An insurance company’s records indicate that the mean compensation paid to clients claiming on motor insurance is R10 800 with standard deviation R2 500. Suppose that 50 claims are made within one week. What is the probability that the mean compensation paid is less than R10 200?

Answer:

B. 7 to the right of the 9

9+(-7)

=9-7=2

so, the 7 is on the right side of 9

Answer:

Explaination down below

Step-by-step explanation:

Before you start this question, make sure you know this rule. When multiplying fractions, Multiply the numerator by the other numerator and multiply the denominator by the other one.

[tex]\frac{1}{5}[/tex] x [tex]\frac{1}{2}[/tex]. 1*1=1, so one is the numerator. 2*5= 10 so 10 is the denominator.

The final answer is [tex]\frac{1}{10}[/tex].

You could also look at it another way. What is one half of one-fifth?

That is another way to look at it.

If this helped, please mark me as brainliest. Thank you! ;)

Answer:

x=4.25

------------------------------------------

8+8=4x-1

16=4x-1

4x=16+1

4x=17

x= 17/4

I have no idea if i am correct just a guesstimate

Have a good day

n + 1 = 4(n - 8)

n + 1 = 4n - 32

n - 4n = -32 - 1

-3n = -33 / : (-3)

n = 11

Answer:

6 * 100 = 600

14 * 10  = 140

12 * 1    = 12

------------------------

752

Answer:

V = 192π cm³ ≈ 603 cm³

Step-by-step explanation:

V = πR²h

V = π(8/2)²(12)

V = 192π cm³ ≈ 603 cm³

J = 3   Hooray, but why?

Answer:

Step-by-step explanation:

Radius r = 4 cm

Height h = 12 cm

Volume = πr²h = 192π cm³ ≈ 576 cm³

the correct answer would be 54 degrees. you would subtract 90 and 54 from 360, leaving 108. you would have to divide by 2 since we have 1 and 2 angles, that leaves 54. hope this helps!

Answer:

last option 180 degrees

Step-by-step explanation:

let ∠1 and angle ∠2 be 2x as both are of same angles

angle sum proprty = 360

90 + 54+ ∠1 +∠2 = 360

144 + 2x = 360

2x = 360 - 144

2x = 216

x = 216 ÷ 2

x = 108

∠2 = 108 degrees

Answer:

20

Step-by-step explanation:

This is because If we are looking for arena then we need to multiply the base by the height if we do this then our answer will be 40, but because we are looking at a triangle we will have to devide that by 2. Which will give us the final answer of 20

Answer:

area = 20 inches

Step-by-step explanation:

Area of a triangle = [tex]\frac{1}{2}[/tex] × Base × Height

= [tex]\frac{1}{2}[/tex] × 8 ×5

= [tex]\frac{1}{2}[/tex] × 40

= [tex]\frac{40}{2}[/tex]

= 20

area = 20 inches

Answer:

225

Step-by-step explanation:

x + y + z = 1305

x = 360

y = 360×2 = 720

z = 1305 - 360 - 720 = 225

Answer:

225

Step-by-step explanation:

since the first number is 360 and the second number is twice the first number meaning it's (360×2) which is 720,you have to add the two and subtract by 1305 to find the value of the third number(which I have represented by x)

360+720+x=1305

1080+x=1305

x=1305-1080

=225

therefore the third number is 225,you can prove it by adding the three to see whether you will get 1305.

I hope this helps

Answer:

I can't understand what you have written and what to find

Step-by-step explanation:

z = 5y/8

x = 3y/8

2x + 3y - z = 50

6y/8 + 3y - 5y/8 = 50

6y/8 + 24y/8 - 5y/8 = 50

25y/8 = 50

25y = 400

y = 16

x = 3y/8 = 3×16/8 = 3×2 = 6

z = 5y/8 = 5×16/8 = 5×2 = 10

3²: It is an example of numeric expression

is a mathematical sentence that encompasses, power, root, multiplication, division, addition and subtraction.

In this question - the following example 3² was given. This example can be classified as a numerical expression, because a power is a multiplication of equal factors.

So, this example is a numeric expression.

Given : The length of a rectangular garden is 4 feet longer than the width. If the perimeter is 192 feet, what is the area of the garden ?

Solution :

Let us assume the breadth be x

The length is 4 ft longer than the Breadth

So, the length be x + 4

Perimeter = 192

❍ Perimeter = 2(Length + Breadth)

Length : x + 4 = 46 + 4 = 50

Breadth : x = 46

Answer:

15/22

Step-by-step explanation:

3/11 ÷ 2/5

3/11 x 5/2

3/11 x 5/2 = 15/22

3/11 divided by 2/5 is equal to 15/22.

Here, we have,

To divide fractions, we can multiply the first fraction by the reciprocal of the second fraction.

The reciprocal of a fraction is obtained by flipping the numerator and denominator.

Let's calculate 3/11 divided by 2/5:

(3/11) ÷ (2/5)

To divide, we multiply by the reciprocal:

(3/11) * (5/2)

Now, multiply the numerators together and the denominators together:

(3 * 5) / (11 * 2) = 15/22

Therefore, 3/11 divided by 2/5 is equal to 15/22.

To learn more on division click:

brainly.com/question/21416852

#SPJ6

Answer:

1.01

Step-by-step explanation:

1^2= 1

0.1^2= 0.01

1+0.01=1.01

Answer:

True

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

Identify

Point (5, 6)

Point (-3, 8)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Answer:

irrational

Step-by-step explanation:

√5 is a non terminating and non recurring number therefore it can't be written as quotient of two numbers so it is irrational.

Note:if you need to ask any question please let me know.

Answer:

[tex]y=-3x+8[/tex]

Step-by-step explanation:

Hi there!

What we need to know:

1) Determine the slope (m)

[tex]y = 4 - 3x\\y = -3x+4[/tex]

Given this equation, we can identify the slope to be -3 since it's in the place of m in [tex]y=mx+b[/tex].

Because parallel lines have the same slope, -3 is therefore the slope of the line we're currently solving for. Plug this into [tex]y=mx+b[/tex]:

[tex]y=-3x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=-3x+b[/tex]

Plug in the given point (1,5) and solve for b:

[tex]5=-3(1)+b\\5=-3+b\\8=b[/tex]

Therefore, the y-intercept is 8. Plug this back into [tex]y=-3x+b[/tex]:

[tex]y=-3x+8[/tex]

I hope this helps!

Answer:

4  2/5

Step-by-step explanation:

4 is 4

0.40 is equal to 4/10 which is equal to 2/5

hoped this helped

Answer:

22/5

Step-by-step explanation:

Step-by-step explanation:

one to one relationship

this is the answer

Answer:

[tex]{ \sf{ = - (\frac{y}{x}) {}^{ - 1} }}[/tex]

Answer: New price =  rs. 1710

Step-by-step explanation:

Given information

Original price (market price) = rs.1800

Discount rate = 5%

Given expression deducted from the question

New price = Original price × (1 - discount rate)

Substitute values into the expression

New price = 1800 × (1 - 5%)

Simplify parentheses

New price = 1800 × 0.95

Simplify by multiplication

New price =[tex]\boxed{rs.1710}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

a^6b^4

Step-by-step explanation:

(a³b²)²

a^6b^4

9514 1404 393

Answer:

  a⁶b⁴

Step-by-step explanation:

The relevant rules of exponents are ...

  (ab)^c = (a^c)(b^c)

  (a^b)^c = a^(bc)

__

These let us simplify the expression as follows:

  [tex](a^3b^2)^2=(a^3)^2(b^2)^2=a^{3\cdot2}b^{2\cdot2}=\boxed{a^6b^4}[/tex]

_____

Additional comment

It might be helpful to remember that an exponent signifies repeated multiplication.

  a·a·a = a³ . . . . . . 'a' is a factor 3 times, so the exponent is 3.

Similarly, ...

  (a³)² = (a³)·(a³) = (a·a·a)·(a·a·a) = a⁶

Answer:

a) 1.50x + 20 = y

c) $27.5

d) 8 hours

Step-by-step explanation:

a) 1.50 times x the amount of hours. 1.50 per hour. 1 hour would be 1.50 and 2 hours would be 3.00. Then just add 20 to that amount.

b) Don't really have time to graph, but here this is the graph using a graphing calculator. It intercepts at 20 because 20 is b, which is the y intercept.

c) Plug in 5 for x

d) Start with 1.50x + 20 = 32. You need to solve for x. Subtract 20 from both sides and you get 1.50x = 12. Divide both sides by 1.50 and you get x = 8. Since x representshe amount of hours, it would be x.

Answer:

8i+3j

Step-by-step explanation:

let point P2(0,3)

point P1(-8,0)

vector P1P2= Position vector of P2- position vector of P1

vector= (0,3)-(-8,0)

vector= (8,3)

vector=8i+3j

Answer:

6 in.

Step-by-step explanation:

To find the area of the rectangle, substitute the given values into the formula A = lw. Then, substitute 36 inches squared into the formula A = s2. Find the square root of both sides of the equation to find s.

Given z = 3 + i, right away we can find

(a) square

z ² = (3 + i )² = 3² + 6i + i ² = 9 + 6i - 1 = 8 + 6i

(b) modulus

|z| = √(3² + 1²) = √(9 + 1) = √10

(d) polar form

First find the argument:

arg(z) = arctan(1/3)

Then

z = |z| exp(i arg(z))

z = √10 exp(i arctan(1/3))

or

z = √10 (cos(arctan(1/3)) + i sin(arctan(1/3))

(c) square root

Any complex number has 2 square roots. Using the polar form from part (d), we have

√z = √(√10) exp(i arctan(1/3) / 2)

and

√z = √(√10) exp(i (arctan(1/3) + 2π) / 2)

Then in standard rectangular form, we have

[tex]\sqrt z = \sqrt[4]{10} \left(\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) + i \sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right)\right)[/tex]

and

[tex]\sqrt z = \sqrt[4]{10} \left(\cos\left(\dfrac12 \arctan\left(\dfrac13\right) + \pi\right) + i \sin\left(\dfrac12 \arctan\left(\dfrac13\right) + \pi\right)\right)[/tex]

We can simplify this further. We know that z lies in the first quadrant, so

0 < arg(z) = arctan(1/3) < π/2

which means

0 < 1/2 arctan(1/3) < π/4

Then both cos(1/2 arctan(1/3)) and sin(1/2 arctan(1/3)) are positive. Using the half-angle identity, we then have

[tex]\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1+\cos\left(\arctan\left(\dfrac13\right)\right)}2}[/tex]

[tex]\sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1-\cos\left(\arctan\left(\dfrac13\right)\right)}2}[/tex]

and since cos(x + π) = -cos(x) and sin(x + π) = -sin(x),

[tex]\cos\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{1+\cos\left(\arctan\left(\dfrac13\right)\right)}2}[/tex]

[tex]\sin\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{1-\cos\left(\arctan\left(\dfrac13\right)\right)}2}[/tex]

Now, arctan(1/3) is an angle y such that tan(y) = 1/3. In a right triangle satisfying this relation, we would see that cos(y) = 3/√10 and sin(y) = 1/√10. Then

[tex]\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1+\dfrac3{\sqrt{10}}}2} = \sqrt{\dfrac{10+3\sqrt{10}}{20}}[/tex]

[tex]\sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1-\dfrac3{\sqrt{10}}}2} = \sqrt{\dfrac{10-3\sqrt{10}}{20}}[/tex]

[tex]\cos\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{10-3\sqrt{10}}{20}}[/tex]

[tex]\sin\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{10-3\sqrt{10}}{20}}[/tex]

So the two square roots of z are

[tex]\boxed{\sqrt z = \sqrt[4]{10} \left(\sqrt{\dfrac{10+3\sqrt{10}}{20}} + i \sqrt{\dfrac{10-3\sqrt{10}}{20}}\right)}[/tex]

and

[tex]\boxed{\sqrt z = -\sqrt[4]{10} \left(\sqrt{\dfrac{10+3\sqrt{10}}{20}} + i \sqrt{\dfrac{10-3\sqrt{10}}{20}}\right)}[/tex]

Answer:

[tex]\displaystyle \text{a. }8+6i\\\\\text{b. }\sqrt{10}\\\\\text{c. }\\\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}}+i\sqrt{\frac{\sqrt{10}-3}{2}},\\-\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}}-i\sqrt{\frac{\sqrt{10}-3}{2}}\\\\\\\text{d. }\\\text{Exact: }z=\sqrt{10}\left(\cos\left(\arctan\left(\frac{1}{3}\right)\right), i\sin\left(\arctan\left(\frac{1}{3}\right)\right)\right),\\\text{Approximated: }z=3.16(\cos(18.4^{\circ}),i\sin(18.4^{\circ}))[/tex]

Step-by-step explanation:

Recall that [tex]i=\sqrt{-1}[/tex]

Part A:

We are just squaring a binomial, so the FOIL method works great. Also, recall that [tex](a+b)^2=a^2+2ab+b^2[/tex].

[tex]z^2=(3+i)^2,\\z^2=3^2+2(3i)+i^2,\\z^2=9+6i-1,\\z^2=\boxed{8+6i}[/tex]

Part B:

The magnitude, or modulus, of some complex number [tex]a+bi[/tex] is given by [tex]\sqrt{a^2+b^2}[/tex].

In [tex]3+i[/tex], assign values:

[tex]|z|=\sqrt{3^2+1^2},\\|z|=\sqrt{9+1},\\|z|=\sqrt{10}[/tex]

Part C:

In Part A, notice that when we square a complex number in the form [tex]a+bi[/tex], our answer is still a complex number in the form

We have:

[tex](c+di)^2=a+bi[/tex]

Expanding, we get:

[tex]c^2+2cdi+(di)^2=a+bi,\\c^2+2cdi+d^2(-1)=a+bi,\\c^2-d^2+2cdi=a+bi[/tex]

This is still in the exact same form as [tex]a+bi[/tex] where:

Thus, we have the following system of equations:

[tex]\begin{cases}c^2-d^2=3,\\2cd=1\end{cases}[/tex]

Divide the second equation by [tex]2d[/tex] to isolate [tex]c[/tex]:

[tex]2cd=1,\\\frac{2cd}{2d}=\frac{1}{2d},\\c=\frac{1}{2d}[/tex]

Substitute this into the first equation:

[tex]\left(\frac{1}{2d}\right)^2-d^2=3,\\\frac{1}{4d^2}-d^2=3,\\1-4d^4=12d^2,\\-4d^4-12d^2+1=0[/tex]

This is a quadratic disguise, let [tex]u=d^2[/tex] and solve like a normal quadratic.

Solving yields:

[tex]d=\pm i \sqrt{\frac{3+\sqrt{10}}{2}},\\d=\pm \sqrt{\frac{{\sqrt{10}-3}}{2}}[/tex]

We stipulate [tex]d\in \mathbb{R}[/tex] and therefore [tex]d=\pm i \sqrt{\frac{3+\sqrt{10}}{2}}[/tex] is extraneous.

Thus, we have the following cases:

[tex]\begin{cases}c^2-\left(\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2=3\\c^2-\left(-\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2=3\end{cases}\\[/tex]

Notice that [tex]\left(\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2=\left(-\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2[/tex]. However, since [tex]2cd=1[/tex], two solutions will be extraneous and we will have only two roots.

Solving, we have:

[tex]\begin{cases}c^2-\left(\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2=3 \\c^2-\left(-\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2=3\end{cases}\\\\c^2-\sqrt{\frac{5}{2}}+\frac{3}{2}=3,\\c=\pm \sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}[/tex]

Given the conditions [tex]c\in \mathbb{R}, d\in \mathbb{R}, 2cd=1[/tex], the solutions to this system of equations are:

[tex]\left(\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}}, \sqrt{\frac{\sqrt{10}-3}{2}}\right),\\\left(-\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}},- \frac{\sqrt{10}-3}{2}}\right)[/tex]

Therefore, the square roots of [tex]z=3+i[/tex] are:

[tex]\sqrt{z}=\boxed{\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}}+i\sqrt{\frac{\sqrt{10}-3}{2}} },\\\sqrt{z}=\boxed{-\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}}-i\sqrt{\frac{\sqrt{10}-3}{2}}}[/tex]

Part D:

The polar form of some complex number [tex]a+bi[/tex] is given by [tex]z=r(\cos \theta+\sin \theta)i[/tex], where [tex]r[/tex] is the modulus of the complex number (as we found in Part B), and [tex]\theta=\arctan(\frac{b}{a})[/tex] (derive from right triangle in a complex plane).

We already found the value of the modulus/magnitude in Part B to be [tex]r=\sqrt{10}[/tex].

The angular polar coordinate [tex]\theta[/tex] is given by [tex]\theta=\arctan(\frac{b}{a})[/tex] and thus is:

[tex]\theta=\arctan(\frac{1}{3}),\\\theta=18.43494882\approx 18.4^{\circ}[/tex]

Therefore, the polar form of [tex]z[/tex] is:

[tex]\displaystyle \text{Exact: }z=\sqrt{10}\left(\cos\left(\arctan\left(\frac{1}{3}\right)\right), i\sin\left(\arctan\left(\frac{1}{3}\right)\right)\right),\\\text{Approximated: }z=3.16(\cos(18.4^{\circ}),i\sin(18.4^{\circ}))[/tex]