The amount of levels left at the end is 105.
How many levels Camila needs to complete?There is a total of 840 levels in the game.
On the first day she completes 1/6 of the total, so she completes:
840/6 = 140
The remaining is 840 - 140 = 700
Then she completes 1/4 of that, which is:
(1/4)*700 = 175
So now she has left 700 - 175 = 525
Then she completes 4/5, so she does:
(4/5)*525 = 420
The amount left is: 525 - 420 = 105
The correct option is B.
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If nori made 2% in interest on $5,000 and her brother Sean made 1% in interest on $10,000, who made more money in interest?
Answer: Nori
Step-by-step explanation:
2% of 5000 = 100
1% of 1000 = 10
The temperature at a point (x, y, z) is given byT(x, y, z) = 10e¯2x² − y² − 3z².In which direction does the temperature increase fastest at the point (1, 3, 1)?Express your answer as a UNIT vector.
The direction of fastest increase in temperature at the point (1, 3, 1) is given by the unit vector (-5/sqrt(10) , -3/sqrt(10) , -9/sqrt(10)).
To find the direction of fastest increase in temperature at the point (1, 3, 1), we need to find the gradient of the temperature function T(x, y, z) at that point.
The gradient of a function is a vector that points in the direction of steepest increase, and its magnitude is the rate of change in that direction. So, we can find the gradient vector ∇T(x, y, z) as follows:
∇T(x, y, z) = ( ∂T/∂x , ∂T/∂y , ∂T/∂z )
=[tex]( -20xe^(-2x^2-y^2-3z^2) , -2ye^(-2x^2-y^2-3z^2) , -6ze^(-2x^2-y^2-3z^2) )[/tex]
Therefore, at the point (1, 3, 1), the gradient of T(x, y, z) is:
∇T(1, 3, 1) = [tex]( -20e^(-8) , -6e^(-8) , -18e^(-8) )[/tex]
To find the direction of fastest increase, we need to normalize this vector to a unit vector. The magnitude of the gradient vector is:
|∇T(1, 3, 1)| = sqrt( (-[tex]20e^(-8))^2 + (-6e^(-8))^2 + (-18e^(-8))^2 )[/tex]
= sqrt( 640e^(-16) )
= 8e^(-8) sqrt(10)
So, the unit vector in the direction of fastest increase is:
( -20e^(-8) / (8e^(-8) sqrt(10)) , -6e^(-8) / (8e^(-8) sqrt(10)) , -18e^(-8) / (8e^(-8) sqrt(10)) )
= ( -5/sqrt(10) , -3/sqrt(10) , -9/sqrt(10) )
Therefore, the direction of fastest increase in temperature at the point (1, 3, 1) is given by the unit vector (-5/sqrt(10) , -3/sqrt(10) , -9/sqrt(10)).
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Use the parametric equations to plot points. Indicate with an arrow the direction in which the curve is traced as t increases. Identify the coordinates of at least 3 points. x = sin t, y = 1 — cost 0 ≤ t ≤ π
The parametric equations to plot points. The sixth point is (0, 1).
The parametric equations given are:
x = sin t
y = 1 − cos t
To plot points for these equations, we can choose some values of t and substitute them in the equations to get the corresponding values of x and y. Here are some points we can plot:
When t = 0, x = sin 0 = 0 and y = 1 − cos 0 = 1.
So the first point is (0, 1).
When t = π/4, x = sin (π/4) = √2/2 and y = 1 − cos (π/4) = 1 − √2/2.
So the second point is (√2/2, 1 − √2/2).
When t = π/2, x = sin (π/2) = 1 and y = 1 − cos (π/2) = 0.
So the third point is (1, 0).
When t = π, x = sin π = 0 and y = 1 − cos π = 2.
So the fourth point is (0, 2).
When t = 3π/2, x = sin (3π/2) = −1 and y = 1 − cos (3π/2) = 0.
So the fifth point is (−1, 0).
When t = 2π, x = sin 2π = 0 and y = 1 − cos 2π = 1.
So the sixth point is (0, 1).
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15 Points! 15 Points 15 Points!
