Are the polygons similar? If they are, write a similarity statement. The figures are not drawn to scale.

An equivalent expression for the total length of fencing is 11y+10 inches.

The whole distance encircling a shape is referred to as its perimeter. It is the length of any two-dimensional geometric shape's boundary or outline. Depending on the size, the perimeter of several figures can be the same.

From the given figure, length of rectangle is (3y+5) inches and breadth is y inches. Sides of equilateral triangle measures y inches.

a) We know that, the perimeter of a rectangle is 2 (Length+Breadth)

= 2(3y+5+y)

= 2(4y+5)

= 8y+10 inches

Perimeter of equilateral triangle is 3×Side

= 3×y

= 3y inches

So, total length = 8y+10+3y inches

b) Equivalent expression is

8y+10+3y

= 11y+10 inches

c) Factors of the expression is 1 and 11y+10.

Therefore, an equivalent expression for the total length of fencing is 11y+10 inches.

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The cost of the washer is $265 and the cost of the dryer is $350.

To solve this word problem with two unknowns using a linear equation, we can use the following steps:

So, the cost of the washer is $265 and the cost of the dryer is $350.

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Answer:

To compare the cost of each option, we need to calculate the cost per flyer.

For the first option, the cost per flyer is:

30 dollars / 100 flyers = 0.3 dollars/flyer

For the second option, the cost per flyer is:

65 dollars / 250 flyers = 0.26 dollars/flyer

Therefore, the second option is cheaper per flyer. However, if you only need 100 flyers, the first option would be more cost-effective.

Step-by-step explanation:

Answer: $65 for 250 flyers is cheaper

Step-by-step explanation:

30 dollars per 100 flyers - 30/100 = 0.30 or 30 cents per flyer

65 dollars per 250 flyers - 65/250 = 0.26 or 26 cents per flyer

A) To graph the constraints of the problem, we need to rearrange each constraint into slope-intercept form (y = mx + b) and plot them on a graph.

For the first constraint, 4x1+6x2 <= 22, we can rearrange it as follows:

6x2 <= -4x1 + 22

x2 <= (-2/3)x1 + (22/6)

For the second constraint, 1x1+5x2 <= 15, we can rearrange it as follows:

5x2 <= -1x1 + 15

x2 <= (-1/5)x1 + (15/5)

For the third constraint, 2x1+1x2 <= 9, we can rearrange it as follows:

1x2 <= -2x1 + 9

x2 <= (-2)x1 + 9

We can now plot these constraints on a graph with x1 on the x-axis and x2 on the y-axis.

B) To solve the LP relaxation of this problem, we can use the simplex method. The objective function is Max 1x1+1x2. The constraints are 4x1+6x2 <= 22, 1x1+5x2 <= 15, 2x1+1x2 <= 9, x1 >= 0, and x2 >= 0.

Using the simplex method, we can find that the optimal solution is x1 = 3 and x2 = 2, with an objective function value of 5.

C) To find the optimal integer solution, we can use the branch and bound method. We start with the LP relaxation solution of x1 = 3 and x2 = 2. Since this is already an integer solution, it is the optimal integer solution. The objective function value is 5.

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The points (1, 1) and (2, 2) have been used to graph the inequality as shown in the image attached below.

The boundary line is dashed.

The boundary line is shaded below.

In Mathematics, there are two (2) main rules that are generally used for writing and interpreting an inequality or system of inequalities that are plotted on a graph and these include the following:

Additionally, the point (2, 2) and point (1, 1) are not solutions to the given inequality y < 1/4(x) + 1 because the lie below the boundary line

y < 1/4(x) + 1

2 < 1/4(2) + 1

2 < 3/2 (False)

y < 1/4(x) + 1

1 < 1/4(1) + 1

2 < 5/4 (False)

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The given information tells us that the sin a is equal to 5/13, and that 0 is less than a, which is less than π/2. Therefore, the exact function value for sin a is 5/13 and the value for a is approximately  5/12.

