Beginning with model year 2008, what type of communication protocol is required for diagnostics?
Beginning with model year 2008, Controller Area Network (CAN) is required for diagnostics.
What is diagnostics?Diagnostics are defined as the process of identifying an injury, ailment, or disease based on the symptoms and signs a person is exhibiting. In order to confirm or rule out illnesses and diseases, diagnostic tests are utilized. Before creating a treatment plan, your doctor needs particular information from a diagnostic test to make an accurate diagnosis.
The robust automotive bus standard known as a Controller Area Network (CAN) enables microcontrollers and other devices to interact with each other's applications without the need for a host computer. Devices and CAN busses are frequently found in industrial and automotive systems. Bosch created the Controller Area Network (CAN) bus, which saw its debut in manufacturing in 1991.
Thus, beginning with model year 2008, Controller Area Network (CAN) is required for diagnostics.
To learn more about diagnostics, refer to the link below:
https://brainly.com/question/12814536
#SPJ2
Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers from 75 to 95 nanometers. What is the probability that the wavelengths of the next photosynthetically active radiations is at most 82 nanometer? Report to two digits after the decimal point.
The probability that the wavelengths of the next photosynthetically active radiations is at most 82 nanometer is 0.35.
What is photosynthetically active radiations?Photosynthetically active radiation (PAR) is light with wavelengths ranging from 400 to 700 nm that is used by plants for photosynthesis.
The photon flux density of photosynthetic photon flux density (PPFD) is defined as the photon flux density of PAR.
Photosynthesis and plant growth require Photosynthetically Active Radiation. Higher PAR promotes plant growth, and monitoring PAR is critical to ensure plants receive enough light for this process.
Given that,
a = 75
b =95
Using uniform distribution
P(x c) = (c - a) / (b - a)
P(x 82) = (82 - 75) / (95 - 75)=0.35
Probability=0.35
Thus, the probability of the given scenario is 0.35.
For more details regarding photosynthetically active radiations, visit:
https://brainly.com/question/10582848
#SPJ1
Air in a large tank at 300C and 400kPa, flows through a converging diverging nozzle with throat diameter 2cm. It exits smoothly at a Mach number 2.8. According to one-dimensional isentropic theory, what is
(a) exit diameter and
(b) mass flow?
Answer:
The answer is "[tex]3.74 \ cm\ \ and \ \ 0.186 \frac{kg}{s}[/tex]"
Explanation:
Given data:
Initial temperature of tank [tex]T_1 = 300^{\circ}\ C= 573 K[/tex]
Initial pressure of tank [tex]P_1= 400 \ kPa[/tex]
Diameter of throat [tex]d* = 2 \ cm[/tex]
Mach number at exit [tex]M = 2.8[/tex]
In point a:
calculating the throat area:
[tex]A*=\frac{\pi}{4} \times d^2[/tex]
[tex]=\frac{\pi}{4} \times 2^2\\\\=\frac{\pi}{4} \times 4\\\\=3.14 \ cm^2[/tex]
Since, the Mach number at throat is approximately half the Mach number at exit.
Calculate the Mach number at throat.
[tex]M*=\frac{M}{2}\\\\=\frac{2.8}{2}\\\\=1.4[/tex]
Calculate the exit area using isentropic flow equation.
[tex]\frac{A}{A*}= (\frac{\gamma -1}{2})^{\frac{\gamma +1}{2(\gamma -1)}} (\frac{1+\frac{\gamma -1}{2} M*^2}{M*})^{\frac{\gamma +1}{2(\gamma -1)}}[/tex]
Here: [tex]\gamma[/tex] is the specific heat ratio. Substitute the values in above equation.
[tex]\frac{A}{3.14}= (\frac{1.4-1}{2})^{-\frac{1.4+1}{2(1.4 -1)}} (\frac{1+\frac{1.4-1}{2} (1.4)^2}{1.4})^{\frac{1.4+1}{2(1.4-1)}} \\\\A=\frac{\pi}{4}d^2 \\\\10.99=\frac{\pi}{4}d^2 \\\\d = 3.74 \ cm[/tex]
exit diameter is 3.74 cm
In point b:
Calculate the temperature at throat.
