The length of the component in the drawing is 2.125 centimeters.
How to find the length of the component represented in a CAD?To find the length of the component in the drawing, we convert the given length from feet to inches. Since 1 foot is equal to 12 inches, the actual length of 12.75 feet is equivalent to 12.75 x 12 = 153 inches.
Next, we apply the scale of the drawing, which is 1 cm: 60 in. This means that for every 60 inches in reality, the drawing represents it as 1 centimeter. To find the length in centimeters, we set up a proportion:
1 cm / 60 in = x cm / 153 in
Cross-multiplying and solving for x, we get:
x = (1 cm * 153 in) / 60 in = 2.55 cm
Rounding to three decimal places, the length of the component in the drawing is approximately 2.125 centimeters.
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The equation relates the sound level, , in decibels (dB), of a noise with an intensity of I to the smallest sound intensity that can be heard by the human ear, (approximately watts/meter2).
The maximum intensity of a car horn is approximately 0. 01 watts/meter2. Based on this information, which value is closest to the maximum sound level, in decibels, of a car horn?
.
100 dB
10 dB
1,000 dB
10,000 dB
The equation relates the sound level, in decibels (dB), of a noise with an intensity of I to the smallest sound intensity that can be heard by the human ear, which is approximately 1 x 10^-12 watts/meter2.
Using this equation and the given maximum intensity of a car horn (0.01 watts/meter2), we can find the maximum sound level in decibels:
Sound level = 10 log (0.01/1 x 10^-12)
Sound level = 10 log (1 x 10^10)
Sound level = 100 dB
Therefore, the value that is closest to the maximum sound level in decibels of a car horn is 100 dB.
; 3. Using the complex form, find the Fourier series of the function. (30%) 1, 2k – .25 < x < 2k +.25, k € Z. a. (15%), f (x) = 0, elsewhere S 1,0
The Fourier series Using the complex form of f(x) is
f(x) = 1/2 + ∑[n=1, ∞] [2*(-1)^(n+k)/(nπ)]*sin(nπx), 2k-0.25 < x < 2k+0.25
where k is an integer.
To find the Fourier series of the function f(x) over the interval [-1, 1], we first note that f(x) is periodic with period T = 0.5. We can then write f(x) as a Fourier series of the form
f(x) = a0/2 + ∑[n=1, ∞] (ancos(nπx) + bnsin(nπx))
where
a0 = (1/T) ∫[0,T] f(x) dx
an = (2/T) ∫[0,T] f(x)*cos(nπx) dx
bn = (2/T) ∫[0,T] f(x)*sin(nπx) dx
Since f(x) = 0 for x < -0.25 and x > 0.25, we only need to consider the interval [-0.25, 0.25]. We can break this interval into subintervals of length 0.5 centered at integer values k
[-0.25, 0.25] = [-0.25, 0.25] ∩ [1.5, 2.5] ∪ [-0.25, 0.25] ∩ [0.5, 1.5] ∪ ... ∪ [-0.25, 0.25] ∩ [-1.5, -0.5]
For each subinterval, the Fourier coefficients can be calculated as follows
a0 = (1/0.5) ∫[-0.25, 0.25] f(x) dx = 1/2
an = (2/0.5) ∫[-0.25, 0.25] f(x)*cos(nπx) dx = 0
bn = (2/0.5) ∫[-0.25, 0.25] f(x)sin(nπx) dx = 2(-1)^k/(nπ)
Therefore, the Fourier series of f(x) is
f(x) = 1/2 + ∑[n=1, ∞] [2*(-1)^(n+k)/(nπ)]*sin(nπx), 2k-0.25 < x < 2k+0.25
where k is an integer.
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The cost to produce x kilograms of whatchamacallits is given by the function C(x) = 50x + 1000 where Cix) is in hundreds of dollars. The revenue for the sale of x whatchamacallits is given by R(x) = 450x where R(x) is in hundreds of dollars. How many kilograms should be produced and sold to realize a maximum profit? What is that maximum profit?
The maximum profit will be realized by producing and selling 2.5 kilograms of whatchamacallits.
The maximum profit, in hundreds of dollars, will be $500.
To find the maximum profit, we need to first calculate the profit function P(x), which is the difference between the revenue and the cost functions:
P(x) = R(x) - C(x)
P(x) = 450x - (50x + 1000)
P(x) = 400x - 1000
To find the amount of kilograms that should be produced and sold to realize a maximum profit, we need to find the value of x that maximizes the profit function.
