Answer question in the photo

The energy used by the 200 W lamp for 24 hours is 17280000 J whereas, the energy used by the 55 W lamp for one day is 4752000. Therefore, by replacing the200 W lamp by 55 W, we save 12,528,000 J of energy.

Power is the unit of energy or work done by an object. It measures how much energy used by the object per second to do a work. Hence, power is the work done or energy by time in seconds.

Given that power of one lamp = 200 W

time = 24 hour= 86400 s.

then energy = power × time

  200 W × 86400 s = 17280000 J

Similarly the energy consumed by the 55 W lamp for 24 hours is:

86400 s × 55 W = 4752000J

Then, if replace the 200 W lamp by the 55 W LED lamp, we can save an energy of 17280000 J - 4752000 J = 12,528,000 J.

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If F = 37 N, the static frictional force between the block and the table and the minimum force required to move it must be equal.

It is the force that regulates itself. The value of static friction varies from zero to the smallest force required to initiate motion. The formula for determining static friction is as follows: Normal Force divided by the static friction coefficient is static friction.

Although the maximum static friction will rise, the frictional force will always be the same as the weight in mg because friction cannot accelerate an object. Because FrN can take any value less than N to balance the weight, this is the case.

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Acidity is indicated by pH values lower than 7, while baseness is shown by pH values higher than 7. The pH of water is actually a measurement of the proportion of free ions of hydrogen and hydroxyl that are in the solution.

The souls were shown by him. He pointed to the nicely arranged clothing on the nightstand next to the bed. They still lacked one goat, according to a hasty count.

The monitored value from the a transaction file that the monitor reported for a known amount of the specified Parameter. Precision is determined by comparing this value to the known quantity known as REAL VALUE.

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Answer:

Approximately [tex]7.2\; {\rm m\cdot s^{-1}}[/tex] (rounded up), assuming that this circle is vertical and [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].

Explanation:

Let [tex]v[/tex] denote the tangential speed of the ball, and let [tex]r[/tex] denote the radius of the circle. Since the ball is in a circular motion, the acceleration on this ball would be equal to the centripetal acceleration [tex]a = (v^{2} / r)[/tex]. The net force on this ball would be [tex]F_{\text{net}} = m\, a = (m\, v^{2} / r)[/tex].

The net force on this ball is also the vector sum of the tension [tex]T[/tex] in the rope and the weight of the ball [tex]m\, g[/tex]:

[tex]F_{\text{net}} = (\text{weight}) + T[/tex].

[tex]T = F_{\text{net}} - (\text{weight})[/tex].

Note that:

[tex]\| T \| = \|F_{\text{net}} - (\text{weight})\| \le \|F_{\text{net}} \| + \| (\text{weight})\|[/tex].

In other words, the magnitude of tension [tex]T[/tex] is at most equal to [tex]\|F_{\text{net}} \| + \| (\text{weight})\| = (m\, v^{2} / r) + (m\, g)[/tex], which happens when weight and net force are in opposite directions.

When the speed of the ball is maximized, the magnitude of tension [tex]T[/tex] would be at the largest possible value of [tex]130\; {\rm N}[/tex]. Rearrange the equation and solve for speed [tex]v[/tex]:

[tex]\displaystyle \frac{m\, v^{2}}{r} + m\, g = \|T\|[/tex].

[tex]\begin{aligned}v^{2} = \frac{r}{m}\, (\|T \| - m\, g) = \frac{r\, \|T\|}{m} - r\, g\end{aligned}[/tex].

[tex]\begin{aligned}v &= \sqrt{\frac{r\, \|T\|}{m} - r\, g} \\ &= \sqrt{\frac{(1.2)\, (130)}{2.5} - (1.2)\, (9.81)}\; {\rm m\cdot s^{-1}} \\ &\approx 7.2\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

Answer:

velocity, power, energy, force and density

Explanation:

The event horizon is directly related to the mass of the black hole, with larger black holes having larger event horizons.

What is Black Hole?

A black hole is an astronomical object that has collapsed to such a small size that its gravitational pull is so strong that nothing, not even light, can escape it. Black holes are formed from the remnants of massive stars that have run out of fuel and undergone a catastrophic collapse, or from the merging of two or more smaller black holes.

M87 and Ton 618 are both supermassive black holes, with masses estimated to be around 6.5 billion and 66 billion times the mass of the Sun, respectively. However, the size of their event horizons would depend not only on their mass but also on their spin and the density of the surrounding matter. It is therefore not possible to predict which black hole would be bigger without additional data and calculations.

