Andrea drove 20 1/2 miles in 1/3 of an hour at constant speed what was that speed

Answer:

25x + 75 ≥ 30

Hope this helps!

Answer:

Step-by-step explanation:

Let the number is x in each case.

Use the property below:

We have:

Answer:

[tex]\log_31=0[/tex]

[tex]\log_33=1[/tex]

[tex]\log_3\left(\frac{1}{9}\right)=-2[/tex]

[tex]\log_{3}81=4[/tex]

Step-by-step explanation:

[tex]\textsf{Apply log law}: \quad \log_ax=c \iff x=a^c[/tex]

Therefore:

[tex]\log_3x=0 \implies x=3^0=1[/tex]

[tex]\log_3x=1 \implies x=3^1=3[/tex]

[tex]\log_3x=-2\implies x=3^{-2}=\dfrac{1}{3^2}=\dfrac{1}{9}[/tex]

[tex]\log_3x=4 \implies x=3^4=81[/tex]

Additionally, the logarithm of 1 with any base is always zero:

[tex]\log_a1=0[/tex]

The logarithm of the same number as the base is always 1:

[tex]\log_aa=1[/tex]

Answer:

17 - 2= 15

so if you do

15 ÷ 3 = 5

so x= 5

Answer:

Logxy =1/2

Step-by-step explanation:

Step-by-step explanation:

that is really, really simple.

h(-3) means that we put the argument (-3) into the formula of the function everywhere where there is x.

h(x) = -3x - 10

so,

h(-3) = -3×-3 - 10 = 9 - 10 = -1

Answer:

-1

Step-by-step explanation:

h(x) = -3x - 10    

h(-3)            means to replace the x in the problem with the value of -3 and  

                   solve.

h(-3) = -3(-3) - 10

h(-3) =  9 - 10

h(3) = -1

Answer:

B

Step-by-step explanation:

In similar triangles corresponding sides are in same ratio

[tex]\dfrac{CV}{CE}=\dfrac{CU}{CD}\\\\\\\dfrac{CV}{54}=\dfrac{14}{98}\\\\CV=\dfrac{14}{98}*84\\\\CV = \dfrac{1}{7}*84\\\\CV = 12[/tex]

Answer:

B) 12

Step-by-step explanation:

CD - 98

CE - 84

~

CU - 14

CV = 12

-

You set up a proportion: 98/84 = 14/x

x=12

Answer:

B = x = 44 degrees

Step-by-step explanation:

Interior angles of a triangle = 180 degrees.

There are 2 congruent sides so the angle to the right of 67 degrees is also 67 degrees

180 - 2(67) = 46 degrees (the third angle of the triangle)

x + 46 degrees = 90 degrees ( complementary angles)

x = 44 degrees

Answer:

um just one question are you sure it's supposed to be d-6 instead of b-6

Step-by-step explanation:

if it's b-6 instead of d then the answer is 1

Answer:

-12/7

Step-by-step explanation:

2/3=4/x+3

2/3-3=4/x    Subtract 3 from both sides

2/3-9/3=4/x   Make them have a common denominator

-7/3=4/x

-7/3x=4

x=(4)/(-7/3)

x=[tex]\frac{-12}{7}[/tex]

Answer:

126°

Step-by-step explanation:

1. We know that 54 degrees and its adjacent are a linear pair, meaning that they add up to 180 degrees. To find the measure of the adjacent angle, we subtract 54 from 180.

2. Now, we know that adjacent of 54 is 126. Also, we know that [tex]l[/tex] ║ [tex]m[/tex] ║ n, and x and 126 degrees are corresponding angles. Corresponding angles are congruent within angle measures, so x = 126 degrees.

Answer:

Step-by-step explanation:

MY SISTER HAVE DIS EQUETION I TELL YOU

The midpoint of a line divides the line into equal segments.

See below for the proof of [tex]\mathbf{MN = \frac{1}{2}AC}[/tex]

The given parameters are:

[tex]\mathbf{A = (-5,-4)}[/tex]

[tex]\mathbf{B = (3,-2)}[/tex]

[tex]\mathbf{C = (-1,6)}[/tex]

The coordinates of M (midpoint of AB) are calculated as follows:

[tex]\mathbf{M = \frac{1}{2}(x_1 + x_2, y_1+y_2)}[/tex]

So, we have:

[tex]\mathbf{M = \frac{1}{2}(-5 + 3, -4-2)}[/tex]

[tex]\mathbf{M = \frac{1}{2}(-2, -6)}[/tex]

[tex]\mathbf{M = (-1, -3)}[/tex]

The coordinates of N (midpoint of BC) are calculated as follows:

[tex]\mathbf{N = \frac{1}{2}(x_1 + x_2, y_1+y_2)}[/tex]

So, we have:

[tex]\mathbf{N = \frac{1}{2}(3 - 1, -2 +6)}[/tex]

[tex]\mathbf{N = \frac{1}{2}(2, 4)}[/tex]

[tex]\mathbf{N = (1, 2)}[/tex]

Distance MN is:

[tex]\mathbf{MN = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}[/tex]

So, we have:

[tex]\mathbf{MN = \sqrt{(-1 - 1)^2 + (-3 - 2)^2}}[/tex]

[tex]\mathbf{MN = \sqrt{29}}[/tex]

Distance AC is calculated as follows:

[tex]\mathbf{AC= \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}[/tex]

So, we have:

[tex]\mathbf{AC= \sqrt{(-5 - -1)^2 + (-4 - 6)^2}}[/tex]

[tex]\mathbf{AC= \sqrt{116}}[/tex]

Split

[tex]\mathbf{AC= \sqrt{4 \times 29}}[/tex]

Take positive square root of 4

[tex]\mathbf{AC= 2\sqrt{29}}[/tex]

To prove that:

[tex]\mathbf{MN = \frac{1}{2}AC}[/tex]

We have:

[tex]\mathbf{\sqrt{29} = \frac{1}{2} \times 2\sqrt{29}}[/tex]

[tex]\mathbf{\sqrt{29} = \sqrt{29}}[/tex]

The above equation is true.

Hence. [tex]\mathbf{MN = \frac{1}{2}AC}[/tex]

Read more about midpoints and distance at:

https://brainly.com/question/11231122

Answer:

40.5

Step-by-step explanation:

x2 - 81 = 0 --> + 81 to both sides

2x = 81 --> divide by 2 on both sides

x = 40.5

Answer:

2x-81=0

2x=0+81

2x=81

x=81

2

x=40.5 ANSWER.

MARK ME AS A BRAINLIST PLZ.

Answer:X=5

Step-by-step explanation:took the test

Answer:

20

Step-by-step explanation:

Assuming you are referring to the day that both teams would play on the same day, it would be the 20th.

There are two ways you can do it.

1. List out the multiples of each number

2. multiply the two days together

If you want to do it the first way it would look like this...

5 10 15 20

4 8 12 16 20

When you do it like this it shows you that the 20th day is the day they would both play together

If you want to do it the second way it would look like this...

4th day X  5th day = 20th day

Either way you solve the problem you get the same answer, this may not work for every problem like this, but it works for this particular one

9514 1404 393

Answer:

  y = 2x +1

Step-by-step explanation:

The line rises 2 units for each 1 unit to the right, so its slope is ...

  m = rise/run = 2/1 = 2

The line crosses the y-axis at y = 1, so the y-intercept is ...

  b = 1

Then the slope-intercept form equation is ...

  y = mx + b . . . . . . . for slope m and y-intercept b

  y = 2x + 1 . . . . . . . . fill in the known values

Answer: 100

Step-by-step explanation:

A line equals 180 so subtract 180-80 to get your answer.

Work Shown:

45.40 - 40 = 5.40

She made $5.40 in profit. Divide this over the original price to find the percentage profit

(5.40)/(40) = 0.135 = 13.5%

Answer:

5, -5

hope this helps

Answer:

Train to BaDussy

Step-by-step explanation:

Answer:

The correct ratio is 7:8, so no, Emma is not correct.

Hello cayleahm253!

[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

There are 35 boys in 6th grade. The number of girls in 6th grade is 40. Emma says that means the ratio of the number of boys in 6th grade to the number of girls in 6th grade is 3:4. Is Emma correct? If not, what is the correct answer?

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

Okay, so we can see from the question that there are 35 boys & 40 girls in the 6th grade. So the ratio of boys is to girls will be 35:40.

__________________

Solving...

[tex]35 : 40 \\ = \frac{35}{40} \\ \\ \sf \: Cancel \: out \: 35 \: and \: 40 \: to \: get \: 7 \: and \: 8.\\ \\ = \frac{7}{8} \\ = \huge \boxed{\boxed{\bf \: 7 : 8}}[/tex]

__________________

__________________

Hope it'll help you ッ

ℓucαzz

Answer: [tex]5^{3}[/tex]

Step-by-step explanation:

Answer:

81+71+x=180

152+x=180

x=180-152

x=28°

Step-by-step explanation:

Hope that this is helpful.

Have a great Day.

Answer:

is this the full question?

Answer:

x equals 375

Step-by-step explanation:

75+0.70x=0.90x

________

[tex] \: [/tex]

5x - 10 = 20

5x = 20 + 10

5x = 30

x = 30 ÷ 5

x = 6✔

Replace all occurrences of x with y + 3 in each equation.

Replace all occurences of x in 6x - 5y = 15 with y + 3.

6 (y+3) -5y = 15

x = y + 3

Simplify 6 (y + 3) - 5y.

Simplify each term.

Apply the distributive property.

6y + 6 · 3 - 5y = 15

x = y + 3

Multiply 6 by 3.

6y + 18 - 5y = 15

x = y + 3

Subtract 5y from 6y.

y + 18 = 15

x = y + 3

Move all terms not containing y to the right side of the equation.

Subtract 18 from both sides of the equation.

y = 15 - 18

x = y + 3

Subtract 18 from 15.

y = -3

x = y + 3

Replace all occurences with y with -3 in each equation.

Replace all occurences of y in x = y + 3 with -3.

x = (-3) + 3

y = -3

Add -3 and 3.

x = 0

y = -3

The solution to the system is the complete set of ordered pairs that are valid solutions.

(0,-3)

The result can be shown in multiple forms.

Point Form:

(0,-3)

Equation Form:

x = 0, y = -3

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The required values are :

Refer to the attachment for solution ~