We can do this by taking the derivative of the profit function and setting it equal to zero:
P'(x) = 400
400 = 0
Since the derivative is a constant value, there is no critical point or inflection point. Therefore, the profit function is increasing at a constant rate, and the maximum profit will be achieved at the highest possible value of x.
To find that value, we can set the profit function equal to zero and solve for x:
P(x) = 400x - 1000 = 0
400x = 1000
x = 2.5
Therefore, the maximum profit will be realized by producing and selling 2.5 kilograms of whatchamacallits.
To find the maximum profit itself, we can substitute this value of x into the profit function:
P(2.5) = 400(2.5) - 1000 = 500
So the maximum profit, in hundreds of dollars, will be $500.
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+
ent will
A circle with center (7,3) and radius of 5 is graphed below with a square inscribed in
the circle.
+
Dillon says to write the equation of the tangent line you need the opposite-reciprocal
slope of the slope of the radius and Chelsey says you need to use the same slope as
the radius. Who is correct and why? Write the equation of the tangent line.
Part B: Find the perimeter of BCDE.
Part C: Find the area of BCDE.
Part D: Prove BCDE is a square.
Chelsey is correct that we use the same slope as the radius to write the equation of the tangent line, even though the slope of the radius is undefined at the points of tangency.
The perimeter will be 20 ✓2 units.
The area will be 50 units²
How to explain the informationChelsey is correct, and the reason is that a tangent line to a circle at a given point is always perpendicular to the radius of the circle at that point. This means that the slope of the tangent line and the slope of the radius at the point of tangency are negative reciprocals of each other.
Chelsey is correct that we use the same slope as the radius to write the equation of the tangent line.
The perimeter will be:
= 4 × BC
= 20 ✓2
The area will be:
= BC²
= (5✓2)²
= 50
It should be noted that BCDE is a square as EBC is 90°.
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Dos personas reciben a los carros que entran a un estacionamiento. La primera persona entrega un boleto verde cada dos carros que entran. La segunda persona entrega un boleto azul cada tres carros que entran. ¿Qué número ocupará en la fila el tercer carro que recibirá boletos de ambos colores?
Por lo tanto, el tercer carro que recibirá boletos de ambos colores ocupará la posición número 18 en la fila.
Hola, entiendo que quieres saber en qué posición de la fila se encontrará el tercer carro que recibirá boletos de ambos colores (verde y azul). Para esto, vamos a analizar la situación:
- La primera persona entrega un boleto verde cada 2 carros.
- La segunda persona entrega un boleto azul cada 3 carros.
Un carro que recibe boletos de ambos colores será aquel que ocupa una posición que es múltiplo común de 2 y 3. El mínimo común múltiplo (MCM) de 2 y 3 es 6. Por lo tanto, cada 6 carros, habrá uno que reciba boletos de ambos colores.
Para encontrar el tercer carro que recibirá boletos de ambos colores, simplemente multiplicamos el MCM (6) por la cantidad de carros que buscamos (3):
6 × 3 = 18
Por lo tanto, el tercer carro que recibirá boletos ición número 18 en la fila.
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A solid is made up of two identical cones, each with base diameter of 14cm and a slant height of 15cm. Find its Volume.
The volume of the solid made up of two identical cones is 1361.48 cm³.
To find the volume of a solid made up of two identical cones, we first need to calculate the volume of one cone and then multiply it by 2. The formula for the volume of a cone is V = (1/3)πr²h, where r is the radius and h is the height.
Given the base diameter of the cone is 14 cm, the radius (r) is half of the diameter, which is 7 cm. To find the height (h) of the cone, we can use the Pythagorean theorem since we have the slant height (15 cm) and radius.
Let h be the height, then:
h² + r² = (slant height)²
h² + 7² = 15²
h² + 49 = 225
h² = 176
h = √176 ≈ 13.27 cm
Now we can calculate the volume of one cone:
V = (1/3)π(7²)(13.27) ≈ 680.74 cm³
Since the solid is made up of two identical cones, we multiply the volume by 2:
Total volume = 2 × 680.74 cm³ ≈ 1361.48 cm³
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Use the coordinates to find the length of each side
Then find the perimeter. (Examples 1 and 2)
D(1, 2), E(1, 7), F(4, 7), G(4, 2)
In ΔRST, s = 990 inches, ∠S=8° and ∠T=60°. Find the area of ΔRST, to the nearest square inch
The area of ΔRST, to the nearest square inch is,
Area = 29,17,735.54 square inches
We have,
In ΔRST, s = 990 inches, ∠S=8° and ∠T=60°.
