there are approximately 0.54 zeptomoles of air trapped inside the container with the movable piston.
To calculate the number of zeptomoles of air trapped inside the container with the movable piston, we first need to calculate the volume of the container.
Assuming the container is a rectangular prism with a length and height equal to the size of the graphene sheet (3 cm) and a width equal to the thickness of the spacer (15 nm), the volume of the container can be calculated as:
V = lwh = (3 cm)(3 cm)(15 nm) = 1.35 x 10^-5 cm^3
Next, we need to calculate the number of moles of air trapped inside the container. We can use the ideal gas law to do this:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
We know that the pressure inside the container is equal to atmospheric pressure, which is approximately 101325 Pa (or 1 atm). The temperature is not given, but we can assume it is room temperature, which is approximately 298 K. The ideal gas constant is 8.314 J/(mol*K).
Therefore, we can rearrange the ideal gas law to solve for n:
n = PV/RT
Substituting in the values we know:
n = (101325 Pa)(1.35 x 10^-5 cm^3)/(8.314 J/(mol*K) * 298 K)
n = 5.41 x 10^-28 mol
Finally, to convert this to zeptomoles, we multiply by 10^21:
n = 5.41 x 10^-7 zmol
Therefore, there are approximately 0.54 zeptomoles of air trapped inside the container with the movable piston.
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Help with homework for work sheet
The theoretical yield of ammonia is 40.8 grams. Rounded to the tenths place, the answer is 40.8 g.
What is the theoretical yield?To determine the theoretical yield of ammonia (NH3), we first need to balance the chemical equation:
N2 + 3H2 → 2NH3
Now we can use the balanced equation to calculate the theoretical yield of NH3. Since we know that 29 L of N2 reacts with 14 g of H2, we need to determine which reactant is limiting and calculate the amount of NH3 that can be formed from that limiting reactant.
First, let's convert the volume of N2 to moles using the ideal gas law:
PV = nRT
n = PV/RT = (1 atm)(29 L)/(0.0821 L·atm/mol·K)(298 K) = 1.2 mol N2
Next, let's convert the mass of H2 to moles:
m = n·M
n = m/M = 14 g / 2.0 g/mol = 7.0 mol H2
Now we can compare the mole ratios of N2 and H2 in the balanced equation to determine which reactant is limiting:
N2:H2 = 1:3
1.2 mol N2 × (3 mol H2/1 mol N2) = 3.6 mol H2
Since we only have 7.0 mol of H2, H2 is not limiting and N2 is limiting. Therefore, we will use the mole ratio between N2 and NH3 to calculate the theoretical yield of NH3:
N2:NH3 = 1:2
1.2 mol N2 × (2 mol NH3/1 mol N2) = 2.4 mol NH3
Finally, we can convert moles of NH3 to grams using the molar mass of NH3:
m = n·M
m = 2.4 mol · 17.0 g/mol = 40.8 g NH3
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100.0 mL of a saturated solution of copper (I) chloride (KSP = 1.72x10-7) with some solid present has
50.0 mL of distilled water added to it. The solution is stirred and some solid remains.
A) What happens to the [Cu+]?
B) What happened to the amount of solid present in the beaker?
C) Sketch an image that shows the solution/solid after the addition of the wate
When 50.0 mL of distilled water is added to 100.0 mL of a saturated solution of copper (I) chloride (KSP = 1.72x10-7) with some solid present, the answer becomes diluted.
What happens to the [Cu+]?When 50.0 mL of distilled water is added to 100.0 mL of a saturated solution of copper (I) chloride (KSP = 1.72x10-7) with some solid present, the [Cu+] will decrease because the answer is now less concentrated. The solid in the beaker will remain the same because the solution is still saturated.
What happened to the amount of solid present in the beaker?The first beaker will expand when heat is applied because it will absorb the heat. Therefore the water level will first decrease due to the beaker's increased volume. Water will eventually warm up and expand as its temperature rises. Water level will consequently rise later.
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The cubic unit cell of rhenium oxide (ReO3) has Re atoms at all eight
corners and O atoms on each of the 12 edges. The atoms touch along the edges. The radii are 137 pm for rhenium and 73 pm for oxygen.
a) Calculate the volume (in cm3) of a unit cell in this crystal.
What is the percent of C in Ca(C2H3O2)2? (Ca= 40.08 g/mol, C = 12.01 g/mol, H= 1.01 g/mol, O = 16.00 g/mol) [?]% C Round your answer to the hundredths place. [?] % C
The percent of C in Ca(C2H3O2)2 is 27.28%.
What is the formula mass of Ca(C2H3O2)2?The formula mass of Ca(C2H3O2)2 is 158.17 g/mol.
What is the percent of H and O in Ca(C2H3O2)2?The percent of H in Ca(C2H3O2)2 is 2.54% and the percent of O is 54.50%.
To find the percent of C in Ca(C2H3O2)2, we first need to calculate the molar mass of the compound:
Molar mass of Ca(C2H3O2)2 = (1 × 40.08) + (2 × (2 × 12.01 + 3 × 1.01 + 2 × 16.00)) = 2 × 158.17 = 316.34 g/mol
Now we can calculate the percent of C:
Mass of C in Ca(C2H3O2)2 = 2 × (2 × 12.01) = 48.04 g/mol
Percent of C in Ca(C2H3O2)2 = (48.04 g/mol ÷ 316.34 g/mol) × 100% = 15.19%
Therefore, the percent of C in Ca(C2H3O2)2 is 15.19%, rounded to the hundredths place.
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what are potential sources of error in rate of reaction lab with hcl and calcium carbonate?
Answer:
human error , random error .
Na2CO3(s)+2HNO3(aq) complete and balance the reaction.
Answer: Na2CO3 + 2 HNO3 → 2 NaNO3 + H2O + CO2
Explanation:
in terms of the henderson-hasselbalch equation, show how it can be solved to find ka of an acid when the concentrations of the conjugate acid and bases are equal.
The pH of the solution is equal to the pKa of the acid when the concentrations of the conjugate acid and base are equal.
The Henderson-Hasselbalch equation is given by:
pH = pKa + log([A-]/[HA])
Where:
pH = the pH of the solution
pKa = the acid dissociation constant of the acid
[A-] = the concentration of the conjugate base
[HA] = the concentration of the acid
When the concentrations of the conjugate acid and base are equal, [A-] = [HA], and the Henderson-Hasselbalch equation can be simplified to:
pH = pKa + log(1)
log(1) = 0, so:
pH = pKa
Therefore, when the concentrations of the conjugate acid and base are equal, the pH of the solution is equal to the pKa of the acid. This can be used to determine the acid dissociation constant (Ka) of the acid by measuring the pH of the solution when the concentrations of the conjugate acid and base are equal.
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An ideal gas (at STP) has a volume of 5 L, how many moles of the gas are present?
Answer:
At STP (standard temperature and pressure), the conditions are:
Temperature (T) = 273.15 K
Pressure (P) = 1 atm = 101.3 kPa
Volume (V) = 22.4 L (for one mole of gas)
So, for a gas at STP with a volume of 5 L, we can use the following formula to calculate the number of moles present:
n = V / Vm
where:
n = number of moles
V = volume of gas (in liters)
Vm = molar volume of gas at STP (22.4 L/mol)
Plugging in the values, we get:
n = 5 L / 22.4 L/mol
n = 0.2232 mol (rounded to four significant figures)
Therefore, there are approximately 0.2232 moles of the gas present.
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What is the Heisenberg Uncertainty Principle?
A. We can know either the speed (momentum) or location, but not both at the same time.
B. We cannot ever know the speed (momentum) or location of the electron.
C. We can know only the speed (momentum) of the electron, but never the location.
D. We can know only the location of the electron, but never the speed (momentum).
According to the Heisenberg Uncertainty Principle, we can only know one of two things at once: either the speed (momentum) or the position.
When does the position of momentum become unpredictable when the location of a particle is uncertain?The uncertainty principle can also be explained in terms of a particle's momentum and position. The momentum of a particle is calculated by dividing its mass by its speed.
What does the Heisenberg uncertainty principle translate into in terms of position and momentum?Heisenberg's Uncertainty Principle states that there is some uncertainty when measuring a particle's variable. a term frequently used to describe the position and momentum of a particle.
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what does the bohr rutherford diagram of water mixing with lithium look like?
Simple atomic models called Bohr-Rutherford diagrams display how many electrons are present in each of an atom's outermost shells.
Does lithium fall within the Bohr model?The Bohr theory only applies to organisms with a single electron. Three electrons make up the lithium atom. Hence, the lithium atom does not fit into Bohr's hypothesis.
How does lithium appear?Lithium is an air-reactive alkali metal that tarnishes quickly to a dull silvery-grey and finally black. It is a silvery-white to grey alkali metal with a metal-lic lustre when new. At 20 °C, it is the least dense and lightest metal of all the elements that are not gases, and it floats on water.
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Complete the word equation:
zinc + hydrochloric acid = __________+hydrogen
copper carbonate + sulfuric acid =_______________+carbon dioxide + water
__________+nitric acid = zinc nitrate+________+water
Answer:
zinc + hydrochloric acid = zinc chloride + hydrogen
copper carbonate + sulfuric acid = copper sulfate + carbon dioxide + water
copper + nitric acid = copper nitrate + nitrogen dioxide + water
Explanation:
Zinc + Hydrochloric acid → Zinc chloride + Hydrogen gasZn + 2HCl → ZnCl2 + H2
Copper carbonate + Sulfuric acid → Copper sulfate + Carbon dioxide + WaterCuCO3 + H2SO4 → CuSO4 + CO2 + H2O
Copper + Nitric acid → Copper nitrate + Nitrogen dioxide + WaterCu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O
Answer:
zinc + hydrochloric acid = zinc chloride + hydrogen
copper carbonate + sulfuric acid = copper sulfate + carbon dioxide + water
zinc + nitric acid = zinc nitrate + hydrogen gas + water
A sample of xenon gas occupies a volume of 5.82 L at 453 K. If the pressure remains constant, at what temperature will this same xenon gas sample have a volume of 2.64 L?
Answer:
204.8 K
Explanation:
(P1 * V1)/T1 = (P2 * V2)/T2
"If the pressure remains constant" means
you can cancel the pressure part of the equation
T2 = (V2 * T1)/(V1)
T2 = (2.64 L * 453 K)/(5.82 L)
T2 = 204.8 K
chatgpt
A sample of xenon gas occupies a volume of 5.82 L at 453 K. If the pressure remains constant, the temperature that will make this same xenon gas sample have a volume of 2.64 L is 220K.
What is combined gas law?The combined gas law is the law of of gaseous state which is made by combination of Boyle's law, Charle's law, Avogadro's law and Gay Lussac's law.
It is a mathematical expression that relates Pressure, Volume and Temperature.
(P1 × V1)÷T1 = (P2 × V2)÷T2
We can also use the following relation-
PV = nRT
At constant pressure,
V1÷T1 = V2÷T2
This is Charles's law.
V1 = 5.82L
T1 = 453K
V2 = 2.64L
T2 = ?
T2 = 220K
Therefore, A sample of xenon gas occupies a volume of 5.82 L at 453 K. If the pressure remains constant, the temperature that will make this same xenon gas sample have a volume of 2.64 L is 220K.
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a buffer is made by adding 0.300 mol ch3cooh (acetic acid) and 0.300 mol ch3coona (sodium acetate) to enough water to make 1.00 l of solution. calculate the ph after 0.020 mol of naoh is added to this buffer. (you may again ignore change in volume as a result of the addition.) reference data: pka of acetic acid is 4.74 g
The pH of the buffer after the addition of 0.020 mol of NaOH is 4.83.
Henderson-Hasselbalch equation: pH = pKa + log([A^-]/[HA]),
[CH3COOH] = 0.300 mol/1.00 L = 0.300 M
[CH3COO^-] = 0.300 mol/1.00 L = 0.300 M
CH3COOH + NaOH → CH3COO^- + H2O
[CH3COOH] = (0.300 mol - 0.020 mol)/1.00 L = 0.280 M
CH3COO^-] = (0.300 mol + 0.020 mol)/1.00 L = 0.320 M
pH = pKa + log([CH3COO^-]/[CH3COOH])
pH = 4.74 + log(0.320/0.280)
pH = 4.83
The pH of a solution can be measured using a pH meter or pH paper, which changes color based on the pH of the solution. It is a dimensionless quantity that indicates the concentration of hydrogen ions (H+) in a solution. pH stands for "power of hydrogen" and is defined as the negative logarithm of the hydrogen ion concentration. A pH of 7 is considered neutral, pH values below 7 indicate acidity, and pH values above 7 indicate alkalinity.
pH is an important parameter in many chemical and biological processes, as it can affect the behavior and properties of molecules and ions in solution. Maintaining the correct pH in biological systems is critical for many physiological processes, and pH control is important in many industrial processes as well.
