Answer:
$6236.56
Step-by-step explanation:
Compound Formula
[tex]A = P (1+\frac{r}{n} )^n^t\\[/tex]
I plugged in the numbers of P, r, and t.
n means the number of times the interest is applied per period. It is compounded monthly, and the time is given 3 years.
This means 12 months x 3 years = 36 months.
[tex]A = $5700(1+.03/36)^3^6^(^3^)[/tex]
[tex]A=6236.559672[/tex]
[tex]A=6236.56[/tex]
Spring fever! Epidemiologists and teachers alike have noticed the cyclic occurrence of the dreaded spring fever. Students afflicted with this disease exhibit certain listlessness in class, and they seem to stare out the windows with remarkable tenacity. At Metro University, teachers have been monitoring the situation and diagnosing spring fever. Their observations began with week 0, the first week in April. The teachers’ data are shown in the following table:
Spring Fever Cases: Raw Data Week Newly Diagnosed with SF No SF Diagnosed
0 0 1,025
1 105 920
2 180 740
3 390 350
4 325 25
For weeks 1–4, fill out the table below. Calculate the incidence and prevalence, show your fractions and answers in the table, and round to the nearest thousandths decimal place. (0.000)
Therefore, teachers should anticipate the greatest increase in spring fever during the 4th week.
A) Spring Fever: Incidence and PrevalenceWeek New Cases Total Cases So Far Individual at Risk at Start of Week Weekly Incidence Prevalence
1 105 105 920 0.102 0.102
2 180 285 740 0.196 0.278
3 390 675 350 0.527 0.659
4 325 1000 25 0.929 0.976
B) Spring Fever: Incidence and Prevalence per 100
Week Weekly Incidence per 100 Prevalence per 100
1 10.2 per 100 10.2 per 100
2 19.6 per 100 27.8 per 100
3 52.7 per 100 65.9 per 100
4 92.9 per 100 97.6 per 100
C) The 4th-week incidence is much higher, indicating an increase from 0.527 in the 3rd week to 0.929 in the 4th week.
Therefore, teachers should anticipate the greatest increase in spring fever during the 4th week.
Incidence= Number of new cases at particular week/total number of cases in that week
Prevalence= Total number of cases diagnosed/total number of subjects
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A ball is thrown from a height of 154 feet with an initial downward velocity of 10 ft/s. The balls height (in feet) after t seconds is given by the following. h=154-10t-16t^2. how long after the ball is thrown does it hit the ground?
Answer:
Step-by-step explanation:
The ball hits the ground when h=0.
[tex]0=154-10t-16t^{2}[/tex]
Solve for t. You can use the quadratic formula.
[tex]t=\frac{-(-10)+-\sqrt{10^{2}(-16\cdot154) } }{2(-16)}[/tex]
[tex]t=\frac{5+-\sqrt{2489} }{16} \\t=-3.43 t=2.81[/tex]
Time cannot be negative. So, the answer is t=2.81 seconds.
A city had a declining population from 1992 to 1998. The population in 1992 was 200,000. Each year for 6 years, the population declined by 3%. Write an exponential decay model to represent this situation.
The exponential decay model for this situation is P(t) = 200,000 * (1 - 0.03)^t
How to find the percentage from the total value?Suppose the value of which a thing is expressed in percentage is "a'
Suppose the percent that considered thing is of "a" is b%
Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).
We need to Write the percent as a fraction in simplest form
16.24%
So, we can rewrite it as;
16.24 / 100
16 and 24/100 or 16 6/25
So the percent as a fraction is 16 6/25
We are given that;
Population in 1992=200000
Time=6years
Rate=3%
To write an exponential decay model to represent this situation, we can use the formula:
P(t) = P * (1 - r)ᵗ
where P(t) is the population after t years, P is the initial population, r is the annual rate of decline as a decimal, and t is the number of years. In this case, the initial population P is 200,000, the annual rate of decline r is 0.03 (since the population declines by 3% each year), and t is the number of years from 1992, so t = 0 corresponds to 1992 and t = 6 corresponds to 1998.
P(t) = 200,000 * (1 - 0.03)^t
where t is the number of years from 1992 to 1998.
Therefore, by the given percent answer will be P(t) = 200,000 x (1 - 0.03)^t
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Fill in the missing number.
18 - ____ = 30
Two factories blow their whistles at exactly the same time. If a man hears the two blasts
exactly 6.1 seconds and 2.7 seconds after they are blown and the angle between his lines of
sight to the two factories is 42.4°, how far apart are the factories? Give your result to the
nearest meter. (Use the fact that sound travels at 344 m/sec.)
Distance between both factories is 1543 m
What is cosine law?In Trigonometry, the law of Cosines, also known as Cosine Rule or Cosine Formula basically relates the length of the triangle to the cosines of one of its angles. It states that, if the length of two sides and the angle between them is known for a triangle, then we can determine the length of the third side. It is given by:
c² = a² + b² – 2ab cosγ
Given,
A man hears the two blasts exactly 6.1 seconds and 2.7 seconds from two factories.
Angle between line of sight γ = 42.4°
Speed of sound = 344m/sec
Distance of factory A from man (a)
6.1 × 344 = 2098.4 m
Distance of factory B from man (b)
2.7 * 344 = 928.8 m
The side opposite the angle between his lines of sight will be the distance between the factories.
Using cosine law
c² = a² + b² – 2ab cos γ, where
c = distance between the factories
c² = 2098.4² + 928.8² – 2(2098.4)(928.8) cos 42.4°
c = √(2098.4² + 928.8² – 2(2098.4)(928.8) cos 42.4°)
c = √(4403282.56 + 862669.44 - 3897987.84(0.74))
c = √(5265952 - 2884511)
c = √2381441
c = 1543.19 m
≈ 1543 m
Hence, 1543 m is the distance between both factories.
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Manuel’s final exam has true/false questions, worth three points each, and multiple choice questions, worth four points each, let x be the number of true/false questions he gets correct, and let y be the number of multiple choice questions he gets correct. He needs more than 82 points on the exam to get an A in the class. Using the values and variables given, right in equality describing it.
Answer: Let T be the number of true/false questions on the exam, and let M be the number of multiple choice questions on the exam.
Then, the total number of points Manuel can earn on the exam is:
3T + 4M
We know that Manuel needs more than 82 points on the exam to get an A in the class. Therefore, we can write the following inequality:
3x + 4y > 82
where x is the number of true/false questions Manuel gets correct, and y is the number of multiple choice questions Manuel gets correct.
Step-by-step explanation:
Determine the quotient and remainder when (2a^(3)+7a^(2)+2a+9) is divided by (2a+3). Use long division or synthetic division
The remainder is -21 and the quotient is 6a2-18a+21.
What is synthetic division?Synthetic division is a method for dividing polynomials by monomials. It is a simplified form of the long division of polynomials, and is useful when the divisor is a monomial. The method involves arranging the coefficients of the dividend in a row, and then dividing each term by the divisor .
To determine the quotient and remainder when (2a3+7a2+2a+9) is divided by (2a+3), you can use either long division or synthetic division.
Using long division:
÷2a+3
2a3+7a2+2a+9
-6a2 (2a3 ÷ 2a = 6a2)
-18a (7a2 ÷ 2a = 3a2 = 18a)
-21 (2a+9 ÷ 2a+3 = -2a+12 ÷ 2a+3 = -21)
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You earned 75% on your badminton practical. If the practical was out of 88, what mark did you earn?
Answer:
66 (at least if that is an answer choice)
Step-by-step explanation:
[tex]\frac{75*88}{100} = 66[/tex]
66 is your answer!
Which point would be included in the region shaded to show the half-plane greater than the line?
The point that would be included in the region shaded to show the half-plane greater than the line is the point that lies above the line.
In order to determine which point is included in the region shaded to show the half-plane greater than the line, we can use the following steps:
1. Identify the equation of the line.
2. Plug in the x and y values of the point into the equation of the line.
3. If the result is greater than the constant term in the equation of the line, then the point is included in the region shaded to show the half-plane greater than the line.
