Answer:
I got
−
902 kJ
for the reaction as-written. How would you rewrite this into
kJ/mol NH
3
?
The standard molar enthalpy of formation is for the formation of
1 mol
of product from its elements as they exist in nature at
25
∘
C
and
1 atm
. For example...
1
2
N
2
(
g
)
+
3
2
H
2
(
g
)
→
NH
3
(
g
)
,
Δ
H
∘
f
(
NH
3
(
g
)
)
=
−
45.9 kJ/mol
But that also means formation of elements in their standard states must yield zero enthalpy change:
1
2
O
2
(
g
)
→
1
2
O
2
(
g
)
,
Δ
H
∘
f
(
O
2
(
g
)
)
=
0
That means we can simply derive from Hess's law and that fact to get:
Δ
H
∘
r
x
n
=
∑
P
n
P
Δ
H
∘
f
,
P
−
∑
R
n
R
Δ
H
∘
f
,
R
where
n
indicates the mols of product
P
or reactant
R
. Here we actually have just summed many formation reactions together that we know have
Δ
H
∘
r
x
n
=
Δ
H
∘
f
.
Here we have:
Δ
H
∘
r
x
n
=
[
4 mols NO
(
g
)
⋅
Δ
H
∘
f
,
N
O
(
g
)
+
6 mols H
2
O
(
g
)
⋅
Δ
H
∘
f
,
H
2
O
(
g
)
]
−
[
4 mols NH
3
(
g
)
⋅
Δ
H
∘
f
,
N
H
3
(
g
)
+
0 kJ/mol
]
where we have set a zero contribution
O
2
(
g
)
right off the bat.
=
[
4 mols NO
(
g
)
⋅
91.3 kJ/mol
+
6 mols H
2
O
(
g
)
⋅
−
241.8 kJ/mol
]
−
[
4 mols NH
3
(
g
)
⋅
−
45.9 kJ/mol
+
0 kJ/mol
]
=
[
−
1085.6 kJ
]
−
[
−
183.6 kJ
]
=
−
902 kJ
for the reaction as-written.
Explanation:
Can someone please help me with this
Which of the following pairs of elements will not form an ionic bond with
each other.
Sodium and lodine
Copper and Oxygen
Magnesium and Chlorine
Carbon and Sulfur
Answer:
Explanation:
Sodium and Iodine are in columns 2 and 17. They will be ionic.
Copper and oxygen will be ionic. Oxygen is a powerful receiver of electrons.
Magnesium and Chlorine same answer as the first one.
Carbon and Sulfur. Not so much. They do not form an ionic bond. They are basically closer to being two non metals.
Help please! I’ll give brainliest!
When balancing redox reactions under acidic conditions in aqueous solution, oxygen is balanced by adding:
Answer:
When balancing redox reactions under acidic conditions in aqueous solution, oxygen is balanced by adding water as much as oxygen we have, on the opposite side, where the oxygens are.
Explanation:
We can see this redox balance, in order to determine what we said.
The unbalanced reaction is: MnO₂ + HCl → MnCl₂ + Cl₂ + H₂O
The HCl determines, we are in acidic conditions.
We need to determine the half reactions:
Mn⁴⁺ → Mn²⁺ (In this case, the oxidation number decreased)
This is the reduction. Mn caught 2 electrons
Mn⁴⁺ + 2e⁻ → Mn²⁺
Cl⁻ → Cl₂
In ground state, the oxidation number is 0. The chloride was oxidized to chlorine. As Cl is a dyatomic molecule, we need 2 chlorides to balance so finally it released 2 electrons. This is the oxidation (ox. number has increased) 2Cl⁻ → Cl₂ + 2e⁻
Mn⁴⁺ + 2e⁻ → Mn²⁺
2Cl⁻ → Cl₂ + 2e⁻
Mn⁴⁺ + 2Cl⁻ → Mn²⁺ + Cl₂
Now we balance the oxygen. In reactant side, we have 2, so we complete with 2 water in the product side. We add water as much as oxygen we have, on the opposite side, where the oxygens are. (If we have 2 oxygen in reactant side, and we have 1 water, we need 1 more water)
So, as we added 2 H₂O, we complete with protons, on the opposite side
Mn⁴⁺ + 4H⁺ + 4Cl⁻ → Mn²⁺ + 2Cl⁻ + Cl₂ + 2H₂O
(Notice, we had 2Cl⁻, but globally we have 4H⁺. At least, we have 4HCl)
The balanced equation is: MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O
easons for the dense packing in metals
Explanation:
Typically, only one element is present, so all atomic radii are the same. -Metallic bonding is not directional. -Nearest neighbor distances tend to be small in order to lower bond energy.
