Answer: Y=6/5
Step-by-step explanation:
Y=1/4X+6/5
(set X to zero 1/4(0) = 0)
Y=0+6/5
Y=6/5
HELPPPP MEEEE I NEED TO TURN IN THIS LATE MATH HOMEWORK
Answer:
enter the step by step answer u did and then add the number the match and enter them in the box and u shall be done
Step-by-step explanation:
Find the missing variable and indicated
angle measure.
X =
S
R
(5x – 2)° | 82°
T
m
O
WILL
MARK THE FIRST PERSON WHO ANSWERS BRAINIEST JUST PLEASE ANSWER. ALSO 24 POINTS:)
Answer:
The missing variable "x" = 20
And the Angle measure = 98°
Step-by-step explanation:
Explaination is given in the picture...
Thank you!
Answer:
the angles are 82 degrees and 98 degrees (5(20) -2), and the missing variable (x) is 20.
Step-by-step explanation:
Let us first look at SL. SL is a straight line and has an angle measure of 180 degrees. Angle RTL is 82 degrees and splits SL into 2. The angle right next to RTL is RTS, which is (5x-2) degrees. Since all of SL adds to 180 degrees, this means that RTL and RTS will add up to 180 degrees, since they are in the middle of it.
82 + 5x-2 = 180
80 +5x = 180
5x = 100
x = 20
Therefore, the angles are 82 degrees and 98 degrees (5(20) -2), and the missing variable (x) is 20.
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Feb 23, 12:41:00 PM If f(x)=3x^(5)+4, then what is the remainder when f(x) is divided by x-2 ?
The remainder when f(x)=3x^(5)+4 is divided by x-2 is 100.
The remainder when f(x)=3x^(5)+4 is divided by x-2 can be found using synthetic division.
Step 1: Set up the synthetic division by writing the coefficients of f(x) in a row and the value of x that makes the divisor equal to zero in a box to the left. In this case, the coefficients are 3, 0, 0, 0, 0, and 4 and the value of x is 2.
2|300004
Step 2: Bring down the first coefficient and multiply it by the value in the box. Write the result under the next coefficient and add them together. Repeat this process for all of the coefficients.
2|300004|612244896|36122448100
Step 3: The last number in the bottom row is the remainder. In this case, the remainder is 100.
Therefore, the remainder when f(x)=3x^(5)+4 is divided by x-2 is 100.
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In one country, 7 out of 1,000 infants die before their first birthday. Convert this figure to a percentage. Is your answer greater than or less than 1%?
PLS NOW
Answer: 0.7% < 1%
Step-by-step explanation:
Percent is out of 100 so...
7/1000 = 0.7/100 = 0.7%
0.7% < 1% so the answer is less than 1%
Hope this helped!
PLS HELP ILL GIVE BRAINLIEST
Use the unit circletofind all the values of between 0 and 2 for which the given statement is true. (Use the exact radian values)
tan()=−√3
The values of Ф solved using a unit circle, between 0 and 2π, for which tanФ = - √3 is 2π/3 and 5π/3.
What is a circle?
A circle is a shape made up of all points in a plane that are at a specific distance from the centre point. In other words, it is the path a moving point in a plane takes to move around a curve while maintaining a constant distance from another point. The circle has an area and a perimeter and is a two-dimensional figure. The distance around a circle, or its circumference, is referred to as the perimeter of the circle. The region enclosed by a circle in a 2D plane is said to be its area.
The complete question is given below.
Given,
tan Ф = - √3
We have to find all values of Ф between 0 and 2π using a unit circle.
The unit circle for trigonometric calculations is given below.
from the unit circle,
tan 60 = √3
In quadrant 2,
tan ( 180 - 60) = - tan 60
tan 120 = - tan 160 = -√3
In quadrant 3, tangent values are positive.
In quadrant 4
tan (360 - 60) = - tan 60
tan 300 = -tan 60 = -√3
Also,
tan 120 = tan 2π/3
tan 300 = tan 5π/3
Therefore the values of Ф solved using a unit circle, between 0 and 2π, for which tanФ = - √3 is 2π/3 and 5π/3.
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For a certain 2-year polytechnic school, studies by the registry show that the probability of a randomly selected first-year student returning for a second year is 0.54. Assume that 8 first-year students are randomly selected.
Create a probability distribution showing the possible outcomes and corresponding probabilities.
Compute and interpret P(X≤3).
Compute the expected number from many trials of randomly selected groups of 8 freshmen that return for the second year.
Compute the standard deviation.
The Student Services Department randomly selected 8 freshmen and met with them for two one-on-one advising sessions during the freshmen year. Of the 8 students who participated, 7 returned for the second year. Can you consider the advising program a success?
The probability distribution for the possible outcomes can be created using the binomial distribution formula:
P(X=x) = (n choose x) * p^x * (1-p)^(n-x)
Where n is the number of trials (in this case, 8), x is the number of successes (returning for a second year), p is the probability of success (0.54), and 1-p is the probability of failure.
The probability distribution is as follows:
| X | P(X) |
|---|------|
| 0 | 0.010 |
| 1 | 0.059 |
| 2 | 0.167 |
| 3 | 0.282 |
| 4 | 0.313 |
| 5 | 0.223 |
| 6 | 0.106 |
| 7 | 0.033 |
| 8 | 0.005 |
To compute P(X≤3), we add the probabilities for X=0, X=1, X=2, and X=3:
P(X≤3) = 0.010 + 0.059 + 0.167 + 0.282 = 0.518
This means that there is a 51.8% chance that 3 or fewer of the randomly selected first-year students will return for a second year.
The expected number of students returning for a second year can be calculated using the formula:
E(X) = n * p = 8 * 0.54 = 4.32
This means that on average, 4.32 of the randomly selected first-year students will return for a second year.
The standard deviation can be calculated using the formula:
σ = √(n * p * (1-p)) = √(8 * 0.54 * 0.46) = 1.39
Finally, to determine if the advising program was a success, we can compare the observed number of students returning (7) to the expected number (4.32). Since 7 is greater than 4.32, it appears that the advising program may have had a positive effect on the students' decision to return for a second year. However, further analysis would be needed to determine if this difference is statistically significant.
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Which graph represents the function f(x) = cos (4x)
The period of the given function f(x) = Cos 4x is π/2
What is a function?A function is a relation from a set of inputs to a set of possible outputs, where each input is related to exactly one output.
Given is a graph of the function f(x) = Cos 4x, we need to identify the period of this function.
We know that, the function of the form of :-
y = A Cos(Bx), The A and B coefficients can tell us the amplitude and period respectively.
So, comparing this equation to the given function equation, we get,
A = 1, Bx = 4x
The period of cosine is 2π, Therefore, the period would be 2π/B
Therefore, the period of the given function is 2π/4
= π/2
Hence, the period of the given function f(x) = Cos 4x is π/2
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Does someone mind helping me with this question? Thank you!
Answer:
543.07214553
Round to the Nearest Whole Number
543
A baseball is hit so that its height, s, in feet after t seconds is S= = - 16t² +60t+2. For what time period is the ball at least 46 ft above the ground?
A baseball is hit so that its height, s, in feet after t seconds is S= - 16t² +60t+2. Based on the inequality, the ball is at least 46 feet above the ground in [0.20, 1.55] seconds.
How do we find this value?To find the period of time the ball is at least 46 feet above the ground, we first need to solve the given inequality, which will be:
S= -16t²+60t+2[tex]\geq[/tex]46Simplifying, we find the following value:
S= -16t²+60t- 44[tex]\geq[/tex] 0Dividing both sides by -4, we find:
S= 4t²-15t+11[tex]\leq[/tex] 0So, to solve this inequality, we can use the quadratic formula:
t= (-b± sqrt(b²-4ac))/2awhere, a=4, b= -15 and c=11.Plugging these values into the formula, we get:
t= [15± sqrt ((-15)² -4(4)(11))]/2x4Simplifying this expression, we get:
t= [15± sqrt(97)]/8Therefore, it follows that the ball is at least 46 feet above the ground during the time period:
[(15- sqrt(97))/8, (15+sqrt(97))/8]So, rounded to two decimal places, this is approximately:
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A market analyst wants to know if the new website he designed is showing increased page views per visit. A customer is randomly sent to one of two different websites, offering the same products, but with different designs. Assume that the data come from a distribution that is Normally distributed. The data is shown in the table to the right. Complete parts a through c below Website1 n, = 70 y1 = 7.5 s1 = 4.9 Website 2 n2 = 90 y2 7.4 S2 5.4 a) Test the null hypothesis at α= 0.05 using the pooled t-test. Assume that the new website is website 1 and the old website is website 2 Choose the null and alternative hypotheses below Calculate the test statistic. Let the difference of the sample means be y1 -y2 t- (Round to three decimal places as needed.) Calculate the P-value P-value- (Round to four decimal places as needed.)
a) The null and alternative hypotheses are:
H0: µ1 = µ2
Ha: µ1 ≠ µ2
b) The test statistic is:
t = 0.117
c) The P-value is:
P-value = 0.9072
To test the null hypothesis at α= 0.05 using the pooled t-test, we need to follow these steps:
Step 1: Choose the null and alternative hypotheses. The null hypothesis is that the mean page views per visit for website 1 are equal to the mean page views per visit for website 2. The alternative hypothesis is that the mean page views per visit for website 1 are not equal to the mean page views per visit for website 2.