[tex]\frac{T*}{T}=(1+\frac{\Gamma-1}{2} M*^2)^{-1}\\\\\frac{T*}{573}=(1+\frac{1.4-1}{2} (1.4)^2)^{-1}\\\\T*=411.41 \ K[/tex]
Calculate the velocity at exit.
[tex]V*=M*\sqrt{ \gamma R T*}[/tex]
Here: R is the gas constant.
[tex]V*=1.4 \times \sqrt{1.4 \times 287 \times 411.41}\\\\=569.21 \ \frac{m}{s}[/tex]
Calculate the density of air at inlet
[tex]\rho_1 =\frac{P_1}{RT_1}\\\\=\frac{400}{ 0.287 \times 573}\\\\=2.43\ \frac{kg}{m^3}[/tex]
Calculate the density of air at throat using isentropic flow equation.
[tex]\frac{\rho}{\rho_1}=(1+\frac{\Gamma -1}{2} M*^2)^{-\frac{1}{\Gamma -1}} \\\\\frac{\rho *}{2.43}=(1+\frac{1.4-1}{2} (1.4)*^2)^{-\frac{1}{1.4-1}} \\\\\rho*= 1.045 \ \frac{kg}{m^3}[/tex]
Calculate the mass flow rate.
[tex]m= \rho* \times A* \times V*\\\\= 1.045 \times 3.14 times 10^{-4} \times 569.21\\\\= 0.186 \frac{kg}{s}[/tex]
A series circuit has a 12-volt power source and two resistors of 1 ohm and 2 ohms respectively. How many amps will flow when
the circuit is closed?
Answer:
6 amps
Explanation:
current =v÷r
12v÷2 ohms= 6amps
A parallel-plate capacitor is disconnected from a battery, and the plates are pulled a small distance further apart. Do the following quantities increase, decrease, or stay the same?.
Answer: capacitance decreases as distance increases
Explanation: when the plates on the capacitor are being pulled what happens is it will decrease in capacitance so the charge will decrease in the capacitor and because the battery is pulled away and if the plate is fully charged the capacitance as the distance increases between the plates the capacitance drops and heres something else i found on it and the capacitance
Capacitance C∝d1 when plates of a capacitor are moved farther, the capacitance decreases. After disconnecting the battery, the charge on capacitor remains constant, therefore the energy stored by capacitor U (=2Cq), increases
I will give brainltest! Help please
Find two careers and explain why you would enjoy being in this career field.
Find two careers and explain why you would NOT enjoy being in this career field.
What is the correct order of energy conversions? * 1. Nuclear to thermal to mechanical to electrical 2. Thermal to mechanical to electrical to potential 3. Nuclear to thermal to mechanical to potential 4. Electrical to mechanical to thermal to nuclear
Answer: Nuclear to thermal to mechanical to electrical.
Explanation:
Nuclear energy is also referred to as atomic energy which will then lead to the generation of the thermal energy. It should be noted that the thermal energy is also referred to as the heat energy and this is due to the rise in temperature which results in the faster movement of atoms and their collision with one another.
This in turn, brings about the mechanical energy which is simply the energy caused by the motion and this in turn, also lead to electrical energy.
Therefore, the correct answer is Nuclear to thermal to mechanical to electrical.
The current flow in an NMOS transistor is due to one of the following:
(a) Electrons
(b) Holes
(c) Both
Answer:
(a) Electrons
Explanation:
When there is a current flow in a transistor of NMOS so it is because of electrons as in NMOS the current is flowing from drain to source. Since the flow of electrons is from source to drain. Also the current would be inverse direction for electrons flow
Therefore the option A is correct
hence, the other options are incorrect
If the total length of a measurement is 10 1/2" what is half of this length?
Answer:
13.335 CM (1 ft, 1.335 cm)
I am 80% sure this is the answer, but i am not too keen on math so if i am wrong let me know and i will try my best to fix it!
