(09.01 MC)
In circle A shown below, Segment BD is a diameter and the measure of Arc CB is 54°:

Points B, C, D lie on Circle A. Line segment BD is the diameter of circle A. Measure of arc CB is 54 degrees.

What is the measure of ∠DBC? (4 points)

Answer:

Step-by-step explanation:

pt=700 is basically evaluate it form the bottom to the top and u must mark me as brainly

Answer:

240

Step-by-step explanation:

You should go to the value 50 °F and see the value that match it

here it's 240 students

Based on the line of best fit, the number of students who wear a jacket to school when the temperature is 50°F is 240.

A graph is a way to represent a lot of data in such a visual format that it is easy for the user to understand the complete information in one go. Usually, the line of the graph is a function that follows the graph.

Given that The graph shows a line of best fit for data collected on the number of students who wear a jacket to school and the average daily temperature in degrees Fahrenheit.

Now, Based on the line of best fit, the number of students who wear a jacket to school when the temperature is 50°F can be found by simply observing the graph when the average daily temperature is 50°F as shown below, and then looking the value of y at that temperature.

Hence,  Based on the line of best fit, the number of students who wear a jacket to school when the temperature is 50°F is 240.

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Answer:

The probability is  [tex]P(X \ge 20 ) = 0.3707[/tex]

Step-by-step explanation:

From the the question we are told that

    The population proportion is  p =  0.60

    The sample size is  n  =  31

The  mean is evaluated as

       [tex]\mu = n * p[/tex]

substituting values  

       [tex]\mu = 31 *0.60[/tex]

       [tex]\mu = 18.6[/tex]

The standard deviation is evaluated as

    [tex]\sigma = \sqrt{n * p * (1- p )}[/tex]

substituting values  

    [tex]\sigma = \sqrt{31 * 0.6 * (1- 0.6 )}[/tex]

    [tex]\sigma = 2.73[/tex]

The  the probability that at least 20 of them have looked at their score in the past six months is mathematically represented as

     [tex]P(X \ge 20) = 1- P(X < 20)[/tex]

 applying normal approximation we have that

     [tex]P(X \ge 20) = 1- P(X < (20-0.5))[/tex]

   Standardizing

         [tex]1 - P(X < 20) = 1 - P(\frac{X - \mu }{\sigma} < \frac{19.5 - \mu }{\sigma } )[/tex]

         [tex]1 - P(X < 20) = 1 - P(Z < \frac{19.5 - 18.6 }{2.73 } )[/tex]

         [tex]1 - P(X < 20) = 1 - P(Z < 0.33)[/tex]

Form the standardized normal distribution table we have that

      [tex]P(Z < 0.0512)[/tex] = 0.6293

=>   [tex]P(X \ge 20 ) = 1- 0.6293[/tex]

=>   [tex]P(X \ge 20 ) = 0.3707[/tex]

Answer:

y = -15

Step-by-step explanation:

x-5y=-15x−5

Let x = -5

-5 -5y = -15 * -5 -5

Combine like terms

-5 -5y = 75-5

-5 -5y = 70

Add 5 to each side

-5y = 75

Divide by -5

y = -15

Answer:

proper because the numerator is lower than the denominator

Answer:

2x - 4.

Step-by-step explanation:

4 less than twice a number is the same thing as a number times 2 minus 4. Let's say that the number is represented by x.

2 * x - 4 = 2x - 4.

Hope this helps!

Answer:

Step-by-step explanation:

Recursively Defined Function               Sequence

f(1) = 13 f(n) = f(n - 1) + 26 for n ≥ 2         13, 39, 65, 91, ...

f(1) = 13 f(n) = 3 · f(n - 1) for n ≥ 2

f(1) = -24 f(n) = -4 · f(n - 1) for n ≥ 2

f(1) = 28 f(n) = f(n - 1) - 84 for n ≥ 2

f(1) = 28 f(n) = -4 · f(n - 1) for n ≥ 2         28, -112, 448, -1,792, ...

f(1) = -24 f(n) = 4 · f(n - 1) for n ≥ 2         -24, -96, -384, -1,536, ...