A student is graduating from college in 12 months but will need a loan in the amount of $10,720 for the last two semesters. The student may receive either an unsubsidized Stafford Loan or a PLUS Loan. The terms of each loan are:
Unsubsidized Stafford Loan: annual interest rate of 5. 95%, compounded monthly, and a payment grace period of six months from time of graduation
PLUS loan: annual interest rate of 6. 55%, compounded monthly, with a balance of $11,443. 63 at graduation
Which loan will have a lower balance, and by how much, at the time of repayment?
The Stafford loan will have a lower balance by $485. 06 at the time of repayment.
The PLUS loan will have a lower balance by $485. 06 at the time of repayment.
The Stafford loan will have a lower balance by $274. 54 at the time of repayment.
The PLUS loan will have a lower balance by $274. 54 at the time of repayment
The Stafford loan will have a lower balance by $272.54 at the time of repayment.
For the Stafford Loan, the principal is $10,720 and the interest rate is 5.95% compounded monthly, so the monthly interest rate is 0.0595/12 = 0.00495833.
After 12 months, the balance of the loan will be:
$10,720(1 + 0.00495833)¹² = $11,204.60
After the time of six-month grace period, the balance will be:
$11,204.60(1 + 0.00495833)⁶ = $11,689.66
For the PLUS Loan, the principal is $11,443.63 and the interest rate is 6.55% compounded monthly, so the monthly interest rate is 0.0655/12 = 0.00545833.
After 12 months, the balance of the loan will be:
$11,443.63(1 + 0.00545833)¹² = $11,962.20
Therefore, the Stafford Loan will have a lower balance at the time of repayment by:
$11,962.20 - $11,689.66 = $272.54
Hence, the Stafford loan will have a lower balance by $272.54 at the time of repayment.
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What is the distance between the bakery (b) and the library (c)? explain using coordinate subtraction.
The distance between the bakery and the library is about 6.7 units.
To discover the distance among points using coordinate subtraction, we want to use the distance formula.
The distance formula is derived from the Pythagorean theorem, which states that during a proper triangle, the forecourt of the period of the hypotenuse( the longest aspect) is identical to the sum of the places of the lengths of the opposite two aspects.
the distance components is as follows
[tex]distance =\sqrt{((x_2 - x_1)^2 + (y_2 - y_1)^2)[/tex]
in which [tex]( x_1, y_1)[/tex] and [tex]( x_2, y_2)[/tex] are the coordinates of the two factors.
In this example, let's anticipate that the equals of the bakery( b) are( 3, 5) and the equals of the library( c) are( 9, 2). applying the space formula, we get
[tex]distance = \sqrt{((9 - 3)^2 + (2 - 5)^2)[/tex]
[tex]distance = \sqrt{x(6^2 + (-3)^2)[/tex]
distance = [tex]\sqrt{( 36 9)[/tex]
distance = [tex]\sqrt{(45)[/tex]
distance ≈ 6.7082
hence, the distance between the bakery and the library is about 6.7 units.
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Will give brainliest for the answer no links
find the lateral surface area of this
cylinder. round to the nearest tenth.
8ft
4ft
[?] ft?
The lateral surface area of a cylinder is given by the formula:
Lateral surface area = 2πrh
where r is the radius of the cylinder and h is the height of the cylinder.
In this case, the height of the cylinder is 8 ft and the radius of the cylinder is 4 ft (half of the diameter). So, we can plug in these values to get:
Lateral surface area = 2π(4 ft)(8 ft)
Lateral surface area = 64π square feet
Rounding to the nearest tenth, we get:
Lateral surface area ≈ 201.1 square feet (rounded to one decimal place)
Therefore, the lateral surface area of the cylinder is approximately 201.1 square feet.
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Task: Attend to Precision
Instructions
A circular pizza box logo has a sector with a central angle of 80% and a diameter of 16 inches.
Complete each of the 2 activitas for this Task.
Activity 1 of 2
Find the area of the sector.
Note: Please round to the nearest tenth
Activity 2 of 2
The unit of measurement for my answer is choose
Area of sector = 161.1 square inches
Activity 1:
The radius of the pizza is half of its diameter, which is 16/2 = 8 inches.
The central angle of the sector is 80%, which is 0.8 times 360 degrees = 288 degrees.
To find the area of the sector, we use the formula:
Area of sector = (central angle / 360) x πr^2
Area of sector = (288 / 360) x π x 8^2
Area of sector = (0.8) x π x 64
Area of sector = 161.1 square inches (rounded to the nearest tenth)
Activity 2:
The unit of measurement for the area of the sector is square inches (in²).