It is worth noting that the first image of a black hole that was released in 2019 was actually an image of the event horizon of the black hole in M87, not the black hole itself. The event horizon of M87's black hole was estimated to be around 40 billion km in diameter, which is larger than the entire solar system.

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The change in gravitational potential energy of the dog is -176.58 J.

The change in gravitational potential energy of an object is given by:

ΔPE = mgh

where

ΔPE is the change in gravitational potential energy

m is the mass of the object

g is the acceleration due to gravity, and

h is the change in height.

In this case, the dog jumps off a 10 m staircase down to his doggy house which is 4 m high. So the change in height,

h = -6 m (negative because the dog is moving downwards).

g = 9.81 m/s^2

m = 3 kg.

Substituting these values into the equation above, we get:

ΔPE = mgh

ΔPE = (3 kg)(9.81 m/s^2)(-6 m)

ΔPE = -176.58 J

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TO be completely Honest with this, Based of reading the questions and answers it may be D. just off sheer legibility of logic alone, Hope this is not wrong.

Answer: 0.002

Explanation:

The magnitude of the bicycle's centripetal acceleration can be calculated using the formula:

a = v^2 / r

where v is the tangential speed and r is the radius of the circular path. Plugging in the given values, we get:

a = (2.7 m/s)^2 / 3.2 m

a = 2.27 m/s^2

The magnitude of the centripetal force on the bicycle can be calculated using the formula:

F = m * a

where m is the combined mass of the bicycle and the child. Plugging in the given values, we get:

F = 54 kg * 2.27 m/s^2

F = 122.58 N

Therefore, the magnitude of the bicycle's centripetal acceleration is 2.27 m/s^2, and the magnitude of the centripetal force on the bicycle is 122.58 N.

Answer:

[tex]\huge\boxed{\sf F_c=123.02 \ N}[/tex]

[tex]\huge\boxed{\sf a_c=2.28 \ m/s^2}[/tex]

Explanation:

Mass = m = 54 kg

Tangential speed = v = 2.7 m/s

Radius = r = 3.2 m

Centripetal force = [tex]F_c[/tex] = ?

Centripetal acceleration = [tex]a_c[/tex] = ?

[tex]\displaystyle F_c=\frac{mv^2}{r}[/tex]

[tex]\displaystyle a_c=\frac{v^2}{r}[/tex]

Put the given data in the above formula.

[tex]\displaystyle a_c=\frac{(2.7)^2}{3.2} \\\\a_c=\frac{7.29}{3.2} \\\\a_c=2.28 \ m/s^2\\\\[/tex]

Put the given data in the above formula.

[tex]\displaystyle F_c=\frac{(54)(2.7)^2}{3.2} \\\\F_c=\frac{(54)(7.29)}{3.2} \\\\F_c=\frac{393.66}{3.2} \\\\F_c=123.02 \ N\\\\\rule[225]{225}{2}[/tex]

The displacement from the midpoint of the motion at which the speed is equal to half of the maximum speed is 1.85 cm.

v = Aω√(1 - (x/A)^2)

v_max = Aω

v = 1/2 v_max = 1/2 Aω

Substituting the given values, we get:

1/2 Aω = 3.08 cm * ω * √(1 - (x/A)^2)

Simplifying and squaring both sides, we get:

(1/4) A^2 ω^2 = 9.4864 cm^2 * (1 - (x/A)^2)

Solving for x/A, we get:

x/A = √(1 - (1/4)(ω^2/A^2) * 9.4864)

x/A = √(1 - (π^2/400))

x/A = 0.6

The displacement from the midpoint of the motion at which the speed is equal to half of the maximum speed is:

x = 0.6 * 3.08 cm = 1.85 cm

Harmonic motion is a type of periodic motion in which an object oscillates back and forth around an equilibrium position with a constant frequency and amplitude. It is characterized by a sinusoidal pattern, where the displacement of the object from its equilibrium position is directly proportional to the sine or cosine of the time elapsed since the motion began.

In harmonic motion, the restoring force acting on the object is proportional to its displacement from the equilibrium position, and the object's motion is governed by Hooke's Law. Examples of harmonic motion include the motion of a mass-spring system, the motion of a simple pendulum, and the vibration of a guitar string.

