A block of mass 2.52 kg is kept at rest
as it compresses a horizontal massless spring
(k 116 N/m) by 9.73 cm. As the block
is released, it travels 0.537 m on a rough
horizontal surface before stopping.
The acceleration of gravity is 9.8 m/s.
Calculate the coefficient of kinetic friction
between surface and block.

Answer:

[tex]0.059\ \text{m/s}[/tex]

Explanation:

[tex]m_1[/tex] = Mass of bullet = 4.2 g

[tex]u_1[/tex] = Initial velocity of bullet = 0

[tex]m_2[/tex] = Mass of hunter with rifle = 69.5 kg

[tex]u_2[/tex] = Initial velocity of hunter with rifle

[tex]v_1[/tex] = Final velocity of the bullet = 970 m/s

[tex]v_2[/tex] = Final velocity of the hunter with the rifle

As the momentum of the system is conserved we have

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}\\\Rightarrow v_2=\dfrac{0-0-0.0042\times 970}{69.5}\\\Rightarrow v_2=-0.059\ \text{m/s}[/tex]

The recoil speed of the hunter is [tex]0.059\ \text{m/s}[/tex] in the opposite direction of the bullet.

Answer:

The other 30% is lost from friction.

Explanation:

       friction 30% ---> |O| <------ 70% work

A machine has an efficiency of 70%, and the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.

In any machine, the total work input is equal to the total work output plus any work that is lost or dissipated due to various factors such as friction, heat transfer, etc., so, for example, if a machine receives 100 units of energy as input, only 70 units of energy are converted into useful output work, and the remaining 30 units of energy are lost as waste energy.

Hence, the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.

Learn more about the work by machine here.

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#SPJ6

Answer:

speed =distance/time taken

5 m/s

Answer:

[tex]F_o=437Hz[/tex]

Explanation:

From the question we are told that:

Frequency of Turning fork [tex]F_t=440Hz[/tex]

Number of beats detected [tex]n=3[/tex]  

Generally the equation for Original frequency [tex]F_o[/tex] of the string  is mathematically given by

[tex]F_o=F_t-F_b[/tex]

Where

[tex]F_b[/tex] Beat frequency

[tex]F_b=1Hz*n\\F_b=1Hz*3[/tex]

Therefore

[tex]F_o=440-3[/tex]

[tex]F_o=437Hz[/tex]

Answer:

D.

The radioactive wastes it produces can spread to any part of the environment.

Explanation:

Fission is the name given to the splitting of a heavy nucleus into two medium-mass nuclei. Fission is said to be induced if it results from the absorption of a neutron to form an unstable nucleus that decays by fission. The induced fission usually produces further neutrons accompanying the fission fragments.

Answer:  D. The radioactive wastes it produces can spread to any part of the environment

Explanation:

Answer:

0.5

Explanation:

In this picture,

Answer:

a.5.85 s b i. 15.7 m/s ii. 21.1m/s c. 61.62 m

Explanation:

(a) when b will overtake a,

Using s = ut + 1/2at² we express the distance moved by each automobile.

Since both automobiles start at rest, their initial speed, u = 0 m/s, a = acceleration of automobile and t = time of travel or overtaking

So s = 0 × t + 1/2at²

s = 0 + 1/2at²

s = 1/2at²

Let time, t be the time the automobile b start, and its acceleration a = 3.6 m/s²

So, s = 1/2 × 3.6 m/s² × t² = 1.8t²

Since automobile a starts 2 seconds earlier, its time of travel is (t + 2) s. Since its acceleration, a = 2 m/s²,

s = 1/2 × 2 m/s² × (t + 2)²

s = (t + 2)²

Since both distances are equal at overtaking

(t + 2)² = 1.8t²

t² + 4t + 4 = 1.8t²

1.8t²- t² - 4t - 4 = 0

0.8t² - 4t - 4 = 0

dividing through by 0.8, we have

0.8t²/0.8 - 4t/0.8 - 4/0.8 = 0

t² - 5t - 5 = 0

Using the quadratic formula to find t,

[tex]t = \frac{-(-5) +/-\sqrt{(-5)^{2} - 4 X 1 X (-5)} )}{2 X 1} \\t = \frac{5 +/-\sqrt{25 + 20} )}{2} \\t = \frac{5 +/-\sqrt{45} )}{2} \\t = \frac{5 +\sqrt{45} )}{2} or \frac{5 -\sqrt{45} )}{2}\\t = \frac{5 + 6.708 )}{2} or \frac{5 - 6.708)}{2}\\t = \frac{11.708 )}{2} or \frac{-1.708}{2}\\t = 5.854 sor -0.854 s[/tex]

t ≅ 5.85 or -0.85

We take the positive answer since t cannot be negative.

So, t = 5.85 s

So, b will overtake a 5.85 s later.

(b) the speed of each automobile at that time,

Using v = u + at for each automobile, where u =initial speed of automobile = 0 m/s (since they both start from rest), a = acceleration of automobile and t = time of travel of automobile

i. Speed of automobile a

For automobile a, its time of travel is (t + 2) s = 5.85 s + 2 s = 7.85 s and its acceleration is 2 m/s²

So, v = u + at

= 0 m/s + 2 m/s² × 7.85 s

= 0 m/s + 15.7 m/s

= 15.7 m/s

ii. Speed of automobile b

For automobile a, its time of travel is t  s = 5.85 s and its acceleration is 3.6 m/s²

So, v = u + at

= 0 m/s + 3.6 m/s² × 5.85 s

= 0 m/s + 15.7 m/s

= 21.06 m/s

≅ 21.1 m/s

c) the location where b overtakes a relative to the traffic signal. -truck

The location where b overtakes a relative to the traffic signal is the distance each automobile moves before overtaking. In section (a), we foundthat distance s = 1/2at² = (t + 2)² = 1.8t²

Using s = (t + 2)²

= (5.85 + 2)²

= 7.85²

= 61.6225 m

≅ 61.62 m

Answer:

strength

Explanation:

Answer:

Potential energy

Explanation:

Since the boy is holding is, it is not moving. So, it has potential energy. Also, since it is in the air, it has gravitational potential energy.

Answer:

dfdfsdf s

Explanation:

fsdfsd fsd fds f vsdvads

Answer:

a)   F = 3.3 10⁴ N,  b)  F = 2.2 10³ N,  c) force when rigid is 15 times greater than when bending the knees

Explanation:

For this exercise we can use the relationship between work and the variation of kinetic energy

          K₀ = ½ m v²

the final kinetic energy is zero because the person is stationary

          W = (∑ F) x

          W = W x - F w

the weight is in the same direction of the displacement therefore the work is positive and the force applied, by the floor, is in the opposite direction to the displacement, consequently the work is negative

we substitute

          ( W-  F ) x = 0-K₀

           F = W + K₀ /x  

          F = mg + [tex]\frac{1}{2} \frac{mv^2 }{2x}[/tex]  

          F = m ( g+  [tex]\frac{v^2 }{2x }[/tex]  )

Let's use kinematics to find the velocity of the person when reaching the floor

           v² = v₀² - 2g (y + y₀)

the initial velocity is true and when reaching the ground y = 0

          v² = -2 g (0-yo)

we calculate

          v = [tex]\sqrt{2 ] 9.8 \ 0.800}[/tex]

          v = - 3.96  m/s

the direction of this velocity is vertical down

let's calculate

a) x = 1.50 cm = 0.0150 m

           F = 62.0 (3.96² / 2 0.0150 + 9.8)

           F = 3.3 10⁴ N

b) x = 30 cm = 0.30 m

           F = 62.0 (3.96² / 2 0.30 + 9.8)

           F = 2.2 10³ N

c) to compare the force let's look for the relationship between the two

           [tex]\frac{F_{rigid} }{ F_{flexible} }[/tex] = 3.3 10⁴ / 2.2 10³

           \frac{F_{rigid}  }{ F_{flexible} } = 15

therefore see that the force when rigid is 15 times greater than when bending the knees

Answer:

hydrogen and helium

Explanation:

i got it 100 percent. Hope this Helps!

Answer:Her likelihood of conceiving will be reduced by at least 50%.

Explanation:

EDGE 2020

Answer:

Her likelihood of conceiving will be reduced by at least 50%

Explanation:

took the test on edge, got it right

Answer:

A. 40N

B. 5m/s

Explanation:

A.

Impulse is equal to the area under the curve of a force vs. time graph. In this case, the area is in the shape of a triangle with base 8 (12-4=8) and perpendicular height 10:

Area of a triangle = (1/2)bh

A=(1/2)*8*10

=40

ANSWER: 40N

B.

Impulse = mass * velocity

40 = 8v

v = 5

ANSWER: 5m/s

Answer: a

Explanation:

when a car dives on a road it a makes friction but it need something to push it or start it which is the balloon in this example

(sorry if im wrong)

Answer:

=> Black holes are points in space that are so dense they create deep gravity sinks. Beyond a certain region, not even light can escape the powerful tug of a black hole's gravity.

=> Anything that ventures too close—be it star, planet, or spacecraft—will be stretched and compressed like putty in a theoretical process aptly known as spaghettification.

[tex] \infty \infty [/tex]

Answer:

It is D

Explanation:

The explanation why the marble undergoes oscillatory motion should be option D.

An object should be classified as the motion oscillates related to an equilibrium position because of the restoring force or torque.  This motion should be significant to study various phenomena like electromagnetic waves, molecules. etc. In the case when the gravitational force should be exerted on the marble here the magnitude and the direction should be the same.

learn more about the motion here: https://brainly.com/question/16335988

Answer:

A. 1.6 Hz

B. 1000 m/s²

C. 50000 N

Explanation:

A. Determination of the frequency.

Period (T) = 0.625 s

Frequency (f) =?

f = 1/T

f = 1/0.625

f = 1.6 Hz

B. Determination of the acceleration.

Radius (r) = 10 m

Velocity (v) = 100 m/s

Acceleration (a) =?

a = v²/r

a = 100² / 10

a = 10000 / 10

a = 1000 m/s²

C. Determination of the net force.

Mass (m) = 50 Kg

Acceleration (a) = 1000 m/s²

Net force (F) =?

F = ma

F = 50 × 1000

F = 50000 N

Answer:

The zygote

Explanation:

The sperm is what fertilized the egg and the zygote is basically part of the female egg cell.

Answer:

the answer is the ovum on edge

Explanation:

Answer:

[tex]\mathbf{\alpha = 25.88 \ rad/s^2 }[/tex]

Explanation:

Consider the force due to friction:

[tex]F = \mu_kN -------- (1)[/tex]

where;

N = normal reaction

[tex]\mu_k[/tex] = coefficient of kinetic friction.

Via the horizontal direction, the forces of equilibrium are:

[tex]\sum F_x = \sum(F_x) _{eff} \\ \\ N- F_{AB} \ cos \theta = 0 \\ \\ F_{AB} \ cos \theta = N ------ (2)[/tex]

where;

[tex]\theta[/tex] = angle of AB is associated with the horizontal;

[tex]F_{AB}[/tex] = force exerted by AB

Let's take a look at the equilibrium of forces along the vertical direction.

[tex]\sum F_y = \sum (F_y)_{eff} \\ \\ F+F_{AB} sin \theta - W = 0\\ \\ \mu_k N + F_{AB} sin \theta -mg =0 \\ \\ F_{AB} sin \theta = mg - \mu_kN-------(3)[/tex]

By dividing (3) by (2), we get:

[tex]\dfrac{F_{AB} sin \theta }{F_{AB} cos \theta} = \dfrac{mg - \mu_k N}{N} \\ \\ tan \theta = \dfrac{mg-\mu_kN}{N} \\ \\ Ntan \theta = mg - \mu_kN \\ \\ N(tan \theta + \mu_k ) = mg \\ \\ N = \dfrac{mg}{tan \theta + \mu_k}[/tex]

By replacing the obtained value of N into:

[tex]F = \mu_k N[/tex]

we have:

[tex]F = \mu_k (\dfrac{mg}{tan \theta + \mu_k}) \\ \\ \\ F = \dfrac{mg \mu_k}{tan \theta + \mu_k}[/tex]

Moment about center A can be expressed as:

[tex]\sum M_A = \sum (M_A) _{eff} \\ \\ Fr = I \alpha\\ \\ \alpha = \dfrac{Fr}{I}[/tex]

where;

[tex]\alpha[/tex] = angular acceleration of the disc

I = mass moment of inertia

r = radius of disc

By replacing F and I; ∝ becomes:

[tex]\alpha = \dfrac{\bigg( \dfrac{mg \mu_k}{tan \theta + \mu_k} \bigg) r}{\dfrac{1}{2}mr^2}[/tex]

[tex]\alpha = \dfrac{2g}{r} \dfrac{\mu_k}{tan \ \theta + \mu_k}------- (4)[/tex]

where;

g = 9.8 m/s²

r = 0.18 m

[tex]\mu_k = 0.54[/tex]

θ = 60°

[tex]\alpha = \dfrac{2(9.8)}{0.18} (\dfrac{0.54}{tan \ 60+ 0.54})[/tex]

[tex]\mathbf{\alpha = 25.88 \ rad/s^2 }[/tex]

Answer:

sugar free

Explanation:

she should most likely take anything sugar free and avoid any bread, bread can increase your blood level as well, my mother had pre diabetes and what she did was eat salads and drink vegetable smoothies until your sugar goes down. splitting an entrée won't do anything, you technically get the same amount of sugar so at the point just eat the whole meal.

Answer:

Static force of friction = 428.75 N

Kinetic Force of Friction = 281.75 N

Explanation:

The static force of friction is equal to Coefficient of static Friction * Mass * g

= 0.35 *125 * 9.8

= 428.75 N

The Kinetic force of friction is equal to Coefficient of kinetic Friction * Mass * g

= 0.23 *125 * 9.8

= 281.75 N

The coefficient of static friction be in order to keep the quarter from sliding outward when the turntable is in motion will be 0.31.

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

Mathematically it is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and acceleration in the different components and balancing the equation gets. The friction force balances centripetal force.

The given data in the problem will be;

m is the mass =6.25 g

r is the radius =25 cm=0.25 m

t is the time = 0.18 sec

μ is the coefficient of static friction =?

[tex]\rm F_c= mw^2r \\\\ f= \mu mg \\\\ F_C=f\\\\ mw^2r= \mu mg \\\\ \rm \mu = \frac{\omega^2r}{g} \\\\ \rm \mu = (\frac{2\pi}{1.8} )^2\frac{0.25}{9.81} \\\\ \rm \mu = 0.31[/tex]

Hence the coefficient of static friction will be 0.31.

To know more about friction force refer to the link;

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Answer:

72mph/sec

Explanation:

The car goes from 100mph to 316mph in three seconds. Meaning it increases its speed by (316 - 100)mph in three seconds. That is 216 mph increase in three seconds. So, we divide the speed increase by the amount of time the increase occurred over. We get:

216mph / 3sec = 72mph/sec, our final answer

Hope it made sense. I would appreciate Brainliest, but no worries.

Answer:

the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

Explanation:

Given the data in the question and as illustrated in the diagram below.

speed of the ship v = 0.90c

base of the ladder from the wall x₀ = 3.0 m

top of the later above the floor y = 4.0 m

we determine angle θ.

from the diagram,

tanθ = y/x₀

tanθ = y / x₀√( 1 - v²/c² )

we substitute

tanθ = 4.0 / 3.0√( 1 - ((0.9c)²/c²) )

tanθ = 4.0 / 3.0√( 1 - ((0.9²)c²/c²) )

tanθ = 4.0 / 3.0√( 1 - (0.9²) )

tanθ = 4.0 / 3.0√( 1 - 0.81 )

tanθ = 4.0 / 3.0√0.19

tanθ = 4.0 / 1.30766968

tanθ = 3.058876

θ = tan⁻¹( 3.058876 )

θ = 71.8965 ≈ 71.9°

Therefore, the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

Answer:

He had a cogenital condition

Explanation:

cogenital conditions are present before or at the time of birth and are considered birth defects

Answer:

The answer is C- He had a congential condition.

Explanation:

Edge