an attempt to estimate the height of a tree the Shadow of an upright metre rule was found to be 25 cm and the length of the Shadow of the tree was 7 m what is the height of the tree​

Answers

Answer 1

Answer:

The actual height of the tree is 28 m

Explanation:

The given information are;

The length of the shadow of an upright meter rule = 25 cm

The actual height of the meter rule = 100 cm

The length of the shadow of the tree = 7 m

The actual  height of the tree  = h

We have

[tex]\dfrac{The \ length \ of \ the \ shadow \ of \ an \ upright \ metre \ rule}{The \ actual \ height \ of \ the \ metre \ rule} = \dfrac{The \ length \ of \ the \ shadow \ of \ the \ tree}{The \ actual \ height \ of \ the \ tree}[/tex]Which gives;

[tex]\dfrac{25 \ cm}{100 \ cm} = \dfrac{7 \ m}{The \ actual \ height \ of \ the \ tree}[/tex]

Therefore;

[tex]The \ actual \ height \ of \ the \ tree = 7 \ m \times \dfrac{100 \ cm}{25\ cm} = 7 \ m \times 4 = 28 \ m[/tex]

That is the actual height of the tree = 28 m.


Related Questions

What must be the tension of a string 202 cm long and 3 x 10-2 Kg / m per unit length (µ) for it to emit a sound of 78 Hz?

Answers

Answer:

2980 N

Explanation:

The fundamental frequency of a string is:

f₁ = √(T/µ) / (2L)

78 Hz = √(T / (0.03 kg/m)) / (2 (2.02 m))

315.12 m/s = √(T / (0.03 kg/m))

99,300 m²/s² = T / (0.03 kg/m)

T = 2980 N

Ionic compounds _____.

Answers

Explanation:

Are the compounds formed by the ionic bonding or electronic bonding. They are formed by transferring the electron form one element's valance shell to other element's shell.

i hope it helps...

A 500 kg car starts with a force of 1000 N

1) Calculate the acceleration with which the car starts.
2) Determine the speed of the car 15 seconds after starting if we know what part of the rest

Answers

Answer:

2 m/s²

30 m/s

Explanation:

1) F = ma

1000 N = (500 kg) a

a = 2 m/s²

2) Given:

v₀ = 0 m/s

a = 2 m/s²

t = 15 s

Find: v

v = at + v₀

v = (2 m/s²) (15 s) + 0 m/s

v = 30 m/s

How much heat is required to convert 500g of liquid water at 28°C into steam at 150 °C? Take the specific heat capacity of water to be 4183 J/Kg °C and the latent heat of vaporization to be 2.26 × 10^6 J/Kg.

Answers

Answer:

Q = 1.404 × 10^(5) KJ

Explanation:

We are given:

Mass;m = 500 g = 0.5kg

Temperature 1;T1 = 28 °C

Temperature:T2 = 150 °C

Specific heat capacity;c_p = 4183 J/Kg °C

Latent heat of vaporization;L = 2.26 × 10^(6) J/Kg.

The heat energy needed is given by;

Q = sensible heat energy + Latent heat

Formula for sensible heat is;

Sensible heat energy = mc(t2 - t1)

Formula for Latent heat is ;

Latent heat = mL

Thus:

Q = mc(t2 - t1) + mL

Q = m[c(t2 - t1) + L]

Q = 0.5((4183(159 - 28) + (2.26 × 10^(6)))

Q = 1.404 × 10^(8) J = 1.404 × 10^(5) KJ


In your own words, discuss how energy conservation applies to a pendulum.
.
Where is the potential energy the most?
Where is the potential energy the least?
• Where is kinetic energy the most?
• Where is kinetic energy the least?

Answers

Answer:

when x=0 kinetic energy is maximum and potential energy is high

when it is in mean position the potential energy is maximum and vise versa

Explanation:

And x=0 when the pendulum is at highest point when moving like velocity become zero when ball reached highest point

mean position is the point when pendulum comes back to original position  

I hope u understand

HELP me pleaseeee somebody

an object is placed 30cm from a mirror of focal length 15 cm the object is 7.5cm tall. where is the image located? how tall is the image??