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2.
in triangle lmn, lm= 8cm, mn = 6 cm and lñn=90°.
x and y are the midpoints of mn and ln respectively.
determine yên and yn.
The conclusion is YEN ≈ 63.43°.and YN = 4√5 cm.
Find out the value of yên and yn.?We can begin by drawing a diagram of the triangle LNM with the given measurements:
N
|\
| \
y| \ x
| \
|____\
L 8cm M
Since X is the midpoint of MN, we know that MX = NX = 6/2 = 3cm. Similarly, Y is the midpoint of LN, so LY = NY = 8/2 = 4cm.
To find YN, we can use the Pythagorean theorem:
Y________N
|\ |
| \ |
| \ | 6cm
| \ |
| \ |
L|_____Y\|
4cm
YN² = YL² + LN²
YN² = 4² + 8²
YN² = 80
YN = √80 = 4√5 cm
Therefore, YN = 4√5 cm.
To find YẼN, we need to find the angle YLN. Since Y is the midpoint of LN, YL is half the length of LN, which is 8cm. So YL = 4cm. We can use trigonometry to find the angle YLN:
tan(YLN) = opposite/adjacent
tan(YLN) = YL/LN
tan(YLN) = 4/8
tan(YLN) = 0.5
YLN ≈ 26.57°
Since LÑN = 90°, we know that YEN is the complement of YLN:
YEN = 90° - YLN
YEN ≈ 63.43°
Therefore, YEN ≈ 63.43°.
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In circle N with \text{m} \angle MQP= 44^{\circ}m∠MQP=44 ∘ , find the angle measure of minor arc \stackrel{\Large \frown}{MP}. MP ⌢. M P N Q
The measure of minor arc MPQ in a circle with central angle <MQP measuring 44 degrees is 316 degrees.
To find the measure of minor arc MPQ, we need to first find the measure of central angle <MNQ that intercepts this arc. Since minor arc MPQ and minor arc MP are adjacent, their sum equals the measure of minor arc MPNQ,
<MPQ+arc MP = <MPNQ
Substituting the measure of minor arc MP as 44 degrees, we get,
ZMPQ+ 44 360
Solving for MPQ, we get,
ZMPQ = 360-44
<MPQ = 316 degrees
Therefore, the measure of minor arc MPQ is 316 degrees.
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What is the current ratio of length to width for us paper money
The current ratio of length to width for US paper money is approximately 2.61 to 6.14 inches. This means that US paper money is roughly rectangular in shape, with a length that is about 2.61 times greater than its width.
The current size of US paper money is standardized by the Bureau of Engraving and Printing (BEP). According to the BEP, the current size of a US paper bill is 2.61 inches wide and 6.14 inches long. This size has remained the same since the 1920s, although earlier bills were larger.
The rectangular shape of US paper money makes it easy to handle and store, and the standardized size ensures that it can be easily recognized and processed by vending machines, bank machines, and other automated devices.
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A real estate agent wants to estimate the mean selling price of two-bedroom homes in a particulararea. She wants to estimate the mean selling price to within $10,000 with an 89. 9% level of confidence. The standard deviation of selling prices is unknown but the agent estimates that the highest selling price is$1,000,000 and the lowest is $50,000. How many homes should be sampled
The agent should sample at least 109 two-bedroom homes to estimate the mean selling price within $10,000 with an 89.9% level of confidence.
To estimate the required sample size, we need to use the formula:
n = (Zα/2 * σ / E)²
where Zα/2 = the critical value of the standard normal distribution for the given confidence level. For an 89.9% level of confidence, the value of Zα/2 is 1.645.
σ = the population standard deviation (unknown)
E = the margin of error (maximum distance between the sample mean and the true population mean)
To estimate σ, we can use the range method, which assumes that the population standard deviation is approximately equal to the range divided by 4:
σ ≈ (highest value - lowest value) / 4
In this case, σ ≈ ($1,000,000 - $50,000) / 4 = $237,500
Substituting the values into the formula,
n = (Zα/2 * σ / E)²
n = (1.645 * $237,500 / $10,000)²
n ≈ 109
Therefore, the agent should sample at least 109 two-bedroom homes to estimate the mean selling price within $10,000 with an 89.9% level of confidence.