Apply sine rule formula,
sin S / s = sin T / t
sin 8° / 990 = sin 60° / t
0.14 / 990 = 0.87 / t
0.14t = 990 x 0.87
0.14t = 861.3
t = 6,152 inches
Here, ∠R = 180° - (8 + 60)°
∠R = 180 - 68
∠R = 112°
sin S / s = sin R / r
sin 8° / 990 = sin 112° / r
0.14 / 990 = 0.92 / r
0.14r = 0.92 x 990
0.14r = 910.8
r = 910.8 / 0.14
r = 6505 inches
We use the formula
Heron's formula = √s(s - a)(s - b)(s - c)
Where s = a + b + c/2
Solving for s
s = 990 + 6505 + 6,152 /2
s = 6823.5
Solving for the area of the triangle
= √6823.5 × (6823.5 - 990) × (6823.5 - 6,152) × (6823.5 - 6505)
= √6823.5 x 5833.5 x 671.5 x 318.5
= 29,17,735.54 square inches
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The function
models the DVD sales, in billions of dollars, from 1999 to 2017, where
is the number of years since 1999.
What is the average rate of change of DVD sales, in billion of dollars, per year for the period from 2001 to 2008? Round your answer to the nearest tenth, if necessary.
The average rate of change of DVD sales is 723.1 billion dollars.
How to determine average rate of change of DVD sales?The average rate of change of an equation can be determine by using the formula below:
average rate of change = (f(x₂)- f(x₁)) / [x₂- x₁]
From the given information of the DVD sales:
f(x) = -158.8x² + 2469.9x + 3010.5
x₁ = 2001 - 1999 = 2
x₂ = 2008 - 1999 = 9
average rate of change = ([-158.8(9)² + 2469.9(9) + 3010.5] - [-158.8(2)² + 2469.9(2) + 3010.5]) / (9-2)
= (12376.8 - 7315.1)/(7)
= 723.1 billion dollars
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Check image attached
Which is the most precise measurement?
4 yd., 9 ft., 638
6
3
8
ft., or 1518
15
1
8
yd.
The most precise measurement is the one with the smallest value, which is 9 ft.
To determine which is the most precise measurement among 4 yd., 9 ft., 638638 ft., or 15181518 yd., we first need to convert all the measurements to a common unit. Let's convert everything to feet:
1 yard = 3 feet
- 4 yd. = 4 (3 ft). = 12 ft.
- 9 ft. = 9 ft. (no conversion needed)
- 638638 ft. = 638638 ft. (no conversion needed)
- 15181518 yd. = 15181518 (3 ft.) = 45544554 ft.
Now that we have all the measurements in feet, we can compare them:
- 12 ft.
- 9 ft.
- 638638 ft.
- 45544554 ft.
The most precise measurement is the one with the smallest value, which is 9 ft.
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If P (6, 1), find the image
of P under the following rotation.
180° counterclockwise about the
origin
([?],
Enter the number that belongs in
the green box,
The image of point P (6, 1) under a 180° counterclockwise rotation about the origin is (-6, -1).
To find the image of point P (6, 1) under a 180° counterclockwise rotation about the origin, we can use the rotation formula for 2D coordinates.
The formula for rotating a point (x, y) counterclockwise by θ degrees about the origin is:
x' = x [tex]\times[/tex] cos(θ) - y [tex]\times[/tex] sin(θ)
y' = x [tex]\times[/tex] sin(θ) + y [tex]\times[/tex] cos(θ)
In this case, θ is 180°.
So, let's substitute the values of x and y from point P into the rotation formula:
x' = 6 [tex]\times[/tex] cos(180°) - 1 [tex]\times[/tex] sin(180°)
y' = 6 [tex]\times[/tex] sin(180°) + 1 [tex]\times[/tex] cos(180°)
Now, let's simplify these equations using the trigonometric values for 180°:
[tex]x' = 6 \times (-1) - 1 \times 0[/tex]
[tex]y' = 6 \times 0 + 1 \times (-1)[/tex]
Simplifying further:
x' = -6
y' = -1
Therefore, the image of point P (6, 1) under a 180° counterclockwise rotation about the origin is (-6, -1).
Please note that the rotation formula assumes angles are measured in radians.
However, for simplicity, we used degrees in this explanation.
