Calculate the number of atoms in 0.0340 g Zn.

Answers

Answer 1

Answer:

moles Hg = 25.8 / 200.59 = 0.129

atoms = 0.129 x 6.02 x 10^23 =7.74 x 10^22

Moles Zn = 0.0340 / 65.39 =0.000520

atoms = 3.13 x 10^20

work in the same way : divide the mass by the molar mass and multiply by 6.02 x 10^23

Explanation:

Answer 2

The number of atoms in 0.0340g of Zinc (Zn) is 3.148 × 10²⁰ atoms.

HOW TO CALCULATE NUMBER OF ATOMS:

The number of atoms contained in a substance can be calculated by multiplying the number of moles of that substance by Avogadro's number (6.02 × 10²³). That is;

no. of atoms = no. of moles × 6.02 × 10²³

In this question, we must first convert 0.0340g of Zinc to moles by using the following formula:

no. of moles = mass ÷ molar mass

no of moles = 0.0340g ÷ 65g/mol

no of moles = 5.23 × 10-⁴mol

Hence, the number of atoms in Zinc is as follows:

no of atoms = 5.23 × 10-⁴ × 6.02 × 10²³

no. of atoms = 5.23 × 6.02 × 10²³-⁴

no of atoms = 31.48 × 10¹⁹

no of atoms = 3.148 × 10²⁰ atoms.

Therefore, the number of atoms in 0.0340g of Zinc (Zn) is 3.148 × 10²⁰ atoms.

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Answer:

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Explanation:

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Explanation:

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Answer:

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Answers

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Answers

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Answers

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Answers

Answer:

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Answers

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Answers

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Answers

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