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Assuming the utility function of an individual is as follows. U= 18q+7q2-1/3q3
determine the utility maximizing units of consumption
The utility maximizing units of consumption are approximately 1 or 15 units, depending on other factors such as budget constraints and the specific preferences of the individual.
To find the utility maximizing units of consumption, we need to calculate the first derivative of the utility function (U) with respect to q and set it equal to zero. Here's the utility function:
U = 18q + 7q^2 - (1/3)q^3
Now, we'll find the first derivative (dU/dq):
dU/dq = 18 + 14q - q^2
To find the utility maximizing units, set dU/dq to zero and solve for q:
0 = 18 + 14q - q^2
Rearrange the equation:
q^2 - 14q + 18 = 0
Now, we'll solve for q using the quadratic formula:
q = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 1, b = -14, and c = 18. Plug these values into the formula:
q = (14 ± √((-14)^2 - 4 * 18)) / 2
q = (14 ± √(196 - 72)) / 2
q = (14 ± √124) / 2
The two possible solutions for q are:
q1 ≈ 1.27
q2 ≈ 14.73
Since the individual consumes discrete units, the utility maximizing consumption will be the whole number closest to these values.
Therefore, the utility maximizing units of consumption are approximately 1 or 15 units, depending on other factors such as budget constraints and the specific preferences of the individual.
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The radius of a circle is 7 centimeters. What is the circumference. Round the answer to the nearest hundredth
Answer:
43.96 cm
Step-by-step explanation:
Given
Radius ( r ) = 7 cm
To find : Circumference of Circle
Formula
Circumference of Circle = 2πr
Note
The Value of π = 3.14
Circumference of Circle
= 2πr
= 2 × 3.14 × 7
= 43.96 cm
Answer:
Not Rounded: 43.9822971503
Rounded: 44
Step-by-step explanation:
r= radius
2[tex]\pi[/tex]r
2[tex]\pi[/tex](7)
= 43.9822971503
OAB is a triangle.
O A = a OB = b
C is the midpoint of OA.
D is the point on AB such that AD: DB = 3:1
E is the point such that OB = 2BE
Using a vector method, prove that the points C, D and E lie on the same straight
line.
Input note: express CE in terms of CD
(5 marks)
â
This evaluated expression is a scalar multiple of -4, which projects that vectors CD and CE are collinear. Then, points C, D, and E lie on the same straight line.
Let us proceed by evaluating the vector CD. Then C is the midpoint of OA, we can evaluate the vector CD by subtracting vector CO from vector OD.
Vector CO = 1/2 × Vector OA
= 1/2 × (a + b)
= 1/2a + 1/2b
Vector OD = 3/4 × Vector AD
= 3/4 × (3/4a - 1/4b)
= 9/16a - 3/16b
Vector CD = Vector OD - Vector CO
= (9/16a - 3/16b) - (1/2a + 1/2b) = 5/16a - 5/16b
Then the value of the vector CE is
OB = 2BE,
we can evaluate the vector BE by dividing vector OB by 2.
Vector BE = 1/2 × Vector OB
= 1/2 × b
= 1/2b
Vector CE = Vector CO + Vector OE
Vector OE = Vector OB - Vector OE
= b - Vector BE
= b - 1/2b
= 1/2b
Vector CE = Vector CO + Vector OE
= (1/2a + 1/2b) + (1/2b)
= 1/2a + b
Then we have to show that vectors CD and CE are collinear. Two vectors are collinear if one is a scalar multiple.
CE can be expressed in terms of CD
CE / CD
= ((1/2a + b) / (5/16a - 5/16b))
Applying simplification for this expression
CE / CD
= (-8a - 8b) / (5a - 5b)
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Circle 1 is centered at (-3,5) and has a radius of 10 units circle 2 is centered at (7,5) and has a radius of 4 units. What transformations can be applied to circle 1 to prove that the circles are similar?
This will result in Circle 1 having the same center and radius as Circle 2, thus proving that the circles are similar.
To prove that Circle 1 and Circle 2 are similar, we can apply the following transformations to Circle 1:
1. Translation: Translate Circle 1 by moving its center from (-3, 5) to (7, 5). This is a horizontal translation of 10 units to the right.
