ANSWER THE QUESTIONS A AND B ! 1ST ONE WHO ANSWERS WITH A CORRECT ANSWER WILL BE MARkED BRAINLIEST!

The length of the third board the builders will add to create a right triangle, according to the Pythagorean Theorem is about 8.72 ft

Pythagorean Theorem is the relationship between the lengths of the three sides of a right triangle. The theorem states that the square of the length of the hypotenuse is equivalent to the sum of the square of the other two sides of the right triangle.

The specified dimensions of the ramp are;

Length of one side of the ramp = 20 ft

Length of the other side of the ramp = 18 ft

The shape of the triangle the builders would like to create = A right triangle

Let x represent the length of the third board, and let the 20 ft board represent the hypotenuse side. Pythagorean Theorem indicates that we get;

20² = 18² + x²

20² - 18² = x²

x² = 20² - 18² = 76

x = √(76) = 2·√(19) ≈ 8.72

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The area of the triangle to the nearest tenth is 5.8cm²

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices. A triangle is also a polygon. Examples of triangle include, isosceles, equilateral , scalene e.t.c

The area of a triangle is expressed as;

A = 1/2 b h for right angle triangle and A = absinC for others.

Here; x = 4.7, y = 7.9, W = 162

area = 1/2× 4.7 × 7.9 sin162

= 1/2 × 4.7 × 7.9 × 0.31

= 5.8 cm²( nearest tenth)

Therefore the area of the triangle is 5.8cm²

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The length of the intercepted arc on the unit circle is equal to the radius of the circle times the angle in radians. In this case, since the unit circle has a radius of 1, the length of the intercepted arc is simply equal to the angle in radians.

So, the length of the intercepted arc for an angle of 1.5 radians is 1.5 units (since the angle is given in radians, not degrees).

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The secant of a °45 angle is defined as the ratio of the length of the hypotenuse to the length of the adjacent side. In this case, the adjacent side is also a leg of length 5, so:

secant(45) = hypotenuse/adjacent = 5√2/5 = √2

The secant function, denoted as sec(x), is a trigonometric function that is defined as the reciprocal of the cosine function, cos(x).

In other words,

sec(x) = 1 / cos(x)

The secant function is defined for all values of x except for those where the cosine function is equal to zero, which corresponds to the values x = (2n+1)π/2 where n is an integer. At these points, the secant function is undefined.

In a °45-°45-°90 triangle, the two legs are congruent, so if the length of the hypotenuse is 5√2, then each leg has a length of:

leg = hypotenuse/√2 = (5√2)/√2 = 5

The sine of a °45 angle is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse. In this case, the side opposite the angle is a leg of length 5, so:

sine(45) = opposite/hypotenuse = 5/5√2 = 1/√2 = √2/2

The secant of a °45 angle is defined as the ratio of the length of the hypotenuse to the length of the adjacent side. In this case, the adjacent side is also a leg of length 5, so:

secant(45) = hypotenuse/adjacent = 5√2/5 = √2

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Answer:

Step-by-the answer is (a) 16

To investigate whether there is an association between cell phone brand and age-group, the researcher can conduct a chi-squared test of independence.

This test compares the observed frequencies in the contingency table to the expected frequencies if there were no association between the variables. If the test results in a p-value less than the chosen significance level (usually 0.05), then the researcher can reject the null hypothesis of no association and conclude that there is evidence of an association between cell phone brand and age-group. The degrees of freedom for this test would be (3-1) * (4-1) = 6.

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Answer:1000

Step-by-step explanation:what about 1000 people

The Taylor series centered at 4 for f(x) = ln(1+x) is: f(x) = ln(5) + (x-4)/5 - (x-4)^2/50 + (2/125)*(x-4)^3 - (6/625)*(x-4)^4 + ... The interval of convergence for this series is (-∞, ∞).

Let's find the Taylor series centered at 4 for the function f(x) = ln(1+x).

We can use the formula for the Taylor series coefficients:

f^(n)(x) = (-1)^(n-1) * (n-1)! / (1+x)^n

where f^(n)(x) denotes the nth derivative of f(x).

