As the distance between the sun and earth decreases, the gravity force between them

a
Increases
b
decreases
c
stays the same

Answer:

a) the rate at which 235U is fissioned is 2895.9 grams per day

b) the rate at which 235U is consumed is 3385.3071 gram/day

Explanation:

Given the data in the question;

a)

designed operation thermal power = 2758 MW.

we know that, the burn up rate fission rate of 235U is 1.05 grams per MW-day.

so, the rate at which 235U is fissioned will be;

⇒ 2758 × 1.05 = 2895.9 grams per day

Therefore, the rate at which 235U is fissioned is 2895.9 grams per day

b)

Consumption rate is given as;

Cr = 1.05 × ( 1 + ∝ )P gram/day

where ∝ is 0.169 for U-235

so,

Cr = 1.05 × ( 1 + 0.169 )2758 gram/day

Cr = 1.05 × 1.169 × 2758 gram/day

Cr = 3385.3071 gram/day

Therefore, the rate at which 235U is consumed is 3385.3071 gram/day

Answer:

the power generation potential is 2.705 x 10⁶ J/s.

Explanation:

Given;

height below the free surface of a large water reservoir, h = 120 m

mass flow rate of the water, m' = 2300 kg/s

The power generation potential is calculated as;

[tex]Power = \frac{Energy}{time} = \frac{F\times h}{t} = \frac{(mg) \times h}{t} = \frac{m}{t}\times gh = m' \times gh\\\\Power = m' \times gh\\\\Power = 2300 \ kg/s \ \times \ 9.8 \ m/s^2 \ \times \ 120 \ m\\\\Power = 2.705 \times 10^6 \ J/s[/tex]

Therefore, the power generation potential is 2.705 x 10⁶ J/s.

Answer:

q = 3.6 10⁵  C

Explanation:

To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth

          r = 6 , 37 106 m

          E = k q / r²

          q = E r² / k

          q = [tex]\frac{100 \ (6.37 \ 10^6)^2}{9 \ 10^9}[/tex]

          q = 4.5 10⁵ C

Now let's calculate the charge on the planet with E = 222 N / c and radius

           r = 0.6 r_ Earth

           r = 0.6 6.37 10⁶ = 3.822 10⁶ m

           E = k q / r²

            q = E r² / k

            q = [tex]\frac{222 (3.822 \ 10^6)^2}{ 9 \ 10^9}[/tex]

            q = 3.6 10⁵  C

Answer:

x = 0.67 m

Explanation:

For this problem, let's use the projectile launch equations, as the jug goes through the bar, it comes out with horizontal speed vx = 1.3 m / s, which does not decrease as there is no friction.

Let's find the time or it takes to get to the floor

          y = y₀ + v_{oy} - ½ g t²

in this case I go = 0 and when I get to the floor y = 0

         0 = y₀ + 0 - ½ g t²

          t² = 2y₀ / g

          t² = 2 1.3 / 9.8 = 0.2653

          t = 0.515 s

now let's find the distance traveled in this time

         x = vx t

         x = 1.3  0.515

         x = 0.6696 m

         x = 0.67 m

Answer:

#_galon = 8,873 gallons

Explanation:

For this exercise let's use a direct rule of proportions (rule of three). If 1 gallon is 142 MJ, how many gallons is 1260 MJ

          #_galon = 1260 MJ (1 gallon / 142 MJ)

          #_galon = 8,873 gallons

therefore air travel uses less fuel than car travel

Answer:

a

Explanation:

Answer:

Explanation:

Net electric field at the centre will be zero .

Since all the charges are equal and they all are symmetrically situated around the centre . So the electric field produced by each will cancel  out each other and hence the resultant electric field will be zero . It happens because electric field is a vector quantity and therefore it adds up vectorially . All the four electric field will form two pairs , in each pair electric fields are acting in opposite direction . So they all cancel out to zero .

Answer:

beacuse it isnt on

Explanation:

Explanation:

The wires isn't in a circulation, the negative side must be connected to the wire

Answer:

1. conduction

2. a convection current

3. Heat is always transferred from the object at the higher temperature to the object with the lower temperature

4. noooooo!Heat is always transferred from the object at the higher temperature to the object with the lower temperature

5.convection

6. Thermal radiation

7. convection again!

A. Conduction is the transfer of thermal energy through direct contact. Convection is the transfer of thermal energy through the movement of a liquid or gas.

B. Radiation is the transfer of thermal energy through thermal emission.

C. the heat required to raise the temperature of the unit mass of a given substance by a given amount

1. conduction, 2. convection current, 3. hotter objects to cooler objects. 4. Radiation, 5. convection, 6. radiation, 7. convection.

There are three main modes of heat transfer:

Conduction: This is the transfer of heat through a material by direct contact between molecules. In this mode, heat flows from hotter to colder regions within the material until the temperature is equalized.

Convection: This is the transfer of heat through a fluid (liquid or gas) by the movement of the fluid itself. This mode of heat transfer can occur by natural convection (due to density differences in the fluid) or forced convection (due to an external source such as a fan).

Radiation: This is the transfer of heat through electromagnetic waves, without the need for a medium to transfer the heat. All objects emit and absorb radiation, and the amount of radiation emitted depends on the temperature of the object. This mode of heat transfer is important for heating and cooling applications, such as radiators or refrigerators.

Here in the question,

1. Heat is transferred directly from one particle of matter to another by the process of conduction.

2. A circular flow of warmer fluid and cooler fluid is called a convection current.

3. Heat is always transferred from hotter objects to cooler objects.

4. Radiation is the transfer of energy by electromagnetic waves.

5. Heat that is transferred by the movement of currents within a fluid is called convection.

6. The only form of heat transfer that does not require matter is radiation.

7. Water bubbling up through a hot spring at Yellowstone National Park is an example of convection.

Therefore, The Answers to those questions are 1. conduction, 2. convection current,3. hotter objects to cooler objects. 4. Radiation, 5. convection, 6. radiation, 7. convection.

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Answer: 3m

Explanation: If he is already 2m away from the mirror then if he walks away 1m then it would equal out to 3. You could also add 1 to 2 so you could get the same results.

Answer:

$84

Explanation:

The coefficient of performance (COP) show the relationship between the power (kW) output of the heat pump and the power (kW) input to the compressor.

The heater consumed by the heater is 1200 kWh.

For a heat pump with a COP of 2.4, the electric input needed to produce an output of 1200 kWh is:

Electric input to heat pump = 1200 / 2.4 = 500 kWh

That means that supplying a heat pump with 500 kWh produces an output of 1200 kWh

The amount of power saved = power consumed by heater - power consumed by heat pump = 1200 - 500 = 700 kWh

Money saved = $0.12/kWh * 700 kWh = $84

The amount of money the homeowner would have saved during the month is $84.

Given the following data:

To determine the amount of money the homeowner would have saved during the month:

In Science, the coefficient of performance (COP) is a mathematical expression that is typically used to show the relationship between the power output (kilowatts) of a heater and the power input (kilowatts) to the compressor.

Mathematically, the coefficient of performance (COP) is given by the formula:

[tex]COP = \frac{E_o}{E_i}[/tex]

Where:

First of all, we would determine the energy input of the heaters.

[tex]E_i = \frac{E_o}{COP} \\\\E_i=\frac{1200}{2.4}[/tex]

Energy input = 500 kWh

For power saved:

[tex]Power = 1200 -500[/tex]

Power = 700 kWh

For the amount of money saved while using these heaters:

[tex]Money = 0.12 \times 700[/tex]

Amount of money = $84

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Answer:

With or without.

Explanation:

According to the National Electrical Code (NEC), here the air conditioner disconnecting means is not within sight from the equipment, the provision for locking or adding a lock to the disconnecting means shall be on the switch or circuit breaker and remain in place with or without the lock installed. Thus, this is in accordance with section 110.25 of the National Electrical Code (NEC).

Answer:

I think its 71.4 if u get it wrong u can slap me

Answer:

The answer is below

Explanation:

The heat flux or heat intensity is the flow of energy per unit area per unit time. measured in watts per meter² (W/m²).

a) The surface area of filament = πDL

D = diameter = 0.5 mm = 5 * 10⁻⁴ m, L = length = 5 cm = 5*10⁻² m

surface area of filament = π* 5 * 10⁻⁴ m * 5*10⁻² m = 25π * 10⁻⁶ m²

The heat flux on the surface of filament = 150 W / (25π * 10⁻⁶ m²) = 1.91 * 10⁶ W/m²

b) Since the glass tube is a sphere with diameter = 8 cm;

radius (r) = diameter / 2 = 4 cm = 4* 10⁻² m

Surface area of glass tube = 4πr² = 4π * (4* 10⁻²)²  = 64π* 10⁻⁴ m²

The heat flux on the surface of filament = 150 W / (64π* 10⁻⁴ m²) = 7.46 * 10³ W/m²

c) The total energy consumed in a year = 150 W * 365 days * 8 hours/day =  438000 Wh = 438 kWh

Cost of energy = unit cost * energy consumed = $0.08/kW * 438 kWh = $35.04

Answer:

Explanation:

Gravitational potential energy = mgh where m is mass , g is acceleration due to gravity and h is height from the ground .

In the first case mass m = volume x density

= 1 x 1000 = 1000 kg

height h = 30 m

potential energy = 1000 x 30 x 9.8 = 294000 J = 294 kJ .

When height decreases by 10 m , potential decreases as follows .

Decrease in potential energy

= mass x gravitational energy x decrease in height

= 1000 x 9.8 x 10

= 98000 J

= 98 kJ .

Answer:

Explanation:

a

Answer:

the average force exerted on the ball by the bat is 11,613.27 N

Explanation:

Given;

mass of the baseball, m = 151 g = 0.151 kg

initial velocity of the baseball, u = 39.5 m/s

final velocity of the baseball, v = 45.1 m/s

time of action, t = 1.10 ms = 1.10 x 10⁻³ s

The average force exerted on the ball by the bat is calculate as;

[tex]F = ma = \frac{m(v-u)}{t} \\\\F = \frac{0.151(45.1-(-39.5))}{1.10\times 10^{-3}} \\\\F = \frac{0.151(45.1\ +\ 39.5)}{1.10\times 10^{-3}} \\\\F = 11,613.27 \ N[/tex]

Therefore, the average force exerted on the ball by the bat is 11,613.27 N

Force excerted is defined as the product of mass and rate of change of velocity .The average force exerted on the ball by the bat will be 11,613.27 N.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

m is the mass of the baseball = 151 g = 0.151 kg

u is the  initial velocity of the baseball =39.5 m/s

v is the final velocity of the baseball = 45.1 m/s

t is time of contact = 1.10 ms = 1.10 x 10⁻³ s

The average force mathematically given as

[tex]\rm F=\frac{m(v-u)}{t} \\\\\rm F=\frac{0.151(45.1-39.85)}{1.10\times10^-3} \\\\\rm F=11,613.27 N[/tex]

Hence the average force exerted on the ball by the bat will be 11,613.27 N.

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Option C shows the direction of the force of the ball on the spring. The direction of the force of the ball on the spring will be downwards.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

The spring is extended downward because the weight is always act downwards. The direction of the force of the ball on the spring will be downwards.

Hence, option C shows the direction of the force of the ball on the spring

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Answer:

dgfggddhdbxbxjxddhsnsxnc

This question is incomplete, the complete question is;

Now we will examine the electric field of a dipole. The magnitude and direction of the electric field depends on the distance and the direction. We will investigate in detail just two directions. With charges available in the simulation (all the charges are either positive or negative 1 nC increments).

how do you create a dipole with dipole moment 1 x 10-9 Cm with a direction for the dipole moment pointing to the right. Make a table below that shows the amounts of  charge and the distance between the charges. There are many correct answers

Answer:

Given the data in question;

Dipole moment P = 1 × 10⁻⁹ C.m

now dipole pointing to the right;

               P→

[tex]_{-\theta }[/tex] (-) ---------------->(+) [tex]_{+\theta }[/tex]

               d

so let distance between the dipoles be d

∴ P = d[tex]\Theta[/tex]

Let [tex]\Theta_{1}[/tex] = 1 nC

so

P = d[tex]\Theta[/tex]

1 × 10⁻⁹ =  1 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (1 × 10⁻⁹)

d = 1 m

Also Let [tex]\Theta_{2}[/tex] = 2 nC

so

P = d[tex]\Theta[/tex]

1 × 10⁻⁹ =  2 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (2 × 10⁻⁹)  

d = 0.5 m

Also Let [tex]\Theta_{3}[/tex] = 3 nC

so

P = d[tex]\Theta[/tex]

1 × 10⁻⁹ =  3 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (3 × 10⁻⁹)

d = 0.33 m

such that;

charge                 distance

1 nC                        1.00 m      

2 nC                       0.50 m

3 nc                        0.33 m

4 nC                       0.25 m

5 nC                       0.20 m      

Answer:

a.432

B. 562

C.402

D. 316

A

Explanation:

Work is defined as the product of applied force and the distance through which the body is displaced on which the force is applied. Work was done by the workman will be 432 Nm.

What is work?

Work is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative.it depend on the diection of body displaced . if the body is displaced in thw same direction of force it will be positive .

while if the displacement is in the opposite direction of force applied the work will be negative work . if their is no displacement of the body the work done will b e zero.

As given in question wall is stationary diplacement will be zero so in that work will also z

The given data in the problem is;

x is the displacement in the horizontal direection=22m

y is the displacement in the verical direection=9.6m

W is the weight of lumber = 45 N

[tex]\rm W=F\times y[/tex]

[tex]\rm W=F\times y \\\\\rm W=45\times 9.6\\\\ \rm W=432\;Nm[/tex]

Hence Work was done by the workman will be 432 Nm.

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Answer:

Explanation:

velocity of first projectile after 3 s

v = u - gt

v = 49.4 - 9.8 x 3

= 20 m /s

Velocity of second projectile after 3 s after being dropped from rest

v = u + gt

= 0 + 9.8 x 3

= 29.4 m /s

They will be moving in opposite direction at the time of meeting , so their relative velocity

= 20 + 29.4 = 49.4 m /s

From the frame of reference of the first projectile, the velocity of the second projectile will be 49.4 m /s .

Answer:

there is no graphs, sorry

Explanation:

your still cool btw :3

Answer:

In my opinion i would ask the team of scientist how was it increasin every year.

Explanation:

Complete Question:

Gauss's law:

Group of answer choices

A. can always be used to calculate the electric field.

B. relates the electric field throughout space to the charges distributed through that space.

C. only applies to point charges.

D. relates the electric field at points on a closed surface to the net charge enclosed by that surface.

E. relates the surface charge density to the electric field.

Answer:

D. relates the electric field at points on a closed surface to the net charge enclosed by that surface.

Explanation:

Gauss's law states that the total (net) flux of an electric field at points on a closed surface is directly proportional to the electric charge enclosed by that surface.

This ultimately implies that, Gauss's law relates the electric field at points on a closed surface to the net charge enclosed by that surface.

This electromagnetism law was formulated in 1835 by famous scientists known as Carl Friedrich Gauss.

Mathematically, Gauss's law is given by this formula;

ϕ = (Q/ϵ0)

Where;

ϕ is the electric flux.

Q represents the total charge in an enclosed surface.

ε0 is the electric constant.

Answer:

first value+2nd +3rd

Explanation:

thug life and there

Answer:

Rafi Bahalul

Explanation:

Israeli Haaretz newspaper reported Feb. 4 that Rafi Bahalul stumbled upon a 3,400-year-old Egyptian stone anchor engraved with hieroglyphs during a morning swim along Israel's northern shores last year.

Answer:

The net acceleration of the SUV is 0.429 meters per square second due west.

Explanation:

Statement is incomplete. Description is presented below:

A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly horizontal road. The surface of the road exerts a resistance force of 500 N due east. At the same time a high wind is blowing a force of 500 N due east in the opposite direction of the car's drive force. Does the car has any acceleration? If yes, then what are the magnitude and direction of the car's acceleration?

According to Newton's Laws of Motion, the SUV will accelerate if and only if net acceleration is different of zero. Let suppose as positive the direction of driving force ([tex]F[/tex]), measured in newtons:

[tex]\Sigma F = F - R -f = F_{net}[/tex] (1)

Where:

[tex]R[/tex] - Resistance force, measured in newtons.

[tex]f[/tex] - Wind force, measured in newtons.

[tex]F_{net}[/tex] - SUV net force, measured in newtons.

If we know that [tex]F = 2500\,N[/tex], [tex]R = 500\,N[/tex] and [tex]f = 500\,N[/tex], then net force experimented by the SUV is:

[tex]F_{net} = 2500\,N-500\,N-500\,N[/tex]

[tex]F_{net} = 1500\,N[/tex]

The car has acceleration.

By definition of force for systems with constant mass, we calculate the acceleration of the vehicle below:

[tex]a_{net} = \frac{F_{net}}{m}[/tex] (2)

Where [tex]m[/tex] is the mass of the SUV, measured in kilograms.

If we know that [tex]F_{net} = 1500\,N[/tex] and [tex]m = 3500\,kg[/tex], then the net acceleration of the car is:

[tex]a_{net} = \frac{1500\,N}{3500\,kg}[/tex]

[tex]a_{net} = 0.429\,\frac{m}{s^{2}}[/tex]

The net acceleration of the SUV is 0.429 meters per square second due west.

Answer:

c

Explanation:

Answer: C

Explanation: