B. It is a reflec
C. They are 6
D. They are 2
3. 6.RP.1.3
A dairy farmer uses two trucks to deliver
milk. The two trucks use different kinds of
fuel. Truck A uses gasoline and Truck B uses
diesel. The table below shows the distance,
in miles, that each truck can travel per
gallon of fuel. Based on the table, what is
the total number of gallons of diesel Truck B
will use to travel 132 miles?
Miles Traveled per Gallon of Fuel
5. 6.NS.3.7
A fish swims at an
A bird flies at an al
Which of the follo
Select all that apply
Gallons
of Fuel
1
2
Truck A Truck B
(Gasoline) (Diesel)
8 miles 12 miles
16 miles 24 miles
24 miles 36 miles
miles
A. The bird's a
fish's altitude.
OB. The bird's al
fish's altitude.
C. The fish is cl
bird.
D. The fish is fa
3
18 maila

Answer:

Step-by-step explanation:

Given

We need to subtract the 2nd polynomial from the 1st.

Answer:

[tex]\log_5 8^{M}[/tex]

Step-by-step explanation:

[tex]\text{We know that,}~ b\log_a c = \log_a c^b[/tex]

Answer:

I got f^-1 (x) = -7x + 21

Step-by-step explanation:

Answer:

Step-by-step explanation:

a whole number can be ANY counting number

10 to the 5th power =  × 10 × 10 × 10 × 10 × 10

when you multiply by any positive power of ten, you are making it really big

23 × 10 × 10 × 10 × 10 × 10 = 2,300,000

30 × 10 × 10 × 10 × 10 × 10 = 3,000,000

100 × 10 × 10 × 10 × 10 × 10 = 10,000,000

the pattern is the whole number followed by 5 zeros that show 5 place values

Answer:

Number of 7th grade = 360 - X

Step-by-step explanation:

As you can see this question is not complete and lacks the essential data. But we will try to create a mathematical expression to calculate the number of students on the A honor roll which are from &th grade. As we know: Total number of students on the A honor roll = 360 We are asked to calculate, number of students from 7th grade on the A honor roll. So, let's assume that "X" represents the all the students who are on the A honor roll except 7th grade. Mathematical Expression: Number of 7th Graders = Total number of students on the A honor roll - X Number of 7th Graders = 360 - X So, if you know the value of X, you can easily calculate the number of students which are from 7th grade on the A honor roll.

Answer:

There are 126 8th grade A honor roll students.

Step-by-step explanation:

Since there are 14 8th grade A honor roll students out of 40 A honor roll students. That means that the fraction is 14/40. After that we do 14/40x360 which results in 126.

Answer:

The total number of different suits consisting of a jacket, shirt, tie, and pants are possible is 576 ways and this can be determined by using the given data.

Given :

A men's department store sells 3 different suit jackets, 6 different shirts, 8 different ties, and 4 different pairs of pants.

The following steps can be used in order to determine the total number of different suits consisting of a jacket, shirt, tie, and pants are possible:

Step 1 - The arithmetic operations can be used in order to determine the total number of different suits consisting of a jacket, shirt, tie, and pants are possible.

Step 2 - According to the given data, the total number of shirts is 6, ties is 8, suit jackets is 3, and pants is 4.

Step 3 - So, the total number of different suits consisting of a jacket, shirt, tie, and pants are possible is:

= 576 ways

Step-by-step explanation:

Answer A: 45 5/16

B: The present of the area as 83%

Step-by-step explanation:

(a)

35= 3+3+3.2x+3.2x+3.2x+3.2x

35= 6 + 12.8

29/12.8 +12.8x/12.8

X=2.265625 = 2/12/64

1x = 2 17/64 * 4 + 9 1/16

P = 45 5/16

(b)

The present of the area as 83%

35 – the bases or 6 = 29

29/35 + 0.82857142857

0.82857142857 * 100 = 82.8571428571

Rounded to the nearest whole number is 83%

Answer:

Step-by-step explanation:

[tex]\sqrt{3}[/tex] =1.73205 In between 1 and 2 closer to 2

[tex]\sqrt{8}[/tex]=2.82842  In between 2 and 3 closer to 3

[tex]\sqrt{23}[/tex]=4.7958  In between 4 and 5 closer to 5

Answer:

How might the situation lead to bullying?

Step-by-step explanation:

How might the situation lead to bullying?

the answer B

In each solution, n is an arbitrary integer.

1. Nothing fancy, just take the inverse tangent.

tan(x) = -5

x = arctan(-5) + nπ

x = -arctan(5) + nπ

2. Recall the identity cos(2x) = 2 cos²(x) - 1, then factorize:

cos(2x) - 3 cos(x) + 2 = 0

(2 cos²(x) - 1) - 3 cos(x) + 2 = 0

2 cos²(x) - 3 cos(x) + 1 = 0

(2 cos(x) - 1) (cos(x) - 1) = 0

2 cos(x) - 1 = 0   or   cos(x) - 1 = 0

cos(x) = 1/2   or   cos(x) = 1

[x = arccos(1/2) + 2nπ   or   x = -arccos(1/2) + 2nπ]

…   or   x = arccos(1) + 2nπ

x = π/3 + 2nπ   or   x = -π/3 + 2nπ   or   x = 2nπ

3. By definition, csc(x) = 1/sin(x) :

csc(2x) + √2 = 0

csc(2x) = -√2

1/sin(2x) = -√2

sin(2x) = -1/√2

2x = arcsin(-1/√2) + 2nπ   or   2x = π - arcsin(-1/√2) + 2nπ

2x = -π/4 + 2nπ   or   2x = 5π/4 + 2nπ

x = -π/8 + nπ   or   x = 5π/8 + nπ

4. More factorization:

2 sin²(x) - sin(x) = 0

sin(x) (2 sin(x) - 1) = 0

sin(x) = 0   or   2 sin(x) - 1 = 0

sin(x) = 0   or   sin(x) = 1/2

x = arcsin(0) + 2nπ

…   or   [x = arcsin(1/2) + 2nπ   or   x = π - arcsin(1/2) + 2nπ]

x = 2nπ   or   x = π/6 + 2nπ   or   x = 5π/6 + 2nπ

5. Yet more factorization. Also recall that |cos(x)| ≤ 1 for all x.

4 cos²(x) - 8 cos(x) + 3 = 0

(2 cos(x) - 3) (2 cos(x) - 1) = 0

2 cos(x) - 3 = 0   or   2 cos(x) - 1 = 0

cos(x) = 3/2   or   cos(x) = 1/2

The first case gives no solution since 3/2 > 1.

x = arccos(1/2) + 2nπ   or   x = -arccos(1/2) + 2nπ

x = π/3 + 2nπ   or   x = -π/3 + 2nπ

6. Recall the identity sin(a - b) = sin(a) cos(b) - cos(a) sin(b).

sin(2x) cos(x) - cos(2x) sin(x) = -√3/2

sin(2x - x) = -√3/2

sin(x) = -√3/2

x = arcsin(-√3/2) + 2nπ   or   x = π - arcsin(-√3/2) + 2nπ

x = -π/3 + 2nπ   or   x = 4π/3 + 2nπ

Answer:

10 men can complete work l in 120 doy . In how many days does 30 me can complete it.

-

Hey there!

3x = 27
DIVIDE 3 to BOTH SIDES

3x/3 = 27/3

CANCEL: 3/3 because it give you 1

KEEP: 27/3 because it help solve for the x-value

NEW EQUATION: x = 27/3

SIMPLIFY IT!

x = 9

Good luck on assignment & enjoy your day!

~Amphitrite1040:)

Answer:

64

Step-by-step explanation:

y = x + 4

y - x = 4

4^3 = 64

Answer:

y=(x−3)2−2

Step-by-step explanation:

The vertex form of a quadratic function isy=x^2-6x+7 , where x, y, are constants. of the parabola is at (x, y).

Answer:

  $2418.07

Step-by-step explanation:

Problems involving the time-value of money are conveniently solved using a TVM app on a suitable calculator or spreadsheet. The result of doing that is shown in the attachment.

__

If you would like to compute the value of Emily's account by hand, the annuity formula is the one you want.

  A = Pn((1 +r/n)^(nt) -1)/r . . . . where r is the annual interest rate, n is the number of times per year it is compounded (12), t is the number of years (1/2), and P is the periodic payment into the acccount (400).

Using the given values in the formula, we have ...

  A = 400(12)((1 +0.036/12)^(12/2) -1)/0.036 = 4800×(1.003^6 -1)/0.036

  A ≈ 2418.07

At the end of 6 months, Emily will have saved $2418.07.

Answer:

[tex] {x} = - 4 \pm \: 2\sqrt{5} [/tex]

Step-by-step explanation:

[tex] {(x + 4)}^{2} - 4 = 16 \\ \\ \implies \: {(x + 4)}^{2} = 16 + 4 \\ \\ \implies \: {(x + 4)}^{2} = 20 \\ \\ \implies \: {(x + 4)} = \pm \: \sqrt{20} \\ \\ \implies \: {x + 4} = \pm \: 2\sqrt{5} \\ \\ \implies \: {x} = - 4 \pm \: 2\sqrt{5} [/tex]

Answer:

The point [tex](3,8)[/tex] will transform into [tex](7,9)[/tex]

Step-by-step explanation:

When you move the unit right, you make the number larger. right and left deal with the X value. you add 4 to 3, and you get 7. Now you move 1 point up, which is just 8+1, which is 9. You get your answer, [tex](7,9)[/tex].

Hope This Helps! :)

Answer:

[tex]x {}^{2} - 36 = 0 \\ \\ x {}^{2} = 36 \\ \\ x = \sqrt{36} \\ \\ x = + 36 \: \: or \: \: - 36[/tex]

hope helpful -,-

Answer:

2. Elana's Family. Elana's Family.

3. 8 minutes 4 seconds

4. Elena's family will have driven 2.76 miles while Andre's family will have driven which is farther.

Step-by-step explanation:

Answer:

Step-by-step explanation:

This is like volume!

Equation:

Solve:

Simplify:

Answer is 216 sq. ft³.

Answer:

2898

Step-by-step explanation:

number of people * number of pages in each book they read =total

mystery bookclub:

5 * 1,296 = 6480

fantasy bookclub:

9 * 398 = 3582

mystery - fantasy = difference in books between the two groups

6480 - 3582 = 2898

possible equation:

(1296 x 5) - (398 x 9) = x

x = answer

Answer:

Step-by-step explanation:

hey i got a couple (10) calculus questions in my profile and im pretty desperate right now

can u pls help

Answer:

I think it is 100

Answer:

Step-by-step explanation:

The answer is 50 ounces

Because 30% silver is right in between 20% silver and 40% silver, it would have to be the same amount to be 30%

180° hope it's correct and really helps....!!!!

Answer:

A) 64

Step-by-step explanation:

16/2=8

8^2= 64

x^2 +16x +64= 69

(x +8)^2= 69

Answer:

P1:40% P2:47500 P3:10%

Step-by-step explanation:

2/5 = 0.4 =40%

5/8= .625

.625 x 76000 =

47500

Shaded area = area of square - area of a circle.

[tex] \\ \\ [/tex]

For this we have to find area of both square and circle which is visible in the picture.

[tex] \\ [/tex]

Part one :

In this part we'll find area of circle.

Given :

To find :

Solution:

We know :

[tex] \boxed{ \rm Area \: of \: circle =\pi {r}^{2} }[/tex]

Steps :

[tex] \dashrightarrow\sf Area \: of \: circle =\pi {r}^{2}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf Area \: of \: circle = \dfrac{22}{7} \times {9}^{2} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf Area \: of \: circle = \dfrac{22}{7} \times 9 \times 9[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf Area \: of \: circle = \dfrac{22}{7} \times 81[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf Area \: of \: circle = \dfrac{22\times 81}{7}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf Area \: of \: circle = \dfrac{1782}{7}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\bf Area \: of \: circle =254.57 \: ft {}^{2} \\ [/tex]

[tex] \\ [/tex]

Part 2

As it's visible diameter of circle = side of square.

So we have to find diameter of circle.

We know :-

[tex] \boxed{ \rm Diameter \: of \: circle =2 \: radius}[/tex]

[tex] \\ [/tex]

Steps:-

[tex] \dashrightarrow\sf Diameter \: of \: circle =2 \: radius \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf Diameter \: of \: circle =2 \times 9\\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\bf Diameter \: of \: circle =18 \: ft[/tex]

We have :

To find:

Solution:

We know :

[tex] \boxed{ \rm Area \: of \: square= {side}^{2} }[/tex]

Steps :

[tex] \dashrightarrow\sf Area \: of \: square= {side}^{2}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf Area \: of \: square= {18}^{2}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf Area \: of \: square= {18} \times 18[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\bf Area \: of \: square= 324 \: {ft}^{2} [/tex]

Part three:

Remember the first line of answer ? :)

So let's insert here:-

[tex] \boxed{ \text{Shaded area = area of square - area of a circle}}[/tex]

Steps :-

[tex] \dashrightarrow\textsf{Shaded area = area of square - area of a circle} \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\textsf{Shaded area = 324 - 254.57} \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\textbf{Shaded area = 69.43 }\bf {ft}^{2} \\ [/tex]

Answer:

About 154 Square

Explanation:

To find an area of a circle you multiply pi by the radius squared so 7² = 49 and 49 x 3.14 = 153.86 which is the closest to 154.