Using this formula, we can find the Taylor series centered at 4: f(4) = ln(1+4) = ln(5) f'(x) = 1/(1+x), so f'(4) = 1/5 f''(x) = -1/(1+x)^2, so f''(4) = -1/25 f'''(x) = 2/(1+x)^3, so f'''(4) = 2/125 f''''(x) = -6/(1+x)^4, so f''''(4) = -6/625 and so on.

Putting it all together, the Taylor series centered at 4 for f(x) is:

f(x) = ln(5) + (x-4)/5 - (x-4)^2/50 + (2/125)*(x-4)^3 - (6/625)*(x-4)^4 + ...

To find the interval of convergence, we can use the ratio test:

lim |(f^(n+1)(x) / f^(n)(x)) * (x-4)/(x-4)| = lim |(-1) * (n+1) * (1+x)^2 / (1+x)^n| * |x-4| = lim (n+1) * (1+x)^2 / (1+x)^n * |x-4| = lim (n+1) / (1+x)^(n-2) * |x-4|

Since this limit is zero for all values of x, the interval of convergence is the entire real line, (-∞, ∞).

So the final answer is: The Taylor series centered at 4 for f(x) = ln(1+x) is: f(x) = ln(5) + (x-4)/5 - (x-4)^2/50 + (2/125)*(x-4)^3 - (6/625)*(x-4)^4 + ... The interval of convergence for this series is (-∞, ∞).

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1. x-3y -3=0, 3x-9y-2=0 has no solution

2. 2x+y=5,3x+2y=8 has a unique solution

3. 3x-5y=20,6x-10y=40 has infinitely many solution

4.  x-3y-7 =0,3x-3y-15=0 has No solution

5. 8x+5y=9,3x+2y=4 has a unique solution

(i) To solve using substitution method, we can rearrange the first equation to x=3y+3 and substitute it into the second equation:

3(3y+3) - 9y - 2 = 0

9y + 9 - 9y - 2 = 0

7 = 0

This is a contradiction, so the pair of equations has no solution.

(ii) To solve using elimination method, we can multiply the first equation by 2 and subtract it from the second equation:

3x + 2y = 8

(4x + 2y = 10)

-x = -2

So, x = 2. Substituting this value into the first equation, we get:

2x + y = 5

2(2) + y = 5

y = 1

Therefore, the unique solution is (x,y) = (2,1).

(iii) To solve using elimination method, we can multiply the first equation by 2 and subtract it from the second equation:

6x - 10y = 40

(6x - 10y = 40)

0 = 0

This equation is true for any value of x and y, so the pair of equations has infinitely many solutions.

(iv) To solve using elimination method, we can subtract the first equation from the second equation:

3x - 3y - 15 - (x - 3y - 7) = 0

2x - 22 = 0

x = 11

Substituting this value into the first equation, we get:

11 - 3y - 7 = 0

-3y = -4

y = 4/3

Therefore, the unique solution is (x,y) = (11,4/3).

(v) To solve using elimination method, we can multiply the first equation by 2 and subtract it from the second equation:

3x + 2y = 4

(16x + 10y = 18)

-29x - 18y = -14

Solving for y, we get:

y = (29/18)x + (7/9)

Substituting this expression for y into the first equation, we get:

8x + 5((29/18)x + (7/9)) = 9

(143/18)x = 2/9

x = 2/13

Substituting this value into the expression for y, we get:

y = (29/18)(2/13) + (7/9) = 41/117

Therefore, the unique solution is (x,y) = (2/13,41/117).

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One if the functions of a protein macromolecule is: c. moving material in and out of cells

Proteins can be described as a complex macromolecules that are responsible for several key functions such as the regulation of cells, tissue, and organs of living organisms including their structure.

Proteins also help in performing the following:

Regulation of gene expression

Structural support, and

Many other cellular processes.

Therefore, a function of a protein macromolecule is: c. moving material in and out of cells.

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The domain of the function f(x) is {x | 0 ≤ x ≤ 3650} and the range is {f(x) | 20 ≤ f(x) ≤ 9145}, where f(x) represents the amount Billy would spend to rent x films.

The domain D of the function f(x) is the collection of all possible values for x. In this scenario, because Billy is not permitted to rent more than ten films every day, the maximum number of films he may rent in a year is ten times the number of days in a year, or 10 x 365 = 3650 films.

Furthermore, because he must pay a membership fee of $20 regardless of how many movies he rents, the minimum number of movies he could rent in a year is zero. As a result, the domain of the function f(x) is as follows:

D = {x | 0 ≤ x ≤ 3650}

The range R of the function f(x) is the collection of all possible values for f(x). In this scenario, the function: returns the amount Billy would spend to rent x films.

f(x) = 2.5x + 20

where 2.5x is the rental charge for x films and 20 is the membership fee. Because x can be any value between 0 and 3650, the smallest value that f(x) can be is:

f(0) = 2.5(0) + 20 = 20

and f(x) has the following maximum value:

f(3650) = 2.5(3650) + 20 = 9145

As a result, the function f(x) has the following range:

R = {f(x) | 20 ≤ f(x) ≤ 9145}

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The correct answer for the equation is  [tex]h = -2cos(\pi t) + 5[/tex] . The correct option is (1)

Given:

[tex]h= -2sin(\pi\tfrac{t}{2} )[/tex]

Examine the answer choices:

[tex]h = -2cos(\pi t) + 5[/tex]

Amplitude: |-2| = 2 (same as the given equation)

Frequency: π (same as the given equation)

Phase Shift: None (different from the given equation)

[tex]h = -2cos(\pi (t/2)) + 5[/tex]

Amplitude: |-2| = 2 (same as the given equation)

Frequency: π/2 (different from the given equation)

Phase Shift: None (different from the given equation)

[tex]h = 2cos(\pi t) + 5[/tex]

Amplitude: |2| = 2 (different from the given equation)

Frequency: π (same as the given equation)

Phase Shift: None (different from the given equation)

[tex]h = 2cos(\pi(t/2)) + 5[/tex]

Amplitude: |2| = 2 (different from the given equation)

Frequency: π/2 (different from the given equation)

Phase Shift: None (different from the given equation)

The correct equation is [tex]h = -2cos(\pi t) + 5[/tex]  .The correct option is (1).

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Mark originally had 28 shoes.

Now we can use the equation for Grace's number of shoes to find her final count:

Grace = x + 16 = 28 + 16 = 44

So Grace ends up with 44 shoes.

Let's start by setting up an equation to represent the given information:

Let the number of shoes Mark has be represented by "x"

Grace has 16 more shoes than Mark:

Grace = x + 16

Mark gives Grace 12 shoes, so Grace now has:

Grace = x + 16 + 12 = x + 28

Mark realized he has half as many shoes as Grace:

x = 0.5(x + 28)

Simplifying this equation:

x = 0.5x + 14

0.5x = 14

x = 28

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The set of numbers is an example of the integers.

The set of numbers is an example of the integers. Integers are whole numbers (positive or negative) and zero. They are often represented by the symbol "Z". In this set, we have all the whole numbers from negative infinity to positive infinity, including negative and positive 3, 2, 1, 0, and all the numbers in between. The use of ellipses indicates that the set goes on indefinitely in both directions. It is worth noting that 1 appears twice in the set, indicating that sets of integers may have repeated elements. Overall, the set of numbers shown is an infinite set of integers.

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Answer:

37.5%

Step-by-step explanation:

If all were the same from opening 3, it would all have to be mushroom soup.  This would look like: desired outcome/total quantity: 3/8 = 0.375 = 37.5%

The area of the path surrounding a rectangular garden is 105 square feet

The area of path will be given by the relation -

Area of path = Outer area - inner area

Inner area = 20 × 12

Multiply the values

Inner area = 240 square feet

Outer area = (20 + 3) × (12 + 3)

Add the values inside parenthesis

Outer area = 23 × 15

Perform multiplication on Right Hand Side of the equation

Outer area = 345 square feet

Area of path = 345 - 240

Subtract the values

Area of path = 105 square feet

Hence, the area of rectangular path is 105 square feet.

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The features of function gif g(x) = f(x + 4) + 8 is vertical asymptote of r = -4.

Since they enable us to convert an exponential equation into a logarithmic equation and vice versa, logarithmic functions are employed to solve equations involving exponents. They are also used in a variety of disciplines, including science, finance, and engineering.

Given equation:

g(x) = f(x + 4) + 8.

f(x) → f(x + 4)

Horizontal translation less 4 unit.

(x, y) → (x - y), y

f(x, y) + 8

Vertical translation up 4 unit.

(x, y) → (x, y + d)

f(x)

Vertical Asymptote x = 0,

f(x + 4) + 8

Vertical Asymptote x+ 4 = 0

x = -4

Therefore, the features of function gif g(x) = f(x + 4) + 8 is vertical asymptote of r = -4.

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The center is located at (2, −4), and the radius is 4.

To find the center and radius of this equation, we need to complete the square for both the x and y terms.

Starting with the x terms:

x^2 - 4x

To complete the square, we need to add and subtract (4/2)^2 = 4:

x^2 - 4x + 4 - 4

Now we can simplify:

(x - 2)^2 - 4

And for the y terms:

y^2 + 8y

We need to add and subtract (8/2)^2 = 16:

y^2 + 8y + 16 - 16

Simplifying:

(y + 4)^2 - 16

Now we can rewrite the original equation:

(x - 2)^2 - 4 + (y + 4)^2 - 16 = -4

Combining like terms:

(x - 2)^2 + (y + 4)^2 = 4

This is in the form of a circle:

(x - h)^2 + (y - k)^2 = r^2

Where the center is (h, k) and the radius is r.

So the center is located at (2, -4) and the radius is 4.

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The tomatoes start to get mushy after more than 6 days.

Note: The calculation assumes that the number of tomatoes harvested is large enough for the continuous division process to approach zero.

Let's assume that Marcos initially harvested X cherry tomatoes.

According to the given information, each day Marcos keeps one-third of the tomatoes and brings the remaining amount into the office. This means that after the first day, Marcos would have 2/3 (or 2/3X) of the original harvest left.

On the second day, he would keep one-third of the remaining tomatoes and bring 2/3 × 1/3 (or 2/9) of the original harvest into the office. This would leave him with 2/3 × 2/3 (or 4/9) of the original harvest.

In general, after N days, the amount of tomatoes left can be calculated using the following formula:

Amount of tomatoes left = (2/3)^N × X

The question states that Marcos has less than one eighty-first of the original harvest left when the tomatoes start to get mushy. In other words, when the amount of tomatoes left is less than 1/81 of the original harvest, we can write the following inequality:

[tex](2/3)^N × X < 1/81[/tex]

To find the number of days (N) when the tomatoes start to get mushy, we need to solve for N in the inequality above.

Taking the logarithm (base 2/3) of both sides of the inequality:

[tex]N > log2/3(1/81) / log2/3(2/3)[/tex]

N > 4 / (2/3)

N > 4 × 3/2

N > 12/2

N > 6

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The measure of the angle ∠S, obtained using the law of cosines is about 59.4°

The law of cosines states that the square of the length of a side of a triangle is equivalent to the sum of the squares of the other two sides less the product of the length of the other two sides and the angle between them. Mathematically; a² = b² + c² - 2·b·c·cos(A)

Where;

a, b, and c = The length of the sides of the triangle

A = The angle between b and c

The lengths of the sides of the triangle, obtained from a similar triangle are;

s = 50 inches, t = 58 inches, and u = 27 inches

The measure of the angle ∠S is required

The angle ∠S is the angle facing TU or the side s

According to law of cosines, we get;

s² = t² + u² - 2·t·u·cos(∠S)

Therefore;

50² = 58² + 27² - 2 × 58 × 27 × cos(∠S)

2 × 58 × 27 × cos(∠S) = 58² + 27² - 50²

cos(∠S) = (58² + 27² - 50²)/(2 × 58 × 27)

∠S = cos((58² + 27² - 50²)/(2 × 58 × 27)) ≈ 59.4°

The measure of the angle ∠S is about 59.4°

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The probability of choosing a ball numbered 25 is 0.

The lottery game contains only 24 balls numbered from 1 to 24. There is no ball numbered 25, so the probability of choosing a ball numbered 25 is 0. The probability of an event is defined as the ratio of the number of favorable outcomes to the total number of possible outcomes.

In this case, the number of favorable outcomes is 0 because there is no ball numbered 25, and the total number of possible outcomes is 24 since there are 24 balls in the game. Therefore, the probability of choosing a ball numbered 25 is 0/24, which simplifies to 0.

