At an animal shelter, a guinea pig eats cabbage at the constant rate. The table shows the
proportional relationship between minutes and pieces of cabbage eaten. 4
3
5
7
9
11
X
11
+6
.6
9
+6
-6
+6
6
18
30
42
54
66
y

The complex zeros of the polynomial function are -1, -2, -2, 1.5, and -4.

To find the complex zeros of the polynomial function, we need to use synthetic division and the quadratic formula.

First, let's use synthetic division to find one of the zeros:

-1 | 2 15 29 24 80
| -2 -13 -16 -8
|_____________________
2 13 16 8 72

Now, we have a new polynomial: 2x^(4)+13x^(3)+16x^(2)+8x+72

Let's use synthetic division again to find another zero:

-2 | 2 13 16 8 72
| -4 -18 -4 -8
|_____________________
2 9 -2 4 64

Now, we have a new polynomial: 2x^(3)+9x^(2)-2x+4

Let's use synthetic division one more time to find another zero:

-2 | 2 9 -2 4
| -4 -10 4
|_____________________
2 5 -12 0

Now, we have a new polynomial: 2x^(2)+5x-12

We can use the quadratic formula to find the remaining zeros:

x = (-b ± √(b^(2)-4ac))/(2a)

x = (-(5) ± √((5)^(2)-4(2)(-12)))/(2(2))

x = (-5 ± √(121))/(4)

x = (-5 ± 11)/(4)

x = (-5 + 11)/(4) or x = (-5 - 11)/(4)

x = 6/4 or x = -16/4

x = 1.5 or x = -4

So, the complex zeros of the polynomial function are -1, -2, -2, 1.5, and -4.

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Teh type of plate was served are 242 child's plates and 212 adult's plates.

To solve this problem, we can use a system of equations. Let x be the number of child's plates and y be the number of adult's plates.

We can write two equations to represent the information given in the problem:

x + y = 454 (the total number of plates served)

3.50x + 7.40y = 2415.80 (the total amount of money collected)

Now we can use the first equation to solve for one of the variables in terms of the other.

For example, we can solve for x in terms of y:

x = 454 - y

Now we can substitute this expression for x into the second equation:

3.50(454 - y) + 7.40y = 2415.80

Simplifying and solving for y, we get:

1589 - 3.50y + 7.40y = 2415.80 3.90y = 826.80 y = 212

Now we can use this value of y to find x: x = 454 - 212 = 242 So there were 242 child's plates and 212 adult's plates served.

Rounded to the nearest whole person, the answer is 242 child's plates and 212 adult's plates.

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The scalar equation of the plane is -5x - 2y = 5.

To find the scalar equation for the plane passing through the points P1=(−3, 5, 3), P2=(−5, 0, 6), and P3=(−1, 10, −1), we need to follow these steps:

1. Find the vectors P1P2 and P1P3 by subtracting the corresponding coordinates of the points:
P1P2 = P2 - P1 = (-5 - (-3), 0 - 5, 6 - 3) = (-2, -5, 3)
P1P3 = P3 - P1 = (-1 - (-3), 10 - 5, -1 - 3) = (2, 5, -4)

2. Find the normal vector to the plane by taking the cross product of P1P2 and P1P3:
n = P1P2 x P1P3 = (-5 * (-4) - 3 * 5, 3 * 2 - (-2) * (-4), -2 * 5 - (-5) * 2) = (-5, -2, 0)

3. Find the scalar equation of the plane by substituting one of the points and the normal vector into the general equation of a plane:
ax + by + cz = d
-5 * (-3) + (-2) * 5 + 0 * 3 = d
d = 5

Therefore, the scalar equation of the plane is -5x - 2y = 5.

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The surface area of the solids are listed below:

In this problem we find three cases of unfolded solids, whose surface area must be determined. The surface area is the sum of the areas of all faces of the solid. The area formulas for the triangle and the rectangle are, respectively:

Rectangle

A = b · h

Triangle

A = 0.5 · b · h

Where:

Now we proceed to determine the surface area of the solids are listed below:

Case 1

A = (9 in)² + 0.5 · (9 in)²

A = 81 in² + 40.5 in²

A = 121.5 in²

Case 2

A = 4 · (10 cm) · (2 cm) + (2 cm)²

A = 80 cm² + 4 cm²

A = 84 cm²

Case 3

A = 3 · (8 ft) · (10 ft) + 2 · (8 ft) · (5 ft)

A = 240 ft² + 80 ft²

A = 320 ft²

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Answer:

the nearest degree is a in the given figure

(\begin{bmatrix}\frac{1}{5} & -\frac{2}{5} \\-\frac{3}{5} & \frac{7}{5}\end{bmatrix}\)

To find the inverse of the given matrix 3. \( \left[\begin{array}{ll}7 & 2 \\ 3 & 1 \\ 2 & 3 \\ \text { 4. }

5 .\end{array}\right] \), use the following steps:

1. Find the determinant of the matrix by using the formula det \(A = ad-bc\). The determinant of the given matrix is \((7*1) - (2*3) = 5\).

2. Find the adjoint of the matrix by using the formula

\(A^T = \begin{bmatrix}
a & b \\c & d\end{bmatrix}^T = \begin{bmatrix}d & -b \\-c & a\end{bmatrix}\)

The adjoint of the given matrix is \\begin{bmatrix}1 & -2 \\-3 & 7\end{bmatrix}\)

3. Find the inverse of the matrix by using the formula \(A^{-1} = \frac{1}{det(A)} \cdot A^T\).

The inverse of the given matrix is \(\begin{bmatrix}\frac{1}{5} & -\frac{2}{5} \\-\frac{3}{5} & \frac{7}{5}\end{bmatrix}\)

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Using long division . The quotient of  (4x^3-6x^2-4x+8) divided by (2x-1) is: 2x^2 - 2x - 2 with a remainder of 7.

Let use long division to determine the quotient of (4x^3-6x^2-4x+8) divided by (2x-1).

Long division:

   2x^2  - 2x  - 2

    --------------------

2x - 1 | 4x^3  - 6x^2  - 4x  + 8

       - (4x^3  - 2x^2)

       --------------

            -4x^2  - 4x

            +  (4x^2  - 2x)

            --------------

                      -2x  + 8

                      -(-2x  + 1)

                      --------

                               7

Therefore, the quotient of (4x^3 - 6x^2 - 4x + 8) divided by (2x - 1) is:

2x^2 - 2x - 2 with a remainder of 7.

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If Jose has done 100 more science experiments than Gabby and the number of science experiments done by Gabby is x, an expression representing Jose's experiments is 100 + x.

Mathematically, an expression is the combination of variables, constants, values, and numbers using mathematical operands but without an equal symbol (=).

The basic mathematical operands include addition (+), subtraction (-), division (÷), and multiplication (×).

Let the number of science experiments performed by Gabby = x

The number of science experiments performed by Jose = x + 100

x + 100

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By applying velocity concept, it can be concluded that the height of the object is 48 feet at 1 second and 3 seconds.

Velocity is the distance traveled, and the direction in which the distance is changing. It can also be described as the instantaneous rate of change of a moving object.

velocity = Δs / Δt  , where:

Δs = distance change

Δt  = time change

The height of the object is given by the equation h = -16t² + 64t.

We need to find the time t when the height is 48 feet.

To do this, we can plug in the value of h and solve for t:

 h = -16t² + 64t

48 = -16t² + 64t

 0 = -16t² + 64t - 48

Dividing by -16 gives us:

0 = t² - 4t + 3

  = (t - 3)(t - 1)

Therefore, the possible values of t are 1 and 3 seconds.

So, the height of the object is 48 feet at 1 second and 3 seconds.

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It will take 5.00 seconds for the object to reach a height of 48 feet.

To answer this question, we need to use the equation given: h = -16t2 + 64t. We know that the height is 48 feet and need to calculate the number of seconds it will take to reach this height.

We can rearrange the equation to solve for t, which will give us the number of seconds it takes to reach 48 feet:

48 = -16t2 + 64t

To solve for t, we can use the quadratic formula:

t = (-64 ± √(642 - 4(-16)(48))) / (2(-16))

After simplifying, we get:

t = (8 ± √384) / -32

Therefore, the two solutions are t = 5.00 seconds and t = -6.25 seconds.

Since the object is being propelled upwards, the only solution that makes sense is t = 5.00 seconds.

Therefore, it will take 5.00 seconds for the object to reach a height of 48 feet.

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The original logarithmic formula of the given expression is log₈3.

The logarithm has different properties that are fundamental to work with it and solve different problems. The change of base formula states that logₐb = (logₓb)/(logₓa), where x is any base.

In this case, the base x is not specified, so it can be any base. Using the change of base formula, we can rewrite the original formula as (logₓ3)/(logₓ8), which is equivalent to the given expression (log3)/(log8). Therefore, the original formula was log₈3.

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Based on the information provided, it can be concluded that Manuel measured the height.

The height of a triangle ( a shape with three sides, three angles, and three vertices) can be defined as the distance between the vertex and the opposite. The vertex refers to the highest point of the triangle, which is usually at the top. In the case of the triangle presented, the height is five and this was correctly obtained by Manuel when he measured the distance from the vertex to its base.

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Answer:

8) Area of triangle ABC is 60

   Area of triangle XYZ is 540

9) The ratio is 1:9

10) (use Pythagorean theorem)

     BC is 12 [tex]\sqrt{13^{2}-5^{2} } =12[/tex]

     YZ=39 (the legs are the same because it is an Isosceles triangle)

11) the ratio is 1:3

Step-by-step explanation:

The child will get about 281.3 cubic centimeters more ice cream in the cylindrical-shaped cup than in the cone-shaped cup.

Volume is an important concept in many areas of science and engineering, including physics, chemistry, and materials science. It is also used in everyday life, such as in calculating the amount of liquid that can be held in a container, or the amount of space that is needed to store a set of objects.

To determine which cup shape holds more ice cream, we need to compare their volumes. The formula for the volume of a cone is (1/3)πr²h, where r is the radius of the circular base and h is the height of the cone. The formula for the volume of a cylinder is πr²h, where r is the radius of the circular base and h is the height of the cylinder.

First, let's find the volume of the cone-shaped cup:

radius = diameter/2 = 8/2 = 4 cm

height = 12 cm

volume = (1/3)πr²h

volume = (1/3)π(4 cm)²(12 cm)

volume ≈ 201.1 cm³

Next, let's find the volume of the cylindrical-shaped cup:

radius = diameter/2 = 8/2 = 4 cm

height = 12 cm

volume = πr²h

volume = π(4 cm)²(12 cm)

volume ≈ 482.4 cm³

The cylindrical-shaped cup has a larger volume, so the child should choose the cylindrical-shaped cup to get the most ice cream.

To find out how much more ice cream the cylindrical-shaped cup holds, we can subtract the volume of the cone-shaped cup from the volume of the cylindrical-shaped cup:

482.4 cm³ - 201.1 cm³ ≈ 281.3 cm³

Therefore, the child will get about 281.3 cubic centimeters more ice cream in the cylindrical-shaped cup than in the cone-shaped cup.

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Answer: Total Lateral Area 96in^2^2 Surface Area 108in^2

Step-by-step explanation:

Lateral Areal:

LA=Ph

P=4+4+4=12 h=8 12(8)=96in^2

Surface Area:

B=1/2(4)(3)=6 SA=12(8)+2(6)=108in^2

1. The median of the sample is obtained through the expression 3+5 / 2. The correct answer is option b.

2. The mean of the ungrouped data distribution is 1.98. The correct answer is option C.

1. The median of a set of data is the middle value when the data is arranged in ascending or descending order. In this case, the data set is (1.9, 3, 5, 7). The middle values are 3 and 5, so the median is the average of these two values, which is (3+5) / 2 = 4.

2. The mean of a set of data is the sum of all the data values divided by the number of data values. In this case, the mean is [(3.2)(2) + (1.3)(5) + (2.4)(3)] / (2+5+3) = 19.8 / 10 = 1.98.

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To rearrange the equation y - 3 = 2x into slope-intercept form, we need to solve for y.

First, we can add 3 to both sides of the equation to isolate y:

y - 3 + 3 = 2x + 3

Simplifying the left side gives:

y = 2x + 3

Now, the equation is in slope-intercept form y = mx + b, where m is the slope (in this case, m = 2) and b is the y-intercept (in this case, b = 3).

The resulting matrix is \( \left[\begin{array}{ll}0 & 0 \\ 0 & 0\end{array}\right] \).

we notice is that the resulting matrix is the zero matrix, which means that all of its elements are zero. This is because the matrices \( A \) and \( B \) are inverses of each other.

To calculate \( A B \), we multiply the elements in each row of \( A \) with the corresponding elements in each column of \( B \) and then add them together. This gives us the elements in the resulting matrix.

So, the first element in the resulting matrix is \( (4 * 1) + (2 * -2) = 4 - 4 = 0 \). The second element is \( (4 * -3) + (2 * 6) = -12 + 12 = 0 \). The third element is \( (2 * 1) + (1 * -2) = 2 - 2 = 0 \). And the fourth element is \( (2 * -3) + (1 * 6) = -6 + 6 = 0 \).

Therefore, the resulting matrix is \( \left[\begin{array}{ll}0 & 0 \\ 0 & 0\end{array}\right] \).

What we notice is that the resulting matrix is the zero matrix, which means that all of its elements are zero. This is because the matrices \( A \) and \( B \) are inverses of each other. When we multiply a matrix by its inverse, we get the identity matrix, which has ones on the main diagonal and zeros everywhere else. But in this case, since the matrices are 2x2, the identity matrix is just the zero matrix.

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Alice therefore requires 72 feet of netting.

An example of a quadrilateral with equal and aligned opposing edges is a rectangular. It is a rectangle with four sides and four edges that are each 90 degrees. A rectangular is a form with only two dimensions.

If the longer dimension of the rectangle is 25 feet, then we can write:

x + 14 = 25

Solving for x, we get:

x = 25 - 14 = 11

Therefore, the height of the rectangle is 11 feet.

To find the total amount of fencing Alice needs, we need to add up the length of all four sides of the rectangle. Since opposite sides of a rectangle are equal in length, we can write:

Total fencing = 2(length + height)

Substituting the values of length and height, we get:

Total fencing = 2(25 + 11)

Total fencing = 72 feet

Therefore, Alice needs 72 feet of fencing.

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A Polyhedron with 10 edges and 6 vertices has 4 faces.  

A. Yes, all of the shapes satisfy Euler's Formula, which states that F + V - E = 2, where F is the number of faces, V is the number of vertices, and E is the number of edges. The following table shows that each shape satisfies this formula:

B. A polyhedron with 10 edges and 6 vertices has 4 faces. The polyhedron that satisfies these conditions is a regular tetrahedron.

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The area of the shaded region under the standard normal curve is 0.4783.

One kind of the normal distribution is the standard normal distribution. It happens when a typical random variable's mean and standard deviation are both one. In other terms, the term "standard normal distribution" refers to a normal distribution with a mean of 0 and a standard deviation of 1. Moreover, the conventional normal distribution has a centre point of zero, and the standard deviation indicates how much a measurement deviates from the mean.

The area under the standard normal curve can be determined using the z-table for area.

For the given figure the area under the standard normal curve is given as:

P[-2.02<Z<0]

=0.5-0.0217

=0.4783

Hence, the area of the shaded region under the standard normal curve is 0.4783.

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The complete question is:

Answer: 1/3

Step-by-step explanation: so there is six cards total and only two of them are even so 2/6 and that can go to 1/3

1/3

There are 2 even numbers, and the total is 6. So 2/6 in the simplest form is 1/3.

Yes, you have correctly applied the FOIL method to the equation f(x)=4(x+1)²-3.

The next step would be to simplify the equation by combining like terms.

This would result in the equation f(x)=4x²+2x-1. From here, you can either set the equation equal to zero and solve for x, or you can find the vertex, axis of symmetry, and other characteristics of the quadratic function.

Here is a step-by-step explanation of the FOIL method and simplification process:

1. Start with the original equation: f(x)=4(x+1)²-3
2. Apply the FOIL method to the (x+1)² term: f(x)=4(x²+2x+1)-3
3. Distribute the 4 to each term inside the parentheses: f(x)=4x²+8x+4-3
4. Combine like terms: f(x)=4x²+8x+1

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Answer:

Proofs attached to answer

Step-by-step explanation:

Proofs attached to answer

Answer:

[tex]x = 2[/tex]

Step-by-step explanation:

[tex]9(2 - x) = 3x - 6 \\ 18 - 9x = 3x - 6 \\ 18 + 6 = 3x + 9x \\ 24 = 12x \\ x = 2[/tex]

[tex] \: [/tex]

[tex] \: [/tex]

[tex] \: [/tex]

[tex] \: [/tex]

[tex] \: [/tex]

[tex] \: [/tex]

[tex] \: [/tex]

[tex] \: [/tex]

The value of x is 2 !

━━━━━━━━━━━━━━━━━━━━━━━

hope it helps! :)

(a) Let P0 = (-1, 2, 3) be the point and v = (7, -1, 5) be the direction vector. Then the equation of the line can be written in vector form as:

r = P0 + tv

where r is a point on the line, t is a scalar parameter, and v is the direction vector. Substituting the values of P0 and v, we get:

r = (-1, 2, 3) + t(7, -1, 5)

or

r = (7t - 1, -t + 2, 5t + 3)

(b) Let P0 = (2, 0, -1) be the point and v = (1, 1, 1) be the direction vector. Then the equation of the line can be written in vector form as:

r = P0 + tv

where r is a point on the line, t is a scalar parameter, and v is the direction vector. Substituting the values of P0 and v, we get:

r = (2, 0, -1) + t(1, 1, 1)

or

r = (t + 2, t, t - 1)

(c) Let P0 = (2, -4, 1) be the point and v = (0, 0, -2) be the direction vector. Then the equation of the line can be written in vector form as:

r = P0 + tv

where r is a point on the line, t is a scalar parameter, and v is the direction vector. Substituting the values of P0 and v, we get:

r = (2, -4, 1) + t(0, 0, -2)

or

r = (2, -4, 1 - 2t)

(d) Let P0 = (0, 0, 0) be the point and v = (a, b, c) be the direction vector. Then the equation of the line can be written in vector form as:

r = P0 + tv

where r is a point on the line, t is a scalar parameter, and v is the direction vector. Substituting the values of P0 and v, we get:

r = (0, 0, 0) + t(a, b, c)

or

r = (at, bt, ct)

Note that the vector form of a line through a point P and parallel to a vector v is not unique, as there are infinitely many scalar multiples of v that are also parallel to it. The above solutions are one possible vector form for each case.

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[tex]\left \{ {{2y-x=-9} \atop {y=2x-3}} \right. \iff \left \{ {{2(2x-3)-x=-9} \atop {y=2x-3}} \right. \iff \{ {{4x-6-x=-9} \atop {y=2x-3}} \right. \\[/tex]

[tex]\{ {{3x=-9+6} \atop {y=2x-3}} \right. \iff \{ {{3x=-3} \atop {y=2x-3}} \right. \iff \{ {{x=-1} \atop {y=2x-3}} \right. \\[/tex]

[tex]\{ {{x=-1} \atop {y=2(-1)-3}} \right \iff \{ {{x=-1} \atop {y=-2-3}} \right \implies \bf \{ {{x=-1} \atop {y=-5}}[/tex]

[tex]\implies (x, \ y) = (-1, \ -5)[/tex]

When one holder has a height of 5 inches and a width of 4 inches, this is approximately have Surface Area of 1385.44  inches² if we round to two decimal places.

what is surface area ?

Surface area is a measurement of the overall space occupied by an object's surface. It is the total area of the object's faces, sides, and curved sections. The surface area of a cube, for instance, is equal to the total of the areas of each of its six square faces. Similar to a sphere, a cylinder's surface area is equal to the total of the areas of its two circular bases and its curved surface. Units of surface area include square inches (in²), square feet (ft²), and square metres (m²). It is a crucial measurement in a variety of industries, including science, engineering, and building.

given

We must first determine the cylinder's surface area in order to determine how much material will be required to create one cylindrical pencil case.

The following is the calculation for a cylinder's surface area:

S = 2πrh + 2πr²

S stands for surface area.

r is the cylinder's radius.

h is the cylinder's height.

The radius of the holder is equal to half of its 4 inch circumference, or 2 inches.

Consequently, the total area for one holder will be:

S = 2π(2)(5) + 2π(2)²

S = 20π

In order to create one pencil holder, Mrs. Howard would require 20 square inches of material.

She would require: to create pencil holders for each of her 22 pupils.

22 × 20 inches of material equals 440  inches².

When one holder has a height of 5 inches and a width of 4 inches, this is approximately 1385.44  inches² if we round to two decimal places.

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The answer to the given question is 220 ft depth at 2:16 pm. Here we have a depth of submersible at 2:16 pm.

A watercraft made to function underwater is submersible. The term "submersible" is frequently used to distinguish between submersibles and other underwater vessels known as submarines. A submersible is typically supported by a nearby surface vessel, platform, shore team, or occasionally a larger submarine, whereas a submarine is a fully self-sufficient craft capable of independent cruising with its own power supply and air renewal system.

At 2:16 p.m.= -180ft - 40ft = -220ft

So, the answer is 220 ft depth.

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The rate in cups per hour, at which the water is leaking from the faucet

is 5/14 cups per hour.

A unitary method is a mathematical way of obtaining the value of a single unit and then deriving any no. of given units by multiplying it with the single unit.

Given, Josh put an empty cup underneath a leaking faucet. After [tex]1\frac{3}{4}[/tex] hours Josh collected 5/8 ​cups of water.

Now, [tex]1\frac{3}{4} = \frac{7}{4}[/tex].

Therefore, The rate in cups per hour, at which the water is leaking from the faucet is,

= (5/8)/(7/4) cups per hour.

= (5/8)×(4/7) cups per hour.

= 5/14 cups per hour.

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To solve the equation, we need to get rid of the fractions by multiplying both sides of the equation by the least common denominator (LCD), which is (b^(2)-9). This will give us:
(8)(b^(2)-9)/(b^(2)-9)-(1)(b^(2)-9)/(b+3)=(1)(b^(2)-9)/(b^(2)-9)
Simplifying the equation gives us:
8-(b^(2)-9)/(b+3)=1
Next, we will isolate the variable term by subtracting 8 from both sides of the equation:
-(b^(2)-9)/(b+3)=-7
Now, we will multiply both sides of the equation by (b+3) to get rid of the fraction:
-(b^(2)-9)=-7(b+3)
Expanding the equation gives us:
-b^(2)+9=-7b-21
Rearranging the equation gives us:
b^(2)-7b-30=0
Factoring the equation gives us:
(b-10)(b+3)=0
Setting each factor equal to zero gives us the possible solutions:
b-10=0 or b+3=0
Solving for b gives us the possible solutions:
b=10 or b=-3
However, we need to check for extraneous solutions by plugging the possible solutions back into the original equation. Plugging in b=10 gives us a true statement, but plugging in b=-3 gives us an undefined expression. Therefore, the only solution is b=10.
Answer: b=10

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