An entertainment company specifies that its employees must weigh between 40 kgs - 50 kgs. If X is the random variable denoting the weights of employees, X is a __________ random variable.

Answers

Answer 1

Answer: Continuous

If X is the random variable denoting the weights of employees,  X is a continuous random variable.

Step-by-step explanation:

Given: An entertainment company specifies that its employees must weigh between 40 kgs - 50 kgs.

here weights of the employees vary.

Also, weight is measured not counted , that means weight is a continuous variable.

If X is the random variable denoting the weights of employees,  X is a continuous random variable.

Answer 2

The weights of employees, X, is a: continuous random variable.

Facts about Random Continuous VariableA continuous variable is obtained simply through measuring.Examples of continuous variable are: weight of students, distance travelled.A continuous random variable are values given for an interval of numbers.

Therefore, the weights of employees, X, is a: continuous random variable.

Learn more about continuous random variable on:

https://brainly.com/question/15238425


Related Questions

Duane is making cookies. The recipe calls for two times as many cups of sugar as butter, two times as many cups of oats as sugar, and two times as many cups of flour as oats. If Duane puts in one cup of butter, how many cups of flour does he need to add? (also this is from MobyMax)

Answers

Answer:

Step-by-step explanation:

Let b represent the number of cups of butter needed.

Let s represent the number of cups of sugar needed.

Let o represent the number of cups of oat needed.

Let f represent the number of cups of flour needed.

The recipe calls for two times as many cups of sugar as butter. It means that

s = 2b

Two times as many cups of oats as sugar. It means that

o = 2s

Two times as many cups of flour as oats. It means that

f = 2o

If Duane puts in one cup of butter, it means that b = 1

Therefore,

s = 2 × 1 = 2 cups

o = 2s = 2 × 2 = 4 cups

f = 2o = 2 × 4 = 8 cups

Therefore, he needs to add 8 cups of flour

Answer: Let b represent the number of cups of butter needed. Let s represent the number of cups of sugar needed. Let o represent the number of cups of oat needed. Let f represent the number of cups of flour needed. The recipe calls for two times as many cups of sugar as butter. It means that s = 2bTwo times as many cups of oats as sugar. It means that o = 2sTwo times as many cups of flour as oats. It means that f = 2oIf Duane puts in one cup of butter, it means that b = 1Therefore, s = 2 × 1 = 2 cupso = 2s = 2 × 2 = 4 cupsf = 2o = 2 × 4 = 8 cups Therefore, he needs to add 8 cups of flour

Step-by-step explanation:

Match each pair of points A and B to point C such that ∠ABC = 90°. A(3, 3) and B(12, 6) C(6, 52) A(-10, 5) and B(12, 16) C(16, -6) A(-8, 3) and B(12, 8) C(18, 4) A(12, -14) and B(-16, 21) C(-11, 25) A(-12, -19) and B(20, 45) A(30, 20) and B(-20, -15) arrowBoth arrowBoth arrowBoth arrowBoth

Answers

Answer:

i) A = (3, 3), B = (12, 6), C = (6, 52) : Not orthogonal, ii) A = (-10, 5), B = (12, 16), C = (6, 52) : Not orthogonal, iii) A = (-8, 3), B = (12, 8), C = (18, 4) : Not orthogonal, iv) A = (12, -14), B = (-16, 21), C = (-11, 25) : Orthogonal, v) A = (-12, -19), B = (20, 45) : Impossible orthogonality, vi) A = (30, 20), B = (-20, -15) : Impossible orthogonality.

Step-by-step explanation:

The statement indicates that segments AB and BC must be orthogonal. Vectorially speaking, this can be expressed by using the following expression from Linear Algebra:

[tex]\overrightarrow {AB} \bullet \overrightarrow {BC} = 0[/tex]

[tex](AB_{x}, AB_{y})\bullet (BC_{x},BC_{y}) = 0[/tex]

[tex]AB_{x}\cdot BC_{x} + AB_{y}\cdot BC_{y} = 0[/tex]

Now, let is evaluate each choice:

i) A = (3, 3), B = (12, 6), C = (6, 52)

[tex]\overrightarrow {AB} = \vec B - \vec A[/tex]

[tex]\overrightarrow {AB} = (12, 6) - (3, 3)[/tex]

[tex]\overrightarrow {AB} = (12-3, 6-3)[/tex]

