box with a a square base and open top must have a volume of 62,500 cm3. Find the dimensions of the box that minimize the amount of material used. sides of base

Answer:

£1960

Step-by-step explanation:

Step 1.

2% = 100% ÷ 50

Step 2.

£2000 ÷ 50 = £40

Step 3.

£2000 - £40 = £1960

Answer:

There are 192 window panes in total.

Step-by-step explanation:

Since each window has four window panes across and four window panes down,the number of panes per window is:

[tex]w=4*4=4^2[/tex]

The total number of window panes in 'n' windows is:

[tex]P=n*4^2[/tex]

With n = 12 windows, the expression that describes the total number of window panes is:

[tex]P=12*4^2\\P=192\ panes[/tex]

There are 192 window panes in total.

Answer:

One window has 4 × 4, or 42, window panes, so 12 windows have 12 × 4^2 window panes.

Step-by-step explanation:

One window has 4 × 4, or 42, window panes, so 12 windows have 12 × 4^2 window panes.

Answer:

Step-by-step explanation:

Let, present age of son be 'x'

present age of father be 'y'

y = 4x→ equation ( i )

After five years,

Son's age = x + 5

father's age = y + 5

According to Question,

[tex]y + 5 = 3(x + 5)[/tex]

Put the value of y from equation ( i )

[tex]4x + 5 = 3(x + 5)[/tex]

Distribute 3 through the parentheses

[tex]4x + 5 = 3x + 15[/tex]

Move variable to L.H.S and change it's sign

Similarly, Move constant to R.H.S. and change its sign

[tex]4x - 3x = 15 - 5[/tex]

Collect like terms

[tex]x = 15 - 5[/tex]

Calculate the difference

[tex]x = 10[/tex]

Now, put the value of X in equation ( i ) in order to find the present age of father

[tex]y = 4x[/tex]

plug the value of X

[tex] = 4 \times 10[/tex]

Calculate the product

[tex] = 40[/tex]

Therefore,

Present age of son = 10

present age of father = 40

Hope this helps..

Best regards!!

Answer:

z=  0.278

Step-by-step explanation:

Given data

n1= 60 ; n2 = 100

mean 1= x1`= 10.4;     mean 2= x2`= 9.7

standard deviation  1= s1= 2.7 pounds ;  standard deviation 2= s2 = 1.9 lb

We formulate our null and alternate hypothesis as

H0 = x`1- x`2 = 0 and H1 = x`1- x`2 ≠ 0 ( two sided)

We set level of significance α= 0.05

the test statistic to be used under H0 is

z = x1`- x2`/ √ s₁²/n₁ + s₂²/n₂

the critical region is z > ± 1.96

Computations

z= 10.4- 9.7/ √(2.7)²/60+( 1.9)²/ 100

z= 10.4- 9.7/ √ 7.29/60 + 3.61/100

z= 0.7/√ 0.1215+ 0.0361

z=0.7 /√0.1576

z= 0.7 (0.396988)

z= 0.2778= 0.278

Since the calculated value of z does not fall in the critical region so we accept the null hypothesis H0 = x`1- x`2 = 0  at 5 % significance level. In other words we conclude that the difference between mean scores is insignificant or merely due to chance.

Answer:

John is 9, Brian is 6.

Step-by-step explanation:

I)

Let [tex]J[/tex] represent John's age and [tex]B[/tex] represent Brian's age.

John is three years older than Brian. In other words:

[tex]J=B+3[/tex]

The product of their ages is 54. Or:

[tex]JB=54[/tex]

II)

Write this as a quadratic by substituting:

[tex]JB=54\\(B+3)B=54\\B^2+3B-54=0[/tex]

III)

Solve the quadratic:

[tex]B^2+3B-54=0\\B^2-6B+9B-54=0\\B(B-6)+9(B-6)=0\\(B+9)(B-6)=0\\B=-9, 6[/tex]

Since age cannot be negative, Brian must be 6 years old right now.

John is three year older, so John is 9.

Answer:

Below

Step-by-step explanation:

The average speed is given by the following formula:

● V = d/t

● d is the distance covered

● t is the time spent to cover the distance d

■■■■■■■■■■■■■■■■■■■■■■■

Ava takes 8 minutes to go from mile marker 0 to mile marker6.

● the distance Ava traveled is 6 miles

● the time Ava spent to reach mile marker 6 is 8 minutes

So the average speed of Ava is:

● V = 6/ 8 = 3/4 = 0.75 mile per min

●●●●●●●●●●●●●●●●●●●●●●●●

Let's The equation of the line that links the number of milemarkers (n) and the time (t).

Ava went from mile marker 0 to mile marker 6.