2. Dilation: Dilate Circle 1 with a scale factor of 0.4, which will reduce its radius from 10 units to 4 units (the same as Circle 2).
These transformations will result in Circle 1 having the same center and radius as Circle 2, thus proving that the circles are similar.
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What’s the answer? I need help asap help me
The matrix that represents a dilation by a factor of 3 followed by a reflection over the horizontal axis is given as follows:
[tex]\left[\begin{array}{cc}3&0\\0&-3\end{array}\right][/tex]
What is a dilation?A dilation can be defined as a transformation that multiplies the distance between every point in an object and a fixed point, called the center of dilation, by a constant factor called the scale factor.
The scale factor for this problem is given as follows:
k = 3.
Hence the matrix is:
[tex]\left[\begin{array}{cc}3&0\\0&3\end{array}\right][/tex]
For the reflection over the horizontal axis, we have that the y-coordinate is multiplied by -1, hence the matrix rule is:
[tex]\left[\begin{array}{cc}3&0\\0&-3\end{array}\right][/tex]
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In between classes, Jade plays a game of online Monopoly on her laptop. Using the sample space for rolling two dice that you created in the Group portion of this lesson, find the probability that when Jade rolls the two dice, she gets the outcome given. Express your answers in exact simplest form
The probability that Jade gets the specific outcome you're interested in when rolling two dice is 1/6.
To find the probability that Jade gets a specific outcome when rolling two dice, we will use the sample space for rolling two dice, which consists of 36 possible outcomes (since there are 6 sides on each die, and we have 2 dice: 6 x 6 = 36).
Step 1: Determine the specific outcome you are interested in (for example, the sum of the numbers on the dice being 7).
Step 2: Count the number of ways this outcome can occur. For example, if we want a sum of 7, there are 6 possible outcomes: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).
Step 3: Calculate the probability by dividing the number of successful outcomes by the total number of possible outcomes in the sample space.
In our example, there are 6 successful outcomes, and there are 36 possible outcomes in the sample space:
Probability = (Number of successful outcomes) / (Total number of possible outcomes) = 6/36
Step 4: Express the probability in its simplest form by reducing the fraction. In our example, 6/36 can be reduced to 1/6.
So, the probability that Jade gets the specific outcome you're interested in when rolling two dice is 1/6.
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Ali needed new pencils for school today. He took 6 pencils from a new box of pencils. If there are 18 pencils left in the box, how many pencils were in the brand new box?
If Ali took 6 pencils from a new box of pencils and there are 18 pencils left in the box, then there were 24 pencils in the brand new box.
To see why, you can add the number of pencils Ali took to the number of pencils left in the box:
6 + 18 = 24
Therefore, there were 24 pencils in the brand new box before Ali took 6 of them.
What is the inverse of y = 2^(x - 3)?
show how you got the answer
Answer:
(3-x)^2=y
Step-by-step explanation:
If the area around the cylinder is 64 cm² and the area of the top is 16 cm², what is the surface area of the cylinder?
help me please lol
The surface area of the cylinder is 96cm²
Calculating the surface area of the cylinder?From the question, we have the following parameters that can be used in our computation:
The area around the cylinder is 64 cm² The area of the top is 16 cm²Using the above as a guide, we have the following:
Surface area of the cylinder = The area around the cylinder + 2 * The area of the top
Substitute the known values in the above equation, so, we have the following representation
Surface area of the cylinder = 64 + 2 * 16
Evaluate
Surface area of the cylinder = 96
Hence, the surface area of the cylinder is 96cm²
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I have a question on this please help
Answer:
I believe the answer is D.
Step-by-step explanation:
18 divided by 6 is 3, meaning y is constantly moving 3 spaces up as x moves to the right 1 on a graph.
An open top box is made by cutting out 2 in by 2 in squares from the corners of a large square piece of cardboard. Using the picture as a guide, find an expression for the surface area of the box. If the surface area is 609 in², find the length of x. Remember, there is no top.
The length of the variable x, obtained from the formula for the surface area of a solid about 10.63 inches
What is the surface area of a solid object?
The surface area of a solid object is the area of the outside surface of the object.
The dimensions of of the open top box with the square corners 2 in by 2 in cut from the corners are;
Length of the box, L = x - 4 inches
Width of the box, W = x - 4 inches
Height of the box, H = 2 inches
The surface area of the box is therefore;
Volume, A = L × W + 2 × L × H + 2 × W × H
Plugging in the expressions for the length, width and height of the box, the surface area = (x - 4) × (x - 4) + 2 × 2 × (x - 4) + 2 × 2 × (x - 4) = 9·x² - 40·x + 16
The surface area of the box, A = 9·x² - 40·x + 16
Second part;
When the surface area = 609 in², we get;
A = 609 = 9·x² - 40·x + 16
9·x² - 40·x + 16 - 609 = 9·x² - 40·x - 593 = 0
x = (20 + √(5737))/9 ≈ 10.63, and x = (20 - √(5737))/9 ≈ -6.19
The length x ≈ 10.63 inches
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A veterinarian measures the weight of each puppy in a litter. She records the puppies' weights in pounds. Puppy Weights: 2. 9, 3. 0, 3. 1, 3. 1, 3. 2, 3. 3, 3. 3, 3. 4, 4. 4 The veterinarian removes the outlier of the data. By how many pounds, rounded to the nearest hundredth of a pound, will the mean of the data change with the removal of the outlier?
The mean of the puppy weights changes by 0.14 pounds.
To determine how the mean of the puppy weights changes with the removal of the outlier, follow these steps:
1. First, identify the outlier in the given data set: Puppy Weights: 2.9, 3.0, 3.1, 3.1, 3.2, 3.3, 3.3, 3.4, 4.4. The outlier is 4.4 as it is significantly higher than the rest of the values.
2. Calculate the mean with the outlier: Add all the weights and divide by the total number of puppies (9). (2.9+3.0+3.1+3.1+3.2+3.3+3.3+3.4+4.4)/9 = 29.7/9 = 3.3
3. Calculate the mean without the outlier: Remove the outlier (4.4) from the sum and divide by the new total number of puppies (8). (29.7 - 4.4)/8 = 25.3/8 = 3.1625
4. Calculate the change in mean by subtracting the mean without the outlier from the mean with the outlier, and round to the nearest hundredth of a pound: 3.3 - 3.1625 = 0.1375, which rounds to 0.14.
With the removal of the outlier, the mean of the puppy weights changes by 0.14 pounds.
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An investor who dabbles in real estate invested 1. 1 million dollars into two land investments. On the fi st investment, Swan Peak, her return was a 110% increase on the money she invested. On the second investment, Riverside Community, she earned 50% over what she invested. If she earned $1 million in profits, how much did she invest in each of the land deals?
The investor invested $500,000 in Swan Peak and $600,000 in Riverside Community.
Let's denote the amount invested in Swan Peak as x and the amount invested in Riverside Community as y.
According to the given information:
1. The return on investment in Swan Peak was a 110% increase, which means the total return was 100% + 110% = 210% of the initial investment.
2. The return on investment in Riverside Community was 50% over the initial investment, which means the total return was 100% + 50% = 150% of the initial investment.
We are also given that the investor earned $1 million in profits.
Based on the above information, we can set up the following equations:
1.1 million = 2.1x + 1.5y (equation 1) [This equation represents the total profits earned by the investor.]
x + y = 1.1 million (equation 2) [This equation represents the total amount invested.]
To solve these equations, we can use substitution or elimination method. Let's use the elimination method:
Multiply equation 2 by 2.1 to make the coefficients of x in both equations equal:
2.1x + 2.1y = 2.31 million (equation 3)
Now, subtract equation 1 from equation 3 to eliminate x:
(2.1x + 2.1y) - (2.1x + 1.5y) = 2.31 million - 1.1 million
0.6y = 1.21 million
Divide both sides by 0.6:
y = 2.01 million / 0.6
y ≈ 3.35 million
Substitute the value of y into equation 2:
x + 3.35 million = 1.1 million
x ≈ 1.1 million - 3.35 million
x ≈ -2.25 million
Since the amount invested cannot be negative, we discard the negative value.
Therefore, the investor invested approximately $500,000 in Swan Peak (x) and approximately $600,000 in Riverside Community (y).
Hence, the investor invested $500,000 in Swan Peak and $600,000 in Riverside Community.
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What adds to the number +29 and multiplys to +100?
Answer:
To find two numbers that add up to +29 and multiply to +100, you can use algebra. Let's call the two numbers "x" and "y". We know that:
x + y = 29
xy = 100
We can use the first equation to solve for one of the variables in terms of the other. For example, we can solve for "y" in terms of "x" by subtracting "x" from both sides:
y = 29 - x
Now we can substitute this expression for "y" into the second equation:
x(29 - x) = 100
Expanding the left-hand side of the equation gives:
29x - x^2 = 100
Rearranging and simplifying gives a quadratic equation:
x^2 - 29x + 100 = 0
This quadratic can be factored as:
(x - 4)(x - 25) = 0
So the two numbers that add up to +29 and multiply to +100 are +4 and +25.
Shirts are packed at random in two sizes, regular and extra-large. four shirts are selected from a box of 24 and checked for size. if there are 15 regular shirts in the box, find the probability that all 4 will be regular size.
The probability that all four shirts selected from the box of 24 will be regular size is 0.1367 or 13.67%.
Probability refers to the likelihood or chance of an event occurring. In this scenario, we are interested in finding the probability that all four shirts selected from the box of 24 will be regular size.
To determine this probability, we first need to find the total number of ways in which we can select four shirts from the box. This is known as the sample space and can be calculated using the combination formula, which is nCr = n!/(r!(n-r)!). In this case, we have 24 shirts and are selecting four, so the sample space is 24C4 = (24!)/(4!(24-4)!) = 10,626.
Next, we need to find the number of ways in which we can select four regular shirts from the 15 available. This can be calculated using the same combination formula, which is 15C4 = (15!)/(4!(15-4)!) = 1,455.
Finally, we can calculate the probability of selecting all four regular shirts by dividing the number of favorable outcomes (i.e., selecting four regular shirts) by the total number of possible outcomes (i.e., the sample space). So, the probability of selecting all four regular shirts is 1,455/10,626 = 0.1367 or 13.67%.
Therefore, the probability that all four shirts selected from the box of 24 will be regular size is 0.1367 or 13.67%.
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Which values for an and b make the polynomial 9x^10 + ax^b + 100 a perfect square trinomial?
Answer:
To make the polynomial 9x^10 + ax^b + 100 a perfect square trinomial, we need to add a constant term to it such that it becomes a square of a binomial.
Let's first write the square of a binomial in general form:
(a + b)^2 = a^2 + 2ab + b^2
If we compare this general form with our polynomial, we can see that the first term, 9x^10, is equal to (3x^5)^2, which means that we can write our polynomial as:
(3x^5)^2 + ax^b + 100 = (3x^5 + c)^2
Expanding the right-hand side of this equation, we get:
(3x^5 + c)^2 = 9x^10 + 6cx^15 + c^2
Comparing the coefficient of x^15 on both sides, we get:
6c = 0
Since c cannot be zero (otherwise we would end up with the original polynomial), this means that we must have:
c = 0
Therefore, we can write our polynomial as:
(3x^5)^2 + ax^b + 100 = (3x^5)^2
Expanding the right-hand side, we get:
(3x^5)^2 = 9x^10
Therefore, we must have:
a = 0
b = 10
So the values of a and b that make the polynomial 9x^10 + ax^b + 100 a perfect square trinomial are a = 0 and b = 10.
Jaleesa deposited $4,000 in an account that pays 4% interest compounded annually. Which expression can be used to find the value of her investment at the end of 6 years?
4,000. Times 1. 4. Times 6.
4,000. Times. 0. 4. To the sixth power.
4,000. Times. 1. 4. To the sixth power.
4,000. Plus. 4,000. Times 0. 4. Times. 6
The correct expression is 4,000 times. 1. 4 to the sixth power.
The formula for the future value of an investment with annual compounding interest is:
A = P(1 + r)ⁿ
A = future value
P = principal amount
r = annual interest rate expressed as a decimal
n = number of years.
In this case, Jaleesa deposited $4,000 at an annual interest rate of 4% (0.04 as a decimal) and the investment is compounded annually for 6 years. So the expression that can be used to find the value of her investment at the end of 6 years is:
A = 4,000(1 + 0.04)⁶
Simplifying the expression, we get:
A = 4,000(1.04)⁶
Therefore, the correct expression is 4,000 times. 1. 4 to the sixth power.