[tex]\overrightarrow {AB} = (9, 3)[/tex]

[tex]\overrightarrow {BC} = \vec C - \vec B[/tex]

[tex]\overrightarrow {BC} = (6, 52) - (12, 6)[/tex]

[tex]\overrightarrow {BC} = (6 - 12, 52 - 6)[/tex]

[tex]\overrightarrow {BC} = (-6, 46)[/tex]

[tex]\overrightarrow {AB} \bullet \overrightarrow {BC} = (9, 3)\bullet (-6, 46)[/tex]

[tex]\overrightarrow{AB} \bullet \overrightarrow {BC} = (9)\cdot (-6) + (3) \cdot (46)[/tex]

[tex]\overrightarrow{AB}\bullet \overrightarrow {BC} = 84[/tex]

AB and BC are not orthogonal.

ii) A = (-10, 5), B = (12, 16), C = (6, 52)

[tex]\overrightarrow {AB} = \vec B - \vec A[/tex]

[tex]\overrightarrow {AB} = (12, 16) - (-10, 5)[/tex]

[tex]\overrightarrow {AB} = (12+10, 16-5)[/tex]

[tex]\overrightarrow {AB} = (22, 11)[/tex]

[tex]\overrightarrow {BC} = \vec C - \vec B[/tex]

[tex]\overrightarrow {BC} = (6, 52) - (12, 16)[/tex]

[tex]\overrightarrow {BC} = (6 - 12, 52 - 16)[/tex]

[tex]\overrightarrow {BC} = (-6, 36)[/tex]

[tex]\overrightarrow {AB} \bullet \overrightarrow {BC} = (22, 11)\bullet (-6, 36)[/tex]

[tex]\overrightarrow{AB} \bullet \overrightarrow {BC} = (22)\cdot (-6) + (11) \cdot (36)[/tex]

[tex]\overrightarrow{AB}\bullet \overrightarrow {BC} = 264[/tex]

AB and BC are not orthogonal.

iii) A = (-8, 3), B = (12, 8), C = (18, 4)

[tex]\overrightarrow {AB} = \vec B - \vec A[/tex]

[tex]\overrightarrow {AB} = (12, 8) - (-8, 3)[/tex]

[tex]\overrightarrow {AB} = (12+8, 8-3)[/tex]

[tex]\overrightarrow {AB} = (20, 5)[/tex]

[tex]\overrightarrow {BC} = \vec C - \vec B[/tex]

[tex]\overrightarrow {BC} = (18, 4) - (12, 8)[/tex]

[tex]\overrightarrow {BC} = (18 - 12, 4 - 8)[/tex]

[tex]\overrightarrow {BC} = (6, -4)[/tex]

[tex]\overrightarrow {AB} \bullet \overrightarrow {BC} = (20, 5)\bullet (-6, -4)[/tex]

[tex]\overrightarrow{AB} \bullet \overrightarrow {BC} = (20)\cdot (-6) + (5) \cdot (-4)[/tex]

[tex]\overrightarrow{AB}\bullet \overrightarrow {BC} = -140[/tex]

AB and BC are not orthogonal.

iv) A = (12, -14), B = (-16, 21), C = (-11, 25)

[tex]\overrightarrow {AB} = \vec B - \vec A[/tex]

[tex]\overrightarrow {AB} = (-16,21) - (12, -14)[/tex]

[tex]\overrightarrow {AB} = (-16-12, 21+14)[/tex]

[tex]\overrightarrow {AB} = (-28, 35)[/tex]

[tex]\overrightarrow {BC} = \vec C - \vec B[/tex]

[tex]\overrightarrow {BC} = (-11,25) - (-16, 21)[/tex]

[tex]\overrightarrow {BC} = (-11+16, 25-21)[/tex]

[tex]\overrightarrow {BC} = (5, 4)[/tex]

[tex]\overrightarrow {AB} \bullet \overrightarrow {BC} = (-28,35)\bullet (5, 4)[/tex]

[tex]\overrightarrow{AB} \bullet \overrightarrow {BC} = (-28)\cdot (5) + (35) \cdot (4)[/tex]

[tex]\overrightarrow{AB}\bullet \overrightarrow {BC} = 0[/tex]

AB and BC are orthogonal.

v) A = (-12, -19), B = (20, 45)

It is not possible to determine the orthogonality of this solution, since point C is unknown.

vi) A = (30, 20), B = (-20, -15)

It is not possible to determine the orthogonality of this solution, since point C is unknown.

