At room temperature, the element bromine is a liquid with a density of 3.12 g/mL.
a Calculate the mass of 542 mL of bromine.
Mass = blank g
b What volume does 60.0 g of bromine occupy?
Volume =
mL

Answer:

[tex]2877kJ/mol[/tex]

Explanation:

Hello.

In this case, since the bond energy per C-H bond is 411 kJ/mol and we of course avoid the C-C bond since we are asked to compute the energy to break 7 C-H bonds, the 411 kJ/mol are multiplied by 7 as shown below:

[tex]7*411kJ/mol\\\\=2877kJ/mol[/tex]

Thus, we obtain the required bond dissociation energy. Note that propane CH₃-CH₂-CH₃ has seven C-H bonds; 3 from the first CH₃, two from the CH₂ and 3 from the last CH₃.

Best regards.

Bond dissociation energy is defined as the energy required to dissociate or break a bond to form two or more molecular fragments.

In the given molecule of propane, the energy required to break the seven C-H bonds is 2877 kJ/mol.

The bond dissociation energy for the highly stable bond will be very high. In the given bonds of carbon and hydrogen, we know that:

Each C-H bond has an energy of 411 kJ/mol.

To calculate the bond dissociation energy of 7 C-H bonds, we have:

1 C-H bonds = 411 kJ/mol

7 C-H bonds = 411 x 7

7 C-H bonds = 2877 kJ/mol

Therefore, the bond dissociation energy required to break the seven C-H bonds is 2877 kJ/mol.

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Answer:

3.24 × 10^5 J/mol

Explanation:

The activation energy of this reaction can be calculated using the equation:

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

Where; Ea = the activation energy (J/mol)

R = the ideal gas constant = 8.3145 J/Kmol

T1 and T2 = absolute temperatures (K)

k1 and k2 = the reaction rate constants at respective temperature

First, we need to convert the temperatures in °C to K

T(K) = T(°C) + 273.15

T1 = 325°C + 273.15

T1 = 598.15K

T2 = 407°C + 273.15

T2 = 680.15K

Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now find Ea

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)

ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4

7.831 = Ea(2.417 × 10^-5)

Ea = 3.24 × 10^5 J/mol

The activation energy is 3.24 × 10^5 J/mol

The activation energy of this reaction can be determined using the equation:

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

Here

Ea = the activation energy (J/mol)

R = the ideal gas constant = 8.3145 J/Kmol

T1 and T2 = absolute temperatures (K)

k1 and k2 = the reaction rate constants at  temperature

Now

First, we need to convert the temperatures in °C to K

So,

T(K) = T(°C) + 273.15

T1 = 325°C + 273.15

T1 = 598.15K

T2 = 407°C + 273.15

T2 = 680.15K

Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now determined Ea

So,

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)

ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4

7.831 = Ea(2.417 × 10^-5)

Ea = 3.24 × 10^5 J/mol

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Answer:

2 NaOH (aq) + H2C2O4(aq) Na2C2O4(aq) + 2H2O (l) Moles of NaOH used = Molarity x Volume (L) = 0.12 mole/L x 0.025

Explanation:

Answer:

[tex]Cp_{metal}=0.922\frac{J}{g\°C}[/tex]

Explanation:

Hello.

In this problem we must realize that there is heat flow that moves from the hot metal object and the hot water to the cold water and the cold aluminum cup, which allows us to write:

[tex]Q_{cup}+Q_{cold,w}=-(Q_{metal}+Q_{hot,w})[/tex]

Which means that the heat lost be the hot metal object and the hot water is gained by both the cold water and the cold aluminum cup, which can be written in terms of mass, specific heats and change in temperature towards the equilibrium temperature (35.9 °C):

[tex]m_{cup}Cp_{cup}(T_{eq}-T_{cup})+m_{cold,w}Cp_{cold,w}(T_{eq}-T_{cold,w})=-(m_{metal}Cp_{metal}(T_{eq}-T_{metal})+m_{hot,w}Cp_{hot,w}(T_{eq}-T_{hot,w})[/tex]

We need to solve for the specific heat of the metal as shown below:

[tex]Cp_{metal}=\frac{m_{cup}Cp_{cup}(T_{eq}-T_{cup})+m_{cold,w}Cp_{cold,w}(T_{eq}-T_{cold,w})+m_{hot,w}Cp_{hot,w}(T_{eq}-T_{hot,w})}{-m_{metal}(T_{eq}-T_{metal})} \\\\Cp_{metal}=\frac{39.78g*0.903\frac{J}{g\°C}(35.9-0.5)\°C+50.01g*4.184\frac{J}{g\°C}(35.9-0.5)\°C +50.72g*4.184\frac{J}{g\°C}(35.9-69.5)\°C }{-49.98g(35.9-69.5)\°C } \\\\Cp_{metal}=\frac{1271.6J+7407.2J-7130.3J}{-1679.3g\°C} \\\\Cp_{metal}=0.922\frac{J}{g\°C}[/tex]Best regards.

Answer:

31

Explanation:

Answer:

v = 10 km/h

Explanation:

Step 1: Given data

Step 2: Calculate the speed in the Bike Trip

The speed (v) is equal to the distance traveled divided by the time elapsed. We will use the following mathematical expression.

v = d/t

v = 1 km/0.1 h

v = 10 km/h

The speed is 10 kilometers per hour.

Answer:

C

Explanation:

If a substance is malleable, it can be hammered flat without breaking

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass of pencil = 3.5 g

density = 0.875 g/mL

So we have

[tex]volume = \frac{3.5}{0.875} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

30 center meters

Explanation:

2.15-1.85=0.30

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

mass = 22 g

volume = 2 cm³

We have

[tex]density = \frac{22}{2} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

In my opinion, I think that furthermore might be a good transition word.

hope this helps :)

Explanation:

sand

Explanation:

it is absorbing it

Answer:

Sand absorbers the water

Explanation:

On other days, however, when winds blow surface water toward land, the water can't just pile up on the beach, so water near the bottom has to compensate, moving offshore. ... One measures the speed and direction of flowing water by reflecting sound off particles carried by the currents.

ammonium, sulfate, phosphate, nitrate

Question: Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP. Of 5.06 grams of KHP are needed to exactly neutralize 35.3 mL of a barium hydroxide solution, what is the concentration of the base solution?

Explanation and answer:

2KHP + Ba(OH)2 ---> 2H2O + Ba(KP)2

you need 2 moles of KHP to neutralise 1 mole of Ba(OH)2

moles KHO = mass / molar mass  

= 2.43 g / 204.22 g/mol  

= 0.0118989 mol

moles Ba(OH)2 = 1/2 x moles KHP

= 0.005949 mol

Molarity Ba(OH)2 = moles / Litres

= 0.005949 mol / 0.0213 L

= 0.279 M (3 sig figs)

Given parameters:

Volume of CuSO₄ = 250mL

Concentration of CuSO₄ = 2.01M

Unknown:

Mass of CuSO₄.5H₂O = ?

To solve this problem, we must write the chemical relationship between both species.;

             CuSO₄.5H₂O  →   CuSO₄ + 5H₂O

Now that we know the expression, it is possible to solve for the unknown mass.

First find the number of moles of CuSO₄;

         Number of moles  = Concentration x Volume

Take 250mL to L so as to ensure uniformity of units;

           Volume  = 250 x 10⁻³L

  Input the parameters and solve for number of moles;

        Number of moles  = 250 x 10⁻³  x  2.01 = 0.5mol

From the equation;

             1 mole of CuSO₄ is produced from 1 mole of CuSO₄.5H₂O  

So  0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O

Now let us find the molar mass of CuSO₄.5H₂O = 63.6 + 32 + 4(16) + 5(2x1 + 16)  = 249.6g/mole

Mass of CuSO₄.5H₂O = number of moles x molar mass

                                      = 0.5 x 249.6

                                     = 124.8g

The mass of CuSO₄.5H₂O is 124.8g

Answer: 313.4 I think

Explanation:

sorry if i got it wrong i tried my best

Answer:

it equals up 30 to 35 for me

Explanation:

sorry if its wrong

Answer:

Explanation:

The Law of Conservation of Mass is defined and explained using examples of reacting mass calculations using the law are fully explained with worked out examples using the balanced symbol equation. The method involves reacting masses deduced from the balanced symbol equation.

Answer:

v=ir

v=2×20

=40V is the answer

Answer:

a

Explanation:

the answer is a

add it up maybe?

Explanation:

The atomic mass of any element can be easily determined with the help of the number of protons and neutrons. You are simply required to add the number of neutrons and protons in order to estimate the atomic mass of any element.

The Atomic mass of an element may be defined as the average mass of the atoms of an element that are significantly measured in the atomic mass unit (amu).

Another method through which you can approximate the value of the atomic mass of any element is that you are simply required to double the value of the atomic number that is known for each specific element.

For example, The atomic number of oxygen is 8, while its atomic mass is 8 × 2 = 16. Similarly, the atomic number of nitrogen is 7, while its atomic mass is 7 × 2 = 14.

Therefore, it is well described above.

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#SPJ2

Answer:

N2H4 is straightforward with no double or triple bonds. In the N2H4 Lewis structure the two Nitrogen (N) atoms go in the center (Hydrogen always goes on the outside). Hydrogen (H) only needs two valence electrons to have a full outer shell. In the Lewis structure for N2H4 there are a total of 14 valence electrons.

Answer:

The electron configuration of sulfur (S) normally is 1s2 2s2 2p6 3s2 3p4

S+ ion of sulfur would be 1s2 2s2 2p6 3s2 3p3

S- ion 1s2 2s2 2p6 3s2 3p5

Answer:

quantum mechanics

Explanation:

Answer:

A substance's specific heat tells you how much heat is required to ... the temperature of 1.0 g of that substance by 1∘C . ... ΔT - the change in temperature, defined s final ...

Answer:

E2

Explanation:

We can generally regard the bromocyclohexane as having a secondary carbon atom to Which the bromine atom is attached.

Tert-butoxide in tert-butanol favours the formation of an alkene (elimination) leading to the predominance of the less substituted alkene.

Generally, bulky bases such as tert-butoxide favours elimination by E2 mechanism over substitution.

The mechanism of Reaction A is E2 and also mechanism over substitution.

We can generally regard the Bromo cyclohexane as maintaining a secondary carbon atom to Which the bromine atom is connected.

Tert-butoxide in tert-butanol prefers the formation of an alkene (elimination) leading to the predominance of the undersized substituted alkene. Therefore, Commonly, bulky bases such as tert-butoxide favors elimination by the E2 mechanism over substitution.

Find more information about Bromine substituent here:

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Answer:

Instead of being a linear process, the scientific method is a complex cycle that involves many people and does not follow set steps, but is more free form in nature. Ideas generate new ideas and lead to new hypotheses, and deeper understanding.

Answer:

The answer is

Cyclic...

: )

Answer:

It is an amine; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.

Explanation:

The boiling point of a compound is a physical property. Such physical property are influenced by the intramolecular bonds between the molecules that makes a up compound.

Both Amine and Alcohols have the same type of intermolecular bonds between them. This bond type is called the hydrogen bonds.

A hydrogen bond is an electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.

 Note: the strength of a hydrogen bond depends on the relative electronegativity of the atom directly joined to the hydrogen.

  The order of strength of the bond is;

             H.....F  > H.....O > H......N

In amines we have the H....N hydrogen bonds, for alcohol, it is the H....O hydrogen bonds.

So, the bonds in hydrogen bonds in the alcohol is stronger and it will impart a higher boiling point on the compound.

Answer: It is an amine; it contains nitrogen-hydrogen bonds that are less polar than oxygen-hydrogen bonds.

Explanation: I TOOK THE TEST AND GOT IT RIGHT

Answer:

jumm453685ruuhkcswch

Answer:

I bealive the answer is D.

Answer:

The options are not given, here are the options.

metal

a. Metal

b. a metalloid

c. a non-metal

d. a gas

The correct option is C.

Non metal

Explanation:

Henry should classify it as non metals because non metals are substances or elements that are poor conductors of heat and electricity they break easily I .e meaning they lack the ducibility of metals, meaning they cannot be stretched, they are brittle, they are not shiny and does not reflect light, they have high electronegativities that is they have atoms that can hold electrons to what they have.

Answer:

C

Explanation:

Because it’s doesn’t reflect light and metals and metalloids do

Answer:

1) 0.9972 g/cm³.

2) 77.62 g.

3) 25.01 cm³.

4) 7.11 cm³

5) 17.9 cm³.

6) 4.34 g/cm³

Explanation:

Hello.

In this case, for this gravimetry problem, we proceed as follows:

1) Since the temperature is 23.75 °C the density computed via lineal interpolation is:

[tex]\rho=1.004g/cm^3+23.75\°C*-0.000273\frac{g/cm^3}{\°C} =0.9972g/cm^3[/tex]

2) The mass of the solid is computed via the mass of the empty flask and the mass of the flask with the solid:

[tex]m_{solid}=135.95g-58.33g\\\\m_{solid}=77.62g[/tex]

3) In this case, since the volume of the flask equals the volume of the flask and the water because the volume of liquid water equals the volume of the container at which it is, we compute the volume of the flask considering both the mass and density of water:

[tex]m_{water}=83.27g-58.33g=24.94g\\\\V_{water}=\frac{24.94g}{0.9972g/cm^3}\\ \\V_{water}=25.01cm^3[/tex]

Thus, the volume of the flask is 25.0 cm³.

4) Here, we compute the volume of water when the water and the solid are inside the flask:

[tex]m_{water}=143.04g-135.95g=7.09g\\\\V_{water}=\frac{7.09g}{0.9972g/cm^3} =7.11cm^3[/tex]

Thus, the volume of the flask not occupied by the solid which corresponds to the water is 7.11 cm³.

5) Considering the previous volume of the flask, the volume of the solid is:

[tex]V_{solid}=25.01 cm^3-7.11cm^3\\\\V_{solid}=17.9cm^3[/tex]

6) Finally, the density of the solid is:

[tex]\rho _{solid}=\frac{77.62g}{17.9cm^3}\\ \\\rho _{solid}=4.34g/cm^3[/tex]

Regards.