an object has a mass of 2000kg what is its weight on earth

Answer:

The answer is False......

Answer:

true

it is equal but opposite

Answer:

30.4 s

Explanation:

A pilot , with plane accelerated at 4 g starts greying out . In the problem , the acceleration of jet is 4 g

a = 4 x 9.8 = 39.2 m /s²

initial velocity u = 0

Final velocity = 3.60 times speed of sound

= 3.6 x 331 = 1191.6 m /s

v = u + at

Putting the values

1191.6 = 0 + 39.2 t

t = 30.4 s .

Answer:

a)    F = 21.16 N,  b)     a = 3.17 10²⁸ m / s

Explanation:

a) The outside between the alpha particles is the electric force, given by Coulomb's law

          F = [tex]k \frac{ q_1 q_2}{r^2}[/tex]

in that case the two charges are of equal magnitude

          q₁ = q₂ = 2q

let's calculate

         F = [tex]9 \ 10^9 \ \frac{ (2 \ 1.6 \ 10^{-19} )^2 }{ (6.60 \ 10^{-15} )^2 }[/tex]

         F = 21.16 N

this force is repulsive because the charges are of the same sign

b) what is the initial acceleration

         F = ma

         a = F / m

         a = [tex]\frac{21.16}{4.0026 \ 1.67 \ 10^{-27} }[/tex]21.16 / 4.0025 1.67 10-27

         a = 3.17 10²⁸ m / s

this acceleration is in the direction of moving away the alpha particles

Answer:

Explanation:

We shall first calculate electric potential at the centre of square due to four charges of Q .

potential = k Q / r , k = 9 x 10⁹ , Q is charge which is placed at distance r from the point where potential is measured .

Distance of corner of square to centre = √ 2 a / 2 = a / √2 = .707 a

potential due to one charge

= k x Q / .707 a

= 9 x 10⁹ x Q / .707a

= 12.73 x 10⁹ Q/a

Potential due to 4  charges

= 4 x 12.73 x 10⁹ Q/a

= 50.92 x 10⁹ Q/a .

Potential at infinity = 0

Work done in carrying charge q from infinity to centre of square

= potential difference x charge

= ( 50.92 x 10⁹ Q/a - 0 ) x q

= 50.92 x 10⁹ x Qq / a  J .

Answer:

D. Yes

m

m mb

m

m

m

n

nn

n

n

n

j

j

jj

Explanation:

The time taken by a wave crest to travel a distance equal to the length of wave is known as wave period.

The relation between wave period and frequency is as follows.

T = \frac{1}{f}T=

f

1

where, T = time period

f = frequency

It is given that wave period is 18 seconds. Therefore, calculate the wave period as follows.

T = \frac{1}{f}T=

f

1

or, f = \frac{1}{T}f=

T

1

= \frac{1}{18 sec}

18sec

1

= 0.055 per second (1cycle per second = 1 Hertz)

or, f = 5.5 \times 10^{-2} hertz5.5×10 −2 hertz

Answer: we divide this equation by pV and use {C}_{p}={C}_{V}+ . ... The temperature, pressure, and volume of the resulting gas-air mixture

Explanation:

The new pressure of the gas relative to its initial pressure P₁ is P₁ × 1.09

From the question given above, the following data were obtained:

Initial temperature (T₁) = 20 °C = 20 + 273 = 293 K

Initial pressure (P₁) = P₁

New temperature (T₂) = 46 °C = 46 + 273 = 319 K

The new pressure of the gas can be obtained as follow:

P₁ / T₁ = P₂ / T₂

P₁ / 293 = P₂ / 319

Cross multiply

293 × P₂ = P₁ × 319

Divide both side by 293

P₂ = (P₁ × 319) / 293

Thus, the new pressure relative to it's initial pressure is P₁ × 1.09

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Answer:

720N

Explanation:

According to Newtons second law;

Force = Mass* Acceleration

Let the acceleration given be 15m/s²

Mass = 48kg

Substitute

Force = 48 * 15\

Force = 720N

Hence the required horizontal force is 720N

Note that the value of the acceleration was assumed

Answer:

The more massive an object is, the greater the gravitational force. Since gravitational force is inversely proportional to the distance between two interacting objects, more separation distance will result in weaker gravitational forces.