Need answers please !!!!

Answers

inital height is 2 meters

Step-by-step explanation:

Which steps can be used in order to determine the solution to Negative 1.3 + 4.6 x = 0.3 + 4 x?

Answers

Answer:

x=8/3 OR 2.7

Step-by-step explanation:

-1.3+4.6x=0.3+4x

4.6x-4x=0.3+1.3

0.6x=1.6

x=1.6/0.6=8/3

x=8/3 OR 2.7

Hope this helps!

Answer:

[tex]\boxed{x = 2\frac{2}{3} }[/tex]

Step-by-step explanation:

[tex]-1.3+4.6x = 0.3 +4x[/tex]

Collecting like terms

[tex]4.6 x -4x = 0.3+1.3[/tex]

[tex]0.6x = 1.6[/tex]

Dividing both sides by 0.6

x = 1.6 / 0.6

x = 2 2/3

Which presents a quadratic function

Answers

Answer:

The answer is option 2.

Step-by-step explanation:

Quadratic function is always written in the form of ax² + bx + c where the highest power of x is 2.

In the options above :

Option 1 is Cubic function.

Option 2 is Quadratic function.

Option 3 and 4 are Linear function.

Answer:

I guess....

Step-by-step explanation:

option 2............

4 to the 4th power equals 256. Explain how to use that fact to more quickly evaluate 4 to the 5th power.

Answers

Answer: Because 4 is the base of what is being exponentially multiplied, you can multiply 256 by 4 to get 4^5

Hi there! Hopefully this helps!

--------------------------------------------------------------------------------------------------------

So, we know that 4 to the 4th power equals 256.

4 to the 4th power = 4 x 4 x 4 x 4.

So we can add another 4 to the equation to quickly get out answer for 4 to the 5th power.

4 to the 5th power = 4 x 4 x 4 x 4 x 4 = 1024.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Or you could break the equation into parts.

For example, there are FOUR 4s in the equation.

4 x 4 = 16.

4 x 4 = 16.

16 x 16 = 256.

Now since we've added ANOTHER 4, it should look like this:

16 x 16 = 256.

256 x 4 = 1024.

Use the given categorical data to construct the relative frequency distribution. Natural births randomly selected from four hospitals in a highly populated region occurred on the days of the week​ (in the order of Monday through​ Sunday) with the frequencies 53​, 63​, 68​, 58​, 61​, 43​, 54. Does it appear that such births occur on the days of the week with equal​ frequency?

Answers

Answer: Yes

Step-by-step explanation:

See explanations in the attached document

What is the value of x in the equation 5 (4 x minus 10) + 10 x = 4 (2 x minus 3) + 2 (x minus 4)?

Answers

Answer:

x = 1.5

Step-by-step explanation:

5(4x-10)+10x=4(2x-3)+2(x-4)

Distribute(5)

20x-50+10x=4(2x-3)+2(x-4)

Distribute(4)

20x-50+10x=8x-12+2(x-4)

Distribute(2)

20x-50+10x=8x-12+2x-8

Combine like terms

30x-50=10x-20

Subtract(10x)

20x-50=-20

Add(50)

20x=30

Divide(20)

x = 1.5

Hope it helps <3

Answer:

x = 3/2

Step-by-step explanation:

5 ( 4x - 10) + 10x = 4(2x - 3) + 2(x - 4)

Expand the terms

That's

20x - 50 + 10x = 8x - 12 + 2x - 8

Simplify

30x - 50 = 10x - 20

Group the constants at the right side of the equation

That's

30x - 10x = - 20 + 50

20x = 30

Divide both sides by 20

x = 3/2

Hope this helps you

For the following telescoping​ series, find a formula for the nth term of the sequence of partial sums ​{Sn​}. Then evaluate Lim Sn to obtain the value of the series or state that the series diverges.
n→[infinity]
[infinity]
Σ (4/√k+5 ) - 4/ √ k+6)
k=1

Answers

Looks like the series is

[tex]\displaystyle\sum_{k=1}^\infty\left(\frac4{\sqrt{k+5}}-\frac4{\sqrt{k+6}}\right)[/tex]