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Since Hooke's law implies linear, i anticipate that the length of a spring will double if the weight hanging on this is doubled. The graph below depicts a spring's ideal Hooke's law graph.

At the range of the material's elastic limit, according to Hooke's law, the strain is inversely related to the applied stress. The molecules and atoms in elastic materials stretch when they are stretched, distort when under stress, and then return to their original shape once the tension is released.

In the year 1660, an English british scientist Robert Hooke discovered Hooke's law, commonly known as that of the law of elasticity. According to Hooke's law,  the magnitude of the deformation is precisely proportional to a deforming load or force.

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Answer:

Option D is the most likely answer: element 119 will only remain stable for an extremely small fraction of a second.

This is because all elements with atomic numbers greater than 92 (i.e., the actinides) are unstable and undergo radioactive decay, with their isotopes having extremely short half-lives. As element 119 would have an atomic number greater than 92, it is highly likely that it too would be unstable and undergo radioactive decay, making it difficult to observe and study.

Option A is not possible, as all elements require neutrons in their nuclei to have stable isotopes. Option B is unlikely, as the properties of element 119 are unknown and it would need to be studied extensively before any industrial applications could be developed. Option C is also unlikely, as elements with large atomic numbers tend to have larger nuclei. Option E is also unlikely, as it is not clear how element 119 could be produced in the Sun, given that it is a highly unstable element.

To calculate the number of photons produced by the carbon dioxide laser, we need to use the formula relating the energy of a photon to its frequency or wavelength.

The formula is: E = hf = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 × 10^-34 J s), f is the frequency, c is the speed of light (3 × 10^8 m/s), and λ is the wavelength. First, we need to calculate the energy of one photon with a wavelength of 10.6 μm: E = hc/λ = (6.626 × 10^-34 J s) × (3 × 10^8 m/s) / (10.6 × 10^-6 m) = 1.862 × 10^-20 J. Next, we need to calculate the total energy produced by the laser in 1.00 ms: Energy = Power × Time = 9.50 MW × 1.00 × 10^-3 s = 9.50 × 10^3 J. Finally, we can calculate the number of photons produced by dividing the total energy by the energy of one photon: Number of photons = Energy / E = (9.50 × 10^3 J) / (1.862 × 10^-20 J) = 5.098 × 10^23 photons. Therefore, the carbon dioxide laser produced 5.098 × 10^23 photons when it emitted infrared radiation with a wavelength of 10.6 μm and a power of 9.50 MW for 1.00 ms.

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10 is the appropriate number. Here, a machine's mechanical advantage. Hence, choice (a) is the appropriate response. Three mechanical advantages exist: force, distance, and speed.

Although though force mechanical advantage is the sole topic covered in the majority of scientific publications, it is nevertheless crucial.

using the mechanical advantage formula.

[tex]MA= \frac{Fo}{Fi}[/tex]

alternative ≠ 480[tex]N[/tex] and [tex]Fi = 50n,[/tex]

[tex]MA = \frac{480n}{50n}[/tex]

simplify  [tex]MA[/tex]  ≈  10

The load to effort ratio is used to quantify mechanical advantage of a machine. A machine's mechanical advantage determines its efficiency. Mechanical Advantage is equal to Load / Effort, or F 0 F I which means that is the mechanical energy, is the production force, and corresponds to the input force.

An object having mass changes its velocity in response to a push or pull. Force is an exterior agent that has the power to alter the rest or motion of something like a body. It has magnitude and direction.

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Answer: D. Increase the density of the substance and there will be more particles to transfer the wave.

Answer:

D. INCREASE THE DENSITY OF THE SUBSTANCE AND THERE WILL BE MORE PARTICLES TO TRANSFER THE WAVE .

Explanation:

BECAUSE WAVES ARE TRANSFERED

Answer:

u

1

=

6.0

m

/

s

u

2

=

4.0

m

/

s

v

1

=

5.0

m

/

s

Explanation:

A. The two new animal populations adapt gradually and separately to their new environments on either side of the mountain. This options explains how does the creation of a new mountain range in an ecosystem affect an animal population.

Explain the role of mountain range in an ecosystem?

When a new mountain range is created, it can act as a barrier that separates animal populations on either side. Over time, the two populations will adapt to their new environments, which may be different due to differences in climate, vegetation, or other factors.

As a result, the two populations may evolve independently of each other, leading to differences in behavior, appearance, and genetic makeup. This process is known as allopatric speciation. It is important to note that while the two populations may become distinct, they may still be able to interbreed if they come into contact again in the future.

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El signo negativo indica que el campo eléctrico apunta en la dirección opuesta a la fuerza experimentada por la carga. Por lo tanto, el campo eléctrico en ese punto es de -4 N/C.

F = qE

En este caso, la carga es de -5x10^-9 C y la fuerza es de 20x10^-9 N. Por lo tanto, podemos despejar el valor del campo eléctrico:

E = F/q = (20x10^-9 N) / (-5x10^-9 C) = -4 N/C

A charge is a fundamental property of matter that describes the amount of electric energy that a particle possesses. It is a scalar quantity, meaning it has only magnitude and no direction. The charge can be either positive or negative and is measured in Coulombs (C).

Charged particles can interact with each other through electromagnetic force, which is one of the four fundamental forces of nature. Like charges repel each other while opposite charges attract. Electric fields are generated by charged particles, and the force they exert on other charged particles is proportional to the magnitude of their charges.

A charge is conserved in isolated systems, meaning that the total amount of charge in a closed system cannot be created or destroyed, but can only be transferred from one object to another.

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The Guide provides estimated fuel economy (in miles per gallon, or MPG) and annual fuel costs (based on national averages of fuel costs and miles driven) for most model year 2022 vehicles for sale in the United States.

The simplest approach to determine your gas mileage is to divide the number of miles traveled by the number of gallons of petrol consumed by your car. In total, it is the number of miles travelled divided by the number of gallons of gas consumed.

Fuel economy is a rating that indicates how far a vehicle can go on a given quantity of gasoline. The higher the fuel efficiency, the less gasoline the vehicle consumes. The conventional metric of fuel efficiency in the United States is miles per gallon (mpg). This metric relates to how far a vehicle can go on a single gallon of fuel.

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Answer:

W = m g h      increase in PE due to lfting bag

W1 = 90 kg * 9.8 m/s^2 * 6 m

W2 = 45 kg * 9.8 m/s^2 * 12 m

W2 / W1 = 1        the work is the same in both cases

The power required is different

P = W / t

Since t is smaller for W2 and the work output is the same the power required to produce W2 is twice as great

The mass of the object is 2,500 kg according to Newton's second law of motion.

Newton's second law of motion states that the force acting on an object is equal to the product of its mass and acceleration. Mathematically, F = ma, where F is the force, m is the mass of the object, and a is its acceleration.

If a force of 25,000 N is applied to an object, and the object is accelerating at a rate of [tex]10 m/s^2,[/tex]  then the mass of the object can be calculated using Newton's second law of motion:

F = ma

where F is the force, m is the mass of the object, and a is its acceleration.

Rearranging this equation, we get:

m = F/a

Plugging in the values given in the problem, we get:

[tex]m = 25,000 N / 10 m/s^2 = 2,500 kg[/tex]

Therefore, the mass of the object is 2,500 kg

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Shawna's hockey coach is committed to helping her players succeed in their upcoming game against their biggest rival.

Mass is a fundamental physical property of every object that exists in the universe. It is the measure of an object's inertia and resistance to acceleration. Mass is measured in kilograms or pounds, and is commonly used to measure the weight of an object. Mass is an intrinsic property of an object that does not depend on its location or the gravitational field in which it is situated. Mass is related to the amount of matter, or material, an object contains, and it is not affected by gravity. Mass is an invariant quantity, meaning it is unaffected by any external forces or conditions.

To this end, she emphasizes the importance of fundamental hockey skills and proper passing techniques. She encourages her players to make quick, accurate passes to teammates in order to create more scoring opportunities; the goal is to always have an open man. To achieve this, the coach instructs the players to pass the puck to a spot slightly ahead of their teammate, the teammate covered by two defenders, their teammate's back skate, or their teammate's front skate. By focusing on the basics and utilizing these strategies, the coach hopes to give her team the best chance of coming out on top.

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The two blocks have an acceleration of 4.12 m/s^2.

To solve this problem, we need to draw a free-body diagram of both blocks and apply the laws of motion.

Let's assume that the positive x-direction is to the right, and the positive y-direction is upwards.