The trigonometric functions (cos and sin) can be evaluated in radians using their corresponding values for 180°.
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Mean Mode 42 X X X X 43 X X X - 44 Median Range X X 45 X X 46 47 48
The mean, median, mode and the range of the data given is 44.21, 44, 44 and 3 respectively.
Given is a dot plot, we need to find the mean, median, mode and the range of the data shared.
So, the data is = 43, 43, 43, 43, 44, 44, 44, 44, 44, 45, 45, 45, 46, 46
So, mean = 43×4+44×5+45×3+46×2 / 14
= 619/14 = 44.21
Median = 44+44/2 = 44
Mode = 44
Range = 46-43 = 3
Hence, the mean, median, mode and the range of the data given is 44.21, 44, 44 and 3 respectively.
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Hudson Marine provides boats sales, service, and maintenance. Boat trailers are one of its top sales items. Suppose the quarterly sales values for the seven years of historical data are as follows. Do not round intermediate calculations. Year Quarter 1 Quarter 2 Quarter 3 Quarter 4 Total Yearly Sales 1 7 17 9 2 35 2 9 19 17 8 53 3 13 28 23 12 76 4 18 27 23 17 85 5 23 32 30 20 105 6 23 38 31 19 111 7 26 41 33 28 128
a. Compute the centered moving average values (first find Four-Quarter Moving Average) for this time series (to 3 decimals). Centered Moving Sales Average 1 6 t N 16 3 11 4 3 5 10 6 6 16 7 17 8 6 9 12 10 28 11 21 12 12 13 20 14 28 15 23 16 16 17 20 18 35 19 30 20 19 21 25 22 37 23 30 24 20 25 30 26 41 27 34 28 27
b. Compute the seasonal indexes for the four quarters (to 3 decimals). Quarter Adjusted Seasonal Index 1 2 3 4
c. When does Hudson Marine experience the largest seasonal effect? Hudson Marine experiences the largest seasonal increase in quarter The largest seasonal effect is the seasonal decrease in quarter
Hudson Marine experiences the largest seasonal effect in quarter 4.
How to calculate the four-quarter moving average values, the seasonal indexes, and the largest seasonal effect of Hudson Marine?a. The four-quarter moving average values can be calculated as follows:
Quarter 1: (7 + 9 + 13 + 18) / 4 = 11.75
Quarter 2: (17 + 19 + 28 + 27) / 4 = 22.75
Quarter 3: (9 + 17 + 23 + 23) / 4 = 18
Quarter 4: (2 + 8 + 12 + 17) / 4 = 9.75
Quarter 5: (17 + 8 + 12 + 20) / 4 = 14.25
Quarter 6: (53 + 23 + 17 + 19) / 4 = 28
Quarter 7: (76 + 85 + 105 + 111) / 4 = 94.25
The centered moving average values can be calculated by averaging the adjacent four-quarter moving averages:
Quarter 3: (11.75 + 22.75 + 18 + 9.75) / 4 = 15.06
Quarter 4: (22.75 + 18 + 9.75 + 14.25) / 4 = 16.19
Quarter 5: (18 + 9.75 + 14.25 + 28) / 4 = 17.75
Quarter 6: (9.75 + 14.25 + 28 + 94.25) / 4 = 36.31
Quarter 7: (14.25 + 28 + 94.25 + 28) / 4 = 41.38
Therefore, the centered moving average values are:
Quarter 3: 15.06
Quarter 4: 16.19
Quarter 5: 17.75
Quarter 6: 36.31
Quarter 7: 41.38
b. The seasonal indexes for the four quarters can be calculated by dividing the centered moving average values by the average of all the centered moving average values and then multiplying by 100:
Quarter 1: (15.06 / 20.31) x 100 = 74.18
Quarter 2: (16.19 / 20.31) x 100 = 79.79
Quarter 3: (17.75 / 20.31) x 100 = 87.40
Quarter 4: (36.31 / 20.31) x 100 = 178.63
Therefore, the seasonal indexes for the four quarters are:
Quarter 1: 74.18
Quarter 2: 79.79
Quarter 3: 87.40
Quarter 4: 178.63
c. Hudson Marine experiences the largest seasonal effect in quarter 4, with a seasonal index of 178.63. This means that the sales in quarter 4 are, on average, 178.63% higher than the average sales for all quarters.
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Ross Times, the student newspaper of Ross College, printed a "What do you think?" column feature asking: "Do you think that the college is doing enough to provide student parking?" Anyone could mail in a response or use the paper's Web site to respond. In all, 126 answers were received.
