Ranking each of the following from least to greatest in terms of the amount of momentum each possesses:
A 5 kg object moving at -25 m/s < A 100N object moving at 5 m/s < A 10kg object moving at 10 m/s < A 30 kg moving at 5 m/s
What is momentum?Momentum is the product of a particle's mass and velocity. The fact that momentum is a vector quantity means that it has both magnitude and direction. The force pushing a particle has an equal-and-opposite impact on the speed at which its momentum changes, according to Isaac Newton's second law of motion. Take a look at Newton's laws of motion.
Newton's second law states that if a particle experiences a constant force for a predetermined period of time, the impulse—which is equal to the force multiplied by the duration—will equal the change in momentum. The amount of time required for a consistent force to bring a particle to rest, in contrast, is measured by a particle's momentum.
We know that momentum, p = mv
Where,
p = momentum
m = mass
v = velocity
Substituting the value in formula we get,
1. A 10kg object moving at 10 m/s
p = 10 × 10
= 100 kg⋅m/s
2. A 30 kg moving at 5 m/s
p = 30 × 5
= 150 kg⋅m/s
3. A 5 kg object moving at -25 m/s
p = 5 × -25
= -125 kg⋅m/s
4. A 100N object moving at 5 m/s
p = (100 × 0.10197 kg) × 5
= 10.197 × 5
= 50.985 kg⋅m/s
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A 0.480 kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change the period to 2.05 s
The mass added to the object to change the period to 2.05 s is 0.42 kg
What is the time period of an oscillation?
The time taken for an oscillating particle to complete one cycle of oscillation is known as the Period of oscillating particle.
Given :
A 0.480-kg mass suspended from a spring oscillates with a period of 1.50 s.
The formula of the time period is given by:
[tex]T=2\pi \sqrt{m/K}[/tex] ------(1)
where m is the mass and K is the spring constant.
The new time period is given by:
[tex]T'=2\pi \sqrt{m^{'} /K[/tex]-----(2)
where m' is the total mass after the addition and K is the spring constant.
Dividing equation (1) by equation (2).
[tex]T/T'=\sqrt{m/m'}[/tex]
Now, substitute the known terms in the above expression.
[tex]\frac{1.50}{2.05} =\sqrt{0.480/m'}[/tex]
[tex]m'=\frac{0.480}{0.5329}[/tex]
[tex]m'=0.9[/tex] kg
Now, the mass added to the object to change the period to 2.05 s is given by:
m" = 0.9 - 0.480
m" = 0.42 Kg
Thus, 0.42kg of mass must be added to the object to change the period to 2.05s.
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A standing wave is set up in a pipe with both ends open. The frequency of its first harmonic is 300 Hz. What is the length of the pipe? Take the speed of sound to be 340 m s–1. Give your answer in meters
When the frequency of a standing wave set up in a pipe (with both ends open) first harmonic is 300 Hz, the length of pipe is 0.567 metres.
Therefore the answer is 0.567 m.
The speed of sound in air is approximately 340 m/s, and the wavelength of the first harmonic of a standing wave in an open pipe is twice the length of the pipe. Therefore, if the frequency of the first harmonic is 300 Hz, the wavelength can be calculated as:
wavelength = speed of sound / frequency
wavelength = (340 m/s) / (300 Hz)
The length of the pipe can be calculated as half the wavelength:
L = wavelength/2
L = (340 m/s) / (2×300 Hz)
L ≈ 0.567 m
So the length of the pipe is 0.68 m
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A point particle of charge -5.40 nC is located at the origin of a Cartesian coordinate system. Determine the magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge.
The magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge is 918.7 N/C.
Given that,
Charge on point particle Q = -5.4 nC = -5.4 × 10⁻⁹ C
Distance from the charge r = 23 cm = 23 × 10⁻² m
The relation between distance charge and electric field is known to be,
E = 1/4πε₀ × Q/r² = 9 × 10⁹ × (-5.4 × 10⁻⁹)/(23 × 10⁻²)² = (9 × 5.4)× 10⁴/(23)² = 918.7 N/C
Thus, the magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge is calculated to be 918.7 N/C.
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Classify the phase-change scenarios according to the direction of the heat flow in each case. No net transfer of heat occurs Heat is transferred from the water to the surroundings Heat is transferred to the water from the surroundings
When working through these problems, think about the heat in terms of movement of the molecules of water.
Heat is transferred from the water to the surroundings --- water molecules slowing down.
Heat is transferred to the water from the surroundings --- water molecules heating up.
a cloud of steam condenses into liquid water - Heat is transferred from the water to the surroundings. Steam has more molecules moving around than liquid water. Therefore the molecules had to slow down, thereby transferring heat to the surroundings.a block of ice sublimates into water vapor - Heat is transferred to the water from the surroundings --- water molecules are heating upa block of ice melts - Heat is transferred to the water from the surroundings. The water molecules are basically not moving. Therefore heat has to be introduced to the molecules, which causes the melting.a puddle of water evaporates - Heat is transferred to the water from the surroundings. The water molecules are moving in the liquid state. However, when more heat is introduced to the liquid, the molecules move more rapidly and evaporate.a puddle of water freezes into ice - Heat is transferred from the water to the surroundings --- water molecules slowing down as they go from a liquid state to a solid state. ABOUT HEAT TRANSFERHeat transfer is the transfer of energy due to the difference of temperature between two different places. The main discussion in heat transfer is how the energy in heat can move places and the rate of transfer under certain conditions. Heat transfer includes the processes of inflow and outflow of heat. In industrial processes, heat transfer is used to achieve the required temperature in the industrial process and maintain the required temperature throughout the process.
Heat transfer from one object to another can occur by conduction, convection, and radiation. The determinant of heat transfer is the temperature difference. The direction of heat transfer starts from a medium with a high temperature to a medium with a lower temperature. Heat transfer can occur with a single process or multiple processes.
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Calculate the rotational kinetic energy of a 12-kg motorcycle wheel if its angular velocity is 120 rad/s and its inner radius is 0.280 m and outer radius 0.330 m.
According to the question the rotational kinetic energy of a 12-kg motorcycle wheel is 809.14 J
What does rotational kinetic energy?The SI unit for rotational kinetic energy is the joule (J). The rotating kinetic energy formula has a similar structure to a translational kinetic energy equation. Kinetic energy is created by spinning objects around an axis. This type of energy is influenced by the object's mass, weight, and center of mass angle with respect to the axis.
Given data -
Mass = 12-kg
Angular velocity (ω) -120rad/s
inner radius = 0.280 m
outer radius = 0.330 m.
By using the formula
I = ½*M (r1² + r2²)
I = ½ *(12) * (0.2802 + 0.3302)
I = 1.1238 Kgm2
K.E = ½*Iω2
K.E = ½ * (1.1238)*(120)2
K.E = 809.14 J
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CAN SOMEONE PLEASE ANSWER THESE 4 QUESTIONS I WILL NEED IT IN A FEW HOURS , YOU WILL GET BRAINLIEST!!
1.) Compare reflection and refraction. How are they similar and how are they different?
2.) In your own words, describe how ray diagrams can be used to describe if light rays are being reflected or refracted.
3.) What is the formula for the Law of Reflection? Define the variables and explain what it tells us about the motion of light.
4.) What is the formula for Snell's? Define the variables and explain what it tells us about the motion of light.
Answer:
1.)Reflection is the act of light reflecting back when it hits a medium on a plane. Refraction is the process by which light shifts its path as it travels through a material, causing the light to bend. Thus, this is the key difference between reflection and refraction. This phenomenon usually occurs in mirrors.
2.)ray diagrams are a visual representation of the propagation of light. They can help us to understand and visualise multiple situations, such as light being reflected off of a mirror or changing its direction while moving through a lens.
3.)Reflection: The process of sending back the light rays which fall on polished surface is called reflection of light.
Laws of reflection:
(i) The angle of reflection is always equal to the angle of incidence.
(ii) The incident rays, reflected rays and the normal, all lie in the same plane.
4.)Snell’s law formula is expressed as: μ= sin i/sin r
, where i is the angle of refraction, r is the angle of refraction and μ is known as the refractive index of the second medium with respect to the first medium.
Which of the following is the law of action-reaction?
OA. Newton's first law
B. Newton's second lav
OC. Newton's third law
OD. Newton's fourth law
Answer:
OC.Newton's third law of motion which states that,"every action has equal and opposite reaction."
*mark me brainliest
Mercury thermometer is not suitable to measure the temperature of very cold place. Why?
The use of a mercury thermometer is not suitable for the purpose of determining the temperature of extremely cold ice because at such low temperatures, mercury transforms into a translucent state, making it impossible to read.
Another reasons why mercury thermometer is not suitable to measure the temperature of the very cold place are:
Since mercury freezes at a temperature of -38.83 degrees Celsius, a mercury thermometer will not work in extremely cold temperatures. We are unable to use a thermometer that contains mercury at low temperatures because the glass could shatter at those temperatures.The body whose temperature we are measuring with the thermometer does not radiate heat in the opposite direction.When exposed to low temperatures, mercury takes on a transparent appearance, making it more challenging to obtain accurate readings.To learn more about mercury thermometer, click here:
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You can tell from reading this passage that -
the narrator will definitely find a diamond at the Crater of Diamonds State Park.
diamonds are rare, valuable gems.
garnet is as valuable as a diamond.
semi-precious stones are ugly.
Answer: B or "diamonds are rare,valuable gems".
Explanation:
since the link does not show very much, I don't know if A is correct or not. D is incorrect because that is an opinion. C is incorrect.
Runner A is initially 2.0 mi west of a flagpole and is running with a constant velocity of 8.0 mi/h due east. Runner B is initially 9.0 mi east of the flagpole and is running with a constant velocity of 4.0 mi/h due west. How far are the runners from the flagpole when they meet?
The definition of constant velocity is the speed of a moving object that doesn't change over time. The system travelling at a constant speed is subject to zero net acceleration.
What distinguishes instantaneous velocity from average velocity?In contrast to instantaneous velocity, which is determined by slope of tangent line, average speed is defined as the shift in location (or displacement) during the course of transit.
Which of the four main claims about how a body can accelerate even when it has no velocity is untrue?Speed is the measure of velocity in magnitude. As a result, it is impossible to have two objects moving at the same velocity. The right response is therefore option A.
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Trends are easier to detect when the signal-to-noise ratio is low.
a True
b False
Answer:
I think it's b. False
Explanation:
A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 34.5 m/s. With what maximum speed can it go around a curve having a radius of 60.0 m
With 20.23 ms⁻¹, maximum speed can it go around a curve having a radius of 60.0 m
What's the maximum speed?The highest rate of speed a person can reach is called maximum speed. When athletes alter the magnitude (how quickly they are moving) or direction (or both) of their motion, or both, their acceleration changes as well since acceleration is related to velocity, which has both a magnitude and a direction connected with it.
ac max = V² max / R ....(1)
Inserting given values we get
ac, max = (34.5)² / 150 = 7.935 ms⁻²
For a changed radius of the curve of 60.0 m, the maximum safe speed from (1) becomes
Unew, max= √ac, max R new
Unew, max = √6.826 x 60
Unew, max 1 = 20.23 ms⁻¹, rounded to one decimal place.
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a typical gps satellites orbit at an altitude of 2.0 x10^7 m. find (a) the orbital period, and (b) the orbital speed of such a satellite
the orbital period is 7200sec or 2hours and orbital speed is 7,27m/s
(a) The orbital period of a satellite is the time it takes for the satellite to make one full orbit around the Earth. To calculate the orbital period, we can use the equation: T = 2 * pi * (a^3/GM)^(1/2) where T is the orbital period, a is the semi-major axis of the orbit (which is equal to the altitude of the satellite), pi is approximately 3.14, G is the gravitational constant (approximately 6.67 x 10^-11 m^3/kgs^2), and M is the mass of the Earth (approximately 5.98 x 10^24 kg).Plugging in the given altitude of 2.0 x 10^7 m for a and the known values for pi, G, and M, we get:
T = 2 * pi * (2.0 x 10^7 m)^3/ (6.67 x 10^-11 m^3/kgs^2 * 5.98 x 10^24 kg)^(1/2)
Simplifying, we get:
T = 2 * pi * (8.0 x 10^21 m^3/ (4.03 x 10^34 kg*m^3/s^2))^(1/2)
T = 2 * pi * (1.98 x 10^13 s^2/kg)^(1/2)
T = 7200 sec (or 2 hours)
(b) The orbital speed is the distance traveled by the satellite in one hour. We can calculate the orbital speed using the equation v = 2πa/T
Plugging in the values of a and T we get :
v = 2π (2.0 x 10^7 m) / 7200 sec
v = 7,27 m/s
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What is momentum Mcq?
L=rp Angular Momentum the linear momentum p. Moment of momentum is another name for angular momentum.
How do you gain traction?List the object's mass and speed in step one. Convert any values into SI units in step two (kg, m, s). Step 3: To calculate an object's momentum, multiply the object's mass and velocity.
Can there be negative momentum?Momentum can go wrong. As a vector quantity with both magnitude and direction, momentum has both. The sign, positive or negative, in physics serves as a cue as to the direction. Positive amounts normally signify a forward or upward motion, whereas negative quantities typically indicate a backward or downward motion.
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What is momentum?
What are some benefits of dynamic exercises prior to playing volleyball how it will prepare your body leading to the game?
The benefits of dynamic exercises before playing volleyball and how they will prepare your body for the match are:
Increased Muscle Strength and PowerImproved Mobility and FlexibilityImproved Agility and Reaction TimeImproved Balance and CoordinationImproved Cardiovascular EnduranceExplanation of each of the benefits of dynamic exercises before playing volleyball and its preparationIncreased Muscle Strength and Power: Dynamic exercises help to increase muscle strength and power, which is essential for performing explosive movements required in volleyball.Improved Mobility and Flexibility: Dynamic exercises help to improve mobility and flexibility, which can help to reduce the risk of injury.Improved Agility and Reaction Time: Dynamic exercises help to improve agility and reaction time, which can help you to react quickly and effectively to the game.Improved Balance and Coordination: Dynamic exercises also help to improve balance and coordination, which can help you to perform better and avoid unnecessary injuries.Improved Cardiovascular Endurance: Dynamic exercises help to increase your cardiovascular endurance, which can help you to last longer during the game and maintain high intensity throughout.Learn more about dynamic stretching:
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The direction of the velocity of the planet is _______________________ (alwaysThe direction of the velocity of the planet is _______________________ (always, seldom, never) perpendicular to the net force acting upon the planet., seldom, never) perpendicular to the net force acting upon the planet.
According to the satellites' orbits and the speed at which they move, it either happens frequently or always.
As we begin to examine satellite orbits, we find that a circular orbit places the satellite always perpendicular to the object's net force and speed.
The orbit is stretched, just like in elliptical orbits. This informs us that the orbit has four points. As a result, the satellite rarely faces the satellite's net force in a perpendicular direction.
Rarely and always for elliptical orbits. According to the satellites' orbits and the speed at which they move, it either happens frequently or always.
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A net force of 10 newtons accelerates an object at 5.0 meters per second^2. What net force would be required to accelerate the same object at 1.0 meters per second^2
The proper answer is that a force of 16 N net would be needed to accelerate the same item at 1.0 m/s2.
How is the net force needed to accelerate calculated?Newton's second law of motion condenses these relationships. The answer to the acceleration equation above can be written as Net Force = Mass Acceleration, or F = m a.
You know that force(F) & acceleration(a) are connected through mass(m),
F=ma
Here you have:
10 = 5 m
so, m = 10/5 = 2 Kg
Then if you have a = 8 m/s^2
you get:
F=2×8=16 N
Force = 16N
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Y’all which ones is incorrect (if there wrong plz tell me what to circle right then) thanks :3
WILL MARK BRAINLIEST FOR THIS :D
How do you find the acceleration of a ball rolling down a slope?
The ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.
Rolling motion of any object occurs when the object starts sliding in a different methods from the other objects such as when the objects starts to roll from the ramp or any other sloppy surface and it rolls down due to the gravitational force and with many other forces such as the rolling tangential force. many forces are acting on the object at the same moment and we are just seeing the gravitational force which is playing a major portion. Hence by this information we can consider that the ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.
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Una atracción de feria consiste en lanzar un trineo de 2 kg por una rampa ascendente que forma un ángulo de 30º con la horizontal. Si el coeficiente de rozamiento es 0,15 ¿con qué velocidad hay que lanzar el trineo para que ascienda 4 m por la rampa?
Answer:
La velocidad con la que se debe lanzar el trineo es aproximadamente 9.96 m/s
Explanation:
La masa del trineo, m = 2 kg
El ángulo de inclinación del trineo, θ = 30 °
El coeficiente de fricción, μ = 0,15
La altura a la que debe ascender el trineo, h = 4 m
La reacción normal del trineo en la rampa, N = m · g · cos (θ)
La fuerza de fricción [tex]F_f[/tex] = N × μ
Dónde;
g = Th aceleración debida a la gravedad ≈ 9.81 m/s²
∴ [tex]F_f[/tex] = 0.15 × 2 kg × 9.81 m/s² × cos (30°) ≈ 2.55 N
La longitud de la rampa que se mueve el trineo, l = h/(sin(θ))
∴ l = 4/(sin(30°)) = 8
La longitud de la rampa que se mueve el trineo, l = 8 m
El trabajo realizado sobre la fricción, [tex]W_f[/tex] = [tex]F_f[/tex] × l
[tex]W_f[/tex] = 2.55 × 8 ≈ 20.4
El trabajo realizado sobre la fricción, [tex]W_f[/tex] ≈ 20.4 Julios
El trabajo realizado para levantar el trineo a 4 metros de altura, P.E. = m·g·h
∴ P.E. = 2 kg × 9.81 m/s² × 4 m ≈ 78.48 Joules
El trabajo realizado para levantar el trineo a 4 metros de altura, P.E. ≈ 78.48 Joules
El trabajo total requerido para levantar el trineo 4 metros por la rampa, [tex]W_t[/tex] = [tex]W_f[/tex] + P.E.
[tex]W_t[/tex] = 20.4 J + 78.84 J ≈ 99.24 J
Energía cinética, K.E. = 1/2 × m × v²
La energía cinética necesaria para mover el trineo por la rampa, K.E. se da de la siguiente manera;
K.E. = 1/2 × 2 kg × v² ≈ 99.24 J
∴ v² ≈ 99.24 J/(1/2 × 2 kg)
La velocidad con la que se debe lanzar el trineo para que ascienda 4 metros por la rampa, v ≈ 9.96 m/s
At an outdoor physies demonstration, a delay of 0.50 second was observed between the time sound waves left a loudspeaker and the time these sound waves reached a student through the air. If the air is at STP, how far was the student from the speaker? (1) 1.5 × 10-m (91.7 × 102 m (3) 6.6 × 10? m (4) 1.5 × 108 m
The distance that is covered by the sound is 1.66 * 10^2 m.
What is the distance?We know that sound is a mechanical wave. The implication of this is that sound woulod need to have a medium through which the sound can be able to travel. The speed of sound in the various media through which the sound travels is not the same.
We know that the speed of sound in air is 331 m/s and we have to use this in our calculations.
Distance = speed * time
Distance = 331 m/s * 0.5 s
= 1.66 * 10^2 m
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If the refractive index from air to water, nw = 1.3 and the velocity of light in the air is
3 x 108 m/s, what is the velocity of light in water?
Answer:
[tex]n _{w} = \frac{c}{v} \\ 1.3 = \frac{3 \times {10}^{8} }{v} \\ v = \frac{3 \times {10}^{8} }{1.3} \\ v = 2 \times {10}^{8} \: m {s}^{ - 1} [/tex]
How do scientists collect evidence about Earth's climate?
"Scientific evidence for warming of the climate system is unequivocal."
What evidence can be used to study the Earth's past climate?Organisms such as diatoms, forams, and coral) can obey useful climate proxies. Other proxies involve ice cores climate, tree rings, and sediment cores. Chemical deputy records include isotope ratios, elemental examination, biomarkers, and biogenic silica.
Climate analyzers use every possible direct and indirect compilation to study the full history of Earth's climate, ice cores drawn from Greenland, Antarctica, and tropical mountain glaciers appear that Earth's climate greets to changes in greenhouse gas levels.
So we can conclude that Climate change is most usually measured using the average surface temperature of the planet.
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How much of the world's energy is hydroelectric?
According to the United Nations Environment Programme, hydropower accounted for 16.6% of global electricity generation in 2018.
This is equivalent to a total installed capacity of 706 GW, making it the second largest energy source after thermal sources.
Hydropower is a renewable energy source and is often seen as a more sustainable alternative to thermal sources, as it does not release any greenhouse gases into the atmosphere. Additionally, hydropower is a reliable source of energy, and can be used to meet peak energy demand.
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After seeing the fur rubbed with the rod attract the neutral paper, imagine you had an instrument that lets you zoom in enough to see what the paper and rod are made of. Draw a model that shows what happens to the neutral paper to cause it to move towards the charged rod. Make sure to label everything in your model
Seeing the fur rubbed with the rod attracts neutral paper, this happens because the friction of the rod with the rubbed can produce a static electric force. It is this static electric force that causes the pieces of paper to be attracted and rod up.
If the rod or ruler has been rubbed into the hair, then brought closer to the paper, then the paper will lift and stick. Indeed, this can happen due to the presence of an electric charge. When you rub a plastic ruler over your hair, it becomes electrically charged, causing the paper to pull and stick.
The electric charge consists of two types of charge, namely negative charge, and positive charge. However, some objects have an equal amount of negative charge and positive charge. Objects that have the same amount of positive and negative charges are called neutral objects. Initially, a plastic ruler is also an electrically neutral object.
When you rub the ruler against dry hair, it gets an electric charge, because of that electric charge the plastic ruler can exert a force on the paper and pull it closer.
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Because of the Doppler effect, a light- or sound-emitting object moving toward you has a ________ compared to a stationary object.
Because of the Doppler effect, a light- or sound-emitting object moving toward you has a lower amplitude compared to a stationary object.
The Doppler effect is generally defined as the shift in wave frequency (whether it be sound or light) caused by relative motion between the wave source and the observer. Every time a source wave moves in reference to the observer, this effect can be seen.
The Doppler effect allows astronomers to determine the frequency of light waves as an object moves in relation to the observer. As it approaches you, the frequency decreases and the item exhibits a blueshift. A redshift indicates that an item is travelling away from us.
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Wilbur ran 1-kilometer. Then he ran 500 meters. How many meters did Wilbur run all together?
A) 15,000
B) 1,500
C) 1000
D) 150
X-rays with wavelengths of 0.95 nm are detected at a scattering angle of straight theta in a Compton-scattering experiment, as shown in the drawing. What is the scattering angle straight theta if the energy of the scattered photon is 5.111 keV. (For accuracy, use h = 6.626 x 10-34 J·s and c = 2.998 x 108 m/s.)
Answer:
The scattering angle is 0.80
Explanation:
As we know
Wave length = h/mc (1-cos α) --1
W = mc^2
m = E/c^2
Substituting this in equation 1 we get
Wavelength = hc/E (1-cos α)
Substituting the given values, we get -
0.95*10^-9 = [(6.626 *10^-34 * 2.998 *10^8)/5.111*1000*1.6*10^-19} (1-cos α)
(1-cos α) = 1.14 *10^-10
cos α = 1- 1.14 *10^-10
α = 0.80
Roller Coaster Physics Gizmo
With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the bottom of this hill from its starting height. To do this start by setting the kinetic and potential energy equations equal to one another. K= U
1/2mv^2 = mhm
a. Use algebra to solver for the speed. V=
b. With the no friction, does the final speed depend on the mass of the car?
c. With no friction, does the final speed depend on the steepness of the hill?
d. What is the final speed of the car if the height of the hill is 55 cm (. 55m)?
A) Using algebra, the required speed V=(2gh)1/2
B) With the no friction, the final speed does not depend on the mass of the car.
C) With no friction, the final speed does depend on the steepness of the hill.
D) The final speed of the car if the height of the hill is 55 cm is 3.569 m/s.
Given that there is no friction considered. Thus, the total energy of the system can be considered as conserved.
Thus, sum of kinetic and potential energy will be constant.
K = U
mu 2 = mgh ......................................(1)
m = mass of object
v = speed of object
g = acceleration due to gravity = 9.8 m/s2
h = height of object with respect to a reference position
Thus for an object at a height from ground, will have its potential energy converted to kinetic energy during it's descent.
(A) from (1)
mv2 = 2mgh
Thus, v2 = 2gh
v = (2gh)1/2
this, is the velocity of an object from conservation of energy.
(B) with no friction, the enrgy is taken to be conserved. from the answer of (A), we know,
v = (2gh)1/2.
clearly this equation doesn't depend on mass.
thus, final speed doesn't depend on the mass.
(C) Given height of hill , h = 65cm = 0.65 m
from (1), v = (2gh)1/2.
the potential energy of car at the hill top = mgh
this potential energy gets entirely converted to kinetic energy at the bottom of hill due to conservation of energy. Thus
v = (2 x 9.8 x 0.65)1/2
= 3.569 m/s
Thus, the final velocity of the car is 3.569 m/s
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13. Shadrach, a form one student performed an experiment to investigate surface tension. he poured some water on a trough and allowed it to settle he then took a razor blade and gently placed it on the surface of the water in an attempt to make it float but failed give two possible reasons why the experiment failed
Answer:
this because the surface tension was lowered by using an impurity or rising the temp of the water