asap I have 2 minutes

pi x 2r = circ

2r = circ/pi

r = circ /(2 x pi) =  65.94/(2 x 3.14) = 10.5 feet

Answer:

k+5

Step-by-step explanation:

k= Elliot

Victoria is 5 years older than Elliot

=k+5

On a number line graph, the inequality X > 12 would be represented as follows:

A number line is a mathematical tool used to represent and visualize numbers, particularly real numbers, in a linear manner.

On a number line graph, the inequality X > 12 would be represented as follows(check attachment)

The line represents all real numbers, with the arrow pointing towards the right indicating that any number greater than 12 is a solution to the inequality. The circle at the end of the line is an open circle, indicating that 12 is not included in the solution set because the inequality is strict, i.e., X is strictly greater than 12.

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Answer: (-2,-3)

Step-by-step explanation:

Answer:
8. A) 3.75

9. B) 5.00

Answer:

The number line that shows ï > 7 would be from 8 to 10, as the symbol > means greater than. So the correct answer is B. Submit B.

Without the specific details or an image of the line segment on the coordinate grid, I'm unable to provide you with the specific numbers included in the range.

To help you generally, a line segment is a part of a line with two endpoints, and it is located on a coordinate grid, which is a two-dimensional plane formed by the intersection of horizontal and vertical lines (x and y axes).

To determine the range of the line segment, you need to identify the y-coordinates of the two endpoints.

The range includes all the y-coordinates between those two points, inclusive of the endpoints. To find the range, observe the line segment and note the y-coordinates of both endpoints. Then, list all the numbers (whole or fractional) between those values, including the endpoints themselves.

Once you have the necessary details or an image of the line segment, feel free to ask again, and I'll be happy to help you identify the numbers within the range.

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Answer:

what is 5+17894874298748

Answer:

Therefore, the total amount the Bells will pay for their house is $344,520.

Step-by-step explanation:

We can start by using the information about the monthly mortgage payment to calculate the total number of payments they will make over the 30-year term:

30 years × 12 months/year = 360 months

So the Bells will make 360 monthly payments of $957. To find the total amount they will pay for the house, we need to multiply the monthly payment by the number of payments:

$957/month × 360 months = $344,520

Therefore, the total amount the Bells will pay for their house is $344,520.

Give me the brainiest. thanks

Answer:

1 ⅓

Step-by-step explanation:

there 4 glasses and you put ⅓ in each one therefore 4 x ⅓ = 1 ⅓

By answering the presented question, we may conclude that Therefore, the solution set to the equation f(x) = 0 is {0}.

In mathematics, a function seems to be a link between two sets of numbers in which each member of the first set (known as the domain) corresponds to a specific member of the second set (called the range). In other words, a function takes input from one collection and creates output from another. The variable x has frequently been used to represent inputs, whereas the variable y has been used to represent outputs. A formula or a graph can be used to represent a function. For example, the formula y = 2x + 1 depicts a functional form in which each value of x generates a unique value of y.

the equation:

[tex]3x^2 + x^2 = 0\\4x^2 = 0\\x^2 = 0\\x = 0[/tex]

Therefore, the solution set to the equation f(x) = 0 is {0}.

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As a result, the original figure's corresponding sides and those of its enlarged image are parallel.

A quadrilateral is a closed, two-dimensional form in geometry that has four straight sides. Four sides, four edges, and four angles make up the polygonal shape. The total of a quadrilateral's internal angles is 360 degrees. Kites, squares, rectangles, parallelograms, and trapezoids are examples of quadrilaterals.

given

Each side of the original figure is expanded to meet the dilation scale factor when a quadrilateral is dilated from an outer centre of dilation, and the sides of the dilated image are parallel.

Parallel lines continue to be parallel after scaling because dilatation scales each side of the quadrilateral by a constant factor.

As a result, the original figure's corresponding sides and those of its enlarged image are parallel.

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a) 40 seconds is hypothesized mean b) mean time to solve problem by UBC students = 40 sec is null hypothesis c) Alternative hypothesis is time taken is different from 40 sec d) t = -2.353 h) 2% sample mean

Part a) The following variables are significant to this hypothesis test:

B. The null hypothesis is based on the assumption that it will take healthy Canadian adults an average of 40 seconds to solve the logic puzzle.

D. The test statistic is calculated using the sample mean, which is the average time it took the 80 UBC students to solve the logic puzzle.

D. Based on our sample data, we wish to determine the mean time it takes for all UBC students to complete the logic problem.

Part b) The null hypothesis would be that it took UBC students an average of 40 seconds to solve the logic puzzle.

The alternate hypothesis (part c) is that students at UBC take longer than 40 seconds on average to answer the logic puzzle (two-sided alternative).

Part d) You can compute the test statistic as:

t = [tex]\sqrt{sample size} / (sample standard deviation / hypothesised mean) / (sample mean - hypothesised mean)[/tex]

[tex]t = (36 - 40) / (17 / \sqrt{80} )[/tex]

t = -2.353

Part e) The normal distribution can be used to approximate the sampling distribution of the test statistic because the sample size is high (n = 80).

Part f) If we reject the null hypothesis, we can draw the conclusion that there is enough evidence to support the idea that UBC students took longer on average than healthy adult Canadians to solve the logic puzzle.

Part g) It's feasible that we are committing a Type I error if we determine that UBC students perform on average better than healthy adult Canadians (rejecting the null hypothesis when it is actually true).

Part h) If the null hypothesis is correct, a p-value of 0.02 indicates that there is a 0.02 chance of receiving a sample mean that is as severe as the one we observed (or more extreme). In other words, there is only a 2% probability of observing a sample mean that is as different from 40 seconds (or more different) as the one we obtained, if the true mean time taken to solve the logic problem by all UBC students is 40 seconds. Hence, at a significance level of 0.05 but not at a significance level of 0.01 we would reject the null hypothesis.

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By adding  the monthly finance charge to the unpaid balance, the new account balance is $4,056.91.

What is addition?

Addition is a mathematical operation that involves combining two or more numbers to produce a sum or total. It is commonly denoted by the plus sign (+) and is one of the four basic arithmetic operations.

To find the new account balance, we need to add the monthly finance charge to the unpaid balance.

First, we need to calculate the monthly finance charge:

Monthly finance charge = 1.75% of unpaid balance

= 0.0175 * $3,987.11

= $69.80

Next, we add the monthly finance charge to the unpaid balance:

New account balance = Unpaid balance + Monthly finance charge

= $3,987.11 + $69.80

= $4,056.91

Therefore, the new account balance is $4,056.91.

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The value of the equation are 1. (-2√3 + 2)(√3 - 5) = -16 + 8√3 2. (5 - 4√5)(-2 + √5) = -30 + 21√. 3. (-2 - 3√5)(5 - √5) = -5 - 17√5. 4. (√5 - √3)(√5 + √3) = 2.

An expression is a mathematical sentence without the equal sign that can include variables, operators, and integers. Although it can be appraised or simplified, there isn't a single perfect answer. An expression is, for instance, 3x + 2y.

A mathematical statement that has an equal sign and expresses the equivalence of two expressions is called an equation, on the other hand. To determine the values of variables that meet an equality, equations can be solved. One equation is 3x + 2y = 7, for instance.

1. Multiplying (-2√3 + 2)(√3 - 5), we get:

= -2√3 × √3 + (-2√3 × -5) + (2 × √3) + (2 × -5)

= -2√(3 × 3) + 10√3 - 2√3 - 10

= -2(3) + 8√3 - 10

= -16 + 8√3

Therefore, (-2√3 + 2)(√3 - 5) = -16 + 8√3.

2. Multiplying (5 - 4√5)(-2 + √5), we get:

= 5(-2) + 5√5 + (-4√5)(-2) + (-4√5)(√5)

= -10 + 13√5 + 8√5 - 4(5)

= -30 + 21√5

Therefore, (5 - 4√5)(-2 + √5) = -30 + 21√5.

3. Multiplying (-2 - 3√5)(5 - √5), we get:

= (-2 × 5) + (-2 × √5) + (-3√5 × 5) + (-3√5 × -√5)

= -10 - 2√5 - 15√5 + 3(5)

= -5 - 17√5

Therefore, (-2 - 3√5)(5 - √5) = -5 - 17√5.

4. Multiplying (√5 - √3)(√5 + √3), we get:

= (√5 × √5) - (√3 × √3)

= 5 - 3

= 2

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I don't think anything is wrong with your values. Since it's an equation, you can see something different and get the right answer.