At t=0 Ava just started travelling from mile marker 0 to 1.

Afrer 8 minutes,she was at mile marker 6.

So 8 min => 6 mile markers (igonring mile marker 0 since the distance there was 0 mile)

6/8= 0.75

Then n/t = 0.75

● n = 0.75 * t

Let's check

● n= 0.75*4 = 3

That's true since after 4 minutes Ava was at mile marker 3.

Answer:

55.563

Step-by-step explanation:

Given the following :

Mean(m) point = 73

Standard deviation( sd) = 10.6

Lower 5% will not get a passing grade (those below the 5% percentile)

For a normal distribution:

The z-score is given by:

z = (X - mean) / standard deviation

5% of the class = 5/100 = 0.05

From the z - table : 0.05 falls into - 1.645 which is equal to the z - score

Substituting this value into the z-score formula to obtain the score(x) which seperates the lower 5%(0.05) from the rest of the class

z = (x - m) / sd

-1.645 = (x - 73) / 10.6

-1 645 * 10.6 = x - 73

-17.437 = x - 73

-17.437 + 73 = x

55.563 = x

Therefore, the score which seperetes the lower 5% from the rest of the class is 55.563

Answer:

AC = DF

Step-by-step explanation:

The SSS Postulate occurs when all three corresponding pairs of sides are congruent, therefore, the only missing pair is AC = DF.

Answer:  $122.50

Step-by-step explanation:

In          Out

8:00    12:00    = 4 hours

12:45    17:30   = 4.75 hours  

          Total        8.75 hours

8.75 hours x $14/hr = $122.50

Note: to subtract 12:45 from 17:30, borrow 1 hour from 17 and add 60 minutes to 30:

 17:30       →         16:90

- 12:45                - 12:45

                            4: 45

4 hours 45 minutes = [tex]4\frac{3}{4}[/tex] = 4.75 hours

NoAnswer:

Step-by-step explanation:

Cause I’m good

Answer:

[tex] \boxed{\sf x = -7} [/tex]

Step-by-step explanation:

[tex] \sf Solve \: for \: x: \\ \sf \implies - 30 = 5(x + 1) \\ \\ \sf - 30 =5(x+ 1) \: is \: equivalent \: to \: 5 (x + 1) = - 30: \\ \sf \implies 5(x + 1) = - 30 \\ \\ \sf Divide \: both \: sides \: of \: 5(x+ 1) = - 30 \: by \: 5: \\ \sf \implies \frac{5(x + 1)}{5} = - \frac{30}{5} \\ \\ \sf \frac{5}{5} = 1 : \\ \sf \implies x + 1 = - \frac{30}{5} \\ \\ \sf - \frac{30}{5} = - \frac{6 \times \cancel{5}}{ \cancel{5}} = - 6 : \\ \sf \implies x + 1 = - 6 \\ \\ \sf Subtract \: 1 \: from \: both \: sides: \\ \sf \implies x + (1 - 1) = - 6 - 1 \\ \\ \sf 1 - 1 = 0 : \\ \sf \implies x = - 6 - 1 \\ \\ \sf - 6 - 1 = - 7 : \\ \sf \implies x = - 7[/tex]

Answer:

[tex] \boxed{x = - 7}[/tex]

Step-by-step explanation:

[tex] \mathrm{ - 30 = 5(x + 1)}[/tex]

Distribute 5 through the parentheses

[tex] \mathrm{ - 30 = 5x + 5} [/tex]

Move constant to L.H.S and change its sign

[tex] \mathrm{ - 30 - 5 = 5x}[/tex]

Calculate

[tex] \mathrm{ - 35 = 5x}[/tex]

Swipe the sides of the equation

[tex] \mathrm{5x = - 35}[/tex]

Divide both sides of the equation by 5

[tex] \mathrm{ \frac{5x}{5} = \frac{ - 35}{5} }[/tex]

Calculate

[tex] \mathrm{x = - 7}[/tex]

Hope I helped!

Best regards!!

Answer:

x=6.28 inches

y=191.08 inches

Step-by-step explanation:

Let the dimensions of the rectangle be x and y

Area of the rectangular sheet

x*y=1200 in^2}

x = circumference of the cylinder

This means x=2πr

Volume of a cylinder=πr^2h

h=y

Volume of the cylind=πr^2(y)=600 in^3

From x=2πr

r=x/2π

Substitute r=x/2π into Volume=πr^2(y)=600 in^3

We have,

Volume of the cylinder=πr^2(y)=600 in^3

π*(x/2π)^2(y)=600

(x^2/4π)y=600

Recall, x*y=1200

y=1200/x

Substitute y=1200/x into (x^2/4π)y=600

(x^2/4π)y=600

(x^2/4π)(1200/x)=600

1200x/4π=600

Multiply both sides by 4π

(x^2/4π)(1200/x)(4π)=600*4π

1200x=2400π

Divide both sides by 1200

1200x/1200 = 2400π/1200

x=2π

Substitute x=2π into y=1200/x

We have,

y=1200/2π

y=600/π

The dimensions are x=2π and y=600/π

Let π=3.14

x=2π

=2(3.14)

=6.28 inches

y=600/π

=600/3.14

=191.08 inches

Answer:

The spread of the data in Set B is greater than the spread of the data in Set A.