Answers

Explanation:

It is given that,

Object distance from the mirror, u = -30 cm

Focal length of the mirror, f = +15 cm

Size of the object, h = 7.5 cm

We need to find the image distance and the size of the image.

Mirror's formula, [tex]\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex]

v is image distance

[tex]\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(15)}-\dfrac{1}{(-30)}\\\\v=10\ cm[/tex]

Let h' is the size of the image. So,

[tex]\dfrac{h'}{h}=\dfrac{-v}{u}\\\\h'=\dfrac{-vh}{u}\\\\h'=\dfrac{-10\times 7.5}{-30}\\\\h'=2.5\ cm[/tex]

So, the image is located at a distance of 10 cm and the size of the image is 2.5 cm.

Find the mass. 10 points. Will give brainliest.

Answers

Answer:

3.94 kg

Explanation:

Given,

Force ( f ) = 30 N

Acceleration(a) = 7.6 m/s

Now, Let's find the mass of the ball

Using the Newton's second law of motion:

We get:

[tex]force \: = mass \: \times acceleration[/tex]

plug the value

[tex]30 \: = m \: \times 7.6[/tex]

Use the commutative property to reorder the terms

[tex] 30 = 7.6 \: m[/tex]

Swap the sides of the equation

[tex]7.6m = 30[/tex]

Divide both sides of the equation by 7.6

[tex] \frac{7.6 \: m}{7.6} = \frac{30}{7.6} [/tex]

Calculate

[tex]m = 3.94 \: kg[/tex]

Hope this helps..

Best regards!!

Answer:

[tex]\displaystyle \boxed{\mathrm{3.95 \: kg }}[/tex]

Explanation:

[tex]\mathrm{force \: (N) = mass \: (kg) \times acceleration \: (m/s^2)}[/tex]

[tex]\mathrm{force = 30N}[/tex]

[tex]\mathrm{acceleration = 7.6 \: m/s^2 }[/tex]

[tex]\mathrm{Find \: the \: mass.}[/tex]

[tex]\mathrm{30 = m \times 7.6}[/tex]

[tex]\displaystyle \mathrm{m =\frac{30}{7.6} }[/tex]

[tex]\displaystyle \mathrm{m = 3.947... }[/tex]

Explain the method to measure the external diameter of a sphere​

Answers

Answer:

Sphere is a geometrical object in dimensional space  that surface of a circle and ball.

Explanation:

Sphere is that the circular objects in the two dimensional space (1) circle

(2) disk. Two dimensional space is a set of points and the distance of that point,The two points of Sphere that length and center.

Sphere can constructed as the named of surface form circle about  any diameter. circle is the special type of the revolution replacing the circle,

sphere is the distance r is the radius of the ball and circle  is the center of mathematical ball,as the center and the radius of the sphere is to respectively.

The ball and sphere has not be maintained mathematical references  as a solid references. A sphere of any radius is centered at the number of zero.

In a Little League baseball game, the 145 g ball reaches the batter with a speed of 15.0 m/s. The batter hits the ball, and it leaves his bat with a speed of 20.0 m/s in exactly the opposite direction. What is the magnitude of the impulse delivered by the bat to the ball

Answers

Answer: 5.075Ns

Explanation:

Given the following :

Mass of ball = 145g

Initial Speed of ball = 15m/s

Final speed of ball when hit by the batter = - 20m/s ( Opposite direction)

The impulse of a body is represented using the relation:

Force(f) * time(t) = mass (m) * (final Velocity(V) - initial velocity(u))

Therefore, using:

m(v - u) = impulse

Mass of ball = 145 / 1000 = 0.145kg

Impulse = 0.145(- 20 - 15)

Impulse = 0.145(-35)

Impulse = 5.075Ns

Iron man wears an awesome ironsuit.He is flying over high current carrying wire. Will he be affected?

Answers

Answer:

According to super hero logic , nothing will happen to him.

But according to science , yes he will get current shock but good news is that he wouldn't get elected until he is in contact with the wires.

He may / may not be affected but his suit will be damaged for sure as it is made of metal.

HOPE THIS HLEP AND PLSSSSS MARK AS BRAINLIEST AND THNXX :)

In this video, we see that a _____ magnetic field can create an electric current. In this video, we see that a _____ magnetic field can create an electric current. Changing Perpendicular Strong Dipole

Answers

Answer:

The correct option is (a) "Changing".

