Barry is selling baseball cards. he sold 2 for $8.00 and 4 for $14.00. what will barry charge for 7 baseball cards if he keeps selling cards at the same rate?

Answer:

Step-by-step explanation:

the answer is R=63

The current drawn by each resistor is: R1: 8 A R2: 9.25 A R3: 14.67 A And the power dissipated by each resistor is: R1: 192 W R2: 222 W R3: 352 W

To calculate the current drawn by each resistor and the power dissipated by each, we will use Ohm's Law and the Power formula.

Ohm's Law is V = IR, and the Power formula is P = IV.

Given: Resistor 1 (R1) = 192 W Resistor 2 (R2) = 222 W Resistor 3 (R3) = 352 W Voltage (V) = 24 V

Step 1: Calculate the current (I) drawn by each resistor using the Power formula (P = IV):

For R1: I1 = P1 / V = 192 W / 24 V = 8 A

For R2: I2 = P2 / V = 222 W / 24 V = 9.25 A

For R3: I3 = P3 / V = 352 W / 24 V = 14.67 A

Step 2: Calculate the power (P) dissipated by each resistor using the Power formula (P = IV):

For R1: P1 = I1 × V = 8 A × 24 V = 192 W

For R2: P2 = I2 × V = 9.25 A × 24 V = 222 W

For R3: P3 = I3 × V = 14.67 A × 24 V = 352 W

So, the current drawn by each resistor is: R1: 8 A R2: 9.25 A R3: 14.67 A And the power dissipated by each resistor is: R1: 192 W R2: 222 W R3: 352 W

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In the formula [tex]A(t) = Pe^{rt}[/tex] continuously compound interest P, r, and t stands for Principal, rate of interest, and time respectively, and A(t) stands for Amount after t amount of time.  If $200 is invested at an interest rate of 4% compounded continuously, then the amount after 3 years is $225.5.

The formula for Compound Interest at a continuous period of time is denoted by [tex]A(t) = Pe^{rt}[/tex]

where the Principal amount is multiplied by the exponential value of the interest rate and time passed.

Hence we are given here

P = $200, r = 4% = 0.04, and the amount to be calculated for t = 3 years

Hence we will find the amount by replacing these values to get

A(3) = 200 × e⁰°⁰⁴ ˣ ³

= $200 × e⁰°¹²

= $225.499

rounding it off to the nearest cent gives us

$225.5

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Correct Question

In the formula [tex]A(t) = Pe^{rt}[/tex] continuously compound interest P, r, and t stands for ______ , _______ , and __________ respectively, and A(t) stands for _______ .

So if $200 is invested at an interest rate of 4% compounded continuously, then the amount after 3 years is $__________. (Round your answer to the nearest cent.)

The congruent triangles is solved and the triangles are congruent by AAS postulate

Given data ,

Let the two triangles be represented as ΔRQT and ΔTQS

And , the side TQ is the common side of both the triangles

Now , the measure of ∠TQR ≅ measure of ∠TQS ( given )

And , the measure of ∠TRQ ≅ measure of ∠TSQ ( given )

So , Two angles are the same and a corresponding side is the same (ASA: angle, side, angle)

Hence , the triangles are congruent by ASA postulate

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We know that they cannot exceed 30 minutes, they should not waste any time and must move quickly during each crossing.

To ensure that Leo's family crosses the bridge before the flashlight runs out, they should follow these steps:
1. Dad and Mom should cross the bridge together, which will take 3 minutes (because the slowest person is Mom, who takes 3 minutes).
2. Dad should return to the starting point, which will take 1 minute.
3. Leo and Brother should then cross the bridge together, which will take 8 minutes (because the slowest person is Brother, who takes 8 minutes).
4. Mom should return to the starting point, which will take 3 minutes.
5. Dad and Grandpa should then cross the bridge together, which will take 12 minutes (because the slowest person is Grandpa, who takes 12 minutes).
6. Dad should return to the starting point, which will take 1 minute.
7. Finally, Dad and Mom should cross the bridge together, which will take 3 minutes (because the slowest person is Mom, who takes 3 minutes).

Adding up all the minutes taken, it will be: 3+1+8+3+12+1+3=31 minutes. However, since they cannot exceed 30 minutes, they should not waste any time and must move quickly during each crossing.

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Ms. Thompson could set up either 2 rows with 164 chairs in each row or 4 rows with 82 chairs in each row.

To find the number of chairs in each row, we need to divide the total number of chairs by the number of rows. Let's start by finding the factors of 328:

1 x 328

2 x 164

4 x 82

8 x 41

Since there must be at least 2 rows and no more than 10 rows, we can eliminate the last two factor pairs. We are left with:

2 x 164

4 x 82

We can see that the first factor pair gives us 2 rows, while the second gives us 4 rows. We are told that each row has an equal number of chairs, so we need to divide the total number of chairs by the number of rows to find out how many chairs are in each row:

For 2 rows: 328 ÷ 2 = 164 chairs in each row

For 4 rows: 328 ÷ 4 = 82 chairs in each row

Your question is incomplete but most probably your full question

Ms. Thompson sets up chairs in rows for a school concert. She uses 328 chairs. She sets up at least 2 rows of chairs but not more than 10 rows of chairs. Each row has an equal number of chairs.

How many rows of chairs does Ms. Thompson set up? Enter the number in the first box.

How many chairs are in each row? Enter the number in the second box.

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Hence, the required equation of the quintic with double roots –4 and 2 is [tex]f(x)=\frac{1}{256} (x+4)^2(x-2)^2(x)[/tex].

Given, an equation of a quintic with double roots –4 and 2, that goes through the origin as well as (4, 4).

Let r be the remaining root of the equation.

Let the required equation in factored form is

[tex]f(x)=a(x+4)^2(x-2)^2(x-r)[/tex]

Given, the quintic goes through the origin.

Then, we know that f(0) = 0.

[tex]f(0)=a(0+4)^2(0-2)^2(0-r)[/tex]

0 = a(16)(4)(-r)

0 = -64ar

64ar = 0

either a = 0 or r = 0.

if a = 0

then the equation reduces to f(x) = 0, which is not a quintic.

a ≠ 0

This means that r = 0

So equation becomes [tex]f(x)=a(x+4)^2(x-2)^2(x)[/tex]   ...(1)

Given, the quintic goes through the point (4, 4)

So, f(4) = 4

[tex]f(4)=a(4+4)^2(4-2)^2(4)[/tex]

4 = 1064 a

a = 4/1064

a = 1/256

Putting in equation (1)

[tex]f(x)=\frac{1}{256} (x+4)^2(x-2)^2(x)[/tex]

Hence, the required equation of the quintic with double roots –4 and 2 is [tex]f(x)=\frac{1}{256} (x+4)^2(x-2)^2(x)[/tex].

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Answer:

For 10 sections you would need 60 rails

The rule for posts is to multiply the section by 3

the rule for rails is to multiply the post by 2

This means that there is a 50% chance that the outcome of a trial will be 17.

The given table represents the frequency distribution of a discrete random variable X, which has four possible outcomes: 15, 16, 17, and 18. The frequency of each outcome indicates the number of times that outcome occurs in 16 trials.

To calculate the probability of a specific outcome, we divide its frequency by the total number of trials. In this case, we want to find P(X=17), which is the probability that the outcome of a trial is 17. From the table, we see that the frequency of X=17 is 8, which means that 17 occurred 8 times out of 16 trials. Therefore,

P(X=17) = frequency of X=17 / total number of trials = 8 / 16 = 0.5

This means that there is a 50% chance that the outcome of a trial will be 17.

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Full Question: The Following Table Is Based On 16 Trials. X 15 16 17 18 Frequency 2 4 8 2 Based On The Table, What Is P(X=17)? Leave Your Answer In Decimal Form To Three Places.

The following table is based on 16 trials.

x 15 16 17 18

frequency 2 4 8 2

Based on the table, what is P(x=17)?

Leave your answer in decimal form to three places.

The probability that Anne could pass both mathematics and English courses is 0.19 or 19%.

To find the probability that Anne could pass both mathematics and English, we can use the formula for the probability of the union of two events: P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where A is the event of passing mathematics, B is the event of passing English, and A ∩ B is the event of passing both courses.
We are given:
P(A) = probability of passing mathematics = 0.42
P(B) = probability of passing English = 0.47
P(A ∪ B) = probability of passing at least one course = 0.7

Now we need to find the probability of passing both courses, P(A ∩ B).
Using the formula, we have:
0.7 = 0.42 + 0.47 - P(A ∩ B)
To find P(A ∩ B), we rearrange the equation:
P(A ∩ B) = 0.42 + 0.47 - 0.7
Now, calculate the probability:
P(A ∩ B) = 0.19
So, the probability that Anne is 0.19 or 19%.

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By compound interest, The initial amount in the account is $300.

What does compound interest mean ?

When you earn interest on your interest earnings as well as the money you have saved, this is known as compound interest. As an illustration, if you put $1,000 in an account that offers 1% yearly interest, you will receive $10 in interest after a year.

                             Compound interest allows you to earn 1 percent on $1,010 in Year Two, which equates to $10.10 in interest payments for the year. This is possible because interest is added to the principle in Year Two.

A = 300(1.035)t

As we know the formula "Compound Interest" :

A = P(1 + r/100)t

So, According to our question,

Rate of interest = 0.35 = 135%

So, equate the both the equations , we get that

Hence, The initial amount in the account = $300

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the series converges for x in the interval: (-1/6, 1/6)

The series ∑(6)^nx^n converges if |x| < 1/6. This can be determined using the ratio test, where we take the limit as n approaches infinity of the absolute value of the ratio of the (n+1)th term to the nth term:

|6(x^(n+1))/(x^n)| = 6|x|

As n approaches infinity, this limit is less than 1 if and only if |x| < 1/6. Therefore, the series converges for all x in the open interval (-1/6, 1/6).

In interval notation, we can write the answer as: (-1/6, 1/6).
The given series is:

∑(6^n)(x^n)

This is a geometric series with a common ratio of 6x. For a geometric series to converge, the absolute value of the common ratio must be less than 1:

|6x| < 1

To find the values of x for which the series converges, we can solve for x in the inequality:

-1 < 6x < 1

Divide by 6:

-1/6 < x < 1/6

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Answer:

k = -3.

Step-by-step explanation:

To answer this question, we need to use our own knowledge and information. Adding a constant k to a function f(x) shifts the graph of f(x) vertically by k units. If k is positive, the graph moves up. If k is negative, the graph moves down. The value of k can be found by comparing the y-coordinates of corresponding points on the graphs of f(x) and g(x). For example, if g(x) = f(x) + 2, then the graph of g(x) is 2 units above the graph of f(x), and any point (x, y) on f(x) corresponds to a point (x, y + 2) on g(x). Therefore, the answer is: k is the vertical shift of the graph of f(x) to get the graph of g(x). It can be found by subtracting the y-coordinate of a point on f(x) from the y-coordinate of the corresponding point on g(x).

Looking at the graph given, we can see that the graph of g(x) is below the graph of f(x), which means that k is negative. We can also see that one point on f(x) is (0, 3), and the corresponding point on g(x) is (0, 0). Using the formula above, we get:

k = y_g - y_f

k = 0 - 3

k = -3

Therefore, the correct option is k = -3.

The expression that is equivalent to −0.75(60–32n)–n is A. −45+23n.

A mathematical or algebraic expression is the combination of variables with numbers, constants, and values using algebraic operands, including addition, multiplication, subtraction, and division.

Mathematical expressions do not bear the equal symbol (+) unlike equations.

−0.75(60–32n)–n

Expanding:

-45 + 24n - n

Simplifying:

−45 + 23n

Thus, the equivalent expression is Option A.

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The volume of the china cabinet is 21 cubic feet.

To find the volume of the china cabinet, we need to multiply its length, width, and height.

Since the dimensions are given in feet, we will use cubic feet as the unit of volume.