H0: µ1 = µ2
Ha: µ1 ≠ µ2
Step 2: Calculate the test statistic. The test statistic for the pooled t-test is given by:
t = (y1 - y2) / (sp * √(1/n1 + 1/n2))
where sp is the pooled standard deviation, given by:
sp = √(((n1 - 1) * s1^2 + (n2 - 1) * s2^2) / (n1 + n2 - 2))
sp = √(((70 - 1) * 4.9^2 + (90 - 1) * 5.4^2) / (70 + 90 - 2)) = 5.178
t = (7.5 - 7.4) / (5.178 * √(1/70 + 1/90)) = 0.117
Step 3: Calculate the P-value. The P-value is the probability of observing a test statistic as extreme or more extreme than the one we calculated, assuming the null hypothesis is true. We can use a t-distribution table or a calculator to find the P-value. The degrees of freedom for the pooled t-test are n1 + n2 - 2 = 70 + 90 - 2 = 158.
Using a t-distribution table or a calculator, we find that the P-value is 0.9072.
Step 4: Since the P-value is greater than the significance level of 0.05, we fail to reject the null hypothesis. There is not enough evidence to suggest that the mean page views per visit for website 1 are different from the mean page views per visit for website 2.
Thus:
a) The null and alternative hypotheses are:
H0: µ1 = µ2
Ha: µ1 ≠ µ2
b) The test statistic t = 0.117
c) The P-value = 0.9072
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O is the center of the regular decagon below. Find its perimeter. Round to the nearest tenth if necessary. 6 O
By answering the above question, we may infer that So the perimeter of the regular decagon is approximately 38.2 units (rounded to the nearest tenth).
what is decagon?In geometry, a decagon is either a decagon or not. There are 144° of inner angles total in a simple decagon. A regular decagon that self-intersects is known as a decagram. A polygon with 10 sides, ten internal angles, and ten vertices is called a decagon. Geometry may contain the form known as a decagon. It also has ten horns and ten horns. A dodecagon is a polygon with twelve sides. Some unusual types of dodecagons are shown in the photographs above. Particularly, a regular dodecagon has angles that are equally placed around a circle and sides that are of the same length.
Each interior angle of a regular decagon measures:
[tex]$$(n-2)\times180^\circ/n = (10-2)\times180^\circ/10 = 144^\circ$$\\$$\cos(72^\circ) = \frac{x}{2y}$$[/tex]
Solving for x, we get:
[tex]$$x = 2y\cos(72^\circ)$$[/tex]
We can use the fact that[tex]$\cos(72^\circ) = \frac{1+\sqrt{5}}{4}$[/tex](which can be derived using the golden ratio) to get:
[tex]$$x = 2y\cos(72^\circ) = 2y\cdot\frac{1+\sqrt{5}}{4} = \frac{y}{2}(1+\sqrt{5})$$\\$$R = \frac{x}{2\sin(180^\circ/10)} = \frac{x}{2\sin(36^\circ)}$$\\[/tex]
We can use this formula to find[tex]$y$:[/tex]
[tex]$$y = R = \frac{x}{2\sin(36^\circ)} = \frac{x}{2\sin(\frac{1}{2}\times72^\circ)} = \frac{x}{2\cos(72^\circ/2)}$$[/tex]
We can use the half-angle identity [tex]$\cos(\theta/2) = \sqrt{\frac{1+\cos(\theta)}{2}}$ to simplify this expression:[/tex]
[tex]$$y = \frac{x}{2\cos(72^\circ/2)} = \frac{x}{2\sqrt{\frac{1+\cos(72^\circ)}{2}}} = \frac{x}{2\sqrt{\frac{1+\frac{1+\sqrt{5}}{4}}{2}}} = \frac{x}{2\sqrt{\frac{3+\sqrt{5}}{4}}} = \frac{x}{\sqrt{3+\sqrt{5}}}$$[/tex]
Putting it all together, we have:
[tex]$$\text{Perimeter} = 10x = 10\cdot\frac{y}{2}(1+\sqrt{5}) = 5\sqrt{10+2\sqrt{5}}\approx 38.2$$[/tex]
So the perimeter of the regular decagon is approximately 38.2 units (rounded to the nearest tenth).
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Workers in an office of 60 staff were asked their favourite type of take-away.
The results are summarised in the table.
Take-away Frequency Angle
Pizza 3
a
Curry 10
b
Fish & chips 14
c
Kebab 19
d
Other 14
e
Work out the size of each angle to draw a pie chart.
Answer:
To find the angle for each category, we need to calculate the percentage of the total frequency for each category, and then multiply by 360 (the total number of degrees in a circle).
The total frequency is:
3 + 10 + 14 + 19 + 14 = 60
The percentage of the total frequency for each category is:
Pizza: 3/60 x 100% = 5%
Curry: 10/60 x 100% = 16.67%
Fish & chips: 14/60 x 100% = 23.33%
Kebab: 19/60 x 100% = 31.67%
Other: 14/60 x 100% = 23.33%
To find the angle for each category, we multiply the percentage by 360:
Pizza: 5% x 360 = 18 degrees
Curry: 16.67% x 360 = 60 degrees
Fish & chips: 23.33% x 360 = 84 degrees
Kebab: 31.67% x 360 = 114 degrees
Other: 23.33% x 360 = 84 degrees
So the table with the angles for each category is:
Take-away Frequency Angle
Pizza 3 18°
Curry 10 60°
Fish & chips 14 84°
Kebab 19 114°
Other 14 84°
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Part 1
A gender-selection technique is designed to increase the likelihood that a baby will be a girl. In the results of the gender-selection technique, 950 births consisted of 483 baby girls and 467 baby boys. In analyzing these results, assume that boys and girls are equally likely.
a. Find the probability of getting exactly 483 girls in 950 births.
b. Find the probability of getting 483 or more girls in 950 births. If boys and girls are equally likely, is 483 girls in 950 births unusually high?
c. Which probability is relevant for trying to determine whether the technique is effective: the result from part (a) or the result from part (b)?
d. Based on the results, does it appear that the gender-selection technique is effective?
In analysis the results are a) 0.017, b) 0.1515, c) punctual probability, and d) Outcome is improbable.
Probability is a way to gauge how likely something is to happen. Several things are difficult to forecast with absolute confidence. With it, we can only make predictions about the likelihood of an event happening, or how likely it is.
a)Sd(Y) = (226) = 15.033 .
Let's call Z the approximation, we conclude:
X = [tex]\frac{Z-452}{15.033}[/tex]
With reference, that would be 0.017.
b) P(Y ≥ 467) is just 0.1515, a low number. This means that it 467girls from 904 births is a pretty high number.
c) Calculating a punctual probability will likely provide a low figure due to a large number of potential outcomes.
d) The results appear to be relatively successful. We thus estimate that getting a comparable or better outcome is improbable.
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Indicate the transformations to f(x) = √x
a) y = 1/2 √ −3(x + 1) + 4
Indicate the transformations to f(x) = x^3
a) y = (2(x − 1))^3 − 5
a) y = 1/2 √ −3(x + 1) + 4
- The function is multiplied by 1/2, indicating a vertical compression by a factor of 1/2.
- The function is multiplied by -3 inside the square root, indicating a horizontal compression by a factor of 1/3 and a reflection across the y-axis.
- The function is shifted 1 unit to the left, indicated by the (x + 1) inside the square root.
- The function is shifted 4 units up, indicated by the + 4 outside the square root.
a) y = (2(x − 1))^3 − 5
- The function is multiplied by 2 inside the cube, indicating a horizontal compression by a factor of 1/2.
- The function is shifted 1 unit to the right, indicated by the (x - 1) inside the cube.
- The function is shifted 5 units down, indicated by the - 5 outside the cube.
The transformations to f(x) = √x are as follows:
a) y = 1/2 √ −3(x + 1) + 4
- The function is multiplied by 1/2, indicating a vertical compression by a factor of 1/2.
- The function is multiplied by -3 inside the square root, indicating a horizontal compression by a factor of 1/3 and a reflection across the y-axis.
- The function is shifted 1 unit to the left, indicated by the (x + 1) inside the square root.
- The function is shifted 4 units up, indicated by the + 4 outside the square root.
The transformations to f(x) = x^3 are as follows:
a) y = (2(x − 1))^3 − 5
- The function is multiplied by 2 inside the cube, indicating a horizontal compression by a factor of 1/2.
- The function is shifted 1 unit to the right, indicated by the (x - 1) inside the cube.
- The function is shifted 5 units down, indicated by the - 5 outside the cube.
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the zeros and their multiplicities. Consider f(x)=2x^(5)+11x^(4)-2x^(3)-74x^(2)-60x+48
The zeros and their multiplicities of the function f(x)=2x^(5)+11x^(4)-2x^(3)-74x^(2)-60x+48 are:
x = -4, multiplicity 1
x = (-5 + √(41))/(2), multiplicity 1
x = (-5 - √(41))/(2), multiplicity 1
The zeros of a function f(x) are the values of x that make f(x) equal to 0. The multiplicity of a zero is the number of times that zero appears as a solution. To find the zeros and their multiplicities of the given function f(x)=2x^(5)+11x^(4)-2x^(3)-74x^(2)-60x+48, we can use synthetic division or factoring.
First, let's use synthetic division to find one of the zeros:
2x^(5)+11x^(4)-2x^(3)-74x^(2)-60x+48 = 0
Using synthetic division, we can find that x = -4 is a zero of the function:
(-4) | 2 11 -2 -74 -60 48
| 0 -8 20 88 104 -176
---------------------------
2 3 18 14 44 -128
Now we can divide the original function by (x+4) to find the remaining zeros:
f(x) = (x+4)(2x^(4)-x^(3)+14x^(2)+10x-32)
Using the quadratic formula, we can find the remaining zeros of the function:
x = (-b ± √(b^(2)-4ac))/(2a)
x = (-(10) ± √((10)^(2)-4(2)(-32)))/(2(2))
x = (-10 ± √(164))/(4)
x = (-10 ± √(4*41))/(4)
x = (-10 ± 2√(41))/(4)
x = (-5 ± √(41))/(2)
So the zeros of the function are x = -4, x = (-5 + √(41))/(2), and x = (-5 - √(41))/(2).
The multiplicity of each zero is 1, since each zero appears only once as a solution.
Therefore, the zeros and their multiplicities of the function f(x)=2x^(5)+11x^(4)-2x^(3)-74x^(2)-60x+48 are:
x = -4, multiplicity 1
x = (-5 + √(41))/(2), multiplicity 1
x = (-5 - √(41))/(2), multiplicity 1
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Pamela is 6 years younger than juri. The sum of their ages is 94
Answer:
Step-by-step explanation:
pamela: j - 6 years = juri's age.
juri: j + 6 years.
sum of pamela and juri = 94 years.
j +(j - 6) = 94
2j - 6 = 94
2j = 94 - 6
2j = 88
j = 44
juri age: 44years and pamela age: 44years - 6years = 38years.
Question 1: You will receive a prize if both a fair coin lands "heads" AND a fair die lands "6". After the coin is flipped and the die is rolled you ask if AT LEAST ONE of these events has occurred and you are told "yes."
Formally calculate the probability of you winning the prize, whilst answering these questions in each step of your answer
i. Specify the joint distribution, P(????,????,????,????), in terms of its constituent conditional distributions
ii. Specify the full prior probabilities for the coin, P(????) and the dice, P(????), events
iii. Specify the full conditional distribution for the event that the coin is heads or dice is six, ????=????∪????
iv. Specify the full conditional distribution for the event that the coin is heads and dice is six, ????=????∩????
v. Use the fundamental rule to derive the distribution for the coin and dice events given the event that the coin is heads or dice is six, P(????,????|????=T????????????)
vi. Calculate the probability of observing that the coin is heads or dice is six, P(????=T????????????)
vii. Specify and calculate the posterior distribution for the joint probability of the coin and dice events given the event that the coin is heads or dice is six, P(????,????|????=T????????????)
viii. Derive the marginal distribution for the event that coin is heads and dice is six given we know the event heads or six, ????=T???????????? | ????=T???????????? , has occurred
ix. Calculate the marginal probability that the coin is heads and dice is six given we know the event heads or six, P(????=T????????????|????=T????????????)
x. Calculate the probability of you winning the prize
i. The joint distribution for the coin and dice events is given by P(C,D) = P(C|D)P(D) = P(D|C)P(C), where C is the event that the coin lands heads and D is the event that the dice lands six.
ii. The prior probabilities for the coin and dice events are P(C) = 0.5 and P(D) = 1/6, since they are both fair.
iii. The full conditional distribution for the event that the coin is heads or the dice is six is given by P(C∪D) = P(C) + P(D) - P(C∩D) = 0.5 + 1/6 - (0.5)(1/6) = 0.5833.
iv. The full conditional distribution for the event that the coin is heads and the dice is six is given by P(C∩D) = P(C|D)P(D) = P(D|C)P(C) = (0.5)(1/6) = 0.0833.
v. The distribution for the coin and dice events given the event that the coin is heads or the dice is six is given by P(C,D|C∪D) = P(C∩D|C∪D)P(C∪D) = (0.0833)(0.5833) = 0.0486.
vi. The probability of observing that the coin is heads or the dice is six is given by P(C∪D) = 0.5833.
vii. The posterior distribution for the joint probability of the coin and dice events given the event that the coin is heads or the dice is six is given by P(C,D|C∪D) = P(C∩D|C∪D)P(C∪D) = (0.0833)(0.5833) = 0.0486.
viii. The marginal distribution for the event that the coin is heads and the dice is six given we know the event heads or six has occurred is given by P(C∩D|C∪D) = P(C,D|C∪D)/P(C∪D) = 0.0486/0.5833 = 0.0833.
ix. The marginal probability that the coin is heads and the dice is six given we know the event heads or six has occurred is given by P(C∩D|C∪D) = 0.0833.
x. The probability of you winning the prize is the same as the probability that the coin is heads and the dice is six, which is given by P(C∩D) = 0.0833.
Therefore, the probability of you winning the prize is 0.0833.
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(x+4)^2=15
solving by talking the square root
Answer:
x = -4 + √15 and x = -4 - √15.
Step-by-step explanation:
To solve for x in the equation (x + 4)^2 = 15 using square roots, we can take the square root of both sides of the equation, remembering to include both the positive and negative square root:
(x + 4)^2 = 15
Taking the square root of both sides:
±(x + 4) = √15
Now we can isolate x by subtracting 4 from both sides of the equation:
x + 4 = ±√15
x = -4 ±√15
Therefore, the solutions to the equation (x + 4)^2 = 15 are x = -4 + √15 and x = -4 - √15.
whats the area of a rectangle with 25 ft and width 30 ft
[tex]\huge\begin{array}{ccc}A=75ft^2\end{array}[/tex]
The area of a rectangle.
The formula:
[tex]\huge\boxed{A=l\cdot w}[/tex]
[tex]l[/tex] - length of a rectangle
[tex]w[/tex] - width of a rectangle
SOLUTION:[tex]l=25ft,\ w=30ft[/tex]
substitute:
[tex]A=25\cdot30=750ft^2[/tex]
Identify the roots of the quadratic function. What is the product when the roots are multiplied?
Check the picture below.
[tex]\begin{cases} x = -1 &\implies x +1=0\\ x = 3 &\implies x -3=0\\ \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{original~polynomial}{a ( x +1 )( x -3 ) = \stackrel{0}{y}}\implies a(x^2-2x-3)=y\hspace{5em}\stackrel{\textit{\LARGE product}}{x^2-2x-3}[/tex]
now, that's not the equation of the parabola, unless the value of "a" is 1, but in this case, doesn't matter, we just need that product part.
Every purchase of a product or service is an exchange of value. A product or service is traded for money that is equal to the value of the product or service.
You are correct, every purchase of a product or service is an exchange of value. In a transaction, a product or service is traded for money that is equal to the value of the product or service.
This is known as the "exchange of value" and is a fundamental concept in economics. The buyer is willing to pay the seller for the product or service because they believe it is worth the amount of money being exchanged.
On the other hand, the seller is willing to provide the product or service in exchange for the money because they believe that the money is worth more than the product or service y are providing. In this way, both parties benefit from the exchange and the transaction is completed.
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Find the area of each parallelogram. Remember to use A = bh.
8 x 9
The area of the parallelogram is
The area of the parallelogram with base of 8cm and height of 9cm is 72cm²
How to determine the area of the parallelogramIt is important to note the following properties of a parallelogram;
Opposite sides are equalOpposite angles are equalSame-Side interior angles (consecutive angles) are supplementary, that is , equal to 180 degreesEach diagonal of a parallelogram divides the shape two equal triangleThe diagonals of a parallelogram bisect each otherFrom the information given, we have that;
Area = bh
Given that;
b is the base of the parallelogramh is the height of the parallelogramNow, substitute the values
Area = 8(9)
Area = 72cm²
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Knowledge Check Solve for u. -(2)/(7)u=-14 Simplify your answer as much as possible. u
The solution to the equation -(2)/(7)u=-14 is u = 49.
Knowledge of inverse operations tells us that we need to multiply both sides of the equation by the reciprocal of -(2)/(7) to cancel out the fraction on the left side of the equation. The reciprocal of -(2)/(7) is -(7)/(2).
Multiply both sides of the equation by -(7)/(2):
u = -(7)/(2) * -(2)/(7)u = -(7)/(2) * -14
Simplify the left side of the equation:
u = 49
Solve for u:
u = 49
Therefore, the solution to the equation -(2)/(7)u=-14 is u = 49.
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Solve the following matrix equation for a, b, c, and d. |a-b b+c | = |13 1| |3d+c 2a-4d| |9 12|
To solve the matrix equation for a, b, c, and d, we can equate the corresponding elements of the matrices on both sides of the equation.
So, we get the following system of equations:
a - b = 13 (1)
b + c = 1 (2)
3d + c = 9 (3)
2a - 4d = 12 (4)
From equation (1), we can express b in terms of a:
b = a - 13 (5)
Substituting equation (5) into equation (2), we get:
a - 13 + c = 1
a + c = 14 (6)
From equation (3), we can express c in terms of d:
c = 9 - 3d (7)
Substituting equation (7) into equation (6), we get:
a + 9 - 3d = 14
a - 3d = 5 (8)
Substituting equation (5) into equation (4), we get:
2a - 4d = 12
a - 2d = 6 (9)
Subtracting equation (9) from equation (8), we get:
d = -1
Substituting d = -1 into equation (7), we get:
c = 9 - 3(-1) = 12
Substituting d = -1 and c = 12 into equation (6), we get:
a + 12 = 14
a = 2
Substituting a = 2 and d = -1 into equation (5), we get:
b = 2 - 13 = -11
So, the solution is a = 2, b = -11, c = 12, and d = -1.
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Find the nth term for the following sequence-5,-2,3,10,19
Answer: To find the nth term of the sequence -5, -2, 3, 10, 19, we need to identify the pattern in the sequence.
Starting with the first term, we can see that we are adding 3 to get to the second term, adding 5 to get to the third term, adding 7 to get to the fourth term, and adding 9 to get to the fifth term.
So, the pattern is that each term is obtained by adding (n-1) x 2, where n is the position of the term in the sequence (starting with n=1 for the first term).
Therefore, the nth term of the sequence is:
-5 + (n-1) x 2
Simplifying this expression, we get:
-5 + 2n - 2 = 2n - 7
So, the nth term of the sequence is 2n - 7.
Step-by-step explanation:
USE A MODEL Without advertising, a Web site had 96 total visits. Today, the owners of the site are starting a new promotion, which is expected to double the total number of visits to their Web site every 5 days. a. Write an equation that relates the total number of visits, v, to the number of days the promotion has been running, d.
The equation that relates the total number of visits to the number of days the promotion has been running is v = 96 × [tex]2^{\frac{d}{5} }[/tex] .
What is an equation?When an equal sign connects two expressions then, it is called an equation.
According to the question, the total number of visits doubled after every 5 days.
So, after 5 days visits= 96×2
After 10 days visits= 96×2×2
After 15 days visists= 96×2×2×2
Therefore, it is a proportional sequence.
Hence, the equation that relates the total number of visits, v, to the number of days the promotion has been running, d comes out to be:
v = 96 × [tex]2^{\tfrac{d}{5} }[/tex]
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elect all expressions that represent a correct solution to the equation 6(x + 4) = 20.
A. (20-4) +6
D.
B. (20-4)
C. 20-6-4
206-4
E.
(20-24)
F. (20-24) +6
The correct solution to the equation is (20 - 24)/6
How to determine the correct solutionFrom the question, we have the following parameters that can be used in our computation:
6(x + 4) = 20.
There are many different expressions that can represent a correct solution to an equation
These expression depends on the specific equation and context.
Open the bracketss
So, we have
6x + 24 = 20
Collect the like terms
6x = 20 - 24
Divide both sides by 6
So, we have the following representation
x = (20 - 24)/6
Hence, the correct expression in the equation solution is (20 - 24)/6
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PLEASE HELP
Bob climbed down a ladder from his roof, while Roy climbed up another ladder next to Bob’s ladder. Each ladder had 30 rungs. Their friend Jill recorded the following information about Bob and Roy:
Bob went down two rungs every second.
Roy went up one rung every second.
At some point, Bob and Roy were at the same height. Which rung were they on?
If Rοy is οn the 10th rung, then Bοb is οn the 30 - 2t = 30 - 20 = 10th rung as weII, since they wiII be at the same height at this pοint. Therefοre, the answer is that Bοb and Rοy were οn the 10th rung when they were at the same height.
Let's start by figuring οut hοw fast each persοn is mοving in terms οf rungs per secοnd. We knοw that Bοb is gοing dοwn twο rungs every secοnd, sο his speed is -2 rungs/secοnd (the negative sign indicates that he is gοing dοwn). SimiIarIy, we knοw that Rοy is gοing up οne rung every secοnd, sο his speed is +1 rung/secοnd.
We want tο knοw at which rung Bοb and Rοy wiII be at the same height, sο Iet's caII that rung "R". We can set up an equatiοn tο describe this situatiοn:
30 - 2t = R (Bοb's pοsitiοn at time t)
R = rt (Rοy's pοsitiοn at time t)
Here, t is the time that has eIapsed since Bοb and Rοy started cIimbing. We knοw that they started at the bοttοm οf their respective Iadders, sο we can assume that t is the same fοr bοth οf them.
Nοw we can sοIve fοr R by setting the twο expressiοns equaI tο each οther:
30 - 2t = rt
We can sοIve fοr t by rearranging the equatiοn:
t = 30/(r+2)
Substituting this vaIue οf t back intο either οf the οriginaI equatiοns wiII give us the vaIue οf R:
R = rt = r * 30 / (r+2)
Tο find the vaIue οf r that makes R an integer (since we're Iοοking fοr the rung they're οn), we can try different vaIues οf r untiI we find οne that wοrks. Starting with r=1:
R = 1 * 30 / (1+2) = 10
This means that if Rοy is οn the 10th rung, then Bοb is οn the 30 - 2t = 30 - 20 = 10th rung as weII, since they wiII be at the same height at this pοint. Therefοre, the answer is that Bοb and Rοy were οn the 10th rung when they were at the same height.
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Write the first five terms of a sequence, don’t make your sequence too simple. Write both an explicit formula and a recursive formula for a general term in the sequence.
Answer:
One example of a sequence is the Fibonacci sequence, which starts with 0 and 1, and each subsequent term is the sum of the two preceding terms:
0, 1, 1, 2, 3, ...
To write the explicit formula for the nth term of the Fibonacci sequence, we can use Binet's formula:
Fn = [((1 + sqrt(5))/2)^n - ((1 - sqrt(5))/2)^n]/sqrt(5)
where Fn is the nth term in the sequence.
To write the recursive formula for the Fibonacci sequence, we can use the definition:
F0 = 0, F1 = 1, and Fn = Fn-1 + Fn-2 for n ≥ 2.
So the first five terms of the Fibonacci sequence are:
F0 = 0
F1 = 1
F2 = 1 (0 + 1)
F3 = 2 (1 + 1)
F4 = 3 (1 + 2)
F5 = 5 (2 + 3)
The explicit formula for the nth term in the sequence is:
Fn = [((1 + sqrt(5))/2)^n - ((1 - sqrt(5))/2)^n]/sqrt(5)
The recursive formula for the nth term in the sequence is:
Fn = Fn-1 + Fn-2 for n ≥ 2, with F0 = 0 and F1 = 1.
Find EG if FG = 8, EH = x - 1, and EG = x + 1
If FG = 8, EH = x - 1: EG = x + 1
How to find EG?In order to find EG, we need to use the fact that the sum of the lengths of the segments EF and FG is equal to the length of segment EG. That is,
EF + FG = EG
We are given that FG = 8, and we know that EH + HF = EF. Therefore,
EF = EH + HF
Putting this all together, we get:
EF + FG = EG
(EH + HF) + 8 = x + 1
EH + HF = x - 7
But we also know that EH = x - 1, so we can substitute that in:
x - 1 + HF = x - 7
Simplifying this equation, we get:
HF = -6
Now we can use the fact that the sum of the lengths of the segments EH and HF is equal to the length of segment EF. That is,
EH + HF = EF
(x - 1) + (-6) = EF
x - 7 = EF
Finally, we can substitute this value for EF into our original equation to find EG:
EF + FG = EG
(x - 7) + 8 = EG
x + 1 = EG
Therefore, EG = x + 1.
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