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7. How many grams of potassium dichromate would have 7.44 x 10^25 atoms of oxygen?
Answer:
simplified-74400000000000000000000000x
Explanation:
PLEASE ANSWER NOWW URGENTTT
S + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O
In the above equation how many moles of water can be made when 102.3 grams of HNO3 are consumed?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:
Element
Molar Mass
Hydrogen
1
Nitrogen
14
Sulfur
32
Oxygen
16
CAN SOMEONE HELP WITH THIS QUESTION?
The minimum mass of hydrochloric acid that could be left over by the chemical reaction is 18.23 g.
What is moles?Moles in chemistry is a unit of measurement for the amount of a substance. It is equal to the number of atoms or molecules in a given mass of a substance, and is represented by the symbol ‘mol’. The molar mass of a substance is the mass of one mole of that substance, expressed in grams. It is important for calculating the amount of energy or reactants needed for a reaction. Moles can also be used to measure the concentration of a solution.
The minimum mass of hydrochloric acid that could be left over by this chemical reaction can be calculated using the following equation:
Moles of HCl = Mass HCl / Molar Mass HCl
Moles of NaOH = Mass NaOH / Molar Mass NaOH
Moles of HCl must equal moles of NaOH in the reaction, so:
Moles HCl = Moles NaOH
Mass HCl / Molar Mass HCl = Mass NaOH / Molar Mass NaOH
Rearranging for mass HCl:
Mass HCl = Molar Mass HCl x Mass NaOH / Molar Mass NaOH
Given:
Mass HCl = 28.8 g
Molar Mass HCl = 36.46 g/mol
Mass NaOH = 20.0 g
Molar Mass NaOH = 40.0 g/mol
Substituting values:
Mass HCl = 36.46 g/mol x 20.0 g / 40.0 g/mol
Mass HCl = 18.23 g
Therefore, the minimum mass of hydrochloric acid that could be left over by the chemical reaction is 18.23 g.
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A chemist is using a solution of HNO3 that has a pH of 3.75.
What is [OH-] for the solution? Round to the
nearest hundredth.
What is the pOH of the solution? Round to the
nearest hundredth.
The level of acidity or alkalinity of aqueous solutions can be conveniently expressed using the pH scale, also known as the pOH scale.
How does pH formula work?"The negative of the logarithm of the molar hydronium-ion concentration" is how pH is defined. The pH formula is written as. P H equals l o g [H 3 0 +] You can alternatively write the pH Formula as. l o g [H +] = p H
The pH of a solution is equal to the solution's hydrogen ion concentration divided by its negative logarithm to base 10:
pH = -log₁₀[H⁺]
pOH = -log₁₀[OH⁻]
For any aqueous solution, the sum of the pH and pOH is 14. That is;
pH + pOH = 14
Now solving for [OH⁻]:
HNO₃ + H₂O → H₃O⁺ + NO₃⁻
Since pH + pOH = 14
pOH = 14 - pH = 14 -3.75 = 10.25
since pOH = -log₁₀[OH⁻]
10.25 = -log₁₀(OH⁻)
[OH⁻] = inverse log₁₀(-pOH)
[OH⁻] = inverse log₁₀(-10.25) = 5.62 x 10⁻¹¹moldm⁻³
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Answer:
[OH− ] = 5.62
n = -11
pOH = 10.25
Explanation:
I did it not too long ago
Calculate the mass of butane needed to produce 67.5 g of carbon dioxide.
Express your answer to three bignificant figures and include the appropriate units.
The mass of butane needed to produce 67.5 g of carbon dioxide is 22.27 g.
