4. Which of the following would NOT be a major process in the formation of sedimentary
rocks?
a Erosion
b. Melting
C Deposition
d. Weathering

Answer:

L  = 6 * ( π + 1 )

Explanation:

The side of the equilateral triangle is  4, and each one of the circles is of radius 1. Then

Triangle vertex   A  B  and C

Trajectory of the belt, beginning in vertex A

1.-First circle  A  one turn

L₁  = 2*π*1   = 2*π

2.-Length between the circle A and B

L₂  = 2

3.- To wrap this circle we need to wrap the circle and to run the belt through the radius twice. The firs over the side AB and the second over the side BC, therefore

L₃ = 2*π*1 + 2*(1)

L₃ = 2*π + 2

4.-Length between two nearest points of circles B and C is 2 and length of the circle in C is 2*π*1. Then

L₄  = 2 + 2*π

Total length of the belt  is:

L  =  L₁ + L₂ + L₃ + L₄

L = 2*π + 2 + (2*π + 2 ) + ( 2 + 2*π )

L  = 6*π + 6

L  = 6 * ( π + 1 )

51.448 g is the required answer!

Answer:

3.63 s

Explanation:

Since distance d = vt where v = velocity and t = time taken to cover the distance.

Now, the baseball traveled a distance of d = 145 m with a horizontal velocity of 40.0 m/s.

So, making t subject of the formula,

t = d/v

Substituting the values of d and v we have

t = 145 m/40.0 m/s

= 3.625 s

≅ 3.63 s

So the time the ball was in the air is 3.63 s

Answer:

443.8 nm

Explanation:

mλ = yd/D = d(y/D)

m = 1

d = 6.42 x 10-5 m

θ = 0.396°

y/D = tanθ = tan(0.396°) ≅ 6.912 x 10-3

λ = (6.42 x 10-5 m) tan(0.396°) = (6.42 x 10-5 m)(6.912 x 10-3) ≅ 4.438 x 10-7 m = 443.8 nm

I JUST WANT TO MAKE CLEAR THAT  d=6.42*10^-5 NOT d = 6.42x10-5 right?

Answer: the answer is 6kg.

Explanation:

Mass= force divided by acceleration, which would be 12 divided by 2.

Answer:

T₂ = 469.73 K = 196.73 °C

Explanation:

First we will find the surface area of rubber stop:

[tex]Area = A= \frac{Volume}{Length} \\\\A = \frac{100\ cm^3}{15\ cm}\\\\A = 6.67\ cm^2 = 6.67 \ x\ 10^{-4}\ m^2[/tex]

Now, we will find the final pressure required to remove the rubber stop:

[tex]Final\ Pressure\ = P_{2} = \frac{Force}{Area}+Atmospheric Pressure \\\\P_{2} = \frac{40\ N}{6.67\ x\ 10^{-4}\ m^2} + 101.3 KPa\\\\ P_{2} = 60000\ Pa + 101.3 KPa = 60\ KPa + 101.3 KPa\\\\P_{2} = 161.3\ KPa[/tex]

Now, we use equation of state:

[tex]\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}[/tex]

for constant volume due to rigid cylinder:

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\\T_{2} = \frac{P_{2} T_{1}}{P_{1}}[/tex]

where,

P₁ = initial pressure = 101.3 KPa

P₂ = final pressure = 161.3 KPa

T₁ = Initial Temperature = 22°C = 295 K

T₂ = Final Temperature = ?

Therefore,

[tex]T_{2} = \frac{(161.3\ KPa)(295\ K)}{101.3\ KPa}[/tex]

T₂ = 469.73 K = 196.73 °C

Answer:

2. How many joules of heat are needed to raise the temperature of 10.0 g of aluminum from 22°C to 55°C, if the specific heat of aluminum is 0.90 J/gºC? c=0.90J/g. 9 (2 sigs.)

Explanation:

Answer:

When the reflecting surface is instead curved, we call it a curved mirror. There are two types of curved mirrors; concave and convex mirror. Curved mirrors whose reflecting surfaces curve inwards are called concave mirrors while those whose reflecting surfaces bulge outwards are called convex mirrors.

Explanation:

Answer:

I think it is Location.

Explanation:

If im wrong im sorry

Answer:

Money

Explanation:

______ is the limiting factor that can keep some people from exercising if they (can’t afford) to purchase certain types of exercise equipment or pay for activities.

Says they cant afford it, therefore it would obviously be money

Answer:

It's A and C

Options A and C are correct.

A. When the semiconductors become charged, current flows from the negative one to the positive one

C. When photons are absorbed, electrons from the semiconductor are freed because of the photoelectric effect.

Semiconductors are materials with conductivity intermediate between conductors and nonconductors or insulators. Semiconductors may be either compound like gallium arsenide.

(A)When the semiconductors become charged, current flows from the negative one to the positive one

Reason: Current flow in a semiconductor is caused by charge carrier migration in both the conduction and valence bands.

Electrons are mobile charges in the conduction band while holes are mobile charges in the valence band.  Drift current occurs in the presence of an electric field,

which creates a net motion of positively charged carriers in the same direction as the field and negatively charged carriers in the opposite direction as a result of the force.

(C)When photons are absorbed, electrons from the semiconductor are free because of the photoelectric effect.

Reason: The photoelectric effect is the creation of a current when the light of a specific frequency strikes a surface, which is commonly metallic or semiconducting.

The current is produced when electrons are jolted out of their stable states by the energy transferred from an incoming photon.

The minimum frequency or energy need indicates the varying energy necessary to release an electron from a specific surface, which varies depending on the atomic configuration of the material.

The outermost electrons in metals are not bonded to each atom which is shared by many atoms. This decentralization is what allows metals to conduct electric currents.

Hence options A and C are correct.

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Answer:

D

Explanation:

The statement i.e. true is option d. The bee exerts a greater force on the Earth than the Earth exerts on the bee.

When the honeybee is in flight that lies between a flower and its hive.

So here the bee should be exerted a high force on the earth as compared to the earth exerted on the bee.

Therefore, the option d is correct.

And, the rest of the options are wrong.

Learn more about force here: https://brainly.com/question/2566388

Answer:

a) The initial elastic potential energy of the block-spring system is 28.113 joules.

b) The final speed of the block is approximately 4.192 meters per second.

Explanation:

a) By applying Hooke's law and definition of work, we define the elastic potential energy ([tex]U_{g}[/tex]), measured in joules, by the following formula:

[tex]U_{g} = \frac{1}{2}\cdot k\cdot x^{2}[/tex] (1)

Where:

[tex]k[/tex] - Spring constant, measured in newtons per meter.

[tex]x[/tex] - Deformation of the spring, measured in meters.

If we know that [tex]k = 865\,\frac{N}{m}[/tex] and [tex]x = 0.065\,m[/tex], then the elastic potential energy is:

[tex]U_{g} = \frac{1}{2}\cdot \left(865\,\frac{N}{m} \right) \cdot (0.065\,m)[/tex]

[tex]U_{g} = 28.113\,J[/tex]

The initial elastic potential energy of the block-spring system is 28.113 joules.

b) According to the Principle of Energy Conservation, the initial elastic potential energy of the block-spring system becomes into translational kinetic energy, that is:

[tex]U_{g} = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (2)

Where:

[tex]m[/tex] - Mass, measured in kilograms.

[tex]v[/tex] - Final speed, measured in meters per second.

Then, the final speed is cleared:

[tex]v = \sqrt{\frac{2\cdot U_{g}}{m} }[/tex]

If we know that [tex]U_{g} = 28.113\,J[/tex] and [tex]m = 3.20\,kg[/tex], then the final speed of the block is:

[tex]v = \sqrt{\frac{2\cdot (28.113\,J)}{3.20\,kg} }[/tex]

[tex]v \approx 4.192\,\frac{m}{s}[/tex]

The final speed of the block is approximately 4.192 meters per second.

Correct question is;

An object exerts a pressure of 2 pa on the ground if another object of the same weight is kept above it then the net pressure will become _____

Answer:

4 pa

Explanation:

We know that formula for pressure is;

P = Force/area

Where formula for force is;

F = mg

Thus;

P = mg/A

We are told P = 2 pa

Thus;

mg/A = 2

Now, when we add the same weight, our new Force is;

F_new = mg + mg = 2mg

Area remains the same A.

Thus, net pressure = F_new/A = 2mg/A

From earlier, we saw that mg/A = 2.

Thus;

net pressure = 2mg/A = 2 × 2 = 4 pa

Answer:

(d) not enough info

Explanation:

because it doesn't specify where the strings are attached

if it was the two ends of the rod then T1 would be equal to T2

Answer:

10.88 km

Explanation:

We shall represent displacement in terms of i , j  unit vectors in the direction of east and north .

4.5 km due west

D₁ = - 4.5 i

6.7 km at an angle of 27° south of west

D₂ = - 6.7 cos27 i - 6.7 sin27j

= - 6.7 x .89 i - 6.7 x .45 j

= - 5.96i - 3 j

Total displacement

= D₁ + D₂

=  - 4.5 i - 5.96i - 3 j

= -10.46 i - 3j

Magnitude = √ ( 10.46² + 3²)

= √ ( 109.41 + 9)

= √ 118.41

= 10.88 km .

We know, acceleration is given by :

a = F/m

a = 16.6/3.1 m/s²

a = 5.35 m/s²

Now, we need to find the speed after it has moved 3.8 m.

By equation of motion :

[tex]v^2 -u^2 = 2as\\\\v=\sqrt{2as}\\\\v = \sqrt{2\times 5.35 \times 3.8 }\ m/s\\\\v = 6.38\ m/s[/tex]

Therefore, the speed after it has moved 3.8 m is 6.38 m/s.

Answer:

Yes of course science has maths

Answer:

////??????????????/

Explanation:

Answer:

As you go talk to her or even before you go talk to her. If that's the case however, start talking to everyone you meet both boys and girls. See, improving your communication with women is easy. Just get a few books on social skills and then go over to talk to all the ladies you see without any hidden agenda.

Explanation:

I really hope this helps your question  ^_^

Answer:

[tex]Q_a=330 cal[/tex]

[tex]Q_w=6000cal[/tex]

Explanation:

From the question we are told that

Mass of the aluminum container 50 g

Mass of the container and water 250 g

Mass of the water 200 g

Initial temperature of the container and water 20°C

Temperature of the steam 100°C

Final temperature of the container, water, and condensed steam 50°C

Mass of the container, water, and condensed steam 261 g

Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C

a) Heat energy on container

Generally the formula for mathematically solving heat gain

      [tex]Q_c=M_c *C_c*( \triangle T)[/tex]

Therefore imputing variables we have

      [tex]Q_a=50g *0.22*50-20[/tex]  

      [tex]Q_a=330 cal[/tex]

b) Heat energy on water

Generally the formula for mathematically solving heat gain

       [tex]Q_w=M_w *C_w*( \triangle T)[/tex]

Therefore imputing variables we have

       [tex]Q_w=200 *1* 50-204[/tex]

       [tex]Q_w=6000cal[/tex]

Answer:

The value is  [tex]V_{os} = 0.001 \ V[/tex]

Explanation:

From the question we are told that

     The circuit resistance is  [tex]R_1 = 10 \ k \Omega[/tex]

     The feedback resistance  is  [tex]R_f = 220 \ k \Omega[/tex]

      The offset current is  [tex]I_{os } = 100 \ nA = 100 * 1)^{-9} \ A[/tex]

Generally the offset voltage is mathematically reparented as

           [tex]V_{os} = R_f * I_{os}[/tex]

=>        [tex]V_{os} = 10 *10^{3}* 100 *10^{-9}[/tex]

=>        [tex]V_{os} = 0.001 \ V[/tex]

Answer:

The electrical field in the region between the plates is 10,000 V/m.

Explanation:

Given;

potential difference between the two parallel plates, V = 100 V

distance between the two parallel plates, d = 1 cm = 0.01 m

The electrical field in the region between the plates is given as;

E = V / d

where;

E is the electrical field in the region between the plates

E = (100) / (0.01)

E = 10,000 V/m

Therefore, the electrical field in the region between the plates is 10,000 V/m.

Answer:

D

Explanation:

The direction that positive charge would move

Answer:

a) 400.4Joules

b) 262.69Joules

Explanation:

Work is said to be done if the force applied to an object cause the object to move through a distance

Workdone = Force × Distance

Given

Force = 76N

Distance= 5.2m

Work done = 77 × 5.2

Work done = 400.4Joules

b) If the force is exerted at an angle of 41°

Work done = Fdsin theta

Work done = 77(5.2)sin41

Work done = 400.4sin41

Work done = 262.69Joules

Answer:

A particle moves in the +x direction and then reverses the direction of its velocity

Explanation:

This is illustrated in that when a particle moves in a straight route with no alterations in direction, this will lead to displacement and distance being equal at any point in time during the movement. Thereby the quantity of average speed and average velocity will equal.

On the other hand, should the particle reverses direction, the distance traveled will be greater than it's displacement, thereby, the average speed will be greater than the average velocity.

Answer:

Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789

The total energy at each point in the path of the skier is constant as the

skier travels down the slope.

Reasons:

1) Given that the total mechanical energy, M.E. is constant, we have;

M.E. = Kinetic Energy, K.E. + Potential Energy, P.E. = Constant

M.E. = K.E. + P.E.

At the start, we have;

P.E. = 25,000 J

K.E. = 0 J

Therefore;

M.E. = 25,000 J + 0 J = 25,000 J

At point 1A, we have, K.E = 10,000 J

P.E. = M.E. - K.E.

Therefore;

P.E. = 25,000 - 10,000 = 15,000

The potential energy at point 1A, P.E. = 15,000 J

At point 1B, we have; PE = 6000 J

K.E. = M.E. - P.E.

Therefore;

K.E. = 25,000 J - 6,000 J = 19,000 J

At 1B, K.E. = 19,000 J

At point 1C, we have; K.E. = 25,000 J

Therefore;

P.E. = 25,000 J - 25,000 J = 0 J

At 1C P.E. = 0 J

2) The Law of Conservation of Energy states that the energy in a closed

system is constant.

The energy transformation follows the Law of Conservation of energy

given that the total mechanical energy is constant at all points along the

path.

3) The energy of a system is not conserved when a external force is

applied.

If the skier experiences friction, the force of friction does work to reduce

the speed of the skier, thereby reducing the kinetic energy at a point

downslope, where the potential energy has already been reduced,

resulting in an reduction in the mechanical energy of the system.

Therefore, if the skier experiences friction, the total energy of the system is

not conserved, as energy will be consumed in the work done by friction

which is converted to heat and sound energies.

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Answer:

O chemical energy into thermal energy

Hope this helped!!

Answer:

chemical energy into thermal energy

Explanation:

Answer:

B.) 3KOH + H3PO4 -> K3PO4 +3H20

Explanation:

:p

Chemical equation models the law of conservation of mass is [tex]3KOH + H_{3} PO_{4}[/tex] → [tex]K_{3} PO_{4} + 3H_{2} O[/tex].

A chemical equation would be a symbol and formula-based symbolic formulation of a chemical reaction.

For every system that is closed across all exchanges of matter including energy, the law of conservation of mass, also known as the theory of mass conservation.

The equation  [tex]3KOH + H_{3} PO_{4}[/tex] → [tex]K_{3} PO_{4} + 3H_{2} O[/tex]. is balanced hence, it will follow mass of conservation law.

Therefore, the correct answer will be option (B).

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#SPJ3

Explanation:

Gravitational potential energy

= mgh

= (85kg)(9.81N/kg)(8848m)

= 7,377,904.8J.

Answer:

a) W=0  b) force of gravity and friction force

Explanation:

a) When the kicker touches the soccer ball, his foot exerts a force on the ball in the same direction of its movement, but the ball is stationary, therefore the displacement of the ball during the very short contact is zero and as the work is the product of force and distance, we conclude that there is no work

   W = F. d

   d = 0

    W = 0

b) When the ball is in flight there is mainly the force of gravity that has a vertical direction and the friction force that opposes the movement at all times

a.He does not do any work on the ball after it loses contact with his toe

b.The force of gravity and friction force doing work on the ball while it is in flight.

Work is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative.it depend on the diection of body displaced . if the body is displaced in the same direction of force it will be positive.

While if the displacement is in the opposite direction of force applied the work will be negative work . if their is no displacement of the body the work done will be zero.

a.He does not do any work on the ball after it loses contact with his toe.

When the kicker makes contact with the soccer ball, his foot exerts a force on the ball in the same direction as its movement, but the ball is stationary,

So the displacement of the ball during the very short contact is zero, and since work is the product of force and distance, we conclude that there is no work.

[tex]\rm W= F \times d \\\\ \rm W= F \times 0 \\\\ \rm W=0[/tex]

Hence he does not do any work on the ball after it loses contact with his toe.

b.The force of gravity and friction force doing work on the ball while it is in flight.

When the ball is in flight, there is primarily a vertical force of gravity and a friction force that resists movement at all times.]

Hence the force of gravity and friction force doing work on the ball while it is in flight.

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