Enter the correct answer in the box.
Write the expression 12-2 in simplest form.

The value of (f· g)(x) from the given functions is  -x^4 - x^2 - x.

Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

Here,

The given functions are f(x)=x³+x+1 and g(x)=-x.

(f·g)(x)= f(x) × g(x)

= (x³+x+1) × (-x)

=  -x^4 - x^2 - x

so, e get,

(g·f)(x)= g(x) × f(x)

= (-x) × (x³+x+1)

= -x^4 - x^2 - x

Therefore, the value of (f· g)(x) from the given functions is  -x^4 - x^2 - x.

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Step-by-step explanation:

To find the zeros of the function f(x), we need to solve the equation f(x) = 0.

f(x) = x^2 + 12x + 32

Setting f(x) equal to zero and factoring, we get:

0 = x^2 + 12x + 32

0 = (x + 4)(x + 8)

Using the zero product property, we set each factor equal to zero and solve for x:

x + 4 = 0 or x + 8 = 0

x = -4 or x = -8

Therefore, the zeros of the function f(x) are -4 and -8.

Answer: 76

Step-by-step explanation:

58 and 18 are both numbers that don't have any variables, so they are like terms, so you just add them together

58+18=76

If you need to break it down a bit more:

50+10=60

8+8=16

60+16=76

The relationship that has a zero slope is option a, he first column, x, has the entries, negative 3, negative 1, 1, 3. The second column, y, has the entries, 2, 2, 2, 2.

Positive slopes and negative slopes are absent from horizontal lines. A horizontal line's slope is always zero. This is due to the fact that it has a constant height—if we use the rise over run technique, rise will always be 0 regardless of what run is.

Option A is the connection with a zero slope.

Regardless of the x-values, option A's y-values are all fixed at (2). This implies that for any change in x (run), the change in y (rise) is always zero, resulting in a slope of zero.

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Other interactions that are confounded with the blocks are BCD and BCD.

(a) Constructing a one replicate of a 24 factorial design in factors A, B, C, and D in blocks of size 4 by confounding the interactions ABC and ACD with the blocks:

1. Number the blocks from 1 to 4.

2. Assign the factor levels to each block, so that the interactions ABC and ACD are confounded. One possible way to do this is as follows:

3. List the contents of two blocks, one of which contains the treatment combination (1) and the other contains treatment combination a.

(b) Other interactions that are confounded with the blocks are BCD and BCD.

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The solution of system of equation is (0, -3).

System A:
Line 1: y = -3x
Line 2: y = -3x + 1

This system of equations is inconsistent. This means the system has no solution. The two lines are parallel and will never intersect, therefore there is no solution to this system of equations.

System B:
Line 1: y = x - 3
Line 2: 2x + 3y = -9

This system of equations is consistent independent. This means the system has a unique solution. The two lines will intersect at one point, which is the solution to this system of equations. We can solve for x and y by using substitution or elimination method.

Using substitution method:
2x + 3(x - 3) = -9
2x + 3x - 9 = -9
5x = 0
x = 0

Substituting x = 0 into Line 1:
y = 0 - 3
y = -3

Solution: (0, -3)

System C:
Line 1: y = -2x - 3
Line 2: y = x + 3

This system of equations is consistent independent. This means the system has a unique solution. The two lines will intersect at one point, which is the solution to this system of equations. We can solve for x and y by using substitution or elimination method.

Using elimination method:
y + 2x = -3
y - x = 3

Adding the two equations:
3x = 0
x = 0

Substituting x = 0 into Line 1:
y = -2(0) - 3
y = -3

Solution: (0, -3)

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Answer:

y ≈ 27

Step-by-step explanation:

using the tangent ratio in the right triangle

tan48° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{30}{y}[/tex] ( multiply both sides by y )

y × tan48° = 30 ( divide both sides by tan48° )

y = [tex]\frac{30}{tan48}[/tex] ≈ 27 ( to the nearest whole number )

The correct measure is given as follows:

x = 6.