This is an example of:
(a) a voluntary response sample.
(b) a multistage sample.
(c) a simple random sample.
(d) a convenience sample.
(e) the placebo effect
The answer is (d) a convenience sample.
This is because the sample is not randomly selected from the population of all students at Ross College. Instead, it relies on individuals who are willing and available to respond to the question through the methods provided by the newspaper.
Therefore, the sample is more likely to be composed of individuals who feel strongly about the issue of student parking or who have had particularly positive or negative experiences with it, rather than being representative of the entire population of Ross College students.
In conclusion, the Ross Times student newspaper's feature column asking for opinions on the provision of student parking at Ross College represents a convenience sample of responses, and may not be representative of the entire population of Ross College students.
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a population of 100 individuals is undergoing exponential growth with a population doubling time of 1 year. what size will this population be in 2 years?
The size of the population of 100 individuals which are undergoing exponential growth is equal to 400.
Population is undergoing exponential growth,
Use the formula of exponential ,
Nt = N0 × e^(rt)
Where,
Nt is the population size at time t
N0 is the initial population size
e is the mathematical constant, approximately 2.71828
r is the growth rate
If the population doubling time is 1 year,
Use the following formula to calculate the growth rate,
r = log(2) / t
Where t is the doubling time,
log(2) is the natural logarithm of 2 = approximately 0.693.
⇒ r = log(2) / 1 year
= 0.693 / year
Plug in the values,
Nt = N0 × e^(rt)
⇒Nt = 100 × e^(0.693 × 2)
Population size in 't' = 2 years.
Nt = 100 × e^1.386
⇒Nt = 100 × 3.998
⇒Nt = 100 ×4.000
⇒ Nt = 400
Therefore, the population will be 400 individuals in 2 years if it continues to undergo exponential growth with a population doubling time of 1 year.
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Si un cateto de un triángulo rectángulo y la hipotenusa miden 5 y 13cm, respectivamente, ¿cuánto mide el otro cateto?
The measure of the other side of the right triangle is given as follows:
12 cm.
What is the Pythagorean Theorem?The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.
The theorem is expressed as follows:
c² = a² + b².
In which:
c is the length of the hypotenuse.a and b are the lengths of the other two sides (the legs) of the right-angled triangle.The parameters for this problem are given as follows:
Sides of 5 and x.Hypotenuse of 13.Hence the other side has the length given as follows:
5² + x² = 13²
25 + x² = 169
x² = 144
x = 12.
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Solve for x, t, r and round to the nearest hundredth
Answer:
x = 14°
t = 12.367 ~ 12.4
r = 2.999 ~ 3
Step-by-step explanation:
1st we can find x by sum theory which is the sum of all side equal to 180° .
x + 90° + 76° = 180 °
x + 166° = 180°
x= 180° - 166°
x = 14° ... So the unknown angle is 14°
and we also can solve hypotenus t and adjecent r by using sin amd cos respectively by angle 76° .
sin(76) = 12/t
sin(76) t = 12 ....... criss cross it
t = 12 / sin(76) ....... divided both side by sin(76)
t = 12.367 ~ 12.4 ....... result
And
cos(76) = r / 12.4
r = cos(76) × 12.4 .......criss cross
r = 2.999 ~ 3 ....... amswer and i approximate it
The scores on the last math quiz are summarized in the following frequency table:
Score
10
9
8
7
6
5
4
3
2
1
0
Frequency
6
7
5
3
2
1
1
0
0
0
0
The information is then put into the following histogram:
A histogram has score on the x-axis, and frequency on the y-axis. A score of 4 has a frequency of 1; 5, 1; 6, 2; 7, 3; 8, 5; 9, 7; 10, 6.
Calculate the mean, median, mode, and midrange of this quiz distribution and explain whether the distribution is skewed to the left or to the right.
a.
Mean = 9, median = 8.2, mode = 7, midrange = 9; skewed to the left.
b.
Mean = 8.2, median = 9, mode = 9, midrange = 7; skewed to the left.
c.
Mean = 8.2, median = 9, mode = 9, midrange = 7; skewed to the right.
d.
Mean = 9, median = 8.2, mode = 7, midrange = 9; skewed to the right.
Please select the best answer from the choices provided
The correct option regarding the data is B. Mean = 8.2, median = 9, mode = 9, midrange = 7; skewed to the left.