I hope this helped! Have a good day :]
helppppppp plssss Identifying job responsibilities for staff members is an example of which section of the project charter?
project requirements
project objectives
project team
project description
Задание3 Напишите развернутый ответ на вопрос: «Почему непобедим тот народ, у которого «память корнями уходит в века?» (5-6 предложений)
What is the height of a W250 x 24? (answer in mm)
Using benefit-cost ratio analysis, determine which one of the three mutually exclusive alternatives should be selected. Each alternative has a 10-year useful life and 20% MARR 247 А в с First Cost $120 $340 $560 $760 Uniform Annual Beneft $40 $100 $140 $170 $0 $0 Salvage Value $40 $50 СА B Stop sharing app honorocos sharing your screen
Which of the following machine parts always require
guards?
Select the 3 answer options that apply.
Fan blades
Levers
Rotating barrels
Abrasive wheel machinery
Answer:fan blades, rotating , abrasive wheel machinery
Explanation:
A Pelton wheel is supplied with water from a lake at an elevation H above the turbine. The penstock that supplies the water to the wheel is of length , diameter D, and friction factor f. Minor losses are negligible. Show that the power developed by the turbine is maximum when the velocity head at the nozzle exit is 2H/3. Note: The result of Problem 12.61 may be of use.
Answer:
Following are the proving to this question:
Explanation:
[tex]\frac{D_1}{D} = \frac{1}{(2f(\frac{l}{D}))^{\frac{1}{4}}}[/tex]
using the energy equation for entry and exit value :
[tex]\to \frac{p_o}{y} +\frac{V^{2}_{o}}{2g}+Z_0 = \frac{p_1}{y} +\frac{V^{2}_{1}}{2g}+Z_1+ f \frac{l}{D}\frac{V^{2}}{2g}[/tex]
where
[tex]\to p_0=p_1=0\\\\\to Z_0=Z_1=H\\\\\to v_0=0\\\\AV =A_1V_1 \\\\\to V=(\frac{D_1}{D})^2 V_1\\\\\to V^2=(\frac{D_1}{D})^4 V^{2}_{1}[/tex]
[tex]= (\frac{1}{(2f (\frac{l}{D} ))^{\frac{1}{4}}})^4\ V^{2}_{1}\\\\[/tex]
[tex]= \frac{1}{(2f (\frac{l}{D}) )} \ V^{2}_{1}\\[/tex]
[tex]\to \frac{p_o}{y} +\frac{V^{2}_{o}}{2g}+Z_0 =\frac{p_1}{y} +\frac{V^{2}_{1}}{2g}+Z_1+ f \frac{l}{D}\frac{V^{2}}{2g} \\\\[/tex]
[tex]\to 0+0+Z_0 = 0 +\frac{V^{2}_{1} }{2g} +Z_1+ f \frac{l}{D} \frac{\frac{1}{(2f(\frac{l}{D}))}\ V^{2}_{1}}{2g} \\\\\to Z_0 -Z_1 = +\frac{V^{2}_{1}}{2g} \ (1+f\frac{l}{D}\frac{1}{(2f(\frac{l}{D}) )} ) \\\\\to H= \frac{V^{2}_{1}}{2g} (\frac{3}{2}) \\\\\to \frac{V^{2}_{1}}{2g} = H(\frac{3}{2})[/tex]
L.H.S = R.H.S
Statement 1: All balls hit the ground at the same time. Statement 2: All balls hit the ground with the same force. Statement 3: The bowling ball hit the ground first and the tennis golf ball hit the ground last. Statement 4: It is not possible to tell how much force each ball hit the ground with. Which statements must be TRUE regarding the rate of force of each falling object. Neglect air resistance.
Answer:
Statement 1: All balls hit the ground at the same time
Explanation:
When there is no resistance of air, the acceleration due to gravity experienced by all the bodies are same. So for falling bodies, neglecting the air resistance, the falling object will be weightless and therefore all the objects will hit the ground at the same time when there is nor air resistance and the objects are considered to be falling in vacuum.
g Clay sized particles in a river are likely to be transported as _______________________, whereas gravel sized particles are likely to be transported as _____________________. Group of answer choices suspended load; dissolved load suspended load; bed load dissolved load; suspended load dissolved load; bed load
Answer:
suspended load; bed load
Explanation:
Suspended load is those particles in a river that are transported and float between and around the middle and top of the river, they often change the color of the river through their suspension such as clay.
