Answer:
the doppler effect shows stars with red shifted light
Explanation:
light from a receding star is shifted toward red or redshifted
redshift is an example of the doppler effect
the wavelength of the light is stretched so the light is seen as shifted towards the red part of the spectrum
A sound wave is produced when a medium begins to
Answer:
when a medium begins to vibrate
Can anyone help me on this? It’s a water cycle.
Answer:
The water cycle shows the continuous movement of water within the Earth and atmosphere. It is a complex system that includes many different processes. Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow.
Explanation:
When ocean temperature rises,
a. excess gas is released into the atmosphere.
b. the ocean absorbs and holds carbon dioxide.
c. carbon dioxide is equalized between the ocean and atmosphere. d. no change takes place.
Answer:
see below
Explanation:
Kind of like when yo open a warm soda .....excess gas is released
An airplane of mass 270,000 kg that is sitting on a runway has its center of gravity located at 10.0 m in front of the main landing wheels as shown. Find the magnitude of the force exerted by the runway on the nose wheel located 25.0 m from the main landing wheels.
For an airplane of mass 270,000 kg , the magnitude of the force exerted is mathematically given as
N2=1584431.13N
N1=1061568.87N
What is the magnitude of the force exerted by the runway on the nose wheel located 25.0 m from the main landing wheels.?Generally, the equation for the Force balance is mathematically given as
N1+N2=270000*g
Therefore
N2*10=N1*15
N1=10N2/15
N1=0.67N2
Hence
0.67N2+N2=270000*g
N2=1584431.13N
N1=1061568.87N
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Please help quickly!!!
State the basic rules to draw a vector quantity
Explanation:
i dont to i want to copy and paste on my printer
A mass of 100kg is acted on by a 400N force acting vertically upward and a 600N force acting at a 45 degrees angle.Calculate the vertical component of the acceleration.The local acceleration of gravity is 9.8 m/s2. A.1.56 B.-1.56 C.-2.43 D.2.43 . E. 3.5
Answer:
A 1.56 see below
Explanation:
I will assume the 45 degree force is upward
vertical component = 600 sin 45 = 424.26 N
added to the other vertical force will total 824.26 N
F = ma
824.26 = 100 * a shows a = 8.24 m/s upward
Now we have to assume the mass is ALSO acted on by gravity and this value is given as 9.8 ( so downward is positive)
9.81 - 8.24 = 1.56 m/s^2
HELP!! ASAP I DONT KNOW HOW TO THIS
Which is an example of radiation?
Answer:
A burning candle emits radiation in the form of heat and light. The Sun emits radiation in the form of light, heat, and particles. Uranium-238 decaying into Thorium-234 emits radiation in the form ofalpha particles.
Answer:
the sun
Explanation:
the sun emits radiation
It the mass of the foot is 10kg and it is moving at 5m/s, what is the momentum of the leg?
A sample of ore containing radioactive strontium 38Sr90 has an activity of 8.2 × 105 Bq. The atomic mass of strontium is 89.908 u, and its half-life is 28.8 yr (1 yr = 3.156 × 107 s). How many grams of strontium are in the sample?
From the activity values and the decay constant, the mass of of Strontium in the sample is:
[tex]1.62 × 10^{-7}g[/tex]
What is the decay constant of an element?The decay constant of an element is the probability of decay of a nucleus per unit time.
{λ = ln 2 / t1/2
where;
t1/2 is the half-life of the isotope.
The half-life is converted to seconds since the decay constant is asked in per seconds.
[tex]28.8 years = 28.8 × 3.156 × 10^{7} = 908928000 s \\ [/tex]
Hence;
[tex]λ = \frac{ln2}{90892800s} = 7.626 s^{-1}[/tex]
The activity of the element, A, the decay constant, λ and the number of nuclei, N are related as follows:
A = (–) λN[tex]N = \frac{8.25 ×10^{5}}{7.626×10^{-10}} = 1.082 × 10^{15} [/tex]
Molar mass of Strontium-90 is 90 g.
1 mole of Strontium-90 contains 6.02×10^23 nuclei.
The mass, m of Strontium in the sample is calculated:
[tex]m = 1.082 × 10^{15} × \frac{90 g}{6.02 × 10^{23}} = 1.62 × 10^{-7}g \\ [/tex]
Therefore, the mass of of Strontium in the sample is:
[tex]1.62 × 10^{-7} \: g[/tex]
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When you think about and describe the characteristics of a giraffe, what type of model are you using?
Answer:
The giraffe is the tallest of all mammals. It reaches an overall height of 18 ft (5.5 m) or more. The legs and neck are extremely long. The giraffe has a short body, a tufted tail, a short mane, and short skin-covered horns
What best describes the relationship between sleep and memory? The quantity of sleep impacts memory, while the quality of sleep does not. The quantity of sleep does not impact memory, while the quality of sleep does. The quantity and quality of sleep have no impact on memory. The quantity and quality of sleep both impact memory.
Answer:
The quantity and quality of sleep both impact memory.
Explanation:
The time period of 2 pendulums are 1.22 s and 0.54 s. Calculate the ratio of their lengths.
[tex]~~~~~\dfrac{T_1}{T_2}= \dfrac{1.22}{0.54}\\\\\\\implies \dfrac{2\pi \sqrt{\dfrac{L_1}{g}}}{2\pi \sqrt\dfrac{L_2}g}}= 2.259\\\\\\\implies \dfrac{\sqrt{L_1}}{\sqrt g} \times \dfrac{\sqrt g}{\sqrt{L_2}} = 2.259\\\\\\\implies \sqrt{\dfrac{L_1}{L_2}} = 2.259\\\\\\\implies \dfrac{L_1}{L_2} = 5.104\\\\\\\implies L_1:L_2 = 5.104[/tex]
PLEASE HELP!! Lab: Electromagnetic Induction
Answer:
I think this is the answer
Explanation:
Then, complete the riddle below by finding the matching number and writing the letter.
Newton's Second Law
44k el effe &
forces cause an object to accelerate.
3
10
Acceleration depends on I & I and M a ½ ½.
11 12
13
14 15
16
17
18
19
As the force increases, the
accelera
i on
20
21
29
30 31
increases, too.
Why did the artist paint on cement blocks instead of paper?
"
11
He wanted to create
Answer:
I have no clue I'm just trying to get points
Explanation:
:) sorry
The position x of a particle moving along x axis varies with time t as x = Asin(wt) , where A and w are constants . The acceleration of the particle varies with its position as
[tex] \small \red{ \rm Nonsense = Report} \checkmark[/tex]
Let's see
[tex]\\ \rm\Rrightarrow x=Asin(\omega t)\dots(1)[/tex]
Now we know the formula of acceleration
[tex]\\ \rm\Rrightarrow \alpha=-A\omega^2sin(\omega t)[/tex]
[tex]\\ \rm\Rrightarrow \alpha=-Asin(\omega t)\times \omega^2[/tex]
From eq(1)[tex]\\ \rm\Rrightarrow \alpha=-x\omega^2[/tex]
Or
[tex]\\ \rm\Rrightarrow \alpha=-\omega^2x[/tex]
Given that the position x of a particle along X-axis varies with time t by the equation:
[tex]{:\implies \quad \sf x=A\sin (\omega t)}[/tex]
As it defines the position, so x is just displacement here, and we need to find the acceleration first for telling with what if varies, so by definition, the second differential coefficient of displacement is acceleration, so differentiating both sides w.r.t.x of the above equation in accordance with chain rule we have:
[tex]{:\implies \quad \sf \dfrac{dx}{dt}=A\cos (\omega t)\cdot \omega \cdot \dfrac{dt}{dt}}[/tex]
[tex]{:\implies \quad \sf \dfrac{dx}{dt}=A\omega \cos (\omega t)}[/tex]
Differentiating both sides w.r.t.x by chain rule again to get the 2nd order derivative
[tex]{:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-A\omega \sin (\omega t)\cdot \omega \dfrac{dt}{dt}}[/tex]
[tex]{:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-A\omega^{2}\sin (\omega t)}[/tex]
Re-write as :
[tex]{:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-\omega^{2}\{A\sin (\omega t)\}}[/tex]
Can be further written as
[tex]{:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-x\omega^{2}}[/tex]
This is the Required answer
If they ask you the differential equation for the acceleration of a wave (as the given equation was general equation of a wave), you can simply write:
[tex]{:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}+x\omega^{2}=0}[/tex]
What is the angular acceleration experienced by a uniform solid disc of mass 5-kg and radius 20 cm when a net
torque of 50 N.m is applied? Assume the disc spins about its center.
Answer:
7.07 radians per second
a sound has a wavelength of 0.52028. If the speed is 343.00m/s, what is the musical note?
The fundamental frequency of a musical note is 330Hz. What is the frequency of the 3rd overtone?
The 3rd overtone or the third harmonic given that the fundamental frequency is 330Hz is 990Hz
What is an Harmonic?Hamonics defined as the number gotten by multiplying the nth overtone by the fundamental frequecency.
In summary, the expression for the nth Hamonic or overtone is given as
Fn = Fundamental Frequency*N
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A(n) __________ __________ is made with an electromagnet that is free to spin between two permanent magnets
Answer:
Like a galvanometer, an electric motor contains (a switch, an electromagnet) that is free to rotate between the poles of a permanent, fixed magnet. 9.
The atmosphere has mass and produces friction as objects move through it.
true or false
true
Explanation:
It has friction when objects move through it.
If you double the mass, what happen to the acceleration?
Answer: The math behind this is quite simple. If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.
Explanation:
How long it take to change the velocity of a car from 100m/s to 250m/s if it accelerates at 5m/s^2
Answer:
30 seconds
Explanation:
The formula for calculating acceleration is
( final velocity - inital velocity) ÷ time
If we enter the values, it would be (250 - 100) ÷ t = 5m/s^2
Now we need to know 't'
So we rearrange the equation to make t the subject.
(250-100) ÷ 5 = 30s
what is kinematics ?
explain ~
Kinematics is the branch of physics and a subdivision of classical mechanics concerned with the geometrically possible motion of a body or system of bodies without consideration of the forces involved. :)
Answer:
Kinematics is a branch of mechanics that deals with pure motion, without reference to the masses or forces involved in it.
Explanation:
Ex. X=2t+1 here x is related to t which is time(function of time)
A small block sits at one end of a flat board that is 2.50 m long. The coefficients of friction between the block and the board are μs = 0.450 and μk = 0.400. The end of the board where the block sits is slowly raised until the angle the board makes with the horizontal is α0, and then the block starts to slide down the board.
Hi there!
In order for a block to begin sliding, the force due to STATIC friction must be overcome.
In this instance, the following forces are acting on the block ALONG the axis of the incline.
Force due to gravity (Fg)Force due to STATIC friction (Fs)Force due to gravity:
On an incline, the component of the force due to gravity contributing to the object's downward movement is equivalent to the horizontal (sine) component.
[tex]F_g = Mgsin\theta[/tex]
Force due to static friction:
The force due to friction is equivalent to the normal force multiplied by the coefficient of friction.
The normal force is the cosine component (perpendicular to the incline), so:
[tex]N = Mgcos\theta\\\\F_s = \mu_sMgcos\theta[/tex]
To find the minimum angle for the block to begin sliding, we can set the two forces equal to 0. They work in opposite directions (let down the incline be negative and up the incline be positive).
[tex]\Sigma F = F_s - F_g\\\\0 = F_s - F_g\\\\0 = \mu_sMgcos\theta - Mgsin\theta\\\\Mgsin\theta = \mu_sMgcos\theta[/tex]
Cancel out 'Mg' and rearrange to solve for theta.
[tex]sin\theta = \mu_scos\theta\\\\tan\theta = \mu_s\\\\\theta = tan^{-1}(\mu_s) = tan^{-1}(.45) = \boxed{24.228^o}[/tex]
I
same 7 kg ball.
9. A 10 N force and a 40 N force are acting in opposite direction on the
ball? What is the magnitude of the acceleration of the ball?
Answer:
Here, m=10 kg
The resultant force acting on the body is
F=(98N)2+(6N)2=10N
Let the resultant force F makes an angle θ w.r.t. 8N force.
From figure, tanθ=8N6N=43
The resultant acceleration of the body is
a=mF=10kg10N=1ms−2
The resulatnt acceleration is along the direction of the resulatnt force.
Hence, the resultant acceleration of the body is 1 ms−2 at an angle of tan−1(43) w.r.t. 8N force.

Select the star life cycle that is accurate.
A. Nebula, star of two stellar mass, supernova, black hole
B. Star of three stellar masses, red supergiant, supernova, neutron
star
C. Supernova, star of three stellar masses, black hole, nebula
D. Nebula, white dwarf, red giant, black hole
Answer:
B according to the picture
Explanation:
Star of 3 stellar masses => red supergiant=>supernova=>neutron star
Star of three stellar masses, red supergiant, supernova, neutron star are the star life cycle that is accurate. Therefore, the correct option is option B.
A star's life cycle is as follows: star formation inside a nebula, evolution into a sequence star, sustained nuclear fusion for a long time, exhaustion of fuel at some point, and gravitational core collapse with resulting high pressures and temperatures.
They typically consist of heated plasma held together by a strong gravitational force and are self-luminous. The thermonuclear process between helium and hydrogen that takes place in a star's core causes it to glow brilliantly. Star of three stellar masses, red supergiant, supernova, neutron star are the star life cycle that is accurate.
Therefore, the correct option is option B.
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After a boater runs out of gas a boater considers dropping the motor into the water to create waves describe the resuming motion of the boat and explains why the boaters plan will not help him reach shore ????
The boat will swing back and forth about the same location, never reaching the land. Due to which the boaters plan will not help him reach shore.
Describe boat motion?The ship rocks back and forth as the wind and waves press against it. Similar to swiveling on a chair, yaw spins the ship on an unseen central line.
Waves travelling perpendicular to the ship's motion might create this, changing the ship's heading or direction.
The motion of the motor will be identical to that of water molecules. Because there is a wave on the water surface,The motor will move in lockstep with the water particle.
The particles of the medium only vibrate perpendicular to the wave propagation as the wave travels through the water surface, but they are not moved from their initial position.
As a result, the boat will swing back and forth about the same location, never reaching the land.
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A. A cord passing over an easily turned pulley (one that is both massless and frictionless) has 7kg mass hanging from one end and a 9kg mass hanging from the other end as shown below. G 7.0 kg 9.0 ks This arrangement is known as Atwood's machine. Calculate the (i). acceleration of the masses (ii). tension in the cord. [2.5
Answer:
M g = M a = a (9 - 7) kg with the two masses going in different directions
(7 + 9) kg * g = a * 2 kg 2 kg effective in prducing acceleration
a = 16 / 2 * g = 9.8 m/s^2 / 8 = 1.23 m/s^2
M1 a = T - M1 * g T producing upward acceleration of 1.23 m/s^2
T = 7 (a + g) = 7 * 11 = 77 N
Check:
M2 a = M2 * g - T M2 producing downward acceleration
T = M2 (g - a) = 9 * (9.8 - 1.23) = 77 N
A piece of fine fiber with a diameter of =6.5 m is used to prop apart the edges of two perfectly flat 3.3-cm-long pieces of glass (see diagram). When the setup is illuminated from above with light of wavelength =590 nm , an interference pattern of alternating bright and dark bands will be seen in the reflected light. If the setup is viewed from high above, how many dark bands will be seen?
We need frequency:-
[tex]\\ \rm\Rrightarrow \nu=\dfrac{c}{\lambda}[/tex]
[tex]\\ \rm\Rrightarrow \nu=\dfrac{3\times 10^8m/s}{590\times 10^{-9}m}[/tex]
[tex]\\ \rm\Rrightarrow \nu=0.0051\times 10^{17}Hz[/tex]
[tex]\\ \rm\Rrightarrow \nu=5.1\times 10^{14}Hz[/tex]