For example, if the equation of the line is y = 2x + 1, and the point is (2,5), we can plug in the x and y values into the equation:
5 = 2(2) + 1
5 = 5
Since the result is equal to the constant term in the equation of the line, the point (2,5) is included in the region shaded to show the half-plane greater than the line.
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Viet, Quinn, and Lucy are going to play Bingo, using a standard game set. They make some predictions before the game begins. The table shows how the numbers match with the letters B, I, N, G, and O.
PART A
Viet describes the probability of each number being called first. Quinn describes the probability of any particular letter being called first. Compare the probabilities.
Comparing the two probabilities, we can see that the probability of any particular letter being called first (1/5) is five times greater than the probability of any particular number being called first (1/75). This is because there are five letters and only one number will be called first.
What is the probability about?Viet's description of the probability of each number being called first can be determined as follows. There are 75 numbers in the set, and each number has an equal chance of being called first. Therefore, the probability of any particular number being called first is 1/75.
Quinn's description of the probability of any particular letter being called first can be determined as follows. There are five letters in the set, and each letter has 15 numbers associated with it. Therefore, the probability of any particular letter being called first is 15/75 or 1/5.
Comparing the probabilities, we can see that the probability of any particular letter being called first is greater than the probability of any particular number being called first. This is because there are fewer letters (5) than numbers (75), so the probability of selecting a particular letter is higher than the probability of selecting a particular number.
Therefore, Quinn's probability of any particular letter being called first is greater than Viet's probability of any particular number being called first.
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See transcribed text below
TOPIC
7
MID-TOPIC PERFORMANCE TASK
Viet, Quinn, and Lucy are going to play Bingo, using a standard game set. They make some predictions before the game begins. The table shows how the numbers match with the letters B, I, N, G, and O.
Letter
Numbers
B - 1-15
1 -16-30
N-31-45
G- 46-60
O- 61-75
PART A
Viet describes the probability of each number being called first. Quinn describes the probability of any particular letter being called first. Compare the probabilities.
Suppose that 511,969 is invested at an interest rate of 5 2% per year, compounded continuously a) Find the exponential function that describes the amount in the account after timet in years b) What is the balance after 1 year? 2 years? 5 years? 10 years? c) What is the doubling time?
The doubling time.
A) The exponential function that describes the amount in the account after time t in years is A(t) = 511969*e^(0.052*t), where A(t) is the amount in the account after time t, e is the base of the natural logarithm, and t is the time in years.
B) The balance after 1 year is A(1) = 511969*e^(0.052*1) = 538,926.41
The balance after 2 years is A(2) = 511969*e^(0.052*2) = 567,639.77
The balance after 5 years is A(5) = 511969*e^(0.052*5) = 661,234.83
The balance after 10 years is A(10) = 511969*e^(0.052*10) = 872,032.74
C) The doubling time is the time it takes for the amount in the account to double. We can find this by setting A(t) = 2*511969 and solving for t.
2*511969 = 511969*e^(0.052*t)
2 = e^(0.052*t)
ln(2) = 0.052*t
t = ln(2)/0.052
t = 13.33 years
So the doubling time is 13.33 years.
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e synthetic division and the Remainder Theorem to evaluate P(C). P(x)=3x^(3)+15x^(2)-10x+9,c=2
P(2) = 73.
To evaluate P(C) using synthetic division and the Remainder Theorem, we will follow the following steps:
Set up the synthetic division table with the value of C on the left and the coefficients of P(x) on the right.
Bring down the first coefficient to the bottom row.
Multiply the value of C by the first coefficient in the bottom row and place the result in the next column.
Add the values in the second column and place the result in the bottom row.
Repeat steps 3 and 4 for the remaining columns.
The last value in the bottom row is the remainder. According to the Remainder Theorem, this is the value of P(C).
Therefore, P(2) = 73.
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If figure QRST is reflected across the x-axis and then translated 3 units down which of the following will be the coordinates for point R?
To find the coordinates of point R after the reflection and translation, we would need to know its original coordinates in the figure QRST. Then we could apply the above rules to get its new coordinates.
What are coordinates ?
Coordinates are numerical values that specify the position or location of a point in a given space. In mathematics, coordinates are often expressed as ordered pairs or triplets of numbers, which correspond to the distances of the point from a set of fixed reference points or axes.
Without seeing the figure QRST, it is not possible to give the exact coordinates for point R after the reflection and translation. However, we can use some general knowledge about the effects of reflection and translation on the coordinates of a point.
When a figure is reflected across the x-axis, the x-coordinates of all its points remain the same, but the y-coordinates are negated. That is, if a point has coordinates (x, y) before the reflection, its coordinates after the reflection will be (x, -y).
When a figure is translated down by 3 units, the y-coordinates of all its points are decreased by 3. That is, if a point has coordinates (x, y) before the translation, its coordinates after the translation will be (x, y - 3).
Therefore, to find the coordinates of point R after the reflection and translation, we would need to know its original coordinates in the figure QRST. Then we could apply the above rules to get its new coordinates.
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David wants to build a pen for his goat. He wants the area of the pen to be 48 square feet. If the length and width of the pen are both whole numbers. What could be the perimeter of the pen. Alright I can’t figure it out please help
If the length and width of the pen are both whole numbers the possible perimeters for the pen are 98, 52, 38, 32, and 28.
To find the possible perimeters of the pen, we first need to find all the possible length and width pairs that would give us an area of 48 square feet. Since the length and width are whole numbers, we can start by listing out all the factors of 48:
1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Each of these factors represents a possible length or width of the pen, and we can find the other dimension by dividing the area (48) by the first dimension. For example, if the first dimension is 1, then the other dimension is 48/1 = 48. However, we need to make sure that the second dimension is also a whole number.
Using this method, we can find all the possible length and width pairs:
1 x 48, 2 x 24, 3 x 16, 4 x 12, 6 x 8
Now we can calculate the perimeter for each of these pairs. The perimeter is the sum of the lengths of all four sides of the pen. Since the length and width are the same for a square pen, we can use the formula:
perimeter = 2(length + width)
For each pair, we can plug in the values for length and width to get the perimeter:
1 x 48: perimeter = 2(1 + 48) = 98
2 x 24: perimeter = 2(2 + 24) = 52
3 x 16: perimeter = 2(3 + 16) = 38
4 x 12: perimeter = 2(4 + 12) = 32
6 x 8: perimeter = 2(6 + 8) = 28
Therefore, the possible perimeters for the pen are 98, 52, 38, 32, and 28.
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Find the value of cos J rounded to the nearest hundredth, if necessary.
The value of cos J rounded to the nearest hundredth is 0.384.
Describe the cosine function.A mathematical function known as the cosine is used in many branches of mathematics, such as geometry and trigonometry. It is described as the proportion between the hypotenuse and the adjacent side of a right triangle. It is represented by the symbol cos-1 or arc cos and is also known as the inverse cosine or arc cosine.
Using Pythagoras theorem lets find IJ
IJ = [tex]\sqrt{13^2 - 12^2}[/tex]
IJ = √25
IJ = 5
Now,
cos θ = Adjacent side/Hypotenuse
cos J = IJ/HJ
= 5/13
= 0.384
Thus, the value of cos J rounded to the nearest hundredth is 0.384.
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Complete question:
Find the value of cos J rounded to the nearest hundredth, if necessary.
The cost to repair a computer was $190. This included $115 for parts and $25 per hour for labor. How many hours of labor were required to fix the computer? hr
Total 3 hours of labor were required to fix the computer.
To find the number of hours of labor required to fix the computer, we can use the following equation:
Total cost = Cost of parts + (Cost of labor per hour × Number of hours of labor)
We can rearrange this equation to solve for the number of hours of labor:
Number of hours of labor = (Total cost - Cost of parts) ÷ Cost of labor per hour
Plugging in the given values:
Number of hours of labor = ($190 - $115) ÷ $25
Number of hours of labor = $75 ÷ $25
Number of hours of labor = 3 hr
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Let \( T_{1} \) and \( T_{2} \) be linear transformations given by \[ \begin{array}{l} T_{1}\left(\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]\right)=\left[\begin{array}{r} 3 x_{1}+6 x_{2}
\[
T_{1} \circ T_{2}\left(\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]\right)=\left[\begin{array}{r} 43 x_{1}+2 x_{2} \\ -10 x_{1}+4 x_{2}\end{array}\right]
\]
Let \(T_{1}\) and \(T_{2}\) be linear transformations given by
\[\begin{array}{l}
T_{1}\left(\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]\right)=\left[\begin{array}{r} 3 x_{1}+6 x_{2} \\ 5 x_{1}-2 x_{2}\end{array}\right] \\
T_{2}\left(\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]\right)=\left[\begin{array}{r} 8 x_{1}+4 x_{2} \\ 5 x_{1}+2 x_{2}\end{array}\right]
\end{array}\]
A linear transformation is a function that takes two input values and returns two output values in a way that preserves the linear structure of the data. It is described by a matrix that determines the output values from the input values. In the case of \(T_{1}\) and \(T_{2}\), the matrix is
\[
M=\left[\begin{array}{cc}
3 & 6 \\
5 & -2
\end{array}\right]
\]
and
\[
M=\left[\begin{array}{cc}
8 & 4 \\
5 & 2
\end{array}\right]
\]
respectively. The two linear transformations can be combined using matrix multiplication, which yields the transformation
\[
T_{1} \circ T_{2}\left(\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]\right)=M_{1} M_{2}\left(\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]\right)
\]
where
\[
M_{1}M_{2}=\left[\begin{array}{cc}
43 & 2 \\
-10 & 4
\end{array}\right].
\]
Therefore, the result of applying both transformations to a given input vector is given by
\[
T_{1} \circ T_{2}\left(\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]\right)=\left[\begin{array}{r} 43 x_{1}+2 x_{2} \\ -10 x_{1}+4 x_{2}\end{array}\right]
\]
This is an example of a linear transformation, where two transformations are combined to produce a single result.
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Need help pleaseeeeeeee
The volume of the right square pyramid with the dimensions e = 5m, h = 4m, and s = 6m is 48m³.
What is pyramid?Pyramid is a structure with a polygonal base and triangular sides that meet at a point. Pyramids have been used throughout history as tombs, temples and monuments. Many of the most famous pyramids are located in Egypt, such as the Great Pyramid of Giza.
The volume of a right square pyramid is equal to one-third of the base area multiplied by the height. To find the volume of this pyramid, we first need to calculate the base area.
The base area of a square pyramid is equal to the length of one side (s) squared. Since the length of one side of this pyramid is 6m, the base area is 6m x 6m, which equals 36m².
Now that we know the base area, we can calculate the volume of the pyramid. The volume is equal to one-third of the base area multiplied by the height. In this case, the volume of the pyramid is one-third of 36m² multiplied by 4m, which equals 48m³.
Therefore, the volume of the right square pyramid with the dimensions e = 5m, h = 4m, and s = 6m is 48m³.
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A store is having a holiday sale and offers no down payment on each credit items. A sound system will cost $29.99 per week for a year. What is the total price?
Answer:$20.40
Step-by-step explanation:
20% off means that the new price of the skirt will be 80% of the original price:
$30(100% – 20%) = $30(80%)
Converting the percent to a decimal gives:
$30(0.8) = $24.00
There is an additional 15% off the sale price of $24.00, so the final price is 85% of the sale price:
$24(100% – 15%) = $24(85%)
Again converting the percent to a decimal gives:
$24(0.85) = $20.40
the perimeter of the rectangle is 22 feet. The perimeter of the triangle is 12 feet. Find the dimensions of the rectangle.
The dimensions of the rectangle is 3.33 by 5.33
How to find the dimensions of the rectangle.From the question, we have the following parameters that can be used in our computation:
The perimeter of the rectangle is 22 feet. The perimeter of the triangle is 12 feet.Using the above as a guide, we have the following:
Third side of triangle, w = 12 - 5 - 1/2l
The perimeter of the rectangle is then calculated a
2 * (1/2l + 1/2l + 12 - 5 - 1/2l) = 22
So, we have
(1/2l + 1/2l + 12 - 5 - 1/2l) = 11
Evaluate
1 1/2l + 7 = 11
This gives
3/2l = 5
Evaluate
l = 10/3
The dimension is then represented as
l by 12 - 5 - 1/2l
This gives
10/3 by 12 - 5 - 1/2 * 10/3
Evaluate
3.33 by 5.33
Hence, the dimension is 3.33 by 5.33
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How much greater is the fractional part of a college student's daily servings that comes from grains than from fruits?
To determine how much greater the fractional part of a college student's daily servings that comes from grains than from fruits, we would need to know the specific fractions or percentages of each type of food that the student consumes. Without this information, it is impossible to accurately answer the question.
For example, if the student consumes 1/2 of their daily servings from grains and 1/4 of their daily servings from fruits, then the difference would be 1/2 - 1/4 = 1/4 or 25%. However, without knowing the specific fractions or percentages, we cannot determine the difference.
It is important to remember that a balanced diet should include a variety of food groups, including grains, fruits, vegetables, proteins, and dairy. The specific amounts of each will vary depending on individual dietary needs and preferences.
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simplify using trig identities
(cos2x-1) / (sin2x)
As a result, the formula is (cos 2x - 1) / (2 sin x cos x)
What are an equation and an expression?A mathematical expression shows the worth of something by combining numbers, factors, and functions. A mathematical assertion known as an equation involves setting two expressions equivalent to one another.
We can start by using the identity:
cos 2x = cos² x - sin² x
We can rearrange this to get:
cos² x = cos 2x + sin² x
Substituting this into the expression we want to simplify, we get:
(cos² x - sin² x - 1) / (sin 2x)
We can then use the identity:
sin 2x = 2 sin x cos x
Substituting this into the expression, we get:
(cos² x - sin² x - 1) / (2 sin x cos x)
We can simplify the numerator using the identity:
cos² x - sin² x = cos 2x
Substituting this into the expression, we get:
(cos 2x - 1) / (2 sin x cos x)
Therefore, the simplified expression is:
(cos 2x - 1) / (2 sin x cos x)
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9 inches of ribbon is needed for wrapping one present. How many presents can be wrapped with 8 yards of ribbon?
9 presents
16 presents
32 presents
45 presents
First, we need to convert 8 yards to inches since the measurement of ribbon needed for one present is given in inches.
1 yard = 36 inches (since 1 yard = 3 feet and 1 foot = 12 inches)
So, 8 yards = 8 x 36 = 288 inches.
To find out how many presents can be wrapped with 288 inches of ribbon, we divide the total length of ribbon by the length needed for one present:
Number of presents = Total length of ribbon ÷ Length of ribbon needed for one present
Number of presents = 288 ÷ 9
Number of presents = 32
Therefore, 32 presents can be wrapped with 8 yards (288 inches) of ribbon.
Hence, the answer is 32 presents.
Answer: c(32
Step-by-step explanation:
The selling price of each cup of lemon juice is 3/2 times as much as the selling price of a cup of apple juice. For every 2 cups of lemon juice sold, Mr Tan sells 5 cups of apple juice. He earns $12 more from apple juice than from lemon juice. How much does Mr Tan earn altogether?
Therefore , the solution of the given problem of unitary method comes out to be Mr. Tan makes a total of $30 Plus $18 = $48.
An unitary method is what?To finish the job using the unitary technique, the equation from this nano section should be multiplied by two. In essence, when a wanted object is present, both the characterised by either a group and the pigment sections are omitted from the unit method. A variable fee of Inr ($1.01), for instance, would be paid for 40 pens. It's conceivable that one nation will have complete control over the strategy used to achieve this. Almost all living things have a unique trait.
Here,
Let's name the CDs' pre-tax cost "x" for simplicity. The overall cost of the CDs before tax is two times because Lena purchased two of them for the same price. The cost of the Discs, with the addition of the $1.80 sales tax, is:
=> 2x + $1.80
Given that we know the final price, including tax, was $23.40, we can create the following equation:
=> 2x + $1.80 = $23.40
By deducting $1.80 from each half, we arrive at:
=> 2x = $21.60
When you divide both parts by 2, you get:
=> x = $10.80
As a result, each Disc cost $10.80 before taxes.
We can create another equation now that we know his revenues from selling apple juice are $12 higher than his profits from selling lemon juice:
=> 30n - 18n = 12
=> 12n = 12
=> n = 1
As a result, Mr. Tan sells 2n + 5n = 7n = 7 glasses of juice, for a total profit of 30n = $30 from the sale of apple juice and 18n = $18 from the sale of lemon juice.
Therefore, Mr. Tan makes a total of $30 Plus $18 = $48.
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The ratio of students who wear glasses to the total class is 2:5. If 5 of the students who didn’t wear glasses now do,what is the ratio of students who wear glasses to those who don’t?
Answer:
Let's say that the class has a total of 7x students, where 2x wear glasses and 5x don't.
After 5 of the students who didn't wear glasses now do, the number of students who don't wear glasses becomes 5x - 5.
So, the new ratio of students who wear glasses to those who don't wear glasses is:
2x : (5x - 5)
We can simplify this ratio by dividing both terms by the greatest common factor, which is x:
2 : (5 - 5/x)
We can't simplify this any further, but we can see that the ratio is not fixed and depends on the value of x.
HELP! i dont know what the answer is and need HELP!
The situation in which the quantities combine to make 0 is D.
What is a combination of quantities?
In mathematics, a combination of quantities usually means taking a group of items or values and selecting some of them without regard to their order. A combination is different from a permutation in that order does not matter in a combination, whereas it does matter in a permutation.
For example, if you have three objects labeled A, B, and C, then the possible combinations of two objects are AB, AC, and BC. These combinations are different from the permutations of two objects, which include AB and BA, AC and CA, and BC and CB.
Combinations are often used in probability, statistics, and combinatorics to calculate the number of ways that objects or values can be selected from a set, without regard to their order.
The situation in which the quantities combine to make 0 is:
D. In the morning, the temperature rises 30 degrees. In the evening, it falls by 30 degrees.
In situation D, the temperature rises by 30 degrees in the morning and then falls by 30 degrees in the evening, which means that the overall change in temperature is 0. In situations A, B, and C, the quantities do not combine to make 0. In situation A, the hot air balloon rises a total of 80 feet, which is not 0. In situation B, Kathy has $10 left after giving half to her friend, which is not 0. In situation C, the player earns a total of 8 points, which is not 0.
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Mipl Analyze a Problem Without calculating, is the product of 7 and 5(3)/(4) greater than or less than 35 ? Explain.
The product is less than 35.
To analyze this problem without calculating, we can look at the factors involved in the product. The first factor is 7, and the second factor is 5(3)/(4).
The second factor, 5(3)/(4), is less than 5 because it is the product of 5 and a fraction less than 1.
When we multiply 7 by a number less than 5, the result will be less than 35.
Therefore, the product of 7 and 5(3)/(4) is less than 35.
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how do i solve this?
Step-by-step explanation:
it is a quadrilateral.
the sum of all angles in a quadrilateral is always 360°.
so,
360 = x + x + 2x + 7 + 2x + 5 = 6x + 12
348 = 6x
x = 348/6 = 58°
that's it.
i need help with this
The value of x and y in the line segment are 6 and 6.5 units repsectively.
How to find length of line segment?The lines are three parallel lines cut by two transversal lines. The transversal lines that cut across the parallel lines have same length at intervals .
Using the information in the diagram let's find the value of x and y in the diagram.
Therefore,
2x + 1 = x + 7
2x - x = 7 - 1
x = 6 units
Therefore,
3y - 8 = y + 5
3y - y = 5 + 8
2y = 13
divide both sides by 2
y = 13 / 2
y = 6.5 units
Therefore,
x = 6 units
y = 6.5 units
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Help!!!!
I’m on the last question
Answer: 28
Step-by-step explanation: Both Of Those Triangles Are Equal. That Means They Both Equal 14. So If We Multiply 14 With 2, We Would Get 28 cm!
Hoped This Helped!
Answer:
28cm
Step-by-step explanation:
its a perfect rectangle so both triangle are Reflexive property so they would be the same size