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The required subtraction problem that is represented on the number line is 3 -(-5). Option B is correct.

Given that,
To determine the subtraction problem that is represented on the number line.

A number line is defined as the number marked on the line calibrated into an equal number of units. For example -1, 0, 1, and so on.

Here,
The line marked above the number line from -5 to 3
The subtraction problem would be given as 3 - (-5)

Thus, the required subtraction problem that is represented on the number line is 3 -(-5). Option B is correct.

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Since questions seem to be incomplete,

The given solution is based on the question given below,
Which subtraction problem is represented by the number line?

A: 3-5

B: 3 - (-5)

C: 3-8

D: 3-(-8)

Answer:

16a

Step-by-step explanation:

14a+2=14+2+a=16a.

Since Barry is going to post-secondary school for three years, a personal line of credit is vital to pay for his education.

It should be noted that when a individual collects a loan, the person will have to pay it back with an extra amount as interest.

In this case, it's important for him to use his personal line or credit rather than collecting a student loan from people. This isn't good in this scenario.

Therefore, since Barry is going to post-secondary school for three years, a personal line of credit is vital to pay for his education.

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Answer:

15 years old

Step-by-step explanation:

Answer: 22

Step-by-step explanation:

this problem is solved by a system of equations

Let Arthur’s current age be represented by:a

His brother’s current age will be represented by: b

The first equation will be:

a = 7 + b

The second equation will be:

a + 8 = 2b

now we solve for the equations. Plug in a = 7+b into a in the second equation.
So now we have

b+7+8=2b

Simplify:

B+15=2b

15=b

We aren’t done yet though

Arthur’s brother is 15 years old but since he is 7 years older we need to add 7 to 15

Hence, Arthur is 22 years old.

We can understand dot plot by taking example of be the choice of foods that you and your friends ate for snacks.

Dot plots are used to represent small amounts of data. To analyze this chart, let's say four people are having a snack together. Snack selections are pizza, burgers, fries, and pasta. Using the dot plant, we can see that everyone chose pizza. Also, her 3 other people in your group added burgers to their snack plates. The graph also shows that two people in the group  added French fries and one person in the group added pasta to their meal.

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The number 1.092×[tex]10^{1}[/tex] is 15.6 times larger than 7×[tex]10^{-1}[/tex]

Given,

The first number = 1.092×[tex]10^{1}[/tex]  

The second number =7×[tex]10^{-1}[/tex]

Here,

Convert the given numbers to the simplest form

The first number 1.092×[tex]10^{1}[/tex] =1.092×10

=10.92

The second numbers 7×[tex]10^{-1}[/tex]= 7×0.1

=0.7

We know the division is one the basic arithmetic operations in the mathematics. It is the process of the splitting a particular amount or number into equal parts.

To find how many time larger 1.092×[tex]10^{1}[/tex] than 7×[tex]10^{-1}[/tex], we have to divide the first number by second number.

10.92 ÷ 0.7 =15.6

Hence, the number 1.092×[tex]10^{1}[/tex] is 15.6 times larger than 7×[tex]10^{-1}[/tex]

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Answer:

m∠a = 100°

m∠b = 100°

m∠c = 110°

Step-by-step explanation:

Calculation of m∠a

∠a is an exterior angle of ΔPST .
Therefore m∠a  = sum of the interior angles of ΔPST
m∠a = 30 + 70 = 100°

Calculation of m∠c

∠c and ∠PST are supplementary so their measures must add up to 180°
m∠c + 70° = 180° so m∠c = 180 - 70 = 110°

Calculation of m∠b
QRST is a quadrilateral.
The sum of the interior angles of the quadrilateral = 360°
So m∠a + m∠b + 50 + m∠c = 360°
We have already computed ∠a = 100° and ∠c = 110°
So 100 + m∠b + 50 + 110 = 360°
260 + m∠b = 360
m∠b = 360 - 260 = 100°

Answer:

5,7 given point its korrect now

The cost for 14 cranberry juice bottles would be $7.56

In this question, Sophia buys 13 bottles of cranberry juice at the corner store for a total cost of $7.02

If each bottle costs the same amount, we need to find the amount for 14 bottles of juice.

Let x be the cost of one bottle of cranberry juice.

13 bottles of cranberry juice costs $7.02

So, we get an equation,

13x = $7.02

We solve above equation to find the cost of 1 bottle of cranberry juice.

x = $0.54

By unitary method the cost for 14 cranberry juice bottles would be,

14 × 0.54 = $7.56

Therefore, the cost for 14 cranberry juice bottles would be $7.56

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The value of x from the given expression is 1

If the point M is on the line LN, then the equivalent addition postulate is expressed as;

LM+MN = LN

Given the following

LN=9,

MN =4x

LM=5x

Substitute

5x + 4x = 9

9x = 9

x =9/9

x = 1

Hence the value of x from the given expression is 1

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Answer:

[tex]27^{\frac{1}{3}} \quad 125^{\frac{2}{3}} \quad 9^{\frac{3}{2}}[/tex]

Step-by-step explanation:

Rewrite 9 as 3²:

[tex]\implies 9^{\frac{3}{2}}=\left(3^2\right)^{\frac{3}{2}}[/tex]

[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]

[tex]\implies 3^{(2 \cdot \frac{3}{2})}=3^3[/tex]

Therefore:

[tex]\implies 3^3= 3 \cdot 3 \cdot 3=27[/tex]

---------------------------------------------------------

Rewrite 27 as 3³:

[tex]\implies 27^{\frac{1}{3}}=\left(3^3\right)^{\frac{1}{3}}[/tex]

[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]

[tex]\implies 3^{(3 \cdot \frac{1}{3})}=3^1[/tex]

Therefore:

[tex]\implies 3^1=3[/tex]

---------------------------------------------------------

Rewrite 125 as 5³:

[tex]\implies 125^{\frac{2}{3}}=\left(5^3\right)^{\frac{2}{3}}[/tex]

[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]

[tex]\implies 5^{(3 \cdot \frac{2}{3})}=5^2[/tex]

Therefore:

[tex]\implies 5^2=5 \cdot 5=25[/tex]

---------------------------------------------------------

Solution

In order, from smallest to largest:

[tex]27^{\frac{1}{3}} \quad 125^{\frac{2}{3}} \quad 9^{\frac{3}{2}}[/tex]

Step 1) : We know that,

[tex]\begin{cases}P = 7000& \\r = 5.6 \% & \\ n = 4 & \\ t = 4 & \end{cases}[/tex]

Step 2) : Formulate and Substitute:

[tex]Substitute\begin{cases}P = 7000& \\ r = 5.6 \% & into \: formula \\ n = 4 & \\ t = 4 & \end{cases}[/tex]

[tex]\bf\longrightarrow{F = P * (1 + \frac{r}{n} )^{(n*t)}} [/tex]

Put the values according to the formula:

[tex]\bf\longrightarrow{F = 7000 * (1 + \frac{ \frac{5.67}{100} }{4} )^{(4*4)}}[/tex]

Step 3) : Evaluate the equation/expression:

[tex]\bf\longrightarrow{8768.1}[/tex]

Answer: 3.23

Step-by-step explanation:

Add 1/6 + 1/7 = 13/42 Take the reciprocal = 42/13 hrs ≈ 3.23 hrs

The expression of Mia's height in cm is 5 + x

The given parameters are

Mia's height = 5 cm taller than her sister

Her sister's height  = x

The parameter "Mia's height = 5 cm taller than her sister" means that

Mia's height = 5 cm + her sister's height

Substitute Her sister's height  = x in Mia's height = 5 cm + her sister's height

Mia's height = 5 cm + x

This means that the expression of Mia's height in cm is 5 + x

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Answer:

Yes

Step-by-step explanation:

Imagine you have 1 cup. It’s 8 oz. Then imagine someone came up and doubled the # of ounces you have. Now you have 16 oz or 2 cups. 2 cups is double one.

This isn’t a good explanation, sorry lol

But honestly, just think of it as a fraction, what you do to the top, you do to the bottom. As long as you do the same thing to the cups that you did to the ounces, the cups and ounces will remain proportional.

The random variable is 3×sigma²/4.

Since, X1, X2 & X3 are independent & identically distributed.

so we have,

var(X1) = var(X2) = var(X3) = \sigma².

And,[tex]cov(X1 , X2) = cov(X2 , X3) = cov(X1 , X3) = 0.[/tex]

Now,  [tex]var(Y1) = var(X2 + X3) = var(X2) + var(X3) + 2.cov(X2 , X3) = \sigma² + \sigma² + 0 = 2.\sigma²[/tex]

[tex]var[(Y1 + Y2 + Y3)/2] = (1/4). [var(Y1) + var(Y2) + var(Y3) + 2.cov(Y1 , Y2) + 2.cov(Y1 , Y3) + 2.cov(Y2 , Y3)] = (1/4). (\sigma² + \sigma² + \sigma² + 0 + 0 + 0) = 3.\sigma²/4[/tex]

The collection of potential outcomes for a random event is referred to as the sample space, which is the domain of a random variable. When a coin is tossed, for instance, there are only two possible outcomes: heads or tails. Read Related Links as well. Probability.

Different from an algebraic variable is a random variable. An algebraic equation's variable is an unknowable but calculable value. The formula [tex]10 + x = 13[/tex] demonstrates that we can determine the precise value of x, which is [tex]3.[/tex] As seen in the example of the dice above, a random variable has a set of values, and any of those values could be the outcome.

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The rope's diameter is 10⁻³ inches greater than that of the floss, for example.

The diameter of a stand of rope is 1.2 × 10⁻³ inch.

The diameter of a strand of floss is 2 × 10⁻⁴ inches.

Subtract the diameter of the floss strand from the diameter of the rope to determine how much longer the diameter of the rope is than the diameter of the floss.

Therefore, the length by which the diameter of the strand of rope is longer than the diameter of the strand of floss will be:

= 1.2 × 10⁻³ inch - 2 × 10⁻⁴ inches

Now,

= 12 × 10⁻⁴ inch - 2 × 10⁻⁴ inch

= 10 × 10⁻⁴ inch

= 10⁻³ inch

The diameter of the strand of rope is 10⁻³ inches longer than the diameter of the strand of floss.

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Answer:

There are 98 terms in this sequence.

The interest rate of the account is 2%

From the question, we are to determine the interest rate of the account

From the compound interest formula, we have that

A = P(1 + r/n)^{nt}

Where A is the amount

P is the principal

r is the rate

n is the number of times compounded

t is the time in years

From the given information,

A = $1,325.71

P = $1,130

n = 6

t = 8 years

Thus,

1325.71 = 1130(1 + r/6)⁶⁽⁸⁾

1325.71 = 1130( 1 + r/6)⁴⁸

1325.71/1130 = ( 1 + r/6)⁴⁸

Take the 48th root of both sides

1.003333 = 1 + r/6

1.003333 - 1 = r/6

0.003333 = r/6

r = 6 × 0.003333

r = 0.019998

r ≈ 0.02

r ≈ 2%

Hence, the interest rate of the account is 2%.

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The critical number of the given function {g(t) = 3t ㏑t} is t = e⁻¹

Assume f(x) is a function with an open interval (a,b). If c is in the interval (a,b) and either f'(c) =0 or f'(c) does not exist, we say c is a critical number of f(x).

Each local minimum as well as maximum of f(x) must correspond to a critical number of f(x). The opposite is not truly the case: not all critical number of f(x) must correspond to a local maximum as well as minimum of f(x).

Now, as per the question;

It should be noted that the broadest possible domain of {g(t) = 3t ㏑t} is given in the set {t : t > 0} as ㏑t can not be defined for negative numbers of zero.

Now, differentiate the given function with respect to t.

[tex]g^{\prime}(t)=\frac{d}{d t}(3 t \ln t)[/tex]

Apply the product rule of differentiation;

[tex]\begin{aligned}&=\left[\frac{d}{d t}(3 t)\right] \ln t+3 t \frac{d}{d t}(\ln t) \\&=3 \ln t+3 t \frac{1}{t} \\&=3 \ln t+3 \\&=3(\ln t+1)\end{aligned}[/tex]

Now, put this value of g'(t) = 0 for finding the critical points.

0 = g'(t)

  = 3(㏑t + 1)

Divide equation by 3.

0 = ㏑t + 1

㏑t = -1

Taking anti log;

t = e⁻¹ (critical value)

Therefore, the critical value obtained for the given function is  t = e⁻¹.

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The complete question is-

how many critical numbers does {g(t) = 3t ㏑t} have? note: critical numbers must be within the domain of the function.

15 protrusions were counted by her.

Clearly, there are multiple ways to treat verruca. For this type of patient, we would try a prescription for Drysol to apply topically once daily. In many of these patients, the skin is too moist. In our practice, we write a prescription for physical therapy for ultrasound application to the verruca. There is no guarantee with any treatment for verruca. Vitamin A adjunct treatment is often instituted: approx 7500 IU /day for 3 weeks.

Let no. of protrusions be x

3 * x = -4 * (-x) - 15

3x-4x = -15

x = 15

Therefore 15 protrusions were counted by her.

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the value y = 0 does not belong to the range, that is why we need to use parenthesis next to the range.

When we write in interval notation, the parenthesis are used to denote that the "ends" of the interval don't belong to the interval.

This means that in (a, b).

a and b don't belong to that interval.

While if instead we wrote [a, b]

In that case, a and b belong.

For the case of the exponential function:

y = a^x

As x tends to really large negative values, the value of y will tend to zero asymptotically. This means that y is really close to zero, but it is never equal to zero.

Then the value y = 0 does not belong to the range, that is why we need to use parenthesis next to the range.

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The equation of the line passing through (14, 25) and (9, -10) is given by y = 7x - 73

An equation is an expression that shows the relationship between two or more numbers and variables.

The standard equation of a line is:

y = mx + b

Where m is the rate of change and b is the y intercept

The equation of the line passing through the point (14, 25) and (9, -10) is:

y - 25 = [(-10 - 25)/(9 - 14)](x - 14)

y = 7x - 73

The equation of the line passing through (14, 25) and (9, -10) is given by y = 7x - 73

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Answer:

The "different" answer is BC-AC and AB

The "same" answer is AC+CB and CA+BC

Step-by-step explanation:

AC+CB and CA+BC if are rearranged wold be the same CA becomes AC and CB becomes BC

Answer:

it's -2/67x12w<3(xyz)

Answer:

A=2.5×x

10cm=2.5×x

10÷2.5=2.5÷2.5×x

x=4

Answer: (-4-[tex]\sqrt{11}[/tex], -4+[tex]\sqrt{11}[/tex]) ==> B

Step-by-step explanation:

x^2+8x+5<0

x^2+8x+16-11<0

(x+4)^2-11<0

(x+4)^2<11

x+4<[tex]\sqrt{11}[/tex]

x<-4+[tex]\sqrt{11}[/tex]

x+4>-[tex]\sqrt{11}[/tex]

x>-4-[tex]\sqrt{11}[/tex]

(-4-[tex]\sqrt{11}[/tex], -4+[tex]\sqrt{11}[/tex]) ==> B

Remember, the solution doesn't include the x values -4-[tex]\sqrt{11}[/tex] and -4+[tex]\sqrt{11}[/tex]  since if they were plugged in x^2+8x+5, the expression would equal 0. The expression is supposed to be LESS than 0, not equal to 0.

Answer:

Answer: (-4-\sqrt{11}11 , -4+\sqrt{11}11 )

x^2+8x+5<0

x^2+8x+16-11<0

(x+4)^2-11<0

(x+4)^2<11

x+4<\sqrt{11}11

x<-4+\sqrt{11}11

x+4>-\sqrt{11}11

x>-4-\sqrt{11}11

(-4-\sqrt{11}11 , -4+\sqrt{11}11 )