United States.

Here, the number of times more high school football players were there

= 1×10⁶/2×10³

= 1×10³/2

= 1000/2

= 500

Therefore, the number of times more high school football players were there is 500.

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"Your question is incomplete, probably the complete question/missing part is:"

In 2015, there were roughly 1×10⁶ high school football players and 2×10³ professional football players in the United States. About how many times more high school football players were there?​

The rocket will hit the ground after 19.09 seconds.

a) The height of the rocket can be describe as:

h(t) = -16t² + 210t + 75

where

t = time in seconds

h(t) = height of the rocket in feet

b) To find the time at which the rocket reaches its maximum height, we need to find the vertex of the parabolic function. The vertex is given by the formula:

t = -b/(2a)

where

a = -16

b = 210

Substituting these values, we get:

t = -210/(2(-16)) = 6.5625 seconds

To find the maximum height, we substitute this value of t back into the equation for h(t):

h(6.5625) = -16(6.5625)² + 210(6.5625) + 75 = 690.625 feet

This means that the rocket reaches its maximum height of 690.625 feet after 6.5625 seconds.

c) We need to find the time interval during which the height of the rocket is greater than 721 feet. We set the height function h(t) greater than 721 and solve for t:

-16t² + 210t + 75 > 721

-16t² + 210t - 646 > 0

Solving for t using the quadratic formula, we get:

t < 2.975 or t > 14.038

Therefore, the rocket will be more than 721 feet above ground level between 0 and 2.975 seconds, and between 14.038 and infinity seconds.

d) To find the time at which the rocket hits the ground, we set h(t) equal to 0 and solve for t:

-16t² + 210t + 75 = 0

Solving for t using the quadratic formula, we get:

t = [tex]\frac{-b \± \sqrt{b^{2} - 4ac } }{2a}[/tex]

a = -16, b = 210, c = 75

t = [tex]\frac{-210 \± \sqrt{210^{2} - 4(16)(75) } }{2(-16)}[/tex]

t = [tex]\frac{-210 \± \sqrt{22225} }{-32}[/tex]

t = [tex]\frac{-210 \± 149}{-32}[/tex]

t = 2.53125 or t = 13.53125

Since the rocket was launched from the top of a 75-foot building, it will hit the ground after an additional time of:

t + 2.53125 = 5.09375 seconds or t + 13.53125 = 19.09375 seconds

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