Explanation:

hope this help:)

Answer:

Magnitude of it's displacement = 1,000 km

Explanation:

Given:

Distance towards east = 800 km

Distance towards north = 600 km

Find:

Magnitude of it's displacement

Computation:

Magnitude of it's displacement = √800² + 600²

Magnitude of it's displacement = √640000 + 360000

Magnitude of it's displacement = √10000000

Magnitude of it's displacement = 1,000 km

Answer:

a) DECREASE, b) INCREASE, c)  power remains constant

Explanation:

The resistance and the battery are connected in series.

a) How the current changes when the resistance changes

               V = I R

               I = V / R

               I = 12 / R

if the resinification increases, the current must DECREASE

b) when you check the expression

                V= I R

, if R increases the voltage of the INCREASE

c) the power in an electric circuit is

               P = I V

Let's analyze this expression, the voltage increases linearly with the increase in resistance and the current decreases linearly with the increase in r, for which the two effects are compensated and the dissipated power remains constant

Answer:

the sign and magnitude of the charge is - 2 x 10⁻⁵ C.

Explanation:

Given;

mass of the particle, m = 1.43 g = 0.00143 kg

electric field experienced by the particle, E = 700 N/C

The force experienced by the particle is calculated as;

F = mg = EQ

Where;

Q is the magnitude of the charge

[tex]Q = \frac{mg}{E} \\\\Q = \frac{0.00143 \times 9.8}{700} \\\\Q = 2\times 10^{-5} \ C[/tex]

The force must be upward in opposite direction to the electric field. Since the force and the electric field are in opposite direction, the charge must be negative.

Therefore, the sign and magnitude of the charge is - 2 x 10⁻⁵ C.

The particle to remain stationary, when placed in a downward-directed electric the force must be in opposite direction which upward directed.

The charge of the given particle to remain stationary should be [tex]-2\times10^{-5}[/tex] C.

The electric force experienced by the body when placed it into the electromagnetic field is called electric charge.

Given information-

The mass of the particle is 1.43 g or 0.00143 kg.

The magnitude of the downward-directed electric field is 700 N/C.

The magnitude of the free-fall acceleration is 9.80 meter per second squared.

The electric field is defined as the electric force per unit charge. It can be given as,

[tex]E=\dfrac{F}{q}[/tex]

Rewrite the equation for the charge,

[tex]q=\dfrac{F}{E}[/tex]

Force experienced by the particle is equal to the product of mass and free fall acceleration (gravity). Thus,

[tex]q=\dfrac{0.00143\times9.8}{700}\\q=2\times10^{-5}[/tex]

Thus the magnitude of the charge is [tex]2\times10^{-5}[/tex] C.

The particle to remain stationary, when placed in a downward-directed electric the force must be in opposite direction which upward directed. For the opposite direction the sign of the charge should be negative.

Thus the charge of the given particle to remain stationary should be [tex]-2\times10^{-5}[/tex] C.

Learn more about the electric charge here;

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Answer:

The time to reach 31.6 m/s is 14.54 s.

Explanation:

Given;

acceleration of the locomotive, a = 1.60 m/s²

distance traveled by the locomotive, s = 20 m

time of motion, t = 2.4 s

final velocity of the locomotive, v = 31.6 m/s

The speed of the of the locomotive as it leaves the 20 m wide crossing;

[tex]v = \frac{d}{t} \\\\v = \frac{20}{2.4} \\\\v = 8.333 \ m/s[/tex]

The time to reach 31.6 m/s is calculated from the equation below;

v = u + at

31.6 = 8.333 + 1.6t

1.6t = 31.6 - 8.333

1.6t = 23.267

t =  23.267 / 1.6

t = 14.54 s

Therefore, the time to reach 31.6 m/s is 14.54 s.

Answer:

static friction and kinetic friction.

Explanation:

Answer: F = 98N

Explanation: The shaft have to sustain the pulley, the cord and the two masses. The pulley and the cord have negligible masses, so, they have negligible weight.

The two masses have two vertical forces acting on them: force of traction because of the cord and force due to gravitational force, also known as weight.

So, the vertical force the shaft has to support is the sum of the weight of each mass:

[tex]F_{net}=F_{g}_{1}+F_{g}_{2}[/tex]

[tex]F_{net}=m_{1}.g+m_{2}.g[/tex]

[tex]F_{net}=g(m_{1}+m_{2})[/tex]

[tex]F_{net}=9.8(7+3)[/tex]

[tex]F_{net}=[/tex] 98

The vertical force that supports the whole system is 98 N.

Answer:

c, its axis is tilted

maybe

As it works its way around the sun, its tilted axis exposes different parts of earth.

C would be it because the roation of Earth on its axis doesn't have anything to do with the exposer of the revolution on its axis

Answer: 50J

Explanation:

Mechanical energy follows the same principles of kinetic energy and potential energy, it is conserved. So Ei = Ef.

Mechanical energy is the sum of ALL energy's. There is no friction, so its just kinetic plus potential.

37.5 + 12.5 = 50J

Since the particle has not touched the ground, it has not transferred any energy to the ground yet, therefore the mechanical energy must still be 50J; mostly in kinetic energy with a very small amount of potential because of the low height relative to the ground.

Answer:

The correct answer is C

Explanation:

In this problem we must remember that charges of the same sign repel and of the same sign attract.

Generator G induces a charge in the closest spheres C, otherwise the charge is negative, therefore in the furthest sphere F, with the ac that is in contact, a positive charge is formed, they do not indicate that the spheres It is in contact with Earth, so the charges remain on them.

As the spheres move away from the generator, the load is redistributed, they return to their initial load, that is, they remain Neutral since no load left or entered the spheres, there was only a redistribution due to the proximity of the generator.

The correct answer is C

Answer:

A.) glass water air

Explanation:

hope this helps :) have a great day!!

Answer:

A.) glass - water - air

good luck, i hope this helps :)

Answer:

Option A. 180000 Kgm/s.

Explanation:

From the question given above, the following data were obtained:

For Train Car A:

Mass of train car A = 45000 Kg

Velocity of train car A = 4 m/s

Momentum of train car A =?

For Train Car B:

Mass of train car B = 45000 Kg

Velocity of train car B = 0 m/s

Momentum is simply defined as the product of mass and velocity. Mathematically, it can be expressed as:

Momentum = mass × velocity

With the above formula, the momentum of train car A before collision can be obtained as follow:

Mass of train car A = 45000 Kg

Velocity of train car A = 4 m/s

Momentum of train car A =?

Momentum = mass × velocity

Momentum = 45000 × 4

Momentum of train car A = 180000 Kgm/s

Answer:

0.75

Explanation:

Since the static frictional force is the maximum force applied just before sliding, our frictional force, F is 300 N.

Since F = μN where μ = coefficient of static friction and N = normal force = 400 N (which is the downward force applied against the surface).

So, μ = F/N

= 300 N/400 N

= 3/4

= 0.75

So, the  coefficient of static friction μ = 0.75

Answer:

No. A is correct because both warming up and cooling down are important

Both warming up and cooling down are important.

This is based on aerobics and human body balance regulation as regards exercising.

Warming up and cooling down in exercising are just based on the level of intensity at which the exercise is carried out.

Thus, Both warming up and cooling down are important.

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Answer:

F = 614913.88 N

Explanation:

We are given;

Mass of pile driver; m = 1800 kg

Height of fall of pole driver; h = 4.6 m

Depth driven into beam; d = 13.6 cm = 0.136 m

Now, from energy equations and applying to this question, we can write that;

Workdone = Change in potential energy

Formula for workdone is; W = F × d

While the average potential energy here is; W = mg(h + d)

Thus;

Fd = mg(h + d)

Where F is the average force exerted by the beam on the pile driver while in bringing it to rest.

Making F the subject, we have;

F = mg(h + d)/d

F = 1800 × 9.81 × (4.6 + 0.136)/0.136

F = 614913.88 N

Explanation:

KE = ½mv²

= ½ × 5 × 4²

= ½ × 5 × 16

= ½ × 80

= 40 J

Answer:

c. The roller coaster is in uniform circular motion

Explanation:

Since the loop is circular with radius r, and its instantaneous speed, v is always constant, and also, its centripetal acceleration, a' = v²/r.

Since the angular speed, ω = v/r does not change, the magnitude of its  tangential acceleration is zero although there is a change in its direction because the direction of its initial velocity changes. That is a" = rα and α = Δω/Δt since Δω = 0, α = 0 and a" = r(0) = 0

So, there is no tangential acceleration. Since there is no tangential acceleration, our instantaneous acceleration which is the vector sum of our centripetal acceleration and tangential acceleration is a = √(a'² + a"²) =  √(a'² + 0²) = √a'² = a' = v²/r

So, a is always v²/r.

Since the instantaneous acceleration is always (a = v²/r) constant, the motion is uniform. So, it is uniform circular motion.

The roller coaster is not in uniform circular motion, and [tex]a = \frac{v^2}{r}[/tex] is only applicable at the very top and bottom of the loop where the tangential acceleration vanishes.

The given parameters;

The motion tension on the loop at the lowest point in the circular motion is given as;

[tex]T = mg + \frac{mv^2}{r}[/tex]

The motion tension on the loop at the highest point in the circular motion is given as;

[tex]T = \frac{mv^2}{r} - mg[/tex]

This shows that circular motion is affected by;

Thus, we can that the roller coaster is not in uniform circular motion, and [tex]a = \frac{v^2}{r}[/tex] is only applicable at the very top and bottom of the loop where the tangential acceleration vanishes.

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Answer:

with that  boom and that boom glare boom that boom glare with that boom the tha ba glare boom that boom glare with that.

Explanation:

Answer:

Explanation:

Total solar energy falling on total surface per second

= 410 x  820 W

= 336200 W

10 % of 336200 = 33620 J is converted into heat which is absorbed by lake water . But its temperature does not rise because heat is used up in evaporating water in the form of vapor .

Total heat released during evaporation = 33620 J

Let evaporation rate be m gram /s

heat absorbed by m gram water = m x latent heat of evaporation

= m x 2260 J .

Given ,

m x 2260 = 33620

m = 14.87 g /s .

Answer:

The temperature of this newly discovered planet violates the third law of thermodynamic, there is a mistake in this value.

Explanation:

The third law of the Thermodynamic says:

At zero kelvin all molecular movement stops, which means that the entropy will be zero at this temperature.

So we can say there is no thermodynamic system that has temperature values less than 0 K.

The conclusion of the report will be.

The temperature of this new planet violates the third law of thermodynamic, there is a mistake in this value.

I hope it helps you!

Answer:

Explanation:

From the information given:

The schematic diagram for the system and the force body diagrams for each charge can be seen in the image attached below

(c)

The symbolic expressions for the net force on each object is as follows:

[tex]N_A = m_Ag \\ \\ F_{net}, A= F_A = \dfrac{kQ_AQ_B}{r^2}[/tex]

[tex]N_B = m_Bg \\ \\ F_{net}, B= F_B = \dfrac{kQ_AQ_B}{r^2}[/tex]

(d) From above

[tex]F_A =F_B[/tex]

[tex]m_Aa_A = m_Ba_B \\ \\ (6m_B)a_A = m_B a_B[/tex]

[tex]a_B = 6a_A[/tex]