Answer:

Length ≥ 40

Width ≥ 5

Perimeter = 2 × (Length + Width)

2 × (Length + Width) ≤ 150

Step-by-step explanation:

To create a graph showing the possible dimensions of the garden, we need to plot the length and width of the rectangular area on the x and y axes, respectively. Since we want the length to be at least 40 feet and the width to be at least 5 feet, we can represent these constraints by the following inequalities:

Length ≥ 40

Width ≥ 5

We also know that the total length of fencing available is 150 feet, which means that the perimeter of the rectangular area must be less than or equal to 150 feet. The perimeter of a rectangle is given by:

Perimeter = 2 × (Length + Width)

So, we can write the inequality representing the perimeter as:

2 × (Length + Width) ≤ 150

To graph the possible dimensions of the garden, we can plot the points that satisfy all three inequalities on the x-y plane.

Regarding the vegetables, it is not clear what vegetables the user would like to plant in the garden. As such, we cannot provide a specific answer to this question.

In summary, we need to write three inequalities to represent the constraints in the problem, and we can graph the solution space using these inequalities.

Answer:

I think a

good luck

have a good day

Answer: -31x

Step-by-step explanation:

|x|31 becomes -x31 which is -31x

Cheryl ran a total of 8 miles in five days.

1 + 1 + 1 + 2 + 3 = 8

Written as a decimal, this is 8.0 miles.

Answer:

To translate a shape, we need to move all its vertices by the same amount in the same direction. Here are the answers to the three parts of the question:

1. To translate parallelogram ABCD 2 units down, we need to subtract 2 from the y-coordinates of all its vertices. Let's say the original coordinates of the vertices are A(a,b), B(c,d), C(e,f), and D(g,h). Then the new coordinates of the vertices will be A'(a,b-2), B'(c,d-2), C'(e,f-2), and D'(g,h-2). Plot these new vertices to get the translated parallelogram.

2. To translate rhombus EFGH 2 units to the left and 4 units down, we need to subtract 2 from the x-coordinates and 4 from the y-coordinates of all its vertices. Let's say the original coordinates of the vertices are E(a,b), F(c,d), G(e,f), and H(g,h). Then the new coordinates of the vertices will be E'(a-2,b-4), F'(c-2,d-4), G'(e-2,f-4), and H'(g-2,h-4). Plot these new vertices to get the translated rhombus.

3. If the coordinates of the vertices of a square LMNO are L(-5,-5), M(-5,5), N(5,5), and O(5,-5), and we want to translate it 3 units to the right and 2 units up, we need to add 3 to the x-coordinates and subtract 2 from the y-coordinates of all its vertices. The new coordinates of the vertices will be L'(-2,-7), M'(-2,3), N'(8,3), and O'(8,-7). Plot these new vertices to get the translated square.

Function[tex]y = arcsin(x)[/tex]is symmetric with respect to the origin, while function [tex]y = arccos(x)[/tex] is not. This is as inverse sine function is an odd function, while inverse cosine function is an even function.

If [tex]f(-x) = -f(x)[/tex] for all values of x in the function's domain, then the function is symmetric with regard to the origin. In other words, a function is said to be symmetric with regard to the origin if it passes through the origin and has the same shape on each side of the y-axis.

We must substitute -x for x in each function and simplify to find out if the functions [tex]y = arcsin(x)[/tex] and [tex]y = arccos(x)[/tex] are symmetric with respect to the origin.

According to the equation [tex]y = arcsin(x)[/tex], we get:

[tex]-arcsin = arcsin(-x) (x)[/tex]

Because it is odd, the function[tex]y = arcsin(x)[/tex] is symmetric with respect to the origin.

According to the equation [tex]y = arccos(x)[/tex]:

[tex]x(-arccos) = -arccos (x)[/tex]

Because it is not odd, the function[tex]y = arccos(x)[/tex] is not symmetric with respect to the origin.

In conclusion, [tex]y = arccos(x)[/tex]is not symmetric with regard to the origin, but [tex]y = arcsin(x[/tex] is. Due to the fact that the inverse cosine function is an even function, whereas the inverse sine function is an odd function, this is the case.

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Answer:

4

Step-by-step explanation:

The product of eight and two is 8 x 2 = 16.

The product of three and four is 3 x 4 = 12.

So, the expression "the product of eight and two, minus the product of three and four" can be written as:

16 - 12 = 4

Therefore, the answer is 4.

In conclusion, the integer solutions of the given system of equations are [tex]$(x, y, z) = (1, 2, 0)$ and $(x, y, z) = (-1, 4, 0)$.[/tex]

An integer is a positive, negative, or zero-valued whole number. It is a number without a fractional or decimal component.

To find all integer solutions of the given system of equations:

[tex]x + y &= 3 \[/tex]

[tex]3xy - z^2 &= 9[/tex]

We can start by solving the first equation for one of the variables. Let's solve for y in terms of x:

[tex]x + y &= 3 \[/tex]

[tex]y &= 3 - x[/tex]

Now we substitute this expression for y into the second equation:

[tex]3xy - z^2 &= 9 \[/tex]

[tex]3x(3-x) - z^2 &= 9 \quad \text{Substituting } y = 3-x \[/tex]

[tex]9x - 3x^2 - z^2 &= 9 \[/tex]

[tex]3x^2 + z^2 &= 9x - 9 \[/tex]

[tex]3x^2 - 9x + z^2 &= -9 \quad \text{(1)}[/tex]

Now we will examine equation (1) for integer solutions.

Case 1: [tex]z= 0[/tex]

If  then equation (1) becomes:

[tex]3x^2 - 9x &= -9 \quad \text{(1a)} \[/tex]

[tex]3x(x-3) &= -9[/tex]

Since we are looking for integer solutions, 3x and x-3 must have opposite signs. The possible pairs of factors of -9 with opposite signs are (3,-3) and (-3,3). So we have two possible sets of equations to solve:

The discriminant is negative, there are no integer solutions. Therefore, there are no integer solutions for the original system of equations when [tex]z \neq 0.[/tex]

In conclusion, the integer solutions of the given system of equations are [tex]$(x, y, z) = (1, 2, 0)$ and $(x, y, z) = (-1, 4, 0)$.[/tex]

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(a) The right distributive law is proven for S.For S, this is expressed as (a,b)·(c,d)=(a,b)·(c,d)=(a·c,a·d+b·c).

(a,b)·(c,d)=(bd−ad−bc,ac−ad−bc)=(a·c,a·d+b·c).

(b) we can deduce that x=1 and y=0. Hence, the multiplicative identity element for S is (1,0).

(c) For S, this is expressed as (a,b)·(1,0)=(a,b). Let (a,b) be an arbitrary element in S. The multiplicative identity law is proven for S.

The right distributive law states that the product of a scalar and a vector is equal to the sum of the products of the scalar with each component of the vector.

(a) For S, this is expressed as (a,b)·(c,d)=(a,b)·(c,d)=(a·c,a·d+b·c).

To prove this, we need to show that (a,b)·(c,d)=(a·c,a·d+b·c).

Let (a,b) and (c,d) be two arbitrary elements in S. Then,

(a,b)·(c,d)=(bd−ad−bc,ac−ad−bc)

=(a·c,a·d+b·c).

Therefore, the right distributive law is proven for S.

(b) The multiplicative identity element for S is (1,0). To find this, we need to find a pair of elements (x,y) such that (a,b)·(x,y)=(a,b).

Let (x,y) be an arbitrary pair of elements in S. Then,

(a,b)·(x,y)=(ax−by,ay+bx)

=(a,b).

From this, we can deduce that x=1 and y=0. Hence, the multiplicative identity element for S is (1,0).

(c) The multiplicative identity law states that the product of a scalar and the multiplicative identity element is equal to the scalar itself. For S, this is expressed as (a,b)·(1,0)=(a,b).

To prove this, we need to show that (a,b)·(1,0)=(a,b).

Let (a,b) be an arbitrary element in S. Then,

(a,b)·(1,0)=(a·1−b·0,a·0+b·1)

=(a,b).

Therefore, the multiplicative identity law is proven for S.

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Answer:

 y = 7x + 10

Step-by-step explanation:

Use your point-slope form: y- y1 = m (x - x1) to substitute the given information.

    y - 6 = 7(x - (-4))

Then simplify.

     y - 6 = 7(x + 4)

Next, distribute the 7 into the parenthesis which will give you the point-slope form.

     y - 6 = 7x + 28

In order to write it in slope-intercept form, add 6 to both sides.

    y - 6 + 6 = 7x + 4 + 6

Then simplify to write the equation in slope-intercept form.

    y = 7x + 10