Can anyone helppppppp look at picture

Step-by-step explanation:

We can start by solving the second equation for one of the variables. Let's solve for y:

3x + 3y = 6

3y = 6 - 3x

y = 2 - x

Now we can substitute this expression for y into the first equation:

9x - 19y = 74

9x - 19(2 - x) = 74 (substituting y = 2 - x)

9x - 38 + 19x = 74

28x = 112

x = 4

Now we can use this value to find y:

y = 2 - x

y = 2 - 4

y = -2

Therefore, the solution to the system of equations is x = 4 and y = -2.

Hopes this helps

Answer:

137 in binary is 10001001

Step-by-step explanation:

Conner's answer did not receive full credit because he did not convert the hexadecimal number #FF0000 to decimal and binary correctly.

While it is true that the letter F represents 1111 in binary, in hexadecimal, FF represents the decimal value 255, not 1111.

Therefore, Conner's answer is incorrect, and he needs to use the correct conversions to get the right answer.

To convert 255 to binary using divisions, we can use the following steps:

Start with the decimal number 255.

Divide 255 by 2, and write down the quotient and remainder. The quotient is 127, and the remainder is 1.

Divide the quotient (127) by 2, and write down the quotient and remainder. The quotient is 63, and the remainder is 1.

Repeat this process of dividing the quotient by 2 and writing down the quotient and remainder until the quotient becomes 0.

The binary equivalent of 255 is the sequence of remainders written in reverse order: 11111111.

Decimal Number      Quotient          Remainder

        255                   127                1

        127                           63                    1

        63                             31                    1

        31                              15                    1

        15                            7                    1

        7                            3                    1

        3                            1                      1

        1                                0                    1

Divide 137 by 2. The quotient is 68, and the remainder is 1.

Divide 68 by 2. The quotient is 34, and the remainder is 0.

Divide 34 by 2. The quotient is 17, and the remainder is 0.

Divide 17 by 2. The quotient is 8, and the remainder is 1.

Divide 8 by 2. The quotient is 4, and the remainder is 0.

Divide 4 by 2. The quotient is 2, and the remainder is 0.

Divide 2 by 2. The quotient is 1, and the remainder is 0.

Divide 1 by 2. The quotient is 0, and the remainder is 1.

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Answer: about 0.75

Step-by-step explanation:

There is no integer answer, but if you put the x value of -2, you will see the y value is about 0.75

Answer:

To translate a shape, we need to move all its vertices by the same amount in the same direction. Here are the answers to the three parts of the question:

1. To translate parallelogram ABCD 2 units down, we need to subtract 2 from the y-coordinates of all its vertices. Let's say the original coordinates of the vertices are A(a,b), B(c,d), C(e,f), and D(g,h). Then the new coordinates of the vertices will be A'(a,b-2), B'(c,d-2), C'(e,f-2), and D'(g,h-2). Plot these new vertices to get the translated parallelogram.

2. To translate rhombus EFGH 2 units to the left and 4 units down, we need to subtract 2 from the x-coordinates and 4 from the y-coordinates of all its vertices. Let's say the original coordinates of the vertices are E(a,b), F(c,d), G(e,f), and H(g,h). Then the new coordinates of the vertices will be E'(a-2,b-4), F'(c-2,d-4), G'(e-2,f-4), and H'(g-2,h-4). Plot these new vertices to get the translated rhombus.

3. If the coordinates of the vertices of a square LMNO are L(-5,-5), M(-5,5), N(5,5), and O(5,-5), and we want to translate it 3 units to the right and 2 units up, we need to add 3 to the x-coordinates and subtract 2 from the y-coordinates of all its vertices. The new coordinates of the vertices will be L'(-2,-7), M'(-2,3), N'(8,3), and O'(8,-7). Plot these new vertices to get the translated square.

Answer:
8. A) 3.75

9. B) 5.00

Answer:

o=3

Step-by-step explanation:

3+0+3=6

The simplified expression when a polynomial is divided by a monomial is [tex]y^3 / u^3 (8u^4 - 3y^2u^4 - 3y^2).[/tex]

A polynomial expression can be represented as a product of other, smaller polynomial expressions through the algebraic process of factoring. The process of factoring can be used to simplify expressions and solve problems. A polynomial equation's roots can be found by factoring, as can the common factors in an expression that can be eliminated. Factoring occasionally enables us to spot trends and connections between several expressions.

Depending on the kind of polynomial and the degree of the terms involved, there are several ways to factor. S

For the given expression [tex](12y^7u^2-32y^5u^6+15y^7u^6) / (-4y^2u^5)[/tex] factor the common term.

[tex](12y^7u^2-32y^5u^6+15y^7u^6) / (-4y^2u^5)\\-4y^5u^2(3y^2 - 8u^4 - 3y^2u^4) / (-4y^2u^5)[/tex]

Cancelling the -4:

[tex]= y^3 / u^3 (8u^4 - 3y^2u^4 - 3y^2)[/tex]

Hence, the simplified expression is [tex]y^3 / u^3 (8u^4 - 3y^2u^4 - 3y^2).[/tex]

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Answer:

1. Weird food combinations that people enjoy can vary widely and may include things like peanut butter and pickles, french fries and ice cream, or even hot sauce on popcorn.

2. Society needs to get over many social stigmas, such as those related to mental health, sexuality, gender identity, and race. Breaking down these stigmas can help create a more inclusive and accepting society.

3. Foods that people have never tried but would like to can also vary widely and may include exotic fruits, unusual vegetables, or traditional dishes from different cultures.

4. People may resent paying for a variety of things, such as taxes, healthcare costs, or overpriced products or services.

5. A world populated by clones of one person would likely be very homogenous and lacking in diversity, both in terms of physical appearance and personality traits.

6. The existence of aliens is a topic of debate and speculation. While there is no conclusive evidence that they exist, some people believe that the vastness of the universe suggests that other intelligent life forms could be out there.

7. People may worry about a wide range of things, such as their health, their relationships, their finances, or the state of the world.

8. Unusual places that people have been may include remote locations, abandoned buildings, or unconventional travel destinations.

9. People may get their news from a variety of sources, such as traditional news outlets, social media, or alternative news sources.

10. Red flags to watch out for in daily life can include warning signs of scams, dangerous situations, or manipulative people.

11. Movies that people can watch over and over without getting tired of can vary widely, from classic comedies to action-packed blockbusters.

12. When people are old, children may ask them to tell stories about their childhood, their family history, or significant events they witnessed throughout their lifetime.

13. Switching two movie characters could lead to a variety of inappropriate scenarios, depending on the characters and the plot of the movie.

14. An inanimate object that played loud upbeat music while being used could be annoying in many situations, such as during a quiet study session or while trying to fall asleep.

I don't think anything is wrong with your values. Since it's an equation, you can see something different and get the right answer.

(a) The right distributive law is proven for S.For S, this is expressed as (a,b)·(c,d)=(a,b)·(c,d)=(a·c,a·d+b·c).

(a,b)·(c,d)=(bd−ad−bc,ac−ad−bc)=(a·c,a·d+b·c).

(b) we can deduce that x=1 and y=0. Hence, the multiplicative identity element for S is (1,0).

(c) For S, this is expressed as (a,b)·(1,0)=(a,b). Let (a,b) be an arbitrary element in S. The multiplicative identity law is proven for S.

The right distributive law states that the product of a scalar and a vector is equal to the sum of the products of the scalar with each component of the vector.

(a) For S, this is expressed as (a,b)·(c,d)=(a,b)·(c,d)=(a·c,a·d+b·c).

To prove this, we need to show that (a,b)·(c,d)=(a·c,a·d+b·c).

Let (a,b) and (c,d) be two arbitrary elements in S. Then,

(a,b)·(c,d)=(bd−ad−bc,ac−ad−bc)

=(a·c,a·d+b·c).

Therefore, the right distributive law is proven for S.

(b) The multiplicative identity element for S is (1,0). To find this, we need to find a pair of elements (x,y) such that (a,b)·(x,y)=(a,b).

Let (x,y) be an arbitrary pair of elements in S. Then,

(a,b)·(x,y)=(ax−by,ay+bx)

=(a,b).

From this, we can deduce that x=1 and y=0. Hence, the multiplicative identity element for S is (1,0).

(c) The multiplicative identity law states that the product of a scalar and the multiplicative identity element is equal to the scalar itself. For S, this is expressed as (a,b)·(1,0)=(a,b).

To prove this, we need to show that (a,b)·(1,0)=(a,b).

Let (a,b) be an arbitrary element in S. Then,

(a,b)·(1,0)=(a·1−b·0,a·0+b·1)

=(a,b).

Therefore, the multiplicative identity law is proven for S.

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a) 40 seconds is hypothesized mean b) mean time to solve problem by UBC students = 40 sec is null hypothesis c) Alternative hypothesis is time taken is different from 40 sec d) t = -2.353 h) 2% sample mean

Part a) The following variables are significant to this hypothesis test:

B. The null hypothesis is based on the assumption that it will take healthy Canadian adults an average of 40 seconds to solve the logic puzzle.

D. The test statistic is calculated using the sample mean, which is the average time it took the 80 UBC students to solve the logic puzzle.

D. Based on our sample data, we wish to determine the mean time it takes for all UBC students to complete the logic problem.

Part b) The null hypothesis would be that it took UBC students an average of 40 seconds to solve the logic puzzle.

The alternate hypothesis (part c) is that students at UBC take longer than 40 seconds on average to answer the logic puzzle (two-sided alternative).

Part d) You can compute the test statistic as:

t = [tex]\sqrt{sample size} / (sample standard deviation / hypothesised mean) / (sample mean - hypothesised mean)[/tex]

[tex]t = (36 - 40) / (17 / \sqrt{80} )[/tex]

t = -2.353

Part e) The normal distribution can be used to approximate the sampling distribution of the test statistic because the sample size is high (n = 80).

Part f) If we reject the null hypothesis, we can draw the conclusion that there is enough evidence to support the idea that UBC students took longer on average than healthy adult Canadians to solve the logic puzzle.

Part g) It's feasible that we are committing a Type I error if we determine that UBC students perform on average better than healthy adult Canadians (rejecting the null hypothesis when it is actually true).

Part h) If the null hypothesis is correct, a p-value of 0.02 indicates that there is a 0.02 chance of receiving a sample mean that is as severe as the one we observed (or more extreme). In other words, there is only a 2% probability of observing a sample mean that is as different from 40 seconds (or more different) as the one we obtained, if the true mean time taken to solve the logic problem by all UBC students is 40 seconds. Hence, at a significance level of 0.05 but not at a significance level of 0.01 we would reject the null hypothesis.

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We can use the method of integrating factors to solve the equation.

Y' + x = (x-1)y' + 1

The integrating factor method is a technique used to solve linear first-order ordinary differential equations.

Find the integrating factor:

The integrating factor is given by:

I(x) = e^(∫x dx) = e^(x^2/2)

Multiply both sides of the equation by the integrating factor I(x)

e^(x^2/2)Y' + xe^(x^2/2) = (x-1)e^(x^2/2)y' + e^(x^2/2)

Let's simplify the left-hand side using the product rule of differentiation

(d/dx)(e^(x^2/2)Y) = e^(x^2/2)Y' + xe^(x^2/2)

Rewrite the equation using the simplified left-hand side

(d/dx)(e^(x^2/2)Y) = (x-1)e^(x^2/2)y' + e^(x^2/2)

Then, Integrate both sides with respect to x

∫(d/dx)(e^(x^2/2)Y) dx = ∫((x-1)e^(x^2/2)y' + e^(x^2/2)) dx

e^(x^2/2)Y = ∫((x-1)e^(x^2/2)y' + e^(x^2/2)) dx

Using integration by substitution and integration by parts, we can evaluate the integral on the right-hand side and simplify the equation:

e^(x^2/2)Y = e^(x^2/2) + C - e^(x^2/2)y + D

where C and D are constants of integration.

We Solve for Y:

Y = 1 - y + Ce^(-x^2/2) + De^(x^2/2)

Therefore, the solution of the given differential equation is:

Y = 1 - y + Ce^(-x^2/2) + De^(x^2/2)

where C and D are constants of integration.

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This allows you to visualize all of the possible solutions that meet the Constraint and determine the optimal solution for your problem.

To graph the feasible region for the constraint y≥0, you would start by using the polygon tool in a graphing program or software. This tool allows you to create and manipulate polygons on a coordinate plane.

To create the feasible region for the constraint y≥0, you would draw a horizontal line at y=0 on the coordinate plane. This line represents the boundary between the feasible and infeasible regions. Any point above the line is infeasible, while any point below the line is feasible.

Once you have drawn the horizontal line, you can use the polygon tool to create the feasible region by shading in the area below the line. This region represents all of the possible solutions that meet the constraint y≥0. Any point within this region would satisfy the constraint, while any point outside the region would violate the constraint.

Overall, using the polygon tool to graph the feasible region for the constraint y≥0 is a simple process that involves drawing a horizontal line at y=0 and shading in the area below it. This allows you to visualize all of the possible solutions that meet the constraint and determine the optimal solution for your problem.

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Answer:

The number line that shows ï > 7 would be from 8 to 10, as the symbol > means greater than. So the correct answer is B. Submit B.

Answer:

Length ≥ 40

Width ≥ 5

Perimeter = 2 × (Length + Width)

2 × (Length + Width) ≤ 150

Step-by-step explanation:

To create a graph showing the possible dimensions of the garden, we need to plot the length and width of the rectangular area on the x and y axes, respectively. Since we want the length to be at least 40 feet and the width to be at least 5 feet, we can represent these constraints by the following inequalities:

Length ≥ 40

Width ≥ 5

We also know that the total length of fencing available is 150 feet, which means that the perimeter of the rectangular area must be less than or equal to 150 feet. The perimeter of a rectangle is given by:

Perimeter = 2 × (Length + Width)

So, we can write the inequality representing the perimeter as:

2 × (Length + Width) ≤ 150

To graph the possible dimensions of the garden, we can plot the points that satisfy all three inequalities on the x-y plane.

Regarding the vegetables, it is not clear what vegetables the user would like to plant in the garden. As such, we cannot provide a specific answer to this question.

In summary, we need to write three inequalities to represent the constraints in the problem, and we can graph the solution space using these inequalities.

The area of this home plate is equal to 216.5 in².

In order to determine the area of home plate, we would have to apply the law of cosine:

C² = A² + B² - 2(A)(B)cosθ

Where:

A, B, and C represent the length of side or side length of a given triangle.

By substituting the given side lengths and angle into the law of cosine formula, we have the following;

C² = A² + B² - 2(A)(B)cosθ

17² = 12² + 12² - 2(12)(12)cosθ

284 = 144 + 144 - 288cosθ

1 = -288cosθ

cosθ = (-1/288)

θ = 90.199

For the area of home plate, we have:

Area of home plate = Area of rectangle + Area of triangle

Area of home plate = 17(8.5) + 1/2(12)(12)sin90.199

Area of home plate = 144.5 + 72(0.9999940)

Area of home plate = 216.5 in².

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After answering the presented question, we can conclude that Softball graphs players drink less than 4 glasses of water, 60% drink 4 to 8 glasses, and 12% drink more than 8 glasses.

Mathematicians use graphs to visually display or chart facts or values in order to express them coherently. A graph point usually represents a relationship between two or more things. A graph, a non-linear data structure, is made up of nodes (or vertices) and edges. Glue the nodes, also known as vertices, together. This graph includes V=1, 2, 3, 5, and E=1, 2, 1, 3, 2, 4, and (2.5). (3.5). (4.5). Statistical graphs (bar graphs, pie graphs, line graphs, and so on) are graphical representations of exponential growth. A triangle-shaped logarithmic graph.

70% of track athletes drink 4 to 8 glasses of water every day.

We can observe that the blue segment, which represents the number of track athletes who drink 4 to 8 glasses of water each day, accounts for almost 70% of the whole bar. The graph does not support any of the other statements. According to the graph, approximately 25% of track athletes take less than 4 glasses of water, while approximately 5% consume more than 8 glasses. Baseball players drink less than 4 glasses of water, 35% drink 4 to 8 glasses, and 25% drink more than 8 glasses. Softball players drink less than 4 glasses of water, 60% drink 4 to 8 glasses, and 12% drink more than 8 glasses.

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Therefore, the smaller of the two acute angles is 8°.

Trigonometry is a branch of mathematics that deals with the relationships between the angles and sides of triangles. Here are some general steps to solve trigonometry problems:

Understand the problem: Read the problem carefully and identify what is being asked for.

Draw a diagram: Draw a diagram of the triangle and label the sides and angles.

Identify the known values: Identify what is given in the problem, such as the lengths of the sides or the measure of an angle.

Choose the appropriate formula: Choose the formula that relates the known values to the unknown value that you need to find.

Solve for the unknown value: Use algebraic manipulation and/or your calculator to solve for the unknown value.

Check your answer: Check your answer to make sure it makes sense and that it satisfies any given constraints.

Let's start by using the trigonometric identity cos(x) = sin(90° - x) for the left-hand side of the equation:

[tex]cos(4x) =[/tex][tex]sin(90^{0} - 4x)[/tex]

Now we can substitute this into the original equation and simplify:

[tex]sin(90^{0} - 4x) = sin(6x + 10)[/tex]

Using the identity sin(a) = sin(b) implies a = b + 2kπ or a = π - b + 2kπ for some integer k, we can set the angles inside the sine function equal to each other and solve for x:

90° - 4x = 6x + 10 + 2nπ or 90° - 4x = π - (6x + 10) + 2nπ

where n is an integer.

Solving for x in the first equation, we get:

10x = 80° + 2nπ

x = 8° + (2n/10)π

Solving for x in the second equation, we get:

10x = 80° + π + 2nπ

x = (8° + π/10) + (2n/10)π

Since we want the acute angle of the right triangle, which is less than 90°, we only need to consider the values of x that satisfy 0° < x < 22.5°. From the two equations above, we see that x can take on values between 8° and 9° or between 89° and 90°. Therefore, the smaller of the two acute angles is 8°.

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Forever Quilting's monthly profit is $10,250. We can caclculate it in the following manner.

To calculate the company's monthly profit, we need to subtract its total expenses from its total revenue.

Total Revenue = Number of kits sold x Price per kit

Total Revenue = 150 kits x $120 per kit

Total Revenue = $18,000

Total Costs = (Cost of materials per kit + Labor cost per kit) x Number of kits sold + Monthly expenses

Total Costs = ($45 + $5) x 150 kits + $1,000 + $200 + $500 + $4,500

Total Costs = $7,750

Monthly Profit = Total Revenue - Total Costs

Monthly Profit = $18,000 - $7,750

Monthly Profit = $10,250

Therefore, Forever Quilting's monthly profit is $10,250.

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The correct answer is B. The spread of the data distribution for Lake Mockingbird is about 40% greater than the spread for Lake Warbler.

What is the data distribution?

The data distribution refers to the pattern of the data values in a dataset. It describes how the data is spread out, including the range of values, the shape of the distribution, and any clustering or gaps in the data. The data distribution can be described using various statistical measures, such as the mean, median, and standard deviation.

The correct answer to the first question is B: "The spread of the data distribution for Lake Mockingbird is about 40% greater than the spread for Lake Warbler."

For the second question, the statement that is NOT true about the data is B: "The distribution for Lake Mockingbird shows a center that is 3 inches greater than the center of the distribution for Lake Warbler."

hence, The correct answer is B. The spread of the data distribution for Lake Mockingbird is about 40% greater than the spread for Lake Warbler.

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Answer:

 y = 7x + 10

Step-by-step explanation:

Use your point-slope form: y- y1 = m (x - x1) to substitute the given information.

    y - 6 = 7(x - (-4))

Then simplify.

     y - 6 = 7(x + 4)

Next, distribute the 7 into the parenthesis which will give you the point-slope form.

     y - 6 = 7x + 28

In order to write it in slope-intercept form, add 6 to both sides.

    y - 6 + 6 = 7x + 4 + 6

Then simplify to write the equation in slope-intercept form.

    y = 7x + 10

The standard form of rational number of -30/75 is -2/5.

The standard form, given is -30/75.

Both numerator and denominator are a multiple of 15,

Hence we divide them by 15,

The result is -2/5 which is its standard form.

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Answer:

Por lo tanto, el segmento AM mide 26 cm.

Step-by-step explanation:

Como M es el punto medio de AB, entonces AM tiene la misma longitud que MB. Por lo tanto, la longitud de AM es:

AM = MB = AB / 2

Sustituyendo los valores dados, tenemos:

AM = MB = AB / 2 = 52 cm / 2 = 26 cm

The balance of the account after six years with a single $1856 deposit at an APR of 2.42% that compounds interest quarterly would be $2,177.89.

To calculate the balance of the account after six years, we need to use the formula for compound interest:

A = [tex]P(1 + r/n)^(nt)[/tex]

Where:

A = the final amount

P = the principal amount (initial deposit)

r = the annual interest rate as a decimal

n = the number of times the interest is compounded per year

t = the time the money is invested in years

Using the given values:

P = $1856

r = 2.42% = 0.0242

n = 4 (compounded quarterly)

t = 6

Substituting these values in the formula, we get:

A = [tex]1856(1 + 0.0242/4)^(4*6)[/tex]

A = [tex]1856(1.00605)^24[/tex]

A = $2,177.89

Therefore, with a single $1856 contribution over the course of six years at an annual percentage rate of 2.42%, the account balance would be $2,177.89.

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The equation of the axis of symmetry of the quadratic function is given by y = -2x² + 8x - 5.

x = 4 is the x-coordinate of the vertex.

x = 0 and x = 4 are the x-coordinates of the x-intercepts.

y = -5 is the y-coordinate of the y-intercept.

A quadratic function has two variables that can be used to model real-world problems. It has a distinct shape of a parabola, which is a symmetrical U-shaped curve.

The coordinates of the vertex of the function can be calculated by taking the derivative of the given equation and setting it equal to 0.

This yields x = 4 as the x-coordinate of the vertex.

Substituting this value in the given equation gives us the y-coordinate of the vertex, which is y = 11.

The coordinates of the x-intercepts of the function can be found by setting y = 0 in the given equation.

This yields x = 0 and x = 4 as the x-coordinates of the x-intercepts. Substituting these values in the given equation gives us the corresponding y-intercepts, which are

y = -5 and y = 0 respectively.

The coordinates of the y-intercept of the function can be found by setting x = 0 in the given equation.

This yields y = -5 as the y-coordinate of the y-intercept.

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Perimeter of circle is 25.7cm

A semicircle is a two-dimensional geometric shape that is exactly half of a circle. It is formed by taking a diameter of a circle and cutting it in half, so that one half of the circle's circumference is traced out by the resulting arc. The boundary of a semicircle is composed of a curved line called the semicircular arc, which is connected to the two endpoints of the diameter, forming a closed shape.

The area of a semicircle is equal to half of the area of the corresponding circle, while its perimeter is equal to the sum of the diameter and half the circumference of the corresponding circle.

Given

Diameter of semicircle=10cm.

Perimeter of circle=πr+2r

=π×5+2×5

=25.7cm

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Answer:

Θ ≈ 41.8103°

Step-by-step explanation:

using the sine ratio in the right triangle

sinΘ = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{4}{6}[/tex] , then

Θ = [tex]sin^{-1}[/tex] ( [tex]\frac{4}{6}[/tex] ) ≈ 41.8103° ( to 4 decimal places )

The formal statement of the Limit Comparison Test are discuss below with ∑bₙ converges, then ∑aₙ converges as well.

The Limit Comparison Test is a method used to determine the convergence or divergence of a series.

Suppose we have two series, aₙ and bₙ. If we can find a third series, cₙ, such that the limit of the ratio aₙ/cₙ and bₙ/cₙ both exist and are finite, and the limit of aₙ/cₙ divided by bₙ/cₙ is also finite and non-zero, then the two series aₙ and bₙ will converge or diverge together.

In other words, we can say that if the series aₙ diverges, then bₙ also diverges, and if the series bₙ converges, then aₙ also converges.

Here's the formal statement of the Limit Comparison Test:

Let aₙ and bₙ  be two positive series. If there exists a positive series cₙ such that  [tex]\lim_{n \to \infty} \frac{a_n}{c_n}[/tex]  and  [tex]\lim_{n \to \infty} \frac{b_n}{c_n}[/tex] both exist and are finite and positive, then:

(i) If ∑bₙ converges, then ∑aₙ converges as well.

(ii) If ∑aₙ diverges, then ∑bₙ diverges as well.

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