Answer:
2
Step-by-step explanation:
In order to make the equation undefined, you should make the denominator 0. Remember that dividing anything by 0 will become undefined.
[tex]2x-4=0\\\frac{2x=4}{2} \\x=2[/tex]
Answer:
[tex]\boxed{x = 2}[/tex]
Step-by-step explanation:
A rational expression is undefined when Denominator = 0
Here Denominator = 2x-4
So,
=> 2x - 4 = 0
Adding 4 to both sides
=> 2x = 4
Dividing both sides by 2
=> x = 2
(Pls do solution or take picture)In the figure, ACEF is a rectangle and BC = CD DE The area of rectangle ACEF is 80 cm. Find the area of the triangle BDF.
Answer:
28 cm²
Step-by-step explanation:
The area of Δ BDF is the area of the rectangle subtract the area of the 3 white triangles.
Since the area of the rectangle = 80 cm² and
area = length × breadth, then
breadth = 80 ÷ 10 = 8 cm
Thus CE = EF = 8 cm and CD = DE = BC = 4 cm
Area of Δ DEF = 0.5 × 10 × 4 = 20 cm²
Area of Δ ABF = 0.5 × 8 × (10 - 4) = 0.5 × 8 × 6 = 24 cm²
Area of Δ BCD = 0.5 × 4 × 4 = 8 cm²
Thus
area of Δ BDF = 80 - (20 + 24 + 8) = 80 - 52 = 28 cm²
Given the functions k(x) = 2x2 − 7 and p(x) = x − 4, find (k ∘ p)(x). (k ∘ p)(x) = 2x2 − 8x + 16 (k ∘ p)(x) = 2x2 − 16x + 32 (k ∘ p)(x) = 2x2 − 16x + 25 (k ∘ p)(x) = 2x2 − 11
Answer:
(k ∘ p)(x) = 2x² - 16x + 25Step-by-step explanation:
k(x) = 2x² - 7
p(x) = x - 4
To find (k ∘ p)(x) substitute p(x) into k(x),
that's replace any x in k(x) by p(x)
We have
(k ∘ p)(x) = 2(x - 4)² - 7
Expand
(k ∘ p)(x) = 2( x² - 8x + 16) - 7
= 2x² - 16x + 32 - 7
Simplify
We have the final answer as
(k ∘ p)(x) = 2x² - 16x + 25Hope this helps you
Answer:
(k ∘ p)(x) = 2x² - 16x + 25
Step-by-step explanation:
hope this helps
ANS ASAP... will mark him/her as BRAINLIEST The 1rst one!!
7x - 14 = 4x + 19
7x - 4x = 14 + 19
3x = 33
x = 11
write the equation of the parabola in vertex form.
Answer:
y = (x - 2)²
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (2, 0) , thus
y = a(x - 2)² + 0
To find a substitute the y- intercept (0, 4) into the equation
4 = a(- 2)² = 4a ( divide both sides by 4 )
a = 1
y = (x - 2)² ← equation of parabola in vertex form
John is planning a party. There are 28 pieces of carrot cake and 7 pieces of marble cake. He wants to create plates with the same number of each type of cake. What is the greatest number of plates he can create?
Answer:
Hey there!
He can create 7 plates at most, with one carrot cake and one marble cake on each plate.
Hope this helps :)
∆ABC is similar to ∆PQR. Corresponds to , and corresponds to . If the length of is 9 units, the length of is 12 units, the length of is 6 units, and the length of is 3 units, then the length of is
Complete question :
∆ABC is similar to ∆PQR. AB¯¯¯¯¯ corresponds to PQ¯¯¯¯¯, and BC¯¯¯¯¯ corresponds to QR¯¯¯¯¯. If the length of AB¯¯¯¯¯ is 9 units, the length of BC¯¯¯¯¯ is 12 units, the length of CA¯¯¯¯¯ is 6 units, and the length of PQ¯¯¯¯¯ is 3 units, then the length of QR¯¯¯¯¯ is ______units and the length of RP¯¯¯¯¯ is ________units.
Answer:
QR = 4 units ; RP = 2 units
Step-by-step explanation:
For similar triangles
Length1 ∆1/length1 ∆2 = Length 2 ∆1 /length 2∆2
AB Corresponds to PQ
BC corresponds to QR
AB = 9 Units, BC = 12 Units
CA = 6 units, PQ = 3 units
Take the ratio of the corresponding sides :
AB/ PQ = BC / QR
9/ 3 = 12 / QR
Cross multiply
9 * QR = 3 * 12
QR = 36 / 9
QR = 4 units
For RP:
AB/PQ = CA/RP
9 / 3 = 6 / RP
9 * RP = 3 * 6
RP = 18 / 9
RP = 2 units
Answer:
rp-2 qr-4
Step-by-step explanation:
The square pyramid shown below has a slant height of 171717 units and a vertical height of 151515 units. What is the length of one of the pyrmaids base?
The required length of the base is 18 units for the square pyramid.
The square pyramid shown below has a slant height of 17 units and a vertical height of 15 units. What is the length of one of the bases of the pyramid to be determined?
In a right-angled triangle, its side, such as hypotenuse, perpendicular, and the base is Pythagorean triplets.
The verticle height = 15
Slant height = 17
Let the base length be a,
For the half slant profile applying the Pythagorean theorem,
slant heigth² = vertical height² + base length ²
17² = 15² + ( a/2 )²
289 - 225 = ( a/2 )²
( a/2 )² = 64
a/2 =8
a = 16
Thus, the required length of the base is 18 units for the square pyramid.
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Please answer this in two minutes
Answer:
k = 4Step-by-step explanation:
It is half of equilateral triangle where 2√3 is its hight so:
[tex]2\sqrt3=\frac{k\sqrt3}2\\\\4\sqrt3=k\sqrt3\\\\k=4[/tex]
(2.5)
(1,1)
Write a rule for the linear function shown in the graph
Answer:
I guess y=2x+5
If you know the value of sin(30°), which of the following can you calculate directly through using the half angle formula?
cos(30°)
sin(45°)
sin(15°)
sin(60°)
Answer:
cos(30)
Step-by-step explanation:
Answer:
sin(15)
Step-by-step explanation:
If f(x)=3x-1 and g(x)= x+2 find (f-g)(x)
Answer:
[tex]\boxed{2x-3}[/tex]
Step-by-step explanation:
[tex]f(x)=3x-1\\ g(x)= x+2[/tex]
[tex](f-g)(x)\\f(x)-g(x)[/tex]
[tex](3x-1)-(x+2)\\ 3x-1-x-2\\2x-3[/tex]
-7
-4
-1
-2
y
7
14
35
56
slope:
Answer:
write the question correctly so I can help you
Step-by-step explanation:
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag
the item to the trashcan. Click the trashcan to clear all your answers.
Find the following expression by multiplying.
(a + b)2
Answer:
[tex]a^2+2ab+b^2[/tex]
Step-by-step explanation:
If we have [tex](a+b)^2[/tex] we can calculate this as:
[tex](a+b)*(a+b)[/tex]
So, applying distribution property, we get:
[tex](a+b)*(a+b)=a*a+a*b+b*a+b*b[/tex]
Where:
[tex]a*a=a^{2}[/tex]
[tex]b*b=b^2[/tex]
[tex]a*b=b*a=ab[/tex]
so:
[tex](a+b)*(a+b)=a^2-ab+ab+b^2\\(a+b)*(a+b)=a^2+2ab+b^2[/tex]
Identify the x-intercept and y-intercept of the line 4x−2y=−12. Select one: a. The x-intercept is (0,-3) and the y-intercept is (6,0). b. The x-intercept is (-3,0) and the y-intercept is (0,6). c. The x-intercept is (4,0) and the y-intercept is (0,-2). d. The x-intercept is (0,6) and the y-intercept is (-3,0).
Answer:
The answer is option BStep-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find the y intercept rewrite the equation in the above form
That's
4x - 2y =- 12
2y = 4x + 12
Divide both sides by 2
y = 2x + 6
comparing with the above formula the y intercept is 6
That's
(0 , 6)
The x intercept of a line the x coordinate on the line when y = 0
To find the x intercept let y = 0
That's
2x + 6 = 0
2x = - 6
Divide both sides by 2
x = - 3
The x intercept is - 3
That's
(- 3 , 0)
Hope this helps you
Answer:
the answer is x=-3 and y=6 so that means it is B.
4x-2y=-12
then; plug in 0 for x and then solve;
y=6
then do the same for the other side. plug in 0 for y and then solve.
x=-3
Hope this helps!
Please help me solve this problem
Answer:
iv, ii, i, iii, vi, v
Step-by-step explanation:
First, it is better if you fix all of these into fractions:
2/3--> 0.6666
-4/5--> -0.8
7/4--> 1.75
-21/8--> -2.625
11/4--> 2.75
root 5--> 2.24...
Hope this helps!!
Find ln 5.1 to the nearest thousandth
Answer:
5.1.
Step-by-step explanation:
5.1 = 5.1000. You would then round down to find the nearest thousandth, which is 5.1.
Hope this helps!
Answer:
Step-by-step explanation:
5.1
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.
Answer:
The third option is correct.
The domain of the function is given by
[tex]Domain = 0 \leq t \leq 40[/tex]
The range of the function is given by
[tex]Range = 0 \leq V(t) \leq 200[/tex]
Step-by-step explanation:
Sara bought a cell phone for $200 and its value has decreased at rate of $5 per month.
V(t) is the value of the phone and t is the number of months.
The domain of the function is the possible values of the number of months t.
The domain of the function is given by
[tex]Domain = 0 \leq t \leq 40[/tex]
The range of the function is the values of V(t) that we get after substituting the possible values of the number of months t.
The range of the function is given by
[tex]Range = 0 \leq V(t) \leq 200[/tex]
When the number of months is t = 0 then the value of the function is maximum V(t) = 200
When the number of months is t = 40 then the value of the function is minimum V(t) = 0
Therefore, the third option is correct.
The graph is a marginal cost curve that compares expenses for producing apple pies. According to the graph, the marginal cost begins to increase when the producer makes two pies. three pies. four pies. five pies.
The correct answer is C. Four pies
Explanation:
Marginal cost refers to an increase in the cost of production as additional units are made. In the case of apple pies, the graph shows the cost for one is $1.00. Moreover, this decreases when two or three pies are produced because the cost is between $0.60 and $0.30. However, if the producer makes four or more units, the cost increases. For example, at four units the cost per unit is $0.60, while at six units the cost is $1.50. Thus, the marginal cost begins to increase at four pies.
Answer: four pies
Step-by-step explanation:
The graph is a marginal cost curve that compares expenses therefore it would equal four pies because the marginal cost rises on the graph starting at 4.
Find the area of the shape shown below. I NEED HELP NOWWWWWW
Answer:
12.5 units[tex] {}^{2} [/tex]Step-by-step explanation:
Given figure : Trapezoid
Base sides,
a = 2.5
b = 7.5
Height ( h ) = 2.5
Now, finding the area:
[tex] \frac{1}{2} (a + b) \times h[/tex]
Plug the values
[tex] = \frac{1}{2 } \times (2.5 + 7.5) \times 2.5[/tex]
Calculate the sum
[tex] = \frac{1}{2} \times 10 \times 2.5[/tex]
Reduce the numbers with G.C.F 2
[tex] = 5 \times 2.5[/tex]
Calculate the product
[tex]12.5 \: \: {units}^{2} [/tex]
Hope this helps...
Best regards!
Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x(1/3) + 6x(4/3). You must justify your answer using an analysis of f ′(x) and f ′′(x).
Answer:
We have an extrema (local minimum) at x = -0.125
An inflection point at x = 0.25
Step-by-step explanation:
The given function is given as follows;
[tex]f(x) = 3x^{1/3} + 6x^{4/3}[/tex]
At the extrema points, f'(x) = 0 which gives;
[tex]0 = \dfrac{\mathrm{d} \left (3x^{1/3} + 6x^{4/3} \right )}{\mathrm{d} x} = \dfrac{(8 \cdot x+1) \times \sqrt[0.3]{x} }{x}[/tex]
(8x + 1) =x- (0/((x)^(1/0.3)) = 0
x = -1/8 = -0.125
f''(x) gives;
[tex]f''(x) = \dfrac{\mathrm{d} \left (\dfrac{(8 \cdot x+1) \times \sqrt[0.3]{x} }{x} \right )}{\mathrm{d} x} = \dfrac{ \left (\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right ) \times \sqrt[0.3]{x} }{x^3}[/tex]
Substituting x = -0.125 gives f''(x) = 32 which is a minimum point
The inflection point is given as follows;
[tex]\dfrac{ \left (\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right ) \times \sqrt[0.3]{x} }{x^3} = 0[/tex]
[tex]\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right }{} = 0 \times \dfrac{x^3}{ \sqrt[0.3]{x}}[/tex]
[tex]\dfrac{8}{3}\cdot x - \dfrac{2}{3} \right }{} = 0[/tex]
x = 2/3×3/8 = 1/4 = 0.25
We check the value of f''(x) at x = 0.24 and 0.26 to determine if x = 0.25 is an inflection point as follows;
At x = 0.24, f''(x) = -0.288
At x = 0.26, f''(x) = 0.252
0.25 is an inflection point
Please answer ASAP. The question is down below.
Answer: 1) c 2) a 3) d
Step-by-step explanation:
[tex]\cos \theta = \dfrac{adjacent}{hypotenuse}\quad \\\\\\\cos 42.1=\dfrac{4.7}{x}\\\\\\x=\dfrac{4.7}{\cos 42.1}\\\\\\\large\boxed{x=6.33}\\[/tex]
******************************************************************************************
Reference angle is the angle measurement from the x-axis. There is no such thing as a negative reference angle.
-183° is 3° from the x-axis so the reference angle is [tex]\large\boxed{3^o}[/tex]
*******************************************************************************************
Coterminal means the same angle location after one or more rotations either clockwise or counter-clockwise.
To find these angles, add or subtract 360° from the given angle to find one rotation, add or subtract 2(360°) from the given angle to find two rotations, etc.
To find ALL of the coterminals, add or subtract 360° as many times as the number of rotations. Rotations can only be integers. In other words, you can only have ± 1, 2, 3, ... rotations. You cannot have a fraction of a rotation.
Given: 203°
Coterminal angles: 203° ± k360°, k ∈ I
help please and thank you
Explanation:
You could use any two points you want. For me, the easiest is when x = 0. Plug this into the equation to get
y = 2x-7
y = 2(0)-7
y = -7
So we have x = 0 and y = -7 pair up to get (0,-7) as our first point. This is the y intercept.
Repeat for x = 1
y = 2x-7
y = 2(1)-7
y = -5
So (1,-5) is another point on this line. You only need two points at minimum to graph a straight line.
hamid has three boxes of different fruits. Box A weighs 5/4 kg more than Box B and Box C weighs 41/4 kg more than Box B. The total weight of the three boxes is 195/4 kg. What is weight of box a
Answer:
The answer is 39 kg
Step-by-step explanation:
We are looking for the weight of box A so we will use the number given to use for Box A.
We also have the total which is 194/4 kg
If we divide 195 by 5 we will get 39 kg
But to check if your answer is correct also divide 195 by 41 and that will give us 4.75 kg
And if you add the two answers up your will get 43.75 kg
Now we need to find the weight of Box B to see if our answer is correct
When you subtract 43.75 from 195 you will get 151.25
When we will add 43.75 to 151.25 you will get 195
So the answer is correct, the answer is 39 Kg
Which describes how to graph g (x) = RootIndex 3 StartRoot x minus 5 EndRoot + 7 by transforming the parent function?
Answer:
[tex]f(x) =\sqrt[3]{x}[/tex]
Step-by-step explanation:
Hello!
Considering the parent function, as the most simple function that preserves the definition. Let's take the function given:
[tex]g(x) = \sqrt[3]{x-5}+7[/tex]
To have the the parent function, we must find the parent one, let's call it by f(x).
[tex]f(x) =\sqrt[3]{x}[/tex]
This function satisfies the Domain of the given one, because the Domain is still [tex](-\infty, \infty)[/tex] and the range as well.
Check below a graphical approach of those. The upper one is g(x) and the lower f(x), its parent one.
Answer:
5 units to the right and 7 units up (B on edge)
Step-by-step explanation:
Help, I need answer ASAP
Step-by-step explanation:
HL states that a hypotenuse and leg of a right triangle must be congruent, so you would need to know the hypotenuses are congruent and a leg is congruent. For 6, You're only given 2 sides instead of 3, and since this is a Side-Side-Side Postulate, you must have the third sides be congruent. For 7, Angle-Side-Angle requires to known congruent angles and a side in between them, so you would need to know that angle I is congruent to angle L. Lastly, Side-Angle-Side needs two sides and an angle between them, so you would need to know that side JI is congruent to HD. HI is already congruent to itself by the Reflexive Property, so you only need to know JI ≅ HD.
which of the following rational functions are graphed below
Answer:
1st one
Step-by-step explanation:
The rational function which is graphed below is F(x)=-1/x, the correct option is B.
What is a function?Function is a type of relation, or rule, that maps one input to specific single output;
In mathematics, a function is an expression, rule, or law that describes the relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable). In mathematics and the physical sciences, functions are indispensable for formulating physical relationships;
Linear function is a function whose graph is a straight line;
We are given that;
The graph of the function
Now,
Points on 1/(x + 4);
The function y = 1/(x + 4) is a hyperbola. It has two branches that extend infinitely in opposite directions. The x-axis and y-axis are both asymptotes of the hyperbola.
Points on y= 1/x-4;
The function y = 1/(x - 4) is also a hyperbola. Its asymptotes are the vertical line x = 4 and the horizontal line y = 0;
Points on y = 1/(x-1);
The function y = 1/(x-1) is also a hyperbola. Its asymptotes are the vertical line x = -4 and the horizontal line y = 0.
Therefore, by the given graph function will be F(x)=-1/x;
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US
Find the value of x.
80
93
112
y
Z
x = [?]
Answer:
x = 74°
Step-by-step explanation:
The diagram shown in this question, is a Quadrilateral inscribed in a circle
It is important to note that
The sum of opposite angles in a Quadrilateral = 180°
93° + z = 180°
z = 180° - 93°
z = 87°
In a cyclic quadrilateral,
Intercepted angle = 1/2(Intercepted arc)
Intercepted angle = 93°
Intercepted arc = x + 112°
Hence,
93° = 1/2(x + 112)°
93° × 2 = x + 112°
186° = x + 112°
x = 186° - 112°
x = 74°
Answer:
It’s 87° for mine
Step-by-step explanation:
Find the product.
2a2(5b2+3ab+6a+1)
PLEASE HELP!!!! ASAP!!!
Answer:
[tex]10a^{2} b^{2} +6a^{3} b+12a^{3} +2a^{2}[/tex]
Step-by-step explanation:
Divide 3x^4 - 4x^3 -3x -1 by x-1 Verify using division algorithm Steps please thanks
Answer:
3x³ − x² − x − 4 + (-5/(x−1))
Step-by-step explanation:
Use long division (see attached picture).
Job A3B was ordered by a customer on September 25. During the month of September, Jaycee Corporation requisitioned $3,200 of direct materials and used $4,700 of direct labor. The job was not finished by the end of September, but needed an additional $3,700 of direct materials and additional direct labor of $7,900 to finish the job in October. The company applies overhead at the end of each month at a rate of 150% of the direct labor cost incurred. What is the balance in the Work in Process account at the end of September relative to Job A3B?
Answer: $14,950
Step-by-step explanation:
Given: Cost of Direct Materials = $3,200
Cost of direct labor = $4,700
Overhead rate = 150%
So, Overhead cost = 150% x (Total direct labor cost)
= $(150% x 4,700) =$ ( 1.5 x 4,700) [150% = 1.5]
= $7,050
Work in Progress = Direct Materials + Direct labor + Overhead
= $(3,200+4,700+7,050)
=$14,950
Hence, the balance in the Work in Process account at the end of September relative to Job A3B = $14,950