Step-by-step explanation:

Just took the test :3

Answer:

The simplified expression is [tex]\frac{10}{3 a^2 b}[/tex]

Step-by-step explanation:

The given expression is:

[tex]\frac{15b}{4} * \frac{8}{9a^2 b^2}[/tex]

Multiply the items in the numerator together ( 15b * 8 = 120 b). Also multiply the items in the denominator together ( 4 * 9a²b² = 36a²b²). The expression thus becomes:

[tex]= \frac{120b}{36 a^2 b^2} \\\\[/tex]

Divide both the numerator and the denominator by 12b:

[tex]= \frac{120b /12b}{36 a^2 b^2/12b}[/tex]

The expression finally becomes:

[tex]= \frac{10}{3 a^2 b}[/tex]

Answer:

Step-by-step explanation:

here u go

Answer:

[tex]\boxed{135\°,315\°}[/tex]

Step-by-step explanation:

Solve the trigonometric equation by isolating the function and then taking the inverse. Use the period to find the full set of all solutions.

[tex]\theta = 135+180n[/tex]

[tex]n[/tex] is any integer value.

The value of [tex]n[/tex] cannot exceed 1 or be less than 0, because the value of [tex]\theta[/tex] must be between 0 and 360 degrees.

[tex]\theta = 135+180(0)[/tex]

[tex]\theta = 135[/tex]

[tex]\theta = 135+180(1)[/tex]

[tex]\theta = 315[/tex]

see attachment a=400 rpm b and c = 200 rpm d = 40 rpm

Answer:

pulley B 200, pulley C 200, pulley D 160

Answer: 0.271

Step-by-step explanation:

Probability of complement of an even is 1 decreased by the probability of the event

P(At least one) =1 - P(none)

The probability that of testing negative is 0.9 because the probability of testing positive is 0.1

P( at least one) = 1 - P(none) = 1 - (0.93^3) = 0.271

Answer:

  145.39

Step-by-step explanation:

The ratio of supply to demand will be 1 at the equilibrium price:

  S(p)/D(p) = 1 = 140e^(0.005p)/(448e^(-0.003p))

  448/140 = e^(0.005p -(-0.003p)) = e^(0.008p)

  ln(448/140) = 0.008p . . . . . . . . . taking the natural log

  p = ln(448/140)/0.008 ≈ 145.39

The equilibrium price is about $145.39.

Answer:

Answer:

Since the transformation is made by shifting the function right, it is a horizontal transformation.

Answer:

j ≥ -44

Step-by-step explanation:

-2/11 j ≤ 8

Multiply each side by -11/2 to isolate j.  Flip the inequality since we are multiplying by a negative

-11/2 * -11/2 j ≥ 8 * -11/2

j ≥ -44

Answer:

[tex]j\geq -44[/tex]

Step-by-step explanation:

The inequality given is:

[tex]\frac{-2}{11}j\leq 8[/tex]

To solve the inequality, we must get the variable j by itself.

j is being multiplied by -2/11. To reverse this, we must multiply by the reciprocal of the fraction.

Flip the numerator (top number) and denominator (bottom number) to find the reciprocal.

[tex]\frac{-2}{11} --> \frac{-11}{2}[/tex]

Multiply both sides of the equation by -11/2.

[tex]\frac{-11}{2} *\frac{-2}{11} j \leq 8*\frac{-11}{2}[/tex]

[tex]j\leq 8*\frac{-11}{2}[/tex]

Since we multiplied by a negative number, we must flip the inequality sign.