Bed load is those particles in a river that are transported at the river bed or floor. This is as a result of their weight. Examples are relatively big stones.
Hence, in this case, Clay sized particles in a river are likely to be transported as SUSPENDED LOAD whereas gravel-sized particles are likely to be transported as BED LOAD
Help please!
Find two careers and explain why you would enjoy being in this career field.
Find two careers and explain why you would NOT enjoy being in this career field.
Note: You should have at least TWO paragraphs
Match List
Match the engineering specialty with its job responsibility. Drag and drop the specialties to the responsibilities.
Construction
Geotechnical
Structural
Transportation
:: Ansure on-site work meets federal and state regulations
W
:: Areate efficient highway designs
Answer:
d
Explanation:
What is the formula for Measurement System Subject.
Answer:
You can see there are four different types of measurement scales (nominal, ordinal, interval and ratio).
Some Important Formulas:
Area of the rectangle, A = L \times B.Area of the square, A =Side ^2.Perimeter of a rectangle, P = 2 \times ( L+B )Perimeter of square, P = 4 \times Side.Area of the triangle, A = \frac{1}{2} \times Base \times Height.Circumference of a Circle, C = 2 \times \pi \times r.Hope this helps!
Don't forget to mark me as Brainliest.
car people i need some advice
what should be my first super car
Answer:
The first one.
Explanation:
The first one without a doubt
this is perfect.........
Which design activity is part of the design for manufacturability (DFM) methodology?
Aavold parts that are mirror Images
B. establish guidelines on the go
с. some asymmetrical parts are acceptable
D.
maximize utilization of setup time
Answer:
D would be correct because it maximizes it.
WHICH TASK BEST FITS THE ROLE OF A DESIGN ENGINEER ?
Answer: drafting blueprints
Explanation:
2.) A fluid moves in a steady manner between two sections in a flow
line. At section 1: A2 = 10 ft?, V = 100 fpm, vl = 4 ftp/lb
At section 2: A2 = 2 ft², P2 = 0.20 lb/ft?
Calculate (a.) the mass flow rate, and
(b.) the speed at section 2
Answer:
[tex]250\ \text{lbm/min}[/tex]
[tex]625\ \text{ft/min}[/tex]
Explanation:
[tex]A_1[/tex] = Area of section 1 = [tex]10\ \text{ft}^2[/tex]
[tex]V_1[/tex] = Velocity of water at section 1 = 100 ft/min
[tex]v_1[/tex] = Specific volume at section 1 = [tex]4\ \text{ft}^3/\text{lbm}[/tex]
[tex]\rho[/tex] = Density of fluid = [tex]0.2\ \text{lb/ft}^3[/tex]
[tex]A_2[/tex] = Area of section 2 = [tex]2\ \text{ft}^2[/tex]
Mass flow rate is given by
[tex]m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}[/tex]
The mass flow rate through the pipe is [tex]250\ \text{lbm/min}[/tex]
As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1
[tex]m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}[/tex]
The speed at section 2 is [tex]625\ \text{ft/min}[/tex].
(a) The mass flow rate will be "250 lbm/min".
(b) At section 2, the speed will be "625 ft/min".
Speed and MassAccording to the question,
Section 1 area, A₁ = 10 ft²
Section 2 area, A₂ = 2 ft²
Water's velocity, V₁ = 100 ft/min
Volume at section 1, v₁ = 4 ft³/lbm
(a) We know the formula,
Mass flow rate, m = ρA₁V₁
= [tex]\frac{A_1 V_1}{v_1}[/tex]
By substituting the values,
= [tex]\frac{10\times 100}{4}[/tex]
= [tex]\frac{1000}{4}[/tex]
= 250 lbm/min
(2) The speed will be:
→ m = ρA₂V₂
or,
V₂ = [tex]\frac{m}{\rho A_2}[/tex]
By substituting the values,
= [tex]\frac{250}{0.2\times 2}[/tex]
= [tex]\frac{200}{0.4}[/tex]
= 625 ft/min
Thus the responses above are correct.
Find out more information about speed here:
https://brainly.com/question/4931057
a homeowner consumes 700 kwh of energy in march. determine the average cost per kwh for the month using the following residential rate schedule: base monthly charge of $10.00. first 100 kwh per month at 16 cents/kwh. next 200 kwh per month at 10 cents/kwh. over 300 kwh per month at 6 cents/kwh.
Answer:
10 cents/kwh
Explanation:
Base monthly charge = $10.00
First 100 kwh at $0.16/kwh = $16.00
Next 200 kwh at $0.10/kwh = $20.00
Remaining 400 kwh at $0.06/kwh = $24.00
Total charge = $10 + $16 + $20 + $24 /(100+200+400)
Average cost = $70/700 or 10 cents/kwh
try to calculate the arc-elasticity percentage change from 80 to 100. input your answer in percent form.
A percentage increase from 80 to 100 is equal to 25%.
What is a percentage?A percentage can be defined as any number that is expressed as a fraction of hundred (100). This ultimately implies that, a percentage indicates the hundredth parts of any given number.
The types of percentage.In Mathematics, there are two main types of percentage and these include the following:
Percentage decreasePercentage increaseMathematically, percentage increase can be calculated by using this formula:
Percentage increase = [Final value - Initial value]/Initial value × 100
Substituting the given parameters into the formula, we have;
Percentage increase = [100 - 80]/80 × 100
Percentage increase = [20]/80 × 100
Percentage increase = 1/4 × 100
Percentage increase = 25%.
Read more on percentage increase here: brainly.com/question/11360390
#SPJ1
What is the safe psi pressure for acetylene
Answer:
15psig
Explanation:
Technician A says the drivetrain on a vehicle includes the steering wheel. Technician B says the drivetrain on a vehicle includes the axles and wheels. Who is correct?
Based on the information provided, Technician B is correct because the drivetrain on a vehicle includes the axles and wheels.
Who is an automotive engineer?An automotive engineer can be defined as a professional who has completed and acquired his or her bachelor's degree in mechanical engineering and has been trained on how to create designs for new automobile vehicles (cars), test prototypes, troubleshoots problems that arise, and oversees the manufacturing process.
What is a drivetrain?A drivetrain can be defined as the group of components or mechanical system that are fitted in automobile vehicles, which is designed and developed to connect the transmission to the drive axles such as:
Universal jointDriveshaft.Axles and wheelsIn this context, we can reasonably infer and logically deduce that Technician B is correct because the drivetrain on a vehicle includes the axles and wheels.
Read more on drivetrain here: https://brainly.com/question/24083630
#SPJ1
Calculate the fraction of lattice sites that are Schottky defects for cesium chloride at 573 oC (this temperature is below the melting temperature (645oC)). Assume an energy for defect formation of 1.86 eV.
Answer:
[tex]2.9\times 10^{-6}[/tex]
Explanation:
[tex]Q_s[/tex] = Energy for defect formation = 1.86 eV
T = Temperature = [tex]573^{\circ}\text{C}=573+273.15=846.15\ \text{K}[/tex]
k = Boltzmann constant = [tex]8.62\times 10^{-5}\ \text{eV/K}[/tex]
The fraction of lattice sites that are Schottky defects is given by
[tex]\dfrac{N_s}{N}=e^{-\dfrac{Q_s}{2kt}}\\\Rightarrow \dfrac{N_s}{N}=e^{-\dfrac{1.86}{2\times 8.62\times 10^{-5}\times 846.15}}\\\Rightarrow \dfrac{N_s}{N}=2.9\times 10^{-6}[/tex]
The required ratio is [tex]2.9\times 10^{-6}[/tex].
An engine cranks slowly. Technician A says a possible cause of the problem is low resistance in the starter circuit connections. Technician B says a possible cause is an open in the starter field coil circuit. Who is correct?
Answer:
The answer is "Neither".
Explanation:
Engine cranking implies that certain energy is applied to both the starter motor to motivate the engine only with one function: crank the wind-shaft of the engine and create an appropriate compressor in at most one piston for a good activation.
In this question, both Technician was wrong because the pressure motor oil is being used, a motor can crank very slowly or can't start throughout the cold weather.