We are given that sin(a) = 5/13 and 0 < a < π/2. We can use the Pythagorean identity cos²(a) + sin²(a) = 1 to find cos(a):

cos²(a) + sin²(a) = 1

cos²(a) + (5/13)² = 1

cos²(a) = 1 - (5/13)²

cos²(a) = 144/169

cos(a) = ± 12/13

Since 0 < a < π/2, we know that cos(a) > 0. Therefore, cos(a) = 12/13. We can use the definition of tangent to find tan(a):

tan(a) = sin(a)/cos(a) = (5/13)/(12/13) = 5/12

Therefore, the exact function value we were asked to find is tan(a) = 5/12.

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Answer:

To find the selling price of the laptop that costs R4 200 before VAT, we need to add 15% VAT to the cost.

The VAT amount can be calculated as:

VAT = 15% of R4 200

VAT = (15/100) x R4 200

VAT = R630

The selling price including VAT will be the cost of the laptop plus the VAT amount:

Selling price = R4 200 + R630

Selling price = R4 830

Therefore, the selling price of the laptop that costs R4 200 before VAT will be R4 830 after adding 15% VAT.

The given expression evaluates to 366.

The sum of the series is computed using the summation formulas. There are many different kinds of sequences, including arithmetic and geometric sequences, and consequently, there are many different kinds of summing formulas for those different kinds of sequences.

As per the given data:

To find [tex]\sum_{n=2} ^6 n (n^2 -n+1)[/tex]

Simplifying the given expression:

[tex]\sum_{n=2} ^6 n^3 - n^2 + n[/tex]

using the formulas:

[tex]\sum n = \frac{n(n+1)}{2}\\\\\sum n^2 = \frac{n(n+1)(2n+1)}{6}\\\\\sum n^3 = \frac{n^2(n+1)^2}{4}[/tex]

=  [tex][\frac{n^2(n+1)^2}{4} - [\frac{n(n+1)(2n+1)}{6}] + \frac{n(n+1)}{2}]_{n=2} ^ 6[/tex]

substitute the values of limit:

= 371 - 5

= 366

Hence, the given expression evaluates to 366.

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The statement  "If G is connected with 2 or more nodes, then all nodes must have a degree bigger or equal to 1." is true.

This is because a connected graph is defined as a graph in which there is a path between any two nodes. If a node has a degree of 0, that means it is not connected to any other nodes, and therefore the graph cannot be connected. So, in order for G to be connected, all nodes must have a degree of at least 1.

In conclusion, the answer is true.

A node is a point where several elements are connected.

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By using Euclid's first book, we can prove that the quadrilateral produced by perpendicular, unequal, bisecting diagonals is a kite. A kite is a quadrilateral with two pairs of adjacent sides that are equal in length. In this case, the two pairs of adjacent sides are formed by the diagonals bisecting the quadrilateral into four smaller triangles with equal areas.

According to Euclid's first book, when two lines intersect at a right angle (perpendicular), they form four right angles. In the case of a quadrilateral with perpendicular, unequal, bisecting diagonals, the diagonals intersect at a right angle and divide the quadrilateral into four smaller triangles with equal areas.

1. Draw a quadrilateral with perpendicular, unequal, bisecting diagonals.
2. Label the points where the diagonals intersect as A, B, C, and D.
3. Label the point where the diagonals intersect as E.
4. Use Euclid's first book to prove that the angles at E are all right angles.
5. Use Euclid's first book to prove that the four triangles formed by the diagonals are congruent (equal in area).
6. Use the definition of a kite to prove that the quadrilateral is a kite (two pairs of adjacent sides are equal in length).
7. Therefore, the quadrilateral produced by perpendicular, unequal, bisecting diagonals is a kite.

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The three-dimensional figure this net will make is a triangular prism and is denoted as option B.

This is defined as a solid figure or an object or shape that has three dimensions such as length, width, and height.

An example is the triangular prism is a polyhedron made up of two triangular bases and three rectangular sides and from the net given above we can deduce that the triangular prism can be formed from it due to the shape and vertices.

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slope = -1/5

used slope forumula

There are 23 students taking exactly 2 subjects.

To find the number of students taking exactly 2 subjects, we can use the formula:

n(A∩B∩C) = n(A) + n(B) + n(C) - 2n(A∩B) - 2n(B∩C) - 2n(C∩A) + 3n(A∩B∩C)

Since we know that no one takes all three subjects, n(A∩B∩C) = 0. We can plug in the values given in the question and solve for n(A∩B), which represents the number of students taking exactly 2 subjects:

0 = 12 + 16 + 18 - 2n(A∩B) - 2(0) - 2(0) + 3(0)

0 = 46 - 2n(A∩B)

2n(A∩B) = 46

n(A∩B) = 23

Therefore, the number of students taking exactly 2 subjects is 23.

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a) There are 128 subsets of A with 8 elements. This is because the number of subsets of a set with n elements is 2 ^ n. Therefore, the number of subsets of A with 8 elements is 2 ^ 8 = 128.

b) There are 82 subsets of A with 8 elements that have only numbers. This is because there are 10 numbers in A and each of these numbers can be included or excluded from the subset of 8 elements. Therefore, the number of subsets of A with 8 elements that have only numbers is 2 ^ 10 = 1024.

c) There are 46 subsets of A with 8 elements that have only letters. This is because there are 6 letters in A and each of these letters can be included or excluded from the subset of 8 elements. Therefore, the number of subsets of A with 8 elements that have only letters is 2 ^ 6 = 64.

d) There are 28 subsets of A with 8 elements that have 2 letters. This is because there are 6 letters in A and each of these letters can be included or excluded from the subset of 8 elements twice. Therefore, the number of subsets of A with 8 elements that have 2 letters is 2 ^ 12 = 4096.

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Answer:

5x - 3

Step-by-step explanation:

Given:

A Number and multiply it by 2.

To Find:

to write it algebraically

Solution:

Let the number that was asked to think to be x.

Then it is multiplied by 2 which becomes 2x.

Now the number is multiplied by 5.

So, x multiplied by 5 will become 5x.

Then, 5x is subtracted from 3.

So, we can write it as 5x - 3

Therefore, it can be written as 5x - 3 algebraically.

The combined rate of all three workers is 6 fences per 3 hours.

To find out how long it would take for all three painters to paint the fence together, we need to find the combined rate of work for Abel, Baker, and Chuck.

Let's first find the rate of work for each painter individually.

Abel's rate of work is 1/18 of the fence per hour (since he can paint the whole fence in 18 hours).

Baker's rate of work is twice as fast as Abel's, so his rate of work is 2/18 (or 1/9) of the fence per hour.

Chuck's rate of work is three times as fast as Abel's, so his rate of work is 3/18 (or 1/6) of the fence per hour.

Now, to find the combined rate of work for all three painters, we simply add their individual rates of work together:

1/18 + 1/9 + 1/6 = 1/18 + 2/18 + 3/18 = 6/18 = 1/3

This means that together, the three painters can paint 1/3 of the fence per hour.

To find out how long it would take them to paint the whole fence, we simply divide the total amount of work (1 whole fence) by their combined rate of work (1/3 of the fence per hour):

1 ÷ 1/3 = 3

So it would take the three painters 3 hours to paint the whole fence together.

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Answer:

To find the shorter route, we need to calculate the distances for both routes and compare them.

Route through Towns P and Q:

The distance between Town A and Town P is 3 units to the right and 5 units up, so it is √(3² + 5²) = √34 km.

The distance between Town P and Town Q is 2 units to the right, so it is 2 km.

The distance between Town Q and Town B is 4 units to the right and 4 units down, so it is √(4² + 4²) = 4√2 km.

Therefore, the total distance for this route is √34 + 2 + 4√2 km.

Route through Town R:

The distance between Town A and Town R is 5 units to the right and 3 units up, so it is √(5² + 3²) = √34 km.

The distance between Town R and Town B is 5 units to the right and 7 units down, so it is √(5² + 7²) = √74 km.

Therefore, the total distance for this route is √34 + √74 km.

Comparing the distances, we can see that:

√34 + 2 + 4√2 km ≈ 10.2 km

√34 + √74 km ≈ 12.6 km

Therefore, the shorter route is the one that goes through Towns P and Q, which is approximately 10.2 km long.

On simplifying ((7)/(8)+(1)/(2))/(2(1)/(4)) the correct answer is 2 3/4.

To solve the problem ((7)/(8)+(1)/(2))/(2(1)/(4)), we can follow these steps:

Step 1: Simplify the expression inside the parentheses in the numerator.
(7/8) + (1/2) = (7/8) + (4/8) = (11/8)

Step 2: Simplify the expression inside the parentheses in the denominator.
2(1/4) = (2/1)(1/4) = (2/4) = (1/2)

Step 3: Divide the simplified numerator by the simplified denominator.
(11/8) ÷ (1/2) = (11/8) × (2/1) = (22/8) = (11/4)

Step 4: Simplifying the final expression, if possible.
(11/4) = 2 3/4

Therefore, the correct answer is 2 3/4.

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Answer:

-8=x

Step-by-step explanation:

-6=x+2

take away 2 from each side

-8= x

Answer:

x = -8

Step-by-step explanation:

To solve for x in equation 3(x - 2) = 4x + 2, we need to simplify the expression on the left side of the equation by using the distributive property. This gives:

3x - 6 = 4x + 2

Next, we need to isolate the variable x on one side of the equation. We can do this by adding 6 to both sides of the equation:

3x - 6 + 6 = 4x + 2 + 6

Simplifying this expression, we get:

3x = 4x + 8

Now, we need to isolate x again by subtracting 4x from both sides:

3x - 4x = 4x + 8 - 4x

Simplifying this expression gives:

-x = 8

Finally, we solve for x by multiplying both sides of the equation by -1:

x = -8

Therefore, the solution to the equation 3(x-2) = 4x + 2 is x = -8.

Answer:

The 7 screws offer superior tensile strength over the 8 nails. The 7 screws are heavier.

Yes, the given ring is commutative.We have that, a commutative ring in abstract algebra is a ring that satisfies a +b = b+a (for a defined operator).

Given: R is a ring such that [tex]$x = x^2$[/tex] for all [tex]$x\in R$[/tex].

To prove: R is a ring commutative.

Proof:

Let [tex]$a$[/tex] and [tex]$b$[/tex] be arbitrary elements in [tex]$R$[/tex].

[tex]$a+b = (a+b)^2 = a^2 + 2ab + b^2$[/tex]

[tex]$b+a = (b+a)^2 = b^2 + 2ab + a^2$[/tex]

Therefore, [tex]$a+b = b+a$[/tex]. Thus, R is a ring commutative.

Q.E.D.

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The matrices A and B are given as:

A = [3/4 0]
[0 3/4]

B = [-4 0]
[0 -4]

2a) Compute AB:

AB = [3/4 0] * [-4 0]
[0 3/4] [0 -4]

= [3/4 * -4 + 0 * 0 3/4 * 0 + 0 * -4]
[0 * -4 + 3/4 * 0 0 * 0 + 3/4 * -4]

= [-3 0]
[0 -3]

2b) Compute BA:

BA = [-4 0] * [3/4 0]
[0 -4] [0 3/4]

= [-4 * 3/4 + 0 * 0 -4 * 0 + 0 * -4]
[0 * 3/4 + -4 * 0 0 * 0 + -4 * 3/4]

= [-3 0]
[0 -3]

2c) How did your answer in part (a) and (b) compare?

The answers in part (a) and (b) are the same. Both AB and BA resulted in the matrix [-3 0] [0 -3].

2d) Will this be true, in general, for any two matrices when you multiply them (assuming their dimensions line up so that they may be multiplied)? If so, explain your reasoning. If not, show an example of two matrices C and D such that CD≠DC.

No, this will not be true in general for any two matrices when you multiply them. The order in which matrices are multiplied matters, and in most cases, AB≠BA. Here is an example of two matrices C and D such that CD≠DC:

C = [1 2]
[3 4]

D = [5 6]
[7 8]

CD = [1 * 5 + 2 * 7 1 * 6 + 2 * 8]
[3 * 5 + 4 * 7 3 * 6 + 4 * 8]

= [19 22]
[43 50]

DC = [5 * 1 + 6 * 3 5 * 2 + 6 * 4]
[7 * 1 + 8 * 3 7 * 2 + 8 * 4]

= [23 34]
[31 50]

As you can see, CD≠DC.

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Answer:

The correct next step is the answer choice

x^2+b/a x=-c/a

Step-by-step explanation:

Answer:

X = 31 1/3

Step-by-step explanation:

3x - 4= 90

Step 1:

* opposite operation *

90 + 4 = 94

94/3 = 31 1/3

CHECK

*Replace x with your solution(s)*

3(3 1/3) - 4

3 x 31/3 = 94

94-4= 90

The length οf οne side οf the square is √17 and the area οf the square is 17 square units.

Cοοrdinate geοmetry is a branch οf mathematics that uses algebraic equatiοns tο describe the relatiοnships between pοints and shapes in a plane. It invοlves using the Cartesian cοοrdinate system tο represent pοints with οrdered pairs οf numbers.

We can start by finding the distance between twο οppοsite vertices οf the square using the distance fοrmula:

d = √[(x2 - x1)² + (y2 - y1)²]

Let's find the distance between the pοints (5, 4) and (1, 5), which are οppοsite vertices οf the square:

d = √[(1 - 5)² + (5 - 4)²] = √[16 + 1] = √17

Sο the length οf οne side οf the square is √17.

Tο find the area οf the square, we can use the fοrmula:

area = side²

Substituting the value οf the side that we fοund abοve, we get:

area = (√17)² = 17

Therefοre, the area οf the square is 17 square units.

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The trigonometric value of angle Cos Z would be = 77°

A trigonometric value is defined as those values that are based on three major trigonometric ratios such as the Sine, Cosine, and Tangent.

According to the rules of trigonometry the following is carried out:

Sine or sin θ = Side opposite to θ / Hypotenuse = XY / XZ

Cosines or cos θ = Adjacent side to θ / Hypotenuse = YZ / XY

Tangent or tan θ =Side opposite to θ / Adjacent side to θ = XY / YZ.

Therefore, the trigonometric value of cos Z = adj/hypo = 9/40 = 0.225

Z = Cos^-1 0.225.

Z = 76.9 = 77°

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1. Completing the conversion of 12 feet 8 inches to inches, Stella who stated that 12 feet 8 inches = 152 inches is correct unlike Vladimir who got 9 inches.

2. Stella and Vladimir need to convert the given measurement into inches.

3. No conversion factor is given for the problem.  However, the conversion factor could be found online or using the mathematical table.

4. Stella's and Vladimir's answers differ because Vladimir failed to convert the feet into inches.

5. Stella's answer is more reasonable, and it is correct because 12 feet equal 144 inches plus 8 inches, giving 152 inches.

6. The final answer should not just be a number without indicating the unit of measurement.

A unit conversion is the mathematical expression of the same property in a different unit of measurement.

For instance, instead of stating distance in kilometers, it can be depicted in miles.  Similarly, instead of reporting time in hours, it can be reported in minutes or seconds.

1 foot = 12 inches

12 feet = 144 inches

12 feet 8 inches = 152 inches (12 x 12 + 8)

Thus, in this situation, the measurement to be converted is feet to inches.

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