Vertical angles are angles that are opposite by the same vertex on crossing segments, hence they share a common vertex, thus being congruent, meaning that they end up having the same angle measure.

Over vertex C, the two angles are congruent, hence the value of x is obtained as follows:

12x - 9 = 6x + 27

6x = 36

x = 6.

(as the vertical angles are congruent, we can just equal the measures of the two angles and then solve the expression for the value of x).

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Step-by-step explanation:

Step 1: Simplify the identity we need to find

[tex] \sin(2x) = 2 \sin(x) \cos(x) [/tex]

So we need to find sin and cos

Here, we are given tan(x)

A simple way to find sin (x) and cos(x) when given tan(x) is to use the definition of the trig functions of acute angles.

[tex] \tan( \alpha ) = \frac{y}{x} [/tex]

[tex] \cos( \alpha ) = \frac{x}{r} [/tex]

[tex] \sin( \alpha ) = \frac{y}{r} [/tex]

where r is

[tex]r = \sqrt{ {x}^{2} + {y}^{2} } [/tex]

Here, y is 4 and x is 3.

So

[tex]r = \sqrt{ {3}^{2} + {4}^{2} } = 5[/tex]

Since both cosine and sine are in quadrant 3, they are both negative.

Know we can plug in the knowns, since we know x,y, and r.

[tex] \cos( \alpha ) = - \frac{3}{5} [/tex]

[tex] \sin( \alpha ) = - \frac{4}{5} [/tex]

Now plug in the knowns for sin 2a

[tex] \sin(2 \alpha ) = 2( - \frac{3}{5} )( - \frac{4}{5} ) = \frac{24}{25} [/tex]

The expanded form of the expression as a sum constant multiple of logarithms is:

log₄(xy⁵z⁴) = log₄(x) + 5log₄(y) + 4log₄(z)

There are four basic properties of logarithms:

logₐ(xy) = logₐx + logₐy.

logₐ(x/y) = logₐx - logₐy.

logₐ(xⁿ) = n logₐx.

logₐx = logₓa / logₓb.

According to the problem, we will use some of the basic logarithmic properties,

Given expression,

log₄(xy⁵z⁴)

We can use the properties of logarithms to expand the expression:

log₄(xy⁵z⁴) = log₄(x) + log₄(y⁵) + log₄(z⁴)

Using the properties of logarithms, we can separate the terms inside the logarithm as separate logarithms, where the multiplication of variables is represented as a sum of logarithms.

So, we have:

log₄(xy⁵z⁴) = log₄(x) + 5log₄(y) + 4log₄(z)

Therefore, the expanded form of the expression as a sum constant multiple of logarithms is:

log₄(xy⁵z⁴) = log₄(x) + 5log₄(y) + 4log₄(z)

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We cannot determine if T is a one-to-one linear operator without more information about the values of N, M, and P2

Yes, T: R3 R3 is a one to one linear operator.

Let x, y, z be elements of R3, then T(x, y, z) = (W1, W2, W3), where W1 = 2Nx - 3y + Mz, W2 = x + 3y - P2 and W3 = -x - Ny + z.

To determine if this is a one to one linear operator, we must show that given two inputs, x, y, z and x', y', z' we have that T(x, y, z) = T(x', y', z') implies x = x', y = y' and z = z'.

We can see that W1 = W1', W2 = W2' and W3 = W3' implies that 2Nx - 3y + Mz = 2Nx' - 3y' + Mz', x + 3y - P2 = x' + 3y' - P2' and -x - Ny + z = -x' - Ny' + z'

Expanding the expressions and simplifying, we have that 2N(x - x') - 3(y - y') + M(z - z') = 0, x - x' + 3(y - y') - P2(z - z') = 0 and -(x - x') - N(y - y') + (z - z') = 0.

Since the expressions must be 0 for all inputs x, y, z and x', y', z' these imply that x = x', y = y' and z = z'. Therefore, T: R3 R3 is a one to one linear operator.
A linear operator T: R3 → R3 is one-to-one if and only if the only solution to the equation T(x, y, z) = (0, 0, 0) is (x, y, z) = (0, 0, 0). In other words, the kernel of T is trivial.

