calculate EG if a=5 and b=15

Answer:

The simplified expressions are

1) a - b + c + m + n

2) x + a + m - 2

3) m + a - k - b

4) x + a - b - c + d

Step-by-step explanation:

1) a - (b - c) + (m + n)

To simplify the above expression, we have;

a - (b - c) + (m + n)  = a - b - (-c) + m + n = a - b + c + m + n

2) x + a + (m - 2)

To simplify the above expression, we have;

x + a + (m - 2) = x + a + m - 2

3) m + (a - k - b)

To simplify the above expression, we have;

m + (a - k - b) =  m + a - k - b

4) x + (a - b) - (c - d) = x + a - b - c -(- d)) = x + a - b - c + d

Answer:

C

Step-by-step explanation:

4:10 ≠ 6:8

Answer:

y = [tex]\frac{1}{2} x - 3[/tex]

x + y = 18

Step-by-step explanation:

Let the kitten's weight be y and the cat's weight be x

Condition # 1:

y = [tex]\frac{1}{2} x - 3[/tex]

Condition # 2:

x + y = 18

Answer:

6th

Step-by-step explanation:

the chart says not, 7th has majority

Answer:

The completed table is

x | 0 | 6 | 12

y | 0 | 2 | 4

Step-by-step explanation:

It is given that y is (1/3) as large as x. That is,

y = (x/3)

x | 0 | 6 | 12

y | ? | ? | ?

y = (x/3)

When x = 0,

y = (0/3) = 0

when x = 6,

y = (6/3) = 2

when x = 12,

y = (12/3) = 4

The completed table is thus

x | 0 | 6 | 12

y | 0 | 2 | 4

Hope this Helps!!!

The values of x will be 0 , 18 , 36 respectively when the value of y is 0, 6, 12.

Given,

y is 1/3 times as large as x.

So, [tex]x=3y[/tex].

We have to calculate the value of x when y is given .

1. when [tex]y=0[/tex]

Then, [tex]x=0[/tex]

2.when, [tex]y=6[/tex]

Then, [tex]x=18\\[/tex]

3. When [tex]y=12[/tex]

[tex]x=3\times 12\\x=36[/tex]

Hence, the values of x will be 0 , 18 , 36 respectively when the value of y is 0, 6, 12.

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Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Following are the description of the given points:

(a) This is a system of probability, which possibility occurs inside an intended manner whenever they choose this specific point of origin from 1 to 100 with no one reserve the possibility about who gets throughout the survey.  

(b) Its method is different from the random sampling technique with the base available. For example, two individuals whose names identical to both the list have no chance to join within the survey.  

(c) its sample is objective to its everyone can enter the test in equal measure.

Answer:

4/5

Step-by-step explanation:

Slope(m) = (y2-y1)/(x2-x1)

Pick two points on your graph that are closest to clear values. (By that I mean you shouldn't pick points that aren't obvious unless you have to.)

For instance, I see the points (-2,0) and (3,4) to be clear; so we don't have to approximate anything.

You could plug these in in a any order but I'm going to let Point 1=(-2,0) and Point 2=(3,4). So:

m=(4-0)/(3--2)=(4/5)

Slope=4/5

Answer:

Geometric sequence

Step-by-step explanation:

Because this is not adding or subtraction, but multiplication, this would be a geometric sequence.

Answer:

Step-by-step explanation:

The equation of a linear function:

y = mx + b

m - slope

b - y-intercept

x = 3 - it's a vertical line. It's not equation of a linear function

y = 16 - it's a horizontal line. It's an equation of a linear function

where m = 0, b = 16

y = -3x + 10 - it's an equation of a linear function

where m = -3, b = 10

y = 3x² + 1 - it's a quadratic function ( x² ).

Answer:

y = 16 and y = -3x + 10

Step-by-step explanation:

hello

Answer:

8

Step-by-step explanation:

8^3 = 8*8*8 = 512

la base = base = 8

Answer:

(2x+15)(x−1)

Step-by-step explanation:

Factor 2x2+13x−15

2x2+13x−15

=(2x+15)(x−1)

Here is the answer good sir

Answer:

(x - 1)(2x + 15)

Step-by-step explanation:

Well let's make the square look at the image below ↓

By looking at the image we can tell that the given equation factored is

(x - 1)(2x + 15).

Hope this helps :)

Answer:

76.

Step-by-step explanation:

It is given that N is a 2-digit number.

Last two digits of N^2 is the same as N.

We know that, a number is even if it ends with 0,2,4,6,8.

[tex]2^2=4,4^2=16,6^2=36,8^2=64[/tex]

If 0 is in end then we get two zeros in the square of that number.

It is clear that, number should ends with 6 to get the same number at the end.

[tex]16^2=256[/tex]

[tex]26^2=676[/tex]

[tex]36^2=1296[/tex]

[tex]46^2=2116[/tex]

[tex]56^2=3136[/tex]

[tex]66^2=4356[/tex]

[tex]76^2=5776[/tex]

[tex]86^2=7396[/tex]

[tex]96^2=9216[/tex]

It is clear that last two digits of (76)^2 is the same as 76.

Therefore, the required number is 76.

Answer:

[tex]\frac{\sqrt{3} }{4} a^2[/tex]

Step-by-step explanation:

To find the area of an equilateral triangle, we can apply a formula.

[tex]A=\frac{\sqrt{3} }{4} s^2[/tex]

[tex]A= area\\s=side \: length[/tex]

The side length is given a.

Plug a in the formula as the side length.

[tex]A=\frac{\sqrt{3} }{4} a^2[/tex]

Answer:

3 square root over 4 a square

Step-by-step explanation:

Answer: Stratified Sampling

Step-by-step explanation: Stratified Sampling involves creating subdivisions of the population such that each subdivisions is seen as a subgroup or smaller chunk of the population which is split based on certain criteria or attribute. The stratified random sampling may be employed in delineating certain characteristics or to investigate further how a feature or characteristics vary between one subdivision to the other.

In the scenario above, the researcher made use of the stratified sampling by performing a random sampling selection of its subjects based on the different subdivisions of students available in the college

Answer:

It's the first option

Step-by-step explanation:

They've constructed two angle bisectors and have shown you where they meet. Their point of intersection is the center of the inscribed circle (the incenter). Therefore, the last step is finding the altitudes (perpendicular lines) from the incenter to all the sides.

Answer:

[tex]-8y^{25}\\-9y^6\\5y^5[/tex]

Step-by-step explanation:

First one.

[tex]((-y)^5)(8y^{20})=-y^5*8y^{20}=-8y^{5+20}=-8y^{25}[/tex]

Second one

[tex]((-y)^{5} )(9y)=-y^5*9y=-9y^{5+1}=-9y^6[/tex]

and last one

[tex]((-y)^5)(-5)=-y^5*(-5)=5y^5[/tex]

Hi!

This problem is the fifth in a series of seven about ratios. At first glance the problem may look to be beyond 6.RP.1, which limits itself to “describe a ratio relationship between two quantities. However, even though there are three quantities (the number of each candidates' votes), they are only considered two at a time.

In the first problem students define the simple ratios that exist among the three candidates. It opens an opportunity to introduce unit rates.

The subsequent problems are more complex. In the second problem, students apply their understanding of ratios to combine two pools of voters to determine a new ratio. In the third problem, students apply a known ratio to a new, larger pool of voters to determine the number of votes that would be garnered.

Solutions

Solution: Question #1

a. John's votes to Will's, 16 to 8, or 2 to 1. Marie's votes to Will's, 12 to 8, 3 to 2, or 32 to 1, the unit ratio. Marie's votes to John's, 12 to 16, 3 to 4, or 34 to 1, the unit ratio.

Solution: Question #2

2. Will now has 8 + 12 = 20 votes to John's 16 votes, so the ratio of Will's votes to John's votes is 20 : 16, 5 : 4, or 54 : 1, the unit ratio.

Solution: Question #3 - Computing votes

There are different ways to approach this problem, but both begin with the fact that Will gets votes in a 5 to 4 ratio compared with John and require recognizing that a 5 to 4 ratio means a total of 9 equal parts. Then it is straightforward to compute:

59×90=50 votes for Will

49×90=40 for John

50−40=10 more votes for Will.

Solution: Question #3 - Applying fractions

One can solve the problem by working fractions by recognizing that Will getting votes in a 5 to 4 ratio means a total of 9 equal parts. It follows that Will gets 59 of the 90 votes and John gets 49 of the 90 votes:

59−49=19 of the voters

19×90=10 more votes for Will

Solution: Question #3 - Equivalent Ratios

An alternate very basic solution to Question 3 involves creating a series of equivalent ratios. This approach may be selected by students who are still developing an understanding of proportional situations. Students may begin with the ratio of 5 to 4 and proceed to find a ratio such that the sum of numerator and denominator is 90. This sequence may appear as follows:

5/4 = 10/8 = 15/12 = 20/16 = 25/20 = 30/24 = 35/28 = 40/32 = 45/36 =50/40

Then 50 - 40 = 10 more votes for Will

Overall answer

10 more votes for will

Answer:

[tex]h=64t-4.9t^{2}[/tex]

Please refer to the attached graph.

Step-by-step explanation:

Given that

Initial velocity of rocket = 64 and is launched vertically.

To find:

Quadratic equation in time to represent the height of rocket in feet.

Solution:

Unit of initial velocity is not given in the question statement, let the velocity be in feet/second only.

Initial velocity, u  = 64 feet/s

The acceleration will be = -g because it is going opposite to gravitational force so it will be negative acceleration motion (speed will be decreasing) so -g will be the acceleration.

Formula for distance traveled is given as:

[tex]s=ut+\dfrac{1}{2}at^2[/tex]

Here Let us represent s by 'h'

a = -g = 9.8 m/[tex]s^2[/tex]

Let us put the known values in the formula:

[tex]h=64t+\dfrac{1}{2}(-9.8)t^2\\\Rightarrow h =64t-4.9t^2[/tex]

It is a quadratic equation, the equation represents the graph of a parabola.

Please refer to the attached graph.

Value of height is 0 at 0 second and ~13 seconds

Answer:

13

Step-by-step explanation:

Answer:

Your correct answer is = 5x + 45

Step-by-step explanation:

To find this, you will need to learn to multiply polynomials.

Answer:

498 m

Step-by-step explanation:

The AAA theorem states that triangles are similar if all three corresponding angles are equal.

1. Compare triangles FHS and ILS

(a) Reason for similarity

∠F = ∠I = 90°

∠S is common.

∴ ∠H = ∠L

(b) Calculate SL

[tex]\begin{array}{rcl}\dfrac{SF}{SH} & = & \dfrac{SI}{SL}\\\\\dfrac{225}{380} & = & \dfrac{225 + 475}{SL}\\\\225SL & = & 380 \times 700\\& = & 266000\\SL & = & \textbf{1182 m}\\\end{array}[/tex]

2. Compare triangles ILS and GLE

(a) Reason for similarity

∠I = ∠G = 90°

∠L is common.

∴ ∠S = ∠E

(b) Calculate LE

[tex]\begin{array}{rcl}\dfrac{IS}{GE} & = & \dfrac{LS}{LE}\\\\\dfrac{700}{180} & = & \dfrac{1182}{LE}\\\\700LE & = & 180 \times 1182\\& = & 212800\\LE & = & \textbf{304.0 m}\\\end{array}[/tex]

3. Calculate EH

               LE + EH + HS = LS

304.0 m + EH + 380 m = 1182 m

                  EH + 684 m = 1182 m

                                 EH = 498 m

The distance from E to H is 498 m.

Answer:

(0,-3)

Step-by-step explanation:

Answer:  n< 3

Step-by-step explanation:

5n - 14 < 1 .  add 14 to both sides

5n -14 +14 < 1 + 14

5n +0 < 15

5n < 15   divide both sides by 5 .5n/5 = 15/5

n < 3

Answer:

20

Step-by-step explanation:

i got it right on a quiz

Height of a can is equal to [tex]\boldsymbol{6.99\,cm}[/tex].

Surface area of a cylinder [tex]=\pi r^2h[/tex] where [tex]r,h[/tex] denote radius, height of a cylinder respectively.

Surface area of a can [tex]=1406.72 \,cm^2[/tex]

Radius of a can [tex]=8 \,cm[/tex]

[tex]1406.72=\frac{22}{7}(8)^2h[/tex]

         [tex]h=6.99\,cm[/tex]

Therefore, height of a can is equal to [tex]\boldsymbol{6.99\,cm}[/tex]

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Answer:

B

Step-by-step explanation:

Answer:

Option 3

Step-by-step explanation:

The curve goes infinitely downwards, so y is infinitely negative while x is limited at the y axis, or x=0 which is the asymptote.

Answer:

two hours after the snow started melting, the depth of the snow would be 8 inches.

Step-by-step explanation:

The melting can be represented by a linear function of the snow depth (D(t)) as a function of time (t). We consider that the initial value is: 11 inches deep at time = 0 (zero). and then decreasing at a rate of 1.5 inches per hour (that is a negative slope = -1.5).

[tex]D(t)=11-1.5\,t[/tex]

Therefore, 2 hours after the snow started melting, one would have:

[tex]D(2)=11-1.5\,(2)=11-3=8\,\,inches[/tex]

Answer:

Options (B) and (C)

Step-by-step explanation:

The given expression is [tex](d^{\frac{1}{8}})^5[/tex]

By simplifying this expression,

[tex](d^{\frac{1}{8}})^5[/tex]

= [tex](\sqrt[8]{d})^{5}[/tex]

Option (B)

Similarly,

[tex](d^{\frac{1}{8}})^5[/tex]

= [tex]d^{\frac{5}{8}}[/tex]

= [tex](d^{5})^{\frac{1}{8}}[/tex]

Option (C)

Therefore, Options (B) and (C) will be the correct options.

Answer:

Step-by-step explanation:

Given the value of a family's home, in Camrose AB, given by the following exponential function f(x) = 130000(1.06)^x, where x is the number of years after the family purchases the house for $130,000. In order to calculate the best estimate for the instantaneous rate of change in the value of the home when the family has owned it for 5 years, we will have to substitute x =5 in the given function and solve as shown;

f(x) = 130000(1.06)ˣ

f(5) = 130000(1.06)⁵

f(5) = 130000*(1.06)⁵

f(5) = 130000*1.338226

f(5) = 173,969.38

Hence, the instantaneous rate of change in the value of the home when the family has owned it for 5 years is approximately  $173,969

Answer:

she walked 6 miles.

Step-by-step explanation:

We know that Ruth walks at a speed of 4 mph and it took her 1.5 hours to walk from her home to the library (from 9 to 10.30).

We can solve this using a rule of three:

If she walks 4 miles in 1 hour, how many hours did she walk in 1.5 hours?

1 hour           4 miles

1.5 hours       x miles

Solving for x we get:

[tex]x=\frac{1.5(4)}{1} =6[/tex] miles

Thus, she walked a distance of 6 miles

The distance between her home and the library is the number of meters between them.

The distance walked is 6 m

The speed is given as:

[tex]\mathbf{Speed = 4mph}[/tex]

The time spent walking is calculated as:

[tex]\mathbf{Time = 10:30am - 9:00am}[/tex]

[tex]\mathbf{Time = 1.5\ hrs}[/tex]

So, the distance is calculated as:

[tex]\mathbf{Distance = Speed \times Time}[/tex]

Substitute known values

[tex]\mathbf{Distance = 4mph \times 1.5hrs}[/tex]

[tex]\mathbf{Distance = 6m}[/tex]

Hence, the distance walked is 6 m

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