How to explain the dataA histogram has score on the x-axis, and frequency on the y-axis. A score of 4 has a frequency of 1; 5, 1; 6, 2; 7, 3; 8, 5; 9, 7; 10, 6.
It shtbe noted that Mean = 8.2, median = 9, mode = 9, midrange = 7; skewed to the left.
This statement describes a distribution with a mean equal to the median and a mode that is likely less than the mean and the median. The fact that the distribution is skewed to the left indicates that the tail of the distribution is longer on the left side, and that there may be some low outliers that are pulling the mean towards the left.
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An ant travels 33cm in walking completely around the edges of a rectangle. If the rectangle is twice as long as it is wide, how long is the shortest side?
Rectangle: w = 5.5cm, l = 11cm. Shortest side is width.
Escribe a cuáles de las bolsas anteriores corresponde la notación decimal aproximada a tres cifras
6.2 × 10⁴ in decimal notation is simply 62,000.
In scientific notation, a number is expressed as the product of a decimal number between 1 and 10 and a power of 10.
Now, let's talk about converting a number in scientific notation to decimal notation. Decimal notation simply means expressing a number in the standard way, using digits and a decimal point. To convert a number in scientific notation to decimal notation, we just need to evaluate the product of the decimal number and the power of 10.
In the case of 6.2 × 10⁴, the decimal number is 6.2, and the power of 10 is 4. To evaluate the product, we simply move the decimal point in 6.2 four places to the right, since the power of 10 is positive. This gives us:
6.2 × 10⁴ = 62,000
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Complete Question:
Convert to decimal notation: 6.2 × 10⁴
The value of the integral ∫ dx/√(1-2x^2) is
So the value of the integral ∫ dx/√(1-2x^2) over the interval [-1/√2, 1/√2] is (1/√2)π.
The value of the integral ∫ dx/√(1-2x^2) is given by:
∫ (1/√(1-2x^2)) dx = (1/2) * arcsin(√2 * x) + C
where C is the constant of integration.
The value of the integral ∫ dx/√(1-2x^2) is equal to the integral of the function 1/√(1-2x^2) with respect to x. This is an example of an integral that requires a trigonometric substitution to evaluate. Specifically, we can let x = sin(θ)/√2 and dx = cos(θ)/√2 dθ. Substituting these expressions into the integral yields:
∫ dx/√(1-2x^2) = ∫ (cos(θ)/√2) / √(1-2(sin(θ)/√2)^2) dθ
Simplifying the denominator gives:
√(1-2(sin(θ)/√2)^2) = √(1 - sin^2(θ)) = cos(θ)
Substituting this expression into the integral gives:
∫ dx/√(1-2x^2) = ∫ (cos(θ)/√2) / cos(θ) dθ = ∫ dθ/√2 = (1/√2)θ + C
To find the value of the integral, we need to substitute back in for x and evaluate at the limits of integration. If we are integrating over the interval [-1/√2, 1/√2], then:
(1/√2)θ evaluated from -π/4 to π/4 gives:
(1/√2)(π/4 + π/4) - (1/√2)(-π/4 - π/4) = (1/√2)π
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A tired frog is jumping across a pond. Her first jump will be her longest. She travels 300 cm. Her second jump carries her another 270 cm. How far will the frog travel before she cannot jump anymore?
S= 1560cm
S= 570cm
S= 2700cm
S= 3000cm
The frog will travel a total distance of 1650 cm before she cannot jump anymore. None of the options given are correct.
To find the total distance the frog will travel, we need to add up the distances of all her jumps. Given that her first jump is her longest at 300 cm and her second jump is 270 cm, we can assume that each subsequent jump is shorter than the one before it.
The difference between the first jump and the second jump is 30 cm. So let's assume that the common difference between each jump is 30 cm. So the frog takes a total of 10 jumps before she cannot jump anymore.
The total distance the frog will travel is:
300 + 270 + (240 + 210 + 180 + 150 + 120 + 90 + 60 + 30) = 1650 cm
So here none of the options are correct.
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The quantity of a substance can be modeled by the function Z(t) that satisfies the dᏃ differential equation dZ/dt = 1/20Z. One point on this function is Z(1) = 140. Based on this model, use a linear approximation to the graph of Z at = 1 to estimate the quantity of the substance at t = 1.2
The estimated quantity of the substance at t = 1.2 is approximately 140.018.
The given differential equation is: dZ/dt = 1/20Z
Separating variables and integrating, we have:
∫ Z dZ = ∫ 1/20 dt
1/2 Z^2 = 1/20 t + C
where C is the constant of integration.
Using the given initial condition Z(1) = 140, we can solve for C:
1/2 (140)^2 = 1/20 (1) + C
C = 9800 - 70 = 9730
So, the equation that models the quantity of the substance is:
1/2 Z^2 = 1/20 t + 9730
Now, we can use linear approximation to estimate the quantity of the substance at t = 1.2, based on the information at t = 1.
The linear approximation formula is:
L(x) = f(a) + f'(a) * (x - a)
where a is the known point and f'(a) is the derivative of the function at a.
In this case, a = 1, so we have:
Z(1.2) ≈ Z(1) + Z'(1) * (1.2 - 1)
To find Z'(1), we take the derivative of the function:
Z(t) = √(40t + 194600)
Z'(t) = (40/2) * (40t + 194600)^(-1/2) * 40
Z'(t) = 800/(40t + 194600)^(1/2)
So, at t = 1, we have:
Z'(1) = 800/(40(1) + 194600)^(1/2) ≈ 0.0898
Now, we can use the linear approximation formula to estimate Z(1.2):
Z(1.2) ≈ Z(1) + Z'(1) * (1.2 - 1)
Z(1.2) ≈ 140 + 0.0898 * 0.2
Z(1.2) ≈ 140.018
Therefore, based on this model, the estimated quantity of the substance at t = 1.2 is approximately 140.018.
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How much will 3. 75 kg of meat cost at ?190. 00 per kilogram?
a. ?71250 b. ?7. 125 0 c. ?712. 50 d. ?7125. 0
3.75 kg of meat will cost 712.50, The correct answer is option (c).To determine how much 3.75 kg of meat will cost at ?190.00 per kilogram, you'll need to perform a multiplication using the given weight and price per kilogram, we need to :
1. Identify the weight of the meat: 3.75 kg.
2. Identify the cost per kilogram: ?190.00.
3. Multiply the weight (3.75 kg) by the cost per kilogram (?190.00).
3.75 kg × ?190.00/kg = 712.50
So, 3.75 kg of meat will cost ?712.50, which corresponds to option (c) in your list of possible answers. Remember to always check your calculations and units when solving problems like this to ensure accuracy.
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If AB is tangent to circle P at B, find Measure of angle 1
To find the measure of angle 1 when AB is tangent to circle P at point B, we must consider some properties of tangents and circles.
A tangent line to a circle is a line that touches the circle at exactly one point, known as the point of tangency. In this case, line AB is tangent to circle P at point B. A crucial property of tangents is that they are perpendicular to the radius of the circle at the point of tangency. Therefore, the radius PB of circle P is perpendicular to tangent AB at point B.
Now, let's examine angle 1. If angle 1 is the angle formed by the tangent AB and the radius PB at point B, then it is a right angle due to the aforementioned property. In this case, the measure of angle 1 is 90 degrees.
However, if angle 1 is not directly formed by the tangent and radius, more information is needed to determine its measure. For example, if angle 1 is an angle inside the circle, you would need to know the measure of other angles or lengths of chords within the circle to calculate it.
In summary, if angle 1 is formed by tangent AB and radius PB at point B, its measure is 90 degrees because tangents are perpendicular to the radius at the point of tangency. If angle 1 is not formed by the tangent and radius, additional information is required to determine its measure.
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a consumer electronics company is comparing the brightness of two different types of picture tubes for use in its television sets. tube type a has mean brightness of 100 and standard deviation of 16, and tube type b has unknown mean brightness, but the standard deviation is assumed to be identical to that for type a. a random sample of tubes of each type is selected, and is computed. if equals or exceeds , the manufacturer would like to adopt type b for use. the observed difference is .
The probability that , Xb exceeds Xa , by 3.0 or more if ub and ua, are equal is 0.2537.
The probability of an occurrence is a figure that represents how likely it is that the event will take place. In terms of percentage notation, it is stated as a number between 0 and 1, or between 0% and 100%. The higher the likelihood, the more probable it is that the event will take place.
Probability is a way to gauge how likely something is to happen. Several things are difficult to forecast with absolute confidence. With it, we can only make predictions about the likelihood of an event happening, or how likely it is.
n1 = n2 = 25,
hypothesis,
standard error for difference,
[tex]\sqrt{\frac{16^2}{25} +\frac{16^2}{25} }[/tex]
=4.525
z =(3-0)/4.525
z=0.663
P(z ≥ 0.663) = 0.2537.
No, there is not strong evidence that [tex]\mu _B[/tex] is greater than [tex]\mu _A[/tex].
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Complete question;
A consumer electronics company is comparing the brightness of two different types of picture tubes for use in its television sets. Tube type A has mean brightness of 100 and standard deviation of 16, and tube type B has unknown mean brightness, but the standard deviation is assumed to be identical to that for type A. A random sample of n = 25 tubes of each type is selected, and X -X, is computed. If u, equals or exceeds u,, the manufacturer would like to adopt type B for use. The observed difference is X,X, - 3.0. a. What is the probability that , exceeds X, by 3.0 or more if ug and u, are equal? b. Is there strong evidence that ug is greater than u,?
The short leg of a triangle measures 17 and the long leg measures 32. What is the measure of the smaller acute angle of the triangle to the nearest tenth of a degree ? Draw a triangle to represent the problem. Be sure to show the trig equation you used when solving
The measure of the smaller acute angle of the triangle to the nearest tenth of a degree is 28.3 degrees.
Let's denote the smaller acute angle of the triangle as θ. We can use the tangent function to find the measure of this angle:
tan(θ) = opposite/adjacent
In this case, the opposite side is the length of the short leg (17) and the adjacent side is the length of the long leg (32). So we have:
tan(θ) = 17/32
Using a calculator, we can take the inverse tangent (tan^-1) of both sides to solve for θ:
θ = tan^-1(17/32) ≈ 28.3 degrees
So the measure of the smaller acute angle of the triangle is approximately 28.3 degrees.
Here's a diagram to illustrate the triangle:
/ l
/ l
17 / l opposite
/ l
/ θ l
/_______l
adjacent
32
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The two-way table shows the number of houses on the market in the castillos’ price range. a 6-column table has 4 rows. the first column has entries 1 bathroom, 2 bathrooms, 3 bathrooms, total. the second column is labeled 1 bedroom with entries 67, 0, 0, 67. the third column is labeled 2 bedrooms with entries 21, 6, 18, 45. the fourth column is labeled 3 bedrooms with entries 0, 24, 16, 40. the fifth column is labeled 4 bedrooms with entries 0, 0, 56, 56. the sixth column is labeled total with entries 88, 30, 90, 208. what is the probability that a randomly selected house with 2 bathrooms has 3 bedrooms? 0.2 0.4 0.6 0.8
The probability that a randomly selected house with 2 bathrooms has 3 is: 0.8.
So, the fourth option is correct.
We have given that,
The two-way table shows the number of houses on the market in the Castillos’ price range.
A 6-column table has 4 rows.
The first column has entries 1 bathroom, 2 bathrooms and 3 bathrooms, in total.
The second column is labeled 1 bedroom with entries 67, 0, 0, 67.
The third column is labeled 2 bedrooms with entries 21, 6, 18, 45.
We are only considering the houses that have 2 bathrooms.
There are a total of 30 of these houses.
Out of these 30, 24 have 3 bedrooms.
What is the formula for probability?
The probability of an event can only be between 0 and 1 and can also be written as a percentage.
This makes the probability 24/30, which is 0.8.
Therefore, the probability that a randomly selected house with 2 bathrooms has 3 is: 0.8.
So, the fourth option is correct.
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A study reports that in 20102010 the population of the United States was 308,745,538308,745,538 people and the land area was approximately 3,531,9053,531,905 square miles. Based on the study, what was the population density, in people per square mile, of the United States in 20102010? Round your answer to the nearest tenth.
The population density is 87.4, under the condition that a study report shows that in 2010 the population of the United States was counted to be 308,745,538 people and the land area is approximately 3,531,905 square miles.
Now to evaluate the population density of the United States in 2010, here we have to use the principles of division
Population density = Population / Land area
Staging the values from the study
Population density = 308,745,538 / 3,531,905
The evaluated Population density = 87.4 people per square mile
Then, the United State's population density in 2010 was evaluated as 87.4 people per square mile.
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The complete question is
A study reports that in 2010 the population of the United States was 308,745,538 people and the land area was approximately 3,531,905 square miles. Based on the study, what was the population density, in people per square mile, of the United States in 2010? Round your answer to the nearest tenth.
Find the missing side
17 cm
1319
a
area = 25 cm²
Answer:
a= 2.9cm
Step-by-step explanation:
area =25 so 17a=50
50/17=2.941176...