The eagle momentum : 320 kg.m/s
Further explanationGiven
mass = 32 kg
d = 100 m
t = 10 s
Required
The momentum
Solution
The velocity of the eagle :
[tex]\tt v=\dfrac{d}{t}\\\\v=\dfrac{100}{10}=10~m/s[/tex]
The momentum (P) :
[tex]\tt P=m\times v\\\\P=32\times 10\\\\P=320~kg.m/s[/tex]
Engineers were planning to install decorative columns made of marble, of density 2560kg/m cubed, in front of a building. The columns were 2.72m tall and of radius 45 cm
a) Calculate the mass of column
ii) Calculate the pressure exerted by each column on the ground
iii) Engineers found out that the ground beneath the columns would not withstand the pressure calculated in c(ii). Suggest 1 possible change to each column, the engineers do , to solve this problem
Answer:
See the answers below.
Explanation:
We must apply the definition of density which is the ratio of mass to volume.
[tex]Ro=m/v[/tex]
where:
Ro = density = 2560 [kg/m³]
m = mass [kg]
v = volume [m³]
With the column height data and column radius we can calculate the volume, since it resembles the volume of a cylinder. In this way the volume of a cylinder is defined by the following expression.
[tex]V=\pi *r^{2}*h[/tex]
where:
r = radius = 45 [cm] = 0.45 [m]
h = height = 2.72 [m]
[tex]V = \pi *(0.45)^{2}*2.72 \\V = 1.73 [m^{3} ][/tex]
a)
The mass can be calculated as follows.
[tex]m=Ro*V\\m=2560*1.73\\m= 4428.8 [kg][/tex]
ii)
Pressure is defined as the relationship of force over an area.
The area can be calculated with the radius of the cylinder.
[tex]A=\pi *r^{2}\\A = \pi *(0.45)^{2}\\A = 0.636 [m^{2} ][/tex]
Therefore
[tex]P=F/A\\where:\\F=m*g\\F=4428.8*9.81\\F=43446.53[N][/tex]
[tex]P=43446.53/0.636\\P=68312.15[Pa]\\P=68.31[kPa][/tex]
iii)
If the pressure is very large we must analyze the pressure equation again.
[tex]P=\frac{F}{A}[/tex]
We can see that the pressure depends on the strength (weight) and the area of the column. In this way if we increase the value of the area (denominator) we see that the pressure decreases.
If the new Radius is 50 [cm] = 0.5 [m]
[tex]A=\pi *(0.5)^{2}\\A = 0.785 [m^{2} ][/tex]
Now we can calculate again the pressure.
[tex]P=43446.53/0.785\\P=55317.84[Pa]=55.32[kPa][/tex]
We can see the reduction in pressure.
WILL MARK BRAINIEST!!!!!! (Fill in the blanks with the possible answers at the bottom)
1. A Shallow __ is a good indicator of tsunamis, but sends data very slowly and cannot detect earthquakes. *
2. A __ is caused by a sudden shift in the ocean crust which displaces the water. *
3. Tsunamis are common at __ plate boundaries, since large earthquakes release the built up pressure, resulting in a quick vertical movement of the plate. *
4. A tsunamis is possible, but unlikely at a __ plate boundary where two plates are moving sideways past each other. *
5. The Indonesian Earthquake of 2004 had a 9.1__, which was the third largest ever recorded in human history. *
ALL POSSIBLE ANSWERS!!!!
A. Earthquake,
B. Tsunami,
C. Magnitude,
D. Sensor,
E. Transform,
F. Convergent,
G. Divergent.
Answer:
Yet Yeet and Yeeeeeet
Explanation:
a communication satellite is stationed in an orbit high abovr the earth. which of the follwoing will not be exhibeted by communication satellites.
a) rotational motion and periodic motion
b) periodic motion and circular motion
c) rotational motion and rectilinear motion
d) periodic motion and oscillatory motion
i) A and B
ii) B and C
iii) A only
iv) D only
Pls help
Answer:
i think ii)
B and c
i'm note sure though
Rank this objects in order of their acceleration small to larger
Answer:
The answer is "DACB".
Explanation:
The missing data of the question is defined in the attached file please find it.
Using formula:
[tex]\to F= m \cdot a\\\\ \to m= 5 \ kg[/tex]
In object A:
[tex]F= 15 \\\\a =\frac{F}{m} = \frac{15}{5} = 3[/tex]
In object B:
[tex]F= 30 \\\\a =\frac{F}{m} = \frac{30}{5} = 6[/tex]
In object C:
[tex]F= 20 \\\\a =\frac{F}{m} = \frac{20}{5} = 4[/tex]
In object D:
[tex]F= 0 \\\\a =\frac{F}{m} = \frac{0}{5} = 30[/tex]
That's why the answer is "DACB" .
The level of mercury falls in a barometer
while taking it to a mountain.
Answer:
This is due to a relative decrease in atmospheric pressure in high places.
Explanation:
Given that atmospheric pressure decreases at the higher point or ground, this reduced atmospheric pressure, however, will be unable to contain the Mercury in the barometer tube.
Therefore, at the top of the mountain where the air pressure is low, the barometer reading ultimately goes down.
Hence, the level of mercury falls in a barometer while taking it to a mountain "due to a relative decrease in atmospheric pressure in high places."
Which topic are you most likely to find in a physics textbook?
A.
photosynthesis
B.
electricity and magnetism
C.
metals and nonmetals
D.
division of a living cell
E.
ionic, covalent, and metallic bonding
Answer: C. electricity and magnetism
Explanation:
Answer:
B.
electricity and magnetism
is the ans
I find this in physics
A bowling ball with a momentum of 18kg-m/s strikes a stationary bowling pin. After the collision, the ball has a momentum of 13kg-m/s directed 55 degrees to the left of its initial direction as shown below. What is the momentum (magnitude and direction) of the pin's resultant velocity?
Answer:
[tex]14.98\ \text{kg m/s}[/tex]
[tex]45.26^{\circ}[/tex]
Explanation:
[tex]P_1[/tex] = Initial momentum of the pin = 13 kg m/s
[tex]P_i[/tex] = Initial momentum of the ball = 18 kg m/s
[tex]P_2[/tex] = Momentum of the ball after hit
[tex]55^{\circ}[/tex] = Angle ball makes with the horizontal after hitting the pin
[tex]\theta[/tex] = Angle the pin makes with the horizotal after getting hit by the ball
Momentum in the x direction
[tex]P_i=P_1\cos55^{\circ}+P_2\cos\theta\\\Rightarrow P_2\cos\theta=P_i-P_1\cos55^{\circ}\\\Rightarrow P_2\cos\theta=18-13\cos55^{\circ}\\\Rightarrow P_2\cos\theta=10.54\ \text{kg m/s}[/tex]
Momentum in the y direction
[tex]P_1\sin55=P_2\sin\theta\\\Rightarrow P_2\sin\theta=13\sin55^{\circ}\\\Rightarrow P_2\sin\theta=10.64\ \text{kg m/s}[/tex]
[tex](P_2\cos\theta)^2+(P_2\sin\theta)^2=P_2^2\\\Rightarrow P_2=\sqrt{10.54^2+10.64^2}\\\Rightarrow P_2=14.98\ \text{kg m/s}[/tex]
The pin's resultant velocity is [tex]14.98\ \text{kg m/s}[/tex]
[tex]P_2\sin\theta=10.64\\\Rightarrow \theta=sin^{-1}\dfrac{10.64}{14.98}\\\Rightarrow \theta=45.26^{\circ}[/tex]
The pin's resultant direction is [tex]45.26^{\circ}[/tex] below the horizontal or to the right.
The megnitude and the direction of the resultant velocity of the pin willl be 14.98 Kgm/sec and 45.26° below the horizontal or to the right.
What is momentum?The momentum is defined as the product of mass and the velocity of the body. It is denoted by the letter P. It occurs due to the applied force. Its unit is Kg m/s².
The given data in the problem is;
P₁ is the initial momentum of the pin = 13 kg m/s
[tex]\rm p_i[/tex] is the initial momentum of the ball = 18 kg m/s
P₂ is the momentum of the ball after hit
[tex]\rm \theta[/tex] is the angle the pin makes with the horizotal after getting hit by the ball
Momentum in x direction;
[tex]\rm P_i= P_1 cos \theta + P_2 cos \theta \\\\ P_2cos \theta = P_i -P_i cos 55^0 \\\\ P_2cos \theta = 10.54 \ Kgm/s[/tex]
Momentum in y direction;
[tex]\rm P_i sin\theta = P_2 sin\theta \\\\ P_2 sin\theta =13 sin 15^0 \\\\ P_2 sin\theta =10.64 \ kgm/sec[/tex]
[tex](P_2 cos \theta )^2 + (P_2 sin \theta)^2 = P_2^2 \\\\ \rm P_2 = \sqrt{(10.54)^} +(10.64)^2[/tex]
[tex]\rm P_2 = 14.98 \ kgm/sec[/tex]
The direction of the resulatnt velocity is find as;
[tex]P_2 sin\theta = 10.64 \\\\ \theta = sin^{-1 } \frac{10.64}{14.98} \\\\ \theta=45.26^0[/tex]
Hence the megnitude and the direction of the resultant velocity of the pin willl be 14.98 Kgm/sec and 45.26° below the horizontal or to the right.
To learn more about the momentum refer to the link;
https://brainly.com/question/4956182
Why are we unable to work long without food
Answer:
Without food your not able to produce energy thats why you cannot work so long
newtons law of gravitation is called a universal law why
Answer:
it is applicable on all bodies having mass and the bodies Will be governed by the same law
Light is one form of energy that travels in electromagnetic waves. This energy is both (1)
and
electrical. There are many different types of electromagnetic (EM) waves. Most of them cannot be seen by humans.
Our eyes see only a small (2)
of EM waves called visible light Visible light is made up of different colors
The colors are red, orange, yellow, green, blue, indigo, and violet. The colors are due to the different (3)
of
light. The (4)
the wavelength, the less energy the wave has. The shorter the wavelength, the more energy
it has. The (5) wavelength of visible light looks red to us the shortest (6)
of visible light looks
vlolet to us
Answer:
Explanation:
Electromagnetic waves are formed by the interference of both electric and magnetic fields. These include: Microwaves, Radio waves, Infrared, Visible, Ultraviolet, X-ray, and gamma rays. These waves can be arranged in a specific order (called spectrum) with respect to their wavelength or frequency. The higher the wavelength, the lower the frequency. And vice versa.
These waves are transverse, and travels at the same speed (speed of light - 3.0 x [tex]10^{8}[/tex] m/s).
In the given question, the answers are:
1 - Magnetic
2 - Region
3 - Refractive indices
4 - Greater
5 - Higher
6 - Wavelength
Calculate the momentum of a 5 kg ball in free fall at 20 m/s. Show your work.
Answer:
100kgm/s
Step by step solution:
mass(m) = 5kg
Initial velocity (u) = 0
i.e u = 0 for free fall
Final velocity (v) = 20m/s
Momentum = m(v - u)
= 5(20 - 0)
= 5(20) = 100kgm/s.
Answer:
[tex]\boxed {\boxed {\sf 100 \ kg*m/s}}[/tex]
Explanation:
Momentum can be found using the following formula.
[tex]p=mv[/tex]
where p is the momentum, m is the mass, and v is the velocity.
1. Define Variables
The mass is 5 kilograms and the velocity is 20 meters per second.
[tex]m= 5 \ kg \\v= 20 \ m/s[/tex]
2. Calculate Momentum
Substitute the values into the formula.
[tex]p= 5 \ kg * 20 \ m/s[/tex]
Multiply.
[tex]p= 100 \ kg*m/s[/tex]
The momentum of the ball is 100 kilograms meters per second.
Why do clownfish rarely go far from their home
Answer:
In the wild, clownfish rarely leave their anemone home. In fact, part of its purpose is to defend the anemone from other fish. However, clownfish bred in aquariums (without an anemone home) may still have this instinct, but it’s much calmer than wild harvested species.
Explanation:
If the distance of a force arm (FA) is 4 feet and the resistance arm (RA) is 2 feet, then the mechanical advantage would be
Answer: 2
Explanation:
From the question, we are informed that the distance of a force arm (FA) is 4 feet and the resistance arm (RA) is 2 feet.
Based on the information given, the mechanical advantage would be calculated as:
= Force Arm / Resistance Arm
= 4 feet / 2 feet
= 2
A 2000 kg roller coaster is at the top of a loop with a radius of 24 m. If its speed is 18 m/s at this point, what force does it exert on the track
Answer:
[tex]46620\ \text{N}[/tex]
Explanation:
m = Mass of roller coaster = 2000 kg
r = Radius of loop = 24 m
v = Velocity of roller coaster = 18 m/s
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Normal force at the point will be
[tex]N-mg=\dfrac{mv^2}{r}\\\Rightarrow N=\dfrac{mv^2}{r}+mg\\\Rightarrow N=\dfrac{2000\times 18^2}{24}+2000\times 9.81\\\Rightarrow N=46620\ \text{N}[/tex]
The force exerted on the track is [tex]46620\ \text{N}[/tex].
A person rides in an elivator. What is the equal and opposite force for the force of the elevator floor pushing up on the person as described by Newton’s third law?
Answer:
weight of the person and reaction force according to that weight by the elevator
every action has an equal and opposite reaction
Weight of the person and reaction force according to that weight by the elevator is balanced.
What is Newton's third law?According to the third law, when two objects interact, they exert equal-sized and opposite-direction forces upon one another.
A person rides in an elivator then the equal and opposite force for the force of the elevator floor pushing up on the person as described by Newton’s third law and are balanced.
Weight of the person and reaction force according to that weight by the elevator is balanced.
To learn more about force refer to the link:
brainly.com/question/13191643
#SPJ5
help pls physics problem
Answer:
0.4329 seconds
Explanation:
We are given;
Distance; d = 0.635 m
Velocity; v = 3.22 m/s
Angle; θ = 62.9°
To find the time, we have to find the horizontal component of the velocity.
Thus, Vx = 3.22 × cos 62.9
Formula for time is;
t = d/Vx
t = 0.635/(3.22 × cos 62.9)
t = 0.4329 sec
Thus the time he will take to clear the hurdle is 0.4329 sec
A -0.6 C charge that moves downward is in a uniform electric field with a strength of 200 N/C what is the magnitude and direction of the force on the charge
Answer:
The magnitude and direction of the force on the charge is 120 N in the direction of the charge.
Explanation:
Given;
magnitude of the charge, q = 0.6 C
electric field strength, E = 200 N/C
The magnitude of the electric force is calculated as;
F = Eq
where;
F is the magnitude of the force
Substitute the given values and solve for F;
F = (200)(0.6)
F = 120 N in the direction of the charge.
Therefore, the magnitude and direction of the force on the charge is 120 N in the direction of the charge.
A bullet has a speed of 500 m/s as it leaves a rifle. If it is fired horizontally from a cliff 12m above a lake, how far does the bullet travel before striking the water?
help me please ASAP
Answer:
F = 1200 [N]
Explanation:
Torque is defined as the product of force by Radius.
[tex]T=F*r[/tex]
where:
T = torque = 300 [N*m]
r = radius = 50/2 = 25 [cm] = 0.25 [m]
[tex]F=T/r\\F = 300/0.25\\F = 1200 [N][/tex]
Which of the following are possible units for a spring constant?
A. J/m
B. cm/N
C. J/N
D. N/km
Answer:
D
Explanation:
The standard international (SI) unit for spring constant is N/m, so N/km is the same thing but bigger.
A runner went from 6 m/s and two seconds what was his acceleration
Answer:
is it 3?
Explanation:
Im taking a guess and just dividing 6 and 2
What equation do I use?
Answer:
I think it's the 3rd one
If someone tells u somethin else, go for it cause im not 100% sure...
A student attempted to measure the specific latent heat of vaporisation of water.
She took the following readings:
First balance reading (g) = 581
Second balance reading (g) = 526
First joulemeter reading (kJ) = 195
Second joulemeter reading (kJ) = 327
Use these results to determine the specific latent heat of vaporisation of water.
Answer:
The latent heat of vaporization of water is 2.4 kJ/g
Explanation:
The given readings are;
The first (mass) balance reading (of the water) in grams, m₁ = 581 g
The second (mass) balance reading (of the water) in grams, m₂ = 526 g
The first joulemeter reading in kilojoules (kJ), Q₁ = 195 kJ
The second joulemeter reading in kilojoules (kJ), Q₂ = 327 kJ
The latent heat of vaporization = The heat required to evaporate a given mass water at constant temperature
Based on the measurements, we have;
The latent heat of vaporization = ΔQ/Δm
∴ The latent heat of vaporization of water = (327 kJ - 195 kJ)/(581 g - 526 g) = 2.4 kJ/g
The latent heat of vaporization of water = 2.4 kJ/g
A piece of wood 400N in weight and 50cm X 30cm X 20cm in size lies on 50cm X 20cm face. Calculate the pressure exerted by it.
Answer:
P = 4000 [Pa]
Explanation:
Pressure is defined as the relationship between Force and the area where the body rests.
The support area is equal to:
[tex]A=50*20=1000[cm^{2} ][/tex]
But we must convert from square centimeters to square meters.
[tex]1000[cm^{2}]*\frac{1^{2}m^{2} }{100^{2}m^{2} }=0.1[m^{2} ][/tex]
And the pressure is:
[tex]P=\frac{F}{A} \\P=400/0.1\\P=4000[N/m^{2} ]or 4000[Pa][/tex]
While helping a friend move, you lift a 176 N box full of books and perform 180 J of work to do so. What distance, directly upward, do you lift the box? Show all your work.
Answer:
d = 1.022 [m]
Explanation:
Work in physics is defined as the product of force by distance. In this way we have the following expression.
[tex]W=F*d[/tex]
where:
W = work done = 180 [J] (units of Joules)
F = force = 176 [N]
d = distance [m]
[tex]d = W/F\\d = 180/176\\d = 1.022 [m][/tex]
The acceleration due to gravity is zero at the
Answer:
the center of the earth
14. A 3.0 kg metal ball, at rest, is hit by a 1.0 kg metal ball moving at 4.0 m/s. The 3.0 kg ball moves
forward at 2.0 m/s and the 1.0 kg ball bounces back at 2.0 m/s.
(a) What is the total kinetic energy before the collision?
Answer:
The kinetic energy before the collision was 8 J
Explanation:
The given parameters are;
The mass of the metal ball at rest, m₁ = 3.0 kg
The velocity of the ball at rest = 0 m/s
The mass of the metal ball that hits the one at rest, m₂ = 1.0 kg
The velocity of the metal ball that hits the one at rest, v₂ = 4.0 m/s
The velocity with which the 3.0 kg ball moves forward = 2.0 m/s
The velocity with which the 1.0 kg ball bounces back = 2.0 m/s
a) Kinetic energy, K.E. = 1/2 × m × v²
Where;
m = The mass of the of the object in motion
v = The velocity of the object
Before the collision, we have;
Initial K.E. = 1/2 × m₁ × v₁² + 1/2 × m₂ × v₂²
∴ Initial K.E. = 1/2 × 3.0 kg × (0 m/s)² + 1/2 × 1.0 kg × (4.0 m/s) ² = 8 J
The kinetic energy before the collision = The initial K.E. = 8 J.
We gonna make the girls dance
I ain't lookin' for enemies
But I ain't playin' n*ce
The way you testing me and look me in the eyes
Want some of my own candy
I love to see you try
Ain't nothing real about the way you look tonight
Answer:
Definition: poem
Explanation:
A piece of wood 400N in weight and 50cm X 30cm X 20cm in size lies on 50cm X 20cm face. Calculate the pressure exerted by it.
Answer:
4kPa
Explanation:
P = force/area
= 400/(0.5×0.2)
= 4000Pa(4kPa)
Answer:
4000pascal
Explanation:preassure = force/area
F = 400N
A = 50cmx 20cm = 1000 cm sq
so we have to convert the area in metre square
so when convert we get the answer 1/10 = 0.1m square
now as per the equation of preassure we have to divide 0.1/400
and then we get the answer 4000pascal.
A 10 g bullet accelerates to 400 m/s after being fired from a gun with a mass of 2.0 kg.
(i) What is the momentum of the bullet?
(ii) What is the momentum of the gun?
(iii) What is the velocity of the recoiling gun?
Answer:
See the answers below.
Explanation:
Momentum is defined as the product of mass by velocity, and can be calculated by means of the following expression.
[tex]P=m*v[/tex]
where:
P = Momentum [kg*m/s]
m = mass = 10 [g] = 0.01 [kg]
v = velocity = 400 [m/s]
i)
[tex]P=0.01*400\\P=4[kg*m/s][/tex]
ii)
The momentum of the gun is equal to zero, because it does not move before being fired, the weapon only moves after having fired the weapon.
[tex]P_{gun}=0[/tex]
iii)
Since the momentum is conserved before and after the shot, the same momentum given to the bullet is equal to the momentum received by the gun.
[tex]P=m*v_{recoil}[/tex]
[tex]v_{recoil}=P/m\\v_{recoil}= 4/2\\v_{recoil}=2[m/s][/tex]