Answer:
55.563
Step-by-step explanation:
Given the following :
Mean(m) point = 73
Standard deviation( sd) = 10.6
Lower 5% will not get a passing grade (those below the 5% percentile)
For a normal distribution:
The z-score is given by:
z = (X - mean) / standard deviation
5% of the class = 5/100 = 0.05
From the z - table : 0.05 falls into - 1.645 which is equal to the z - score
Substituting this value into the z-score formula to obtain the score(x) which seperates the lower 5%(0.05) from the rest of the class
z = (x - m) / sd
-1.645 = (x - 73) / 10.6
-1 645 * 10.6 = x - 73
-17.437 = x - 73
-17.437 + 73 = x
55.563 = x
Therefore, the score which seperetes the lower 5% from the rest of the class is 55.563
please help me ☣️☢️☢️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️▫️
Answer:
(a) 27 degrees (nearest degree)
(b) 17.9 m (to one decimal place)
Step-by-step explanation:
Wow, that's along ladder, perhaps for the firemen!
From diagram,
(a)
sin(x) = 9 / 20 = 0.45
x = arcsin(0.45) = 26.74 degrees
(b)
height of wall ladder reaches
h = 20*cos(x) = 20*cos(26.74) = 17.86 m
In a survey from 1998, 449 teenagers were surveyed about the music that they listen to. Of these teenagers, 129 of them said that their favorite genre of music is hip-hop. In a similar survey from 2008, 176 of 509 teenagers surveyed said that their favorite genre is hip-hop. Use a two-proportion hypothesis test to determine whether the proportion of teenagers whose favorite genre of music is hip-hop has changed from 1998 to 2008. Assume that the samples are random and independent. Use α=0.01. Let the sample from 1998 correspond to sample 1 and the other to sample 2. (a) Which answer choice shows the correct null and alternative hypotheses for this test? Select the correct answer below: H0:p1=p2; Ha:p1p2, which is a right-tailed test. H0:p1=p2; Ha:p1≠p2, which is a two-tailed test.
Answer:
H0:p1=p2; Ha:p1≠p2, which is a two-tailed test.
Step-by-step explanation:
We formulate our hypotheses as
H0:p1=p2; Ha:p1≠p2, which is a two-tailed test.
Supposing the probability or proportion of the first survey is equal to the probability or proportion of the second survey. This will be the null hypothesis and the alternative hypotheses would be that these two proportions or probabilities are unequal.
This is a two tailed test.
In the year 2000, the population of Mexico was about 100 million, and it was growing by 1.53% per year. At this growth rate, the function f(x) = 100(1.0153)x gives the population, in millions, x years after 2000. Using this model, in what year would the population reach 111 million? Round your answer to the nearest year.
Answer: The population reach 111 million in 2007.
Step-by-step explanation:
In the year 2000, the population of Mexico was about 100 million, and it was growing by 1.53% per year.
At this growth rate, the function [tex]f(x) = 100(1.0153)^x[/tex] gives the population, in millions, x years after 2000.
Put f(x)=111 million.
Then,
[tex]111=100(1.0153)^x\\\\\Rightarrow\ (1.0153)^x=\dfrac{111}{100}=1.11\\\\\Rightarrow (1.0153)^x=1.11[/tex]
Taking log on both the sides , we get
[tex]x\log1.0153=\log1.11\\\\\Rightarrow\ x=\dfrac{\log1.11}{\log1.0153}=\dfrac{0.045323}{0.0066}=6.86712121212\approx7[/tex]
Hence, the population reach 111 million in 2007 (approx).
Brainliest for correct awnser Estimate the line of best fit using two points on the line.A.y = −8x + 80B.y = 4x + 80C.y = −4x + 80D.y = 8x + 80
Answer:
A.y = −8x + 80B
Step-by-step explanation:
first you have to find the slope :
P1(2,64). P2(6,32)
slope=Y2-Y1/X2-X1
slope=64-32/2-6
slope= -8
y= -8x + b. now solve for "b" by using one of the coordinates given above.
y= -8x + b. I will use coordinate p(2,64)
64= -8(2) + b
64 + 16 = b
80= b
you can use any of the coordinates i.e either P1(2,64)or P2(6,32) it doesn't affect the value of "b".
line of equation is :
.y = −8x + 80B
Answer: y= -8x+80
Step-by-step explanation:
Find the value of annuity if the periodic deposit is $250 at 5% compounded quarterly for 10 years
Answer:
The value of annuity is [tex]P_v = \$ 7929.9[/tex]
Step-by-step explanation:
From the question we are told that
The periodic payment is [tex]P = \$ 250[/tex]
The interest rate is [tex]r = 5\% = 0.05[/tex]
Frequency at which it occurs in a year is n = 4 (quarterly )
The number of years is [tex]t = 10 \ years[/tex]
The value of the annuity is mathematically represented as
[tex]P_v = P * [1 - (1 + \frac{r}{n} )^{-t * n} ] * [\frac{(1 + \frac{r}{n} )}{ \frac{r}{n} } ][/tex] (reference EDUCBA website)
substituting values
[tex]P_v = 250 * [1 - (1 + \frac{0.05}{4} )^{-10 * 4} ] * [\frac{(1 + \frac{0.05}{4} )}{ \frac{0.08}{4} } ][/tex]
[tex]P_v = 250 * [1 - (1.0125 )^{-40} ] * [\frac{(1.0125 )}{0.0125} ][/tex]
[tex]P_v = 250 * [0.3916 ] * [\frac{(1.0125)}{0.0125} ][/tex]
[tex]P_v = \$ 7929.9[/tex]
Discuss the validity of the following statement. If the statement is always true, explain why. If not, give a counterexample. If the 2 times 2 matrix P is the transition matrix for a regular Markov chain, then, at most, one of the entries of P is equal to 0. Choose the correct answer below. A. This is false. In order for P to be regular, the entries of P^k must be non-negative for some value of k. For k=1 the matrix Start 2 By 2 Table 1st Row 1st Column 0 2nd Column 1 2nd Row 1st Column 0 2nd Column 1 EndTable has non-negative entries and has two zero entries. Thus, it is a regular transition matrix with more than one entry equal to 0. B. This is true. If there is more than one entry equal to 0, then the number of entries equal to zero will increase as the power of P increases. C. This is true. If there is more than one entry equal to 0, all powers of P will contain 0 entries. Hence, there is no power k for which Upper P Superscript k contains all positive entries. That is, P will not satisfy the definition of a regular matrix if it has more than one 0. D. This is false. The matrix P must be regular, which means that P can only contain positive entries. Since zero is not a positive number, there cannot be any entries that equal 0.
Answer:
C. This is true. If there is more than one entry equal to 0, all powers of P will contain 0 entries. Hence, there is no power k for which Upper P Superscript k contains all positive entries. That is, P will not satisfy the definition of a regular matrix if it has more than one 0
Step-by-step explanation:
The correct option is C as it represents that by considering a matrix P that involves more than one zero and at the same time the powers for all P has received minimum one zero or it included at least one zero
Therefore the statement C verified and hence it is to be considered to be valid
Hence, all the other statements are incorrect
3^x = 27^a+b and a^2-b^2/(a-b)=5 What is x?
A sample of 32 boxes of cereal has a sample standard deviation of 0.81 ounces. Construct a 95% confidence interval to estimate the true standard deviation of the filling process for the boxes of cereal.
a. (0.656, 1.064)
b. (0.520, 1.100)
c. (0.430, 1.132)
d. (0.729, 0.729)
e None of the above
Answer:
a. (0.656, 1.064)
Step-by-step explanation:
The sample of cereal is :
n = 32, Standard deviation = 0.81
The confidence interval is 95%
degrees of freedom = df = 31 (n - 1)
[tex]\alpha[/tex] = 95%
1 - 0.95 = 0.05
1 - [tex]\frac{ \alpha }{2}[/tex]
1 - 0.025 = 0.975
Using chi square distribution we get,
0.656, 1.064
Based on a poll, among adults who regret getting tattoos, 12% say that they were too young when they got their tattoos. Assume that ten adults who regret getting tattoos are randomly selected, and find the indicated probability.
