distance of object = (½ baseline)/(tanθ/2)
= (½ × 1000)/(tan0.5")
= 500/0.000000242 km
distance of object = 206248306 km
Definition of parallax?
Particularly: the angular difference in direction of a celestial body as measured from two places on the earth's orbit. The apparent displacement or the difference in apparent direction of an object as seen from two separate points that are not on a straight line with the object
The apparent movement of objects when observed from various angles is referred to as "parallax." An illustration of this can be noticed while traveling on the highway; when you glance out the window, electricity poles close to the road seem to fly by, while distant trees seem to drift by slowly.
The angle here between Earth at one time of year and the Earth 6 months later, as measured from a nearby star, is defined as the parallax angle.
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who is Isacc.Newton??
Answer:
Sir Isaac Newton contributed significantly to the field of science over his lifetime. He invented calculus (opens in new tab) and provided a clear understanding of optics. But his most significant work had to do with forces, and specifically with the development of a universal law of gravitation and his laws of motion
Explanation:
A genius with dark secrets. Isaac Newton changed the way we understand the Universe. Revered in his own lifetime, he discovered the laws of gravity and motion and invented calculus. He helped to shape our rational world view.
Q|C The speed of a one-dimensional compressional wave traveling along a thin copper rod is 3.56 km/s . The rod is given a sharp hammer blow at one end. A listener at the far end of the rod hears the sound twice, transmitted through the metal and through air, with a time interval Δt between the two pulses.(d) Imagine that the copper rod is replaced by another material through which the speed of sound is v_r . What is the length of the rod in terms of t and v_r ?
The length of rod in terms v(r) and t is L = [ Δt / (1/343) - (1/v(r)) ].
3.56 km/s is the speed of a one-dimensional compressional wave moving along a thin copper rod.
At one end of the rod, a hard hammer strike is delivered. With a time interval of Δt between the two pulses, a listener at the other end of the rod hears the sound twice as it travels through the metal and the air.
The time interval is given by t = L/v.
We know, The speed of air, v(air) = 343 m/s
Now,
When the copper rod is swapped out for a different substance and the sound speed is measured as v(r).
The delay between pulses arrivals is:
Δt = L [(1/v(air)) - (1/v(copper))]
Then,
L = [ Δt / (1/v(air)) - (1/v(r)) ]
L = [ Δt / (1/343) - (1/v(r)) ]
Here L is the length of the rod, Δt is in seconds and v(r) is the speed of sound in the rod.
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What is the mass of a rocket 5,000m above the Moon’s surface if 84kJ
of gravitational potential energy is stored? Assume g on the Moon =
1.63N/kg.
Considering the definition of potential energy, the mass of a rocket 5,000 m above the Moon’s surface is 10.31 kg.
Potential energyPotential energy is the energy that measures the ability of a system to do work based on its position. In other words, this is the energy that a body located at a certain height above the ground has.
Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the strength of gravity. Then, the expression applied to the gravitational energy of the object is:
Ep= m×g×h
Where:
Ep is the potential energy in joules (J).m is the mass in kilograms (kg). h is the height in meters (m).g is the acceleration of the fall in m/s².Mass of the rocketIn this case, you know:
Ep= 84 kJ= 84,000 J (being 1 kJ= 1,000 J)m= ?h= 5,000 mg= 1.63 N/kg= 1.63 m/s²Replacing in the definition of gravitational potential energy:
84,000 J= m×1.63 m/s²×5,000 m
Solving:
84,000 J= m× 8,150 m/s²×m
84,000 J÷ (8,150 m/s²×m)= m
10.31 kg= m
Finally, the mass of a rocket 5,000 m above the Moon’s surface is 10.31 kg.
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Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it.
The value of the acceleration of the earth toward it when it accelerates toward the earth with 9.8m/s² is a = 7.35×10-²³m/s².
What is acceleration?Acceleration in theoretical terms refers to the derivative of the velocity function, it is the rate of change of this variable, and the physical magnitude of the motion that gives rise to the change of position.
What are forces?Forces are the definition of Newton's second law, which is stated under the relation:
∑ Force = mass × acceleration.
In other words, force is the origin of motion since it generates acceleration in a system.
In this case we must complete the statement:
"A student with mass 45 kg jumps off a high diving board. Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it."
We determine the Force of the student:
F = ma
F = 45kg * 9.8m/s².
F = 441N
Now we go to the acceleration of the earth:
a = F/m
a = 441N / 6×10²⁴ Kg
a = 7.35×10-²³m/s².
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An amusement park designer wants his swing to have a centripetal
acceleration of 21 m/s2. If the velocity of the swing is 13 m/s, how long
should the chain on the swing be?
The chain on the swing should be 8.0 m long .
Centripetal Acceleration ( a ) = v ² / r ........... Eq. 1
It is given that ,
a = 21 m / s ²
v = 13 m / s
Now , using the values of ' a ' and ' v ' i.e. 21 m / s ² & 13 m / s respectively in Eq. 1
a = v ² / r
21 = ( 13 ) ² / r
21 = ( 13 x 13 ) / r
r = ( 13 x 13 ) / 21
r = 8.047 m
⇒ r = 8.0 m ( rounded off to nearest tenth )
Hence , the chain on the swing should be 8.0 m long .
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A 100kg box is on an incline of 60 degrees. What is the perpendicular force
Answer:
490N
Explanation:
the formula to use for perpendicular force is:
[tex]Fg=mg(cos\theta)[/tex]now we plug in:
*for g, it can be 9.8 m/s^2 or 10 m/s^2 depending on your teacher
[tex]Fg=(100)(9.8)(cos60)[/tex]
then you get:
[tex]Fg=490N[/tex]
Which two types of potential energies would be types of mechanical energies?
electrical and kinetic
nuclear and chemical
radiant and thermal
elastic and gravitational
The two types of potential energies which would be types of mechanical energies are elastic and gravitational.
The correct answer choice is option D
What is meant by potential energy?Potential energy means the energy a body possess in relation to its position. Other forms of energy include
Electrical energyKinetic energyChemical energySound energyNuclear energy Thermal energy Radiant energyKinetic energy is the energy a body possesses due to its motion.
So therefore, the two types of potential energies which would be types of mechanical energies are elastic and gravitational. The correct answer choice is option D
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Answer: it is d
Explanation: i took the unit test on edge
if you run off the pavement, you should: steer straight ahead and speed up steer straight and slow down before attempting to return to the pavement turn the steering wheel quickly toward the road apply the brakes hard submit answer
If you run off the pavement, you should turn the steering wheel quickly toward the road and is denoted as option C.
What is Pavement?This is a path which is found in almost all roads and is designed to enhance foot traffic in most climes. This is the path where individuals walk so as not to get hit down by a vehicle.
In a situation where a car runs into the pavement, the best choice is to turn the steering wheel quickly toward the road as braking hard could damage the brakes of the car and cause accident in subsequent trips.
This is therefore why option C was chosen as the correct choice.
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Answer: Steer straight and slow down before attempting
Explanation:
a rocket was launched into the air from a podium 6 feet off the ground. the rocket path is represented by the equation h(t)
The average rate of change of height from the initial launch to the maximum height is 180 feet.
The given function is
[tex]h(t) = -16t^{2} +120t+6[/tex]
The average rate of change of h(t) from t=a to t=b is given by:
[tex]\frac{h(b)-h(a)}{b-a}[/tex]
Vertical Velocity will be zero at maximum height. To find maximum height we differentiate the equation to get an equation for the velocity and set it to zero.
On differentiating we get,
h'(t) = -16(2)t + 120
h'(t) = -32t + 120
now equating to zero we get
t = 3.75 s
This is the time at which the rocket reaches maximum height.
The initial launch occurs at t = 0
substituting it in the original equation we get
[tex]h(t)[/tex] = [tex]-16(0)^{2}+120(0)+6[/tex]
[tex]h(t) = 6[/tex]
The average rate of change from the initial launch to the maximum height is:
[tex]\frac{h(3.75)-h(0)}{3.75-0}[/tex]
= [tex]\frac{681-6}{3.75}[/tex]
= 180
Hence the average rate of change from the initial launch to the maximum height is 180 feet.
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What is inertia and how does it relate to Newton's first law of motion?
Answer:
inertia is basically the fact that something will continue moving until something else stops it. take friction for example. If you roll a ball on the ground, it will eventually stop because of friction, you can kind of think of it like a gear wheel. and i guess it relates to newtons first law of motion because it is his first law?? i don't know how to answer that
Explanation:
10 pts the classic millikan oil drop experiment was the first to obtain an accurate measurement of the charge on an electron. in it, oil drops were suspended against the gravitational force by a vertical electric field. consider an oil drop with a weight of 1.2 x 10-14n, if the drop has a single excess electron, find the magnitude (in n/c) of the electric field needed to balance its weight. your should round your answer to an integer, indicate only the number, do not include the unit.
the magnitude of the electric field needed to balance its weight is
0.75 ×10⁵N/C
The oil drop method was performed by Robert A Millikan in 1909.
It is used to determine the size of the charge on an atom.
Millikan used vacuum pump oil for this his experiment.
to find out the magnitude of electric field
W = q E,
W = weight (W = mg)
q = charge (1.6×10⁻¹⁴C)
E = Electric field
→ oil drops were suspended against the gravitational force by a vertical electric field such that its weight is balanced by the electron force i.e.
W = 1.2× 10⁻¹⁴
1.2× 10⁻¹⁴ = q × E
E = 1.2× 10⁻¹⁴N/ 1.6×10⁻¹⁹C
E = 0.75 ×10⁵N/C
the magnitude of the electric field needed to balance its weight is
0.75 ×10⁵N/C
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Positively charged particles of radiation emitted from the decay of radioactive substances are known as.
Positively charged particles of radiation emitted from the decay of radioactive substances are known as alpha particles.
What is an alpha particle?A helium nucleus that some radioactive compounds release that was once thought to be a ray. Ionized alpha particles are made up of two protons, neutrons ( no charge), and no electrons.
Two protons and two neutrons from the atom's nucleus combine to form the positive charge alpha particles (α). The most toxic radioactive materials, such as uranium, radium, and polonium, decay to produce alpha particles.
A ray-like emission of a helium nucleus from some radioactive materials.
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three scientists measure the standard meter bar kept at the international bureau of standards (the definition of a meter). their measurements are 1.01 m, 0.99 m, and 1.00 m. are their measurements accurate, precise, or both? group of answer choices accurate but not precise neither accurate nor precise precise by not accurate accurate and precise
The measurements by the different scientists were 1.01 m, 0.99 m and 1.00 m, which are not exactly same as the standard value of a meter. But all the three values are very much close to each other.
Meter is a fundamental unit of length in the metric system and in the International Systems of Units (SI). It is denoted by m.
Therefore the measurements for the bar kept at the international bureau of standards taken by the three scientists were precise but not accurate.
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Review. For a certain type of steel, stress is always proportional to strain with Young's modulus 20 × 10¹⁰ N/m² . The steel has density 7.86× 10³kg / m³. It will fail by bending permanently if subjected to compressive stress greater than its yield strength бy = 400MPa. A .rod 80.0cm long, made
of this steel, is fired at 12.0 m/s straight at a very hard wall.(b) After the front end of the rod hits the wall and stops, the back end of the rod keeps moving as described by Newton's first law until it is stopped by excess pressure in a sound wave moving back through the rod. What time interval elapses before the back end of the rod receives the message that it should stop?
[tex]1.58\times 10^{-4}\ \mathrm{s}$[/tex] is the time interval elapses before the back end of the rod receives the message that it should stop.
Given:
Length of the rod, L = 80 cm = 0.800 m
Young's modulus, Y = [tex]20 \times 10^{10}\;N/m^{2}[/tex]
steel density, [tex]\rho = 7.86 \times 10^{3}\;kg/m^{3}[/tex]
The speed of the wave in the rod is,
[tex]$v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$[/tex]
Consequently, the length of the rod's end is traveled by the wave in at
[tex]$t=\frac{L}{v} = \frac{0.800\ \mathrm{m}}{5044\ \mathrm{m/s}} = 1.58\times 10^{-4}\ \mathrm{s}$[/tex]
Hence, [tex]1.58\times 10^{-4}\ \mathrm{s}$[/tex] is the time interval elapses before the back end of the rod receives the message that it should stop.
What are Newtons Laws?The three fundamental laws of classical mechanics known as Newton's laws of motion describe how an object's motion and the forces acting on it interact. The following paraphrase of these statutes is available
Unless a force acts upon a body, it remains at rest or in continual straight-line motion.
When a force acts on a body, the force is equal to the time rate at which the body's momentum changes.
When two bodies exert force on one another, the direction and amount of the force are opposed.
Isaac Newton first identified the three laws of motion in his 1687 book Philosophize Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy).
They served as the cornerstone for classical mechanics as Newton used them to examine and explain the motion of numerous physical objects and systems. The conceptual foundations of classical physics have been reconstructed in several ways since Newton, utilizing various mathematical techniques that have revealed insights that were hidden in the original, Newtonian formulation.
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The furniture was designed to go a top speed of 87.0mph. How far would this sofa travel to the mall 1.00 hour away?
The sofa with a top speed of 87 mph would travel a distance of 43.5 miles to the mall 1 hour away.
Considering the sofa accelerates constantly throughout the motion,
s = ( u + v ) t / 2
s = Distance
u = Initial velocity
v = Final velocity
t = Time
v = 87 mph
t = 1 hr
u = 0
s = ( u + v ) t / 2
s = ( 0 + 87 ) 1 / 2
s = 43.5 mi
This is an equation of motion.
Therefore, the sofa would travel a distance of 43.5 miles
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A wire 2.80m in length carries a current of 5.00A in a region where a uniform magnetic field has a magnitude of 0.390T. Calculate the magnitude of the magnetic force on the wire assuming the angle between the magnetic field and the current is (b) 90.0° .
The force on the wire will be
F = 5.46 Newton.
We have a current carrying wire in a uniform magnetic field.
We have to determine the magnitude of the magnetic force on the wire assuming the angle between the magnetic field and the current is 60.0°.
What is the magnitude of force acting on a current (I) carrying wire of length (L) placed in a Magnetic field (B)?The force on the current carrying wire will be -
F = IBL sinθ
According to the question, we have -
L = 2.80 m
I = 5 A
B = 0.39 T
Therefore -
F = IBL sinθ
F = 5 x 0.39 x 2.80 x sin(90)
F = 5.46 x sin(90)
F = 5.46 Newton
Hence, the force on the wire will be
F = 5.46 Newton
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The magnitude of the magnetic force on the wire 5.46 N.
To find the magnetic force, the values given are:
Length A = 2.80m
Current I = 5 A
Magnetic field B = 0.390 T
Angle = 90° .
What is meant by magnetic force?
The attraction or repulsion that arises between electrically charged particles because of their motion is called Magnetic force.Magnetic force is the basic force which is responsible for such effects as the action of electric motors and the attraction of magnets.A force experienced through the magnetic field with some moving charges is perpendicular to its own velocity.The formula to find the magnetic force,F =iBLsinθ Newton
Substituting the values given,
Magnetic force,
F = 5 A × 0.390 T × 2.80 m × Sin 90°
= 5 A × 0.390 T × 2.80 m × 1
F = 5.46 N.
The magnitude of the magnetic force on the wire 5.46 N.
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Pressure is a derived quantity with a formula suxh as Force per unit area what do you think which base quantities will be involved to form this derived quantity.
Answer:
you can find answer in this
Explanation:
https://physics.nist.gov/cuu/Units/units.html
Owen and Dina are at rest in frame S' , which is moving at 0.600 c with respect to frame S . They play a game of catch while Ed , at rest in frame S , watches the action (Fig. P39.75). Owen throws the ball to Dina at 0.800 c (according to Owen), and their separation (measured in S' ) is equal to 1.80 × 10¹²m .(a) According to Dina, how fast is the ball moving?
The speed of the ball with respect to Dina is 0.800c.
A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.
If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.
In frame S', Dina and Owen are at rest.
The speed of the ball with respect to Owen, u =0.800c
The speed of the frame S' with respect to frame S, v = 0.600c
Distance between Dina and Owen, L(p) = 1.8 × 10¹² m
Speed of light, c = 3 × 10⁸ m/s
Therefore, the speed of the ball according to Dina is 0.800c. As Dina and Owen are in the same frame.
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an object of mass m is traveling at constant speed v in a circular path of radius r. how much work is done by the centripetal force on mass m during an angular displacement of 2π revolutions?: *
The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J
Centripetal force - a force acts on an moving object in circular path.
the centripetal force is given by
F= mv²/r (equation1)
Work done is given by
W = Fd (equation 2)
d = 2π
work is done by the centripetal force on mass m during an angular displacement of 2π revolutions is given by:
to calculate work done using equation 1 in 2 we get
W = mv² d/r
W = mv² × 2π /r J
The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J
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Which question would best determine how electromagnetic and mechanical waves are similar?
The question 'How do electromagnetic and mechanical waves compare?'
There are many similarities between electromagnetic waves and mechanical waves.
In Physics, both electromagnetic and mechanical waves have amplitude, wavelength, and frequency.
Electromagnetic waves can travel through empty spaces as well such as vacuums, gases, liquids, and solids.
While mechanical waves can not propagate through space they can only travel through liquids, solids, and gases.
water waves and ripples in a pool are examples of mechanical waves.
Examples of EM waves are radio signals and light waves, microwaves, and X-rays.
To put it simply, EM waves do not require a medium to travel whereas mechanical waves require a medium to propagate.
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One pole of a magnet attracts a nail. Will the other pole of the magnet attract the nail? Explain. Also explain how a magnet sticks to a refrigerator door.
Yes, either pole generates a field that causes atoms within the iron to rotate in order to align their magnetic moments with the exterior field.
A magnet has a significant normal force acting on the door. The magnet is then held in place by frictional force.
What is a magnet?A magnet is defined as a magnetic field-producing item capable of attracting unlike poles and repelling similar poles.
Magnets are manufactured from a class of metals known as ferromagnetic metals. These metals include nickel and iron. These metals are unusual in their ability to magnetize consistently. When we ask how a magnet works, we mean how the magnetic field of a magnet affects the thing.
There are many different sizes and shapes of magnets.
Magnets can be found in a variety of objects and settings, including toys, cabinet hardware, ornamental pieces placed on refrigerators, and other objects and sites.
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13. Two identical metallic spheres A and B, each carry- ing a charge q, repel each other with a force F. A third metallic sphere C of the same size, but un- charged, is successively made to touch the spheres A and B, and then removed away. What is the force of repulsion between A and B? (Ans. 3F/8) 4.
Answer:
Who knows the answer please I need the answer
when driving downhill, gravity will cause you to go slower and decrease your stopping distance. a. true b. false
False.While driving downhill, the gravity will cause you to go faster and increase your stopping distance.
What is stopping distance?Brakes are suddenly applied while the body is travelling at a given speed. You would have observed that after travelling a given distance, the body stops entirely. The stopping distance is that distance.
The distance travelled between the moment the body decides to stop a moving vehicle and the moment the vehicle comes to a complete stop is known as the stopping distance. The stopping distance, indicated by the letter d, is dependent on a number of variables, including as the road's surface and the driver's reflexes.
Stopping Distance formula is given by,
[tex]d=\frac{v^{2} }{2ug}[/tex]
Where,
d = stopping distance (m)
v = velocity (m/s)
μ = friction coefficient
g = the gravitational acceleration
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Help please ;((((((((
Answer:
42- electromagnetic force
Explanation:
electrons keep orbiting around the nucleus thanks to electromagnetic force :)
hope this helped!
a total charge of 300 c flows past a given cross section of a conductor in 30 seconds. what is the value of the current?
Explanation:
Q = charge in C(coulombs)
I = current in A(amps)
t = time in s(seconds)
Q = I × t
I = Q / t
Substitute in given values.
I = 300C / 30s
= 10A
Hope this helped! ^^
The electric current generated by a charge of 300 coulombs passing through the cross section of a conductor in a time of 30 seconds is: 10 A
To solve this exercise the formula for electric current and the procedure we will use is:
I= q/t
Where:
I = intensity of the electric currentq= electric charget = timeInformation about the problem:
q= 300 Ct = 30 sI=?1 C/s = 1 AApplying the electric current intensity formula we have:
I= q/t
I= 300 C / 30 s
I= 10 A
What is electric current intensity?In physics the intensity of the electric current is the magnitude that expresses the amount of electric charge or electric current in coulomb (c) that passes through an electrical conductor in a given time in seconds (s). Its unit of measurement in the international system is the Ampere (A).
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Answer please with working out
Answer:
(1) a) S=D/T
b)5m/s
c)3.33s
(2) a) 1.104m
Explanation:
(1) b) S=D/T
S=1500/300
S=5m/s
c) T= V-U/a
v=10
u= 2
a= 2.4
10-2=8/2.4=3.33s
(2) a) d=s×t
0.46×2.4=1.104m
A 2 kg block of cheese is in an elevator accelerating down at a rate of 1.5 m/s².
What is the normal force on the cheese?
A tank for compressed gas has a maximum safe pressure limit of 850 kPa. The pressure
gauge reads 425 kPa when the temperature is 28°C. What is the highest temp in degrees
Celsius the tank can withstand safely?
Rank the wavelengths of the following quantum particles from the largest to the smallest. If any have equal wavelengths, display the equality in your ranking. (a) a photon with energy 3eV(b) an electron with kinetic energy 3eV(c) a proton with kinetic energy 3eV(d) a photon with energy 0.3eV(e) an electron with momentum 3eV/c
The wavelengths of the following quantum particles from the largest to the smallest is (d) > (a) = (e) > (b) > (c)
De Broglie proposed that because light has both wave and particle properties, matter exhibits both wave and particle properties. This property has been explained as the dual behavior of matter. From his observations, de Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship.De Broglie's relationship is given by [tex]\lambda=\frac{h}{mv}[/tex] .
This can be written as [tex]\lambda=\frac{h}{p}[/tex] .....(1) where λ is known as de Broglie wavelength and p is momentum , h = Plank’s constant .
As we know that mass of proton is greater than electron and photon .
(a)For photon , the momentum is given by [tex]p=\frac{E}{c}[/tex] ...(2) where c is the speed is the speed of light .
Putting E = 3eV in equation (2) , we get
[tex]p=\frac{3\times 1.6\times10^-^1^9}{3\times 10^8} \\p=1.6\times10^-^2^7Js/m[/tex]
Putting this value of p in equation (1) , we get
[tex]\lambda=\frac{6.62\times10^{-34}}{1.6\times10^{-27}}\\\lambda=4.13\times10^{-7}[/tex]
(b) As we know that kinetic energy is given by
[tex]K.E=\frac{1}{2} mv^2\\\\2K.E = mv^2\\2K.E\times m = m^2v^2\\2K.E\times m = (mv)^2\\2K.E\times m = p^2\\\\\sqrt{2K.E\times m }=p[/tex] ...(3)
Where mass of electron is [tex]9.1\times10^-^3^1 kg[/tex] .
Putting K.E = 3eV in equation (3) , we get
[tex]\sqrt{2K.E\times m }=p\\p=\sqrt{2\times3\times1.6\times10^{-19} \times 9.31\times10^{-31} }\\p=\sqrt{89.376\times10^{-50}} \\p=9.45\times10^{-25}Js/m[/tex]
Putting this value of p in equation (1) , we get
[tex]\lambda=\frac{6.62\times10^{-34}}{9.45\times10^{-25}}\\\lambda=0.7005\times10^{-9}[/tex]
(c) Putting [tex]m=1.67\times10^{-27}kg[/tex] and K.E = 3eV in equation (3) , we get
[tex]\sqrt{2K.E\times m }=p\\p=\sqrt{2\times3\times1.6\times10^{-19} \times 1.67\times10^{-27} }\\p=\sqrt{16.032\times10^{-46}} \\p=4.003\times10^{-23}Js/m[/tex]
Putting this value of p in equation (1) , we get
[tex]\lambda=\frac{6.62\times10^{-34}}{4.003\times10^{-23}}\\\lambda=1.65\times10^{-11}[/tex]
(d) Putting E = 0.3eV in equation (2) , we get
[tex]p=\frac{0.3\times 1.6\times10^-^1^9}{3\times 10^8} \\p=1.6\times10^-^2^8Js/m[/tex]
Putting this value of p in equation (1) , we get
[tex]\lambda=\frac{6.62\times10^{-34}}{1.6\times10^{-28}}\\\lambda=4.13\times10^{-6}[/tex]
(e) Putting [tex]p=3eV/c[/tex] in equation (1) , we get
[tex]\lambda=\frac{6.62\times10^{-34}\\\times3\times10^8}{3\times1.6\times10^{-19}}\\\lambda=4.13\times10^{-7}[/tex]
On comparing the wavelength order should be (d) > (a) = (e) > (b) > (c) .
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which truth did isaac newton’s investigations of gravity explain? jupiter has more moons than earth. jupiter has more moons than earth. the sun is more massive than earth. the sun is more massive than earth. gravity acts on all objects in the universe. gravity acts on all objects in the universe. earth is not the center of the universe. earth is not the center of the universe.
Newton's investigations of gravity explain the truth that Jupiter has more moons than Earth.
The fact that Jupiter has more moons than Earth was first discovered by Galileo Galilei in 1610, and it was later confirmed by Newton. In addition to having more moons, it is also thought that Jupiter may be home to some of the most powerful magnetic fields in the solar system.
What was explained by Isaac Newton's law of gravity?Every particle in the cosmos attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers, according to Newton's law of universal gravitation.
Thus, the equation for universal gravity has the following structure:
[tex]{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}}{\displaystyle[/tex]
where r is the distance between the centers of the two objects' masses, m1 and m2 are their respective masses, G is the gravitational constant, and F is the gravitational force acting between them.
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The correct answer is; Gravity acts on all objects in the universe.
The answer above is incorrect…