Answer please????????????????????????

Answer:

Step-by-step explanation:

The null hypothesis and alternative hypothesis can be formulated as:

[tex]\mathbf{H_o: P_1 - P_2 \le 0}[/tex]

[tex]\mathbf{H_1 : P_1 -P_2> 0}[/tex]

From the information given:

The sample proportion of rooms occupied for the current year.

[tex]P_1 = \dfrac{1470}{1750}[/tex]

[tex]P_1 = 0.84[/tex]

Sample size [tex]n_1[/tex] = 1750 (total number of rooms for the current year)

The sample proportion of rooms occupied for the previous year.

[tex]P_2 = \dfrac{1440}{1800}[/tex]

[tex]P_2 =0.8[/tex]

Sample size [tex]n_2[/tex] = 1800 (total number of rooms for the previous year)

Thus, the estimated proportion of the hotel rooms occupied each year are:

Current     Previous

0.84            0.80

Since this is a one-sided right-tailed test;

The pooled proportion can  be computed as:

[tex]\hat p= \dfrac{p_1 \times n_1 + p_2 \times n_2}{n_1 + n_2}[/tex]

[tex]\hat p= \dfrac{0.84 \times 1750 + 0.80 \times1800}{1750 +1800}[/tex]

[tex]\hat p=0.8197[/tex]

The standard error SE = [tex]\sqrt{\hat p ( 1- \hat p) ( \dfrac{1}{n_1} + \dfrac{1}{n_2} )}[/tex]

[tex]= \sqrt{0.8197 ( 1-0.8197) ( \dfrac{1}{1750} + \dfrac{1}{1800} )}[/tex]

[tex]= \sqrt{0.8197 ( 0.1803) (0.00112698 )}[/tex]

[tex]=0.0129[/tex]

Finally, the test statistics is calculated as:

[tex]Z_{calc} = \dfrac{(0.84 - 0.8)}{0.0129}[/tex]

[tex]Z_{calc} = 3.101[/tex]

Answer:

6h +210

Step-by-step explanation:

6 x h = 6h

3.5 x 6 = 210

Answer:

he is the answer

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

5.50 + 1.50x = 19

x = 9

Ava can ride 9 rides.

Step-by-step explanation:

5.50 + 1.50x = 19

-5.50                -5.50

1.50x = 13.50   (divide both sides by 1.50)

x = 9

Answer:

Uhm would it be 4 c?

Step-by-step explanation:

Answer:

4 degree c

Step-by-step explanation:

15-11=4

Answer:

8xy

Step-by-step explanation:

Subtract -13xy from -5xy

-5xy - (-13xy) =

-5xy + 13xy =

8xy

good luck, i hope this helps:)

Answer:

[tex]\frac{-27}{40}[/tex]

Step-by-step explanation:

[tex](\frac{-3}{8})[/tex]÷[tex]\frac{5}{9}[/tex]

[tex]\frac{-3}{8}[/tex]×[tex]\frac{9}{5}[/tex]

[tex]\frac{-27}{40}[/tex]

Answer:

Well the answer to the first half of the question is 9.6 so.. 13 would be greater than that.   :/

Step-by-step explanation:

Answer:

48/5 <= 13 is always true there are infinitely many solutions

Answer:

x = 1

y = 7

Step-by-step explanation:

Two equations, two unknowns. We know that y = 7x so we can substitute that into the first equation to get:

[tex]-5+2\left(7x\right)=9[/tex]

[tex]-5+14x=9[/tex]

[tex]14x=14[/tex]

This gives us x = 1.

Now plug this bag into either equation to find y, I will use the second since it's easier:

y = 7(1) = 7

Answer:

2(x+y+11)

Step-by-step explanation:

2(x+5)+3y+12−y

Use the distributive property to multiply 2 by x+5.

2x+10+3y+12−y

Add 10 and 12 to get 22.

2x+22+3y−y

Combine 3y and −y to get 2y.

2x+22+2y

Answer:

2x+22 +2y

Step-by-step explanation:

Answer:

B.

Step-by-step explanation:

Answer:

The answer is 95°!

Step-by-step explanation:

180°-60°-25°= 95°

Answer:

0.2027 = 20.27% probability that a non-defective product came from the second machine

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Non-defective product.

Event B: From the second machine.

Probability of a non-defective product:

100-13 = 87% of 30%(first machine)

100-9 = 91% of 20%(second machine)

100-9 = 91% of 50%(third machine).

So

[tex]P(A) = 0.87*0.3 + 0.91*0.2 + 0.91*0.5 = 0.898[/tex]

Non-defective and from the second machine:

91% of 20%. So

[tex]P(A \cap B) = 0.91*0.2 = 0.182[/tex]

What is the probability that a non-defective product came from the second machine

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.182}{0.898} = 0.2027[/tex]

0.2027 = 20.27% probability that a non-defective product came from the second machine

Answer:

(0,-2) (3,-4) (6,-6)

Step-by-step explanation:

I think you start at (0,-2) then go over 3 to the right and down 2 since it's negative each time

Answer:

89n

Step-by-step explanation:)

Answer:

33289

Step-by-step explanation:

July reading + Useage

= 32347 + 942 = 33289

Answer:

b.

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

Because 10 1/3 divided by 1 2/5 would be 7 and something and the question is asking how many full pieces, so just 7

Answer:

Step-by-step explanation:

Given that:

For PCC

The sample size [tex]n_1[/tex] = 25

sample mean [tex]\overline x_1[/tex] = 75

standard deviation [tex]s_1[/tex] = 17.50

For ELAC

The sample size [tex]n_2[/tex] = 20

Sample mean [tex]\overline x_2 = 89[/tex]

Standard deviation [tex]s_2[/tex] = 14.40

Significance level = 0.05

The null hypothesis:

[tex]H_o : \mu_1 =\mu_2[/tex]

The alternative hypothesis;

[tex]H_1 : \mu_1< \mu_2[/tex]

Since the population standard deviation are synonymous pooled standard deviation; Then:

[tex]sp = \sqrt {\dfrac {(n_1-1)s_1^2)+(n_2-1)s_2^2 }{n_1+n_2-2}[/tex]

[tex]sp = \sqrt {\dfrac {(25-1)17.50^2)+(20-1)14.40^2 }{25+20-2}[/tex]

[tex]sp = 16.20[/tex]

The test statistics can be computed as:

[tex]t = \dfrac{\overline x_1 -\overline x_2}{sp \times \sqrt{\dfrac{1}{n_1} + \dfrac{1}{n_2} }}[/tex]

[tex]t = \dfrac{75-89}{16.20 \times \sqrt{\dfrac{1}{25} + \dfrac{1}{20} }}[/tex]

[tex]t = -2.88[/tex]

The p-value [tex]= P(t_{n_1+n_2-1} <t)[/tex]

[tex]= P(t_{43} <-2.88)[/tex]

= 0.0031

Decision Rule: To reject the null hypothesis if the p-value is less than the significance level

Conclusion: There is sufficient evidence to conclude that the mean amount spent by all PCC students is less than the mean amount spent by all ELAC students.

Answer:

its too donk

Step-by-step explanation:

alright ill go open up the shades

Answer:

-4

Step-by-step explanation:

3(2x+8) = 0

Distribute

6x + 24 = 0

24 = -6x + 0

24/-6  = -4

Answer:

29

Step-by-step explanation:

PEMDAS

PARENTHESIS: [3-10]=7

EXPONENTS: 3^3= 27

MULTIPLICATION:8×7=56

DIVISION:NONE

ADDITION:NONE

SUBTRACTING: 56-27=29

ANSWER: 29

Answer:

0.3036 = 30.36% probability that at least 9 of the flashlights function properly.

Step-by-step explanation:

For each flashlight, there are only two possible outcomes. Either it works, or it does not. Flashlights are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Flashlight works correctly if both its batteries have acceptable voltages:

Each battery has an 88% = 0.88 probability of working correctly(having acceptable voltage), so the probability of the flashlight working correctly is given by:

[tex]p = (0.88)^2 = 0.7744[/tex]

10 flashlights.

This means that [tex]n = 10[/tex]

What is the probability that at least 9 of the flashlights function properly?

This is

[tex]P(X \geq 9) = P(X = 9) + P(X = 10)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 9) = C_{10,9}(0.7744)^{9}.(0.2256)^{1} = 0.2260[/tex]

[tex]P(X = 10) = C_{10,10}(0.7744)^{10}.(0.2256)^{0} = 0.0776[/tex]

[tex]P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2260 + 0.0776 = 0.3036[/tex]

0.3036 = 30.36% probability that at least 9 of the flashlights function properly.

Answer:

21.96 ; 24.72

Step-by-step explanation:

Given that :

Give the equation:

A(t) = 700(1.03)^t

A.)

Average rate of change over the first 4 years ;

(t=0 to t=4)

At t = 0

A(0) = 700(1.03)^0 = 700

A(1) = 700(1.03)^1 = 721

A(2) = 700(1.03)^2 = 742.63

A(3) = 700(1.03)^3 = 764. 9089

A(4) = 700(1.03)^4 = 787.856167

[(721 - 700) + (742.63 - 721) + (764.9089 - 742.63) + (787.856167 - 764.9089)] / 4

= 87.856167 / 4

= 21.96404175

= 21.96

Over the 2nd 4 years :

A(4) = 700(1.03)^4 = 787.856167

A(5) = 700(1.03)^5 = 811.49185201

A(6) = 700(1.03)^6 = 835.8366075703

A(7) = 700(1.03)^7 = 860.911705797409

A(8) = 700(1.03)^8 = 886.73905697133127

[(811.49185201 - 787.856167) + (835.8366075703 - 811.49185201) + (860.911705797409 - 835.8366075703) + (886.73905697133127 - 860.911705797409)] / 4

= 98.88288997133127 / 4

= 24.72

Answer:

[tex]Probability = 0.56[/tex]

Step-by-step explanation:

Represent the probability that Alice does well with P(A), the probability that Bob does well with P(B).

So, we have:

[tex]P(A) = 0.8[/tex]

[tex]P(B) = 0.4[/tex]

Required

Determine the probability that only one of them do well

This event is represented as: (A and B') or (B and A')

Where B' means Bob does not perform well and A' means Alice does not perform well.

And:

[tex]P(B') = 1 - P(B)[/tex]

[tex]P(A') = 1 - P(A)[/tex]

So, the probability becomes:

[tex]Probability = P(A\ and\ B')\ or\ P(B\ and\ A')[/tex]

[tex]Probability = P(A) * P(B')\ +\ P(B)*P(A')[/tex]

[tex]Probability = P(A) * (1-P(B)) +\ P(B)*(1-P(A))[/tex]

[tex]Probability = 0.8 * (1-0.4) +\ 0.4*(1-0.8)[/tex]

[tex]Probability = 0.8 * 0.6 +\ 0.4*0.2[/tex]

[tex]Probability = 0.48 + 0.08[/tex]

[tex]Probability = 0.56[/tex]

Hence, the required probability is 0.56

Answer:

124

Step-by-step explanation:

100 x .09=9

100 x ,15=15

9 + 15=24

100+24=124

Answer:

0.1634 = 16.34% probability the fatality resulted from a fall

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question, we have that:

1795 + 837 + 741 + 645 + 404 + 113 = 4535 total fatalities.

Of those, 741 from falls.

741/4535 = 0.1634

0.1634 = 16.34% probability the fatality resulted from a fall