Required:
a. Find the probability that the number of selected adults saying they were too young is 0 or 1.
b. Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.
c. Find the probability that none of the selected adults say that they were too young to get tattoos.
Answer:
a. 0.6588
b. 0.3978
c. 0. 279
Step-by-step explanation:
In the given question the success and failure are given the number of outcomes is fixed so binomial distribution can be applied.
Here success= p = 12 % or 12/100 = 0.12
failure = q= 1-p = 1-0.12 = 0.88
n= 10
Using binomial probability distribution
a. Probability that the number of selected adults saying they were too young is 0 or 1 is calculated as:
P (x=0,1) = 0.12 ⁰(0.88)¹⁰10 C0 + 0.12 (0.88)⁹ 10 C1= 1* 0.279 * 1 + 0.12 ( 0.3165) 10 = 0. 279 + 0.3978= 0.6588
b. Probability that exactly one of the selected adults says that he or she was too young to get tattoos is calculated as
P (x=1) = 0.12 (0.88)⁹ 10 C1= 0.12 ( 0.3165) 10 = 0.3978
c. Probability that none of the selected adults say that they were too young to get tattoos is
P (x=0) = 0.12 ⁰(0.88)¹⁰10 C0 = 1* 0.279 * 1 = 0. 279
If m
X=49, y=41
X=90, y= 49
X=41, y =49
X=90, y=41
Answer:
x=90 degrees and y=41 degrees.
Step-by-step explanation:
In the diagram
[tex]AB=AC\\$Therefore \triangle ABC$ is an isosceles triangle[/tex]
[tex]m\angle C=49^\circ[/tex]
Since ABC is Isosceles
[tex]m\angle B=m\angle C=49^\circ $ (Base angles of an Isosceles Triangle)[/tex]
[tex]m\angle A+m\angle B+m\angle C=180^\circ $ (Sum of angles in a Triangle)\\m\angle A+49^\circ+49^\circ=180^\circ\\m\angle A=180^\circ-(49^\circ+49^\circ)\\m\angle A=82^\circ[/tex]
[tex]m\angle x=90^\circ $(perpendicular bisector of the base of an isosceles triangle)[/tex]
[tex]m\angle y=m\angle A \div 2 $ (perpendicular bisector of the angle at A)\\m\angle y=82 \div 2\\m\angle y=41^\circ[/tex]
Therefore:
x=90 degrees and y=41 degrees.
In an ESP experiment subjects must predict whether a number randomly generated by a computer will be odd or even. (Round your answer to four decimal places.) (a) What is the probability that a subject would guess exactly 18 correct in a series of 36 trials
Answer: The answer is 0.1350
Step-by-step explanation:
Given data
n=36
p=1/2
q=1/2
X=18
O=3
U = 18
a. With n = 36 and p = q = 1/2, you may use the normal approximation with µ = 18 and o = 3. X = 18 has real limits of 17.5 and 18.5 corresponding to z = -0.17 and z = +0.17. p = 0.1350.
The probability that a subject would guess exactly 18 correct in a series of 36 trials is 0.1350.
Given that,
ESP experiment subjects must predict whether a number randomly generated by a computer will be odd or even.
We have to determine,
What is the probability that a subject would guess exactly 18 correct in a series of 36 trials?
According to the question,
Number of trials n = 36
The probability must per whether a number randomly generated by a computer will be odd is 1/2 or even is 1/2.
By using the normal approximation,
[tex]\mu = 18 \ and \ \sigma = 3[/tex]
Therefore,
X = 18 has real limits of 17.5 and 18.5 corresponding to z = -0.17 and z = +0.17.
p = 0.1350
Hence, the probability that a subject would guess exactly 18 correct in a series of 36 trials is 0.1350.
To know more about Probability click the link given below.
https://brainly.com/question/17090368
In 2005, there were 14,100 students at college A, with a projected enrollment increase of 750 students per year. In the same year, there were 42,100 students at college B, with a projected enrollment decline of 1250 students per year. According to these projections, when will the colleges have the same enrollment? What will be the enrollment in each college at that time?
Set up two equations and set equal to each other. Let number of years = x:
College A = 14100+750x
College B = 42100-1250x
Set equal:
14100 + 750x = 42100 - 1250x
Subtract 750x from both sides:
14100 = 42100 - 2000x
Subtract 42100 from both sides:
-28000 = -2000x
Divide both sides by -2000:
x = -28000 / -2000
x = 14
It will take 14 years for the schools to have the same enrollment.
Enrollment will be:
14100 + 750(14) = 14100 + 10500 = 24,600
Answer:
(a)2019 (14 years after)
(b)24,600
Step-by-step explanation:
Let the number of years =n
College A
Initial Population in 2005 = 14,100
Increase per year = 750
Therefore, the population after n years = 14,100+750n
College B
Initial Population in 2005 = 42,100
Decline per year = 1250
Therefore, the population after n years = 42,100-1250n
When the enrollments are the same
14,100+750n=42,100-1250n
1250n+750n=42100-14100
2000n=28000
n=14
Therefore, in 2019 (14 years after), the colleges will have the same enrollment.
Enrollment in 2019 =42,100-1250(14)
=24,600
Solve for x: 4 over x plus 4 over quantity x squared minus 9 equals 3 over quantity x minus 3. (2 points) Select one: a. x = -4 and x = -9 b. x = 4 and x = -9 c. x = -4 and x = 9 d. x = 4 and x = 9
Answer:
c. x = -4 or x = 9Step-by-step explanation:
[tex]\dfrac{4}{x}+\dfrac{4}{x^2-9}=\dfrac{3}{x-3}[/tex]
Domain:
[tex]x\neq0\ \wedge\ x^2-9\neq0\ \wedge\ x-3\neq0\\\\x\neq0\ \wedge\ x\neq\pm3[/tex]
solution:
[tex]\dfrac{4}{x}+\dfrac{4}{x^2-3^2}=\dfrac{3}{x-3}[/tex]
use (a - b)(a + b) = a² - b²
[tex]\dfrac{4}{x}+\dfrac{4}{(x-3)(x+3)}=\dfrac{3}{x-3}[/tex]
multiply both sides by (x - 3) ≠ 0
[tex]\dfrac{4(x-3)}{x}+\dfrac{4(x-3)}{(x-3)(x+3)}=\dfrac{3(x-3)}{x-3}[/tex]
cancel (x - 3)
[tex]\dfrac{4(x-3)}{x}+\dfrac{4}{x+3}=3[/tex]
subtract [tex]\frac{4(x-3)}{x}[/tex] from both sides
[tex]\dfrac{4}{x+3}=3-\dfrac{4(x-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x}{x}-\dfrac{(4)(x)+(4)(-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-\bigg(4x-12\bigg)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-4x-(-12)}{x}\\\\\dfrac{4}{x+3}=\dfrac{-x+12}{x}[/tex]
cross multiply
[tex](4)(x)=(x+3)(-x+12)[/tex]
use FOIL
[tex]4x=(x)(-x)+(x)(12)+(3)(-x)+(3)(12)\\\\4x=-x^2+12x-3x+36[/tex]
subtract 4x from both sides
[tex]0=-x^2+12x-3x+36-4x[/tex]
combine like terms
[tex]0=-x^2+(12x-3x-4x)+36\\\\0=-x^2+5x+36[/tex]
change the signs
[tex]x^2-5x-36=0\\\\x^2-9x+4x-36=0\\\\x(x-9)+4(x-9)=0\\\\(x-9)(x+4)=0[/tex]
The product is 0 if one of the factors is 0. Therefore:
[tex]x-9=0\ \vee\ x+4=0[/tex]
[tex]x-9=0[/tex] add 9 to both sides
[tex]x=9\in D[/tex]
[tex]x+4=0[/tex] subtract 4 from both sides
[tex]x=-4\in D[/tex]
i dont understand how to find Which ordered pair is a solution of the equation? y=8x+3
Answer:
Step 1:
To find ordered pair solutions, you could create an x and y graph and fill out the x side. Then, plug in an x number to get your y number and graph the ordered pairs to see if they give you a straight line. I'm going to use these numbers: -1, 0, 1, and 2.
[tex]...x...|...y...[/tex]
[tex]\left[\begin{array}{ccc}-1&?\\0&?\\1&?\\2&?\end{array}\right][/tex]
Now, let's plug in -1 into the equation first to see what we get for y.
[tex]y=8(-1)+3\\y=-8+3\\y=-5\\(-1,-5)[/tex]
-5 is our y if x was -1.
We do the same for the other three numbers.
[tex]y=8(0)+3\\y=0+3\\y=3\\(0,3)[/tex]
[tex]y=8(1)+3\\y=8+3\\y=11\\(1,11)[/tex]
[tex]y=8(2)+3\\y=16+3\\y=19\\(2,19)[/tex]
Step 2:
With all that done, we can now fill out our table and graph the points.
[tex]....x...|...y....[/tex]
[tex]\left[\begin{array}{ccc}-1&-5\\0&3\\1&11\\2&19\end{array}\right][/tex]
If you graph these points on graph paper / a graphing website, you will see that these points go in a straight line. If you are given an ordered pair already (for example: (3,5)), then all you have to do is plug in the x into the equation (3) and see if the outcome is true (5).
[tex]5=8(3)+3\\5=24+3\\5\neq 27[/tex]
Since they don't equal each other, then (3,5) is false.
Here is the graph for the table above. I hope I helped you!
Lets go over the solutions.
Let's start with (1, 11). After substituting x = 1 and y = 11, it results in the equation 11 = 11, which is a true statement. Hence, this is one solution.
Now, let's look at (-1 -5). After substituting x = -1 and y = -5, it results in the equation -5 = -5, which is also a true statement. So, this being said, (-1, -5) would also be a solution.
Hence, our two solutions are:
Both [tex](1, 11)[/tex] and [tex](-1, -5)[/tex].
Hope this helps!
Which statements are true about these lines? Select three options.
The slope of line MN is Two-thirds.
The slope of line PQ is undefined.
The slope of line RS is Negative three-halves.
Lines RS and TV are parallel.
Line RS is perpendicular to both line MN and line PQ
Answer:
A) The slope of line MN is Two-thirds.
C) The slope of line RS is Negative three-halves.
E) Line RS is perpendicular to both line MN and line PQ.
Step-by-step explanation:
i did the work
Let f(x)=6x and g(x)=x+4 what’s the smallest number that’s in the domain of F(G)
Answer:
(-4) will be the smallest value.
Step-by-step explanation:
Two functions have been given in this question,
f(x) = [tex]\sqrt{6x}[/tex] and g(x) = x + 4
Then the composite function (fog)(x) will be,
(fog)(x) = f[g(x)]
f[g(x)] = [tex]\sqrt{6(x+4)}[/tex]
Since this function is defined for (x + 4) ≥ 0
(x + 4) - 4 ≥ 0 - 4
x ≥ -4
Domain of this function : [-4 ∞)
Therefore, the smallest number in the domain or smallest value for 'x' should be (-4).
3/4 (1/2x - 12) + 4/5 HELP
Answer:
3/8x - 9 4/5
Step-by-step explanation:
Well we need to simplify the following expression,
[tex]\frac{3}{4} (\frac{1}{2}x - 12) + \frac{4}{5}[/tex]
So we need to distribute 3/4 to (1/2x - 12)
3/8x - 9 + 4/5
3/8x - 9 4/5
Thus,
the answer is 3/8x - 9 4/5.
Hope this helps :)
Cirlce B is given the equation, (x-2)^2 + (y-9)^2 = 25. What are the coordinates of the center and the length of the radius?
Answer:
The answer to your question is Center = (2, 9) Radius = 5 units
Step-by-step explanation:
Data
(x - 2)² + (y - 9)² = 25
Process
1.- Determine the coordinates of the circle.
The coordinates are the numbers after the x and y just change the signs.
h = 2 and k = 9
Then the coordinates are (2, 9)
2.- The length of the radius is the square root of the number after the equal sign.
radius = [tex]\sqrt{25}[/tex]
radius = 5 units
Solve by using logarithms, not the same base. I have absolutely no clue how to solve so any help would be amazing, thanks
Answer:
-5/48
Step-by-step explanation:
(8 · 2⁷ˣ)⁴ = (1/16)⁵ˣ · 128
Take log of both sides.
log (8 · 2⁷ˣ)⁴ = log ((1/16)⁵ˣ · 128)
Use log exponent/product rules.
4 log (8 · 2⁷ˣ) = log (1/16)⁵ˣ + log 128
Use log exponent/product rules.
4 (log 8 + log (2⁷ˣ)) = 5x log (1/16) + log 128
Use log exponent rule.
4 (log 8 + 7x log 2) = 5x log (1/16) + log 128
Distribute.
4 log 8 + 28x log 2 = 5x log (1/16) + log 128
Write as powers of 2.
4 log 2³ + 28x log 2 = 5x log (2⁻⁴) + log 2⁷
Use log exponent rule.
12 log 2 + 28x log 2 = -20x log 2 + 7 log 2
Combine like terms.
5 log 2 + 48x log 2 = 0
Divide by log 2.
5 + 48x = 0
Solve for x.
x = -5/48
Six years ago, an investor purchased a downtown apartment complex and an adjacent piece of land. The current value of the property is $850,000. Of the total, the current value of the apartment complex is $710,000 and the current value of the land is $140,000. Using the straight-line method, assuming an average appreciation of 6% on the land and an average depreciation of 3% on the apartment complex, what was the original value of the property? Round your answer to the nearest dollar.
Answer: $951,064.06 would be your answer.
Step-by-step explanation: Hope that helped!
What are the trigonometric ratios? Write all six.
Step-by-step explanation:
Check that attachment
Hope it helps :)
Hey! :)
________ ☆ ☆_________________________________________
Answer:
There are six trigonometric ratios, which will be under “Explanation”
Step-by-step explanation:
Trigonometric ratios are a measurements of a right triangle.
Here are the all the six trigonometric ratios.
1. cotangent (cot)
2. cosecant (csc)
3. cosine (cos)
4. secant (sec)
5. sine (sin)
6. tangent (tan)
Hope this helps! :)
_________ ☆ ☆________________________________________
By, BrainlyMember ^-^
Good luck!
An exterior angle of a triangle is 120° and one of the interior opposite angle is 50°. Find the other two angles of the triangle.
Answer:
interior angle (2)= 70
interior angle (3)= 60
Step-by-step explanation:
Given:
exterior angle=120°
interior angle (1)=50°
Required:
interior angle (2)=?
interior angle (3)=?
Formula:
exterior angle=interior angle (1) + interior angle (2)
Solution:
exterior angle=interior angle (1)+ interior angle (2)
120°=50°+interior angle (2)
120°+50°=interior angle (2)
70°=interior angle (2)
interior angle (3)= 180°-interior angle (1)- interior angle (2)
interior angle (3)=180°-50°+70°
interior angle (3)=180°-120°
interior angle (3)= 60°
Theorem:
Theorem 1.16
The measure of an exterior angle of a triangle is greater than either of the measures of the remote interior angles.
Hope this helps ;) ❤❤❤
Explain how to use the vertex and the value of “A” to determine the range of an absolute value function. PLEASE HELP!!
Answer:
First, a absolute value function is something like:
y = f(x) = IxI
remember how this work:
if x ≥ 0, IxI = x
if x ≤ 0, IxI = -x
Notice that I0I = 0.
And the range of this function is all the possible values of y.
For example for the parent function IxI, the range will be all the positive reals and the zero.
First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.
Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:
y ≥ A
Or all the real values equal to or larger than A.
if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:
y ≤ A
Or "All the real values equal to or smaller than A"
Look at the number pattern shown below:3 × 17 = 5133 × 167 = 5511333 × 1667 = 555111What will be 33333 × 166667?
Answer:
33333 x 166667 = 5555511111
I think that is the answer you wanted
Step-by-step explanation:
166667
x 33333
5555511111
Four buses carrying 198 students from the same school arrive at a football stadium. The buses carry, respectively 90, 33, 25, and 50 students. One of the students is randomly selected. Let X denote the number of students who were on the bus carrying the randomly selected student. One of the four bus drivers is also randomly selected. Let Y denote the number of students on her bus. a) Which of E[X] or E[Y] do you think is larger
Answer:
E[x] is larger
Step-by-step explanation:
I think E[x] is larger because the expected number of students on the bus of a randomly chosen student is larger.
This is because the higher the number of students present in a bus, the higher the probability that a randomly selected student would have been on that bus.
Whereas, for every driver to be chosen, the probability of any bus being chosen is 1/4 irrespective of the number of students in that particular bus
y (10) = -7.5*² (101² + 113x + 1652
Answer: What is the question to this?
Step-by-step explanation: thank you have a good day yup yup
Explain how estimating the quotient helps you place the first
digit in the quotient of a division problem.
Step-by-step explanation:
look at the picture and if you still need help let me know or if this doenst help then well im sorry lol
Explain what a directed line segment is and describe how you would find the coordinates of point P along a directed line segment AB that partitions AB so that the ratio of AP to PB is 3:1.
Answer: see below
Step-by-step explanation:
In order to partition line segment AB so that AP and PB have a ratio of 3 : 1
1) Find the x- and y-lengths of the segment AB.
2) Divide the x- and y-lengths by (3 + 1) to find the length of one section.
3) Add 3 times those lengths to point A to find point P ...or...
Subtract 1 times those lengths from point B to find point P.
For example: Consider A = (0, 0) and B = (4, 8)
1) The length from A to B is
x = 4-0 = 4
y = 8-0 = 8
2) Divide those by (3 + 1):
x = 4/4 = 1
y = 8/4 = 2
3) Add 3 times those values to A to find point P:
x = 0 + 3(1) = 3
y = 0+3(2) = 6
--> P = (3, 6)
Note: We could have also subtracted 1 from the x-value of B and 2 from the y-value of B to find that point P = (4-1, 8-2) = (3, 6)
Now we know that the distance from point A to point P is 3 times the distance from point P to point B.
Suppose that any baseball that has a coefficient of restitution that exceeds 0.625 is considered too lively. Based on the available data, what proportion of the baseballs in the sampled population are too lively
Answer:
hello some parts of your question is missing attached below is the missing parts of the question
Answer : The proportion of the baseballs in the sampled population that are too lively
P = x / n = 18 / 40 = 0.450
Step-by-step explanation:
coefficient of restitution > 0.625
Based on available data the proportion of the baseballs that is in the sampled population that are too lively can be calculated using the values below
n = 40
x = n ( p > 0.625 ) = 18
The proportion of the baseballs in the sampled population that are too lively
P = x / n = 18 / 40 = 0.450
a student took a test that had 60 questions.if he got 45 right,what percentage of the question did he get right?
Answer:
25 %
is your answer
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