For the 10 kg block:

The weight force (W) acts downwards and has a magnitude of 10 x 9.8 = 98 N

The force of tension (T) acts upwards and is transmitted through the string from the 5 kg block

The frictional force (f) acts in the opposite direction to the motion and has a magnitude of 20 N

The force applied (F) acts at an angle of 30 degrees with the horizontal

We can resolve the applied force into its x- and y-components:

The x-component of the force (F cos 30) opposes the frictional force

The y-component of the force (F sin 30) opposes the weight force and is balanced by the tension force

Therefore, we can write the following equations of motion for the 10 kg block:

ΣFx = [tex]\sqrt{x}[/tex]T - F cos 30 - f = ma

ΣFy = T - W - F sin 30 = 0

For the 5 kg block:

The weight force (W) acts downwards and has a magnitude of 5 x 9.8 = 49 N

The force of tension (T) acts upwards and is transmitted through the string to the 10 kg block

The frictional force (f) acts in the opposite direction to the motion and has a magnitude of μkN, where μk is the coefficient of kinetic friction and N is the normal force

We can write the following equation of motion for the 5 kg block:

ΣFx =Δ f - T = ma

Now, we can solve for the unknowns.

From the equation ΣFy = T - W - F sin 30 = 0, we get:

T = W + F sin 30

T = 10 x 9.8 + 50 sin 30

T = 109.8 N

From the equation ΣFx = T - F cos 30 - f = ma, we get:

a = (T - F cos 30 - f) / m

a = (109.8 - 50 cos 30 - 20) / 10

a = 2.33 m/s^2

From the equation ΣFx = f - T = ma, we get:

a = √(f - T) / m

a = (0.2 x N - 109.8) / 5

a = -4.96 m/s^2

Since the acceleration of the two blocks is the same (due to the inextensible string), we can equate the two values of acceleration and solve for N:

2.33 = -4.96

N = 73.8 N

Now we can calculate the frictional force on the 5 kg block:

f = √μkN

f = 0.2 x 73.8

f = 14.76 N

Finally, we can use the equation ΣFx = T - F cos 30 - f = ma to find the acceleration:

a = (T - F cos 30 - f) / m

a = (109.8 - 50 cos 30 - 14.76) / 10

a = 4.12 m/s^2

Therefore, the two blocks accelerate to the right with an acceleration of 4.12 m/s^2.

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If at a given moment, the swimmer in a 100m backstroke swimming race then,

a) The distance traveled if she has just started is 0 meter.

b) The distance traveled if she has just started is 100 meters.

c) The displacement is 0 m in case a and 100 m is case b. No they do not coincide.

Since the swimmer has just started, therefore she has not traveled any distance yet.

As it is mentioned that the swimmer has already touched the end of the pool, she has traveled a distance of 100 meters.

The displacement of the swimmer in cases a and b is zero because displacement is the distance between the starting point and the ending point, regardless of the path taken. In case a, the swimmer has not moved from the starting point yet, so the displacement is zero. In case b, the swimmer has returned to the starting point, so the displacement is also zero.

No, the displacement does not coincide with the distance traveled in either case because the swimmer's path is not necessarily a straight line from the starting point to the ending point. The displacement only considers the initial and final positions of the swimmer, while the distance traveled takes into account the length of the path taken by the swimmer.

Therefore, it could be concluded that at the start diatance is 0m and at the end it is 100m and the displacement at starting is 0m and at the end it is 100m. These do not coincide with each other.

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The question is :

At a given moment, the swimmer in a 100m backstroke swimming race is below the false start rope. State :

a) The distance traveled if she has just started

b) The distance traveled if she has already touched the end of the pool

c) The displacement of the swimmer in cases a and b. Does it coincide with the distance traveled in any case?

The roller coaster car contains a total of 19810 joules of energy at this point.

First, we need to consider its kinetic energy and potential energy.

The potential energy of the car at a height of 5 m above Earth's surface is given by:

PE = m * g * h

Where

Substituting the given values, we get:

PE = (200 kg) * (9.81 m/s²) * (5 m)

PE = 9810 J

The kinetic energy of the car is given by:

KE = (1/2) * m * v²

Where v is the velocity of the car.

Substituting the given values, we get:

KE = (1/2) * (200 kg) * (10 m/s)²

KE = 10000 J

Therefore, the total energy of the roller coaster car at this point is:

Total Energy = KE + PE

Total Energy = 10000 J + 9810 J

Total Energy = 19810 J

Therefore, the roller coaster car contains a total of 19810 joules of energy at this point.

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Answer:

C

Explanation: