at a location in europe, it is necessary to supply 300 kw of 60-hz power. the only powersource available operate at 50-hz. it is decided to generate the power by means of motor-generator set consisting of synchronous motor driving a synchronous generator. how manypoles should each of the two machines have in order to convert 50-hz to 60-hz power?

Answers

Answer 1

The synchronous motor should have 24 poles and the synchronous generator should have 20 poles in order to convert 50 Hz to 60 Hz power

Given that the location in Europe requires 300 kW of 60 Hz power and the only power source available operates at 50 Hz, it is decided to generate the power by means of a motor-generator set consisting of a synchronous motor driving a synchronous generator. It is required to find how many poles each of the two machines should have in order to convert 50 Hz to 60 Hz power.

Let the synchronous motor have ns number of poles and synchronous generator have ng number of poles.In a synchronous machine, the number of poles is directly proportional to the synchronous speed of the machine.

Hence, synchronous speed (n) is given by; n = 120f/p

where f is the frequency of the supply in Hz and p is the number of poles.

Since the generator is required to deliver power at 60 Hz, the synchronous speed of the generator should be 3600 RPM.∴ 3600 = 120 × 60 / ng

Solving this, we get;

[tex]n_g = 20[/tex]

Also, since the motor is supplied with a 50 Hz power supply, its synchronous speed should be 3000 RPM.∴ 3000 = 120 × 50 / [tex]n_s[/tex]

Solving this, we get; [tex]n_s[/tex] = 24

Therefore, the synchronous motor should have 24 poles and the synchronous generator should have 20 poles in order to convert 50 Hz to 60 Hz power.

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Related Questions

Physics is the branch of science that involves the study of physical phenomena in order to
establish patterns.

false
true

Answers

True. In order to develop patterns, the study of physical phenomena is considered to be a part of physics.

Is physics the scientific discipline that studies phenomena?

The field of research known as physics studies the interactions between the underlying elements of the cosmos and the structure of matter. Quantum mechanics is used to study very small objects, and general relativity is used to study everything in the universe.

Does a field of physical science that focuses on heavenly phenomena and objects fall under the category of natural science?

The study of celestial objects and space in general—basically, everything outside of Earth's atmosphere—is known as astronomy.

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A group of students is given a loop of wire connected to a light bulb and a bar magnet. They are asked to make the light bulb light up. N S Which of the following would cause the light bulb to glow?
a) Leaving the magnet at rest beside the light bulb. b) Moving the magnet next to the light bulb. c) Moving the magnet through the coil of wire. d) Leaving the magnet at rest inside the coil of wire.

Answers

The following would cause the light bulb to glow : c) Moving the magnet through coil of wire.

What causes the light bulb to glow?

When magnet moves through a coil of wire, it creates changing magnetic field that induces electric current in the wire. This current flows through light bulb, causing it to light up.

Bulbs work by sending electricity through curly tungsten filament. The long, twisting path increases electrical resistance faced by traveling electrons, heating filament to some 3000 K. At that temperature, filament glows with  warm yellowish white light.

LED bulb as compared to halogen lamps or incandescent bulbs, has much higher resistance on count of integrated power supply unit. The serial connection of glow lamp clamps the circuit even when the switch is turned off.

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P1 = 10 p2=20 v1=100 v2_ solve for v2

Answers

Answer:

p1:10 and v1:100

meaning p2 :20 andv2 :200

=200

what characteristic is shared by sunspots, solar flares, and coronal mass ejections? select the two correct responses.

Answers

The two correct responses that describe a characteristic shared by sunspots, solar flares, and coronal mass ejections are as follows:

They all are connected to the magnetic activity of the Sun.

They are all associated with the Sun's corona and solar atmosphere.

What are sunspots, solar flares, and coronal mass ejections?

Sunspots are dark areas on the surface of the sun. They have a cooler temperature than the surrounding area because they are regions where the magnetic fields prevent hot, plasma-carrying gases from moving in and out of the sun.