This series has n-th partial sum

[tex]S_n=\displaystyle\sum_{k=1}^n\bullet[/tex]

(where [tex]\bullet[/tex] is used as a placeholder for the summand)

[tex]S_n=\displaystyle\left(\frac4{\sqrt6}-\frac4{\sqrt7}\right)+\left(\frac4{\sqrt7}-\frac4{\sqrt8}\right)+\cdots+\left(\frac4{\sqrt{n+4}}-\frac4{\sqrt{n+5}}\right)+\left(\frac4{\sqrt{n+5}}-\frac4{\sqrt{n+6}}\right)[/tex]

In each grouped term, the last term is annihilated by the first term of the next group; that is, for instance,

[tex]\displaystyle\left(\frac4{\sqrt6}-\frac4{\sqrt7}\right)+\left(\frac4{\sqrt7}-\frac4{\sqrt8}\right)=\frac4{\sqrt6}-\frac4{\sqrt8}[/tex]

Ultimately, all the middle terms will vanish and we're left with

[tex]S_n=\dfrac4{\sqrt6}-\dfrac4{\sqrt{n+6}}[/tex]

As [tex]n\to\infty[/tex], the last term converges to 0 and we're left with

[tex]\displaystyle\sum_{k=1}^\infty\bullet=\lim_{n\to\infty}S_n=\frac4{\sqrt6}=\boxed{2\sqrt{\dfrac23}}[/tex]

You are hiking and are trying to determine how far away the nearest cabin is, which happens to be due north from your current position. Your friend walks 245 yards due west from your position and takes a bearing on the cabin of N 22.6°E. How far are you from the cabin? answer asap and ill give you a pat on the back

Answers

Answer:

101.98 yards.

Step-by-step explanation:

Please refer to the diagram that I drew (sorry for the messiness; I do not own a stylus and so I was using my mouse to try to draw it).

Since the triangle is a right triangle, you can use SOH CAH TOA. In this case, you are trying to figure out the opposite length, but you are given the adjacent. So, we will use tangent to solve this (TOA = Tangent, Opposite over Adjacent).

The angle is 22.6 degrees, and the tangent of the angle is equivalent to the opposite length, x, divided by the adjacent length, 245 yards.

tan(22.6) = x / 245

x / 245 = tan(22.6)

x = tan(22.6) * 245

x = 0.4162598242 * 245

x = 101.9836569

So, you are about 101.98 yards from the cabin.

Hope this helps!

write an expression: A number squared
added to 16​

Answers

Answer:

16+x²

Step-by-step explanation:

Choose the correct answer.
1/1,000 liter

A: 1 milliliter
B: 1 deciliter
C: 1 centiliter

Answers

Answer:

A. 1 milliliter

Step-by-step explanation:

1000 milliliters = 1 liter

0.001 liters = 1 milliliter

As 1/1000 is 10^-3, if you remember the S.I prefixes, you will know that that is 1 mL

A basketball team plays half of its games during the day and half at night. Ten scores from day games and ten scores from night
games were randomly selected by the team's statistician. The following statistical information was calculated from the final game
scores.
Day Night
Mean 58 72
Median 46 63
Mode 50. 70
Range 21 33

Based on these samples, what generalization can be made?
A. The basketball team scored the same number of points in day games as night games.
OB. The basketball team scored more points in night games than in day games.
OC. The basketball team scored more points in day games than in night games.
OD. Not enough information is provided to draw any of these conclusions,

Answers

Option B

Because the average points scored in the night is more than that of the day

What is the density of a brownie the shape of a cube weighing 15 grams measuring 5 cm on a side?

Answers

Answer:

  0.12 g/cm³

Step-by-step explanation:

Density is the ratio of mass to volume. The volume of the brownie is the cube of its side dimension:

  V = s³ = (5 cm)³ = 125 cm³

Then the density is ...

  ρ = M/V = (15 g)/(125 cm³) = 0.12 g/cm³

The density of the brownie is 0.12 g/cm³.

One integer is
5 less than another. The sum of their squares is
157. Find the integers.

