As the temperature of a blackbody increases, what happens to the peak wavelength of the light it radiates

Answer:

Given = 55kg, 4.5 m

Unknown = Work done

Formula = (mg) × d

Solution = 2425.5 J

Answer = 2425.5 J

Explanation:

Formula we use,

→ W = (mg) × d

Then the value of work done is,

→ (55 × 9.8) × 4.5

→ 539 × 4.5

→ 2425.5 J

Hence, the work done is 2425.5 J.

Answer:

The heat absorbed in each cycle is 9,234.286 J

Explanation:

Given;

power output, P = 5 kW = 5,000 W

efficiency of the engine, e = 30 % = 0.3

thermal heat expelled, [tex]Q_c[/tex] = 6464 J

let the heat absorbed = [tex]Q_h[/tex]

The efficiency of the engine is given as;

[tex]e = \frac{W}{Q_h} = \frac{Q_h-Q_c}{Q_h} = \frac{Q_h}{Q_h} - \frac{Q_c}{Q_h} = 1-\frac{Q_c}{Q_h}\\\\e = 1-\frac{Q_c}{Q_h}\\\\0.3 = 1-\frac{Q_c}{Q_h}\\\\\frac{Q_c}{Q_h} = 1-0.3\\\\\frac{Q_c}{Q_h} = 0.7\\\\Q_h = \frac{Q_c}{0.7} \\\\Q_h = \frac{6464}{0.7} = 9,234.286 \ J.[/tex]

Therefore, the heat absorbed in each cycle is 9,234.286 J.

heat and thermal energy can be differentiated as is that thermal energy is not actually transferred. It is not moving, but remains part of the system's internal energy. Heat, on the other hand, is a passing energy. H. Energy transferred from a hotter system.

In summary, thermal energy is the energy hipster. As such, it cannot be converted into other types of energy. Only the difference in thermal energy can be converted/used to do work. Such processes are never 100% efficient. Every energy form that cannot be recovered.

Thermal energy transfer occurs in three ways: convection, conduction and radiation. When heat energy is transferred between adjacent molecules that are in contact with each other, it is called conduction

Thermal energy and temperature are closely related. However, temperature is the average kinetic energy of matter particles and thermal energy is the total kinetic energy of matter particles.

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Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

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Answer:

Humans can detect sounds in a frequency range from about 20 Hz.

Answer:

112.5 J

Explanation:

I calculated it by K/G BY M/S TO POTENTIAL ENERGY.

Given values are:

The change in Potential energy is:

→ [tex]\Delta PE = mgh[/tex]

By substituting the values, we get

            [tex]= 1.0\times 9.8\times 15[/tex]

            [tex]= 147 \ J[/tex]

Thus the above response is correct.  

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Answer:

The frequencies the other string could have are 258.4 Hz and 261.6 Hz.

Explanation:

Given;

beat frequency, Fb = 1.60 Hz

frequency of the first string, F₁ = 260.00 Hz

frequency of the second string, F₂ = ?

Beat frequency is given as;

Fb = F₂ - F₁     or      Fb = F₁ - F₂

Fb + F₁ = F₂    or      F₂ = F₁ - Fb

1.6 + 260 = F₂   or   F₂ = 260 - 1.6

261.6 Hz = F₂  or   F₂ = 258.4 Hz

Therefore, the frequencies the other string could have are 258.4 Hz and 261.6 Hz.

Solution :

The expression for the intensity of light is given by :

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a \sin \theta}{\lambda}}{\frac{\pi a \sin \theta}{\lambda} }\right)^2$[/tex]

For a small angle, θ

sin θ = tan θ

        [tex]$=\frac{y}{L}$[/tex]

Therefore the above equation becomes,

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a y}{\lambda L}}{\frac{\pi a y}{\lambda L} }\right)^2 $[/tex]

The given data is

λ = 546.1 nm

L = distance between the slit and the screen = 140 cm

  = 1.40 m

a = width of the slit

  = [tex]$0.50 \times 10^{-3} \ m$[/tex]

Therefore,

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20}}{\frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20} }\right)^2 $[/tex]

  [tex]$=\left(\frac{0.170}{9.82}\right)^2$[/tex]

 [tex]$= 2.89 \times 10^{-4} \ I_{max}$[/tex]

Therefore the fractional intensity is   [tex]$\frac{I}{I_{max}}= 2.89 \times 10^{-4} $[/tex]

Answer:

0 m/s^2

Explanation:

If you're driving at constant speed in the same direction, your acceleration is always 0 m/s^2. acceleration is a vector, so any change in speed or direction would result in acceleration.

Answer:

The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.

Explanation:

The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.

Also notice that convex mirror always makes virtual images.