Solar flares are sudden, violent eruptions of energy on the sun's surface that release huge amounts of energy. They are also associated with the magnetic activity of the sun.

Coronal mass ejections (CMEs) are huge eruptions of plasma and magnetic fields from the sun's corona. They can have significant impacts on Earth's magnetosphere, and hence, on electrical power grids, satellite communications, and even GPS systems.

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I need help answer please.

Answers

Answer:the mass of the water in the bowl when it is placed in the freezer is 0.5 kg.

Explanation:To calculate the mass of the water in the bowl when it is placed in the freezer, we can use the formula:

mass = volume × density

The volume of the water is given as 500 cm³. To convert this to m³, we can use the conversion factor:

1 m³ = 1,000,000 cm³

So, the volume in m³ is:

500 cm³ × (1 m³ / 1,000,000 cm³) = 0.0005 m³

The density of water is given as 1000 kg/m³. Now we can calculate the mass:

mass = 0.0005 m³ × 1000 kg/m³ = 0.5 kg

15. The diagram shows an electric circuit including a photocell.
The photocell contains a metal plate X that is exposed to
electromagnetic radiation. Photoelectrons emitted from the
surface of the metal are accelerated towards the positive
electrode Y. A sensitive ammeter measures the current in the
circuit due to the photoelectrons emitted by the metal plate
X. The metal plate X has a work function of 2.2 eV. The
maximum kinetic energy of an emitted photoelectron from
this plate is 0.3eV.
5
KE/10-19 J
4
2
a) Calculate the energy of a single photon in eV and in joules.
b) Calculate the frequency of the incident electromagnetic radiation.
c) Deduce the effect on the current if the radiation has the same intensity, but the frequency is
greater than in (b).
16. A negatively charged metal plate is exposed to electromagnetic radiation of frequency (f). The
diagram below shows the variation with (f) of the maximum kinetic energy KEmax of the
photoelectrons emitted from the surface.
1
0-
0
2
6
a) Define the threshold frequency of a metal.
b)
+
8
Electroma
10
radiation
vacuum
12
f/10¹4 Hz
14
i. Explain how the graph shows that the threshold frequency of this metal is
5.0 x 10¹4 Hz.
ii. Calculate the work function of this metal in joules.

Answers

Answer:

15.

a) The energy of a single photon can be calculated using the equation: E = hf, where h is Planck's constant (6.63 x 10^-34 J s) and f is the frequency of the radiation. Thus, E = (6.63 x 10^-34 J s)(c/λ), where c is the speed of light (3.00 x 10^8 m/s) and λ is the wavelength of the radiation. Using the maximum kinetic energy of an emitted photoelectron (0.3 eV) and the work function of the metal plate (2.2 eV), we can find the energy of a single photon: E = 2.5 eV = 4.0 x 10^-19 J.

b) The maximum kinetic energy of a photoelectron can be related to the frequency of the radiation by the equation: KEmax = hf - Φ, where Φ is the work function. Thus, f = (KEmax + Φ)/h. Substituting the given values, we get: f = (0.3 + 2.2) eV/(6.63 x 10^-34 J s) = 3.4 x 10^14 Hz.

c) If the frequency of the radiation is increased, more photoelectrons will be emitted per unit time, so the current in the circuit will increase.

16. a) The threshold frequency of a metal is the minimum frequency of radiation required to emit photoelectrons from the surface of the metal.

i. The graph shows that the kinetic energy of the emitted photoelectrons is zero for frequencies below 5.0 x 10^14 Hz. This means that the photoelectrons are not emitted below this frequency, indicating that the threshold frequency is 5.0 x 10^14 Hz.

ii. The work function of the metal can be calculated using the equation: Φ = hf - KEmax, where h is Planck's constant and KEmax is the maximum kinetic energy of the emitted photoelectrons. At the threshold frequency, KEmax is zero, so Φ = hf. Substituting the given values, we get: Φ = (6.63 x 10^-34 J s)(5.0 x 10^14 Hz) = 3.32 x 10^-19 J.