The length of the china cabinet is given as 1 ft, the width as 7 ft, and the height as 3 ft.

The volume can be calculated as follows:

Volume = length * width * height

Volume = 1 ft * 7 ft * 3 ft

Volume = 21 cubic feet

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Answer:

D. lines A and D are perpendicular

Answer:

[tex]y=log_{9} (x)[/tex]   (the middle choice)

Step-by-step explanation:

Key Concepts

Concept 1. Exponential vs logarithm

Concept 2. Logarithm rules

Concept 1. Exponential vs logarithm

The first two choices are logarithmic functions whereas the last function is an exponential function.  The graph cannot be that of an exponential function because exponential functions cannot cross the x-axis (an asymptote) unless a shift transformation is applied (which would look like adding or subtracting a constant number at the end of the equation.

A second way to verify is to simply input 2 into the function.  The number 2 raised to the 9 power is 2*2*2*2*2*2*2*2*2=512, but the graph clearly does not have a height of 512 when the input is 2.  Therefore, the correct answer cannot be the last choice.

Concept 2. Logarithm rules

One important rule for logarithms is that a number input into logarithm that matches the base of the logarithm will yield 1 as a result.  In other words:

For all real numbers b, such that b is positive and not equal to 1, [tex]log_{b}(b)=1[/tex]

Observe that for the first option, this means that [tex]log_{\frac{1}{9}}(\frac{1}{9})=1[/tex].  However, for an input of 1/9, the output is still below the x-axis -- a negative output -- clearly not 1.

Observe that for the second option, this means that [tex]log_{9}(9)=1[/tex], and that for an input of 9, the output on the graph is at a height of 1.

Therefore, the correct function for this question must be the middle option.

577 square feet is the area of the painted part of the wall.

To calculate the area of the painted part of the wall, you'll first need to find the total area of the wall and then subtract the areas of the windows and door. Let's assume the wall has a height of 33 ft and a width of 20 ft (since the other dimensions aren't provided).

1. Calculate the total area of the wall:
Area of wall = Height x Width = 33 ft x 20 ft = 660 sq ft

2. Calculate the areas of the windows and door:
Window A = 6 ft x 5 ft = 30 sq ft
Window B = 3 ft x 4 ft = 12 sq ft
Window C = 9 sq ft (already provided)
Door D = 4 ft x 8 ft = 32 sq ft

3. Subtract the areas of the windows and door from the total wall area:
Painted area = Wall area - (Window A + Window B + Window C + Door D) = 660 sq ft - (30 sq ft + 12 sq ft + 9 sq ft + 32 sq ft) = 660 sq ft - 83 sq ft = 577 sq ft

The area of the painted part of the wall is 577 square feet.

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Part a): To find f(10)(a), we need to take the 10th derivative of the Taylor series of f(x) at x=a. Since the Taylor series is given by ¿ (-1)n (x-a)^(2n), we need to differentiate this series 10 times with respect to x. Each differentiation will give us a factor of (2n) or (2n-1) times the previous term, and the (-1)n factor will alternate between positive and negative values.

Starting with n=0, we get:

f(x) = ¿ (-1)^n (x-a)^(2n)
f'(x) = ¿ (-1)^n (2n)(x-a)^(2n-1)
f''(x) = ¿ (-1)^n (2n)(2n-1)(x-a)^(2n-2)
f'''(x) = ¿ (-1)^n (2n)(2n-1)(2n-2)(x-a)^(2n-3)
...

After 10 differentiations, we end up with:

f^(10)(x) = ¿ (-1)^n (2n)(2n-1)(2n-2)...(2n-8)(2n-9)(x-a)^(2n-10)

To evaluate this at x=a, we can replace all instances of (x-a) with 0, and we end up with:

f^(10)(a) = ¿ (-1)^n (2n)(2n-1)(2n-2)...(2n-8)(2n-9)(a-a)^(2n-10)
f^(10)(a) = ¿ (-1)^n (2n)(2n-1)(2n-2)...(2n-8)(2n-9)(0)
f^(10)(a) = 0

Therefore, f(10)(a) = 0.

Part b): To find f(11)(a), we need to differentiate the series from part a one more time. We start with the series:

f(x) = ¿ (-1)^n (x-a)^(2n)

and differentiate it 11 times:

f(x) = ¿ (-1)^n (x-a)^(2n)
f'(x) = ¿ (-1)^n (2n)(x-a)^(2n-1)
f''(x) = ¿ (-1)^n (2n)(2n-1)(x-a)^(2n-2)
f'''(x) = ¿ (-1)^n (2n)(2n-1)(2n-2)(x-a)^(2n-3)
...
f^(10)(x) = ¿ (-1)^n (2n)(2n-1)(2n-2)...(2n-8)(2n-9)(x-a)^(2n-10)

and then differentiate once more:

f^(11)(x) = ¿ (-1)^n (2n)(2n-1)(2n-2)...(2n-8)(2n-9)(2n-10)(x-a)^(2n-11)

To evaluate this at x=a, we can replace all instances of (x-a) with 0, and we end up with:

f^(11)(a) = ¿ (-1)^n (2n)(2n-1)(2n-2)...(2n-8)(2n-9)(2n-10)(a-a)^(2n-11)
f^(11)(a) = ¿ (-1)^n (2n)(2n-1)(2n-2)...(2n-8)(2n-9)(2n-10)(0)
f^(11)(a) = 0

Therefore, f(11)(a) = 0.

Given the Taylor series of function f(x):

f(x) = Σ(-1)^n * (x-a)^(2n) / (n+2), where the summation runs from n = 0 to infinity and is centered at x = a.

Part a) To find f(10)(a), we need to determine the 10th derivative of f(x) with respect to x, evaluated at x = a.

Notice that only even terms contribute to the derivatives. The 10th derivative of the Taylor series will have n = 5 (since 2*5 = 10):

f(10)(a) = (-1)^5 * (a-a)^(2*5) / (5+2) = (-1)^5 * 0^10 / 7 = 0

Part b) To find f(11)(a), we need to determine the 11th derivative of f(x) with respect to x, evaluated at x = a. However, the given Taylor series only contains even powers of (x-a), and taking odd derivatives will result in terms with odd powers. Therefore, all odd derivatives, including the 11th derivative, will be 0:

f(11)(a) = 0

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The old coordinates are;

W (3, 14)

Y (12, 14)

X (6, 11)

While the new coordinates for the reflected triangle are:

W'' (3, -14)

X'' (6, -11)

Y'' (12, -14).

See the attached image.

A reflection is referred to as a flip in geometry. A reflection is the shape's mirror image. The line of reflection is formed when an image reflects through a line.

A figure is said to mirror another figure when every point in one figure is equidistant from every point in another figure.

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The problem is asking for the probability of construction given that Max had to stop for a passing train on his route to work. This can be solved using Bayes' theorem, which states that the probability of A given B is equal to the probability of B given A multiplied by the probability of A, divided by the probability of B.

In this case, let A be the event that there is construction on Max's route, and let B be the event that Max has to stop for a passing train. We are looking for the probability of A given B.

Using Bayes' theorem, we have:

P(A|B) = P(B|A) * P(A) / P(B)

We know that P(B) = 0.5, the probability that Max has to stop for a passing train. We also know that P(B|A) = 0.4, the probability that there is construction and Max has to stop for a passing train.

To find P(A), the probability of construction on Max's route, we need to use the complement of the event A, which is the probability that there is no construction:

P(not A) = 1 - P(A) = 1 - 0.4 = 0.6

Finally, we can plug in the values and solve for P(A|B):

P(A|B) = 0.4 * 0.4 / 0.5 = 0.32

Therefore, the probability that there was construction if Max had to stop for a passing train on his route to work is 0.32 or 32%.

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The probability of at least 33 male lambs is approximately 74.2%, which rounds to 25.9%  to the nearest tenth of a percent.

To solve this problem, we can use the binomial distribution formula:

P(X≥33) = 1 - P(X<33)

where X is the number of male lambs born out of 60, and P(X<33) is the probability that less than 33 male lambs are born.