Explanation:

If a coil is placed in the magnetic field, due to the change in its magnetic flux an emf will induce in it. EMF is like voltage. So, due to the induced emf and current is induced in it. Hence, we can say that changing the magnetic field can create an electric current.

A catapult is usedto fire an object into the air describe the energy transfers when the catapult is released and stretched

Answers

Explanation:

potential energy ===> kinetic energy

when an object is stretched there will be a stored energy in it enough to react to the upcoming change

that is the potential energy

similar to a stretched elastic band

kinetic energy is the energy on a moving object

*If a kinetic energy takes place there must gave been a potential energy before*

A catapult is used to fire an object into the air, the potential energy transfers as the elastic potential energy and to the kinetic energy when the catapult is released and stretched.

What is the energy conversion taken place in Catapult?

The potential energy is associated with bodies that are above a reference point, at that reference point the value of potential energy is taken as zero. For example, if an object with a mass M is in a tower that is 140 meters high, its potential energy is defined as the product of the mass of the object by gravity and by the height at which the object is measured from the reference point.

Ep =mgh

When talking about elastic objects such as springs or elastic fibers, it is usually understood that there is an elastic potential energy associated with the constant of the spring. This can be calculated using the following equation:

U ela = 1/2×k×(Dx)²

where:

k = elastic constant of the elastic material [N/m]

Dx = distance stretched or compressed of the elastic material [m]

U = elastic energy [Joules]

So, there are difference between the elastic potential energy and the potential energy.

In a catapult, Initially, energy is stored in the form of potential energy which is later converted into kinetic energy. Potential energy can be stored in the form of elastic potential energy in the case of elastic. It suddenly releases the energy to propel the object into the air.

Learn more about catapult,

https://brainly.com/question/20899342

#SPJ2

how to find volume of a cuboid in cm3

Answers

Answer:

we have to use formula of volume to find volume of a cuboid. ( i.e v = l ×b ×h)

Explanation:

here, let your length of cuboid be x cm, breadth be y cm and height be z cm .

now, formula to find volume of cuboid = length ×

breadth × height.

so, v( volume)= l (length)× b (breadth)× h (height)

or, v= x cm × y cm × z cm

therefore, volume is xyz cm^3..... answer.

hope it helps..

Answer: length times width times height

Explanation:

A uniform metre rod of 5 metre length is suspended horizontally by two strings P and Q.Pis attached 0.8 metre from one end and Q is attached 2 metre from the other end.Given that the weight of the rod is 110N. Calculate the tension in each string

Answers

Answer:

The tension in string P is 25 N, while that of Q is 85 N.

Explanation:

Considering the conditions for equilibrium,

i. Total upward force = Total downward force

                     [tex]T_{P}[/tex] + [tex]T_{Q}[/tex] = 110 N

ii. Taking moment about P,

clockwise moment = anticlockwise moment

110 × (2.5 - 0.8) = [tex]T_{Q}[/tex] × (3 - 0.8)

110 × 1.7 = [tex]T_{Q}[/tex] × 2.2

187 = 2.2[tex]T_{Q}[/tex]

[tex]T_{Q}[/tex] = [tex]\frac{187}{2.2}[/tex]

[tex]T_{Q}[/tex] = 85 N

From the first condition,

[tex]T_{P}[/tex] + [tex]T_{Q}[/tex] = 110 N

[tex]T_{P}[/tex] + 85 N = 110 N

[tex]T_{P}[/tex] = 110 - 85

[tex]T_{P}[/tex] 25 N

Therefore, the tension in string P is 25 N while that of Q is 85 N.

A vertical bar consists of three prismatic segments A1, A2, and A3 with cross-sectional areas of 6000 mm2 , 5000 mm2 , and 4000 mm2 , respectively. The bar is made of steel with E 5 200 GPa. Calculate the displacements at points B, D

Answers

Answer and Explanation:

For computing the displacement at point B and D we need to determine the following calculations

[tex]P_Net = P_C + P_E + P_B[/tex]

= 250 + 350 - 50

= 550 N

Now the deflection for bar AB is

[tex]\delta_{AB} = \frac{PL_{AB}}{AE} \\\\ = \frac{550 \times 500}{6,000 \times 200 \times 10^{3}}[/tex]

[tex]= 2.292 \times 10^{-4} mm[/tex]

Now for bar BC it is

[tex]\delta_{BC} = \frac{PL_{BC}}{AE} \\\\ = \frac{(550 + 50) \times 250}{5,000 \times 200 \times 10^{3}} \\\\ = 1.5 \times 10^{-04} mm[/tex]

And for bar CD it is

[tex]\delta_{CD} = \frac{PL_{CD}}{AE} \\\\ = \frac{(550 -250 + 50) \times 250}{5,000 \times 200 \times 10^{3}} \\\\ = 0.875 \times 10^{-4} mm[/tex]

Now the displacement is as follows

For B

2.292 × 10^{-4} mm

For D, it is

[tex]= 2.292 \times 10^{-4} + 1.5 \times 10^{-4} + 0.875 \times 10^{-4} mm \\\\ = 4.667 \times 10^{-4} mm[/tex]

We simply applied the above formulas for determining the  displacements at points B, D and the same is to be considered  

An object weighs 0.250 kgf in air, 0.150 kgf in water and 0.125 kgf in an oil.
Find out the density of the object and the oil.​

Answers

Answer: Upthrust = Weight - Apparent weight

= 0.250 kgf - 0. 150 kgf

= 0.100 kgf

Density = mass / volume

volume = mass / density

= 0.100 kg / (1000 kg / m³)

= 0.0001 m³

density of object  = mass / volume

= 0.250 kg / 0.0001 m³

= 2500 kg / m³

upthrust of oil = Weight - Apparent weight

= 0.250 kgf - 0.125 kgf

= 0.125 kgf

density = mass / volume

= 0.125 kg / 0.0001 m³

= 1250 kg/m³

density of the object = 2500 kg / m³

density of oil = 1250 kg / m³

A 0.675 kg mass is attached to a
spring of spring constant 72.4 N/m,
pulled, and released. What is the
period of the resulting oscillation?
(Unit = s)

Answers

Answer:

T= 0.6 sec

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

[tex]T= 2\pi \sqrt{\frac{m}{k} }[/tex]

Substituting the given data into the expression above we have

[tex]T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6[/tex]

T= 0.6 sec

Answer:

0.607

Explanation:

Trust me

Two trains run in the opposite direction with speeds of v1 = 15 m / s and v2 = 20 m / s. A passenger on the first train (the one on v1) notes that train 2 takes 6 s to pass on its side. What is the length of the second train? (The passenger is supposed to be immobile looking through the window)

Answers

Answer:

210 m

Explanation:

The speed of train 2 relative to train 1 is 15 m/s + 20 m/s = 35 m/s.

It takes 6 seconds for the train to pass, so the length of the train is:

(35 m/s) (6 s) = 210 m

hey help me plzzzzz i will mark brainliest​

Answers

Answer:

The answer to your question is given below.

Explanation:

Mechanical advantage (MA) = Load (L)/Effort (E)

MA = L/E

Velocity ratio (VR) = Distance moved by load (l) / Distance moved by effort (e)

VR = l/e

Efficiency = work done by machine (Wd) /work put into the machine (Wp) x 100

Efficiency = Wd/Wp x100

Recall:

Work = Force x distance

Therefore,

Work done by machine (wd) = load (L) x distance (l)

Wd = L x l

Work put into the machine (Wp) = effort (E) x distance (e)

Wp = E x e

Note: the load and effort are measured in Newton (N), while the distance is measured in metre (m)

Efficiency = Wd/Wp x100

Efficiency = (L x l) / (E x e) x 100

Rearrange

Efficiency = L/E ÷ l/e x 100

But:

MA = L/E

VR = l/e

Therefore,

Efficiency = L/E ÷ l/e x 100

Efficiency = MA ÷ VR x 100

Efficiency = MA / VR x 100

A 6.0-μF capacitor charged to 50 V and a 4.0-μF capacitor charged to 34 V are connected to each other, with the two positive plates connected and the two negative plates connected. What is the total energy stored in the 6.0-μF capacitor at equilibrium?

Answers

Answer:

5702.88 J or 5.7mJ

Explanation:

Given that :

C 1 = 6.0-μF

C 2 = 4.0-μF

V 1 = 50V

V 2 = 34V

Note that : Q = CV

Q 1 = C1 * V1

Q 1 = 50×6 = 300μC

Q 2 = 34×4 = 136μC

Parallel connection = C 1 + C 2

= 6+4 = 10μC

V = Qt/C

Where Qt = Q1+Q2

V = Q1+Q2/C

V = 300+136/10

V = 437/10

V = 43.6volts

Uc1 = 1/2×C1V^2

= 1/2 × 6μF × 43.6^2

= 1/2 × 6μF × 1900.96

= 3μF × 1900.96volts

= 5702.88J

= 5702.88J/1000

= 5.7mJ

Earthquake damage causes two rabbits to be separated from the rest of the rabbits in their large habitat. They have no way to get back to their original habitat. The two rabbits mate with each other. Over time, all the offspring in the new habitat are descendants of the original two rabbits. What are the outcomes of this situation? A.The rabbits in the new habitat will have lower genetic variation than the rabbits in the original habitat. B. The rabbits in the new habitat will have a higher risk of random genetic mutations than the rabbits in the original habitat. C. The rabbits in the original habitat have a greater likelihood of choosing an unrelated mate than the rabbits in the new habitat. D.The rabbits in the original habitat will be less likely to reproduce than the rabbits in the new habitat.

Answers

Answer:

A.The rabbits in the new habitat will have lower genetic variation than the rabbits in the original habitat.

Explanation:

If two animals of opposite sex are isolated from a larger group of animal, and made to reproduce. They will produce offspring with similar genetic makeup. If this offspring still remain isolated, and continue to interbreed within themselves for a number of consecutive generations, their offspring will all be very closely related genetically. Situations like this just as with the two rabbits in the question leads to a lower genetic variation within the offspring of the two animals.

Animals need to reproduce within a larger group in order to increase genetic variation. Increasing genetic variation reduces the risk of been sucked into a gene pool. A lower genetic variation reduces the fitness of the animals involved. It is only an advantage in cases in which the the original pair are resistant to a deadly disease. In this case all the offspring also develop this immunity. Mostly the effects of a lower genetic variation leaves negative impacts, and animals try to avoid this by preferring to interbreed with unrelated partner

Answer:

I got this and got the answer correct.

Explanation:

Hope it helps :)

you (60 kg) are standing in a (500 kg) elevator that is moving upwards from a ground floor on a building what is the power rating of the motor that can lift this elevator if the elevator travels a distance of 20m upwards in 15 s

Answers

Explanation:

Power = work / time

Power = force × distance / time

P = (650 kg) (10 m/s²) (20 m) / (15 s)

P = 8667 W

A projectile is fired from a height of 80 M above sea level, horizontally with a speed of 360 M / S, calculate: The time it takes for the projectile to reach the water. The Horizontal scope. The height that remains to descend after 2 seconds of being launched.

Answers

Answer:

(a) The projectile takes approximately 4.420 seconds to reach the water, (b) The horizontal scope of the projectile is 1591.2 meters, (c) The remaining height to descend after 2 seconds of being launched is 63.624 meters.

Explanation:

The projectile experiments a parabolic motion, where horizontal speed remains constant and accelerates vertically due to the gravity effect. Let consider that drag can be neglected, so that kinematic equation are described below:

[tex]x = x_{o}+v_{o,x} \cdot t[/tex]

[tex]y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}[/tex]

Where:

[tex]x_{o}[/tex], [tex]y_{o}[/tex] - Initial horizontal and vertical position of the projectile, measured in meters.

[tex]v_{o,x}[/tex], [tex]v_{o,y}[/tex] - Initial horizontal and vertical speed of the projectile, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]x[/tex], [tex]y[/tex] - Current horizontal and vertical position of the projectile, measured in meters.

Given that [tex]x_{o} = 0\,m[/tex], [tex]y_{o} = 80\,m[/tex], [tex]v_{o,x} = 360\,\frac{m}{s}[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the kinematic equations are, respectively:

[tex]x = 360\cdot t[/tex]

[tex]y = 80-4.094\cdot t^{2}[/tex]

(a) If [tex]y = 0\,m[/tex], the time taken for the projectile to reach the water is:

[tex]80 - 4.094\cdot t^{2} = 0[/tex]

[tex]t = \sqrt{\frac{80}{4.094} }\,s[/tex]

[tex]t \approx 4.420\,s[/tex]

The projectile takes approximately 4.420 seconds to reach the water.

(b) The horizontal scope is the horizontal distance done by the projectile before reaching the water. If [tex]t \approx 4.420\,s[/tex], the horizontal scope of the projectile is:

[tex]x = 360\cdot (4.420)[/tex]

[tex]x = 1591.2\,m[/tex]

The horizontal scope of the projectile is 1591.2 meters.

(c) If [tex]t = 2\,s[/tex], the height that remains to descend is:

[tex]y = 80-4.094\cdot (2)^{2}[/tex]

[tex]y = 63.624\,m[/tex]

The remaining height to descend after 2 seconds of being launched is 63.624 meters.

Diagram 7 shows the velocity-time graph of an
object for 12 s.

When is the object at a distance of one-quarter of
the total distance travelled in the 12 s?
A 3 s
B 4 s
C 5 s
D 6 s

*The answer is D but can anyone tell me the solving steps? Or perhaps the answer is wrong?*​

Answers

Answer:

t = 6

Explanation:

Displacement is equal to the area under a velocity vs time graph.

In this case, the area is a triangle.  At time t, the base of the triangle is t.  The height of the triangle can be found with similar triangles:

h / t = 8 / 12

h = ⅔ t

So the distance traveled at time t is:

d = ½ (t) (⅔ t)

d = ⅓ t²

The distance traveled at time 12 is:

D = ½ (12) (8)

D = 48

We want to find when d = D/4.

d = D/4

⅓ t² = 48/4

⅓ t² = 12

t² = 36

t = 6

Alternatively, since the acceleration is constant here, we could use a constant acceleration equation.

Δx = v₀ t + ½ at²

Given v₀ = 0 m/s and a = ⅔ m/s²:

Δx = (0) t + ½ (⅔) t²

Δx = ⅓ t²

When t = 12, Δx = 48.

⅓ t² = 48/4

t = 6

Janaki Temple and Pashupatinath Temple are increasing our pride how​

Answers

Answer:

Janaki temple and Pashupatinath Temple are found in Nepal. These structures are religious and they increase the pride of the country through tourism. These temples are important in the country and are mostly visited by tourists.

This also helps to bring in income for the country and also helps by attracting many visitors and a corresponding development of its tourism industry.

define the unit of current​

Answers

Answer:

The unit of current is defined as the flow of 1 coulomb of charge in one second

Which statement best describes the difference between how lenses and
mirrors interact with light?

A. Lenses bring light to a point; mirrors do not.
B. Lenses form images by reflecting light; mirrors do not.
C. Lenses spread light apart; mirrors do not.
D. Lenses form images by refracting light; mirrors do not.

Answers

D I think this is the right answer but I am not completely sure

Answer:D

Explanation:

Apex

PLEASE HELP. i will mark brainliest. and do more!

Answers

I would suggest an easier route. So for example, I would research light energy, where it comes from, and what causes it. I won't be able to do the work for you though.

ride and average of 15mph for 30 miles, how long does it take?

Answers

Answer:

2 hrs

Explanation:

time = distance ÷ speed

We have seen that starlight passing through the interstellar medium is dimmed and reddened. Look at the photo of a sunset on Earth. The Sun’s light also appears reddish at sunset. Given your understanding of the reddening of starlight, why do you think sunsets appear red?

Answers

Answer:

Explanation:

Reddening of sun's rays at sunset and sunrise is due to scattering of light . The white light consisting of seven colours coming from the sun are scattered in different directions when they fall on the air particles present in atmosphere . Red coloured light scatters least and it travels straight forward to the viewer on the earth . On the other hand other colours scatter most and therefore they go out of area of vision for the viewer on the earth . Since only red colour reaches the eye of the viewer , sun's ray appear red . This happens during sunrise and sunset . It is so because during this period , sun rays travel far greater distance through  atmosphere , so scattering is most pronounced .

Other Questions
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