__

The initial values are easily seen. They match f(1). The recursive functions can be tested to see if they match the offered sequences.

  sequence 1 has a common ratio of 4 (not -4)

  sequence 2 has a common ratio of -4 (it is not arithmetic)

  sequence 3 has a common difference of 26 (it is not geometric)

Answer:

1 is sequence 3

5 is sequence 2

6 is sequence 1

(These r not included in the test, so don't use them)

 |

\ /

2 is no matching sequence

3 is no matching sequence

4 is no matching sequence

Step-by-step explanation:

PLATO

Answer:

Step-by-step explanation:

[tex]\frac{sin~x}{sec~x+1} =\frac{sin~x}{\frac{1}{cos~x}+1 } =\frac{sin~x~cos~x}{1+cos~x} \\=\frac{sin~x~cos~x}{1+cos~x} \times \frac{1-cos~x}{1-cos~x} \\=\frac{sin~x~cos~x(1-cos~x)}{1-cos^2 x} \\=\frac{sin~x~cos~x(1-cos~x)}{sin^2x} \\=\frac{cos~x(1-cos~x)}{sin~x} \\=cos ~x(csc~x-cot~x)\\or\\=cot~x(1-cos~x)[/tex]

the answer is x=-2

and y=12

Answer:

Step-by-step explanation:

A linear graph with y values (height of tree) going up 2.5 with each increase of x (growing season)

This is the model that best fits the graph describing a growth of a plant

Answer:

The answer is option C.

Step-by-step explanation:

- 9x - 3 > 51

Group like terms

- 9x > 51 + 3

- 9x > 54

Divide both sides by -9

x < - 6

Hope this helps you

Answer:

a)x - 4y -14 =0

5x - y - 13 =0

Step-by-step explanation:

Using substitution method to solve equation above gives:

x - 4y - 14 =0 ....eq1

5x - y -13 =0 ....eqn2

From eqn1, making x the subject formula:

x - 4y - 14 =0

x - 4y =14

x = 14+4y ...eqn3

From eqn2, substitute value of x and solve for y:

5(14+4y)-y-13 =0

70+20y-y-13 =0

70+19y-13 =0

70 - 13 = -19y

57 = -19y

divide both sides by -19

-57/19 = -19y/-19, then

y = -3

From eqn1:

x = 14 + 4y

substitute the value of y in the expression above

x = 14 + 4(-3)

x = 14 + (-12)

x = 14 - 12

x = 2

Answer:

15) 2.08m

Step-by-step explanation:

We kow tanA= p/b

Here, A=33°

b=3.2m

Then,

tan33°=p/3.2

0.65=p/3.2

p=0.65*3.2

p=2.08

So, The height of tree is 2.08m

14) 59.58ft

tan50°=p/b

1.19=p/50

p=59.58ft

So, The height of signpost is 59.58ft

In both of these problems, we will be using trigonometry! Remember, SOH-CAH-TOA.

14. x = 13.5950 ft

Visualization of the problem is attached below.

We want to find out the opposite side to the angle, and we know the adjacent side. Therefore, we should use the tangent function.

tan(50) = x / 50

x = tan(50) * 50

x = 13.5950 ft (round off wherever you need)

15. x = 241.0016 m

The visualization of the problem is already given. We know the same information as we need in the previous problems, an angle and an adjacent side, and we want to find the opposite side. Therefore, we should use the tangent function.

tan(33) = x / 3.2

x = tan(33) * 3.2

x = 241.0016 (round off wherever you need)

Hope this helps!! :)

Answer:

9.941*10^-6

Step-by-step explanation:

Probability of at most 1 means not more than 1 defective= probability of 1 or probability of 0

Probability of 1 = 50C1(0.25)(0.75)^49

Probability= 50(0.25)*7.55*10^-7

Probability= 9.375*10^-6

Probability of 0

= 50C0(0.25)^0(0.75)^50

= 1(1)(0.566*10^-6)

= 0.566*10^-6

Total probability

= 9.375*10^-6+ 0.566*10^-6

= 9.941*10^-6

Answer:

(-2, -(2pi)/3)

Step-by-step explanation:

a p ex

In da pic :)))))))))

Answer:

m = 26+32

Step-by-step explanation:

To determine the total number of miles biked, add the days together

m = 26+32

Answer:

26+32=m

Step-by-step explanation:

That is the general eqaution of this, because u must add both days worth of biked miles together.

Answer:

T(n) = 5n + 20

Step-by-step explanation:

1 candy has a mass of 5 g.

n candies have a mass of 5n grams.

The box has a mass of 20 grams.

total mass = mass of candies + mass of box

T(n) = 5n + 20

n         T(n)

0           20

25         145

50         270

75          395

100        520

Answer:

It would be B. Circle

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            Hi my lil bunny!

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Let's solve this step by step.

[tex]2^x + 4^x + 8^x = -14[/tex]

              ↓

In order to factor an integer, we need to repeatedly divide it by the ascending sequence of primes (2, 3, 5...).

The number of times that each prime divides the original integer becomes its exponent in the final result.

    Prime number 2 to the power of 2 = 4                

[tex]2^x + (2^2)^x + (2^3) ^x = -14[/tex]

                    ↓

Prime number 2 to the power of 3 = 8

[tex]2^x + 2^2x + 2^3x = -14[/tex]

                    ↓

We need to exponentiate the power.

The following rule is applied:

           [tex](A^B) ^C = A^BC[/tex]

In our example,

   A is equal to 2,

   B is equal to 2 and

   C is equal to x.

[tex]( 2^x + 2^2x + 2^3x ) + 14 = -14 + 14[/tex]

                         ↑

In order to solve this non-linear equation, we need to move all the terms to the left side.

In our example,

- term −14, will be moved to the left side.

Notice that a term changes sign when it 'moves' from one side of the equation to the other.

___________________

We need to get rid of expression parentheses.

If there is a negative sign in front of it, each term within the expression changes sign.

Otherwise, the expression remains unchanged.

In our example, there are no negative expressions.

                                  ↓

            [tex]2^x + 2^2x + 2^3x + 14 = 0[/tex]

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Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

Answer:

B. 3

Step-by-step Explanation:

To find the average rate of change of the exponential function represented by the table of values above can be calculated using the general formula for average rate of change of a function, which is given as [tex] m = \frac{f(b) - f(a)}{b - a} [/tex]

Where,

[tex] a = 1, f(1) = 7 [/tex]

[tex] b = 3, f(3) = 13 [/tex]

Plug in the above values in the average rate of change formula:

[tex] m = \frac{13 - 7}{3 - 1} [/tex]

[tex] m = \frac{6}{2} [/tex]

[tex] m = 3 [/tex]

Average rate of change is B. 3

Answer:

3

Step-by-step explanation:

Answer:

Graph B

Step-by-step explanation:

We are looking for a graph with a double root at x=3. In such cases, the function will "touch' the x-axis at x=3. The graph that shows such behavior is Graph B.

Answer:B

X intercepts (3,0) Y intercepts (0,9)

Answer:

The worst-case probability is 0.05

Step-by-step explanation:

The given significance level ([tex]\alpha[/tex]) = 0.05

since Probability of a type I error is [tex]\alpha[/tex]

∴ P (type I error) = 0.05

0.05 will be the worst-case probability of a type I error in at least one of the tests.

Answer:

Given that

radius of circle =5units

So, circumference of circle=2πr

=2×π×5

=10π units

hope it helps u...

plz mark as brainliest...

Answer:

[tex]\boxed{Circumference = 10\pi \ units}[/tex]

Step-by-step explanation:

Circumference = [tex]2\pi r[/tex]

Where r = 5

=> Circumference = 2π(5)

=> Circumference = 10π units

Answer: Regression line equation:  [tex]\hat{y}=-1.008x+39.1704[/tex]

Step-by-step explanation:

Equation of least-squares regression line for predicting y :

[tex]\hat{y}=b_1x+b_o[/tex]

, where [tex]\text{Slope} (b_1)=r\dfrac{s_y}{s_x}[/tex] ,  [tex]\text{intercept}(b_0)=\bar{y}-b_1\bar{x}[/tex]

Given: [tex]\bar{x}=8.8,\ s_x=1.5,\ s_y=1.8,\ \bar{y}=30.3,\ r=-0.84[/tex]

Then,

[tex]b_1=(-0.84)\dfrac{ 1.8}{ 1.5}\\\\\Rightarrow\ b_1=-1.008[/tex]

Now,

[tex]b_0=30.3-(-1.008)(8.8)=30.3+8.8704\\\\\Rightarrow\ b_0=39.1704[/tex]

Then, Regression line equation:  [tex]\hat{y}=-1.008x+39.1704[/tex]

We're told (and we can confirm) that [tex]v_3=2v_1-3v_2[/tex], so [tex]v_3[/tex] is a linear combination of the other two vectors.

This means H is sufficiently spanned by [tex]\{v_1,v_2\}[/tex]; no need for the third vector.

But this also means we can write either [tex]v_1[/tex] as a linear combination of [tex]\{v_2,v_3\}[/tex], and [tex]v_2[/tex] as a lin. com. of [tex]\{v_1,v_3\}[/tex]. So any set of these three vectors taken two at a time will span the subspace H. Hence all of b, c, and d are acceptable.

The slope would be 4/3 and the y-intercept is 1

Create a table x and y and in x there is -3/4 and 0 and for the y side is 0 and 1. The line would be in the 2 quadrant with 2 points on on the y axis 1 and the other on the x axis 0.9 and that would be the graphed description of the line. Sorry if this is hard to understand i don’t have a access to draw or insert an image.

The graph of the linear equation is on the image at the end.

To do it, we need to find two points on the line, so let's evaluate it.

When x = 0

y = (4/3)*0 + 1 = 1 ----> (0, 1)

When x = 3

y = (4/3)*3 + 1 = 5 ---> (3 , 5)

Now just graph these two points and connect them with a line, that will be the graph of the linear equation.

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Answer:

work is shown and pictured

Answer:

y=2.2

Step-by-step explanation:

1: Distribute all numbers to get rid of all parenthesis

2: Solve

Hope this helped :) LET ME KNOW IF YOU NEED THE ANSWER IN A DIFFERENT FORM I CAN GET IT FOR YOU

Step-by-step explanation:

. 345,000 cm³.

b. 124,300 hl.

c. 9,000 cm³.

d. 32.5 dm³.

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

a. 3,450 deciliters to cubic decimeters:

1 deciliter=100 cubic decimeters

(3,450dl)(\frac{100cm^{3}}{1dl})=345,000cm^{3}(3,450dl)(

1dl

100cm

3

)=345,000cm

3

b. 124.3 hectoliters to deciliters:

1 hectoliter=1,000 deciliters

(124,3hl)(\frac{1,000dl}{1hl})=124,300hl(124,3hl)(

1hl

1,000dl

)=124,300hl

c. 9 liters to cubic centimeters:

1 liter=1,000 cubic centimeters

(9L)(\frac{1,000cm^{3}}{1L})=9,000cm^{3}(9L)(

1L

1,000cm

3

)=9,000cm

3

d. 32.5 liters to cubic decimeters:

1 liter=1 cubic decimeter

32.5L=32.5dm^{3}32.5L=32.5dm

3

your answer follow me plzzz

Answer:

The first one is 345,000 cm³.

The second is 124,300 hl.

the Third is 9,000 cm³.

Anddd the fourth one is 32.5 dm³

:)

Answer:

(a) The probability that the sample mean will be more than 61 pounds is 0.0069.

(b) The probability that the sample mean will be more than 57 pounds is 0.4522.

(c) The probability that the sample mean will be between 55 and 58 pounds is 0.6112.