[tex]j\geq 8*\frac{-11}{2}[/tex]

Multiply 8 and -11/2

[tex]j\geq 8*-5.5[/tex]

[tex]j\geq -44[/tex]

The solution to the inequality is: [tex]j\geq -44[/tex]

Answer:  see below

Step-by-step explanation:

[tex]P(x)=\dfrac{2}{3x-1}\qquad \qquad Q(x)=\dfrac{6}{-3x+2}\\[/tex]

P(x) ÷ Q(x)

[tex]\dfrac{2}{3x-1}\div \dfrac{6}{-3x+2}\\\\\\=\dfrac{2}{3x-1}\times \dfrac{-3x+2}{6}\\\\\\=\large\boxed{\dfrac{-3x+2}{3(3x-1)}}[/tex]

P(x) + Q(x)

[tex]\dfrac{2}{3x-1}+ \dfrac{6}{-3x+2}\\\\\\=\dfrac{2}{3x-1}\bigg(\dfrac{-3x+2}{-3x+2}\bigg)+ \dfrac{6}{-3x+2}\bigg(\dfrac{3x-1}{3x-1}\bigg)\\\\\\=\dfrac{2(-3x+2)+6(3x-1)}{(3x-1)(-3x+2)}\\\\\\=\dfrac{-6x+4+18x-6}{(3x-1)(-3x+2)}\\\\\\=\dfrac{12x-2}{(3x-1)(-3x+2)}\\\\\\=\large\boxed{\dfrac{2(6x-1)}{(3x-1)(-3x+2)}}[/tex]

P(x) - Q(x)

[tex]\dfrac{2}{3x-1}- \dfrac{6}{-3x+2}\\\\\\=\dfrac{2}{3x-1}\bigg(\dfrac{-3x+2}{-3x+2}\bigg)- \dfrac{6}{-3x+2}\bigg(\dfrac{3x-1}{3x-1}\bigg)\\\\\\=\dfrac{2(-3x+2)-6(3x-1)}{(3x-1)(-3x+2)}\\\\\\=\dfrac{-6x+4-18x+6}{(3x-1)(-3x+2)}\\\\\\=\dfrac{-24x+10}{(3x-1)(-3x+2)}\\\\\\=\large\boxed{\dfrac{-2(12x-5)}{(3x-1)(-3x+2)}}[/tex]

P(x) · Q(x)

[tex]\dfrac{2}{3x-1}\times \dfrac{6}{-3x+2}\\\\\\=\large\boxed{\dfrac{12}{(3x-1)(-3x+2)}}[/tex]

Greetings from Brasil...

In a linear function, the rate of change is given by M (see below).

M = rate of change

N = linear coefficient

The Function 2 has M = 4, cause

F(X) = 4X + 1

(M = 4 and N = 1)

For Function 1 we have a rate of change equal to zero, becaus it is a constant function... let's see:

M = ΔY/ΔX

M = (3 - 3)/(4 - 0)

M = 0/4 = 0

So, the Function 2 has 4 times more rate of change than the first

Your answer is two!!

Answer:

y+2 = 4(x-6)

Step-by-step explanation:

The point slope equation of a line is

y-y1 = m(x-x1)  where m is the slope and ( x1,y1) is a point on the line

y - -2 = 4( x-6)

y+2 = 4(x-6)

Answer:

-3

Step-by-step explanation:

2x + 3 +7x = -24

Add the X together

9x +3 = -24

Bring over the +3. [when you bring over change the sign]

9x = -24 -3

9x = -27

-27 divide by 9 to find X

therefore answer is

x= -3.

Hope this helps

Answer:

x = -3

Step-by-step explanation:

question is

2x + 3 + 7x = -24

First you combine the like terms

2x and 7x you can add them so it will be 9x

so it will then it will be like this:

9x + 3 = -24

now you take the 3 and send it to the other side, and right now the 3 is positive so when it goes to the other side it will turn into -3

so

9x = -24 -3

again now you combine the like terms

-24 -3 = - 27

now you have

9x = -27

now just divide each side by 9

x = -27/9

x = -3

Sorry if this doesnt help

Answer:

when we add all the angles.

=58+94+15=167

so it's a 180..

180_167

=13

round to nearest tenth.

=10..

Answer:

3+x

Step-by-step explanation:

sum= addition

a number= a number

Answer:

3+x  

eplanation                                  

This question is incomplete

Complete Question

The function s(V) = ∛V describes the side length, in units, of a cube with a volume of V cubic units.

Jason wants to build a cube with a minimum of 64 cubic centimeters.

What is a reasonable range for s, the side length, in centimeters, of Jason’s cube?

a) s > 0

b) s ≥ 4

c) s ≥ 8

d) s ≥ 16

Answer:

b) s ≥ 4

Step-by-step explanation:

From the above question, we are given Volume of the cube = 64cm³

We are given the function

s(V) = ∛V

Hence,

The range for the side length s =

s(V) ≥ ∛V

s(V) ≥ ∛64 cm³

s(v) ≥ 4 cm

Therefore, the reasonable range for s, the side length, in centimeters, of Jason’s cube

Option b) s ≥ 4

Answer:

s≥ 4

Step-by-step explanation: