Answer: The correct answer would be Graph H.
Step-by-step explanation:
Answer:
top right
Step-by-step explanation:
600 per 10 hours is a rate of 60/hour.
You need a graph that has a slope of 60 and includes the point (1, 60).
Answer: top right
Problem 7. Given a in Quadrant III, with cot a = 7, find the exact values of sin 0 and cos 0. Problem 8. Suppose sin a = - 24/25 and cos a =-7/ 25 and consider the angle B = Phi - a. (a) Find sin B and cos B (b) Indicate the quadrant the angle B belongs to
a) sin B = y/r = -1/5sqrt(2) and cos B = x/r = 7/5sqrt(2) (b) Since sin B is positive and cos B is negative, we found that angle B belongs in Quadrant II.
Given that cot a = 7, we know that tan a = 1/7. Since tan a = y/x, we can let x = 7 and y = -1 (since a is in Quadrant III and both x and y values are negative in this quadrant).
Using the Pythagorean Theorem, we can find r:
r = sqrt(x^2 + y^2) = sqrt(7^2 + (-1)^2) = sqrt(50) = 5sqrt(2)
Now we can find sin B and cos B:
sin B = y/r = -1/5sqrt(2)
cos B = x/r = 7/5sqrt(2)
We can use the double angle formulas for sine and cosine, sin B and cos B: sin B = sin(Phi - a) = sin Phi cos a - cos Phi sin a = (0)(-7/25) - (1)(-24/25) = 24/25 cos B = cos(Phi - a) = cos Phi cos a + sin Phi sin a = (1)(-7/25) + (0)(-24/25) = -7/25.
Since sin B is positive and cos B is negative, we know that angle B is in Quadrant II.
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Mountain Equipment Co-op (MEC) wants to price a new backpack. The backpack can be purchased for a list price of $59.95 less a trade discount of 25% and a quantity discount of 10%. MEC estimates expenses to be 18% of cost and it must maintain a markup on selling price of 35%. 1. What is the cost of backpack? 2. What is the markup amount? 3. What is the regular unit selling price for the backpack? 4. What profit will Mountain Equipment Co-op realize? 5. What happens to the profits if it sells the backpack at the MSRP instead?
The cost of backpack is $38.97. The markup amount is $13.64. The regular unit selling price for the backpack is $52.61
Mountain Equipment Co-op will be $19.02.The profit will be $19.02, which is higher than the profit of $6.63 when selling at the regular unit selling price.
To find the cost, markup amount, regular unit selling price, and profit for the backpack, we need to use the following formulas:
1. Cost = List Price - Trade Discount - Quantity Discount
2. Markup Amount = Cost × Markup Percentage
3. Regular Unit Selling Price = Cost + Markup Amount
4. Profit = Regular Unit Selling Price - Cost - Expenses
Let's plug in the given values and calculate each of these:
1. Cost = $59.95 - ($59.95 × 0.25) - ($59.95 × 0.10) = $59.95 - $14.99 - $5.99 = $38.97
2. Markup Amount = $38.97 × 0.35 = $13.64
3. Regular Unit Selling Price = $38.97 + $13.64 = $52.61
4. Profit = $52.61 - $38.97 - ($38.97 × 0.18) = $52.61 - $38.97 - $7.01 = $6.63
Now, if MEC sells the backpack at the MSRP (Manufacturer's Suggested Retail Price), the profit will be different. The MSRP is typically higher than the regular unit selling price, so the profit will be higher as well. Let's say the MSRP is $65. The profit would be:
Profit = MSRP - Cost - Expenses = $65 - $38.97 - ($38.97 × 0.18) = $65 - $38.97 - $7.01 = $19.02
So, if MEC sells the backpack at the MSRP, the profit will be $19.02, which is higher than the profit of $6.63 when selling at the regular unit selling price.
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Prove : cscx - sinx = cosxcotx
Answer:
Please review the trigonometric proof below
Step-by-step explanation:
Given
[tex]\csc x -\sin x=\cos x \cot x[/tex]
Apply the reciprocal identity to [tex]\csc x[/tex].
[tex]\frac{1}{\sin x} -\sin x=\cos x \cot x[/tex]
Write [tex]-\sin x[/tex] as a fraction then multiply by [tex]\frac{\sin x}{\sin x}[/tex].
[tex]\frac{1}{\sin x} + \frac{-\sin x}{1} =\cos x \cot x[/tex]
[tex]\frac{1}{\sin x} + \frac{-\sin x}{1} *\frac{\sin x}{\sin x}=\cos x \cot x[/tex]
[tex]\frac{1}{\sin x} + \frac{-\sin x\sin x}{\sin x}=\cos x \cot x[/tex]
Combine the numerators over the common denominator.
[tex]\frac{1-\sin x\sin x}{\sin x}=\cos x \cot x[/tex]
Multiply [tex]\sin x[/tex] by [tex]\sin x[/tex].
[tex]\frac{1-\sin^2 x}{\sin x}=\cos x \cot x[/tex]
Apply the Pythagorean identity [tex]1-\sin^2 x=\cos^2 x[/tex]
[tex]\frac{\cos^2 x}{\sin x}=\cos x \cot x[/tex]
Factor [tex]\cos x[/tex] out of [tex]\cos^2 x[/tex].
[tex]\frac{\cos x\cos x}{\sin x}=\cos x \cot x[/tex]
Separate into two fractions.
[tex]\frac{\cos x}{1} *\frac{\cos x}{\sin x}=\cos x \cot x[/tex]
Apply the quotient identity [tex]\frac{\cos x}{\sin x}=\cot x[/tex].
[tex]\frac{\cos x}{1} *\cot x=\cos x \cot x[/tex]
Anything over 1 is just itself.
[tex]\cos x\cot x=\cos x \cot x[/tex]
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, = space
Answer:
csc x − sin x
= [tex]\frac{1}{sin, x}[/tex] - sin x
= [tex]\frac{1 - sin^{2}, x }{sin, x}[/tex]
= [tex]\frac{cos^{2}, x }{sin, x}[/tex]
= [tex]\frac{cos, x}{sin, x}[/tex] * cos x
= cot x cos x
∴csc x - sin x - cot x cos xQED
It is the most " explanation " I can think of.
Thus the answer is shown above..
HELP PLEASE !!!!!
2g) Letty is simplifying the square root of 48 using the Product Property of Square Roots. She wants to use the factors 4 and 12 to simplify the radical. Explain why these are not the best factors to use.
2h) What factors would be a better choice to use to simplify the square root of 48? Why should you choose those
factors and not any other pair?
Answer:
2g) Letty cannot use the factors 4 and 12 to simplify the square root of 48 using the Product Property of Square Roots because 4 is a perfect square, but 12 is not. The Product Property of Square Roots only applies to factors that are both perfect squares.
2h) A better choice to simplify the square root of 48 would be to use the factors 16 and 3. This is because 16 is a perfect square and is a factor of 48, which means it can be taken out of the radical completely. The remaining factor is 3, which cannot be simplified any further since it is not a perfect square. Therefore, the square root of 48 can be simplified to 4 times the square root of 3. It is important to choose 16 and 3 as the factors and not any other pair because 16 is the largest perfect square factor of 48, and 3 is the remaining factor after taking out 16 that cannot be simplified any further.
2g) These factors (4 and 12) are not the best choice to simplify the square root of 48 because 4 is a perfect square, but 12 is not.
2h) a better choice to simplify the square root of 48 would be to use the factors 16 and 3. This is because 16 is the largest perfect square factor of 48, which simplifies the radical the most.
Now, Using the Product Property of Square Roots, we can simplify the square root of 48 as :
√48 = √(4 x 12)
However, these factors (4 and 12) are not the best choice to simplify the square root of 48 because 4 is a perfect square, but 12 is not.
Hence, We want to simplify the radical by finding the largest perfect square that is a factor of 48.
For this, we can break down 48 into its prime factors:
48 = 2 x 2 x 2 x 2 x 3
Then, we group the prime factors into pairs of the same number:
48 = (2 x 2) x (2 x 2) x 3
This gives us two perfect squares, 4 and 16.
Hence, We can simplify the square root of 48 by using the largest perfect square factor, which is 16:
√48 = √(16 x 3)
√48 = √16 x √3
√48 = 4√3
Therefore, a better choice to simplify the square root of 48 would be to use the factors 16 and 3.
This is because 16 is the largest perfect square factor of 48, which simplifies the radical the most.
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For the given expression, find the quotient and the remainder. Check your work by verifying that (Quotient)(Divisor) Remainder= Dividend. - 6x3+4x2-2 divided by x -1 Quotient Remainder:
The quotient is -6x^2-2x-2 and the remainder is -4.
To find the quotient and remainder for the given expression, we can use long division.
First, we divide the first term of the dividend (-6x^3) by the first term of the divisor (x) to get -6x^2. This is the first term of the quotient.
Next, we multiply the first term of the quotient (-6x^2) by the divisor (x-1) to get -6x^3+6x^2. We subtract this from the dividend to get -2x^2-2.
We repeat this process with the new dividend (-2x^2-2) and the same divisor (x-1). We divide the first term of the new dividend (-2x^2) by the first term of the divisor (x) to get -2x. This is the second term of the quotient.
We multiply the second term of the quotient (-2x) by the divisor (x-1) to get -2x^2+2x. We subtract this from the new dividend to get -2x-2.
We repeat this process one more time with the new dividend (-2x-2) and the same divisor (x-1). We divide the first term of the new dividend (-2x) by the first term of the divisor (x) to get -2. This is the third term of the quotient.
We multiply the third term of the quotient (-2) by the divisor (x-1) to get -2x+2. We subtract this from the new dividend to get -4. This is the remainder.
So, the quotient is -6x^2-2x-2 and the remainder is -4.
We can check our work by verifying that
(Quotient)(Divisor) + Remainder = Dividend:
(-6x^2-2x-2)(x-1) + (-4) = -6x^3+6x^2-2x^2+2x+2x-2-4 = -6x^3+4x^2-2
Therefore, our answer is correct.
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9.9=3.1 - 3.4x solve for x
Answer:
x = -2.
Step-by-step explanation:
9.9 = 3.1 - 3.4x
9.9 - 3.1 = -3.4x
6.8 = -3.4
6.8 /-3.4 = -3.4/-3.4
-2 = x
At a carnival, Ivan bought 14 packs of 9 tickets each. He also found 8 more tickets on the ground. How many tickets did Ivan have in all?
Answer: 134 tickets.
Step-by-step explanation:
Since we have 14 packs of 9 tickets, we can say it is 14 groups of 9. Which means we multiply. So 9 times 14 equals 126. But Ivan found 8 more tickets on the groud which means we add. so 126 plus 8 equals 134. The answer is 134 tickets.
Answer:
Step-by-step explanation:
multiply # of packs by # of tickets in each pack then add 8
14 x 9 = 126 + 8 = 134
Question 1 of 5, Step 1 of 1 One integer is 10 more than another. Their product is 375 . Find the integers.
The integers are 16.8 and 26.8. To find the integers, we need to use a system of equations. Let's call the first integer x and the second integer y. We know that one integer is 10 more than another, so we can write the first equation as: x = y + 10. We also know that their product is 375, so we can write the second equation as: xy = 375.
Now we can substitute the first equation into the second equation to solve for one of the integers.
y(y + 10) = 375
y^2 + 10y - 375 = 0
Using the quadratic formula, we can find the value of y:
y = (-10 ± √(10^2 - 4(1)(-375)))/2(1)
y = (-10 ± √1900)/2
y = (-10 ± 43.6)/2
y = 16.8 or y = -26.8
Since y has to be an integer, we can only use the value of 16.8.
So, y = 16.8 and x = 16.8 + 10 = 26.8.
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The cylinder below has a height of 31mm and a volume of 4700mm. Work out the radius of the cylinder. If your answer is a decimal, give it to two decimal places
Answer:
4700=πr²×31
4700/31=πr²
151.6.../π=r²
√151.6.../π=
6.946933566=r
r=6.95mm
Explain:
Volume of cylinder=
πr²×height
who knows, What is the area of a cross section that passes through the center of a sphere with a diameter of 7 centimeters? Express your answer in terms of π.
The area of a cross section that passes through the center of a sphere with a diameter of 7 centimeters will be 12.25π cm².
What is A sphere ?Three-dimensional objects with a sphere-like shape exist in all three dimensions. Three axes, the x-axis, y-axis, and z-axis, are used to define the sphere. The key distinction between a circle and a sphere is this. In contrast to other 3D shapes, a sphere lacks any vertices or edges.
The sphere's points are evenly spaced apart from one another on its surface. In light of this, the sphere's surface and core are always equally separated from one another. The sphere's radius is the measurement between these points. Ball, globe, planets, and other objects are all examples of spheres.
Given : Diameter of Sphere = 7 cm
∴ Radius = 7/2 = 3.5 cm.
Since It is a cross section in a sphere, so, it would be circle.
So, Area of the cross section = Area of circle
Hence, Area of Cross section = πr²
= π (3.5)²
= 12.25π cm²
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The points H(8,1), I(7,-5), and J(1, -4) form a triangle. Find the desired slopes and lengths, then fill in the words that characterize the triangle. - slope of HI = ____ slope of IJ = ___ slope of HJ= ___
- length of HI = ___ length of IJ = ___ length of HJ = ___
Triangle HIJ is _______ Submit Answer = √__
slope of HI = 6, slope of IJ = -1/6, slope of HJ = 5/7, length of HI = √37, length of IJ = √37, length of HJ = √74, Triangle HIJ is isosceles
The slope of a line is found by the formula (y2-y1)/(x2-x1). The length of a line is found by the formula √((x2-x1)²+(y2-y1)²).
Slope of HI = (1-(-5))/(8-7) = 6/1 = 6
Slope of IJ = (-5-(-4))/(7-1) = -1/6
Slope of HJ = (1-(-4))/(8-1) = 5/7
Length of HI = √((8-7)²+(1-(-5))²) = √(1²+6²) = √(1+36) = √37
Length of IJ = √((7-1)²+(-5-(-4))²) = √(6²+(-1)²) = √(36+1) = √37
Length of HJ = √((8-1)²+(1-(-4))²) = √(7²+5²) = √(49+25) = √74
Triangle HIJ is isosceles because it has two sides with the same length (HI and IJ).
- slope of HI = 6
- slope of IJ = -1/6
- slope of HJ = 5/7
- length of HI = √37
- length of IJ = √37
- length of HJ = √74
Triangle HIJ is isosceles
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23. F is the centroid of ACE. AD = 15x² + 3y. Write expressions to represent A. F and FD
In a triangle EAC, F is the centroid and two medians, then the required expressions are 10x² + 2y , 5x² +y respectively.
The centroid is the centre point of the object. It is a point at which three medians of a triangle meet. Properties :
The centroid is also called center of figure.The medians are divided into a two ratio one by the centroid.The centroid of a triangle is always inside a triangle.We have a triangle AEC, with centroid point F. Here, two medians of triangle AEC. Here, AD = 15x² + 3y, we have to determine the expression for bigger and smaller parts of median. As we know, centroid point F, divides median into ratio, 2: 1, i.e., bigger divided part/smaller divided part = 2/1
First expression for bigger divided part of median = (2/3) (15x² + 3y)
= 10x² + 2y
second expression for smaller divided part of median = (1/3) ( 15x² + 3y)
= 5x² + y
Hence, required expression are 10x² + 2y and 5x² + y.
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what is the answers thank you
Answer: 50in^2
Remember the formula for finding the area of a rectangle is:
A = (base)(height)
In this problem you find the area like so:
A = (12[tex]\frac{1}{2}[/tex])(4)
= ([tex]\frac{25}{2}[/tex])([tex]\frac{4}{1}[/tex])
= ([tex]\frac{25}{1}[/tex])([tex]\frac{2}{1}[/tex])
= 50in^2
HELP ME!! i don't really understand this!
Answer:
Step-by-step explanation:
lol sorry I know it but don’t know how up to right it sorry
OC EXPLANATION Two inequalities joined by the word and or the word or form a compound inequality. To solve the compound inequality, we first solve each inequality. 3u-2<=-14 or 4u+4<28
The solution to the compound inequality 3u-2<=-14 or 4u+4<28 is u<=-4 or u<6.
Determine the compound inequalityA compound inequality is an equation that combines two inequalities with the word "and" or "or".
To solve a compound inequality, we need to solve each inequality separately and then combine the solutions.
For the compound inequality 3u-2<=-14 or 4u+4<28, we will solve each inequality separately.
First, we will solve 3u-2<=-14: 3u-2<=-14 3u<=-14+2 3u<=-12 u<=-4
Next, we will solve 4u+4<28:
4u+4<28 4u<28-4 4u<24 u<6
Now, we will combine the solutions.
Since the word "or" is used in the compound inequality, the solution is the union of the two solutions. This means that the solution is any value of u that satisfies either inequality.
The solution is u<=-4 or u<6. This can also be written in interval notation as (-∞,-4] U (-∞,6).
So, the solution to the compound inequality 3u-2<=-14 or 4u+4<28 is u<=-4 or u<6.
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5. 25 it takes gallons of paint to paint a fence. How much paint is needed for 3/5 of the fence?
Answer:
If 2.5 gallons of paint are needed for the entire fence, then for 1/5 of the fence we need:
2.5 gallons / 5 = 0.5 gallons
To find how much paint is needed for 3/5 of the fence, we can multiply 0.5 gallons by 3:
0.5 gallons * 3 = 1.5 gallons
Therefore, 1.5 gallons of paint are needed for 3/5 of the fence.
Answer:
15 gallons
Step-by-step explanation:
1/5 of the fence would be 5 gallons, because 25/5 is 5, so to find how much paint for 3/5, we have to multiply 3 and 5 which gives us 15. We need 15 gallons of paint to paint 3/5 of the fence
Hope it helped!
A cylindrical jar of peanut butter has a height of 6 inches and a diameter of 4 inches. How many cubic inches of peanut butter can the jar hold? Use π = 3.14.
24 in3
75.36 in3
150.72 in3
301.44 in3
Therefore, the jar can hold 75.36 cubic inches of peanut butter.
The answer is B) 75.36 in3.
What is inch?An inch is a unit of measurement that is commonly used in the United States, United Kingdom, and other countries that follow the Imperial system of measurement. It is defined as 1/12th of a foot or 2.54 centimeters. In other words, there are 12 inches in a foot. The inch is often used to measure the length or width of small objects or to express the size of computer screens, TVs, and other electronic displays.
Given by the question.
The volume of a cylinder can be calculated using the formula: V = πr^2h, where r is the radius of the base of the cylinder and h is its height.
In this case, the jar has a diameter of 4 inches, which means the radius is 2 inches (diameter = 2 × radius). The height is given as 6 inches. So, we can calculate the volume of peanut butter that the jar can hold as follows:
V = π[tex]r^{2}[/tex]h
V = 3.14 × [tex]2^{2}[/tex] × 6
V = 3.14 × 4 × 6
V = 75.36 cubic inches
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How many people live in south african house- holds? to find out, we collected data from an srs of 48 out of the over 700,000 south african students who took part in the censusatschool survey proj- ect. The mean number of people living in a house-
Based on the sample of the 48 South African households collected from the Census At School survey project, the mean number of people living in a household will be 6.208, and the standard deviation is 2.576.
However, it is important to note that this sample only represents a small fraction of the total number of the households in South Africa, so we cannot make definitive conclusions about the entire population based on this sample alone.
To get a more accurate estimate of the number of people living in the South African households, a larger and the more representative sample would need to be collected.
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ve the compound inequality. 4v+3<=23 and 3v+4<1 te the solution in interval notation.
The solution to the compound inequality 4v + 3 <= 23 and 3v + 4 < 1 is v in the interval (-1, 5].
To solve the compound inequality, we need to solve each inequality separately and then find the intersection of the two solutions.
First, let's solve the inequality 4v+3<=23:
4v+3<=23
4v<=20
v<=5
Next, let's solve the inequality 3v+4<1:
3v+4<1
3v<-3
v<-1
Now, we need to find the intersection of the two solutions, which is the solution that satisfies both inequalities. The intersection of v<=5 and v<-1 is the interval (-1, 5].
So, the solution to the compound inequality is v in the interval (-1, 5]. In interval notation, this is written as (-1, 5].
Therefore, the solution to the compound inequality 4v+3<=23 and 3v+4<1 is v in the interval (-1, 5].
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Use the suggested substitution to write the expression as a
trigonometric expression. Simplify your answer as much as possible.
Assume 0≤θ≤π2.
√4x^2+100, x/5=tan(θ)
We are given the expression √4x^2+100 and the substitution x/5=tan(θ). Our goal is to use the substitution to write the expression as a trigonometric expression and simplify as much as possible.
First, let's substitute x/5=tan(θ) into the expression:
√4(tan(θ)*5)^2+100
Next, let's simplify the expression:
√4(25tan^2(θ))+100
√100tan^2(θ)+100
Now, let's factor out 100 from the expression:
√100(tan^2(θ)+1)
10√tan^2(θ)+1
Finally, let's use the trigonometric identity 1+tan^2(θ)=sec^2(θ) to simplify the expression further:
10√sec^2(θ)
10sec(θ)
Therefore, the expression √4x^2+100 can be written as 10sec(θ) using the substitution x/5=tan(θ).
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Choose all of thr terms thag correctly complete the statement.
The set of all first components of the ordered pairs of a
function are called the ____
-Elements
-Relation
-Independent Variable
- Range
The set of all first components of the ordered pairs of a function are called the Independent Variable.
In a function, the first component of the ordered pairs is known as the independent variable, which is the input value of the function. The second component of the ordered pairs is known as the dependent variable, which is the output value of the function. The set of all first components is also called the domain of the function, while the set of all second components is called the range of the function.
Therefore, the correct term to complete the statement is the Independent Variable.
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Bank of America charges $22 for each overdraft check. Kelsie has $370 in her account. She recently wrote checks for $46, $82, $264, and $127.
How much does she owe the bank including any overdraft charges?
Answer:
Step-by-step explanation:
Kelsie has written checks for a total of $46 + $82 + $264 + $127 = $519.
Since she only has $370 in her account, this means she has overdraft by $519 - $370 = $149.
Therefore, the bank will charge her $22 for each overdraft, which gives a total of $22 * 7 = $154.
Thus, Kelsie owes the bank a total of $519 + $154 = $673. Answer: \boxed{673}.
(a) Show that if φ : G → G′ is a homomorphism of groups, then
H = ker(φ) has the property that NG(H) = G. (b) Conclude that if G = D2n =
⟨r, s |rn = s2 = 1, rs = sr−1⟩ for n > 2, then there does not exist a group homomor-
phism φ : D2n →G′ to another group G′ such that ker(φ) = {1, s}.
There does not exist a group homomorphism φ : D2n → G′ such that ker(φ) = {1, s}.
(a) To show that NG(H) = G, we need to show that every element of G normalizes H. Let g ∈ G, and let h ∈ H. Since H = ker(φ), we know that φ(h) = 1. Now, we need to show that ghg⁻¹ ∈ H. Using the properties of a homomorphism, we can write:
φ(ghg⁻¹) = φ(g)φ(h)φ(g⁻¹) = φ(g)1φ(g⁻¹) = φ(g)φ(g⁻¹) = φ(gg⁻¹) = φ(1) = 1
Therefore, ghg⁻¹ ∈ H, and so g normalizes H. Since this is true for any g ∈ G, we can conclude that NG(H) = G.
(b) Suppose there exists a group homomorphism φ : D2n → G′ such that ker(φ) = {1, s}. Since s ∈ ker(φ), we know that φ(s) = 1. However, we also know that rs = sr⁻¹, and so φ(rs) = φ(sr⁻¹). Using the properties of a homomorphism, we can write:
φ(r)φ(s) = φ(s)φ(r⁻¹) = φ(s)φ(r)⁻¹
Since φ(s) = 1, this simplifies to:
φ(r) = φ(r)⁻¹
But this means that φ(r) is its own inverse, and so φ(r)² = 1. However, we also know that rn = 1, and so φ(rn) = 1. Using the properties of a homomorphism, we can write:
φ(rn) = φ(r)ⁿ = (φ(r)²)ⁿ/2 = 1ⁿ/2 = 1
But this means that n/2 must be an integer, which contradicts the fact that n > 2. Therefore, there does not exist a group homomorphism φ : D2n → G′ such that ker(φ) = {1, s}.
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Item 6
Write a unit rate for the situation.
Situation: 20 bracelets in 5 hours
Unit rate: ____bracelets per hour
Answer: 4 bracelets per hour
Step-by-step explanation:
You're basically finding the amount made in one hour instead of 5, so we just use an equation:
20 = 5x
x = 4
4 are made in an hour. Hope this helps!
HELP HELP HELP
a student divided 3p^4-8x^2-11x+1 by x-2 using LONG DIVISION. Where did they go wrong?
First step is wrong (x-2) × 3x³ should be 3x⁴ - 6x³
not 6x²
Help ive been stuck on this for a while
The length of Diagonal is 14.73 unit.
What is Prism?A three-dimensional solid object called a prism has two identical ends. It consists of equal cross-sections, flat faces, and identical bases. Without bases, the prism's faces are parallelograms or rectangles.
Given:
l = 9, w= 10 and h= 6
The Formula for Diagonal length of Prism is:
d =√l² + w² + h²
Here, d = length of the diagonal, l = length of the rectangular base of the prism, w = width of the rectangular base of the prism, and h = height of the prism.
Substitute the value in the equation,
d =√9² + 10² + 6²
d =√81+ 100 + 36
d = √217
d = 14.73 units
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The amount of merchandise (in millions) that store A sold can be represented by A = 13x squared + 8x - 3. The amount of merchandise (in millions) that store B sold can be represented by B = 8x squared - 3x + 11. Find the total amount of merchandise that stores A and B sold.
The total amount of merchandise that stores A and B sold is 21x²+5x+8
What is equation?An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values.
For example, 3x + 5 = 15.
Given that, are two stores selling merchandise given by equation,
A = 13x²+8x-3 and B = 8x²-3x+11, we need to find the total amount of merchandise that stores A and B sold.
We add both the equations to find the same,
Total merchandise sold = 13x²+8x-3 + 8x²-3x+11
= 21x²+5x+8
Hence, the total amount of merchandise that stores A and B sold is 21x²+5x+8
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When Veronica visit great Britain one British pound was worth US$1.40 while AU$1.00 was worth US$0.70 in this case how many AU$ was a British pound worth 
In the given question, 1 British pound will be equal to AU$2.00.
What is Algebra?Algebra is a common thread that runs through almost all of mathematics. It is the study of variables and the principles for manipulating them in formulas. Since all mathematical uses involve manipulating variables as though they were numbers, elementary algebra is a prerequisite.
The area of mathematics known as algebra aids in the representation of situations or issues as mathematical expressions. To create a meaningful mathematical expression, it takes variables like x, y, and z along with mathematical processes like addition, subtraction, multiplication, and division.
What is Transitive Property?A homogeneous relation R over the set A, which includes the elements x, y, and z, is what mathematicians refer to as a transitive relation. If R relates x to y and y to z, then R also relates x to z.
In this question,
1£ = US$1.40 (Equation 1)
AU$1 = US$0.70 (Equation 2)
Multiplying equation 2 by 2, we get
AU$2 = US$1.40
Using equation 1, we can say that,
1£ = AU$2
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Geometry
Solve for x and y
The value of 'x' and 'y' in the given circle and triangle are 30 and 12 respectively.
What is a triangle?A triangle is a three-sided closed-plane figure formed by joining three noncolinear points.
Based on the side property triangles are of three types they are Equilateral triangle, Scalene triangle, and Isosceles triangle.
What is Pythagoras's theorem?In a right-angled triangle, the sum of the squares of the smaller two sides of a right-angle triangle is equal to the square of the largest side.
From the given information we can form,
x² = 18² + 24². (As tangent is always perpendicular to the radius).
x² = 900.
x = 30.
Now, y = x - radius.
y = 30 - 18.
y = 12.
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Givenf(x)=x2+3x+1g(x)=x2find:(f+g)(x)=(f−g)(x)=(f⋅g)(x)=(f/g)(x)=
Knowing the functions f(x) and g(x) we have:
(f+g)(x) = 2x² + 3x + 1(f-g)(x) = 3x + 1(f·g)(x) = x⁴ + 3x³ + x²(f/g)(x) = 1 + 3/x + 1/x²To find the sum, difference, product, and quotient of two functions, we simply perform the corresponding operations on the expressions for each function.
For (f+g)(x), we add the expressions for f(x) and g(x):
(f+g)(x) = (x² + 3x + 1) + (x^2) = 2x² + 3x + 1
For (f-g)(x), we subtract the expression for g(x) from the expression for f(x):
(f-g)(x) = (x² + 3x + 1) - (x²) = 3x + 1
For (f·g)(x), we multiply the expressions for f(x) and g(x):
(f·g)(x) = (x² + 3x + 1) · (x²) = x⁴ + 3x³ + x²
For (f/g)(x), we divide the expression for f(x) by the expression for g(x):
(f/g)(x) = (x² + 3x + 1) / (x²) = 1 + 3x/x² + 1/x² = 1 + 3/x + 1/x²
So, the final answers are:
(f+g)(x) = 2x² + 3x + 1
(f-g)(x) = 3x + 1
(f·g)(x) = x⁴ + 3x³ + x²
(f/g)(x) = 1 + 3/x + 1/x²
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