as the degrees of freedom increase, what distribution does the student's t distribution become more like? uniform chi-square standard normal (z) binomial

An event where two or more things happen at the same time is called B. Compound event

The term that describes an event where two or more things happen at the same time is a compound event.

A compound event is an event that involves two or more independent events occurring at the same time. For example, tossing a coin and rolling a dice at the same time is a compound event.

In contrast, a dependent event is an event where the outcome of one event affects the outcome of another event.

An organized list is a method used to determine the total number of possible outcomes of an event, usually for small sets of outcomes. It involves listing all possible outcomes in an organized manner.

Therefore, in the context of the question, the correct answer is B. Compound event.

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The probability that the water in Willow Pond will have a pH of 7 in at least 4 out of 5 tests is approximately 0.0278 or 2.78%

This means that it is not very likely that the pond water will have a pH of 7 in at least 4 out of Laura's 5 tests.

Laura's simulation involves picking a shell from a bag with 3 green shells and 7 white shells.

Each pick represents one of Laura's tests, and picking a green shell represents a pH of 7.

Based on the results of 300 trials, we can calculate the probability of getting at least 4 green shells (pH of 7) out of 5 tests using the binomial distribution formula:

P(X >= 4) = 1 - P(X < 4)

= 1 - (P(X=0) + P(X=1) + P(X=2) + P(X=3))

where X is the number of green shells (pH of 7) in 5 tests.

Using the table, we can see that P(X=0) = 50/300, P(X=1) = 109/300, P(X=2) = 92/300, and P(X=3) = 40/300.

Therefore,

P(X >= 4) = 1 - (50/300 + 109/300 + 92/300 + 40/300) = 0.0278.

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Answer: y = ax2 + bx + c

Step-by-step explanation:

Step 1: The equation of any parabola is given by y = ax2 + bx + c, where a, b, and c are constants.

Step 2: We can calculate the axis of symmetry (x-coordinate) by using the formula x = -b/2a.

Step 3: We can calculate the value of a by looking at the width of the parabola.

Step 4: Once we have the values of a and b, we can substitute them into the equation to get the equation of the parabola: y = ax2 + bx + c.

The volume of the cube-shaped  = 1,331 volume of the hole cut out of the block = 125 cubic inches Subtract 1331 - 125 = 1206, the correct option is A

volume of the hole cut out of the block = 5 inches x 5 inches x 5 inches

volume of the hole cut out of the block = 125 cubic inches.

volume of the cube-shaped block = 11 inches x 11 inches x 11 inches

volume of the cube-shaped block = 1,331

To find the volume of the wood remaining after the hole is cut out, we can subtract the volume of the hole from the volume of the block:

1,331 cubic inches - 125 cubic inches = 1,206 cubic inches

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Answer: The median changed the most.

Old median = 79.5

new median = 86.5

===============================================

Explanation:

To find the mean, we add up the values and divide by 12 since there are 12 numbers in this list.

mean = (add up the values)/(number of values)

mean = (58+61+71+77+91+100+105+102+95+82+66+57)/12

mean = 80.41667 approximately

--------

To get the median, we need to sort the numbers from smallest to largest

57, 58, 61, 66, 71, 77, 82, 91, 95, 100, 102, 105

There are n = 12 items in this set.

Because n = 12 is an even number, the median is between slots n/2 = 12/2 = 6 and 7

The midpoint of those values is (77+82)/2 = 79.5 which is the median.

--------

The range is the difference between the min and max

range = max - min = 105 - 57 = 48

The IQR will involve splitting the sorted set into two halves

L = lower half = stuff below the median

L =  {57, 58, 61, 66, 71, 77}

U = upper half = stuff above the median

U = {82, 91, 95, 100, 102, 105}

The median of set L is (61+66)/2 = 63.5 which is the value of Q1.

The median of set U is (95+100)/2 = 97.5 which is the value of Q3

IQR = interquartile range

IQR = Q3 - Q1

IQR = 97.5 - 63.5

IQR = 34

--------

Here is a summary of what we calculated

If we were to replace the "71" with "93", and redo the calculations, then we'll get these results:

The range and IQR stay the same, but the mean and median values are different.

Let's see which of those two values changed the most.

The median has changed the most because the +7 is larger than +1.83333

The exact probability that a student response is from a freshman, given the student prefers to watch reality shows on television, is approximately 46.15%.

To solve this question, we'll use Bayes' theorem:

P(Freshman | Reality Show) = (P(Reality Show | Freshman) * P(Freshman)) / P(Reality Show)

We know:

We need to find P(Reality Show), which is the probability that a randomly chosen student prefers reality shows. We can find this by adding the probability of each class preferring reality shows:

P(Reality Show) = P(Reality Show & Freshman) + P(Reality Show & Sophomore) + P(Reality Show & Junior) + P(Reality Show & Senior)

We can calculate each probability by multiplying the probability of the class preferring reality shows with the probability of the class:

P(Reality Show & Freshman) = P(Reality Show | Freshman) * P(Freshman) = 0.6 * 0.3 = 0.18

P(Reality Show & Sophomore) = P(Reality Show | Sophomore) * P(Sophomore) = 0.4 * 0.25 = 0.1

P(Reality Show & Junior) = P(Reality Show | Junior) * P(Junior) = 0.3 * 0.2 = 0.06

P(Reality Show & Senior) = P(Reality Show | Senior) * P(Senior) = 0.2 * 0.25 = 0.05

P(Reality Show) = 0.18 + 0.1 + 0.06 + 0.05 = 0.39

Now we can calculate the probability:

P(Freshman | Reality Show) = (P(Reality Show | Freshman) * P(Freshman)) / P(Reality Show) = (0.6 * 0.3) / 0.39 ≈ 0.4615

The exact probability that a student response is from a freshman, given the student prefers to watch reality shows on television, is approximately 46.15%.

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There are 1000 students in total:

300 freshmen

250 sophomores

200 juniors

250 seniors

The preferences for watching reality shows are as follows:

60% of freshmen prefer reality shows

40% of sophomores prefer reality shows

30% of juniors prefer reality shows

20% of seniors prefer reality shows

What is the exact probability that a student response is from a freshman, given the student prefers to watch reality shows on television, considering the above student population and preferences?

Distance from Breadth of one side of the wall = L/3 units

Distance from one corner i.e from Breadth = L - L/3 - L/6 = L/2

Distance from floor i.e surface = H/6 units

Distance from Ceiling= H - H/6 = 5H/6 units

Considering the room to be in the shape of a Cuboid as well as the Bed to be in the shape of a Cuboid.

Dimensions of Room:

In mathematics, space is the only light without elements; its magnitude or cardinality (number of elements in the set) is zero.

Let the Length of the cuboid which is in the shape of a room = L

The breadth of the cuboid which is in the shape of a room = B

Height of cuboid which is in the shape of a room = H

Considering, L>B>H

Dimension of Bed

Length = L/6 units

Breadth = B/4 units

Height = H/6 units

Taking one corner at origin i.e (0,0,0)

You can keep your bed at any place inside the room, but you want your bed to be at that place inside the room where the window is located so that proper ventilation and sunlight can enter your room.

Taking the bed to be in the middle of the room near the window and considering its upper face

Distance from one corner i.e from length= B- B/4 = 3B/4 Units

Distance from other corner =  0 Units

Distance from Breadth of one side of the wall = L/3 units

Distance from one corner i.e. from Breadth = L - L/3 - L/6 = L/2

Distance from floor i.e. surface = H/6 units

Distance from Ceiling= H - H/6 = 5H/6 units

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The scale factor of the dilation in size from the first piece of pizza to the second piece of pizza is 1.6.

We must compare the corresponding side lengths of the two triangles in order to determine the scale factor for the size expansion from the first to the second piece of pizza. The scaling factor will equal the ratio of any two matching side lengths because the two triangles are similar.

Let's select the first pizza's sides that correlate to the second pizza's sides. The first pizza has a base that is 7.5 inches in diameter and sides that are 2.75 inches apiece. The base and sides of the second pizza are also 12 inches in diameter. To determine the scale factor, we can utilize the ratio of the corresponding side lengths:

Scale factor = (second pizza's matching side length) / (corresponding side length in first pizza)

Either side length can be used as the equivalent side length. Let's decide that the corresponding side length is 2.75 inches. Next, we have

scale factor=4.4/2.7

If we simplify, we get:

1.6 scale factor

As a result, the scale factor for the size difference between the first and second pizzas is 1.6. In all dimensions, this indicates that the second pizza is 1.6 times bigger than the first.

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The car traveled at a faster rate in the last six minutes compared to the first six minutes.

In the first six minutes, the car traveled 2 miles, which means it had a speed of (2 miles)/(6 minutes) = 0.33 miles per minute.

In the last six minutes, the car traveled 8 miles, which means it had a speed of (8 miles)/(6 minutes) = 1.33 miles per minute.

Comparing the two speeds, we can see that the car traveled at a faster rate in the last six minutes. This could be because the driver increased the speed or drove on a more favorable road surface. It is also possible that the driver had to slow down in the first six minutes due to traffic or other road conditions.

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Answer:

and H(3,7), I(2,2), J(5,2).

To solve for the perimeter, we need to find the distance between each pair of consecutive points and add them up.

The distance between E and F is 3 units, between F and G is approximately 5.83 units, between G and H is 5 units, between H and I is approximately 5.83 units, and between I and J is 3 units.

So the perimeter of EFG is approximately 22.66 units.

Now, we need to check if HIJ has the same side lengths.

The distance between H and I is 5 units, between I and J is 3 units, and between J and H is approximately 5.83 units.

Therefore, HIJ does not have the same side lengths as EFG since their perimeters are different.

The rate at which the volume of water is changing with respect to time when the height of the water is 5 feet is (5.2/3)π√3 cubic feet per minute.

When the height is 5 feet, it is stated that the height of the water in a tank rises at a pace of 0.26 feet per minute.

When the water reaches five feet high, we can determine the rate of change in water volume with respect to time using the model from part (c).

We may calculate the volume of water in the tank using the formula V = (1/3)r2h, where r is equal to 3 feet and h is the height of the water in feet.

The Pythagorean theorem can be used to get the tank's radius at a height of 5 feet: r = ((102 - 52) = 75 = 53 feet.

Taking the derivative of the volume with respect to time, we get:

dV/dt = (1/3)π(2r)(dh/dt)

Substituting the values we have:

dV/dt = (1/3)π(2(5√3))(0.26)

= (5.2/3)π√3 cubic feet per minute

As a result, when the water level is 5 feet high, the rate of change in water volume with respect to time is (5.2/3)3 cubic feet per minute.

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a. The two parameters of the gamma distribution are

shape parameter (α) and velocity parameter (β).

The mean of the gamma distribution = α/β and the standard deviation = sqrt(α)/β.

mean = 5 seconds

standard deviation =2.5 seconds.

α/β = 5 (equation 1)

sqrt(α)/β = 2.5 (equation 2)

Squaring equation 2 and multiplying both sides by β^2 yields:

[tex]α = 6.25β^2[/tex]

Substituting this value of α into Equation 1 yields:

[tex]6.25β^2/β = 5[/tex]

Simplified, it looks like this:

β = 0.8

Substituting this value of β into Equation 1 yields:

a = 4

Therefore, the parameters of the gamma distribution are α = 4 and β = 0.8.

b. I need to find the probability that this software will take more than 10 seconds to run.

The probability density function (PDF) of the gamma distribution is given by

[tex]f(x) = (β^α * x^(α-1) * e^(-βx)) / Γ(α)[/tex]

where Γ(α) is the gamma function.

Using the values ​​of α and β obtained in part (a), we can write the PDF as

[tex]f(x) = (0.8^4 * x^(4-1) * e^(-0.8x)) / Γ(4)[/tex]

I need to find the probability that the execution time exceeds 10 seconds. This can be written as:

P(X > 10) = ∫(10 to infinity) f(x) dx

Using software or a calculator, we can evaluate this integral to get:

P(X > 10) = 0.0559 (rounded to four decimal places)

Therefore, the probability is 0.0559.

c.Since it has already taken more than 5 seconds, we need to find the probability of this software where will take more than 10 seconds to run.

This is a conditional probability and should be calculated using Bayes' theorem.

P(X > 10 | X > 5) = P(X > 10 and X > 5) / P(X > 5)

The numerator can be simplified to

P(X > 10 and X > 5) = P(X > 10)

Using the results obtained in part (b), we can write

P(X > 10 and X > 5) = 0.0559

The denominator can be written as:

P(X > 5) = ∫(5 to infinity) f(x) dx

Using the same PDF as before, we can evaluate this integral and get:

P(X > 5) = 0.2615 (rounded to four decimal places)

Substituting these values ​​into the conditional probability formula gives:

P(X > 10 | X > 5) = 0.0559 / 0.2615

Simplified, it looks like this:

P(X > 10 | X > 5) = 0.214

Therefore, the probability that his single run of this software took longer than 5 seconds to take longer than 10 seconds is 0.214 (rounded to three decimal places).

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answer

W

50°

X

Xy-step explanation:

The probability that a randomly selected lobster weighs more than 2.5 lb is 0.0026.

Let X be the weight of a randomly selected Maine lobster. We know that X is normally distributed with mean μ = 1.8 lb and standard deviation σ = 0.25 lb.

We need to find the probability that a randomly selected lobster weighs

a) less than 1.5 lb

b) between 1.6 and 2 lb

c) more than 2.5 lb

To solve these problems, we need to standardize the variable X using the standard normal distribution

Z = (X - μ) / σ

a) To find the probability that a randomly selected lobster weighs less than 1.5 lb, we need to find P(X < 1.5). Standardizing X, we have

Z = (1.5 - 1.8) / 0.25 = -1.2

Using a standard normal distribution table or calculator, we find that P(Z < -1.2) = 0.1151.

Therefore, the probability that a randomly selected lobster weighs less than 1.5 lb is 0.1151.

b) To find the probability that a randomly selected lobster weighs between 1.6 and 2 lb, we need to find P(1.6 < X < 2). Standardizing X, we have

Z1 = (1.6 - 1.8) / 0.25 = -0.8

Z2 = (2 - 1.8) / 0.25 = 0.8

Using a standard normal distribution table or calculator, we find that P(-0.8 < Z < 0.8) = 0.5328

Therefore, the probability that a randomly selected lobster weighs between 1.6 and 2 lb is 0.5328.

c) To find the probability that a randomly selected lobster weighs more than 2.5 lb, we need to find P(X > 2.5). Standardizing X, we have:

Z = (2.5 - 1.8) / 0.25 = 2.8

Using a standard normal distribution table or calculator, we find that P(Z > 2.8) = 0.0026.

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Answer:

Therefore, the volume of the cylinder is approximately 2,262.9 cubic centimeters.

Step-by-step explanation:

The formula for the volume of a cylinder is V = πr^2h, where r is the radius of the base and h is the height of the cylinder.

Substituting the given values, we get:

V = π(6 cm)^2(20 cm)

V = 720π cm^3

To find the volume to the nearest tenth, we can use the approximation π ≈ 3.14 and calculate:

V ≈ 720(3.14) cm^3

V ≈ 2,262.8 cm^3

Rounding to the nearest tenth, we get:

V ≈ 2,262.8 cm^3 ≈ 2,262.9 cm^3

Therefore, the volume of the cylinder is approximately 2,262.9 cubic centimeters.

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Area of trapezoid = 675 in², Area of triangle = 54 in² and Total Shaded Area = 621 in²

A trapezοid, alsο knοwn as a trapezium, is a flat clοsed shape having 4 straight sides, with οne pair οf parallel sides.

The parallel sides οf a trapezium are knοwn as the bases, and its nοn-parallel sides are called legs. A trapezium can alsο have parallel legs. The parallel sides can be hοrizοntal, vertical οr slanting.

The perpendicular distance between the parallel sides is called the altitude.

From the figure given:

Area of trapezoid [tex]\rm = \frac{a + b}{2} \cdot h[/tex]

Area of trapezoid [tex]\rm = \frac{24 + 51}{2} \cdot 18[/tex]

Area of trapezoid = 675 in²

Area of triangle = 1/2 × base × height

Area of triangle = 1/2 × 9 × 12

Area of triangle = 54 in²

Total Shaded Area = 675 - 54

Total Shaded Area = 621 in²

Thus, Area of trapezoid = 675 in², Area of triangle = 54 in² and Total Shaded Area = 621 in²

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a. Yes, the estimate of age based on 500 plots is influenced by sampling error.

Sampling error occurs because the sample is only a portion of the entire population, and the sample may not perfectly represent the whole population.

Therefore, the estimate of the mean age derived from the sample might deviate from the true mean age of the entire population.

b. If the investigators had used a sample of only 100 plots instead of 500, the sampling error of the estimate of mean age would likely increase. As the sample size decreases, the likelihood of the sample representing the whole population accurately decreases as well.

Consequently, the deviation between the sample means age and the true population mean age would likely be larger, leading to a higher sampling error.

Sampling error refers to the difference or discrepancy between a sample's characteristics and the corresponding characteristics of the entire population from which the sample was drawn. It arises due to the fact that a sample is only a subset of the population, and the sample may not perfectly represent the whole population. Sampling error can impact the accuracy of statistical inferences and conclusions drawn from the sample, such as estimates of mean, variance, or correlation.

As the sample size decreases, the likelihood of the sample representing the whole population accurately decreases as well, leading to higher sampling error.

Therefore, minimizing sampling error is crucial in ensuring the validity and reliability of research findings.

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Answer:

9 and 40investment is costing 542

Volume is a three-dimensional scalar quantity. The correct option is B, (4/3)π(10)³ - (4/3)π(4)³.

We have been given that a large sphere has a diameter of 20 feet. A smaller sphere with a radius of 4 feet is cut out of the center of the larger sphere. We are asked to find the volume outside smaller sphere and inside larger sphere.

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

The volume, in cubic units, of the shaded part of the sphere is the difference between the volume of the larger sphere and the smaller sphere. Therefore, the volume can be written as,

The volume of the sphere = (4/3)π(10)³ - (4/3)π(4)³

Hence, the correct option is B, (4/3)π(10)³ - (4/3)π(4)³.

Complete Question:

The large sphere has a diameter of 20 feet. A large sphere has a diameter of 20 feet. A smaller sphere with a radius of 4 feet is cut out of the center of the larger sphere. Which expression represents the volume, in cubic units, of the shaded part of the sphere? Four-thirdsπ(103) + Four-thirdsπ(43) Four-thirdsπ(103) – Four-thirdsπ(43) Four-thirdsπ(203) + Four-thirdsπ(43) Four-thirdsπ(203) – Four-thirdsπ(43)

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The best question to determine the evidence for the given hypotheses is "If we examine the proportion of students at their campus who still live at home with their parents, how likely is that proportion to be more than 36%?" so, the correct option is D).

This question directly relates to the alternative hypothesis which states that the proportion of millennial students living at home with their parents is more than 36%.

Therefore, we need to determine the probability of observing a proportion of 36% or higher in a sample of 300 students if the true proportion is actually 36%.

So, the correct answer is D).

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--The given question is incomplete, the complete question is given

" Question 3 Select one answer Living with parents: The Pew Research Center reported that 36% of American Mille nnials (adults ages 18-31) still live at home with their parents. 10 points A group of students wants to conduct a study to determine whether this result is true for students at their campus. They survey 300 randomly selected students at their campus and determine that 43% of them live at home with their parents. With this data, they test the following hypotheses H o: Of Mille nnial students at their campus, 36% live at home with their parents. Ha: More than 36% of Millennial students at their campus live at home with their parents In order to assess the evidence, which question best describes what we need to determine?

A. If we examine a sample of students at their campus and determine the proportion who  still live at home with their parents, how likely is that proportion to be 36%?

B. If we examine a sample of students at their campus and determine the proportion who  still live at home with their parents,  how likely is that proportion to be 43% or more?

C.  If we examine the proportion of students at their campus who  still live at home with their parents, still live at home with their how likely is that proportion to be more than 36%?

D. IF if we examine the proportion of students at their campus who still live at home with their parents,  how likely is that proportion to be 36%?

E. If we examine the proportion of students at their campus who still live at home with their still live at home with their parents, how likely is that proportion to be 43%?"--

The shaded area under the curve is approximately 9.11, which confirms our result.

In calculus, an integral is a mathematical object that represents the area between a curve and the x-axis. It is a fundamental concept in calculus, and is used to calculate quantities such as the area under a curve, the volume of a solid, and the work done by a force. The process of finding an integral is called integration, and it involves finding an antiderivative (or indefinite integral) of a function, which is a function whose derivative is equal to the original function. The definite integral is then calculated by evaluating the antiderivative at two limits, which represent the beginning and end points of the area being calculated.

Here,

We can start by expanding the integrand using the distributive property:

(9 - t)√t = 9√t - t√t

Now we can integrate each term separately using the power rule of integration:

∫(9 - t)√t dt = ∫9√t dt - ∫t√t dt

= 18/2 * [tex]t^{(1/2)}[/tex] - 2/3 * [tex]t^{(3/2)}[/tex] + C

where C is the constant of integration.

Evaluating the definite integral from 0 to 2:

∫(9 - t)√t dt from 0 to 2 = [18/2 * [tex]2^{(1/2)}[/tex] - 2/3 * [tex]2^{(3/2)}[/tex]] - [18/2 * [tex]0^{(1/2)}[/tex] - 2/3 * [tex]0^{(3/2)}[/tex]]

= 9√2 - 4/3

≈ 9.11

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Hence, the circle's basic shape is as follows: [tex]x^2 - 30x + y^2 - 14y + 199=0[/tex] as the equation for a circle from standard form to general form.

All the points on a planar that are equally spaced from a specific point known as the circle's centre make up the geometric shape known as a circle. The radius of a circle is the separation between the centre and any point along its circumference. The fact that all of a circle's radii (plural of radius) are the same length, that the inner diameter (the distance it around circle) is proportional to the diameter (the length across the circle passing through the centre), and that the area enclosed by such a circle is inversely proportional to the square of its radius are just a few of the many significant properties of circles. From geometry and mathematics via architecture, art, and science, circles are employed in a variety of disciplines.

given

We must expand the square terms and simplify the equation in order to translate the equation for a circle from standard form to general form.

Using the circle's conventional form as a starting point:

[tex](x - 15)^2 + (y - 7)^2 = 25[/tex]

Adding phrases to the squares

[tex]x^2 - 30x + 225 + y^2 - 14y + 49 = 25[/tex]

Simplifying by grouping together all the terms:

[tex]x^2 - 30x + y^2 - 14y + 199 = 0[/tex]

Hence, the circle's basic shape is as follows: [tex]x^2 - 30x + y^2 - 14y + 199=0[/tex] as the equation for a circle from standard form to general form.

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The gas used by Abby while travelling in her pizza delivery route is 1/4.

As per the given question here we have to implement the basic principles of subtraction along with application of LCM.

The total amount of gas that Abby had in her car = 11/12

After coming to pizzeria the amount of gas left in her tank = 3/4

Here, we have to perform Subtraction to find out the amount of gas used for travelling. Therefore,

= 11/12 - 3/4

performing the LCM, we get

= 11 - 9/12

= 3/12 => 1/4

The gas used by Abby while travelling in her pizza delivery route is 1/4.

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The statements that are True about the Confounding variables are :

(a) Variables can make the relationship look different than it really is,

(b) Variables that are associated with both exposure and outcome.

The Confounding-Variables are defined as variables that are associated with both the exposure and outcome variables in a study.

These variables can make the relationship between the exposure and outcome variables look-different than it really is, which can lead to biased results.

The confounding variables are associated with both the exposure and outcome variables it means that if the relationship between the exposure and outcome variables is not properly adjusted for the confounding variable, the effect of the exposure on the outcome may be overestimated or underestimated.

Therefore, the correct options are (a) and (b).

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The given question is incomplete, the complete question is

Which of the following is/are true about confounding variables?

(a) Variables can make the relationship look different than it really is

(b) Variables that are associated with both exposure and outcome

(c) Variable that decreases the independent variable's impact on the dependent variable

(d) Variables that can increase the chance of a type ii error while eliminating the chance of a type i error

Let's assume the height of the wall as 'h' meters.

Given, the perimeter of the wall = area of the wall

The perimeter of the wall = 2(length + breadth) = 2(7+h) = 14+2h meters

The area of the wall = length × breadth = 7 × h = 7h square meters

According to the problem, the perimeter and area of the wall have the same value.

So, 7h = 14 + 2h

Subtracting 2h from both sides, we get:

5h = 14

Dividing both sides by 5, we get:

h = 2.8 meters

Therefore, the height of the wall is 2.8 meters.

Hence, the answer is 2.8 meters

Answer:

2.8 meters

I've done the quiz

Answer:

9/8, 1.125, or 1 1/8

Answer: [tex]\frac{21}{8}[/tex] or 2.625

Step-by-step explanation:

Improper fractions

First, we want to convert 1 3/4 to an improper fraction.

We multiply the denominator(4)  by the coefficient (1) and add it to the numerator (3).

This gets us [tex]\frac{7}{4}[/tex]

Keep change flip

When dividing fractions, a helpful thing to remember is "keep change flip"

This means you keep the first number as it is, change the division sign to multiply, and flip the divisor, in this case 2/3, to be 3/2.

So, the problem becomes [tex]\frac{7}{4} *\frac{3}{2}[/tex]

Now, you jut multiply the numerators and denominators

[tex]\frac{7*3}{4*2} =\frac{21}{8}=2.625[/tex]

(a) The experimental probability of rolling a 3 is approximately 8%.

(b) The experimental probability of rolling a 6 is 25%.

(c) The experimental probability of rolling a number less than 4 is 50%.

The experimental probability of rolling a 3 can be determined from the result presented in the table as shown below.

from the result presented, there a total outcome of 12

number of rolling a 3 in the result = 1

P(3) = 1/12 = 0.083

P(3) ≈ 8%

The experimental probability of a rolling a 6 is calculated as;

number of 6 obtained in the result = 3

P(6) = 3/12

P(6) = 0.25

P(6) = 25%

The experimental probability of rolling a number less than 4:

P ( less than 4) = P(1) + P(2) + P(3)

P ( less than 4) = 17% + 25% + 8%

P ( less than 4) = 50%

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the amount of money available can be represented by the following inequality: 5a + 7b ≤ 200

What is inequality?

Mathematical expressions with inequalities on both sides are known as inequalities. In an inequality, we compare two values as opposed to equations. In between, the equal sign is changed to a less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

Since the aprons with 2 pockets cost $5 each and the aprons with 4 pockets cost $7 each, the constraint on the number of aprons that can be purchased based on

Hence, the amount of money available can be represented by the following inequality: 5a + 7b ≤ 200

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A complete graph is one in which there is an edge connecting every vertex to every other vertex. In order to determine for what values of n a complete graph with n vertices has an Euler circuit and a Hamiltonian circuit, let's discuss the definitions and requirements of each type of circuit.

1. Euler Circuit: An Euler circuit is a path that traverses each edge of a graph exactly once and returns to its starting vertex. For a graph to have an Euler circuit, all vertices must have an even degree (number of edges connected to the vertex).

2. Hamiltonian Circuit: A Hamiltonian circuit is a path that visits every vertex in a graph exactly once and returns to its starting vertex. A complete graph always has a Hamiltonian circuit, regardless of the number of vertices.

Now, let's determine for what values of n a complete graph has an Euler circuit:

In a complete graph with n vertices, each vertex is connected to every other vertex, which means the degree of each vertex is (n-1). For a complete graph to have an Euler circuit, all vertices must have an even degree. This implies that (n-1) must be even, so n must be odd.

So, for a complete graph with n vertices to have an Euler circuit, n must be an odd number.

In summary:
- A complete graph with n vertices always has a Hamiltonian circuit.
- A complete graph with n vertices has an Euler circuit if n is an odd number.

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