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Two spacecraft are following paths in space given by rt sin(t),t,02 and rz cos(t) , -t,73) . If the temperature for the points is given by T(x, y.2) = x y(5 2) , use the Chain Rule to determine the rate of change of the difference D in the temperatures the two spacecraft experience at time =4 (Use decimal notation. Give your answer to two decimal places )
To find the rate of change of the temperature difference between the two spacecraft, we need to first find the temperature at each spacecraft's position at time t=4.
For the first spacecraft, rt sin(t) = r4sin(4) and t=4, so its position is (4sin(4), 4, 0). Using the temperature function, we have T(4sin(4), 4, 0) = (4sin(4))(4)(5-2) = 48.08.
For the second spacecraft, rz cos(t) = r3cos(4) and t=-4/3, so its position is (3cos(4), -4/3, 7). Using the temperature function, we have T(3cos(4), -4/3, 7) = (3cos(4))(-4/3)(5-2) = -9.09.
Therefore, the temperature difference D between the two spacecraft at time t=4 is D = 48.08 - (-9.09) = 57.17.
To find the rate of change of D with respect to time, we use the Chain Rule. Let x = 4sin(t) and y = 4, so D = T(x, y, 0) - T(3cos(t), -4/3, 7). Then,
dD/dt = dD/dx * dx/dt + dD/dy * dy/dt
We already know that D = 48.08 - 9.09 = 57.17, so dD/dx = dT/dx = y(5-2x) = 4(5-2(4sin(4))) = -31.64.
We also have dx/dt = 4cos(4) and dy/dt = 0, since y is constant.
To find dD/dy, we take the partial derivative of T with respect to y, holding x and z constant: dT/dy = x(5-2y) = (4sin(4))(5-2(4)) = -28.16.
Putting it all together, we get:
dD/dt = dD/dx * dx/dt + dD/dy * dy/dt
= (-31.64)(4cos(4)) + (-28.16)(0)
= -126.56
Therefore, the rate of change of the temperature difference between the two spacecraft at time t=4 is -126.56.
Given the paths of the two spacecraft: r1(t) = (t sin(t), t, 0) and r2(t) = (t cos(t), -t, 7), and the temperature function T(x, y, z) = x * y * z^2, we want to determine the rate of change of the temperature difference D at time t=4 using the Chain Rule.
First, let's find the temperature for each spacecraft at time t:
T1(t) = T(r1(t)) = (t sin(t)) * t * 0^2
T1(t) = 0
T2(t) = T(r2(t)) = (t cos(t)) * (-t) * 7^2
T2(t) = -49t^2 cos(t)
Now, find the temperature difference D(t) = T2(t) - T1(t) = -49t^2 cos(t)
Next, find the derivative of D(t) with respect to t:
dD/dt = -98t cos(t) + 49t^2 sin(t)
Now, we need to evaluate dD/dt at t=4:
dD/dt(4) = -98(4) cos(4) + 49(4)^2 sin(4) ≈ -104.32
Thus, the rate of change of the temperature difference D at time t=4 is approximately -104.32 (in decimal notation, rounded to two decimal places).
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Kevin can clean a large aquarium tank in about 7 hours. When Kevin and Lara work together, they can
clean the tank in 3 hours. Enter and solve a rational equation to determine how long, to the nearest tenth
of an hour, it would take Lara to clean the tank if she works by herself? Complete the explanation as to
whether the answer is reasonable.
It would take Lara about 7hours to clean the tank by herself. The answer is reasonable because it
is (select) and, when substituted back into the equation, the equation is true.
The answer is reasonable because it is positive and also the equation is true . it would take Lara about 5.3 hours to clean the tank by herself.
Let's denote the time it takes for Lara to clean the tank alone as "L". We can use the formula for the combined work rate of two people, which is:
(1/7) + (1/L) = (1/3)
Multiplying both sides by the least common denominator, 21L, gives:
3L + 21 = 7L
Subtracting 3L from both sides, we get:
21 = 4L
Dividing both sides by 4, we get:
L = 5.25 hours (to the nearest tenth)
The answer is reasonable because it is positive, and it is also less than 7 hours, which is Kevin's time. When substituted back into the original equation, we get:
(1/7) + (1/5.25) = (1/3)
0.1429 + 0.1905 = 0.3333
0.3334 ≈ 0.3333
The equation is true, so the answer is reasonable. Therefore, it would take Lara about 5.3 hours to clean.
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