Let's substitute the given values of W1, W2, and W3 into the equation T(x, y, z) = (0, 0, 0) and solve for x, y, and z:

2Nx - 3y + Mz = 0

x + 3y - P2 = 0

-x - Ny + z = 0

From the second equation, we can solve for x in terms of y:

x = P2 - 3y

Substituting this into the first equation gives:

2N(P2 - 3y) - 3y + Mz = 0

Simplifying and rearranging terms:

(6N + 3)y = 2NP2 + Mz

y = (2NP2 + Mz)/(6N + 3)

Substituting this back into the equation for x gives:

x = P2 - 3(2NP2 + Mz)/(6N + 3)

Finally, substituting these values of x and y into the third equation gives:

-(P2 - 3(2NP2 + Mz)/(6N + 3)) - N(2NP2 + Mz)/(6N + 3) + z = 0

Simplifying and rearranging terms:

z(6N + 3 - M - 3N) = P2(6N + 3) - 6NP2

z = (P2(6N + 3) - 6NP2)/(6N + 3 - M - 3N)

Now we have expressions for x, y, and z in terms of the constants N, M, and P2. If these expressions are all equal to zero, then the only solution to the equation T(x, y, z) = (0, 0, 0) is (x, y, z) = (0, 0, 0), and T is a one-to-one linear operator.

However, it is not clear from the given information if these expressions are all equal to zero. Therefore, we cannot determine if T is a one-to-one linear operator without more information about the values of N, M, and P2.

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In answering the question above, the solution is If you know the lengths Pythagorean theorem of the other two sides of the right triangle, you may use these formulae to determine the length of the missing side.

The fundamental Euclidean geometry relationship between the three sides of a right triangle is the Pythagorean Theorem, sometimes referred to as the Pythagorean Theorem. This rule states that the areas of squares with the other two sides added together equal the area of the square with the hypotenuse side. According to the Pythagorean Theorem, the square that spans the hypotenuse (the side that is opposite the right angle) of a right triangle equals the sum of the squares that span its sides. It may also be expressed using the standard algebraic notation, a2 + b2 = c2.

[tex]a^2 + b^2 = c^2[/tex]

where a and b are the lengths of the other two sides, and c is the length of the hypotenuse.

c = √[tex](a^2 + b^2)[/tex]

You may rewrite the formula as follows to get the length of one of the other sides:

a = √[tex](c^2 - b^2)[/tex]

b = √[tex](c^2 - a^2)[/tex]

If you know the lengths of the other two sides of the right triangle, you may use these formulae to determine the length of the missing side.

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The value of the variable 'x' in the isosceles right-angle triangle will be 2√2 units.

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as,

H² = P² + B²

The length of the hypotenuse is 4. And the triangle is an isosceles right triangle.

In the isosceles right triangle, the perpendicular and base of the triangle will be the same. Then the value of the variable 'x' is given as,

4² = x² + x²

2x² = 16

x² = 8

x = 2√2

The value of the variable 'x' in the isosceles right-angle triangle will be 2√2 units.

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Answer:

X is Greater than or equal to 31/10

For the logarithmic function y = log (5x+6), the domain is (-6/5, [infinity]).

The domain of a logarithmic function is the set of all values for which the function is defined. In the case of y = log(5x+6), the function is only defined for values of x that make the expression inside the logarithm, 5x+6, greater than zero. This is because the logarithm of a negative number or zero is not defined.

To find the domain analytically, we need to solve the inequality 5x+6 > 0 for x:

5x+6 > 0

5x > -6

x > -6/5

This means that the domain of the function is all values of x greater than -6/5. In interval notation, this can be written as (-6/5, infinity).

So the domain of the logarithmic function y = log(5x+6) is (-6/5, infinity).

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Answer:

[tex]\displaystyle 1-\dfrac{5}{4}x+\dfrac{5}{8}x^2-\dfrac{5}{32}x^3+\dfrac{5}{256}x^4-\dfrac{1}{1024}x^5[/tex]

Step-by-step explanation:

A binomial expansion is the result of multiplying out the brackets of a polynomial with two terms.

Use the binomial formula to expand the given expression.

[tex]\displaystyle \left(1+ax\right)^n=1+\binom{n}{1}(ax)+\binom{n}{2}(ax)^2+\binom{n}{3}(ax)^3+...+(ax)^n[/tex]

where:

[tex]\displaystyle \binom{n}{r}=\dfrac{n!}{r!(n-r)!}=\phantom{l}^nC_r[/tex]

Given expression:

[tex]\left(1-\dfrac{1}{4}x\right)^5[/tex]

Therefore:

Substitute a = -1/4 and n = 5 into the binomial formula:

[tex]\displaystyle =1+\binom{5}{1}\left(-\dfrac{1}{4}x\right)+\binom{5}{2}\left(-\dfrac{1}{4}x\right)^2+\binom{5}{3}\left(-\dfrac{1}{4}x\right)^3+\binom{5}{4}\left(-\dfrac{1}{4}x\right)^4+\left(-\dfrac{1}{4}x\right)^5[/tex]

[tex]\displaystyle =1+5\left(-\dfrac{1}{4}x\right)+10\left(\dfrac{1}{16}x^2\right)+10\left(-\dfrac{1}{64}x^3\right)+5\left(\dfrac{1}{256}x^4\right)+\left(-\dfrac{1}{1024}x^5\right)[/tex]

[tex]\displaystyle =1-\dfrac{5}{4}x+\dfrac{10}{16}x^2-\dfrac{10}{64}x^3+\dfrac{5}{256}x^4-\dfrac{1}{1024}x^5[/tex]

[tex]\displaystyle =1-\dfrac{5}{4}x+\dfrac{5}{8}x^2-\dfrac{5}{32}x^3+\dfrac{5}{256}x^4-\dfrac{1}{1024}x^5[/tex]

Therefore, the expansion of (1 - ¹/₄x)⁵ is:

[tex]\displaystyle \left(1-\dfrac{1}{4}x\right)^5=1-\dfrac{5}{4}x+\dfrac{5}{8}x^2-\dfrac{5}{32}x^3+\dfrac{5}{256}x^4-\dfrac{1}{1024}x^5[/tex]

Please note there was note enough room to add the binomial coefficients calculations to the main calculation, so please find them below:

[tex]\displaystyle \binom{5}{1}=\dfrac{5!}{1!(5-1)!}=\dfrac{5\times \diagup\!\!\!\!4\times\diagup\!\!\!\!3\times\diagup\!\!\!\!2\times\diagup\!\!\!\!1}{1\times\diagup\!\!\!\!4\times\diagup\!\!\!\!3\times\diagup\!\!\!\!2\times\diagup\!\!\!\!1}=\dfrac{5}{1}=5[/tex]

[tex]\displaystyle \binom{5}{2}=\dfrac{5!}{2!(5-2)!}=\dfrac{5\times 4\times\diagup\!\!\!\!3\times\diagup\!\!\!\!2\times\diagup\!\!\!\!1}{2 \times 1\times \diagup\!\!\!\!3\times\diagup\!\!\!\!2\times\diagup\!\!\!\!1}=\dfrac{20}{2}=10[/tex]

[tex]\displaystyle \binom{5}{3}=\dfrac{5!}{3!(5-3)!}=\dfrac{5\times 4\times\diagup\!\!\!\!3\times\diagup\!\!\!\!2\times\diagup\!\!\!\!1}{\diagup\!\!\!\!3\times\diagup\!\!\!\!2\times\diagup\!\!\!\!1\times2 \times 1\times}=\dfrac{20}{2}=10[/tex]