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what is the current through a long straight wire if the magnetic field at a point 3.70 cm away is 1.70 t?

Answers

The current through the long straight wire is 45.7 A.

The magnetic field produced by a long straight wire carrying a current is given by the formula B = (μ0I)/(2πr), where B is the magnetic field, μ0 is the permeability of free space, I is the current, and r is the distance from the wire. Rearranging the formula to solve for I, we get I = (2πrB)/μ0.

Substituting the given values, we have B = 1.70 T and r = 0.0370 m. The permeability of free space μ0 is a constant equal to 4π × 10⁻⁷ T·m/A. Thus, we can calculate the current I as I = (2π0.0370 m1.70 T)/(4π × 10⁻⁷ T·m/A) = 45.7 A.

Therefore, the current through the long straight wire is 45.7 A.

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How do we know how much gravitational force objects have?

Answers

Answer:

understand Newton's second law of motion,F is equal to ma where F is the force ,m is the mass of the object,a is acceleration

Which fossil fuel has the highest heating value per pound?A) CoalB) OilC) Natural gas.

Answers

The correct answer is A) Coal. Coal has the highest heating value per pound compared to oil and natural gas.

This is due to the fact that coal has a higher carbon content and burns more slowly and steadily than other fossil fuels. To further explain, coal is a black or brown rock-like substance that is composed primarily of carbon.

It is formed over millions of years from the remains of ancient plants that were buried and subjected to high pressure and heat. Coal is typically burned to produce electricity and heat, and it is a primary energy source for many countries around the world.

Oil and natural gas are also fossil fuels, but they have lower heating values per pound than coal. Oil is a liquid petroleum product that is refined from crude oil and is used primarily as a transportation fuel.

Natural gas is a colorless, odorless gas that is primarily composed of methane and is used for heating, cooking, and electricity generation. While these fossil fuels are also important sources of energy, coal has the highest heating value per pound.

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A boy is swinging a ball attached to a string in a horizontal circle. What happens If the string snaps?

Answers

If the string snaps while a boy is swinging a ball attached to it in a horizontal circle, the ball will move tangentially away from the circle. This is because of the tendency of an object in motion to continue moving in a straight line, according to Newton's first law of motion.

At the moment when the string snaps, the ball is moving at a tangent to the circle, and it will continue to move in that direction due to its inertia. This means that the ball will no longer be moving in a circular path, but rather in a straight line.

The direction and speed of the ball after the string snaps will depend on the exact moment at which the string breaks and the velocity of the ball at that moment. If the boy is swinging the ball with a lot of force, the ball may travel quite far before it comes to a stop. On the other hand, if the boy is swinging the ball with less force, the ball may not travel very far at all before coming to a stop.

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the current in an electromagnet connected to a 240 v line is 17.5 a. at what rate must cooling water pass over the coil if water temperature is to rise no more than 6.5 k?

Answers

To determine the rate at which cooling water must pass over the coil, we need to find the power of the electromagnet and then use the specific heat capacity of water to calculate the required mass flow rate.

Explanation:

Step 1: Calculate the power of the electromagnet.
Power = Voltage x Current
Power = 240 V x 17.5 A = 4200 W

Step 2: Determine the specific heat capacity of water.
The specific heat capacity of water is approximately 4.18 J/(g ·K).

Step 3: Calculate the required mass flow rate.
Power = mass_ flow_ rate x specific_ heat_ capacity x temperature_ rise
4200 W = mass_ flow_ rate x 4.18 J/(g ·K) x 6.5 K

Rearrange the formula to find the mass flow rate:
mass_ flow_ rate = 4200 W / (4.18 J/(g· K) x 6.5 K)
mass_ flow_ rate = 4200 W / (27.17 J/g) = 154.54 g/s

So, the cooling water must pass over the coil at a rate of 154.54 g/s to keep the water temperature rise no more than 6.5 K.