The probability of getting a male lamb is 0.5, assuming that males and females are equally probable. So, the probability of getting exactly x male lambs out of 60 is:

P(X=x) = (60 choose x) * 0.5^60

where (60 choose x) is the number of ways to choose x items out of 60, which is calculated by the binomial coefficient formula:

(60 choose x) = 60! / (x! * (60-x)!)

Using a binomial distribution calculator or a spreadsheet program like Excel, we can find the probability of getting less than 33 male lambs:

P(X<33) = sum(P(X=x), x=0 to 32) ≈ 0.0459

Therefore, the probability of getting at least 33 male lambs is:

P(X≥33) = 1 - P(X<33) ≈ 1 - 0.0459 ≈ 0.9541

To convert this to a percentage, we can multiply by 100 and round to the nearest tenth:

P(X≥33) ≈ 95.4%

So, the answer is not one of the options given. The closest option is D) 25.9%, which is the probability of getting exactly 30 male lambs.

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Daniel will earn $54,271.35 in 4 years if a job pays him $42,000 a year and a 6.5% of increment in salary every year.

Salary = $42,000 a year

Increment per year =  6. 5%

Time period (n) = 4 years

To calculate the total earnings of Daniel in 4 years is:

Earnings after n years = Initial salary * (1 + yearly pay increase rate) ^ n

Substituting the above values, we get:

Earnings after 4 years =[tex]$42,000 * (1 + 0.065)^4[/tex]

Earnings  = $42,000 * 1.29503225

Earnings  = $54,271.35

Therefore, we can conclude that Daniel will earn $54,271.35 in 4 years at an increment of 6.5% per year.

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The height of tank which is 65 cm wide and 85 cm long is 40 cm and when it is 3/4 filled the water height is 30cm.

Mika can follow these steps to find the height of the water:

1. Convert the volume from liters to cubic centimeters: 221 L * 1000 cm³/L = 221,000 cm³
2. Calculate the total volume of the tank: V = lwh (where V is the volume, l is the length, w is the width, and h is the height)
3. Solve for the height of the tank: 221,000 cm³ = 65 cm * 85 cm * h
4. Calculate the height of the tank: h = 221,000 cm³ / (65 cm * 85 cm) ≈ 40 cm
5. Since Mika plans to fill the tank 3/4 full, calculate the height of the water: (3/4) * 40 cm = 30 cm

So, the correct steps are:

- Divide the volume by the length and width to find the height
- Calculate the total volume of the tank
- Find the height of the tank
- Calculate the height of the tank
- Calculate the height of the water when the tank is 3/4 full

The height of the water will be 30 cm.

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The substitution u = 3x transforms the integral 31 de into: ∫(3/31)du

This is because the substitution u = 3x implies that du/dx = 3, which means dx = (1/3)du. Substituting this expression for dx in the original integral and using the fact that e is a constant, we have:

∫e^(3x) dx = ∫e^(u) (1/3)du = (1/3)∫e^(u)du = (1/3)e^u + C

where C is the constant of integration. So the final answer in terms of x is:

(1/3)e^(3x) + C

which is equivalent to the original integral. This is an example of how the technique of substitution can be used to simplify an integral and make it easier to solve. It is also a common step in many integral transforms.

When performing an integral with substitution, you transform the original integral into a new one with a different variable. In your case, the substitution is given as u = 3x.

To apply substitution, first find the derivative of the substitution equation with respect to x, which is du/dx = 3. Then, solve for dx: dx = du/3.

Now, substitute u = 3x into the original integral and replace dx with du/3. The transformed integral will have the new variable u and a constant factor 1/3.

Without knowing the specific function you're trying to integrate (it seems like "31 de" might be a typo), I cannot provide the exact transformed integral.

However, I hope this explanation of substitution and transforming integrals is helpful. Please feel free to provide more information or clarify your question if you need further assistance!

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If 16 of his cards are baseball cards, 21 are football cards and 13 are basketball cards, the possible outcome is (10, 10, 5). So, correct option is B.

One possible method to approach this problem is to first find the total number of trading cards Royce has in his collection, which is the sum of baseball cards, football cards, and basketball cards:

Total number of cards = 16 + 21 + 13 = 50

Then, we can find half of the total number of cards, which is the number of cards Royce gives to his friend:

Half of total number of cards = 1/2 x 50 = 25

To find possible outcomes of this selection, we can start by considering how many baseball cards Royce can give to his friend. Since he has 16 baseball cards in total, he can give any number of them from 0 to 16, but he cannot give more than 25 cards in total.

Similarly, he can give any number of football cards from 0 to 21 and any number of basketball cards from 0 to 13.

Therefore, possible outcomes of this selection can be represented by the set of triples (x, y, z) where x is the number of baseball cards, y is the number of football cards, and z is the number of basketball cards, such that x + y + z = 25 and 0 ≤ x ≤ 16, 0 ≤ y ≤ 21, and 0 ≤ z ≤ 13.

The possible outcome is (10, 10, 5), which means Royce gives 10 baseball cards, 10 football cards, and 5 basketball cards to his friend.

So, correct option is B.

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Complete question is:

Royce has a collection of trading cards. 16 of his cards are baseball cards, 21 are football cards and 13 are basketball cards. He chooses half of this collection and gives them to his friend. Which of the following represent possible outcomes of this selection?

A) (10.20,20)

B) (10, 10, 5)

C) (20, 10, 5)

D) (10, 10, 25)

Answer: 7.1

Step-by-step explanation:

Use pythagorean again.

c²=b²+a²      

c=distance

a= distance in x direction = 7

b= distance in y direction =1

plug it in

d²=7²+1²

d²=49+1

d²=50

d=√50    put in calculator

d=7.1

The partial derivative using implicit differentiation is:

[tex]dz/dy = (-7x * e^(7xy) * (dx/dy) - 4) / (5x * cos(5xz))[/tex]

To calculate the partial derivative of the given equation with respect to y (dz/dy), we'll use implicit differentiation. The given equation is:

[tex]e^(7xy) + sin(5xz) + 4y = 0[/tex]

First, differentiate both sides of the equation with respect to y:

[tex]d(e^(7xy))/dy + d(sin(5xz))/dy + d(4y)/dy = 0[/tex]

Apply the chain rule for the first and second terms:

[tex](7x * e^(7xy)) * (dx/dy) + (5x * cos(5xz)) * (dz/dy) + 4 = 0[/tex]
Now, we are interested in finding dz/dy. To solve for it, rearrange the equation:

[tex](5x * cos(5xz)) * (dz/dy) = -7x * e^(7xy) * (dx/dy) - 4Finally, divide by (5x * cos(5xz)) to isolate dz/dy:dz/dy = (-7x * e^(7xy) * (dx/dy) - 4) / (5x * cos(5xz))[/tex]

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Yes, all three triangles RQS, QSR, and PRS are similar to triangle PQR.

Congruency of triangles refers to the condition in which two or more triangles have the same size and shape. In other words, if two or more triangles have congruent sides and angles, then they are said to be congruent.

The criteria for determining the congruency of triangles are based on the properties of sides and angles. There are various ways to show that two triangles are congruent, including the following:

Side-Side-Side (SSS) Congruence: If the three sides of one triangle are equal to the three sides of another triangle, then the two triangles are congruent.

Side-Angle-Side (SAS) Congruence: If two sides and the angle between them in one triangle are equal to two sides and the angle between them in another triangle, then the two triangles are congruent.

Angle-Side-Angle (ASA) Congruence: If two angles and the side between them in one triangle are equal to two angles and the side between them in another triangle, then the two triangles are congruent.

Angle-Angle-Side (AAS) Congruence: If two angles and a side not between them in one triangle are equal to two angles and the corresponding side not between them in another triangle, then the two triangles are congruent.

Hypotenuse-Leg (HL) Congruence: If the hypotenuse and one leg of a right triangle are equal to the hypotenuse and one leg of another right triangle, then the two triangles are congruent.

Yes, all three triangles RQS, QSR, and PRS are similar to triangle PQR.

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