[tex]\displaystyle \binom{5}{4}=\dfrac{5!}{4!(5-4)!}=\dfrac{5\times \diagup\!\!\!\!4\times\diagup\!\!\!\!3\times\diagup\!\!\!\!2\times\diagup\!\!\!\!1}{\diagup\!\!\!\!4\times\diagup\!\!\!\!3\times\diagup\!\!\!\!2\times\diagup\!\!\!\!1 \times 1}=\dfrac{5}{1}=5[/tex]

The formula for the pressure of a gas is given by the Ideal Gas Law, which states that P = nRT/V, where P is the pressure, n is the amount of gas in moles, R is the ideal gas constant, T is the temperature in kelvin, and V is the volume in cubic centimeters (cc).

Given the initial conditions, we can find the value of the ideal gas constant R:
1170 kpa = (6 moles)(R)(260 K) / (720 cc)
R = (1170 kpa)(720 cc) / (6 moles)(260 K)
R = 8.27 kpa·cc/mol·K
Now, we can use this value of R to find the pressure under the new conditions:
P = (3 moles)(8.27 kpa·cc/mol·K)(280 K) / (180 cc)
P = 3898.6 kpa·cc / 180 cc
P = 2166 kpa

Therefore, the pressure of the gas when the number of moles is 3, the temperature is 280 K, and the volume is 180 cc is 2166 kpa.

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If you have a 3600 m³ cube, then you can fit 3600 kiloliters in the cube.

A kiloliter (kL) is defined as a unit of volume which is used to measure liquids. It is equal to 1,000 liters, and it is used to measure large volumes of water, oil, and other liquids.

We know that 1 cubic meter is equal to 1 kiloliter,

We have to convert 3600 meter cube to Kiloliter,

So , we multiply by 3600,

On multiplying,

We get,

⇒ 3600 meter cube = 3600 × 1 Kiloliter,

⇒ 3600 meter cube = 3600 Kiloliter,

Therefore, 3600 Kiloliter can fill in the cube having the volume as 3600 meter cube.

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Step-by-step explanation:

Let the number of students in each van be "x" and the number of students in each bus be "y". We can then set up a system of equations to represent the given information:

From High School A: 8x + 8y = 240

From High School B: 4x + y = 54

We can use the second equation to solve for y in terms of x:

y = 54 - 4x

We can then substitute this expression for y into the first equation and solve for x:

8x + 8(54 - 4x) = 240

8x + 432 - 32x = 240

-24x = -192

x = 8

Now that we know x = 8, we can use the equation for y to solve for y:

y = 54 - 4x = 54 - 4(8) = 22

Therefore, there were 8 students in each van and 22 students in each bus.

7/25 = x/100 17•100= 1700÷25=

60 answer is 68%

To compare fractions using equivalent fractions, we need to find a common denominator, convert each fraction to an equivalent fraction with that denominator, and then compare the numerators directly.

To compare fractions 3/4 and 7/12 using equivalent fractions, we need to find a common denominator for both fractions. A common denominator is a number that is divisible by all the denominators of the fractions being compared. In this case, the least common denominator (LCD) for 4 and 12 is 12.

To convert 3/4 to an equivalent fraction with a denominator of 12, we need to multiply both the numerator and denominator by 3. This gives us the equivalent fraction of 9/12.

To convert 7/12 to an equivalent fraction with a denominator of 12, we need to multiply both the numerator and denominator by 1. This gives us the equivalent fraction of 7/12.

Now that both fractions have the same denominator, we can compare them directly. We can see that 9/12 is greater than 7/12 since 9 is greater than 7. Therefore, 3/4 is greater than 7/12.

This method allows us to compare fractions with different denominators and make accurate comparisons based on the relative size of the numerators.

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The cord length is k* theta radian, where theta radian is the central angle and k is the proportionality constant. This means that the rope length is proportional to the central angle in radians.

The complete cord length for a full central angle of 2pai is 2pai * r if the cord arc is a segment of a circle of radius r, where k=2pai is the proportionality constant.

What is arc?

In mathematics, an arc is a portion of the boundary of a circle or curve. It is sometimes referred to as an open curve.

The measurement around a circle that determines its edge is called the circumference, often known as the perimeter. As a result, the distance between any two locations along an arc's circumference is how it is defined.

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The area of rectangle S is 84.15 square unit.

Area is the region enclosed by the shape of an object. The space covered by a figure or any two-dimensional geometric shape in the plane is the area of ​​the shape, or

Area is a measure of the surface area of ​​a shape. To find the area of ​​a rectangle or square, you need to multiply the length and width of the rectangle or square.

Solution according to the given information in the question:

Area of rectangle R = 187

Ratio of rectangle R = 17

Ratio of rectangle S = 7.65

Area of rectangle S = (7.65/17)×187

                                 = 84.15 square unit

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From left to right, function f has zeros at x = 0, x = 3, x = -3, x = 1/2, and x = -3/2.

An expression, rule, or law in mathematics that explains how one independent variable and one dependent variable are connected (the dependent variable).

The factors of the function f(x) can be found by factoring the expression:

f(x) = 2x⁴ - x³ - 18x² + 9x = x(2x³ - x² - 18x + 9)

To find the zeros of f(x), we need to find the values of x that make the expression in the parentheses equal to zero:

2x³ - x² - 18x + 9 = 0

We can use synthetic division or other methods to factor this polynomial and find its zeros. Alternatively, we can use the Rational Zeros Theorem to test possible rational zeros:

Possible rational zeros: ±1, ±3, ±9, ±1/2, ±3/2, ±9/2

Testing x = 1: 2(1)³ - (1)² - 18(1) + 9 = -8, not a zero

Testing x = -1: 2(-1)³ - (-1)² - 18(-1) + 9 = 28, not a zero

Testing x = 3: 2(3)³ - (3)² - 18(3) + 9 = 0, a zero

Testing x = -3: 2(-3)³ - (-3)² - 18(-3) + 9 = 0, a zero

Using polynomial division or factoring by grouping, we can factor the polynomial further:

2x³ - x² - 18x + 9 = (x - 3)(2x² + 5x - 3)

The quadratic factor can be factored using the quadratic formula or other methods:

2x² + 5x - 3 = (2x - 1)(x + 3)

Therefore, the zeros of f(x) are:

x = 0 (from the factor x)

x = 3 (from the factor x - 3)

x = -3 (from the factor x + 3)

x = 1/2 (from the factor 2x - 1)

x = -3/2 (from the factor 2x - 1)

So the completed statement is:

From left to right, function f has zeros at x = 0, x = 3, x = -3, x = 1/2, and x = -3/2.

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We have proved that a set containing three non-zero vectors in V cannot be linearly independent if {v1, v2} is a spanning set for V.

To prove that a set containing three non-zero vectors in V cannot be linearly independent, we will use the definition of linear independence and the fact that {v1, v2} is a spanning set for V. Here are the steps:

Let {v1, v2, v3} be a set containing three non-zero vectors in V.

Since {v1, v2} is a spanning set for V, any vector in V can be written as a linear combination of v1 and v2. In particular, v3 can be written as v3 = a*v1 + b*v2 for some scalars a and b.

Now, consider the linear combination 0 = c1*v1 + c2*v2 + c3*v3, where c1, c2, and c3 are scalars. Substituting v3 = a*v1 + b*v2, we get 0 = (c1 + a*c3)*v1 + (c2 + b*c3)*v2.

Since {v1, v2} is a spanning set, the only way for this linear combination to be equal to 0 is if both coefficients are 0, i.e., c1 + a*c3 = 0 and c2 + b*c3 = 0.

If c3 = 0, then c1 = 0 and c2 = 0, which means that the set {v1, v2, v3} is linearly independent. However, if c3 is not 0, then we can solve for c1 and c2 in terms of c3, and we get c1 = -a*c3 and c2 = -b*c3.

This means that there are infinitely many solutions to the linear combination 0 = c1*v1 + c2*v2 + c3*v3, and therefore the set {v1, v2, v3} is not linearly independent.

we have proved that a set containing three non-zero vectors in V cannot be linearly independent if {v1, v2} is a spanning set for V.

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The value of x of the triangle is given by the trigonometric relation x = 30°

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

tan θ = sin θ / cos θ

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

Given data ,

Let the triangle be represented as ΔPQR

Now , the measure of side PQ = 48 cm

The measure of side PQ = 96 cm

The measure of ∠x is calculated by

From the trigonometric relations ,

sin x = opposite side / hypotenuse

On simplifying , we get

sin x = 48 / 96

sin x = 1/2

Taking inverse on both sides , we get

x = sin ⁻¹ ( 1/2 )

x = π/6

x = 30°

Therefore , the value of x is 30°

Hence , the angle of the triangle is 30°

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The measure of angle IHJ is 131 degree.

The angle subtended by an arc at the center is twice the angle subtended at the circumference . More simply, the angle at the center is double the angle at the circumference.

From the figure,

3) Given that, arc ML=53 degree

∠LHM = 1/2 ×53

= 26.5

Arc MI = 89°

∠MHI=1/2 × 89°

= 44.5°

Here, ∠IHJ+∠MHI+∠LHM+∠LHK+∠KHJ=360°

∠IHJ+44.5°+26.5°+88°+70°=360°

∠IHJ=360°-229°

∠IHJ=131°

4) Arc WV= 1/2 ×55° = 27.5°

Here, Arc WT = Arc TU + Arc UV + Arc WV

= 50°+100°+27.5°

= 177.5°

5) Here, HG= 1/2 ×40 =20°

Arc FH= Arc FG+ Arc HG°

= 60°+20°

= 80°

Therefore, the measure of angle IHJ is 131 degree.

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The IQR is a measure of the spread or variability of the data. It represents the range of the middle 50% of the data values and is less sensitive to outliers than the range.

The steps below can be used to determine the interquartile range (IQR) in a box plot:

Find the data set's median (Q2) value. With 50% of the data above and 50% of the data below, this value splits the data in half.

Find the lower half of the data set's median (Q1). With 25% of the data above and 75% below, this value divides the lower half of the data into two quarters.

Find the top half of the data set's median (Q3). With 75% of the data above and 25% below, this value divides the upper half of the data into two quarters.

The interquartile range (IQR) is calculated as the difference between the third and first quartiles (Q3 and Q1, respectively).

Below is an illustration to show you how to find the IQR:

Let's say we have the following collection of data:

10, 11, 12, 15, 16, 18, 20, 22, 25, 30

We must determine the quartiles in order to generate a box plot:

Median (Q2) = (16 + 18) / 2 = 17

Lower half: 10, 11, 12, 15, 16

Median (Q1) = (11 + 12) / 2 = 11.5

Upper half: 18, 20, 22, 25, 30

Median (Q3) = (22 + 25) / 2 = 23.5

The IQR is: because the box ranges from Q1 to Q3.

IQR = Q3 - Q1 = 23.5 - 11.5 = 12

Hence, 12 is the interquartile range.

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The equation for the given tangent function is f(x) = 3 tan(x - π/2) - 1.

What is Trigonometric function ?

Trigonometric functions are mathematical functions that relate to angles of a right-angled triangle. The three most common trigonometric functions are sine, cosine, and tangent, which are denoted by sin, cos, and tan, respectively.

The general form of a tangent function is given by:

f(x) = A tan(B(x - C)) + D

where A is the amplitude, B is the frequency (inverse of the period), C is the horizontal shift, and D is the vertical shift.

Given the information, we have:

A = 3

period = π

frequency = 1/period = 1/π

horizontal shift = π/2 to the right

vertical shift = down 1

So, we can plug in the values into the general form and get:

f(x) = 3 tan(1(x - π/2)) - 1

Simplifying:

f(x) = 3 tan(x - π/2) - 1

Therefore, the equation for the given tangent function is f(x) = 3 tan(x - π/2) - 1.

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