Approximate 0.007349 to 3 significant figure​

Answers

Answer 1

Answer:

0.007349 to 3 significant figure=0.00735

Step-by-step explanation:

Approximate 0.007349 to 3 significant figure

Significant figure start from 1 to 9 with the exclusion of 0

From the question above, there are two zeros after the decimal point, so it will be ignored because it is not a significant figure.

0.007349

The first significant number is 7 after 0

The second significant number is 3

The next

The third significant number is 4

The fourth significant number is 9

We want to approximate to three significant figure, so, all figure after 4(third significant figure) will be rounded up or down.

If the numbers are below 5(0, 1,2,3,4) they will be rounded down to 0

If the numbers are above 4(5,6,7,8,9), they will be rounded up to 1

So the number after 4 is 9, therefore it will be rounded up to make 4=5

0.007349 to 3 significant figure=0.00735


Related Questions

A shop has a sale of 10% off all items in stock. If the original price of a dress is £60 what would be its sale price?

Answers

Answer:

£ 54

Step-by-step explanation:

Given,

Discount percent = 10%

Marked price ( MP ) = £ 60

Selling price ( SP ) = ?

Now, finding the discount amount:

Discount amount = discount percent of MP

= 10% of 60

= £ 6

Selling price = Marked price - Discount amount

=£ 60 - £ 6

= £ 54

hope this helps...

Good luck on your assignment..

MP= £60
Discount= 10%

SP= 60-(10/100*60)
= 60-6
= £54

Hope it helps
Please mark my answer as BRAINLIEST

How do I know that the following equation is true:

Answers

Answer:

Half angle Identity for cosine:

[tex]$\cos \left(\frac{\theta}{2} \right)=\pm \sqrt{\frac{1+\cos(\theta)}{2} } $[/tex]

[tex]\text{Note that it is} \pm \text{because we don't know which Quadrant the half-angle is, }[/tex][tex]\text{the information of}\cos(\theta) \text{is not enough to conclude the angle}[/tex]

[tex]$\frac{\pi}{8} \text{ is a Quadrant I angle, therefore, positive}$[/tex]

[tex]$\cos \left(\frac{\pi}{8} \right)=\sqrt{\frac{1+\cos(\frac{\pi}{4} )}{2} } $[/tex]

The equation is true.

Solve: d |6n+7|=8 can you guys answer me plezzzzzzzz

Answers

Answer: -5/2 or 1/6

Step-by-step explanation:

I6n + 7I = 8

Therefore (6n + 7) = 8 or -8 because modulus means we're only getting it's absolute value, (it's positive value) meaning it could equal 8 or -8 before it's modulus'ed.

Therefore 6n + 7 = 8

or 6n + 7 = -8

Leaving us with:

6n = 1

6n = -15

So n = 1/6

or n = -5/2 (-2.5)

Answer:

n = 1/6                          n = -5/2

Step-by-step explanation:

|6n+7|=8

This has two solutions, one positive and one negative

6n+7 = 8  and 6n+7 = -8

Subtract 7 from each side

6n+7-7 = 8-7         6n+7-7 =-8-7

6n =1                        6n = -15

Divide by 6

6n/6 = 1/6                 6n/6 = -15/6

n = 1/6                          n = -5/2

Which inequality is equivalent to absolute value x-4 < 9

Answers

Answer:

–9 < x – 4 < 9

Step-by-step explanation:

Pls help I need help with 12

Answers

Answer:

B. 14

Step-by-step explanation:

22/x = 11/(21-x)

462 - 22x = 11x

462 = 33x

x = 14

Answer: The value of x is 14, answer choice B

Let y be the other line segment connected to x

Using proportions:

[tex]\dfrac{11}{22}=\dfrac{y}{x}[/tex]

Cross multiply and simplify

[tex]22y=11x[/tex]

[tex]y=\dfrac{1}{2}x[/tex]

We know that x and y add to 21, so we can create the following equation:

[tex]x+y=21[/tex]

Substitute y=(1/2)x

[tex]x+\dfrac{1}{2}x=21[/tex]

Simplify by adding like terms

[tex]\dfrac{3}{2}x=21[/tex]

Divide both sides by 3/2

[tex]x=14[/tex]

Let me know if you need any clarifications, thanks!

The formula for finding the kinetic energy, E, of an object is given below, where m represents the mass and v represents the speed of the object.

Answers

Answer:

v=√E/m or v=√E /√m

Step-by-step explanation:

Complete question below:

The formula for finding the kinetic energy, E, of an object is given below, where m represents the mass and v represents the speed of

the object.

E = mv^2

Solve the formula for v.​

Solution

E=mv^2

Where,

E=kinetic energy

m=mass

v=speed of the object

E=mv^2

Divide both sides by m

E/m=mv^2/m

E/m=v^2

It can be rewritten as

v^2=E/m

Square root both sides

√(v^2)=√E/m

v=√E/m

Or

v=√E/√m

This is to say speed (v)=square root of kinetic energy (E) Over masa(m)

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