Another feature of the convex mirror is that an upright image is always formed by the convex mirror.

An important mirror formula to remember which is applicable for both convex and mirrors

Here:

'u' is an object which gets placed in front of a spherical mirror of focal

length 'f' and image 'u' is formed by the mirror.

Answer:

right side up

Explanation:

Answer:

3.33s

Explanation:

Given parameters:

Acceleration  = 15m/s²

Initial velocity  = 0m/s

Final velocity  = 50m/s

Unknown:

Time taken for the acceleration  = ?

Solution:

To solve this problem, we must understand that acceleration is the rate of change of velocity with time.

Mathematically;

           a  = [tex]\frac{v - u}{t}[/tex]  

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

     So;

          15  = [tex]\frac{50 - 0}{t}[/tex]  

           15t  = 50

              t  = 3.33s

Answer:

Explanation:

The velocity of sound wave is expressed using the formula;

[tex]v = f \lambda[/tex] where

f is the frequency

[tex]\lambda\\[/tex] is the wavelength

Given

f = 1300Hz

v = 38m/s

Required

wavelength [tex]\lambda\\[/tex]

From the formula;

[tex]\lambda\\[/tex] = v/f

[tex]\lambda\\[/tex] = 38/1300

[tex]\lambda\\[/tex] = 0.0292m

Hence the required value of the wavelength is 0.0292m

The wavelength of a stationary listener is 0.029 m.

The given parameters;

The wavelength of a stationary listener is calculated as follows;

[tex]v = f\lambda[/tex]

where;

λ is the wavelength of the sound wave

The value of the wavelength is determined as;

[tex]\lambda = \frac{v}{f} \\\\\lambda = \frac{38}{1300} \\\\\lambda = 0.029 \ m[/tex]

Thus, the wavelength of a stationary listener is 0.029 m.

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Answer:

0.56 km/s

Explanation:

We will define a single system of units for measurement, for this case meters per second [m/s]. That is, we must convert the rest of units such as centimeters per second and kilometers per second to meters per second.

[tex]560[\frac{cm}{s}]*(\frac{1m}{100cm} )=5.6[m/s]\\0.56[\frac{km}{s}]*(\frac{1000m}{1km} )=560[m/s][/tex]

Therefore the speed of 0.56 [km/s] is the greatest of all

Answer:

a spring scale

Explanation:

i think it is correct

Answer:

The inertia of an object does not change as the objects velocity changes because the inertia will remain the same as long as the mass is the same.

:

Answer:

c) Aeroplane

Explanation:

The aeroplane has the greatest mass than the other three objects, so it experiences the greatest gravitational force. Hence, the option (c) is the answer.

Answer:

It is a value that reading in the galvanometer must be multiplied with to get the ordinary unit

Explanation:

What is a galvanometer?

A galvanometer is an electromechanical instrument used for detecting and indicating an electric current.

A Number by which a certain function of the reading of a galvanometer must be multiplied to obtain the current value in ordinary units is a galvanometer constant

Answer:

[tex]CPD = 80[/tex]

[tex]PCD = 44[/tex]

Explanation:

Given

[tex]AB || CD[/tex]

[tex]BAD = 56[/tex]

[tex]CPA = 100[/tex]

See attachment

Required

Determine PCD and CPD

First, we need to calculate CPD

Since DPA is a straight line and CPA = 100;

We have that:

[tex]CPA + CPD = 180[/tex] --- angle on a straight theorem

Substitute 100 for CPA

[tex]100 + CPD = 180[/tex]

Subtract 100 from both sides

[tex]100-100 + CPD = 180-100[/tex]

[tex]CPD = 80[/tex]

Next, we calculate PCD

We have that:

[tex]DAB= ADC = 56[/tex]  --alternate angle

In triangle PCD

[tex]PCD + CPD + PDC = 180[/tex] --- angles in a triangle

Where

[tex]PDC = ADC = 56[/tex]

So, we have:

[tex]PCD +80 + 56 = 180[/tex]

[tex]PCD +136 = 180[/tex]

Subtract 136 from both sides

[tex]PCD = 180 - 136[/tex]

[tex]PCD = 44[/tex]

Answer:

[tex]t = 0.55[/tex]

Explanation:

Given

[tex]Height, s = 1.5m[/tex]

[tex]Velocity, v = 70m/s[/tex]

Required

Determine the time to hit the ground

Using free fall formula:

[tex]S = \frac{1}{2}gt^2[/tex]

Take g as 9.8 and substitute value for S

[tex]1.5 = \frac{1}{2} * 9.8 * t^2[/tex]

[tex]1.5 = 4.9 * t^2[/tex]

Make t^2 the subject

[tex]t^2 = \frac{1.5}{4.9}[/tex]

[tex]t^2 = 0.30612244898[/tex]

Solve for t

[tex]t = \sqrt{0.30612244898[/tex]

[tex]t = 0.55[/tex] -- approximated

Answer:

1.791 MN

Explanation:

Thrust of the rocket can be found using the relation

T = v.dm/dt, where

T = thrust off the rocket

v = speed of the rocket, 9 km/s = 9000 m/s

dm/dt = rate at which fuel burns, 199 kg/s

Substituting the values into the formula, we have

T = 9000 * 199

T = 1791000 N

T = 1.791*10^6 N

Since 1 MN = 10^6, thus

T = 1.791 MN

The thrust of the rocket in units of MN is 1.71 Meganewton.

Given the following data:

Conversion:

Relative speed = 9 km/s to m/s = 9000 m/s

To determine the thrust of the rocket in units of MN:

Mathematically, the thrust of an object is given by this formula:

[tex]Thrust = V\frac{dm}{dt}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Thrust = 9000 \times 199[/tex]

Thrust = 1,791,000 Newton

In units of MN:

1 MN = [tex]1 \times 10^6\;N[/tex]

Thrust = 1.71 MN

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Answer:

its it filled with energy

Answer:

The light slows down.

Explanation:

Answer:

The time spent in air by the rock before it returns to the thrower is 4.5 s

Explanation:

Given;

initial velocity of the rock, u = 22 m/s

Neglecting air resistance, the time it takes the rock to go up equals the time it takes it to return to the thrower. This is also called time of flight.

The time to go up is calculated as;

v = u - gt

where;

v is the final velocity at the maximum height

0 = u - gt

gt = u

t = u / g

t = 22 / 9.8

t = 2.245 s

thus time to go up = 2.245 s

and time to return to the thrower = 2.245s

The total time spent in air by the rock before it returns to the thrower

 = 2.245 s + 2.245s

 = 4.5 s

Answer:

25 N

If you’re doing ck-12

The object may be swung with maximum velocity of 7.07 m/s without breaking the string.

The centripetal force definition states that: The force applied to an item in curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.

Newtons are used to measure centripetal force.

Given that:

mass of the object = 0.500 kg.

The length of the string = 1.00 m.

If the maximum speed of the object be v,

maximum centripetal force be = 0.5v²/1.0 N = v²/2 N.

As the maximum force the string can withstand without breaking is 25.0 N,

25.0 = v²/2

⇒ v = 5√2 m/s = 7.07 m/s.

Hence,   the object may be swung with maximum velocity of 7.07 m/s without breaking the string.

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1) The longitudinal waves move in parallel direction to the source of vibration. The transverse waves move in perpendicular direction to the source of vibration . They are similar in the sense that energy is transferred in the form of waves.

2) Reflection occurs when waves bounce from a surface back toward the source. Refraction is when waves are deflected when the waves go through a substance.

3) The Law of Conservation of Energy

states that energy can neither be created

nor destroyed, it can only be transferred or

changed from one form to another.

Answer:

I = 1.5*10⁻³ kg*m²

Explanation:

       [tex]I = \frac{1}{2}*m*r^{2} = \frac{1}{2}*0.400 kg*(0.0865m)^{2} = 1.5e-3 kg*m2[/tex]

Explanation:

Because it is the easiest branch of science to understand

Answer:

Work done = 1/2 × Ne

Explanation:

Given that if  a force of N stretches a spring m beyond its natural​ length, how much work does it take to stretch the spring m beyond its natural​ length

Using Hook's law

Force = N

Let the extension = e

Work done in stretching spring m beyond its natural length will be

Workdone = 1/2 × Ne

Or

From Hook law,

N = Ke

Work done = 1/2 × Ke^2

Answer:

magma

Explanation:

I wanna think that that's right if it's not in so sorry but I'm pretty sure it's magma

Intrusive magma forced up towards the ocean ridge is the force responsible for seafloor spread. The correct option is B.

Seafloor spreading is a process that occurs at mid-ocean ridges where the oceanic crust is produced by volcanic activity and then moves away from the ridge.

Plate tectonics' continental drift is explained by seafloor spreading. When oceanic plates diverge, tensile stress causes fractures in the lithosphere.

Ridge push occurs when plates are not subducting and are driven by gravity as they slide off the elevated mid-ocean ridges.

Magma rises from the fractures at a spreading center and cools on the ocean floor to form a new seabed.

The spreading rate is the rate at which an ocean basin widens due to seafloor spreading and determines whether the ridge is fast, intermediate, or slow.

Thus, the correct option is B.

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Answer:

L/E =de/dl so dl is 10m de=4m E=5N

Explanation:

L=(de x E)/dl = 2N

so when load is < effort it is speed multiplayer