Bill has two dollars and 2 cents. How much money does he have?

Answer:

1) How does "Abe" relate to the merry-go-round? (The problem doesn't seem to say.)

2) How many people did each person provide for? So how many dozens were brought? How many are in a dozen? So how many cookies were brought?

Step-by-step explanation:

nm the top

There are n seats on a merry- go-round. A boy takes n rides. Between each ride, he moves clockwise a certain number of places to a new horse. Each time he moves a different number of places. Find all n for which the boy ends up riding each horse.

2) So if there are n horses, first the boy could move by one place then he could move by n+1 places then by 2n+1 so on and so forth, until he moves (n−2)n+1 places, in which case he'd would have been ridden each horse only one time and taken unique number of steps, which implies that all n's satisfy given condition.

1) I don't know how to cancer this let me resheerch and ill get back to you

P>S let this be help only if you need to annotate or reword thx

Answer:

4х +4y +z= 24 Correct

2x – 4у +z= 0 Correct

- 3х + 6z =- 12 Correct

Step-by-step explanation: I hoped I helped you yo.

Answer:

Step-by-step explanation:

Given:

and

Find g(f(x)), substitute the value of f(x) into equation:

Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.

The question is an illustration of permutation and combinations.

The given parameters are:

[tex]\mathbf{n = 7}[/tex]

[tex]\mathbf{r = 4}[/tex]

(a) Choose 4 of 7 paintings

Choosing 4 of 7 paintings implies combination.

So, we have:

[tex]\mathbf{^nC_r = \frac{n!}{(n - r)!r!}}[/tex]

Substitute values for n and r

[tex]\mathbf{^7C_4 = \frac{7!}{(7 - 4)!4!}}[/tex]

[tex]\mathbf{^7C_4 = \frac{7!}{3!4!}}[/tex]

Expand

[tex]\mathbf{^7C_4 = \frac{7 \times 6 \times 5 \times 4!}{3 \times 2 \times 1 \times 4 !}}[/tex]

[tex]\mathbf{^7C_4 = 35}[/tex]

Hence, the number of ways she can choose 4 out of the 7 paintings is 35

(b) Arrange 4 of 7 paintings

Arranging 4 of 7 paintings implies permutation.

So, we have:

[tex]\mathbf{^nP_r = \frac{n!}{(n - r)!}}[/tex]

Substitute values for n and r

[tex]\mathbf{^7P_4 = \frac{7!}{(7 - 4)!}}[/tex]

[tex]\mathbf{^7P_4 = \frac{7!}{3!}}[/tex]

Expand

[tex]\mathbf{^7P_4 = \frac{7 \times 6 \times 5 \times 4 \times 3!}{3!}}[/tex]

[tex]\mathbf{^7P_4 = 840}[/tex]

Hence, the number of ways she can arrange 4 out of the 7 paintings is 840

Read more about permutation and combinations at:

https://brainly.com/question/15301090

Answer:

5)42º

6)112º

7)112º

8)38º

Step-by-step explanation:

m<6         180-68=112

m<5         180=26+112+x            42=x

m<7 is congruent to m<6

m<8         180=30+112+x            38=x

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Given terms :

Distance covered (d) = 12 miles

Time taken (t) = 1.5 hour

Average speed :

average speed = 8 mph

Answer:

8mph

Speed= Distance/Time

12/1.5= 8mph

Step-by-step explanation:

bro, MO bisects into 2 equal halves. ..

so, there will be

Angle AMO is equal to angle BMO.__(A)

MO is common side ___( S)

Angle AOM is equal to angle MOB___(A)

hence ,

∆AMO is congrent to ∆BMO

hence proved

Answer:

it is C

Step-by-step explanation:

The real numbers have the following important subsets: rational numbers, irrational numbers, integers, whole numbers, and natural numbers.

8 is an a integer, a whole number and a rational number.

Hope this helps,

if so mark brainliest...

Answer:

M = [tex]\frac{5}{6}[/tex] Is correct answer

Step-by-step explanation:

Write in slope-intercept form,  y = m x + b.

m = [tex]\frac{5}{6}[/tex]

Graph in pic

(Hope this helps can I pls have brainlist (crown)☺️