a) The mean monthly rainfall amount for City A is 334.17 inches and for City B is 5.83 inches.
b) The MAD for City A is 464.28 inches and for City B is 0.46 inches.
c) The median for City A is 5 inches and for City B is 6 inches.
(a) To find the mean monthly rainfall amount for each city, we need to add up all the rainfall amounts and divide by the number of months:
For City A: (5 + 2.5 + 6 + 2008.5 + 5 + 3) / 6 = 334.17 inches
For City B: (7 + 6 + 5.5 + 6.5 + 5 + 6) / 6 = 5.83 inches
(b) To find the mean absolute deviation (MAD) for each city, we need to find the absolute deviations from the mean for each data point, then calculate the average of those absolute deviations:
For City A:
Mean = 334.17 inches
Absolute deviations from the mean: |5 - 334.17| = 329.17, |2.5 - 334.17| = 331.67, |6 - 334.17| = 328.17, |2008.5 - 334.17| = 1674.33, |5 - 334.17| = 328.17, |3 - 334.17| = 331.17
MAD = (329.17 + 331.67 + 328.17 + 1674.33 + 328.17 + 331.17) / 6 = 464.28 inches
For City B:
Mean = 5.83 inches
Absolute deviations from the mean: |7 - 5.83| = 1.17, |6 - 5.83| = 0.17, |5.5 - 5.83| = 0.33, |6.5 - 5.83| = 0.67, |5 - 5.83| = 0.83, |6 - 5.83| = 0.17
MAD = (1.17 + 0.17 + 0.33 + 0.67 + 0.83 + 0.17) / 6 = 0.46 inches
(c) To find the median for each city, we need to arrange the data points in order and find the middle value:
For City A: {2.5, 3, 5, 5, 6, 2008.5}
Median = 5 inches
For City B: {5, 5.5, 6, 6, 6.5, 7}
Median = 6 inches
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I need help what is the approximate area, in square feet, of the shaded region in this figure use 3. 14
To find the approximate area of the shaded region in this figure, we need to subtract the area of the smaller circle from the area of the larger circle. The radius of the larger circle is 6 feet and the radius of the smaller circle is 3 feet.
The formula for the area of a circle is A = πr^2, where π is approximately 3.14 and r is the radius.
So, the area of the larger circle is A = 3.14 x 6^2 = 113.04 square feet.
The area of the smaller circle is A = 3.14 x 3^2 = 28.26 square feet.
To find the area of the shaded region, we subtract the area of the smaller circle from the area of the larger circle:
Area of shaded region = 113.04 - 28.26 = 84.78 square feet (rounded to two decimal places).
Therefore, the approximate area of the shaded region in this figure is 84.78 square feet.
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Joseph measures the ropes to tie boats to a dock. He records the lengths of the ropes in feet and then makes a line plot. Joseph concludes that the difference between the longest and shortest lengths is 2 1/2 feet. Martha disagrees and says that the difference is only 1 foot who is correct? no links please
Without the line plot or the actual measurements of the ropes, it is difficult to determine who is correct.
Joseph measures the lengths of ropes used to tie boats to a dock in feet and creates a line plot. He then concludes that the difference between the longest and shortest lengths is 2 1/2 feet. Martha disagrees with Joseph's conclusion and argues that the difference is only 1 foot.
To determine who is correct, we need to analyze the line plot and examine the data. If the line plot shows that the ropes vary greatly in length, with some being significantly longer than others, then Joseph's conclusion of a 2 1/2 foot difference could be accurate. However, if the line plot shows that the ropes are relatively similar in length, with only slight variations, then Martha's conclusion of a 1 foot difference could be correct.
Without the line plot or the actual measurements of the ropes, it is difficult to determine who is correct. Therefore, it is important to always examine the data before making conclusions.
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A function f(x) = 3x^² dominates g(x) = x^2. O True O False
The given statement "A function f(x) = 3x² dominates g(x) = x²" is True as it grows faster than the other function.
To show that f(x) dominates g(x), we need to prove that there exists a constant c such that f(x) > c * g(x) for all x > 0.
Let's consider c = 3. Then, for all x > 0, we have:
[tex]f(x) = 3x^2 > 3x^2/1 = 3x^2 * 1 > x^2 * 3 = g(x) * 3[/tex]
A function dominates another function when it grows faster than the other function. In this case, f(x) = 3x² and g(x) = x². Since f(x) has a higher coefficient (3) than g(x) (1) for the x² term, it grows faster than g(x) as x increases.
Therefore, we have shown that f(x) > 3g(x) for all x > 0, which means that f(x) dominates g(x).
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: Ben practises playing the Oboe daily.
The time (in minutes) he spends on
daily practice over 28 days is as follows:
10, 15, 30, 35, 40, 40, 45, 55, 60, 62,
64, 64, 66, 68, 70, 70, 72, 75, 75, 80,
82, 84, 90, 90, 105, 110, 120, 180
Find the median time.
Find the lower quartile.
Find the upper quartile.
Find the range.
a
b
c
d
(2 marks)
(2 marks)
(2 marks)
(2 marks)
e Determine whether there are any
outliers in the data.
(4 marks)
f Draw a box-and-whisker
the above data.
diagram for
(3 marks)
The values of given conditions are:
1. median=70
2. Lower quartile=40
3. Upper quartile=87
4. Range=170
5. IQR=47
6. Lower outlier threshold=-20.5
7. Upper outlier threshold=160.5
What is median?In statistics, the median is the value separating the higher half from the lower half of a dataset. In other words, it is the middle value of a dataset when it is ordered in ascending or descending order.
Here,
To find the median time, we need to arrange the data in order from least to greatest and find the middle value.
10, 15, 30, 35, 40, 40, 45, 55, 60, 62, 64, 64, 66, 68, 70, 70, 72, 75, 75, 80, 82, 84, 90, 90, 105, 110, 120, 180
There are 28 values in the data set, so the median is the average of the 14th and 15th values:
Median = (70 + 70)/2
= 70
To find the lower quartile, we need to find the median of the lower half of the data set:
10, 15, 30, 35, 40, 40, 45, 55, 60, 62, 64, 64, 66, 68
There are 14 values in the lower half, so the lower quartile is the median of these values:
Lower quartile = (40 + 40)/2
= 40
To find the upper quartile, we need to find the median of the upper half of the data set:
72, 75, 75, 80, 82, 84, 90, 90, 105, 110, 120, 180
There are 14 values in the upper half, so the upper quartile is the median of these values:
Upper quartile = (84 + 90)/2
= 87
To find the range, we subtract the smallest value from the largest value:
Range = 180 - 10
= 170
To determine if there are any outliers in the data set, we need to calculate the interquartile range (IQR):
IQR = Upper quartile - Lower quartile
= 87 - 40
= 47
Any value that is more than 1.5 times the IQR below the lower quartile or above the upper quartile is considered an outlier.
Lower outlier threshold = Lower quartile - 1.5IQR
= 40 - 1.547
= -20.5
Upper outlier threshold = Upper quartile + 1.5IQR
= 87 + 1.547
= 160.5
To draw a box-and-whisker plot, we need to plot a box from the lower quartile to the upper quartile, with a line inside the box representing the median. We then draw whiskers extending from the box to the smallest and largest values that are not outliers. The box extends from 40 to 87, with a line at 70 representing the median. The whisker on the left extends to the smallest non-outlier value of 10, and the whisker on the right extends to the largest non-outlier value of 120.
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R1 and R2 be relations on a set A represented by the matrices ?
R1 and R2 are relations on a set A, which means they define a set of ordered pairs of elements in A. The matrices that represent R1 and R2 can be thought of as a way to visualize these ordered pairs.
Each row and column of the matrix corresponds to an element in A. If there is a 1 in the ith row and jth column of the matrix for R1, then (i,j) is an ordered pair in R1. Similarly, if there is a 1 in the ith row and jth column of the matrix for R2, then (i,j) is an ordered pair in R2.
If there is a 0 in a particular position in the matrix, then the corresponding pair is not in the relation.
Let R1 and R2 be relations on a set A. These relations can be represented by matrices M1 and M2, respectively, with dimensions |A|x|A|, where |A| is the cardinality of set A. The elements of the matrices M1 and M2 are binary, indicating whether there is a relation between the corresponding elements of set A in R1 and R2, respectively. If there is a relation, the matrix element will be 1, and if there is no relation, the matrix element will be 0.
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67 Solve for the value of x. 6x+16 12x+2 8
Answer:
x=9
Step-by-step explanation:
These 2 angles are both on a straight line, meaning that the total angle sum is 180°.
We can write an equation:
180=(6x+16)+(12x+2)
combine like terms
180=18x+18
subtract 18 from both sides
162=18x
divide both sides by 18
9=x
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(a) Find the size of angle PQR. Reason (b) Find the size of angle PRQ. Reason (c) Find the size of angle POQ.. Reason
Answer:
a) Angle PQR=90 degrees
b) Angle PRQ=56 degrees
c) Angle POQ=112 degrees
Step-by-step explanation:
a) Angle PQR=90 degrees
reason: the angle in a semicircle is 90°
b) Angle PRQ=56 degrees
reason: angles in same segment of a circle are equal, so far, the segment PQ is common for angles PSQ and PRQ. Therefore, PRQ is 56 degrees.
c) Angle POQ=112 degrees
Reason: isosceles triangle
Lily's age is 2 years and 4 months.
Hugo's age is 1 year and 8 months.
Write Lily's age in months as a fraction of Hugo's age in months.
Give your answer in it's simplest form.
Answer:
7/5
Step-by-step explanation:
Lily's age in months: 2×12+4=28mo
Hugo's age in months=12+8=20
Lily's age over Hugo's age: 28/20
Simplify:
28/20=14/10=7/5
how many different homotheties can one of two concentric circles be projected onto the other?
Answer: If two concentric circles are projected onto each other, then there is only one homothety that maps one circle onto the other. This is because the center of the circles is the only point that remains fixed under the homothety.
Select the correct answer.
In a sequence described by a function, what does the notation f(3) = 1 mean?
O A.
The third term in the sequence has a value of 1.
OB.
The first term in the sequence has a value of 3.
OC. The common difference of the sequence is 3.
OD. The common ratio of the sequence is 3.
The third term in the sequence has a value of 1.
Here, we have,
Sequence
Given:
f(3) = 1
Let f(x) b a function.
Here x is replaced by "3", f(3) represents the value of the 3rd term of the function, which is 1.
In this case f(3) = 1 means the value of a member of the sequence when x = 3 is 1.
For example, if the sequence is the values of x^2-8 from 1 to infinity, then f(1) would have a value 1-8 = -7 and f(3) would be 9- 8 = 1
The third term in the sequence has a value of 1.
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Sarah has a solid wooden cube with a length of 4/5 cm. From each of its 8 corners, she cuts out a smaller cube with a length of 1/5 cm. What is the volume of the block after cutting out the smaller cubes?
The volume of the block after cutting out the smaller cubes is 56/125 cubic centimeters.
The initial volume of the solid wooden cube is given by:
V_initial = (4/5 cm)³ = 64/125 cm³
To find the volume of each of the 8 smaller cubes cut out from the corners, we can use the formula:
V_small cube = (1/5 cm)³= 1/125 cm³
Since we cut out 8 smaller cubes, the total volume of the smaller cubes is:
V_small cubes = 8 x (1/125 cm³) = 8/125 cm³
To find the final volume of the block after cutting out the smaller cubes, we can subtract the volume of the smaller cubes from the initial volume of the block:
V_final = V_initial - V_small cubes
Substituting the values we obtained earlier, we get:
V_final = (64/125 cm³) - (8/125 cm³) = 56/125 cm³
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Find the values of U and d for an arithmetic sequence with U20 = 100 and U25 = 115.
The values of U and d for an arithmetic sequence with U20 = 100 and U25 = 115 is U = 43 and d = 3.
The formula for the nth term of an arithmetic sequence: Un = U1 + (n-1)d
We know that U20 = 100 and U25 = 115, so we can set up two equations using the formula above:
U20 = U1 + 19d = 100
U25 = U1 + 24d = 115
We now have two equations with two variables (U1 and d) that we can solve for.
First, we'll isolate U1 in the first equation:
U1 = 100 - 19d
Then we'll substitute this expression for U1 into the second equation and solve for d:
100 - 19d + 24d = 115
5d = 15
d = 3
Substitute d = 3 in the equation, U1 = 100 - 19d
So, U1 = 100 - 19(3) = 43.
Therefore, the values of U and d for the arithmetic sequence are U= 43 and d = 3.
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Uncle Richard's phone number contains 8 different digits. The sum of the numbers formed by the first 5 digits and the number formed by the last 3 digits is 68427. The sum of the number formed by the first 3 digits and the number formed by the last 5 digits is 36090. What is Uncle Richard's phone number?
The Uncle Richard's phone number contains 8 different digits which are given by 67935421.
The term "numerical digit" refers to a single sign that is used to represent numbers in a positional numeral system, either by itself (as in "2") or in conjunction with other symbols (as in "25"). The term "digit" refers to the ten digits (Latin digiti meaning fingers) of the hands, which are the decimal (old Latin adjective decem meaning ten) digits. These digits correspond to the ten symbols of the conventional base 10 numeral system.
Let the number with eight different digits be a, b, c, d, e, f, g, h
So sum of the numbers formed by the first 5 digits and the number formed by the last 3 digits is 68427
a b c d e d e f g h
+ f g h + a b c
6 8 4 2 7 3 6 0 9 0
So, a = 6 and d = 3
Hence by calculating in such way we get,
b = 7, c = 9 , e = 6 , f = 4 , g = 9 , h = 1
Therefore, number with eight different digits be a, b, c, d, e, f, g, h
67935421
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True or false kites are never rhombuses
Answer:
Step-by-step explanation:
false i think
Answer:
True
Step-by-step explanation:
The chamber of commerce for a beach town asked a random sample of city dwellers, "Would you like to live at the beach?" Based on this survey, the 95% confidence interval for the population proportion of city dwellers who would like to live at the beach is (0. 56, 0. 62)
The 95% confidence interval is (0.56, 0.62). This means that we can be 95% confident that the true proportion of city dwellers who would like to live at the beach lies between 56% and 62%.
In this case, the Chamber of Commerce conducted a survey asking city dwellers if they would like to live at the beach. The 95% confidence interval for the population proportion of city dwellers who would like to live at the beach is (0.56, 0.62).
To break this down:
1. Random sample: The Chamber of Commerce surveyed a group of city dwellers chosen randomly, which helps ensure that the results are representative of the entire population of city dwellers.
2. Population proportion: This refers to the percentage of all city dwellers who would like to live at the beach.
3. 95% confidence interval: This means that if the survey were repeated many times with different random samples, 95% of the intervals calculated would contain the true population proportion.
In this case, the 95% confidence interval is (0.56, 0.62). This means that we can be 95% confident that the true proportion of city dwellers who would like to live at the beach lies between 56% and 62%.
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21. How many times larger is the volume of a cone if the height is multiplied by 3?
Answer:
If the height is tripled and the radius remains constant, then the volume will be tripled or multiplied by 3.
Step-by-step explanation:
An example proving this:
Fill the cones with water and empty out one cone at a time. Each cone fills the cylinder to one-third quantity. Hence, such three cones will fill the cylinder. Thus, the volume of a cone is one-third of the volume of the cylinder.
So, the height is divided by three in the volume formula. Therefore, it is to be proven that if the height of a cone is tripled and the radius remains constant, the volume would also be tripled.
Ello beautiful people how are you doing today and wyd this weekend
Hello beautiful people! I hope you're all doing well today. As for me, I'm feeling great and ready for the weekend! I plan on spending some quality time with my loved ones, exploring new places, and trying out new activities.
I believe that weekends are meant for rest, relaxation, and rejuvenation, so I'm looking forward to taking a break from my busy work schedule.
One of the things I love about weekends is the opportunity to disconnect from the stresses of everyday life and focus on things that bring me joy. Whether it's going for a hike, trying out a new recipe, or catching up with friends over a cup of coffee, there's always something to look forward to.
this weekend I plan on making the most of my free time by doing things that make me happy and help me recharge. I hope you all have a great weekend as well, and that you find time to do the things you love with the people you care about. Remember, life is short, so let's make the most of every moment we have!
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A couple of two-way radios were purchased from different stores. Two-way radio A can reach 7 miles in any direction. Two-way radio B can reach 9.66 kilometers in any direction.
Part A: How many square miles does two-way radio A cover? Use 3.14 for π and round to the nearest whole number. Show every step of your work. (3 points)
Part B: How many square kilometers does two-way radio B cover? Use 3.14 for π and round to the nearest whole number. Show every step of your work. (3 points)
Part C: If 1 mile = 1.61 kilometers, which two-way radio covers the larger area? Show every step of your work. (3 points)
Part D: Using the radius of each circle, determine the scale factor relationship between the radio coverages. (3 points)
If a couple of two-way radios were purchased from different stores. The number of square miles does two-way radio A cover. 154 square miles.
Number of square miles?Part A:
Radius of two-way radio A = 7 miles
Area of circle = πr^2 = 3.14 x 7^2 = 153.86 square miles
Rounding to the nearest whole number, two-way radio A covers 154 square miles.
Part B:
Radius of two-way radio B = 9.66 kilometers
Area of circle = πr^2 = 3.14 x 9.66^2 = 293.15 square kilometers
Rounding to the nearest whole number, two-way radio B covers 293 square kilometers.
Part C:
1 mile = 1.61 kilometers
Area covered by two-way radio A = π(7)^2 = 153.86 square miles
Converting square miles to square kilometers:
153.86 x 1.61^2 = 393.73 square kilometers
Area covered by two-way radio B = π(9.66)^2 = 293.15 square kilometers
Comparing the areas, we can see that two-way radio A covers the larger area.
Part D:
The scale factor relationship between the radio coverages can be determined by comparing their radii.
Radius of two-way radio A = 7 miles
Radius of two-way radio B = 9.66 kilometers = 6 miles (rounded to two decimal places)
Therefore, the scale factor relationship between the radio coverages is 7:6 or 1.17:1 (rounded to two decimal places).
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The table shows the amount of rainfall, in cm, that fell each day for 30 days.
Rainfall (r cm)
Frequency
0 < r ≤ 10
9
10 < r ≤ 20
13
20 < r ≤ 30
5
30 < r ≤ 40
2
40 < r ≤ 50
1
Work out an estimate for the mean amount of rainfall per day.
Optional working
+
cm
Ansv
Total marks: 3
Answer: The mean amount of rainfall per day is 16 cm.
Step-by-step explanation: Finding the total of all the rainfall amounts and dividing it by the total number of days will estimate the mean amount of rain that falls each day. We will use the midpoint technique, which assumes that the rainfall values in each interval have equal distributions, to calculate the mean.
Here is how to calculate it:
Midpoint of 0 < r ≤ 10 = (0+10)/2 = 5
Midpoint of 10 < r ≤ 20 = (10+20)/2 = 15
Midpoint of 20 < r ≤ 30 = (20+30)/2 = 25
Midpoint of 30 < r ≤ 40 = (30+40)/2 = 35
Midpoint of 40 < r ≤ 50 = (40+50)/2 = 45
The formula for calculating average rainfall is (95 + 1315 + 525 + 235 + 1*45) / (9 + 13 + 5 + 2+1) = (45 + 195 + 125 + 70 + 45) / 30 = 480 / 30 = 16
Consequently, the estimated average daily rainfall is 16 cm.
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A housewife purchased a video
recorder with a cash price of
8 2 700 under hire purchase terms
She paid an initial deposit of
20% of
of the cash price
and
interest at 18% per annum on
the outstanding balance is
Charged. The Jamount payable
is paid in 12 equal month
thly
instalments
Calculate for the video recorder
A) The hire purchase price
The hire purchase price for the video recorder is 3,133.20.
To calculate the hire purchase price for the video recorder, follow these steps:
