A car with an initial speed of 6.50 m/s accelerates at a uniform rate of 0.920 m/s2 for
3.60 s. Find the final velocity.

Answers

Answer 1

Answer:

v = 9.812 m/s

Explanation:

Given that,

The initia speed of a car, u = 6.5 m/s

Acceleration of the car, a = 0.92 m/s²

Time, t = 3.6 s

We need to find the final velocity of the car. Let the final velocity be v. Using equation of motion to find it as follows :

v = u +at

Putting all the values,

v = 6.5+(0.92)(3.6)

v = 9.812 m/s

So, the final velocity of the car is 9.812 m/s.


Related Questions

At the mail racing championship in England, the winner moved at an average velocity of 2.4 mm/s [ford] for 140 s. Determine the winning snail's displacement during this time interval. [​

Answers

Answer:

Explanation: 1.2 mm

Time= 140 sec

Initial Velocity= 0

Average Velocity= 2.4 mm/s

Displacement=  0.5* (2.4/140) *140 = 1.2 mm

Damage to internal organs will present as pain associated with a particular surface area of the body. Why would something like irritation to the diaphragm, which is between the thoracic and abdominal cavities, feel like pain in the shoulder or neck?

Answers

A dish shaped large muscle which moves up and down when there is contraction and expansion of lungs is the diaphragm which is present between the chest cavity and lower abdominal region. The action of the diaphragm is affected by an inflammation occurring below the muscular disc which will affect the process of breathing. The forceful breathing may result in strain and stress in the back muscles of the human body. This in turn causes pain in the shoulder.

Suppose, that you are measuring the length of a wood block and the edge of your block appears to be lined up exactly with a millimeter mark. How would you express the estimate part of a millimeter when you record the block’s length?

Answers

When taking the measurement, the estimate part of a millimeter when recording the block’s length can be expressed as ± 0.5 mm.

What are measurements?

Measurements are the processes by which the attributes and properties of a given object or substance is quantified.

There are two types of measurements that can be obtained from any given object and they are:

quantitative measurementsqualitative measurements

Quantitative measurements measures the properties of objects in terms of numbers. Some examples of quantitative measurements are length, temperature, time, mass, etc.

Qualitative measurements describe the non-numerical features of objects such as color, texture, etc.

The measurement of length of a block of wood is a quantitative measurement.

The uncertainty or estimate of a measurement is half plus or minus the smallest division in the measurement.

The uncertainty or estimate of the millimeter block = ¹/₂ * 1 mm

The uncertainty or estimate of the millimeter block = ±0.5 mm

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if A.B=A.C
does this imply that B must be equal to c ?
I need answer with example please ​

Answers

Answer:

Yes

Explanation:

[tex]Consider\ three\ variables\ a,b\ and\ c.\\If,\\ab=ac\\a*b=a*c\\We\ may\ now\ divide\ the\ LHS\ and\ RHS\ by\ a,\\Hence,\\\frac{a*b}{a} =\frac{a*c}{a}\\Hence,\\b=c[/tex]

[tex]Ex: \\Consider\ a=5, b=6.\\Hence\ if,\\a*b=a*c\\5*6=5*c\\Hence,\\30=5c\\Hence, c=\frac{30}{5}\\c=6\\As\ b\ also\ equals\ to\ 6,\\b=c[/tex]

The world record for a woman running a marathon is approximately 2.25 hours. If a marathon's distance is 26.2 miles (42164.81 meters) and it is run
in a southeast direction, what is the velocity?
60 mph southeast
0.09 mph southeast
Omph southeast
11.6 mph southeast

Answers

Answer:

11.6mph South East

Explanation:

Given parameters:

Time = 2.25hrs

Displacement  = 26.2miles south east

Unknown:

Velocity = ?

Solution:

Velocity is the displacement divided by the time taken. It is a vector quantity with both magnitude and direction.

 Now;

       Velocity  = [tex]\frac{displacement}{time taken}[/tex]

       Velocity  = [tex]\frac{26.2}{2.25}[/tex]   = 11.6mph South East

Answer:

11.6mph south east.

As a 3.0 kg bucket is being lowered into a 10 m deepwell, starting from top, the tension in the rope is 9.8 N. theacceleration of the bucket will be:____________A) 6.5 m/s2 downwardB) 9.8 m/s2 downwardC) zeroD) 3.3 m/s2 upwardE) 5.6 m/s2 upward

Answers

Answer:

A) 6.5 m/s²

Explanation:

Mass of the bucket, m = 3.0 kg

depth of the well, d = 10 m

tension on the rope, T = 9.8 N

The net downward force on the bucket is given as;

T = mg - ma

where;

a is downward acceleration of the bucket

9.8 = (3 x 9.8) - 3a

9.8 = 29.4 - 3a

3a = 29.4 - 9.8

3a = 19.6

a = 19.6 / 3

a = 6.53 m/s² downwards

Therefore, the acceleration of the bucket is 6.53 m/s² downwards

A toy car in the figure below runs off the edge of a table that is h = 1.36 m high. The
car lands d= 0.88 m from the base of the table. How fast was the car going on the
table?

Answers

The toy car was going at a speed of 1.66 m/s on the table.

When the toy car runs off the edge of the table, it travels vertically as well as horizontally and it is an example of a horizontal projectile from a height.

The distance covered vertically will be equal to the height of the table which is 1.36m. And horizontal distance is given as d.

Vertical distance = H = 1.36m

Horizontal distance = d = 0.88m

Now, we for a free-falling body, in

Speed in vertical direction = u  = 0 m/s

Distance = h = 1.36

Using the second equation of motion,

h = ut + 1/2gt²

Put in the value, we get

1.36 = (0)t + 1/2(9.8)t²

t² = 1.36/4.9

t² = 0.278

t = 0.53 seconds

Now distance traveled in a horizontal direction is given by

Distance in horizontal direction = Speed on table × time of travel

Put in the value, we get

0.88 = V × 0.53

V = 0.88/0.53

V = 1.66 m/s

So, the toy car was going at a speed of 1.66 m/s on the table.

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A 120V AC signal is available at the wall port. You are required to convert it to a constant DC voltage of 12V for a laptop to operate. What are the three electrical components you will be using to achieve the same? Name the components in order and the function it performs.

Answers

Answer:

The following components shall be used in given order:

1. Step Down Transformer     2. Diode as Rectifier     3. Capacitor

Explanation:

The following components shall be used in given order:

1. Step Down Transformer     2. Diode as Rectifier     3. Capacitor

1.STEP DOWN TRANSFORMER:

The step down transformer is first used to convert the 120 V AC signal into 12 V AC signal. Because the output required is of 12 V.

2.DIODE AS RECTIFIER:

Now, the PN Junction diode is used as a rectifier to convert the 12 V AC signal to 12 V  DC signal.

3.CAPACITOR:

Now, the output is in waveforms. So, in order to linearize it in the form of DC current, we use capacitor. The main function of capacitor is to smoothen the signal into a straight line.

If a container, with a fixed number of molecules inside, is
reduced in volume, less molecules will hit the sides of the
container per unit time, causing less pressure.
TRUE
FALSE
Check it

Answers

Answer:

FALSE

FALSE

FALSE

FALSE

when does a circuit is said to be over loaded?​

Answers

Answer:

Every electric circuit in a wiring system must be protected against overloads. A circuit overload occurs when the amount of current flowing through the circuit exceeds the rating of the protective devices. The amount of current flowing in a circuit is determined by the load -- or the "demand" -- for current.

Explanation:

Hope this helps :)

What does an electromagnet in an electric motor do? I need help asap

Answers

Answer:the Correct Answer is

It transforms electrical energy into mechanical energy.

Explanation:

I got the answer right

How much work is done by an applied force to lift a 15-Newton 3Meters and 9.8?

Given=
Unknown=
Formula=
Solution=
Answer=​

Answers

The work done by the applied force of 15 Newton to lift the object up 3 meters is 45 J

W = F d

W = Work done

F = Force

d = Distance

F = 15 N

d= 3 m

W = 15 * 3

W = 15 J

Work done is the amount of force required to move an object. It is denoted by W. Its unit is usually Joules.

Therefore, the work done to lift the object is 15 J

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HELP URGENT- will give brainliest if correct

Answers

Answer:

6 km is the right answer

hope it helps you

Explanation:

please mark me as brainliest

Britney is on the starting line to run a track race. The distance around the track is 400m.
She starts the race and runs 400m around the track. She ends up in the same place where
she started. What distance did she cover? What was her displacement?

Answers

So she started from the finish line , she ran the track 400m so she only cover 400 m so your answer is 400m

F x T = m (Vf - Vi)
in this equation what does the M stand for

Answers

Answer:

m = mass [kg]

Explanation:

This equation is characteristic of the amount of motion and momentum.

[tex]F*t = m*(v_{f}-v_{i})[/tex]

where:

F = force [N] (units of Newtons)

t = time = [s]

m = mass [kg]

Vf = final velocity [m/s]

Vi = initial velocity [m/s]

Now using the units and placing them in the equation above.

[tex][N]*[s] = [kg]*(m/s-m/s)\\[/tex]

[tex][N]=[kg*m/s^{2} ][/tex]

Now replacing:

[tex][kg*m/s^{2}]*[s]=[kg*m/s][/tex]

The s² is cancelled with the s, therefore.

[tex][kg*m/s]=[kg*m/s][/tex]

To pass a vehicle inspection, your Must be heard from 200 feet away.
Ohorn
Omuffler
windshield wipers
stereo

Answers

A I think sorry if I'm wrong

A person holds a ladder horizontally at its center. Treating the ladder as a uniform rod of length 4.15 m and mass 7.98 kg, find the torque the person must exert on the ladder to give it an angular acceleration of 0.396 rad/s2.

Answers

Answer:

4.535 N.m

Explanation:

To solve this question, we're going to use the formula for moment of inertia

I = mL²/12

Where

I = moment of inertia

m = mass of the ladder, 7.98 kg

L = length of the ladder, 4.15 m

On solving we have

I = 7.98 * (4.15)² / 12

I = (7.98 * 17.2225) / 12

I = 137.44 / 12

I = 11.45 kg·m²

That is the moment of inertia about the center.

Using this moment of inertia, we multiply it by the angular acceleration to get the needed torque. So that

τ = 11.453 kg·m² * 0.395 rad/s²

τ = 4.535 N·m

The Torque will be "4.535 N.m".

Given:

Mass of ladder,

m = 7.98 kg  

Length of ladder,

L = 4.15 m

The moment of inertia will be:

→ [tex]I = \frac{mL^2}{12}[/tex]

     [tex]= \frac{7.98\times (4.15)^2}{12}[/tex]

     [tex]= \frac{7.98\times 17.2225}{12}[/tex]

     [tex]= 11.45 \ kg.m^2[/tex]

hence,

The torque will be:

→ [tex]\tau = 11.453\times 0.395[/tex]

      [tex]= 4.535 \ N/m[/tex]

Thus the above approach is correct.      

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Helium balloons pop in a hot car because

Answers

Answer:

This is because helium molecules get bigger when they heat up , so if your balloons keep getting hotter , they will eventually pop

Answer:

the helium molecules within the ballon expand as they heat up, resulting in the eventually resulting in popping.

Explanation:

^^^^^

10. The Earth's radius is about 6370 km. An object that has a mass of 20 kg is taken to a
height of 160 km above the Earth's surface. How much does the object weigh at this
height?

Answers

Answer:

Weight:

P =m·g₁ = 20·9.55 = 191 H

Explanation:

Given:

R = 6 370 км = 6 370·10³ m

m = 20 kg

h = 160 km = 160·10³ m

g = 9.8 m/s²

____________________

P - ?

Acceleration of free fall at the Earth's surface:

g = G*M / R²    (1)

Acceleration of free fall at height h:

g₁ = G*M / (R + h) ²    (2)

Divide (1) by (2):

g / g₁ = ((R + h) / R)²

g / g₁ = ( 1 + h / R)² = ( 1 + 160 / 6 370)² ≈ 1.026

g₁ = g / 1.026 = 9.8 / 1.026 ≈ 9.55 m/s²

Weight:

P =m·g₁ = 20·9.55 = 191 H

HELP right awayyy !!!

Answers

Answer:

Question 4 is actually Acceleration

4 is actually acceleration

Which of the following will increase if the voltage in a circuit is increased?
Check all that apply
A.Magnetic force
B. Resistance
C. Current
D. Heat produced by the circuit

Answers

Answer:

D i think (apologies if incorrect)

What is the voltage of a circuit that has a current of 3.7 amps and a resistance of 1.5 ohms.

Answers

Answer:

V = 5.55 volts

Explanation:

Given that,

Current, I = 3.7 A

Resistance, R = 1.5 ohms

We need to find the voltage of the circuit. Let V is the voltage. We can find it using Ohm's law as follows :

V = IR

Substituting all the values, we get :

[tex]V=3.7\times 1.5\\\\=5.55\ V[/tex]

So, the voltage of the circuit is 5.55 V,

Dale and Alex push on opposite sides of a couch. Dale pushes to the left with a force of 40 N, while Alex pushes to the right with a force of 32 N. If the
couch has a mass of 28 kg, what is the acceleration of the couch?
A. 2.6 m/s^2 right
B. 2.6 m/s^2 left
C. 0.3 m/s^2 left
D. 0.3 m/s^2 right

Answers

0.3 m/s^2 left will be  the acceleration of the couch.

we have given in the statement

force towards left  40 N

force towards right 32 N

net force = 40-32 = 8 N towards left

couch  mass = 28 kg

now we will use newtons 2nd law to find acceleration

F=ma, here f is force m is mass a is acceleration

a=F/m

a=8/24

a=0.285 ≅ 0.3 N

An object's rise in velocity rate is referred to as acceleration. It is a vector quantity that is sign-sensitive, and the route shift and body speed variance establish the sign norm. it's unit is m/s^2

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0.3 m/s squared left Answer:

Explanation:

A source of heat at 1000 K transfers 1000 kW of power to a power generation device, while producing 400 kW of useful work. Determine the second law efficiency of the system, if the environment is at 300 K.

Answers

Answer:

The value is [tex]\eta _2 = 0.57[/tex]

Explanation:

From the question we are told that

    The temperature of the heat source is [tex]T_s = 1000 \ K[/tex]

    The amount of power transferred is  [tex]P_s = 1000 \ kW = 1000 *10^{3} \ W[/tex]

      The work produced is  [tex]W = 400 \ kW[/tex]

       The temperature of the environment [tex]T_e = 300 \ K[/tex]

Gnerally the Carnot efficiency of the system is mathematically represented as

        [tex]\eta_c = 1 -\frac{T_e}{T_s}[/tex]

=>    [tex]\eta_c = 1 -\frac{300}{1000}[/tex]

=>      [tex]\eta_c = 0.7[/tex]

Generally the first  law efficiency of the system is mathematically represented as

            [tex]\eta _1 = \frac{W}{P_s}[/tex]

=>         [tex]\eta _1 = \frac{400}{1000}[/tex]  

=>         [tex]\eta _1 = 0.40[/tex]

Generally the second  law efficiency of the system is mathematically represented as

                [tex]\eta _2 = \frac{\eta_1}{\eta_c}[/tex]

=>               [tex]\eta _2 = \frac{0.4}{0.7}[/tex]

=>               [tex]\eta _2 = 0.57[/tex]

PLEASE HELP ME!! I NEED ANSWERS ASAP!!!!

Answers

Answer:

I do not know the answer because not all of the information is there.

Explanation:

Answer:

Beep Beep

Explanation:

A car is stopped for a traffic signal. When the light turns green,
the car accelerates, increasing its speed from 0 to 5.20 m/s in
0.832 s. What are the magnitudes of (a) the linear impulse and
(b) the average total force experienced by a 70.0-kg passenger
in the car during the time the car accelerates?

Answers

Answer:

Impulse, p = 364 N·s
Force F =  437.5 N

Explanation:

First some definitions:

Momentum, p is defined as the product of the mass, m  and velocity v.
p = mv
Impulse, J is the change in momentum of a body
J = Δp = p₂ - p₁ = mv₂ - mv₁ = mΔv   where the subscript 1 refers to initial values and subscript 2 to final values.

Part (a)
Since the car is initially at rest, its initial momentum is 0.
When the car reaches a velocity of 5.20 m/s, the momentum experienced by a 70 kg passenger is

Δv = 5.20 - 0 = 5.20 m/s

p = 70 kg x 5.20 m/s =  50.3248 kg m/s =  364 N·s

p = 384 N.s

Part (b)

Force is given by F=m(Δv/Δt) = 70 kg x (5.20 m/s / 0.832 s) = 437.5 N
F = 437.5 N

The subjective perception of the frequency of sound is called ?

Answers

Answer: The subjective perception of the frequency of sound is called a Pitch

Explanation: Because the Pitch has a lowest and highest  of a sound fundamental

If you are satisfied please leave a like


needdd helppppppppp

Answers

Answer:

divide 223 by 74 and you'll get your answer

7. What is the acceleration of a 24.00 kg mass pushed by an 8.0 N force?

Answers

Answer:

3 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question we have

[tex]a = \frac{24}{8} \\ [/tex]

We have the final answer as

3 m/s²

Hope this helps you

As a ladder leans against a wall it exerts a force on both the wall and ground. What are the two reactant forces on the ladder?
Responses

−Fwall on ladder and −Fground on ladder
−Fwall on ladder and −Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline

Fwall on ladder and −Fground on ladder
Fwall on ladder and −Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline

Fwall on ladder and Fground on ladder
Fwall on ladder and Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline

−Fwall on ladder and Fground on ladder
−Fwall on ladder and Fground on ladder

Its -Fwallonladdy and -fgroundonladder just made sure to add this since no one else did yet

Answers

The two reactant forces on the ladder are -Fwall on Ladder and -Fground on Ladder

What are the two reactant forces on the ladder?

To know the reactant forces on the ladder, we use Newton's third law of motion.

What is Newton's third law of motion?

Newton's third law of motion states that for every action, there is an equal and opposite reaction.

So, for the ladder, as the ladder leans against a wall it exerts a force on both the wall and ground.

Now, since the ladder exerts a force on the wall, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the wall is Fladder on wall, then the reaction force of wall on the ladder is Fwall on ladder.

So, Fladder on wall = -Fwall on Ladder

Also, since the ladder exerts a force on the ground, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the ground is Fladder on ground, then the reaction force of ground on the ladder is Fground on ladder.

So, Fladder on ground = -Fground on Ladder

So, the two reactant forces on the ladder are -Fwall on Ladder and -Fground on Ladder

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