Mathematically, the probability of choosing a ball numbered 25 can be calculated as:

P(choosing ball numbered 25) = number of favorable outcomes / total number of possible outcomes

= 0 / 24

= 0

Therefore, the probability of choosing a ball numbered 25 is 0.

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Answer:

D. Lines A and D are perpendicular.

DAnswer:

Step-by-step explanation:

We would expect 9 pumpkin cupcakes to be sold in the next 21 cupcakes. The probability of a chocolate cupcake being sold is approximately 14%.

The question asks to determine how many of the next 21 cupcakes sold would be expected to be pumpkin cupcakes, and also to find the probability of a chocolate cupcake being sold.

First, let's analyze the given data:
- Chocolate cupcakes: 2
- Pistachio cupcakes: 1
- Banana cupcakes: 5
- Pumpkin cupcakes: 6

Total cupcakes sold: 2 + 1 + 5 + 6 = 14

To find the expected number of pumpkin cupcakes in the next 21 sold, calculate the proportion of pumpkin cupcakes in the original data, and then multiply by 21:

(6 pumpkin cupcakes / 14 total cupcakes) * 21 = 9 (rounded)

So, we would expect 9 pumpkin cupcakes to be sold in the next 21 cupcakes (Answer A).

For Part B, we need to find the probability of a chocolate cupcake being sold. To do this, divide the number of chocolate cupcakes by the total number of cupcakes:

Probability (chocolate cupcakes) = (2 chocolate cupcakes / 14 total cupcakes) = 0.142857

Now, convert this probability to a percentage and round to the nearest whole number:

0.142857 * 100 = 14.29% ≈ 14%

So, the probability of a chocolate cupcake being sold is approximately 14%.

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The expression to represent the situation is 2.85g + 3.15c.

Joe bought g gallons of gasoline for $2.85 per gallon and c cans of oil for $3.15 per can.

An algebraic expression is made up of variables and constants, along with algebraic operations such as addition, subtraction, division, multiplication etc.

Therefore, the expression that can be used to determine the total amount Joe spent on gasoline and oil can be calculated as follows:

Therefore,

total cost = 2.85g + 3.15c

where

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The coordinates of point D would be (0,y) where y is the vertical distance between points A and D.

Without knowing the exact location of point A and the dimensions of the rectangle, it is impossible to determine the coordinates of points B and D with certainty.

However, if we assume that point A is located at (0,0), and the length and width of the rectangle are given by the horizontal and vertical distances between points A and B, and between points A and D, respectively, we can find the coordinates of points B and D.

For example, if the length of the rectangle is 5 and the width is 3, then point B would be located at (5,0) and point D would be located at (0,3).

In general, the coordinates of point B would be (x,0) where x is the horizontal distance between points A and B, and the coordinates of point D would be (0,y) where y is the vertical distance between points A and D.

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The expression 0.85(1.4s) explains what happened to the price of the jacket through the two changes made by the store owner.

So, the expression 0.85(1.4s) explains what happened to the price of the jacket through the two changes made by the store owner.

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According to the information, and example of a counterexample is: A line can cross the circle only at one point.

To find a counterexample to this statement we must read it carefully and identify the main idea of it. In this case you are stating that a line always crosses a circle at two points.

Later we must analyze this statement and evaluate if it is true or false. In this case it is false because we can make a line that crosses a circle only once. So, the counter example sentence would be.

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The length of the legs are 20 cm and 21 cm

The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.

We know that from the Pythagoras theorem;

[tex]c^2 = a^2 + b^2[/tex]

Let the hypotenuse be c and the other two sides be a and b

We have that;

[tex]29^2 = x^2 + (x -1)^2\\841 = x^2 + x^2 - 2x + 1\\841 = 2x^2 - 2x + 1\\2x^2 - 2x + 1 - 841 = 0\\2x^2 - 2x - 840 = 0\\x = -20 or 21[/tex]

Since length can not be negative, x = 21 cm

Thus the other leg is 20 cm

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The triple integral ∫∫∫ (x+8y)dV where E is bounded by the parabolic cylinder is 512,604.17.

The triple integral is ∫∫∫(x+8y)dV.

Curves from the question are:

y = 7x², z = 2x, y = 35x, z = 0

Then, 7x² = 35x

Divide by x on both side, we get

7x = 35

Divide by 7 on both side, we get

x = 5

And z = 2x or z = 0. So

2x = 0

x = 0

Now the limits are:

x = 0 to x = 5

y = 7x² to y = 35x

z = 0 to z = 2x

Now the integral is

∫∫∫(x+8y)dV = [tex]\int_{0}^{5}\int_{7x^{2}}^{35x}\int_{0}^{2x}(x+8y)dzdydx[/tex]

Now first integrate with  respect to z

∫∫∫(x+8y)dV = [tex]\int_{0}^{5}\int_{7x^{2}}^{35x}(x+8y)[z]_{0}^{2x}dydx[/tex]

∫∫∫(x+8y)dV = [tex]\int_{0}^{5}\int_{7x^{2}}^{35x}(x+8y)[2x-0]dydx[/tex]

∫∫∫(x+8y)dV = [tex]\int_{0}^{5}\int_{7x^{2}}^{35x}(2x^2+16xy)dydx[/tex]

Now integrate with respect to y

∫∫∫(x+8y)dV = [tex]\int_{0}^{5}\left[2x^2(y)_{7x^{2}}^{35x}+16x(\frac{y^2}{2})_{7x^{2}}^{35x}\right]dx[/tex]

∫∫∫(x+8y)dV = [tex]\int_{0}^{5}\left[2x^2(35x - 7x^2)+16x(\frac{1225x^2}{2}-\frac{49x^4}{2})\right]dx[/tex]

∫∫∫(x+8y)dV = [tex]\int_{0}^{5}\left[2x^2(35x - 7x^2)+8x(1225x^2-49x^4)\right]dx[/tex]

∫∫∫(x+8y)dV = [tex]\int_{0}^{5}\left[70x^3 - 14x^4+9800x^3-392x^5\right]dx[/tex]

∫∫∫(x+8y)dV = [tex]\left[\frac{70x^4}{4} - \frac{14x^5}{5}+\frac{9800x^4}{4}-\frac{392x^6}{6}\right]_{0}^{5}[/tex]

∫∫∫(x+8y)dV = [tex]\left[\frac{70(5)^4}{4} - \frac{14(5)^5}{5}+\frac{9800(5)^4}{4}-\frac{392(5)^6}{6}\right]-\left[\frac{70(0)^4}{4} - \frac{14(0)^5}{5}+\frac{9800(5)^4}{4}-\frac{392(5)^6}{6}\right][/tex]

∫∫∫(x+8y)dV = [10937.5 - 8750 + 1531250 - 1020833.33]-0

∫∫∫(x+8y)dV = 512,604.17

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The complete question is:

Evaluate the triple integral ∫∫∫(x+8y)dV where E is bounded by the parabolic cylinder.

y = 7x² and the planes

z = 2x, y = 35x, and

z = 0

The only option that represents the universal set from the subsets is:

B: A set of cricket players of the school.

The universal set is defined as a set that is said to consist of all the elements or objects, which includes its own elements. This universal set is represented by just a symbol 'U'

Now, a subset is also defined as a part of the universal set which is basically a group under the universal set.

Now, from the given options, the only one that could possible represent a universal set of all the options given is "a set of cricket players of the school."

Therefore we conclude that Option B provides the correct answer to the universal set definition.

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The completed matrix represents the system of equations in a convenient format for solving using matrix operations.

The given system of equations has been represented in a matrix form, where the coefficients of the variables x and y and the constant terms are arranged in a matrix. To solve the system of equations, we can use matrix operations to isolate the variables and find their values. The completed matrix shows that the coefficient of x is 700, the coefficient of y is -200, and the constant term is 0 for the first equation. Similarly, the coefficient of x is -75, the coefficient of y is 200, and the constant term is 5000 for the second equation.

To solve this system using matrix operations, we can perform row operations to eliminate one of the variables. For example, we can multiply the first row by 75 and the second row by 200, and then add the two rows to eliminate x. This gives us a new system of equations with only one variable, which we can solve to find the values of x and y.

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