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a 70 n force pulls a box straight up 5 m above the ground. if the box is not moving after it is lifted, what type of energy does it now have? a. chemical b. elastic c. gravitational d. kinetic

Answers

The box has gravitational energy. Therefore, option c is correct.

Gravitational potential energy is the energy an object has due to its position in a gravitational field. When the box is lifted to a height of 5m above the ground, it gains an amount of gravitational potential energy equal to the work done on it, which is equal to the force (70N) multiplied by the distance (5m).


When a 70 N force pulls a box straight up 5 m above the ground, and the box is not moving after it is lifted, the type of energy it now has is gravitational energy. Gravitational potential energy is the potential energy stored in an object because of its height over the Earth's surface. An object that has been lifted above the ground has the ability to do work when it falls back to the ground. The work is generated by the object's gravitational potential energy, which is a function of its mass and height over the ground.

As a result, the option c, gravitational, is the correct answer.

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one end of a 3.0-m rope is tied to a tree; the other end is tied to a car stuck in the mud. the motorist pulls sideways on the midpoint of the rope, displacing it a distance of 0.25 m. if he exerts a force of 200.0 n under these conditions, determine the force exerted on the car.

Answers

The force exerted on the car when motorist is pulling on the midpoint of the 3.0-m rope is 400 N.


The question involves the determination of the force exerted on the car when one end of a 3.0-m rope is tied to a tree; the other end is tied to a car stuck in the mud.

The motorist pulls sideways on the midpoint of the rope, displacing it a distance of 0.25 m. If he exerts a force of 200.0 N. Under these conditions, the force exerted on the car can be calculated as follows;

Since the displacement of the rope is perpendicular to the direction of the applied force, the component of the force perpendicular to the rope's direction must be considered. We can calculate the force perpendicular to the direction of the applied force as follows;

F_perpendicular = F x sinθ

where, F is the force exerted, and θ is the angle between the force and the direction of the rope (90°).

Therefore,

F_perpendicular = 200 x sin(90°) = 200 x 1 = 200 N

The force acting on the car is the force in the direction of the rope, which is equal to two times the force perpendicular to the rope direction. Therefore,

F_car = 2 x F_perpendicular

F_car = 2 x 200 N = 400 N

Therefore, the force exerted on the car is 400 N.

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a tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. her racket was traveling at 65 kilometers per hour. the ball accelerated at a rate of 10 meters per second squared. the ball hits the floor on the south end of the tennis court. the floor sends the ball toward the tennis player's opponent with the same acceleration. how much force did the floor on the south end of the court exert on the ball?(1 point)

Answers

The force exerted by the racket on the south end on the ball is 1.2 N.

Mass of the ball , m = 0.1 kg, velocity of the ball, v₁ = 65 km/h = 18.06 m/s. Distance travelled by the ball, S = 23.78.

S = v₁t + 1/2at²

23.78 = 18.06t + 5t²

t = 1.7 s

F = ΔP

F = mv₂ /t, F = 0.1 x 20.83/1.7 and F = 1.2 N.

A push or a pull that an object experiences as a result of interacting with another item is known as a force. some forces are the result of contact interactions (normal, frictional, tensional, and applied forces are examples of contact forces), whilst other forces (gravitational, electrical, and magnetic forces) are the consequence of action-at-a-distance interactions.

Thus, The force exerted by the racket on the south end on the ball is 1.2 N.

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the term we use to generally describe the total incoming solar energy from the sun to the earth is called

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The term we use to generally describe the total incoming solar energy from the sun to the Earth is called solar radiation or solar insolation.

This refers to the electromagnetic radiation emitted by the sun, which includes visible light, ultraviolet (UV) radiation, and infrared (IR) radiation, among others. Solar radiation is the primary source of energy that drives many Earth systems, such as the atmosphere, oceans, and land surface. It is responsible for warming the Earth's surface and fuels photosynthesis in plants, among other important processes. The amount and distribution of solar radiation that reaches the Earth's surface depend on various factors, including latitude, time of day, season, and atmospheric conditions.

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---The complete question is, the term we use to generally describe the total incoming solar energy from the sun to the earth is called ___________.------

an empty balloon sits 10 meters away from a golf ball. jamie wants to increase the gravitational force between the two objects by filling the balloon with a substance and holding it 10 meters away from the golf ball. which substance should jamie use to increase the gravitational force between the balloon and the golf ball the most?

Answers

Jamie should use Lead as the substance to increase the gravitational force between the balloon and golf ball the most.

The gravitational force between two objects is influenced by their masses and the separation between them. The gravitational force is calculated using the formula F = G × (m1 × m2) / r², where F is the gravitational force, G is the gravitational constant, m1, and m2 are the objects' masses, and r is the separation between them. Jamie has to either reduce the distance between the items or raise their masses in order to enhance the gravitational pull between the balloon and the golf ball.

The only way to increase the gravitational force since the separation is fixed at 10 meters is to increase the masses of the objects. As a result, Jamie ought to inflate the balloon with something heavy. Jamie may increase the balloon's mass and, as a result, the gravitational pull between the balloon and the golf ball by filling the balloon with lead.

Hence, Jamie should use Lead as the substance to increase the gravitational force between the balloon and golf ball the most.

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Three 21 ohm resistors are wired in parallel, what is the total resistance?​

Answers

Answer:

7 Ω

Explanation:

Given:

R1 = 21 Ω

The connection is parallel

Since all 3 of the resistors have the same resistance, we can use this formula to find the total resistance of the circuit:

R = R1/n (R1 is the resistance of one resistor and n is the number of resistors)

R = 21/3 = 7 Ω

you are riding in a train. since the train car is almost empty, you and your friend are pushing a cart (with almost no friction) back and forth between the front and rear of the car. the train is moving at a speed of 5.4m/s and each time you push the cart, the cart has a speed of 2.4m/s. what is the velocity of the cart relative to the ground when the cart is moving toward the front of the car

Answers

The relative velocity of the cart relative to the ground when the cart is moving toward the front of the car is 3 m/s.

Given Data:

Train's speed, v = 5.4 m/s

Cart's speed, u = 2.4 m/s

The relative velocity of the cart relative to the ground when the cart is moving toward the front of the car is to be determined. The velocity of an object in a moving frame is equal to the sum of the velocity of the object relative to the moving frame and the velocity of the moving frame. We know that the velocity of the train, v = 5.4 m/s

When the cart is moving forward, the velocity of the cart is the sum of the velocity of the train and the velocity of the cart relative to the train. Therefore, the velocity of the cart when it is moving toward the front is given as:

v = v_train + v_cart (towards the front)v_cart = v - v_trainv_cart = 5.4 - 2.4v_cart = 3 m/s

Therefore, the relative velocity of the cart relative to the ground when the cart is moving toward the front of the car is 3 m/s.

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Defferentiate between vector and scalar quantity giving relevannt example in case

Answers

A scalar quantity is a quantity that just has magnitude and no direction. Scalars include things like length, mass, speed. But a physical quantity is referred to as a vector quantity if it includes both magnitude and direction.

A number of physical quantities that each express a unique meaning and significance in that context can be used to explain each scientific explanation. A physical quantity is a measurable, quantifiable physical property that carries specific information, according to the definition. Physical quantities can be divided into the scalar and vector categories depending on how dependent they are on direction. These two numbers are used to depict an object's motion.

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what are the radii of a symmetric converging plastic lens (i.e., two equally curved surfaces) that will form an image on the screen twice the height of the object? (take the index of refraction of plastic to be 1.59.)

Answers

The radii of a symmetric converging plastic lens that will form an image on the screen twice the height of the object is [tex]R_1[/tex] = 4.28 cm and [tex]R_2[/tex] = 2.1333 cm.

The index of refraction of plastic is 1.59.

The height of the object = h

The height of the image = 2h

We know that the magnification formula is M = -v/u,

where M = -2 (since the height of the image is twice the height of the object),

v is the distance between the image and the lens and

u is the distance between the object and the lens.

Therefore, -v/u = -2 ... (1)

We also know that the lens formula is [tex]\frac{1}{v} - \frac{1}{u} = \frac{1}{f}[/tex],

where f is the focal length of the lens.

Since the lens is symmetric, the radius of curvature of the two surfaces will be equal, which is the same as the focal length of the lens.

Therefore, f = R/2, where R is the radius of curvature of the lens surfaces.

Substituting f = R/2 in the lens formula and simplifying it,

we get, u = 2f/3 ... (2)

We can get the value of v by substituting equation (2) in equation (1) and solving for v.

We get v = -4f/3.

Substituting u and v values in the lens formula, we get,

[tex]\frac{1}{v} - \frac{1}{u} = \frac{1}{f}[/tex], Solving for f, we get

f = 1.0667 cm.

We also know that f = R/2, so R = 2f.

Substituting f value, we get R = 2(1.0667) = 2.1333 cm.

The radii of the two surfaces of the lens will be equal, so [tex]R_1 = R_2[/tex] = 2.1333 cm.

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voltmeter is connected in parallel with loads why?​

Answers

Answer:A Voltmeter has very high resistance to ensure that it's connection do not alter flow of current in the circuit. Now if it is connected in series then no current will be there in the circuit due to it's high resistance. Hence it is connected in parallel to the load across which potential difference is to be measured.

Explanation:

after turning out the light for the night, your head hits the pillow. gradually, your muscles relax and drowsiness occurs. this drowsy yet wakeful state is associated with brain waves. question 25 options: a) alpha b) beta c) theta d) delta

Answers

After turning out the light for the night, your head hits the pillow. gradually, your muscles relax and drowsiness occurs. This drowsy yet wakeful state is associated with brain waves: Alpha. The correct option is A.

When turning out the light for the night, your head hitting the pillow signals the body to relax. Muscles loosen and drowsiness begins to set in, creating a state between wakefulness and sleep. This drowsy yet wakeful state is associated with brain waves, specifically alpha.

Alpha waves occur during a relaxed, awake state and are present when the eyes are closed. Beta waves appear during alertness and active thinking. Theta waves are associated with the beginning stages of sleep, but can also be present when an individual is in a relaxed, meditative state. Lastly, delta waves are the slowest brain waves and are only present during deep sleep.

In conclusion, when turning out the light for the night and your head hitting the pillow, your muscles relax and drowsiness occurs. This drowsy yet wakeful state is associated with brain waves, specifically alpha, beta, theta, and delta waves. These waves are categorized by their different frequencies and are associated with different states of consciousness.

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Two charged balloons, one black and one red, are separated by some distance r. The black balloon has 5 times the charge of the red balloon The black balloon exerts a force of F black-red on the red balloon, and the red balloon exerts a force of F red-black on the black balloon. How does the magnitude of F black-red compare to F red-black?​

Answers

The magnitude of F black-red compared to F red-black  5 times greater.

Gravitational force problem

The force exerted between two charged objects is given by Coulomb's law:

F = k * (q1 * q2) / r^2

where F is the force, k is Coulomb's constant, q1 and q2 are the charges of the two objects, and r is the distance between them.

Let's denote the charge on the red balloon as q_red and the charge on the black balloon as q_black. Since the black balloon has 5 times the charge of the red balloon, we can write:

q_black = 5 * q_red

Now let's consider the force exerted by the black balloon on the red balloon. According to Coulomb's law, this force is given by:

F_black-red = k * (q_black * q_red) / r^2

Substituting q_black = 5 * q_red, we get:

F_black-red = k * (5 * q_red * q_red) / r^2

Simplifying this expression, we get:

F_black-red = 5 * (k * q_red^2) / r^2

Similarly, the force exerted by the red balloon on the black balloon is given by:

F_red-black = k * (q_red * q_black) / r^2

Substituting q_black = 5 * q_red, we get:

F_red-black = k * (q_red * 5 * q_red) / r^2

Simplifying this expression, we get:

F_red-black = 5 * (k * q_red^2) / r^2

Comparing the two expressions, we can see that:

F_black-red = 5 * F_red-black

Therefore, the magnitude of the force exerted by the black balloon on the red balloon is 5 times greater than the magnitude of the force exerted by the red balloon on the black balloon.

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what is the strength of an electric field that will balance the weight of a proton? express your answer in newtons per coulomb to two significant figures.

Answers

The strength of an electric field that will balance the weight of a proton is 1.6 x 10^-18 N/C.

The strength of an electric field that will balance the weight of a proton is given by the Coulomb force formula which is F=Eq. Therefore, the electric field strength that balances the weight of a proton is given by:

E=qg

where E is the electric field strength, q is the charge of the proton, and g is the acceleration due to gravity.

Electric field strength (E) = qg

From the Coulomb's law, we know that, q = e = 1.60 x 10^-19 C

Also, the weight of the proton (F) is given by:

F = mg

where m is the mass of the proton and g is the acceleration due to gravity.

Therefore, the value of g is 9.81 m/s^2

Therefore,

F = m * g = (1.67 x 10^-27 kg) * (9.81 m/s^2) = 1.64 x 10^-26 N

Therefore, the electric field strength that balances the weight of a proton is:

E=qg = (1.60 x 10^-19 C) * (9.81 m/s^2) = 1.57 x 10^-18 N/C

Approximately, the electric field strength is 1.6 x 10^-18 N/C

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superman throws a boulder of weight 2200 n at an adversary. what horizontal force must superman apply to the boulder to give it a horizontal acceleration of 13.0 m/s2 ?

Answers

Superman must apply a horizontal force of 2918.5 N to the boulder to give it a horizontal acceleration of 13.0 m/s^2.

We can use Newton's second law, which states that force equals mass times acceleration. In this case, the mass of the boulder is not given, so we cannot directly calculate the force. However, we know that weight is equal to mass times the acceleration due to gravity (9.8 m/s^2), so we can use this relationship to determine the mass of the boulder.

[tex]2200 N = m * 9.8 m/s^2\\\Solving for mass, we get:\\\m = 224.5 kg[/tex]

We can use Newton's second law to find the horizontal force:

[tex]F = m * a = 224.5 kg * 13.0 m/s^{2 }= 2918.5 N[/tex]

Therefore, Superman must apply a horizontal force of 2918.5 N to the boulder to give it a horizontal acceleration of 13.0 m/s^2.

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1. If the astronaut in the picture has a mass of 100kg, the rock has a mass of 200kg and the rock gains a
velocity of 2 m/s to the right, what velocity does the astronaut gain to the left?

Answers

The astronaut gains a velocity of 4 m/s to the left.

What is Velocity?

The unit of velocity is meters per second (m/s) in the International System of Units (SI). Velocity can be positive or negative, depending on the direction of motion. A positive velocity means the object is moving in the positive direction, while a negative velocity means it is moving in the opposite direction.

According to the law of conservation of momentum, the total momentum of the system before the collision is equal to the total momentum after the collision, provided there are no external forces acting on the system.

Let's assume that the astronaut and the rock are initially at rest, so the total momentum before the collision is zero. After the rock is thrown to the right, the momentum of the system is:

P = m1 * v1 + m2 * v2

where m1 and v1 are the mass and velocity of the astronaut, m2 and v2 are the mass and velocity of the rock, and P is the total momentum.

Substituting the values given, we get:

P = 100 kg * v1 + 200 kg * 2 m/s

P = 100 kg * v1 + 400 kg*m/s

Since the total momentum of the system must be conserved, the total momentum after the collision must also be zero. Therefore:

P' = m1 * v1' + m2 * v2' = 0

where v1' and v2' are the final velocities of the astronaut and the rock, respectively.

We know that the rock gains a velocity of 2 m/s to the right, so its final velocity is v2' = 2 m/s. Substituting this into the above equation, we get:

100 kg * v1' + 200 kg * 2 m/s = 0

Solving for v1', we get:

v1' = -4 m/s

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a point mass of 1 grams located 5 centimeters to the left of the origin and a point mass of 3 grams located 7 centimeters to the right of the origin are connected by a thin, light rod. find the center of mass of the system.

Answers

The center of mass of the system is located 1.75 centimeters to the right of the origin.

The center of mass of the system can be found using the formula:

x_cm = (m1x1 + m2x2) / (m1 + m2)

Where x_cm is the center of mass, m1, and m2 are the masses of the two-point masses, and x1 and x2 are their respective positions.

Substituting the values given, we get:

x_cm = (1 gram * -5 cm + 3 grams * 7 cm) / (1 gram + 3 grams)

x_cm = (3 grams * 2 cm) / 4 grams

x_cm = 1.5 cm

Therefore, the center of mass of the system is located 1.5 centimeters to the right of the origin.

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Which situations show examples of work occurring? Check all that apply

Answers

Examples of work taking place include options 1, 2, and 3.

Work is said to be done when a force causes a displacement in an object in the direction of the force. The following situations are examples of work occurring:

Lifting a box off the ground: The force of lifting the box causes a displacement in the box in the upward direction, which is the same direction as the force applied. Therefore, work is done on the box.

Pushing a car up a hill: The force of pushing the car causes a displacement in the car in the direction of the hill, which is the same direction as the force applied. Therefore, work is done on the car.

Carrying a backpack: Although the backpack may not be moving, work is still being done because the force of carrying the backpack causes a displacement in the person's body in the upward direction.

Holding a heavy object: If a person is holding a heavy object, but not moving it, no work is being done on the object because there is no displacement. However, the person's muscles are still working to maintain the position, which is an example of isometric work.

Therefore, options 1, 2, and 3 are examples of work occurring. Option 4 is not an example of work being done on the object, but it is an example of work being done by the person's muscles.

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The electric field in a region of space is Ex = -1000 xV/m, where x is in meters. What is the potential difference between xi = −30cm and xf = 60cm? I got -900 but it is wrong.

Answers

The potential difference between xi = -30 cm and xf = 60 cm for the given electric field is -135 V.

To find the potential difference follow these steps:
1. Convert the given positions from centimeters to meters: xi = -0.3 m and xf = 0.6 m.
2. Calculate the potential difference using the formula ΔV = -∫(E(x) dx) over the interval [xi, xf].
3. Integrate the electric field function, Ex = -1000 x, with respect to x: ∫(-1000 x dx) = -500 x² + C, where C is the integration constant.
4. Find the potential difference by evaluating the integral at the given points: ΔV = -500 (xf² - xi^2) = -500 (0.6² - (-0.3)^2) = -500 (0.36 - 0.09) = -500 (0.27).
5. Calculate the result: ΔV = -500 * 0.27 = -135 V.

The potential difference between xi = -30 cm and xf = 60 cm for the given electric field is -135 V.

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What type of volcanic material indicates an eruption under water? a) AA flows b) Pyroclastic flows c) Pillow lavas d) Pahoehoe flows. e) Pillow lavas.

Answers

The type of volcanic material that indicates an eruption underwater is pillow lavas. So the correct answer is option C or E.

Pillow lavas are igneous rock formations that occur when magma extrudes from a volcano's vent and cools quickly under seawater or other bodies of water. When magma comes into contact with the water, it cools quickly and solidifies into what looks like a pile of stacked pillows. Pillow lavas are a clear indication of an underwater eruption. Pillow lavas are typically found in submarine basaltic volcanoes, which are located near mid-ocean ridges, and can be found in a variety of other underwater volcanic settings.

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