StepsThe balanced chemical equation for the combustion of butane (C4H10) is:
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
This equation shows that 2 moles of butane react with 13 moles of oxygen to produce 8 moles of carbon dioxide. The molar mass of butane is 58.12 g/mol, and the molar mass of carbon dioxide is 44.01 g/mol.
To calculate the mass of butane needed to produce 67.5 g of carbon dioxide, we can use the following steps:
Calculate the number of moles of carbon dioxide produced:
67.5 g CO2 x (1 mol CO2 / 44.01 g CO2) = 1.534 mol CO2
Use the mole ratio from the balanced chemical equation to find the number of moles of butane needed:
1.534 mol CO2 x (2 mol C4H10 / 8 mol CO2) = 0.3835 mol C4H10
Calculate the mass of butane needed:
0.3835 mol C4H10 x 58.12 g/mol = 22.27 g C4H10
Therefore, the mass of butane needed to produce 67.5 g of carbon dioxide is 22.27 g.
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Copper and Silver Nitrate Lab The purpose of this experiment is to observe the chemical reaction between copper wire and silver nitrate and to record the stoichiometric relationship between the reactants and the products in this reaction
Answer questions below:
1a) What are some possible explanations for why you could have a percent yield less than 100% in this lab?
1b) What are some possible explanations for why you could have a percent yield higher than 100% in this lab?
assume that the product was dry for 1a
Because it demonstrated how the atoms of copper and silver were changed by oxidation and reduction, the experiment achieved its goal. The presence of a specific halogen in a presumed halogenoalkane can be determined using silver nitrate solution.
What does the term "stoichiometric" mean?Calculating the products and reactants of a chemical process is what we mean by stoichiometry. Numbers are essentially its main focus. When using balanced formulas to determine the proportions of reactants and products, stoichiometry is a key concept in chemistry.
The name "stoichiometric" refers to what?The study of quantifiable correlations found in chemical equations and reactions is known as stoichiometry. The terms stoicheion, which means element, and metron, which means measure, are the origins of the name.
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Lab: Measuring pH Assignment: Lab Report
A sample lab report that measures pH levels is given below:
The Laboratory ReportIntroduction:
In this experiment, we measured the pH levels of various substances using a pH meter. The pH meter measures the acidity or basicity of a substance on a scale of 0 to 14, with 0 being extremely acidic, 7 being neutral, and 14 being extremely basic.
Materials:
pH meter
Distilled water
Hydrochloric acid (HCl)
Sodium hydroxide (NaOH)
Vinegar
Lemon juice
Baking soda
Tap water
Procedure:
Calibrated the pH meter according to the manufacturer's instructions using distilled water.
Prepared five test solutions in beakers:
50 mL of 0.1 M HCl
50 mL of 0.1 M NaOH
50 mL of vinegar
50 mL of lemon juice
50 mL of baking soda
Rinsed the pH meter probe with distilled water and then dipped it into each test solution, making sure that the probe did not touch the bottom or sides of the beaker.
Recorded the pH measurement for each solution and compared it to the expected pH range based on the known properties of the substances.
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Answer:
I have attached my interpretation of the pH measuring lab. All I ask is that you at least change some of the answers, please
Explanation:
Based on the above calculation, is the formation of MgO exothermic (negative) or endothermic (positive)?
The amount of energy for the reaction using Hess's Law is -459.82 kJ/mol.
Based on the calculation, the formation is exothermic.
How to calculate amount of energy?To use Hess' Law, we need to rearrange and multiply the given chemical equations to get the desired equation:
2 Mg + 2 HCl → 2 MgCl₂ + H₂ (multiply Equation 1 by 2)
2 MgO + 4 HCl → 2 MgCl2 + 2 H₂O (multiply Equation 2 by 2)
2 H₂ + O₂ → 2 H₂O (multiply Equation 3 by 2)
2 Mg + O₂ + 4 HCl → 2 MgCl₂ + 2 H₂O (add the above equations)
The enthalpy change of the desired equation can be calculated as follows:
AH = [AH₁ × 2] + [AH₂ × 2] + [AH₃ × (-2)]
AH = [(Answer to #5 -1) × 2] + [(-125 kJ/mol) × 2] + [(-285.82 kJ/mol) × (-2)]
AH = [-457.82 - 2] kJ/mol
AH = -459.82 kJ/mol
Since the value of AH is negative, the formation of MgO is exothermic. This means that energy is released during the formation of MgO.
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What is the mass percent of water in Zn(NO₃)₂ ･ 6 H₂O? Provide an answer to one decimal place.
Suppose of lead(II) acetate is dissolved in of a aqueous solution of ammonium sulfate.
Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the lead(II) acetate is dissolved in it.
The final molarity of the acetate anion in the solution is 0.06148 M.
StepsThe balanced chemical equation for the reaction between lead(II) acetate and ammonium sulfate is:
[tex]Pb(CH_3COO)_2 + (NH_4)_2SO_4 -- > PbSO_4 + 2NH_4CH_3COO[/tex]
So, if we dissolve 1 mole of Pb(CH₃COO)₂, it will produce 2 moles of acetate anion.
Moles of Pb(CH₃COO)₂ = (mass of Pb(CH₃COO)₂) / (molar mass of Pb(CH₃COO)₂)
Assuming the mass of Pb(CH₃COO)₂ is given, let's say it is 5 g, then:
Moles of Pb(CH₃COO)₂ = (5 g) / (Pb(CH₃COO)₂ molar mass)
The molar mass of Pb(CH₃COO)₂ is:
207.2 g/mol (molar mass of Pb) + 2(16.00 g/mol) + 2(12.01 g/mol) = 325.27 g/mol
Substituting the values, we get:
Moles of Pb(CH₃COO)₂ = (5 g) / (325.27 g/mol) = 0.01537 mol
Since 1 mole of Pb(CH3COO)₂ produces 2 moles of acetate anion, the total number of moles of acetate anion in the solution is:
Moles of acetate anion = 2 x 0.01537 mol = 0.03074 mol
We can calculate the final molarity of the acetate anion in the solution:
Molarity of acetate anion = Moles of acetate anion / Volume of solution
Molarity of acetate anion = 0.03074 mol / 0.5 L = 0.06148 M
The final molarity of the acetate anion in the solution is 0.06148 M.
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State two conditions for the reaction in C2H4 +H2O = CH3CH2OH
The reaction between C2H4 (ethylene) and H2O (water) to form CH3CH2OH (ethanol) is a type of hydration reaction. For this reaction to occur, two conditions need to be met:
The presence of a suitable catalyst: The reaction is catalyzed by an acid catalyst, such as phosphoric acid (H3PO4). The acid catalyst helps to break the double bond in C2H4 and promotes the addition of water to form ethanol.
Appropriate reaction conditions:The reaction requires high pressure and temperature to proceed. The typical reaction conditions involve a temperature range of 300-400 °C and a pressure range of 60-70 atm. These conditions are necessary to overcome the high activation energy of the reaction and promote the formation of the desired product, ethanol.
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Suppose that you have a piece of aluminum foil and have
rolled it into a ball. You take another piece of foil the same size and make it into a flat, open box. Then you put both of these
objects in a tub of water. What do you think would happen?
The ball will sink because its weight is greater than the amount of water it displaces. Since their weight is less than the amount of water they displace, objects made of aluminium foil like a boat, paper and cups will float on water.
Why can metal foil that has been rolled into a ball float in water whereas solid aluminium sinks?Whether an item will float or sink in another material depends on its density. If an object's density is lower than the liquid it is placed in, it will float. If an object is heavier than the liquid it is immersed in, it will sink.
While individuals may create their goods or aluminium foils with the aluminium, beating the metal to form aluminium foil is a physical change.
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Look up some everyday objects and the amounts of energy they use or release.
How does this compare to the reaction found via Hess' Law.
Several everyday items, such as incandescent light bulbs (60 joules/s) and gasoline (130 million joules/gallon), use or release energy in varying amounts. Chemical reactions are predicted to change in energy by Hess' Law.
What practical applications of Hess's law exist?The Hess law is most commonly used in business to measure how much energy an engine produces and consumes, as well as in our bodies' responses to food consumption.
What are a few illustrations of Hess law?For instance, carbon and extra oxygen can react to generate carbon dioxide. Directly or indirectly, when carbon and oxygen combine, carbon dioxide is produced, either first as carbon monoxide and later as carbon dioxide.
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what volume of 0.300M would contain 1.5g
(H=1, S=32, O=16
To calculate the volume of 0.300M solution that contains 1.5g of the solute, we need to use the following formula:
moles of solute = mass of solute / molar mass of solute
moles of solute = (1.5g) / (1 x H + 1 x S + 3 x O) g/mol
moles of solute = (1.5g) / (1 + 32 + 3x16) g/mol
moles of solute = (1.5g) / 98 g/mol
moles of solute = 0.015306 moles
Now, we can use the following formula to calculate the volume of the solution:
moles of solute = molarity x volume (in liters)
0.015306 moles = 0.300 M x volume (in liters)
volume (in liters) = 0.015306 moles / 0.300 M
volume (in liters) = 0.05102 L
Finally, we can convert the volume from liters to milliliters (mL):
volume (in mL) = 0.05102 L x 1000 mL/L
volume (in mL) = 51.02 mL
Therefore, 51.02 mL of 0.300M solution would contain 1.5g of solute.
Aqueous hydrochloric acid (HCI) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCI) and liquid water (H2O).
Suppose 30.g of hydrochloric acid is mixed with 14.3g of sodium hydroxide. Calculate the maximum mass of sodium chloride that could be produced by the chemical reaction.
Answer:
Explanation:
The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is:
HCl(aq) + NaOH(s) → NaCl(aq) + H2O(l)
From the balanced equation, we can see that one mole of hydrochloric acid reacts with one mole of sodium hydroxide to produce one mole of sodium chloride and one mole of water.
First, we need to determine which reactant is limiting, i.e., which reactant is completely consumed in the reaction. To do this, we need to compare the number of moles of each reactant, using their respective molar masses:
Molar mass of HCl = 1.008 g/mol (atomic weight of hydrogen) + 35.45 g/mol (atomic weight of chlorine) = 36.46 g/mol
Molar mass of NaOH = 22.99 g/mol (atomic weight of sodium) + 16.00 g/mol (atomic weight of oxygen) + 1.008 g/mol (atomic weight of hydrogen) = 39.99 g/mol
Number of moles of HCl = mass / molar mass = 30.0 g / 36.46 g/mol ≈ 0.823 mol
Number of moles of NaOH = mass / molar mass = 14.3 g / 39.99 g/mol ≈ 0.358 mol
Since the stoichiometric ratio between HCl and NaOH is 1:1, NaOH is the limiting reactant because it has fewer moles than HCl.
Therefore, we can calculate the maximum mass of NaCl that can be produced by the reaction using the number of moles of NaOH:
Number of moles of NaCl produced = number of moles of NaOH used in the reaction = 0.358 mol
Mass of NaCl produced = number of moles of NaCl produced x molar mass of NaCl
Molar mass of NaCl = 22.99 g/mol (atomic weight of sodium) + 35.45 g/mol (atomic weight of chlorine) = 58.44 g/mol
Mass of NaCl produced = 0.358 mol x 58.44 g/mol = 20.9 g
Therefore, the maximum mass of NaCl that can be produced by the reaction is approximately 20.9 g
If 25.0 g of NH₃ and 36.7 g of O₂ react in the following reaction, what is the mass in grams of NO that will be formed?
4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g)
How many grams of H₂0 will be produced if 195.9 grams of Fe
are produced?
O a. 16
O b. 84
O c. 180
O d. 810
Fe3O4 + H₂ → Fe + H₂O
The mass of the water that is going to be produced from the balanced reaction equation is 84 g.
What is the stoichiometry?Stoichiometry is the branch of chemistry that deals with the quantitative relationship between the reactants and products in a chemical reaction. It involves the calculation of the amounts of reactants needed to produce a certain amount of product, or the amount of product produced from a given amount of reactants.
Number of moles of Fe = 195.9 g/56 g/mol
= 3.5 moles
If 3 moles of Fe is produced when 4 moles of water is produced
3.5 moles of Fe is produced when 3.5 * 4/3
= 4.7 moles
Now we have that the mas of water is;
4.7 moles * 18 g/mol
= 84 g
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