The runners meet at 0.615mi away from the flagpole due to constant velocity.
Velocity informs us of the rate of change of your position, or how quickly your location is altering in relation to time. The difference between your end and beginning positions is referred to as displacement in physics, and velocity is defined as displacement divided by time. Additionally, an object is considered to be moving with constant velocity if it covers the same distance every second.
A vector is a speed that is constant. For a quantity to be fully described, it needs both a magnitude and a direction. Distance per time units is defined as constant velocity. The velocity tells you how quickly your distance is changing per unit of time or how quickly your location is changing.
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a 1.0 kg ball falls from rest a distance of 15m. what was its change in potential energy
Answer:
112.5 J
Explanation:
I calculated it by K/G BY M/S TO POTENTIAL ENERGY.
Given values are:
Mass, m = 1.0 kgDistance, h = 15 mg = 9.8 m/s²The change in Potential energy is:
→ [tex]\Delta PE = mgh[/tex]
By substituting the values, we get
[tex]= 1.0\times 9.8\times 15[/tex]
[tex]= 147 \ J[/tex]
Thus the above response is correct.
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A trailer truck traveling east at 38 m/s sounds a 1300 Hz horn. what is the wavelength stationary listener west?
Answer:
0.0292mExplanation:
The velocity of sound wave is expressed using the formula;
[tex]v = f \lambda[/tex] where
f is the frequency
[tex]\lambda\\[/tex] is the wavelength
Given
f = 1300Hz
v = 38m/s
Required
wavelength [tex]\lambda\\[/tex]
From the formula;
[tex]\lambda\\[/tex] = v/f
[tex]\lambda\\[/tex] = 38/1300
[tex]\lambda\\[/tex] = 0.0292m
Hence the required value of the wavelength is 0.0292m
The wavelength of a stationary listener is 0.029 m.
The given parameters;
speed of the truck's sound, v = 38 m/sfrequency of the truck's sound, f = 1300 HzThe wavelength of a stationary listener is calculated as follows;
[tex]v = f\lambda[/tex]
where;
λ is the wavelength of the sound wave
The value of the wavelength is determined as;
[tex]\lambda = \frac{v}{f} \\\\\lambda = \frac{38}{1300} \\\\\lambda = 0.029 \ m[/tex]
Thus, the wavelength of a stationary listener is 0.029 m.
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calculate the load placed 10m from the fulcrum that can be balanced by an effort of 5 N applied at a distance of 4 m from the fulcrum in a lever .
Answer:
L/E =de/dl so dl is 10m de=4m E=5N
Explanation:
L=(de x E)/dl = 2N
so when load is < effort it is speed multiplayer
The middle-C hammer of a piano hits two strings, producing beats of 1.60 Hz. One of the strings is turned to 260.00 Hz. What frequencies (in Hz) could the other string have?
Answer:
The frequencies the other string could have are 258.4 Hz and 261.6 Hz.
Explanation:
Given;
beat frequency, Fb = 1.60 Hz
frequency of the first string, F₁ = 260.00 Hz
frequency of the second string, F₂ = ?
Beat frequency is given as;
Fb = F₂ - F₁ or Fb = F₁ - F₂
Fb + F₁ = F₂ or F₂ = F₁ - Fb
1.6 + 260 = F₂ or F₂ = 260 - 1.6
261.6 Hz = F₂ or F₂ = 258.4 Hz
Therefore, the frequencies the other string could have are 258.4 Hz and 261.6 Hz.
A ball is thrown horizontally at a height of 1.5 meters at a velocity of 70 m/s. Assume no air resistance. How long until the ball reaches the ground?
0.25 s
0.38 s
0.55 s
0.67 s
Answer:
[tex]t = 0.55[/tex]
Explanation:
Given
[tex]Height, s = 1.5m[/tex]
[tex]Velocity, v = 70m/s[/tex]
Required
Determine the time to hit the ground
Using free fall formula:
[tex]S = \frac{1}{2}gt^2[/tex]
Take g as 9.8 and substitute value for S
[tex]1.5 = \frac{1}{2} * 9.8 * t^2[/tex]
[tex]1.5 = 4.9 * t^2[/tex]
Make t^2 the subject
[tex]t^2 = \frac{1.5}{4.9}[/tex]
[tex]t^2 = 0.30612244898[/tex]
Solve for t
[tex]t = \sqrt{0.30612244898[/tex]
[tex]t = 0.55[/tex] -- approximated
You are driving your car down a straight road at a constant speed of 23 m/s
(about 50 mi/h). What is your acceleration?
Answer:
0 m/s^2
Explanation:
If you're driving at constant speed in the same direction, your acceleration is always 0 m/s^2. acceleration is a vector, so any change in speed or direction would result in acceleration.
A rock is thrown straight up with an initial speed of 22 m/s. How long will it be in the air before it returns to the thrower?
Answer:
The time spent in air by the rock before it returns to the thrower is 4.5 s
Explanation:
Given;
initial velocity of the rock, u = 22 m/s
Neglecting air resistance, the time it takes the rock to go up equals the time it takes it to return to the thrower. This is also called time of flight.
The time to go up is calculated as;
v = u - gt
where;
v is the final velocity at the maximum height
0 = u - gt
gt = u
t = u / g
t = 22 / 9.8
t = 2.245 s
thus time to go up = 2.245 s
and time to return to the thrower = 2.245s
The total time spent in air by the rock before it returns to the thrower
= 2.245 s + 2.245s
= 4.5 s
5. Correct the statement : Human being
can hear sounds of frequencies upto
60000Hz.
Answer:
Humans can detect sounds in a frequency range from about 20 Hz.
A diffraction pattern is formed on a screen 150 cm away from a 0.500-mm-wide slit. Monochromatic 546.1-nm light is used. Calculate the fractional intensity I/Imax at a point on the screen 4.10 mm from the center of the principal maximum.
Solution :
The expression for the intensity of light is given by :
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a \sin \theta}{\lambda}}{\frac{\pi a \sin \theta}{\lambda} }\right)^2$[/tex]
For a small angle, θ
sin θ = tan θ
[tex]$=\frac{y}{L}$[/tex]
Therefore the above equation becomes,
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a y}{\lambda L}}{\frac{\pi a y}{\lambda L} }\right)^2 $[/tex]
The given data is
λ = 546.1 nm
L = distance between the slit and the screen = 140 cm
= 1.40 m
a = width of the slit
= [tex]$0.50 \times 10^{-3} \ m$[/tex]
Therefore,
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20}}{\frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20} }\right)^2 $[/tex]
[tex]$=\left(\frac{0.170}{9.82}\right)^2$[/tex]
[tex]$= 2.89 \times 10^{-4} \ I_{max}$[/tex]
Therefore the fractional intensity is [tex]$\frac{I}{I_{max}}= 2.89 \times 10^{-4} $[/tex]
what are the different intensity of an earthquake
Ranking Earthquake Intensity
Magnitude Average number per year Modified Mercalli Intensity
2.0 – 2.9 >1 million I
3.0 – 3.9 about 100,000 II – III
4.0 – 4.9 about 10,000 IV – V
5.0 – 5.9 about 1,000 VI – VII
Explanation:
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How much work is done by an applied mass to lift 55 kg block and 4.5 meter high?
Given=
Unknown=
Formula=
Solution=
Answer=
Answer:
Given = 55kg, 4.5 m
Unknown = Work done
Formula = (mg) × d
Solution = 2425.5 J
Answer = 2425.5 J
Explanation:
Formula we use,
→ W = (mg) × d
Then the value of work done is,
→ (55 × 9.8) × 4.5
→ 539 × 4.5
→ 2425.5 J
Hence, the work done is 2425.5 J.
Need Help Please and Thank You). Question 1: Explain how longitudinal waves and transverse waves are similar to each other and different from each other. Question 2) Compare and contrast reflection and refraction. Question 3) What does it mean that energy is neither created nor destroyed? ( Please No Plagiarism and Be 100% positive with your answer. Will Mark Brainliest. If you write anything down that doesn't contain to my question you will be reported. Need two answers.
1) The longitudinal waves move in parallel direction to the source of vibration. The transverse waves move in perpendicular direction to the source of vibration . They are similar in the sense that energy is transferred in the form of waves.
2) Reflection occurs when waves bounce from a surface back toward the source. Refraction is when waves are deflected when the waves go through a substance.
3) The Law of Conservation of Energy
states that energy can neither be created
nor destroyed, it can only be transferred or
changed from one form to another.
Which describes one feature of the image formed by a convex mirror?????
Answer:
The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.
Explanation:
The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.
Also notice that convex mirror always makes virtual images.
Another feature of the convex mirror is that an upright image is always formed by the convex mirror.
An important mirror formula to remember which is applicable for both convex and mirrors
1/f= 1/u + 1/vHere:
'u' is an object which gets placed in front of a spherical mirror of focal
length 'f' and image 'u' is formed by the mirror.
Answer:
right side up
Explanation:
A baseball accelerates at 15m/s2, changing its velocity from 0m/s to 50 m/s down the way. How long did it take the baseball to accelerate?
Answer:
3.33s
Explanation:
Given parameters:
Acceleration = 15m/s²
Initial velocity = 0m/s
Final velocity = 50m/s
Unknown:
Time taken for the acceleration = ?
Solution:
To solve this problem, we must understand that acceleration is the rate of change of velocity with time.
Mathematically;
a = [tex]\frac{v - u}{t}[/tex]
a is the acceleration
v is the final velocity
u is the initial velocity
t is the time taken
So;
15 = [tex]\frac{50 - 0}{t}[/tex]
15t = 50
t = 3.33s
A rocket burns fuel at a rate of 199 kg/s and exhausts the gas at a relative speed of 9 km/s. Find the thrust of the rocket. Answer in units of MN.
Answer:
1.791 MN
Explanation:
Thrust of the rocket can be found using the relation
T = v.dm/dt, where
T = thrust off the rocket
v = speed of the rocket, 9 km/s = 9000 m/s
dm/dt = rate at which fuel burns, 199 kg/s
Substituting the values into the formula, we have
T = 9000 * 199
T = 1791000 N
T = 1.791*10^6 N
Since 1 MN = 10^6, thus
T = 1.791 MN
The thrust of the rocket in units of MN is 1.71 Meganewton.
Given the following data:
Rate = 199 kg/sRelative speed = 9 km/s.Conversion:
Relative speed = 9 km/s to m/s = 9000 m/s
To determine the thrust of the rocket in units of MN:
Mathematically, the thrust of an object is given by this formula:
[tex]Thrust = V\frac{dm}{dt}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Thrust = 9000 \times 199[/tex]
Thrust = 1,791,000 Newton
In units of MN:
1 MN = [tex]1 \times 10^6\;N[/tex]
Thrust = 1.71 MN
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Uses Hooke's Law to solve this problem. If a force of N stretches a spring m beyond its natural length, how much work does it take to stretch the spring m beyond its natural length?
Answer:
Work done = 1/2 × Ne
Explanation:
Given that if a force of N stretches a spring m beyond its natural length, how much work does it take to stretch the spring m beyond its natural length
Using Hook's law
Force = N
Let the extension = e
Work done in stretching spring m beyond its natural length will be
Workdone = 1/2 × Ne
Or
From Hook law,
N = Ke
Work done = 1/2 × Ke^2
help asap
what is the force responsible for seafloor spreading and the formation of new ocean floor at mid ocean ridges
Answer:
magma
Explanation:
I wanna think that that's right if it's not in so sorry but I'm pretty sure it's magma
Intrusive magma forced up towards the ocean ridge is the force responsible for seafloor spread. The correct option is B.
What is seafloor spreading?Seafloor spreading is a process that occurs at mid-ocean ridges where the oceanic crust is produced by volcanic activity and then moves away from the ridge.
Plate tectonics' continental drift is explained by seafloor spreading. When oceanic plates diverge, tensile stress causes fractures in the lithosphere.
Ridge push occurs when plates are not subducting and are driven by gravity as they slide off the elevated mid-ocean ridges.
Magma rises from the fractures at a spreading center and cools on the ocean floor to form a new seabed.
The spreading rate is the rate at which an ocean basin widens due to seafloor spreading and determines whether the ridge is fast, intermediate, or slow.
Thus, the correct option is B.
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A grinding wheel is a uniform cylinder with a radius of 8.65 cm and a mass of 0.400 kg . Calculate its moment of inertia about its center.
Answer:
I = 1.5*10⁻³ kg*m²
Explanation:
It can be showed that the moment of inertia (or rotational inertia) for a uniform cylinder of mass m and radius r, respect an longitudinal axis going through its center (parallel to the height of the cylinder) can be written as follows:[tex]I = \frac{1}{2}*m*r^{2} = \frac{1}{2}*0.400 kg*(0.0865m)^{2} = 1.5e-3 kg*m2[/tex]
What happens when light from the sun passes through any type of matter
Answer:
its it filled with energy
Answer:
The light slows down.
Explanation:
Physical science
HELP ASAP PLZ!! Which represents the greatest speed: 56 m/s, 560 cm/s or .56 km/s? Explain your answer with math.
Answer:
0.56 km/s
Explanation:
We will define a single system of units for measurement, for this case meters per second [m/s]. That is, we must convert the rest of units such as centimeters per second and kilometers per second to meters per second.
[tex]560[\frac{cm}{s}]*(\frac{1m}{100cm} )=5.6[m/s]\\0.56[\frac{km}{s}]*(\frac{1000m}{1km} )=560[m/s][/tex]
Therefore the speed of 0.56 [km/s] is the greatest of all
A 0.500 kg object tied to a string is swung around a person's
head in a horizontal circle. The length of the string is 1.00 m
and the maximum force the string can withstand without
breaking is 25.0 N. What is the maximum speed the object may
be swung without breaking the string?
Answer:
25 N
If you’re doing ck-12
The object may be swung with maximum velocity of 7.07 m/s without breaking the string.
What is centripetal force?The centripetal force definition states that: The force applied to an item in curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.
Newtons are used to measure centripetal force.
Given that:
mass of the object = 0.500 kg.
The length of the string = 1.00 m.
If the maximum speed of the object be v,
maximum centripetal force be = 0.5v²/1.0 N = v²/2 N.
As the maximum force the string can withstand without breaking is 25.0 N,
25.0 = v²/2
⇒ v = 5√2 m/s = 7.07 m/s.
Hence, the object may be swung with maximum velocity of 7.07 m/s without breaking the string.
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what is the job title) makes the decision regarding the quality of produce and if it will be sold fresh or processed?
Im need some help with this please
Answer:
c) Aeroplane
Explanation:
The aeroplane has the greatest mass than the other three objects, so it experiences the greatest gravitational force. Hence, the option (c) is the answer.
A particular engine has a power output of 5 kW and an efficiency of 30%. If the engine expels 6464 J of thermal energy in each cycle, find the heat absorbed in each cycle. Answer in units of J.
Answer:
The heat absorbed in each cycle is 9,234.286 J
Explanation:
Given;
power output, P = 5 kW = 5,000 W
efficiency of the engine, e = 30 % = 0.3
thermal heat expelled, [tex]Q_c[/tex] = 6464 J
let the heat absorbed = [tex]Q_h[/tex]
The efficiency of the engine is given as;
[tex]e = \frac{W}{Q_h} = \frac{Q_h-Q_c}{Q_h} = \frac{Q_h}{Q_h} - \frac{Q_c}{Q_h} = 1-\frac{Q_c}{Q_h}\\\\e = 1-\frac{Q_c}{Q_h}\\\\0.3 = 1-\frac{Q_c}{Q_h}\\\\\frac{Q_c}{Q_h} = 1-0.3\\\\\frac{Q_c}{Q_h} = 0.7\\\\Q_h = \frac{Q_c}{0.7} \\\\Q_h = \frac{6464}{0.7} = 9,234.286 \ J.[/tex]
Therefore, the heat absorbed in each cycle is 9,234.286 J.
How does the movement of thermal energy differ from that of other forms of energy?
heat and thermal energy can be differentiated as is that thermal energy is not actually transferred. It is not moving, but remains part of the system's internal energy. Heat, on the other hand, is a passing energy. H. Energy transferred from a hotter system.
In summary, thermal energy is the energy hipster. As such, it cannot be converted into other types of energy. Only the difference in thermal energy can be converted/used to do work. Such processes are never 100% efficient. Every energy form that cannot be recovered.
Thermal energy transfer occurs in three ways: convection, conduction and radiation. When heat energy is transferred between adjacent molecules that are in contact with each other, it is called conduction
Thermal energy and temperature are closely related. However, temperature is the average kinetic energy of matter particles and thermal energy is the total kinetic energy of matter particles.
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Which measurement is used to determine if an object has balanced forces
Answer:
a spring scale
Explanation:
i think it is correct
In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.
Answer:
[tex]CPD = 80[/tex]
[tex]PCD = 44[/tex]
Explanation:
Given
[tex]AB || CD[/tex]
[tex]BAD = 56[/tex]
[tex]CPA = 100[/tex]
See attachment
Required
Determine PCD and CPD
First, we need to calculate CPD
Since DPA is a straight line and CPA = 100;
We have that:
[tex]CPA + CPD = 180[/tex] --- angle on a straight theorem
Substitute 100 for CPA
[tex]100 + CPD = 180[/tex]
Subtract 100 from both sides
[tex]100-100 + CPD = 180-100[/tex]
[tex]CPD = 80[/tex]
Next, we calculate PCD
We have that:
[tex]DAB= ADC = 56[/tex] --alternate angle
In triangle PCD
[tex]PCD + CPD + PDC = 180[/tex] --- angles in a triangle
Where
[tex]PDC = ADC = 56[/tex]
So, we have:
[tex]PCD +80 + 56 = 180[/tex]
[tex]PCD +136 = 180[/tex]
Subtract 136 from both sides
[tex]PCD = 180 - 136[/tex]
[tex]PCD = 44[/tex]
What do you mean by Galvanometer Constant?
Answer:
It is a value that reading in the galvanometer must be multiplied with to get the ordinary unit
Explanation:
What is a galvanometer?
A galvanometer is an electromechanical instrument used for detecting and indicating an electric current.
A Number by which a certain function of the reading of a galvanometer must be multiplied to obtain the current value in ordinary units is a galvanometer constant
1. Why is physics sometimes called the fundamental science?
Because it explains the basics of all sciences
Because it examines the rules that govern the universe
Because it does not require experiments or the scientific method
Because it was developed before any other branch of science
Because it is the easiest branch of science to understand
Explanation:
Because it is the easiest branch of science to understand
Determine whether the inertia of an object changes as the object's
velocity changes.
Answer:
The inertia of an object does not change as the objects velocity changes because the inertia will remain the same as long as the mass is the same.
: