A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge per unit length of λ, and the cylinder has a net charge per unit length of 2λ . From this information, use Gauss's law to find (a) the charge per unit length on the inner surface of the cyli
The charge per unit length on the inner surface of the cylinder is 3λL.
The electric flux across any closed surface is proportional to the net electric charge q enclosed by the surface, according to Gauss's law of electricity, which reads as = q/0, where 0 is the electric permittivity of free space, which has a value of 8.854 10-12 square coulombs per newton per square meter.
Here, q stands for charge.
Volt-metres (V m), the SI base unit of electric flux, is also equivalent to newton-meters squared per coulomb (N m2 C-1). On top of that, the fundamental units of electric flux are kgm3s-3A-1.
Q 1 = L as a result of the wire's induction of the cylinder's inner surface.
"q cylinder" is equal to "q in + q out" (cylinder).
L = L + q out
⇒q out =λL+(2λ)
L = q out =3λL
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It takes a sample of molecules 10 s to diffuse 1.0 mm. how long will it take to diffuse 2.0 mm ?
The time taken to diffuse 2.00 mm will be 20 seconds.
The velocity of diffusion(v) is given by the following formula:
v = Distance/Time
We are given that it takes a sample of molecules 10 seconds to diffuse 1.00 mm.
Thus, its velocity is
v = 1.0 mm/10 s = 0.1 mm/s
In the second case, the distance is given, so we can calculate the time required for diffusion by again applying the same formula
0.1 = 2.00 mm/Time
On rearranging above equation, we get
Time = 20 seconds
Thus, the time taken to diffuse 2.00 mm will be 20 seconds.
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When a wave encounters an obstacle or a slit that is comparable in size to its wavelength, it bends around it. This characteristic is called ________.
When a wave encounters an obstacle or a slit that is comparable in size to its wavelength, it bends around it. This characteristic is called diffraction.
Diffraction refers to the phenomenon in which a propagating wave bends when it encounters an obstacle or a slit, especially when the obstacle or slit is similar in size to the wavelength of the wave.
The characteristic pattern produced from a diffracted wave is as a result of the interference of individual spherical wavelets, as described by the Huygens–Fresnel principle. Diffraction occurs in all waves, including water waves, sound waves, electromagnetic waves and even gravitational waves.
Sound waves can also diffract around objects. For example, a person is able to hear his name being called even though he is standing at the other side of an obstacle, as the sound waves bend around the obstacle.
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In a long, straight, vertical lightning stroke, electrons move downward and positive ions move upward and constitute a current of magnitude 20.0kA. At a location 50.0m east of the middle of the stroke, a free electron drifts through the air toward the west with a speed of 300 m/s . (a) Make a sketch showing the various vectors involved. Ignore the effect of the Earth's magnetic field.
A magnetic field, often known as a vector field, describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. A force acting on a charge while it travels through a magnetic field is perpendicular to both the charge's motion and the magnetic field.
In a long, straight, vertical lightning stroke, downward-moving electrons and upward-moving positive ions produce a current of magnitude I = 20.0 kA.
At a location r = 50.0 m east of the stroke's center, a free electron is moving through the atmosphere at a speed of v = 300 m/s.
Let B represent the magnetic field and F represent the magnetic force. The vector sketch may then be represented as follows:
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Marta gives long, involved answers to every question, even simple ones. She uses technical vocabulary even if the people she is talking to do not understand it. What is the BEST advice Marta’s supervisor could give her?
A.
Use technology to your team’s advantage.
B.
Manage information, not people.
C.
Make sure your networks are strong.
D.
Adapt your communication style.
Please HELP
Answer:
D. Adapt your communication style.
Explanation:
It is quite difficult to gauge the protocol here given the lack of information about the work environment; but as a general answer, communication skills are always handy. Furthermore, it seems that Marta in particular struggles with this. Assuming Marta is providing a specialized service of a sort, she would need to understand that there is a reason why her services are required at all. Through this, hopefull she'll understand that they are most likely outside of this field of work, and ergo [she] must cater and gear her actions towards the interest of the person(s) in question.
It is to be noted that this is merely my surmise.
Describe how you would measure the diameter of a tennis ball
As the people sing in church, the sound level everywhere inside is 101 dB . No sound is transmitted through the massive walls, but all the windows and doors are open on a summer morning. Their total area is 22.0 m² . (a) How much sound energy is radiated through the windows and doors in 20.0 min?
The sound energy radiated through the windows and doors in 20 min is 332.6 J.
What do you mean by Sound energy?When a force, such as sound or pressure, causes an item or substance to vibrate, the result is sound energy. That energy moves through the substance in waves. Those sound waves are called kinetic mechanical energy. Sound waves are sometimes dubbed mechanical waves because sound waves require a physical medium to propagate. Liquids, gases, or solid materials transfer pressure variations, creating mechanical energy in waves. Like all waves, sound waves include peaks and valleys. The peaks are called compressions, while rarefaction is the term used for the lows. The oscillations between compression and rarefaction move through gaseous, liquid, or solid media to produce energy. The number of compression/rarefaction cycles in a given period determines the frequency of a sound wave.
Sound energy = E = power x time
energy = force x time / area
Given:
sound level, [tex]\beta=101 dB[/tex]
Area, A = [tex]22\;m^{2}[/tex]
Time, [tex]\triangle t=20\;min=1200\;s[/tex]
Intensity, [tex]I_{o}=1 \times 10^{-12}\;W/m^{2}[/tex]
We know that, Sound level is,
[tex]\beta=10 \times log\frac{I}{I_{o} }[/tex]
Solving the above equation for sound intensity,
[tex]I=I_{o}\times 10^{\frac{\beta}{10} }[/tex]
[tex]I=I \times 10^{-12} \times 10^{\frac{101}{10} }[/tex]
[tex]I=0.0126\;W/m^{2}[/tex]
Therefore, The sound energy is,
[tex]E = P \times \triangle t[/tex]
Substitute [tex]P=I \times A[/tex] in the above equation,
[tex]E = I \times A \times \triangle t[/tex]
[tex]E = 0.0126 \times 22 \times 1200[/tex]
[tex]E = 332.6\;J[/tex]
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a mass on a spring undergoing simple harmonic motion completes 8 oscillations in 4.0 s. what is the period of the motion?
The period of oscillation is 0.5 second.
We need to know about period of oscillation to solve this problem. Period is how much time taken to do one oscillation. It can be determined as
T = t / n
where T is period, t is time and n is how many oscillations.
From the question above, we know that
n = 8
t = 4 s
By substituting the parameters, we get
T = t / n
T = 4 / 8
T = 0.5 second
Hence, the period of oscillation is 0.5 second.
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A cheetah can accelerate from rest to a speed of 30. 0 m/s in 7. 00 s. What is its acceleration?.
The cheetah that can accelerate from rest to a speed of 30.0 m/s in 7.00s has an acceleration of: 4.285 m/s²
The formula and procedure we will use to solve this exercise is:
a = (vf - vi) /t
Where:
a = accelerationvf = final velocityvi = initial velocityt = timeInformation about the problem:
vi= 0 m/svf = 30.0 m/st = 7.00 sa=?Applying the acceleration formula we have:
a = (vf - vi) /t
a = (30.0 m/s - 0 m/s) /7.00 s
a = (30.0 m/s m/s) /7.00 s
a = 4.285 m/s²
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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Review. A global positioning system (GPS) satellite moves in a circular orbit with period 11h 58 min.(b) Determine its speed.
The global positioning system (GPS) satellite that moves in a circular orbit with period of 11h 58 min has a speed of: 3872.9848 m/s
To solve this problem the formulas and the procedures we will use are:
r =[(G* m *T²)/(4 * π²)]v = (2*π * r)/ TWhere:
r = orbital radiusG = Gravitational constantm = Mass of the EarthT = Time period of the satelliteπ = mathematical constantv = tangential velocityInformation about the problem:
T = 11h 58 minG = 6.67 × 10⁻¹¹ m³/kgs²m= 5.972 × 10²⁴ kgπ = 3.1416r =?v =?By converting the time period of (h) and (min) from (s) we have:
T = (11h *3600 s/ 1 h) + (58 min * 60 s/1 min)
T = 39600 s +3480 s
T = 43080 s
Applying the orbital radius formula we get:
r =[(G* m *T²)/(4 * π²)]
r =[(6.67 × 10⁻¹¹ m³/kgs² * 5.972 × 10²⁴ kg *(43080 s)²)/(4 * (3.1416)²)]
r =[1.8725*10^22 m³]
r= 26.55465166*10^6 m
Applying the tangential velocity formula we get:
v = (2*π * r)/ T
v = (2 * 3.1416 * 26.55465166*10^6 m)/ 43080 s
v = 3872.9848 m/s
What is the orbital radius?It is the maximum of the radial distribution curve of the outermost orbital.
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a large beaker of water is filled to its rim with water. a block of wood is then carefully lowered into the beaker until the block is floating. in this process, some water is pushed over the edge and collects in a tray. the weight of the water in the tray is a large beaker of water is filled to its rim with water. a block of wood is then carefully lowered into the beaker until the block is floating. in this process, some water is pushed over the edge and collects in a tray. the weight of the water in the tray is less than the weight of the block. greater than the weight of the block. equal to the weight of the block.
The correct answer is Equal to the weight of the block.
We are aware that when an object floats, the water it displaces weighs the same as the weight of the floating body. The upthrust is now equivalent to the body weight in this situation. The beaker is overflowing with water in this instance. The body was then created to float into it. When it reaches equilibrium in water, it expels water that must have been the same weight as it. Over the edge, the liquid spilled, collecting on the tray.
Therefore, the amount of water gathered on the tray must match the weight of the person floating.
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what does is mean if the VR of the machine is 2?
Answer:
Velocity ratio of simple machine is the ratio of distance traveled by the effort to the distance traveled by the load in the machine. As velocity ratio or ideal mechanical advantage is a simple ratio of two distances.Hence always remains constant. Option A is correct.
*PLEASE MARK AS BRAINLIEST*
Answer:
Velocity ratio of simple machine is the ratio of distance traveled by the effort to the distance traveled by the load in the machine. As velocity ratio or ideal mechanical advantage is a simple ratio of two distances.Hence always remains constant. Option A is correct.
Explanation:
EXTRA:Velocity ratio of a lever is 3 means distance travelled by effort is 3 times the distance travelled by the load. Efficiency of the pulley is 60% means 40% of the energy is lost in the machine due to the friction.
EXTRA:Ans:- MA of a lever is 3 it means that the load is 3 times of effort and VR of a lever is 4 it means that effort distance is 4 times of load distance.
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The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in 1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n=1.33 is the index of refraction of water.(b) Show that for v<
It is proved that when v<<c , then speed of the light measured in the laboratory frame is , u = c/n + v -v/n^2 .
Given ,
The motion of a transparent medium influences the speed of light .
The water moves with speed v in a horizontal pipe .
Assume that the light travels in the same direction as the water moves .
The speed of the light with respect to the water is c/n
Where n = 1.33 is the refractive index of water .
Let us assume ,
u' be the speed of light in water , in the frame moving with the water .
u' is related to the refractive index of water ,n as :
u'=c/n
where , c is the speed of light .
let , u be the speed of light in water in the lab frame .
Now , u and u' are related as : u = (u'+ v )/(1+ u'v/c^2)
Here v is the speed of water in the horizontal pipe .
we know the value of u' , so by substituting the value , we will get ,
u= (c/n+ v)/(1+cv/nc^2)
u= c/n(1+ nv/c)/(1+v/nc)
(b) We have , v<<c
v/c<<1 .
so , (1+v/nc )^-1 = (1-v/nc)
Now substituting this , we will get ,
u = c/n(1+nv/c) (1-v/nc)
u≈c/n(1+ nv/c-v/cn)
u≈c/n + v - v/n^2
Hence , it is proved that when v<<c , then speed of the light measured in the laboratory frame is , u = c/n + v -v/n^2 .
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Disclaimer : incomplete question , here is the complete question .
Question: The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n=1.33 is the index of refraction of water.(a) Use the velocity transformation equation to show that the speed of the light measured in the laboratory frame isu = c/n (1 + nv/c / 1+ v/nc) . (b) show that for v<<c , the expression from part (a) becomes , to a good approximation , u ≈ c/n + v - v/n^2 .
An object is moving and velocity of 8 m/s and accelerates to 35 m/s or 6.3 seconds. what is the acceleration?
Answer:
4m/s^2
Explanation:
u find the average of the two velocities then place the outcome in the acceleration formula given time as 6.3 seconds .....dividing the average of the velocities
Sam jumped from a plane. His acceleration was -9.8 m/s². He hit the ground in 30
seconds. What was his velocity just before he hit the ground?
The velocity of Sam just before hitting the ground is 294 m/s.
The above situation represents a case of motion in one dimension.
This type of motion is governed by the following three equations of motion,
v = u + at
v² - u² = 2as
S = ut + 1/2 at²
As in the given case, the acceleration and time have been given and the final velocity is to be calculated, therefore the 1st equation can be used,
v = u+ at
As Sam jumped from the plane, his initial velocity is zero.
So,
v = 0 + 9.8(30)
v = 294 m/s.
Thus, Sam's velocity just before hitting the ground is 294 m/s.
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(a) A proton moving with velocity →v = vi experiences a magnetic force →F = Fi(j) . Explain what you can and cannot infer about \overrightarrow{\mathbf{B}} from this information.
The current must be along +x axis.
What is electric current?
A stream of charged particles, such electrons or ions, traveling through an electrical conductor or a vacuum is known as an electric current. It is calculated as the net rate of passage of electric charge through a surface or into a control volume. Charge carriers, which can be any one of a number of particle kinds depending on the conductor, are the moving particles. Electrons travelling through a wire are frequently the charge carriers in electric circuits. They may be electrons or holes in semiconductors. Ions are the charge carriers in an electrolyte, whereas ions and electrons make up plasma, an ionized gas.
Explanation:
Given,
Velocity of proton,V = [tex]V_{i} i[/tex]
Magnetic force,F = [tex]F_{i} j[/tex]
Magnetic Field= B
(a)
If proton (p+) is moving in ve x-direction.
So,current(I) must be along +x axis.
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What does small q show in the following formula: q1=q2=Q=CeqV?
Answer:
A parallel plate capacitor of capacitance C is charged using a battery. • Charge = Q, potential difference = V. • Battery is then disconnected.The electric field is a function of position, but does not depend on the test charge. It is a real entity, because we will show that it carries energy! Hope this helps!
Standing at a crosswalk, you hear a frequency of 560 Hz from the siren of an approaching ambulance. After the ambulance passes, the observed frequency of the siren is 480 Hz . Determine the ambulance's speed from these observations.
[tex]Given data : f01 = 560 hz f02 = 480 hz vs = 340 m/s ( velocity of sound ) vx = velocity of source ( police car )Condition 1 when source approach observer : f01 =[ vs /( vs - vx )].fs ...........(1)Condition 2 when source passes observer : f02 = [vs /( vs + vx) ].fs ............(2)eq(1) : eq (2) we get : f01 / f02 = ( vs + vx )/( vs - vx ) 7/6 = ( 340 + vx ) / ( 340 - vx )[/tex][tex]solve this equation get vx = 26.15 m/s[/tex]
What is frequency?The frequency of a repeated event is its number of instances per unit of time. In certain cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively. One (event) per second is equal to one hertz (Hz), which is how frequency is stated. The period is the reciprocal of the frequency since it represents the length of time for one cycle in a recurring occurrence. For instance, the period, T—the space between beats—of a heart beating at a frequency of 120 beats per minute (2 hertz), is equal to 0.5 seconds (60 seconds divided by 120 beats).
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A football player pushes a 590 n tackling sled. his coach observes this and believes that this is too light and wants to present the player with a greater physical challenge. he asks two players (player a weighs 100 kg and player b weighs 125 kg). the coefficient of static friction between the sled and grass is 0.70. how much force must the player exert to start the tackling sled in motion with players a and b on it
The player has to apply a force of 1956.5N to start tackling sled in motion.
Coefficient of static friction μ[tex]_{s}[/tex] = 0.70
Weight of sled = mg
= 590N
Weight of Player A = [tex]m_{a}g[/tex]
= 100 × 9.8
= 980N
Weight of Player B = [tex]m_{b}g[/tex]
= 125 × 9.8
= 1225N
Combined weight of sled:
W = (590+980+1225)N
= 2795N
Now, friction on sled:
f = μ[tex]_{s}[/tex]R
= 0.70 × 2795
= 1956.5N
Therefore, the player has to apply force equal to static friction to start tackling sled in motion.
∴ Force = Static friction = 1956.5N
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What does weight require?
Responses
gravity and volume
gravity and volume
only mass
only mass
mass and gravity
mass and gravity
mass and volume
Answer:
Mass and gravity
Explanation:
[tex]{ \rm{weight = mass \times gravity}}[/tex]
Weight is the force exerted on an object due to gravity. The correct answer is mass and gravity. The correct option is an option (3).
Weight requires both mass and gravity.
The formula for calculating weight is given by:
Weight = mass × gravitational acceleration
W = m × g
The gravitational acceleration is known by the strength of the gravitational field, which is typically constant at any given point.
The mass of an object and the strength of its gravitational field is its weight. It is the gravitational force that pulls an object toward the center of the Earth.
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Therefore, The correct option is (3).
The complete question is:
What does weight require?
1) gravity and volume
2) only mass
3) mass and gravity
4) mass and volume
if you Launch a cannonball at a launch angle of 55° and an initial speed of 30m/s. What is the cannonball's range?
Answer:
86.2 m range
Explanation:
Vertical component of initial shot = 30 sin 55= 24.575 m/s
Now you can find out for how long it is in the air
when it hits the ground , position = 0
0 = 24.575 t - 1/2 ( 9.81) t ^2
finds t = 5.01 seconds (Using quadratic formula)
HORIZONTAL component = 30 cos 55 = 17.21 m/s
it travels this speed for 5.01 seconds
5.01 * 17.21 = 86.2 m
A seat on a Ferris wheel moves at a constant tangential speed around the wheel. If the seat is 7 m from the center of the wheel and has a tangential speed of 0.5 m/s, what centripetal acceleration does the seat experience?
0.04 m/s2
0.07 m/s2
0.1 m/s2
Answer:
centripetal acceleration formula
a = v²/r
v velocity
r radius
a= .5²/7
a = .25/7
a= .03571
ans .o3571
Answer:
A
Explanation:
2. Do you think the density of the ice affected the melting rate of the ice, or do you think adding the objects affected the melting rates?
The density of ice does not affect its melting rate. Adding objects will affect the melting rate.
A physical process called melting or fusing causes a substance to change its phase from a solid to a liquid. This happens when the solid's internal energy rises, usually as a result of heat or pressure being applied, which raises the substance's temperature to the melting point.The term "density" refers to an extensive quality, which means that it is independent of the substance's concentration. Every substance in the world demonstrates its distinctive density. Since it does not fluctuate, it would not affect the rate of melting. The addition of the objects could speed up the process, though, as each one generates heat that could act as the mediating force for the melting process.To learn more about density, visit :
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orange light has a wavelength, λ, of 6.0 × 10-7 m. in a vacuum, the speed of light, c, is 3.0 × 108 m/s. what is the frequency, f, of the orange light? (remember: 1 hz
The frequency of orange light is 5 x 10¹⁴ Hz or 500 THz.
We need to know about photon frequency to solve this problem. The photon frequency can be determined as
f = c / λ
where f is frequency, c is speed of light (3x10⁸ m/s) and λ is wavelength.
From the question above, we know that:
c = 3x10⁸ m/s
λ = 6 x 10¯⁷ m
By substituting parameters, we get
f = c / λ
f = 3 x 10⁸ /( 6 x 10¯⁷ )
f = 5 x 10¹⁴ Hz
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what happens when a charged insulator is placed near an uncharged metallic object? they exert no electrostatic force on each other. they repel each other. they may attract or repel each other, depending on whether the charge on the insulator is positive or negative. the charged insulator always spontaneously discharges. they attract each other.
A metallic item becomes polarised when a charged insulator is brought close to it, as a result of the free charges in the metal moving about. The centre of charge for the type of charge opposite to that on the insulator will be positioned within the metallic item closer to the charged insulator .
What happens if a charged insulator comes into contact with a conductor?When a negatively charged insulator is in contact with a positively charged conductor, the extra negatively charged electrons will migrate to the conductor until they would prefer not to move at all. We refer to this as the system having attained equilibrium when it occurs.
When an uncharged metal item and a charged insulator are positioned close to one another, the charged insulator will induce the opposite charge, and the two objects will be drawn to one another.
The insulator and a metallic item are therefore attracted to one another by the net electric force.
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Halley’s comet has a perihelion distance of 0. 6 au and an orbital period of 76 years. What is the aphelion distance of halley’s comet from the sun?.
The aphelion distance of Hailey's comet from the sun is 36 A. U.
The perihelion distance of Hailey's comet = 0.6 amu
The orbital period of Hailey's comet = 76 years
According to Kepler's law,
The time duration is T.
T = 76 years.
The semi-major axis is a.
The semi-major axis is,
[tex]T ^{2} =a ^{3} [/tex]
[tex]a = \sqrt[3]{(T) ^{2} }[/tex]
[tex]a = \sqrt[3]{(76) ^{2} }[/tex]
= 18 A. U
The aphelion distance of Hailey's comet from the sun is,
= 2 × a
= 2 × 18
= 36 A. U
Therefore, the aphelion distance of Hailey's comet from the sun is 36 A. U.
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A light aircraft makes a flight during changeable weather conditions.
(a) Initially, in still air, the aircraft travels at a velocity of 44 ms' relative to the ground, on a bearing of 056°. Calculate the magnitude of the component of the aircraft's velocity that is directed northwards.
(b) A southward wind begins to blow with a velocity of 11 ms. The pilot does not correct the aircraft in response to the changing wind. Calculate the magnitude and bearing of the aircraft's new velocity.
Answer: a it goes north b goes south
Explanation:
an electron and a proton are fixed at a separation distance of 897 nm. find the magnitude ???? and the direction of the electric field at their midpoint.
The electric field at a midpoint is 1.425 x 10⁴ N/C.
We need to know about the electric fields to solve this problem. The electric field produced by a single-point positive charge is a radial field, whose strength is given by the equation
E = k.Q/r²
where E is the electric field, Q is the charge and r is the radius.
From the question above, we know that
k = 9 x 10⁹ Nm²/C²
Q1 =e = 1.6 x 10¯¹⁹ C
Q2 = e = 1.6 x 10¯¹⁹ C
x = 897 nm = 8.97 x 10¯⁷ m
from midpoint (r = 4.495 x 10¯⁷ m)
The electric field radially outward from proton to electron so that the total electric field between the charges will be added up.
Etotal = E1 + E2
Etotal = k.e/r² + k.e/r²
Etotal = 2. k.e/r²
Etotal = 2 x 9 x 10⁹ x 1.6 x 10¯¹⁹/(4.495 x 10¯⁷)²
Etotal = 1.425 x 10⁴ N/C
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The proportions and arrangement of atoms in any compound are always
the same
or
different
A proton moves at 0.950 c . Calculate its (c) kinetic energy.
The kinetic energy of the proton is 1982.31 MeV.
We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by
Eo = m₀ . c²
where Eo is rest energy, m₀ is rest mass and c is the speed of light (3 x 10⁸ m/s).
The total energy of object can be described as
E = Eo / √(1 - v²/c²)
where E is total energy, v is the object speed.
Kinetic energy can be defined as energy change from rest energy until total energy. It can be determined as
KE = E - Eo
where KE is kinetic energy.
From the question above, we know that :
m₀ = 1.6 x 10¯²⁷ kg
c = 3 x 10⁸ m/s
v = 0.95c
Find the rest energy
Eo = m₀ . c²
Eo = 1.6 x 10¯²⁷ . (3 x 10⁸)²
Eo = 1.44 x 10¯¹⁰ joule
Eo = 1.44 x 10¯¹⁰ / (1.6 x 10¯¹⁹) eV
Eo = 900 x 10⁶ eV
Eo = 900 MeV
Determine the total energy
E = Eo / √(1 - v²/c²)
E = 900 / √(1 - (0.95c)²/c²)
E = 900 / 0.31
E = 2882.31 MeV
Calculate the kinetic energy
KE = E - Eo
KE = 2882.31 MeV - 900 MeV
KE = 1982.31 MeV
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