Answers

Answer:

[tex]\large \boxed{\sf \ \ 6 \ and \ 11 \ \ }[/tex]

Step-by-step explanation:

Hello,

Let's note a and b the two numbers.

a = b - 5

[tex]a^2+b^2=157[/tex]

We replace a in the second equation and we solve it

[tex](b-5)^2+b^2=157 \\ \\ \text{*** develop the expression ***} \\ \\b^2-10b+25+b^2=157 \\ \\ \text{*** subtract 157 from both sides ***} \\ \\2b^2-10b+25-157=2b^2-10b-132=0 \\ \\ \text{*** divide by 2 both sides ***} \\ \\b^2-5b-66=0[/tex]

It means that the sum of the two roots is 5 and the product is -66.

because

     [tex](x-\alpha )(x-\beta )=x^2-(\alpha +\beta )x+\alpha \beta \\ \\ \text{ where } \alpha \text{ and } \beta \text{ are the roots }[/tex]

And we can notice that 66 = 6 * 11 and 11 - 6 = 5

So let's factorise it !

    [tex]b^2-5b-66=0 \\ \\b^2+6b-11b-66=0 \\ \\b(b+6)-11(b+6)=0 \\ \\(b-11)(b+6) =0 \\ \\ b=11 \ or \ b=-6[/tex]

It means that the solutions are

(6,11) and (-6,-11)

I guess we are after positive numbers though.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

If 4 bushels of oats weigh 58 kg, how much do 6.5 bushels of oats weigh?

Answers

Answer:

94.25 kg I think

Step-by-step explanation:

58/4 =14.5 kg per bushel

6.5 x 14.5=94.25 kg

Answer:

94.25

Step-by-step explanation:

First you need to find the unit rate which is 58/4 which equals to 14.5 then you multiply by 6.5 to find 94.25

magazine provided results from a poll of adults who were asked to identify their favorite pie. Among the ​respondents, ​% chose chocolate​ pie, and the margin of error was given as percentage points. What values do ​, ​, ​n, E, and p​ represent? If the confidence level is ​%, what is the value of ​?

Answers

Complete Question

A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 ​respondents, 12 ​% chose chocolate​ pie, and the margin of error was given as plus or minus 5 percentage points.What values do ​ [tex]\r p , \ \r q[/tex], ​n, E, and p​ represent? If the confidence level is 90​%, what is the value of [tex]\alpha[/tex] ​?

Answer:

a

   [tex]\r p[/tex] is the sample proportion   [tex]\r p = 0.12[/tex]

   [tex]n[/tex] is the  sample size is  [tex]n = 500[/tex]

   [tex]E[/tex] is the  margin of error is [tex]E = 0.05[/tex]

   [tex]\r q[/tex] represents the proportion of those that did not chose chocolate​ pie i.e                        [tex]\r q = 1- \r p[/tex]

b

   [tex]\alpha = 10\%[/tex]

Step-by-step explanation:

Here

    [tex]\r p[/tex] is the sample proportion   [tex]\r p = 0.12[/tex]

   [tex]n[/tex] is the  sample size is  [tex]n = 500[/tex]

    [tex]\r q[/tex] represents the proportion of those that did not chose chocolate​ pie i.e  

      [tex]\r q = 1- \r p[/tex]

      [tex]\r q = 1- 0.12[/tex]

      [tex]\r q = 0.88[/tex]

     [tex]E[/tex] is the  margin of error is [tex]E = 0.05[/tex]

Generally [tex]\alpha[/tex] is the level of significance and it value is mathematically evaluated as

     [tex]\alpha = ( 100 - C )\%[/tex]

Where  [tex]C[/tex] is the confidence level which is given in this question as  [tex]C = 90 \%[/tex]

So  

    [tex]\alpha = ( 100 - 90 )\%[/tex]

    [tex]\alpha = 10\%[/tex]

Which graph shows a line with a slope of 0?

Answers

The graph D shows a line with slope zero.

Zero slope:Zero slope is perfectly flat as horizontal line.Since it is perfectly a horizontal line, it is also known as horizontal line.Here the x value and the y value both are independent.It is neither increasing nor decreasing.Formula used in zero slope/ horizontal line is given by y=c; where c is constant.

Since graph A, B and C doesn't make horizontal line, it is not a zero slope/ horizontal line.

Graph D is a horizontal line. It doesn't depend on any y value. It is neither increasing nor decreasing.

Therefore, graph D shows a line with a slope of zero.