In our bodies, glucose is broken down into carbon dioxide and water, much like a combustion reaction. How many grams of O2 are needed to fully react with 150g glucose? C6H12O6(s) + 6O2(g) -->6CO2(g) + 6H2O(g)
Answer:
160 g
Explanation:
The chemical equation is:
C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(g)
According to the equation, 1 mol of glucose (C₆H₁₂O₆) reacts with 6 moles of O₂. We calculate the masses of the reactants from the molar masses of the chemical elements:
1 mol C₆H₁₂O₆ = (6 x 12 g/mol)+ (12 x 1 g/mol) + (6 x 16 g/mol) = 180 g
6 mol O₂ = 6 x (2 x 16 g/mol) = 6 x 32 g/mol = 192 g
So, 180 g of C₆H₁₂O₆ reacts with 192 g of O₂. The stoichiometric ratio is 192 g O₂/180 g C₆H₁₂O₆. To calculate the grams of O₂ needed to react with 150 g of C₆H₁₂O₆ we can simply multiply the stoichiometric ratio by the grams of C₆H₁₂O₆:
150 g C₆H₁₂O₆ x 192 g O₂/180 g C₆H₁₂O₆ = 160 g O₂
Therefore, 160 grams of O₂ are needed to fully react with 150 g of glucose.
When 2.3 × 10^3 g of CaCO3 are heated, the actual yield of CaO is 1.09 × 10^3g. What is
the percent yield?
1. 51.0643
2. 54.084
3. 53.0474
4. 84.5827
5. 59.4924
6. 93.7005
7. 49.4244
8. 78.3748
9. 44.6193
10. 72.7638
Answer in units of %.
The percent yield : 4. 84.58%
Further explanationReaction
CaCO₃ ⇄ CaO+CO₂
mass CaCO₃ = 2.3 × 10³ g
mol CaCO₃ (MW=100.0869 g/mol) :
[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{2.3\times 10^3}{100,0869}\\\\mol=22.98[/tex]
From the equation, mol CaCO₃ : CaO = 1 : 1, so mol CaO=22.98
mass CaO(MW=56.0774 g/mol)⇒ (theoretical) :
[tex]\tt mass=mol\times MW\\\\mass=22.98\times 56,0774\\\\mass=1288.659~g[/tex]
The percent yield :
[tex]\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{1090}{1288.659}\times 100\%\\\\\5yield=84.58\%[/tex]
How many moles of H2 are needed to produce 34.8 moles of NH3?
Moles H₂ needed = 52.2
Further explanationA reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
N₂(g)+3H₂(g)⇒2NH₃(g)
From the reaction equation above, the reaction coefficient shows the mole ratio of reagents and products
moles NH₃ produced = 34.8
mol H₂: moles NH₃ = 3: 2, so moles H₂ :
[tex]\tt moles~H_2=\dfrac{coefficient~H_2}{coefficient~NH_3}\times moles~NH_3\\\\moles~H_2= \dfrac{3}{2}\times 34.8=52.2[/tex]
A child and her mother are at the park.The child walks around the rectangular park while her mom waits on a bench. The child returns to the bench ,finishing her walk at the same place she started.The park is 411 meters wide and 475 meters long. What was the displacement of the child?
A. 0 m
B. 886 m
C. 1,772 m
D. 64 m
The displacement of the child : A. 0 m
Further explanationDistance is a scalar quantity that indicates the length of the trajectory that is traveled by an object within a certain interval. Distance has no direction, only has a magnitude
Can be simplified distance = total meters traveled
Displacement is a vector quantity that shows changes in the position of objects in a certain interval of time. Displacement has magnitude and direction
Can be simplified displacement = distanced traveled from starting point to ending point
So the displacement of the child : 0 m
and the distance = the circumference of the rectangle :
[tex]\tt =2(l+W)\\\\=2(475+411)\\\\=1772~m[/tex]
Please help me I need these answers
Answer:
Q8) True
Q9) First ionization energy
Q10) A metal oxide
Explanation:
One of the properties of group one elements (alkali metals) is that they combine with water to form basic solutions. E.g 2Na(s)+2H2O(l)→2NaOH(aq)+H2(g).
An inverse relationship exists between the distance of the outermost electron in the atom from the nucleus and the first ionization energy. As the distance between the outermost electron and the nucleus in group 17 elements increases, their first ionization energies decreases accordingly.
Group 1 elements react with oxygen to yield the corresponding metal oxides. E.g 4 Na + O2 --> 2 Na2O
Catalysts are used in the oil industry to increase octane ratings in gasoline. Octane ratings tell how much fuel has to be compressed to promote better fuel ignition in some cars. Which of the following catalytic effects would be most beneficial for the oil industry?
Higher temperatures and pressures can be used.
Lower temperatures and pressures can be used.
Less product can be formed from a given amount of material.
More product can be formed from a given amount of material.
The catalytic effects 'lower temperatures and pressures can be used' would be most beneficial for the oil industry.
What is a catalyst?A catalyst is a chemical substance that has the potential to speed up the velocity if a particular reaction.
In biology, the most common catalysts are specific proteins called enzymes.In conclusion, the catalytic effects 'lower temperatures and pressures can be used' would be most beneficial for the oil industry.
Learn more about catalysts here:
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Answer:
B
Explanation:
8. Give me an example of a number that we use that is actually exact and not subject to sig, digit rules. Again, give me the name of the number (My example "I have 25 students in class). US
Answer:
There are 58 people in the cinema.
Explanation:
This number is actually exact and not subject to sig, digit rules.
What is a chemical treatment process used to remove dissolved ionic species from contaminated aqueous streams?
Answer:
Ion exchange.
Explanation:
One of the ways in which water can be treated is through the process known as ION EXCHANGE. Using this for treating water has to do basically with the transfer or say the exchange of ions.
Ion exchanges is done by exchanging ions which are considered as 'unfit' or contaminants by the ones that are "fit".
Ions from what is known as zeolite or resin is been exchanged with the ions in the water. Cations are exchanged with cations and anions are exchanged with anions.
NB: this method is a good method or removing contaminants that are ions but not contaminants that are not ions.
1. Why the names such as sodium(l) chloride for NaCl and
magnesium(II) chloride for MgCl2 are not used?
Answer:
It's because the NaCl and MgCl2 is shorter and easier to remember
Newton's Second Law of Motion says that the acceleration of an object depends on the object's mass and the
A
equation E=MC^2E=MC
2
.
B
amount of force applied to the object.
C
negative acceleration factor.
D
amount of atoms the object has.
Answer: Hello! I do believe the answer is A.
Explanation: please mark me brainliest! hope this helps
Answer:
B
Explanation:
Is a Krypton atom still a Krypton atom if you change the number of neutrons?
Group of answer choices
Answer:
Yes
Explanation:
A krypton atom will remain the same despite changing the number of neutrons they contain.
The neutron is a nuclear particle found within an atom.
Atoms with different number of neutrons belonging to the same element are called isotopes. Only changes to the number of protons changes the elemental designation of an atom. A change in the number of electrons and neutrons does not affect the identity of such atom.pls help I I alot of HELP
Answer:
They need more oxhygen to fraction to incresse
Explanation:
What is different about the presence of water on Earth that sets it apart from the other inner planets?
The difference about the presence of water on Earth that sets it apart from the other inner planets is that either the planet is too hot that the water vaporizes or too cold that the water freezes.
The primary components of inner planets, commonly referred to as terrestrial planets, are rocks and metals. In comparison to the outer planets, they are modest in both size and shape. They have a molten metal core and a solid surface. The Solar System's four innermost planets are as follows (Mercury, Venus, Earth, and Mars).
Most importantly, since the temperature permits liquid water to exist for long periods of time, Earth is unique in that the majority of our planet is covered with liquid water.
Only the Earth possesses liquid water because all the other planets and moons are either too hot or too cold, causing any water that may be present to boil away or freeze.
To learn more about inner planets refer- https://brainly.com/question/11023671
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What is the cation in the chemical formula MnSe?
Answer:
Mn
Explanation:
The cation in the chemical formula MnSe is the Mn specie.
A cation is a positively charge ion or radical. Such an ion has lost electrons and this leaves a net positive charge on them. The Mn is the cationMost metals forms cations as they readily lose electrons due to their large atomic radius. Se is the anion as it will carry a negative chargeMost non-metals are anionsCalculate the mass in grams of 18.6 mol of CuSO4.5H2O.
Answer:
just multiply 18.6 to molar mass of cuso4.5h20
Explanation:
if you have any doubt comment
What is the frequency of UV light that has an energy of 5.2 x 10^-8 J?
This table shows data collected about four different landforms. Landform What Is Its Landmass? What Is Its Shape? Is There Water? W Large Has steep sides No X Large Goes down and comes back up No Y Small A circle Filled with water Z Small Rises up in the middle then goes back down Surrounded by water Question Which landform is an island?
A.
W because it has steep sides.
B.
X because it dips in the middle.
C.
Y because it is small and a circle.
D.
Z because it is surrounded by water
Answer:
answer is d
Explanation:
because it is surrounded by water
Draw the structures of the products of the neutralization reaction between hydroxide ion and methylammonium ion.
Answer:
[CH3NH3]+ +OH- ----> CH3NH2 +H2O
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The mass of Ba(CIO), formed when 0.50 mole of Ba(OH), is treated with 0.80 mol of HCIO, according to the reaction below is
Ba(OH), + 2HCIO, ----> Ba(CIO3)2 + 2H,0
Ba: 137.3 g/mol
O: 16 g/mol
H: 1 g/mol
Cl: 35.45 g/mol
Flag question
16
Select one:
304 2 g
243.4 g
121.79
380.7 g
None of the above
Next page
The mass of Ba(CIO₃)₂ : 121.72 g
Further explanationReaction
Ba(OH)₂ + 2HCIO₃ ----> Ba(CIO₃)₂ + 2H₂O
Limiting reactant :
Ba(OH)₂ : 2HCIO₃ =
[tex]\tt \dfrac{0.5}{1}\div \dfrac{0.8}{2}=0.5\div 0.4\rightarrow HClO_3~limiting(smaller~ratio)[/tex]mol Ba(CIO₃)₂ based on limiting reactant(HCIO₃) :
[tex]\tt \dfrac{1}{2}\times 0.8=0.4[/tex]
MW Ba(CIO₃)₂ =Ba+2.Cl+6.O=137.3 + 2 x 35.5 + 6 x 16 = 304.3
mass of Ba(CIO₃)₂ :
[tex]\tt mass=mol\times MW\\\\mass=0.4\times 304.3=121.72~g[/tex]
How do we write a formula for those combinations of atoms?
Answer:
please follow me
Explanation:
hope it helps.......
If you start with 50 grams of potassium-42, how much will remain after 62.0 hours?
Answer:
26.5 is your answer thank you
If 45.0 mL of ethanol (density =0.789g/mol) initially at 6.0°C mix with 45.0 mL of water (density =1.0 g/mol) initially at 28.0°C in an insulated beaker, what is the final temperature of the mixture, assuming that no heat is lost? (CetOH =2.42 J/G C)
The final temperature of the mixture : 21.1° C
Further explanationThe law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released
Q in(gained) = Q out(lost)
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
Q ethanol=Q water
mass ethanol=
[tex]\tt mass=\rho\times V\\\\mass=0.789\times 45=35.505~g[/tex]
mass water =
[tex]\tt mass=1~g/ml\times 45~ml=45~g[/tex]
then the heat transfer :
[tex]\tt 35.505\times 2.42~J/g^oC\times (t-6)=45\times 4.18~J/g^oC\times (28-t)\\\\85.922t-515.533=5266.8-188.1t\\\\274.022t=5782.33\rightarrow t=21.1^oC[/tex]
Calculate the mass of ammonia (NH3) that contains a billion (1.00 * 10^12) hydrogen atoms.
Answer:
The mass of ammonia (NH3) that contains [tex]1.00 \times 10^12[/tex] hydrogen atoms is [tex]9.4\times 10^{-12}[/tex] g.
Explanation:
As [tex]6.022\times 10^{23}[/tex] atoms of hydrogen = 1 mole of the hydrogen atom
Therefore, [tex]10^{12}[/tex] atoms of hydrogen [tex]= \frac{1}{6.022 \times 10^{23}}\times 10^{12}=1.66\times 10^{-12}[/tex] moles of the hydrogen atom.
Now, there are 3 moles of hydrogen atoms in 1 mole of ammonia [tex](NH_3)[/tex].
As the mass of 1 mole of ammonia is 17g, so
when there are 3 moles of hydrogen atoms, then the mass of ammonia = 17 g
Therefore, when there are [tex]1.66\times 10^{-12}[/tex] moles of hydrogen atoms, then the mass of ammonia [tex]= \frac{17}{3}\times 1.66\times 10^{-12}=9.4\times 10^{-12[/tex] g.
Hence, the mass of ammonia [tex](NH_3)[/tex] that contains [tex]1.00 \times 10^12[/tex] hydrogen atoms is [tex]9.4\times 10^{-12}[/tex] g.
if T1=454 K and T2=356 K atm and V1=101.85 mL. then what is V2? please help asap!!!
Answer:
opp
Explanation:
How to get nail polish remover off the top of your chrome book
Answer:
Explanation: I saw that you answered someone else's same question with toothpaste. What toothpaste did you use?