(d) The probability that the sample mean will be less than 55 pounds is 0.14686.

(e) The probability that the sample mean will be less than 48 pounds is 0.00001.

Step-by-step explanation:

We are given that the Aluminum Association reports that the average American uses 56.8 pounds of aluminum in a year.

A random sample of 51 households is monitored for one year to determine aluminum usage. Also, the population standard deviation of annual usage is 12.2 pounds.

Let [tex]\bar X[/tex] = sample mean

The z-score probability distribution for the sample mean is given by;

                             Z  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = average aluminum used by American = 56.8 pounds

           [tex]\sigma[/tex] = population standard deviation = 12.2 pounds

           n = sample of households = 51

(a) The probability that the sample mean will be more than 61 pounds is given by = P([tex]\bar X[/tex] > 61 pounds)

   P([tex]\bar X[/tex] > 61 pounds) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{61-56.8}{\frac{12.2}{\sqrt{51} } }[/tex] ) = P(Z > 2.46) = 1 - P(Z [tex]\leq[/tex] 2.46)

                                                               = 1 - 0.9931 = 0.0069

The above probability is calculated by looking at the value of x = 2.46 in the z table which has an area of 0.9931.

(b) The probability that the sample mean will be more than 57 pounds is given by = P([tex]\bar X[/tex] > 57 pounds)

   P([tex]\bar X[/tex] > 57 pounds) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{57-56.8}{\frac{12.2}{\sqrt{51} } }[/tex] ) = P(Z > 0.12) = 1 - P(Z [tex]\leq[/tex] 0.12)

                                                               = 1 - 0.5478 = 0.4522

The above probability is calculated by looking at the value of x = 0.12 in the z table which has an area of 0.5478.

(c) The probability that the sample mean will be between 55 and 58 pounds is given by = P(55 pounds < [tex]\bar X[/tex] < 58 pounds)

P(55 pounds < [tex]\bar X[/tex] < 58 pounds) = P([tex]\bar X[/tex] < 58 pounds) - P([tex]\bar X[/tex] [tex]\leq[/tex] 55 pounds)    

   P([tex]\bar X[/tex] < 58 pounds) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\frac{58-56.8}{\frac{12.2}{\sqrt{51} } }[/tex] ) = P(Z < 0.70) = 0.75804

   P([tex]\bar X[/tex] [tex]\leq[/tex] 55 pounds) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] [tex]\leq[/tex] [tex]\frac{55-56.8}{\frac{12.2}{\sqrt{51} } }[/tex] ) = P(Z [tex]\leq[/tex] -1.05) = 1 - P(Z < 1.05)

                                                               = 1 - 0.85314 = 0.14686

The above probability is calculated by looking at the value of x = 0.70 and x = 1.05 in the z table which has an area of 0.75804 and 0.85314.

Therefore, P(55 pounds < [tex]\bar X[/tex] < 58 pounds) = 0.75804 - 0.14686 = 0.6112.

(d) The probability that the sample mean will be less than 55 pounds is given by = P([tex]\bar X[/tex] < 55 pounds)

   P([tex]\bar X[/tex] < 55 pounds) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\frac{55-56.8}{\frac{12.2}{\sqrt{51} } }[/tex] ) = P(Z < -1.05) = 1 - P(Z [tex]\leq[/tex] 1.05)

                                                               = 1 - 0.85314 = 0.14686

The above probability is calculated by looking at the value of x = 1.05 in the z table which has an area of 0.85314.

(e) The probability that the sample mean will be less than 48 pounds is given by = P([tex]\bar X[/tex] < 48 pounds)

   P([tex]\bar X[/tex] < 48 pounds) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\frac{48-56.8}{\frac{12.2}{\sqrt{51} } }[/tex] ) = P(Z < -5.15) = 1 - P(Z [tex]\leq[/tex] 5.15)

                                                               = 1 - 0.99999 = 0.00001

The above probability is calculated by looking at the value of x = 5.15 in the z table which has an area of 0.99999.