Learn more about slope here:

https://brainly.com/question/3493733

#SPJ2

Since "a line has a slope of zero when it does not have any vertical rise. It will be a straight horizontal line." the answer is D

In order to determine the average price of hotel rooms in Atlanta, a sample of 64 hotels was selected. It was determined that the average price of the rooms in the sample was $112 with a standard deviation of $16. Use a 0.05 level of significance and determine whether or not the average room price is significantly different from $108.50.
Which form of the hypotheses should be used to test whether or not the average room price is significantly different from $108.50?
H0:
a. mu is greater than or equal to $108.50
b. mu is greater than $108.50
c. mu is less than $108.50mu is less than or equal to $108.50
d. mu is equal to $108.50mu is not equal to $108.50
Ha:
a. mu is greater than or equal to $108.50
b. mu is greater than $108.50mu is less than $108.50
c. mu is less than or equal to $108.50
d. mu is equal to $108.50mu is not equal to $108.50

Answers

Answer:

H0 :

a. mu is greater than or equal to $108.50

Ha:

c. mu is less than or equal to $108.50

Step-by-step explanation:

The correct order of the steps of a hypothesis test is given following  

1. Determine the null and alternative hypothesis.

2. Select a sample and compute the z - score for the sample mean.

3. Determine the probability at which you will conclude that the sample outcome is very unlikely.

4. Make a decision about the unknown population.

These steps are performed in the given sequence

In the given scenario the test is to identify whether the average room price significantly different from $108.50. We take null hypothesis as mu is greater or equal to $108.50.

Find the minimum sample size necessary to be 99% confident that the population mean is within 3 units of the sample mean given that the population standard deviation is 29. (a) What is the critical value that corresponds to the given level of confidence? Round your answer to two decimals, and remember that critical values are always positive.

Answers

Answer:

623

Step-by-step explanation:

Given that margin of error (E) = 3 unit, standard deviation (σ) = 29, sample size (n) = ?

a) The confidence (C) = 99% = 0.99

α = 1 - C = 1 - 0.99 = 0.01

α/2 = 0.01 / 2 = 0.005

From the normal distribution table, The z score of α/2 (0.005) is the critical value and it corresponds to the z score 0.495 (0.5 - 0.005) which is 2.58.

[tex]critical\ value = z_{\frac{\alpha}{2} }=z_{0.005}=2.58\\[/tex]

b) The margin of error (E) is given as:

[tex]E=z_{\frac{\alpha}{2} }*\frac{\sigma}{\sqrt{n} }\\\\\sqrt{n}= z_{\frac{\alpha}{2} }*\frac{\sigma}{E }\\ \\n=( z_{\frac{\alpha}{2} }*\frac{\sigma}{E })^2\\\\Substituting:\\\\n=(2.58*\frac{29}{3} )^2=622.0036\\\\\\n=623(to\ the \ next\ whole\ number)[/tex]

The minimum sample size (n) is 623

a 12- inch ruler is duvided into 3 parts. the large part is 3 times longer than the small. the meddium part is times longer than then small, the medium part is 2 times long as the smallest .how long is the smallest part?

Answers

Answer:

2 inches

Step-by-step explanation:

x= smallest

3x=largest

2x=medium

x+3x+2x=12

6x=12

x=2

so smallest is 2

largest is 6 (3x)

medium is 4 (2x)

2+6+4=12

Holly wants to save money for an emergency. Holly invests $500 in an account that pays an interest rate of 6.75% How many years will it take for the account to
reach $14,300? Round your answer to the
nearest hundredth.

Answers

Answer:

51.339

Step-by-step explanation:

Hello,

At the beginning Holly has $500

After one year

   he will get 500*(1+6.75%)=500*1.0675

After n year (n being real)

   he will get

   [tex]500\cdot1.0675^n[/tex]

and we are looking for n so that

   [tex]500\cdot1.0675^n=14,300\\<=> ln (500\cdot1.0675^n)=ln(14,300)\\<=>ln(500)+n\cdot ln(1.0675)=ln(14,300)\\<=> n= \dfrac{ln(14,300)-ln(500)}{ln(1.0675)}=51.338550...\\[/tex]

so we need 51.339 years

Hope this helps

What is the five-number summary for this data set?
12, 15, 17, 20, 22, 25, 27, 30, 33, 37
Assume the numbers in each answer choice are listed in this order: min, Q1,
median, Q3, max.

Answers

Answer: min = 12, Q1 =17,  median =23.5 , Q3 = 30, max = 37 .

Step-by-step explanation:

The five-number summary for this data set consists  of  min, Q1,

median, Q3, max.

Given data: 12, 15, 17, 20, 22, 25, 27, 30, 33, 37, which is already arranged in a order.

Minimum value = 12

Maximum value = 37

since , number of observations = 10 (even)

So , Median = Mean of middle most terms

Middle most terms = 22, 25

Median =[tex]\dfrac{22+25}{2}=23.5[/tex]

First quartile ([tex]Q_1[/tex])= Median of first half ( 12, 15, 17, 20, 22)

= middle most term

= 17

Third quartile ([tex]Q_3[/tex]) = Median of second half (25, 27, 30, 33, 37)

= middle most term

= 30

Hence, five-number summary for this data set :

min = 12, Q1 =17,  median =23.5 , Q3 = 30, max = 37 .

how yo calculate step by step 0.082×100​

Answers

Answer:

8.2

Step-by-step explanation:

When you calculate it by 100, there are two zeros, so you move two decimals to the right.

This makes 8.2, and 8.2 will be the answer.

Another example could be... 0.082✖️10.

In this case, there is 1 zero, so you move the decimal to the right once, making it 0.82.

Hope this helps!!!

Answer:

8.2

Step-by-step explanation:

When you calculate it by 100, there are two zeros, so you move two decimals to the right.

so you will get 8.2

hope it helps you

Identify which equations have one solution, infinitely many solutions, or no solution. No

Answers

Answer: all of them have one solutions

Step-by-step explanation:

The length of a rectangle is four times its width. If the perimeter of the rectangle is 50 yd, find its area

Answers

Answer:

100yd²

Step-by-step explanation:

length=4x

width=x

perimeter=2(l+w)

50=2(4x+x)

50=2(5x)=10x

50=10x

x=5yd

width=5yd

length=20yd

area=length×width

=20×5

=100yd²

Answer:

[tex]\boxed{\red{100 \: \: {yd} ^{2}}} [/tex]

Step-by-step explanation:

width = x

length = 4x

so,

perimeter of a rectangle

[tex] p= 2(l + w) \\ 50yd = 2(4x + x) \\ 50yd= 2(5x) \\ 50yd= 10x \\ \frac{50yd}{10} = \frac{10x}{10} \\ x = 5 \: \: yd[/tex]

So, in this rectangle,

width = 5 yd

length = 4x

= 4*5

= 20yd

Now, let's find the area of this rectangle

[tex]area = l \times w \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \times 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 100 {yd}^{2} [/tex]

2 x - 3 + 3x equals -28 what is the value of x

Answers

Answer:

[tex]x = -5[/tex]

Step-by-step explanation:

We can simplify this equation down until x is isolated.

[tex]2x - 3 + 3x = -28[/tex]

We can combine the like terms of x.

[tex]5x - 3 = -28[/tex]

Add 3 to both sides.

[tex]5x = -25[/tex]

Now we can divide both sides by 5.

[tex]x = -5[/tex].

So x = -5.

Hope this helped!

Answer:

x=-5

Step-by-step explanation:

first combine like terms

5x-3=-28

add on both sides

5x=-25

divide

x==-5

Consider a normal distribution with mean 21 and standard deviation 4. What is the probability a value selected at random from this distribution is greater than 21

Answers

Answer:

P [ Z > 21 ] = 0,5   or   P [ Z > 21 ] = 50 %

Step-by-step explanation:

Normal Distribution N(21;4)

The question here is what is the area of the bell shape curve. As 21 is a mean for this distribution is in the middle of the bell, so values bigger than 21 will have a probability of 0,5, and values smaller than 21 will have the same probability 0,5. We must remember that the whole area under the curve has an area of 1 ( or 100% )

3. Use the Counting Principle to find the probability.
rolling a 1 on each of 4 number cubes
329
324
1
24
1
1, 296​

Answers

Step-by-step explanation:

Each number cube has 6 possible values, so there are 6⁴ = 1296 possible permutations.  Only 1 of those permutations is all ones.  Therefore, the probability is 1/1296.

solve for the variable x^2 - 8 = -1 Show all work please

Answers

Answer:

x = ±sqrt(7)

Step-by-step explanation:

x^2 - 8 = -1

Add 8 to each side

x^2 - 8+8 = -1+8

x^2 = 7

Take the square root of each side

sqrt(x^2) = ±sqrt(7)

x = ±sqrt(7)

Other Questions
Use ____ references when you want different formulas to refer to the same cell. The compare_strings function is supposed to compare just the alphanumeric content of two strings, ignoring upper vs lower case and punctuation. But something is not working. Fill in the code to try to find the problems, then fix the problems.import redef compare_strings(string1, string2):#Convert both strings to lowercase#and remove leading and trailing blanksstring1 = string1.lower().strip()string2 = string2.lower().strip()#Ignore punctuationpunctuation = r"[.?!,;:-']"string1 = re.sub(punctuation, r"", string1)string2 = re.sub(punctuation, r"", string2)#DEBUG CODE GOES HEREprint(___)return string1 == string2print(compare_strings("Have a Great Day!", "Have a great day?")) # Trueprint(compare_strings("It's raining again.", "its raining, again")) # Trueprint(compare_strings("Learn to count: 1, 2, 3.", "Learn to count: one, two, three.")) # Falseprint(compare_strings("They found some body.", "They found somebody.")) # False which is another name for an orthodox view of historical event or period ? Before you start taking measurements though, well first make sure you understand the underlying concepts involved. By what method is each of the spheres charged? For the reaction C + 2H2 - CH2, how many moles of hydrogen are required to produce19.26 mol of methane, CHA?Select one:O a. 19.26O b. 38.52O c. 15.0O d. 24.7 Helppppp............ a system of linear equations is given by the tables. One of the tables is represented by the equation y= -1/3x + 7 the equation that represents the other equation y= x + the solution of the system is ( , ) [tex](5mn^3)^{3} [/tex] What class of organic product results when 1-heptyne is treated with a mixture of mercuric acetate (HgSO4) in aqueous sulfuric acid (H2O/H2SO4) A person with normal vision can focus on objects as close as a few centimeters from the eye up to objects infinitely far away. There exist, however, certain conditions under which the range of vision is not so extended. For example, a nearsighted person cannot focus on objects farther than a certain point (the far point), while a farsighted person cannot focus on objects closer than a certain point (the near point). Note that even though the presence of a near point is common to everyone, a farsighted person has a near point that is much farther from the eye than the near point of a person with normal vision.Both nearsightedness and farsightedness can be corrected with the use of glasses or contact lenses. In this case, the eye converges the light coming from the image formed by the corrective lens rather than from the object itself.Required:a. If a nearsighted person has a far point df that is 3.50 m from the eye, what is the focal length f1 of the contact lenses that the person would need to see an object at infinity clearly?b. If a farsighted person has a near point that is 0.600 m from the eye, what is the focal length f2 of the contact lenses that the person would need to be able to read a book held at 0.350 m from the person's eyes? SCREENSHOT OF MY QUESTION: What is the minimum magnitude of an electric field that balances the weight of a plasticsphere of mass 5.4 g that has been charged to -3.0 nC the product of two rational number is -10/9. If one of the number is -5/27 ,find the other. Which graph below shows the solutions for the linear inequality ys x-3?BDO A. GraphO B. Graph BO C. Graph D Find the area of the shape shown below. ead the excerpt from Loom and Spindle.That was a hard, cold winter; and for warmth's sake my mother and her four children all slept in one bed, two at the foot and three at the head,but her richer neighbor could not get the little daughter; and, contrary to all the modern notions about hygiene, we were a healthful and a robust brood. We all, except the baby, went to school every day, and Saturday afternoons I went to a charity school to learn to sew.Which characteristics of a memoir are present in the excerpt? Check all that apply.first-person narrationhistorical researchauthentic dialoguethe writers opinionsthe writers personal experiences Find 83 1 3 % of 384 please help I really need it Which class of macromolecules is not organized in repeating units of monomers? proteins lipids nucleic acids carbohydrates I'm very happy _____ in England. I really miss being there.A. to liveB. to have livedC. be livedD. to be living 9. Select the CORRECT statement below. The National Response Framework:A. Is an integrated set of guidance, concepts, processes, and tools that enable the whole community to meet the National PreparednessGoalB. Describes key roles and responsibilities for integrating capabilities across the whole community.C. Provides local, territorial, state, and Federal responders with specific operational plans for managing a wide range of incidentsD. Serves only federal agencies