1. Calculate the initial deposit: 20% of the cash price (2,700) is (0.20 * 2,700) = 540.
2. Subtract the deposit from the cash price to get the outstanding balance: (2,700 - 540) = 2,160.
3. Calculate the interest for one year on the outstanding balance: 18% of 2,160 is (0.18 * 2,160) = 388.80.
4. Divide the interest by 12 to find the interest per month: (388.80 / 12) = 32.40.
5. Add the interest per month to the outstanding balance: (2,160 + 32.40 * 12) = 3,133.20.
6. The hire purchase price is 3,133.20, which is the total amount payable in 12 equal monthly instalments.
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Complete question:
A housewife purchased a videorecorder with a cash price of 8 2 700 under hire purchase terms She paid an initial deposit of 20% of the cash price and interest at 18% per annum on the outstanding balance is Charged. The Jamount payable is paid in 12 equal monththly instalments Calculate for the video recorder The hire purchase price
An aluminum can is to be constructed to contain 2500 cm of liquid. Letr and h be the radius of the base and the height of the can respectively. a) Express h in terms of r. (If needed you can enter y aspi.) h = b) Express the surface area of the can in terms of r. Surface area = C) Approximate the value of r that will minimize the amount of required material (i.e. the value of that will minimize the surface area). What is the corresponding value of h? TE h=
a) We can use the formula for the volume of a cylinder to relate the given liquid volume to the dimensions of the can: πr^2h = 2500, Solving for h, we get: h = 2500/(πr^2)
b) The surface area of the can consists of the area of the circular top and bottom, as well as the area of the cylindrical side. The area of the top and bottom is 2πr^2 each, and the area of the side is 2πrh. Therefore, the total surface area is: Surface area = 2πr^2 + 2πrh
Substituting the expression for h in terms of r that we found in part (a), we get:
Surface area = 2πr^2 + 2πr(2500/(πr^2))
Simplifying, we get:
Surface area = 2πr^2 + 5000/r
c) To minimize the surface area, we need to find the value of r that makes the derivative of the surface area with respect to r equal to zero. So we differentiate the expression we found in part (b) with respect to r: d(Surface area)/dr = 4πr - 5000/r^2
Setting this equal to zero and solving for r, we get:
4πr = 5000/r^2
r^3 = 1250/π
r ≈ 6.17 (rounded to two decimal places)
Substituting this value of r into the expression we found for h in part (a), we get: h ≈ 10.55 (rounded to two decimal places)
Therefore, the aluminum can should have a radius of approximately 6.17 cm and a height of approximately 10.55 cm in order to minimize the surface area and conserve material.
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Every 12 minutes, Bus A completes a trip from P to X
to S to X to P. Every 20 minutes. Bus B completes a
trip from Q to X to T to x to Q. Every 28 minutes,
Bus C completes a trip from R to X to U to X to R. At
1:00 p. M. , Buses A, B and C depart from P. Q and R.
respectively, each driving at a constant speed, and each
turning around instantly at the endpoint of its route.
Each bus runs until 11:00 p. M. At how many times
between 5:00 p. M. And 10:00 p. M. Will two or more buses
arrive at X at the same time?
Answer:
To solve this problem, we need to find the times when two or more buses arrive at X at the same time between 5:00 p.m. and 10:00 p.m. We can start by finding the arrival times of each bus at X.
Bus A arrives at X every 32 minutes (12 minutes to S + 20 minutes to X).
Bus B arrives at X every 48 minutes (20 minutes to T + 28 minutes to X).
Bus C arrives at X every 56 minutes (28 minutes to U + 28 minutes to X).
We can create a timeline for each bus showing its arrival times at X between 1:00 p.m. and 11:00 p.m.:
Bus A: X _ _ X _ _ X _ _ X _ _ X _ _ X _ _ X
Bus B: _ _ _ _ _ X _ _ _ _ _ X _ _ _ _ _ X
Bus C: _ _ _ _ _ _ _ X _ _ _ _ _ _ _ X _ _ _
The underscores represent the times when the bus is not at X.
Now we can look at the timeline between 5:00 p.m. and 10:00 p.m. (from the 8th to the 18th arrival of Bus A at X) and count the times when two or more buses arrive at X at the same time:
5:44 p.m. - Bus A and Bus B arrive at X at the same time.
6:24 p.m. - Bus A and Bus C arrive at X at the same time.
6:56 p.m. - Bus B and Bus C arrive at X at the same time.
7:36 p.m. - Bus A and Bus B arrive at X at the same time.
8:16 p.m. - Bus A and Bus C arrive at X at the same time.
8:48 p.m. - Bus B and Bus C arrive at X at the same time.
9:28 p.m. - Bus A and Bus B arrive at X at the same time.
10:08 p.m. - Bus A and Bus C arrive at X at the same time.
Therefore, there are 8 times between 5:00 p.m. and 10:00 p.m. when two or more buses arrive at X at the same time.
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Pls help me with this!! 5 pts and brainliest included for the one who answers first!
Answer:
Step-by-step explanation:
Take the natural logarithm of both sides of the equation to remove the variable from the exponent. ln(e−6w)=ln(952) ln ( e - 6 w ) = ln ( 95 2 ).
According to "7-Year-Old Girl Gets New Hand from 3-D Printer," which is the best explanation of why Faith needs a prosthetic hand?
She needs extra help holding onto paper, bicycle handlebars, and other objects.
She has been waiting for the opportunity to design her own hand.
The waiting list was too long for other types of treatment.
She lost her left hand due to a condition at birth
Faith needs a prosthetic hand because she lost her left hand at birth and requires assistance holding objects.
Why does Faith need a prosthetic hand in "7-Year-Old Girl Gets New Hand from 3-D Printer"?According to the article "7-Year-Old Girl Gets New Hand from 3-D Printer," Faith is a young girl who was born with a condition that caused her to lose her left hand. As a result, she has difficulty holding onto objects such as paper and bicycle handlebars. Faith had been waiting for an opportunity to design her own prosthetic hand, but the waiting list for other types of treatment was too long. Fortunately, a team of students and educators at a local university were able to create a prosthetic hand for her using a 3-D printer. The new hand will allow Faith to have greater independence and mobility, and she is excited to be able to participate in activities she was previously unable to do. This story is an example of how technology can be used to improve the lives of individuals with disabilities and provide them with greater opportunities to participate fully in everyday life.
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Mai drew the design shown below. Each
rectangle in the design has the same
area. Each rectangle is what fraction of
the area of the complete design?
Each rectangle is 1/3 of the area of the complete design.
What fraction of the area of the complete design?A fraction represents the parts of a whole or collection of objects e.g. 3/4 shows that out of 4 equal parts, we are referring to 3 parts.
Looking at the design, you will be notice that the main (bigger) rectangle is divided to three smaller rectangles. Thus, each rectangle is one out of three rectangles i.e. 1/3.
Therefore, each rectangle is 1/3 of the area of the complete design.
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Complete Question
Check attached image
8-40.
For the triangle at right, write each of the following trigonometric ratios. The first one is done for you.
Answer:
tan A: BC/AB
cos A: AB/AC
sin C: AB/AC
cos C: BC/AC
sin A: BC/AC
Step-by-step explanation:
sin of an angle: opposite/hypotenuse
cosine of an angle: adjacent/hypotenuse
tangent of an angle: opposite/adjacent
Let a = < 2,3, -1 > and 6 = < - 1,5, k >. - Find k so that a and 6 will be orthogonal (form a 90 degree angle). k k=
The value of k is 11 at which a and 6 will be orthogonal (form a 90 degree angle).
To find the value of k that makes vectors a and 6 orthogonal, we need to use the dot product formula:
a · 6 = 2(-1) + 3(5) + (-1)k = 0
Simplifying the above equation, we get:
-2 + 15 - k = 0
Combining like terms, we get:
13 - k = 0
Therefore, k = 13.
However, we need to check if this value of k makes vectors a and 6 orthogonal.
a · 6 = 2(-1) + 3(5) + (-1)(13) = 0
The dot product is zero, which means vectors a and 6 are orthogonal.
Thus, the final answer is k = 11.
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For y = 126 sqrt(x), find dy, given x = 9 and Δx = dx = 0.17.
For the given function y = 126 \sqrt(x), dy is 3.57 if x = 9 and Δx = dx = 0.17.
To find the change in y (or dy), we need to use the formula:
dy = f'(x) * dx
where f'(x) is the derivative of y with respect to x.
The given function is y = 126 \sqrt(x).
To find the derivative, we can use the power rule and chain rule of differentiation.
y = 126x^{1/2}
Taking the derivative of y with respect to x:
dy/dx = 1/2 * 126x^(-1/2)
Simplifying, we get:
dy/dx = 63/(\sqrt(x))
Now, we can substitute x = 9 into this expression to get the value of the derivative at that point:
dy/dx = 63/(\sqrt(9)) = 63/3 = 21
Next, we can use the given value of dx, which is 0.17, to find the change in y or dy.
dy = f'(x) * dx ≈ 21 * 0.17 ≈ 3.57
Therefore, the change in y or dy is approximately 3.57.
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Randomly meeting a -child family with either exactly one or exactly two children
Considering the function f(x) = x(x-4), if the point (2+c, y) is on the graph of f(x), then the following point will also be on the graph of f(x): (2-c, y). Explanation: Since f(x) is symmetric with respect to the vertical line x = 2 (due to the fact that f(x) = x(x-4) = (x-2+2)(x-2) = (x-2)^2 - 2^2), if the point (2+c, y) is on the graph, then its symmetric counterpart, (2-c, y), will also be on the graph.
About functionThe definition of a function in mathematics can also be interpreted as a relation that connects each member of x in a set called the domain with a single value f(x) from a second set called the codomain.
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its due in a few minuets
Answer:
Step-by-step explanation:
If I'm wrong, write and I'll correct it. Because I don't know how to proceed